Answer:
1. 30 neutrons
2. 26 electrons
Explanation:
The number of neutron = mass - #protons = 56 - 26 = 30
The number of electrons = #protons = 26
A chemist determined by measuring that 0.0750 moles of calcium participated in a chemical reaction. Calculate the mass of the calcium that participated in the chemical reaction. Be sure your answer Has the correct number of significant digits.?g
The mass of 0.0750 moles of calcium is 3.01g.
To calculate the mass of calcium we need to use the molar mass that we can find in the Periodic Table of Elements.
The molar mass of calcium is 40.1 g/mol.
Now, with a mathematical Rule of Three we can calculate the mass of calcium of 0.0750 moles:
[tex]\begin{gathered} 1\text{ mol Ca \_\_\_\_\_\_\_\_ 40.1 g} \\ \text{ 0.0750 mol \_\_\_\_\_\_\_ x = }\frac{0.0750\text{mol . 40.1g }}{1\text{mol}} \\ \\ x=3^{}.01\text{ g} \end{gathered}[/tex]So, the mass of 0.0750 moles of calcium is 3.01g.
You heat 3.939 g of a mixture of Fe3O4 and FeO to form 4.197 g Fe2O3. The mass of oxygen reacted is
Explanation:
A mixture of differet iron oxides is heated and they it absorbs oxygen from the air to form iron (II) oxide. The reaction can be represented like this:
2 Fe₃O₄ + 2 FeO + O₂ ----> 4 Fe₂O₃
The mass of the mixture of Iron oxides is 3.939 g. The mass of Fe₂O₃ formed is greater than the original mass, it is 4.197 g. That means that the sample absorbed oxygen.
mass of Fe₃O₄ + mass of FeO = 3.939 g
mass of Fe₂O₃ = 4.197 g
The law of conservation of mass states that no mass is loss or created in a chemical reaction. A mass balance can be written:
mass of Fe₃O₄ + mass of FeO + mass of O₂ = mass of Fe₂O₃
The known values can be replaced in the equation, and it can be solved for mass of O₂ to obtain the answer to the problem.
mass of Fe₃O₄ + mass of FeO + mass of O₂ = mass of Fe₂O₃
mass of O₂ = mass of Fe₂O₃ - (mass of Fe₃O₄ + mass of FeO)
mass of O₂ = 4.197 g - 3.939 g
mass of O₂ = 0.258 g
Answer: the mass of oxygen reacted is 0.258 g
Drag each tile to the correct location.
What types of mixtures are these?
peanuts and almonds mixed
food coloring dissolved in water
cup of tea and sugar
together in a bowl
a bucket full of sand and gravel
Homogeneous Mixture
Heterogeneous Mixture
Hetergeneous mixture peanuts and almonds mixed ,a bucket full of sand and gravel. Homogeneous Mixture -food coloring dissolved in water together in a bowl,cup of tea and sugar .
A Heterogeneous Mixture: what is it?When the composition of a mixture is not constant throughout the mixture, the mixture is said to be heterogeneous. A variety of make up vegetable soup. Each mouthful of soup will have variable proportions of the soup's various veggies and other ingredients.
Describe homogenous mixture using an example.For illustration A mixture of sugar and water, or salt and water, both of which have the same component ratio throughout the mixture, are examples of homogenous mixes.
TO know about Homogeneous Mixture& Heterogeneous Mixture visit:
https://brainly.com/question/24898889
#SPJ13
What is the mass of 9.50 moles of magnesium chloride, MgCl2 ?'
A student sets up the following equation to convert a measurement.(The ? stands for a number the student is going to calculate.)Fill in the missing part of this equation. (0.020 g/ml) *_=? g/l
0.02g/L
This question involves conversion of units and in this case, we are converting from g/ml to g/l.
1 g/ml = 1000 g/L
And we are given 0.020 g/ml to convert into g/L. The easiest way to do this is simply multiply 0.020 g/mL by 1000 to convert it into g/L
[tex]0.020\text{ }\frac{g}{mL}\times1000=20\text{ }\frac{g}{L}[/tex]From the calculation above, 0.020g/ml is equivalent to 20g/L.
