ANSWER
[tex]P=\frac{100A}{100+RT}[/tex]EXPLANATION
We want to make the subject of the formula in the given equation:
[tex]A=P+\frac{PRT}{100}[/tex]First, factorize the right-hand side of the equation:
[tex]A=P(1+\frac{RT}{100})[/tex]Simplify the bracket:
[tex]A=P(\frac{100+RT}{100})[/tex]Now, divide both sides by the term in the bracket:
[tex]\begin{gathered} \Rightarrow P=A\cdot\frac{100}{100+RT} \\ \Rightarrow P=\frac{100A}{100+RT} \end{gathered}[/tex]That is the answer.
George filled up his car with gas before embarking on a road trip across the country. The capacity of George's gas tank is 12 gallons and her car uses 2 gallons of gas for every hour driven. Make a table of values and then write an equation for G, in terms of t, representing the number of gallons of gas remaining in George's gas tank after t hours of driving.
Given that the capacity of George's gas tank is 12 gallons and her car uses 2 gallons of gas for every hour driven.
[tex]\begin{gathered} G_{\circ}=12 \\ m=-2 \end{gathered}[/tex]slope m is negative since the gas is reducing every hour.
Writing the equation for G, in terms of t, representing the number of gallons of gas remaining in George's gas tank after t hours of driving.
[tex]\begin{gathered} G=G_{\circ}+mt \\ G=12+(-2)t \\ G=12-2t \end{gathered}[/tex]The equation for G is;
[tex]G=12-2t[/tex]Calculating the number of gallons remaining in the tank after 0,1,2 and 3 hours, we have;
[tex]\begin{gathered} G=12-2t \\ at\text{ t=0}; \\ G_0=12-2(0)=12 \\ at\text{ t=1}; \\ G_1=12-2(1)=10 \\ at\text{ t=2}; \\ G_{2_{}}=12-2(2)=12-4=8 \\ at\text{ t=3;} \\ G_3=12-2(3)=12-6=6 \end{gathered}[/tex]Completing the table, we have;
A portion of $ 100,000 (x) is invested with a 3% after one year. The rest of the investment (and) obtained a return of 1%. The total return on investment was $ 1,800. 1) What equation shows the return on investment? 2) What equation shows how the $ 100,000 was divided?3) how much money was invested at a 3% rate of return?4) how much money was invested at a rate of return of 1%
We can write a system of equations that describe our problem.
Since we don't know how the original $100,000 was divided, we call the two parts X and Y
So we know that X + Y = 100000
Then we know the Combined Interest coming from the accounts.
We use the Interest formula for return on investment:
I = P * r * t
were P is the principal, r is the percent rate (in decimal form), and t is the number of years (in our case 1)
Then the interest from the 3% account (let's call it I1) (if X amount of money was deposited there) is:
I1 = X * 0.03 * 1 = 0.03 X
Similarly, the interest I2 coming from the 1% account (if Y amount of money was deposited there) is given by:
I2 = Y * 0.01 * 1 = 0.01 Y
Then, the addition of these two interest is our total return of $1800:
0.03 X + 0.01 Y = 1800
Then our system of equations is:
X + Y = 100000
0.03 X + 0.01 Y = 1800
which we solve by substituting for example for Y in the first equation:
Y = 100000 - X
and replacing the Y by this expression in our second equation:
0.03 X + 0.01 (100000 - X) = 1800
use distributive property to eliminate parenthesis:
0.03 X + 1000 - 0.01 X = 1800
combine like terms
0.02 X + 1000 = 1800
subtract 1000 from both sides
0.02 X = 800
divide both sides by 0.02 to completely isolate X:
X = 800 / 0.02
X = $40000
This is the amount deposited on the 3% account
Then we easily calculate the amount deposited in the other account by replacing x with $40000 in the equation we use for substitution:
Y = $100000 - $40000 = $60000
Then, the amount deposited in the 1% account was $60000
and the amount deposited in the 3% account was $40000.
through: (5,-4), slope = -9/5
The slope intersept form of a line is ,
[tex]y-y_1=m(x-x_1)[/tex]Given the point (x1,y1) is (5,-4) and slope is -9/5 implies,
[tex]undefined[/tex]i need help with this too
a The value of (2.3 × 10⁴) × (1.5 × 10^-2) is 3.45 × 10^2
b. The value of (3.6 × 10^-5) ÷ (1.8 × 10^2) is 2 × 10^-3. This illustrates the concept of standard form.
What is standard form?The standard form is simply used in Mathematics to illustrate the numbers that are either too large or too small.
It's important to note that the multiplication of exponents is an addition and the division of the power is subtraction.
Therefore, (2.3 × 10⁴) × (1.5 × 10^-2) will be:
= (2.3 × 1.5) × (10^(4-2)
= 3.45 × 10^2
Also, (3.6 × 10^-5) ÷ (1.8 × 10^2) will be:
= (3.6 ÷ 1.8) × 10^(-5 + 2)
= 2 × 10^-3.
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Use the distance formula to calculate the length of the leg CD
To calculate the distance between two points on the coordinate system you have to use the following formula:
[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]Where
d represents the distance between both points.
(x₁,y₁) are the coordinates of one of the points.
(x₂,y₂) are the coordinates of the second point.
To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph
C(2,-1)
D(-1,-2)
Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)
[tex]\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}[/tex]The length of CD is √10 units ≈ 3.16 units
Question 2 (7 points)Match the fractions and decimals to the corrects percentage.
we can change a fraction to a percentage multiplying the fraction by 100
also, we can change a decimal number to a percentage multiplying by 100
for example
1. 1/5
[tex]\frac{1}{5}\cdot100=20[/tex]In this case, 1/5 represent 20%
4. .625
[tex]0.625\cdot100=62.5[/tex]In this case, 0.625 represent 62.5%
If we do the same process to all the next numbers we will obtain the next solutions.
1. 1/5 ------ a. 20%
2. 8/10 ------ f. 80%
3. 0.08 ------ d. 8%
4. .625 ---- g. 62.5%
5. 32/100 ---- b. 32%
6. 1/2 ------ c. 50%
7. 1.25 ---- e. 125%
(Algebra 1 Equivalent equations)
In a family, the middle child is 5 years older than the youngest child.
Tyler thinks the relationship between the ages of the ages of the children can be described with 2m-2y=10, where m is the age of the middle child and y is the age of the youngest.
Explain why Tyler is right.
Let the middle child is m and youngest is y.
The middle child is 5 years older than the youngest child, it can be shown as:
m - y = 5Tyler's equation is equivalent to ours since it can be obtained by multiplying both sides of our equation by 2:
2(m - y) = 2*52m - 2y = 10 ⇔ m - y = 5So Tyler is right.
Please help:What are the zeros of the quadratic function?f (z )= 3z^2 − 11z − 4Enter your answers, as simplified fractions if necessary, in the boxes.The zeros of f (z) are __ and __.
We need to find the zeros for the next function:
[tex]f(z)=3z^2−11z−4[/tex]We can find those zeros using the quadratic formula given by:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Use the form ax²+bx+x.
Where a=3
b= -11
c=-4
Replacing :
[tex]\begin{gathered} x=\frac{-(-11)\pm\sqrt{(-11)^2-4(3)(-4)}}{2(3)} \\ Simplify \\ x=\frac{11\pm\sqrt{169}}{2\ast3} \\ x=\frac{11\pm13}{2\ast3} \\ Therefore: \\ x_1=\frac{11-13}{6}=\frac{-2}{6}=-\frac{1}{3} \\ x_2=\frac{11+13}{6}=\frac{24}{6}=4 \end{gathered}[/tex]Therefore, the zeros of f (z) are -1/3 and 4.