The reaction represented by the following equation is a reversible process. N2O4(g)➡️⬅️2NO2(g)If you were to allow 1 mol of NO2 to react in a sealed container for some time, what would you expect to find in the container?NO2 onlyN2O4 onlyNothing, the vessel would be emptySome N2O4 and some NO2
Explanation:
The reaction:
N2O4(g) <=> 2NO2(g)
Inicially 0 [1 mol/Volume]
Reacts +x -2x
Equilibrium +x [1 mol/Volume]-2x
[1 mol/Volume] means molarity
In a chemical reaction, chemical equilibrium is the state in which the forward reaction rate and the reverse reaction rate are equal. The result of this equilibrium is that the concentrations of the reactants and the products do not change.
Therefore, the answer: Some N2O4 and some NO2
A saturated solution of MgF2 is prepared at 27°C. After equilibrium has been reached, the concentrationof magnesium ions in the solution is found to be 1.2 x 10-3 M. Type in the correct values for A and B inthe ICE table.A:Mg2+(aq)2F (aq)1SolidAMBMB:DONEс-Dissolvedsolid+?M+?MELess solid?M?MIntro
Answer:
A: 0
B: 0
Explanation:
Initially the concentration of Mg+2 ions and F- ions is zero. The ICE table is:
The energy released when a nucleus forms is calledQuestion 26 options: enthalpy. atomic mass. a becquerel. binding energy.
The correct answer in this case is binding energy, which is the energy released when a collection of nucleons form a nucleus.
The correct answer is the last choice.
A -13.68 gram of sample of iron is heated in the presence of excess fluorine. A metal Fluoride is formed with a mass of 27.64g. Determine the empirical formula of the metal fluoride.
Explanation:
A 13.68 g sample of iron is reacted in presence of excess fluorine and an iron fluoride with a mass of 27.64 g is formed.
We have to find the empirical formula of our compound. This compound has two elements: Fe and F. We can express it like:
metal fluoride = FeₐFₓ
Where a is the subscript of Fe and x is the subscript for F.
First we have to find the mass of F present in the compound. We know that our compound has a total mass of 27.64 g and the mass of Fe present is 13.68 g. Since it only has two elements we can find the mass of F.
mass of sample = mass of Fe + mass of F
mass of F = mass of sample - mass of Fe
mass of F = 27.64 g - 13.68 g
mass of F = 13.96 g
So we found that our sample has 13.96 g of F and 13.68 g of Fe. Now we can determine the number of moles of each element that are present in the sample by using their molar masses.
molar mass of Fe = 55.85 g/mol
molar mass of F = 19.00 g/mol
moles of Fe = 13.68 g * 1 mol/(55.85 g)
moles of Fe = 0.245 moles
moles of F = 13.96 g * 1 mol/(19 g/mol)
moles of F = 0.735 moles
By definition the empirical formula is "simplest whole number ratio of atoms present in a compound". So if we want to find the ratio between them we have to divide both of them by the smallest number.
a = subscript of Fe = 0.245/0.245 = 1
x = subscript of F = 0.735/0.245 = 3
So the empirical formula of our compound is:
empirical formula = FeₐFₓ
empirical formula = FeF₃
Answer: empirical formula = FeF₃
12: from the following list, decide whether the following are Arrhenius bases or acids.•HCl•NaOh•HBr•H2SO4•NH4OH•H3PO4•HNO3•LiOH•Ba(OH)2•CsOH•HF•KOH
Answer:
The Arrhenius acids in the list are:
HCl, HBr , H2SO4 , H3PO4 , HNO3 , HF
The Arrhenius bases are:
NaOH , NH4OH , LiOH , Ba(OH)2 , CsOH and KOH
Explanation:
An Arrhenius acid increases the concentration of H+ ions while an Arrhenius acid increases the concentration of OH- ions
Thus, an Arrhenius acid would yield H+ ions on ionization while an Arrhenius base will yield OH- ions on ionization
The Arrhenius acids in the list are:
HCl, HBr , H2SO4 , H3PO4 , HNO3 , HF
The Arrhenius bases are:
NaOH , NH4OH , LiOH , Ba(OH)2 , CsOH and KOH
How many liters of oxygen gas at STP are required to react with 30.25 g of aluminum in the production of aluminum oxide?