Find the measures in the parallelogram4. Find AB and AC
Okay, here we have this:
Considering that in a parallelogram the opposite sides are congruent, we obtain the following:
AB=CD
AB=9 units
AC=BD
AC=4 units
Simplify the following: (4x + 3) -2(4x - 7) - 3(x +7)
Simplify: (4x + 3) -2(4x - 7) - 3(x +7)
Explanation:
[tex]\begin{gathered} (4x+3)-2(4x-7)-3(x+7) \\ =4x+3-8x+14-3x-21 \\ =4x-11x+17-21 \\ =-7x-4 \end{gathered}[/tex]Final answer: -7x-4 is required simplify form .
Determine a third pair of congruent parts to establish congruence between the triangles. Give the congruence postulate involved
In this problem, we have that
mYO ≅ XO
The third pair of congruent parts is
m by vertical angles
therefore
triangle YOT ≅ triangle XOB ----> by ASA congruence postulate
A data set includes weights of garbage discarded in one week from 62 different households. The paired weights of paper and glass were used to obtain the results shown to the right. Is there sufficient evidence to support the claim that there is a linear correlation between weights of discarded paper and glass? Use a significance level of α=0.05. correlation matrix: Variables Paper Glass Paper 1 0.1983 Glass 0.1983
There is not enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.
Given,
A data set includes weights of garbage discarded in one week from 62 different households.
significance level of α=0.05.
Now, According to the question:
The correlation matrix provided is:
Variables Paper Glass
Paper 1 0.1853
Glass 0.1853 1
The hypothesis for the test is:
H₀: ρ = 0 vs. H₀: ρ ≠ 0
The test statistic is:
r = 0.1983 ≈ 0.198
As the alternate hypothesis does not specifies the direction of the test, the test is two tailed.
The critical value for the two-tailed test is:
[tex]r_{alpha}/2, (n -2) = r_{0.005}/2 ,(62-2) = 0.250[/tex]
The conclusion is:
Because the absolute value of the test statistic is less than the positive critical value, there is not enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.
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r is the midpoint of op and qr is perpendicular to op in the diagram below find the the length of qr
Given:
OP = 20 in
QP = 26 in
Since R is the midpoint of OP, then, OR = RP
Thus
[tex]OR=RP=\frac{OP}{2}=\frac{20}{2}=10\text{ in}[/tex]To find the length of QR, use pythagoras theorem below:
[tex]\begin{gathered} a^2+b^2=c^2 \\ \\ RP^2+QR^2=PQ^2 \end{gathered}[/tex]Input values into the formula:
[tex]10^2+QR^2=26^2[/tex]Subtract 10² from both sides:
[tex]\begin{gathered} 10^2-10^2+QR^2=26^2-10^2 \\ \\ QR^2=26^2-10^2 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{QR^2}=\sqrt[]{26^2-10^2} \\ \\ QR=\sqrt[]{676-100} \\ \\ QR=\sqrt[]{576} \\ \\ QR=24 \end{gathered}[/tex]Therefore, the length of QR is 24 in
HELP PLEASEEEEEEEE!!!
The rational number is -91/100 or -0.91.
What is Rational number?Any number of the form p/q, where p and q are integers and q is not equal to 0, is a rational number. The letter q stands for the set of rational numbers.
The word "ratio" is where the word "rational" first appeared. Rational numbers are therefore closely tied to the idea of fractions, which stand for ratios. In other terms, a number is a rational number if it can be written as a fraction in which the numerator and denominator are both integers.
Given:
We have to find the rational number between -0.45 and -0.46
Now, make both decimal into fraction
-0.45 and -0.46
-45/100 and -46/100
Now, multiply 2
-45/100 x 2/2 and -46/100 x 2/2
-90/100 and - 92/100
Hence, the rational number is -91/100 or -0.91.
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The rational number is -91/100 or -0.91.
What is Rational number?Any number of the form p/q, where p and q are integers and q is not equal to 0, is a rational number. The letter q stands for the set of rational numbers.
The word "ratio" is where the word "rational" first appeared. Rational numbers are therefore closely tied to the idea of fractions, which stand for ratios. In other terms, a number is a rational number if it can be written as a fraction in which the numerator and denominator are both integers.
Given:
We have to find the rational number between -0.45 and -0.46
Now, make both decimal into fraction
-0.45 and -0.46
-45/100 and -46/100
Now, multiply 2
-45/100 x 2/2 and -46/100 x 2/2
-90/100 and - 92/100
Hence, the rational number is -91/100 or -0.91.
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Find the degree measure of the central angle for sector C. (image attached)
We will determine the angle as follows:
We know that the whole circle contains 360°, so we determine the angle of 0.35 as follows:
[tex]C=\frac{0.35\ast360}{1}\Rightarrow C=126[/tex]So, the measure of the central angle for sector C is 126°.
i do not understand what i am getting wrong for the 3rd question
ANSWER:
-4.1201
SOLUTION
[tex]\log _b\frac{1}{4}=\log _b1-\log _b4[/tex]this is also equivalent to
[tex]\log _b\frac{1\times7}{4\times7}=\log _b\frac{7}{28}=\log _b7-\log _b28=5.7833-9.9034=-4.1201[/tex]Olivia goes out to lunch. The bill, before tax and tip, was $13.90. A sales tax of 6% was added on. Olivia tipped 23% on the amount after the sales tax was added. How much was the sales tax? Round to the nearest cent.
According to the information given in the exercise, the bill before the tax and tip was $13.90 and the sales tax of 6% was added to that amount.
By definition, you can write 6% as a Decimal number by dividing it by 100. Then, this is:
[tex]\frac{6}{100}=0.06[/tex]Let be "t" the amount (in dollars) of the sales tax.
To find the value of "t", you can set up the following equation:
[tex]t=(13.90)(0.06)[/tex]Finally, evaluating, you get that this is:
[tex]t=0.834[/tex]Rounded to the nearest cent, this is:
[tex]t\approx0.83[/tex]The answer is: $0.83
solve the inequality for h. h-8> 4h+5. write the answer in simplest form
Subtract '4h' from both RHS (Right-Hand side) and LHS of the inequality (Left-Hand side).
[tex]\begin{gathered} h-8-4h>4h+5-4h \\ (h-4h)-8>5+(4h-4h) \\ -3h>5 \end{gathered}[/tex]Add '8' on both LHS and RHS of the above expression.
[tex]undefined[/tex]Divide both RHS and LHS of the above expression with '-3'. Whenever an inequality is divide or multiple with a negative value, the sign of the inequality shifts. Here, the above expression is dividing with '-3'. Thus, the > symbol shifts to < symbol.
[tex]\begin{gathered} \frac{-3h}{-3}<\frac{5}{-3} \\ h<\frac{-5}{3} \end{gathered}[/tex]Thus, the iniequality for h is h<-(5/3).
Mari pushed a cube- shaped box to explore force. She examined the attributes of the box. Does a face of her box have a right angle? Explain
The face of a cuboid box have 4 right angles.
What is mean by Cuboid?
A cuboid is the solid shape or three-dimensional shape. A convex polyhedron which is bounded by six rectangular faces with eight vertices and twelve edges is called cuboid.
Given that;
Mari pushed a cube- shaped box to explore force.
And, She examined the attributes of the box.
Now,
In the cube shape, faces are all squares.
And, A square is a quadrilateral in which all angles are 90 degree.
Thus, The face of a cuboid box have 4 right angles.