Answer:
18.82L of oxygen gas are needed.
Explanation:
1st) It is necessary to write and balance the chemical reaction:
[tex]3O_2+4Al\rightarrow2Al_2O_3[/tex]2nd) From the balanced reaction, we can see that 3 moles of oxygen gas (O2) react with 4 moles of aluminum (Al). To convert moles to grams, it is necessary to use the molar mass of oxygen (32g/mol) and aluminum (27g/mol):
- O2 conversion:
[tex]\begin{gathered} 1mol-32g \\ 3mol-x=\frac{3mol*32g}{1mol} \\ x=96g \end{gathered}[/tex]- Al conversion:
[tex]\begin{gathered} 1mol-27g \\ 4mol-x=\frac{4mol*27g}{1mol} \\ x=108g \end{gathered}[/tex]Now we can see that 96g of O2 react with 108g of Al.
3rd) We have to calculate the grams of O2 that will react with 30.25g of Al:
[tex]\begin{gathered} 108gAl-96gO_2 \\ 30.25gAl-x=\frac{30.25gAl*96gO_2}{108gAl} \\ x=26.89gO_2 \end{gathered}[/tex]Using the molar mass of oxygen, we know that 26.89g represent 0.84 moles of O2.
4th) Finally, a mole of a gas at STP conditions occupies a volume of 22.4L. With this number and the moles of oxygen gas, we can calculate the liters:
[tex]\begin{gathered} 1mol-22.4L \\ 0.84mol-x=\frac{0.84mol*22.4L}{1mol} \\ x=18.82L \end{gathered}[/tex]So, 18.82L of oxygen gas are needed.
strategies for controlling carbon monoxide are in conflict with strategies for controlling oxides of nitrogen .
Answer:
I do not know how to answer this question. Is it even a question?
Explanation:
How many pounds in 16.1lbmol of pure HCl
Answer:
586.846 lbs
Explanation:
the molar mass of HCl is 1 + 35.45 = 36.45
this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845
check alll of the following statements that are true about the ion whose symbol Ca2+
The correct statement about the description of ion whose symbol is Ca2+ among the choices above are:
It is a cationIt is a divalent metalThe options b and d are correct.
How calcium ion is a cation and divalent metalIt follows that elements whose charge on them are positive are called cations. In order words, in the periodic table of science of chemistry, the positively charged ions of elements are known as cations. Calcium has a positive of 2 on as it ion and this makes it a cation.
In addition to the above, calcium ion helps in signal transduction pathways of cells of living organisms. This goes to say that they also help in the body's normal functioning of the human body.
However, on a second note, calcium in the periodic table belongs to group 2, has a valence electrons of 2 and a metallic element; thereby making it a divalent metal.
In conclusion, we can now confirm from all said above that calcium above is a cation.
Complete question:
Check all of the following statements that are true about the ion whose symbol Ca2+
a. It is an anion
b. It is a cation
c. Its atoms is connected by tripple bonds
d. It is a divalent metal
Read more on ions:
https://brainly.com/question/22277121
#SPJ1
PART 1Select Introduction, and for the following unbalanced reactions found in the sim provide the missing coefficients.CoefficientReactant1CoefficientReactant2CoefficientProduct1CoefficientProduct2N2+H2HONH3H2O2COz
They give us the reactions with their respective products and reactants. To balance a reaction we must bear in mind that matter is neither created nor destroyed, it only transforms. So the mass that we have in the reactants must be the same in the products. We verify this by counting the atoms of each element on each side of the reaction.