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Pep Boys Automotive paid $208.50 for a pickup truck bed liner. The original selling price was $291.90, but this was marked down 35%. If operating expenses are 28% of the cost, find the absolute loss
Step 1: State the given in the question
THe following were given:
[tex]\begin{gathered} \text{Amount Paid (}A_{\text{paid}})=208.50 \\ (Originalsellingprice)SP_{ORIGINAL}=291.90 \\ \text{Marked Percentage=35\%} \\ \text{Operating expenses=28\%} \end{gathered}[/tex]Step 2: State what is to be found
We are to find the absolute loss
Step 3: Calculate the selling price
Please note that the selling price is the marked down price
The marked down price would be
[tex]\begin{gathered} P_{\text{MARKED DOWN}}=(100-35)\text{ \% of original selling price} \\ P_{\text{MARKED DOWN}}=65\text{ \% of }SP_{ORIGINAL} \\ P_{\text{MARKED DOWN}}=\frac{65}{100}\times291.90=189.74 \end{gathered}[/tex]The selling price is the marked down price which is $189.74
Step 4: Calcualte the operating expenses
Please note that the cost price is amount paid. Therefore, the operating expenses would be as calculated below:
[tex]\begin{gathered} E_{\text{OPEARATING}}=28\text{ \% of Amount Paid} \\ E_{\text{OPERATING}}=28\text{ \% of }A_{\text{paid}}=\frac{28}{100}\times208.50 \\ E_{\text{OPERATING}}=0.28\times208.50=58.38 \end{gathered}[/tex]Hence, the operating expenses is $58.38
Step 5: Calculate the total cost price
The total cost price is the addition of the cost price and the operating expenses. This is as calculated below:
[tex]\begin{gathered} C_{\text{TOTAL COST PRICE}}=E_{OPERATING}+A_{PAID} \\ C_{\text{TOTAL COST PRICE}}=58.38+208.50=266.88 \end{gathered}[/tex]Hence, the total cost price is $266.88
Step 6: Calculate the absolute loss
The absolute loss is the difference between the total cost price and the marked down price (or the actual selling price). This is as calculated below:
[tex]\begin{gathered} L_{\text{ABSOLUTE LOSS}}=C_{TOTAL\text{ COST PRICE}}-P_{MARKED\text{ DOWN}} \\ L_{\text{ABSOLUTE LOSS}}=266.88-189.74=77.14 \end{gathered}[/tex]Hence, the absolute loss is $77.14
what is the solution set for the inequality
A. x ≤ -5
B. x ≤ 5
C. x ≤ 1
d. x ≤ -14
The solution set to the inequality, 4x + 12 ≤ -8, is determined as: A. x ≤ -5.
How to Find the Solution Set of an Inequality?The solution set is the value of x that would make an inequality statement true. To find the value of x, solve as you would solve a normal equation.
Using the key to the given model in the diagram, we can write the inequality as follows:
On the left, we would have, 4x + 12.
On the right, we would have, -8.
The inequality would be expressed as:
4x + 12 ≤ -8
Solve for x
4x + 12 - 12 ≤ -8 - 12 [subtraction property of equality]
4x ≤ -20
4x/4 ≤ -20/4
x ≤ -5
The solution set is: A. x ≤ -5.
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In 1980 approximately 4,825 million metric tons of carbon dioxide emissions were recorded for the United States. That number rose to approximately 6,000 million metric tons in the year 2005. Here you have measurements of carbon dioxide emissions for two moments in time. If you treat this information as two ordered pairs (x, y), you can use those two points to create a linear equation that helps you make predictions about the future of carbon dioxide emissions!A) Organize the measurements into ordered pairs. B) Find the slope,C) Set up an equation in point-slope form,D) Show the equation in slope-intercept form,E) Predict emissions for the year 2020,
ANSWER and EXPLANATION
A) To organize the measurements in ordered pairs implies that we want to put them in the form:
[tex](x_1,y_1);(x_2,y_2)[/tex]Therefore, the measurements in ordered pairs are:
[tex]\begin{gathered} (1980,4825) \\ (2005,6000) \end{gathered}[/tex]Note: 4825 and 6000 are in millions (10⁶) of metric tons
B) To find the slope, apply the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Therefore, the slope is:
[tex]\begin{gathered} m=\frac{6000-4825}{2005-1980} \\ m=\frac{1175}{25} \\ m=47\text{ million metric tons per year} \end{gathered}[/tex]C) To find the in point-slope form, we apply the formula:
[tex]y-y_1=m(x-x_1)_{}[/tex]Therefore, we have:
[tex]y-4825=47(x-1980)[/tex]Note: the unit is in million metric tons
D) To show the equation in point-slope form, we have to put it in the form:
[tex]y=mx+b[/tex]To do that, simplify the point-slope form of the equation:
[tex]\begin{gathered} y-4825=47(x-1980) \\ y=47x-93060+4825 \\ y=47x-88235 \end{gathered}[/tex]E) To predict the emissions for the year 2020, substitute 2020 for x in the equation above:
[tex]\begin{gathered} y=47(2020)-88235 \\ y=94940-88235 \\ y=6705\text{ million metric tons} \end{gathered}[/tex]That is the prediction for the year 2020.