In the first reaction we have nitrogen and hydrogen. We have 2 nitrogens and 2 hydrogens in the reactants. We start off-balanced in nitrogen, so we place coefficient 2 in the NH3 molecule to get 2NH3. Now that we have 2 nitrogens and 6 hydrogens in the products, we must balance the hydrogen in the reactants. For that, we place the coefficient 3 in the H2 in such a way that there will be 6 hydrogen atoms in the reactants. The equation is balanced and will be:
[tex]N_2+3H_2\rightarrow2NH_3[/tex]We do this same procedure for the other two equations. We count the atoms, we put the coefficients so that the number of atoms is conserved and we count again until the number of atoms of each element is the same on each side of the reaction. For the other two reactions we have:
[tex]2H_2O\rightarrow2H_2+O_2[/tex][tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]The value of AH rxn for the following reaction is -72 kJ. How many kJ of heat is released when 0.989 g of HBr (80.91 g/mol) is formed? H2 (g) + Br2 (g) -› 2 HBr (gram). A. -144B. -72 C. -0.44 D. -36
Answer:
[tex]C\text{ : -0.44 KJ}[/tex]Explanation:
Here, we want to get the amount of heat released in KJ
From the change in enthalpy given and the equation of reaction, we know that 2 moles of HBr would lead to that amount of heat
Now, let us get the actual amount of heat released
We need to get the actual number of moles of HBr produced
Mathematically, we can calculate that by dividing the mass of HBr by its molar mass
We have that as:
[tex]\frac{0.989}{80.91}\text{ = 0.0122 mol}[/tex]From the reaction information:
-72 KJ was released by 2 moles
x KJ would be released by 0.0122 mol
To get the value of x, we have it that:
[tex]\begin{gathered} x\text{ }\times2\text{ = 0.0122 }\times\text{ \lparen-72\rparen} \\ \\ x\text{ = -36 }\times\text{ \lparen0.0122\rparen = -0.44 KJ} \end{gathered}[/tex]The isomerization of methyisocyanide, CH3NC, to acetonitrile, CH3CN, is a first-order reaction. If 2.56 mg of CH3NC is present initially, and 1.89 mg is present after 474 min at 230 °C, what is the value of the rate constant, k?Assume the volume is constant. min-1
To solve this question we will use the integrated rate late law for first order reaction:
[tex]\begin{gathered} ln[A]=-kt+ln[A]_0 \\ [A]:concentration\text{ }of\text{ }A\text{ }at\text{ }certain\text{ }time=1.89mg \\ k:rate\text{ }constant=x \\ t:time=474\text{ }mins \\ [A]_0:initial\text{ }concentration=2.56mg \end{gathered}[/tex]By substituting the values we have to determine the unknown we get:
[tex]\begin{gathered} ln1.89=-k\times474min+ln2.56 \\ \frac{0.637-0.940}{-474min}=k \\ k=6.392\times10^{-4}\text{ }min^{-1} \end{gathered}[/tex]Answer: Rate constant k is 6.392x10^-4 per min.
The soft drinks sold at county fairs are often dispensed from large pressurized containers that contain carbon dioxide gas above the liquid at a partial pressure of about 4 atm, compared to carbon dioxide’s normal partial pressure of 0.00035 atm in the air at sea level. a. Describe the reversible change that takes place inside one of these soft drink containers when the pressure of CO2 above the liquid is first brought from 0.00035 atm to 4 atm. Explain why this system comes to a dynamic equilibrium in which there is no net change in the amount of gas above the liquid or the amount of gas dissolved in the liquid.
CO2 particles move faster through the solution. Gas solubility increases as liquid CO2 partial pressure rises.
Dynamic equilibrium occurs when the solution rate matches the escape rate, and neither the gas above the liquid nor the gas dissolved in it changes.
This is further explained below.
What is dynamic equilibrium?Generally, The idea of partial pressure is connected to the changes that occur in soft drink containers. Since there are no gas particles in the liquid when we add CO2 at a typical partial pressure of 0.00035, the CO2 gas begins to move into the solution at a faster pace than it can leave.
But when the concentration of CO2 gas rises, it begins to diffuse into the liquid, and eventually, a dynamic equilibrium is attained when the rate of the solution equals the rate of escape.
However, as we continue to add CO2 to this dynamic equilibrium, its partial pressure will rise until it reaches 4 atm, and this rise in partial pressure accelerates the rate of solution. Thus, raising the partial pressure of CO2 causes this reversible transformation to occur.
When the rate of the solution equals the rate of escape, this is known as dynamic equilibrium, and neither the quantity of gas above the liquid nor the amount of gas dissolved in it changes in any significant way.
Now here comes what role is played by partial pressure. When the rate of solution and the rate of escape reach a dynamic equilibrium and we begin to introduce additional CO2 gas to this dynamic equilibrium stage.
The CO2 gas particle's partial pressure and concentration both rise. Because of the increased rate of collision between the surface of CO2 gas and the surface of the liquid particles due to the increasing concentration, the rate of solution also rises. The pace of solution has now surpassed the rate of escape.
As a result, the rate at which CO2 gas particles travel through the solution increases. This is how a rise in CO2 partial pressure over liquid causes a rise in gas solubility.
Read more about CO2 partial pressure
https://brainly.com/question/15121846
#SPJ1
Balance the following equation:ZnO(s)⟶ΔZn(l)+O2(g) Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer:2ZnO(s)→2Zn(l)+O2(g)
Explanation:
If you wanted to dilute the 3M NaOH solution to 500mL of 1M NaOH solution, how much L of the 3M NaOH solution would you need?
0.167L
Explanation:In order to know how much L of the 3M NaOH solution would you need, we will simply set up an equal proportion solution expressed as;
[tex]C_1V_1=C_2V_2[/tex]C1 and C2 are the concentration of the solutions
V1 and V2 are the volumes of the solutions
Given the following parameters;
C1 = 1M
V1 = 500mL
C2 = 3M
V2 = ?
Substitute the given parameters into the formula above to get the required litre of solution needed.
[tex]\begin{gathered} 1\times500=3\times V_2_{} \\ 500=3V_2 \\ \text{Swap} \\ 3V_2=500 \end{gathered}[/tex]Divide both sides by 3:
[tex]\begin{gathered} \frac{3V_2}{3}=\frac{500}{3}_{} \\ V_2=166.67mL \end{gathered}[/tex]Converting to litres
Since 1mL = 0.001L
166.67mL = x
Cross multiply
[tex]\begin{gathered} 1\times x=166.67\times0.001 \\ x=0.167L \end{gathered}[/tex]Hence the amount of L of the 3M NaOH solution would you need is 0.167L
How many moles of argon atoms are present in 11.2 L of argon gas at STP? Round your molar mass to whole numbers andgive your answer in the correct number of sig figs and units
STP or Standard Pressure and Temperature is widely used when the subject is gases. The used standard temperature is 273 K or 0°C and the standard temperature used is 1 atm. At these conditions 1 mol will be equal to 22.4 L of volume, therefore if we have 11.2 L of Argon:
22.4 L = 1 mol
11.2 L = x moles of Argon
22.4x = 11.2 L
x = 0.500 moles of Ar will be present in 11.2 L of volume
How many atoms of oxygen are in the reactants of the following equation? 3NO2 + H2O --> NO + 2HNO3
The reactants are the compounds before the arrow and the products are after the arrow. Just as they show us, the oxygen atoms in the reagents will bJust as the reaction shows, the oxygen atoms in the reactants will be:
Answer: There are 7 atoms of oxygen in the reactants
When working with electric charges, what symbol is used in equations torepresent the electric force on an object?A. rB. qC. FeD. E
A. r: distance
B. q: charge
C. Fe: electric force
D. E: Electric field
So the answer is option C.
Draw the Lewis structure for chloroform, CHCl3
Answer:
Explanation:
To write the Lewis structure, it is important to look for the electrons of each atom in the Periodic Table of Elements.
C has 4 valence atoms, H has 1 valence atom and Cl has 7 valence atoms.
We write the C atom in the center. Then we have to complete the Octet in each atom, except in Hydrogen, because it can only has 2 electrons bonded.
What is the number of formula units in a 9.21 mol sample of CaO ?
Answer:
5.546262 x 10^24 formula units
Explanation:
Use avogadro's number
9.21 mol CaO ((6.022 x 10^23 formula units CaO)/1 mol CaO)) = 5.546 x 10^24.
I rounded to 3 sig figs.
Define hydrogen bonding and explain how hydrogen are bonding involved in the
transfer of genetic material.
Answer:
Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.
Explanation:
What is the mass in grams of 8 moles of ammonia, NH3?
The first step to find the mass of the 8 moles of NH₃ is to find the molar mass of NH₃. The molar mass of any compound is the mass of one mol of it. To calculate it, we have to look for the atomic masses of the elements that the molecule has.
N: 14.01 amu
H: 1.01 amu
Then the molar mass of NH₃ will be:
molar mass of NH₃ = 14.01 + 3 * 1.01
molar mass of NH₃ = 17.04 g/mol
Now that we know the molar mass of NH₃ (the mass of one mol of it) we can easily find the mass of 8 moles.
mass = 8 moles of NH₃ * 17.04 g/mol = 136.32 g
mass = 136.32 g
Answer: the mass in grams of 8 moles of ammonia is 136.32 g
determine the mass (in grams) of c4h10 that is required to produce 14.7 g co2
According to the stoichiometry, 4.85 g of propane is required to produce 14.7 g carbon dioxide.
What is stoichiometry?
It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given problem as per balanced equation of combustion of propane 2 molecules of propane produce 8 molecules of carbon dioxide.That is, 116.24 g of propane produces 352.08 g of carbon dioxide.
∴14.7 g of carbon dioxide is produced by, 14.7×116.24/352.08=4.85 g of propane.
Thus, 4.85 g of propane is required to produce 14.7 g of carbon dioxide.
Learn more about stoichiometry,here:
https://brainly.com/question/28780091
#SPJ1
Which of the listed species have the following electron configuration?
(See attached)
Answer:
Al 3+
Na+
Mg2+
F-
Explanation:
The element with the given electron that isn't an ion is Neon. It has 10 electrons in total.
Looking at the periodic table attached will help to see how the elements below are related to the one circled in red (Ne).
Al 3+ lacks 3 (because it has a 3+ charge) of its normal electrons so it has 10 and will have the same electron configuration as shown.
Na+ lacks one electron so it will also have 10 electrons instead of its normal 11.
Mg 2+ lacks two electrons so it will also have 10 total electrons.
F- has gained an extra electron so it now has 10 instead of 9.
Al3+, Na+, F-, and Mg2+ will have the given electronic configuration.
The electronic configuration given in the question is:
2p6, 2s2, 1s2
If it was a stable atom, the answer would have been Neon.
And if that would have been negative ion or anion (to be precise),
the answer would have been either F- or O2-.
But in the case of positive ions or we can say cations,
Al3+, Na+, and Mg2+ have the given electronic configurations.
Because the atom of Aluminum loses three electrons to achieve another state which is responsible for the formation of Al3+.
Similarly,
The atoms of Sodium and Magnesium also lose one and two electrons respectively to form Na+ and Mg2+.
So, we can conclude that Al3+, Na+, F- and Mg2+ will have the given electronic configuration.
Learn more about Electronic Configuration at
https://brainly.com/question/11422000
17 was found from determination in a mass spectrometer that an element X has three Isotopes whose mass are & 19.19,20.99 and 21.99 respectively The abundance of these I sotopes are 90.92% 0.25% $8.83% respectively Calculate the relative atomic mass.
The relative atomic mass of the given element is 40.372 amu.
What is relative atomic mass?The relative atomic mass of an element is considered as the sum of the isotopes masses each multiplied by the percentage which is found in nature.
The formula which is used to calculate the relative atomic mass is
Relative atomic mass = sum of all atomic masses of isotopes × fractional abundance
Given,
Mass of isotopes 1 = 19.19 amu
Mass of isotopes 2 = 20.99 amu
Mass of isotopes 3 = 21.99 amu
Fractional abundance of isotope 1 = 0.9092
Fractional abundance of isotope 2 = 0.0025
Fractional abundance of isotope 3 = 0.0883
By substituting all the values, we get
[( 19.19 × 0.9092) + (20.99 × 0.0025) + (21.99 × 0.883)]
= 17.447 + 0.052 + 22.873
= 40.372 amu.
Thus, we concluded that the relative atomic mass of the given element is 40.372 amu.
learn more about relative atomic mass:
https://brainly.com/question/13055840
#SPJ10