name each angle pair as corresponding, alternate interior, alternate exterior, consecutive interior angle, or no relationship. identify the transversal that connects each angle pair.
Round to the nearest thousand.52.60552,605 rounded to the nearest thousand is
A bag contains 8 red marbles, 7 blue marbles and 6 green marbles. If three marbles are drawn out of the bag without replacement, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be red?
SOLUTION
Given the question, the following are the solution steps to answer the question.
STEP 1: Write the formula for probability
[tex]Probability=\frac{number\text{ of required outcomes}}{number\text{ of total possible outcomes}}[/tex]STEP 2: Write the outcomes of the events
[tex]\begin{gathered} number\text{ of red marbles}\Rightarrow n(red)\Rightarrow8 \\ number\text{ of blue marbles}\Rightarrow n(blue)\Rightarrow7 \\ number\text{ of green marbles}\Rightarrow n(green)\Rightarrow6 \\ number\text{ of total marbles}\Rightarrow n(total)\Rightarrow21 \end{gathered}[/tex]STEP 3: Write the formula for getting the probability that all three marbles drawn will be red
[tex]Pr(Red\text{ and Red and Red\rparen}\Rightarrow Pr(red)\times Pr(red)\times Pr(red)[/tex]STEP 4: Calculate the probability
[tex]\begin{gathered} Pr(all\text{ three are reds\rparen}\Rightarrow\frac{8}{21}\times\frac{7}{20}\times\frac{6}{19} \\ =\frac{336}{7980}=0.042105263 \\ To\text{ percentage will be to multiply by 100} \\ 4.210526316\% \\ To\text{ the nearest tenth will be:} \\ \approx4.2\% \end{gathered}[/tex]Hence, the probability, to the nearest 10th of a percent, that all three marbles drawn will be red is 4.2%
A chef is going to use a mixture of two brands of italian dressing. the first brand contains 7% vinegar and the second brand contains 12% vinegar. the chef wants to make 280 milliliters of a dressing that is 9% vinegar. how much of each brand should she use
We know that
• The first brand contains 7% vinegar.
,• The second brand contains 12% vinegar.
,• The chef wants 280 milliliters with 9% vinegar.
Using the given information, we can express the following equation.
[tex]0.07x+0.12(280-x)=0.09(280)[/tex]Notice that 0.07x represents the first brand, 0.12(280-x) represents the second brand, and 0.08(280) represents the final product the chef wants to make.
Let's solve for x.
[tex]\begin{gathered} 0.07x+33.6-0.12x=25.2 \\ -0.05x=25.2-33.6 \\ -0.05x=-8.4 \\ x=\frac{-8.4}{-0.05} \\ x=168 \end{gathered}[/tex]Therefore, the chef needs 168 of the first brand and 112 of the second brand.Notice that 280-168 = 112.
lana 15:02If two events A and B are independent and you know that P(A) = 0.3, what is the value of P(A|B)?
Since the events are independent, we have the following property:
[tex]P(A)=P(A|B)[/tex]That is, the probability of A is the same as the probability of A given B (since the events are independent, event B does not affect event A).
So, if P(A) = 0.3, therefore P(A|B) is also equal to 0.3.
I need help with this problem. Quick answer is fine
[tex]a^{\frac{-m}{n}}=\frac{1}{a\frac{m}{n}}=\frac{1}{\sqrt[n]{a^m}}[/tex]
Nikki and four friends had lunch at their favorite restaurant. The total bill was $29.00, and they wanted to leave a 15% tip. Which amount of money is closest to the 15% tip? A $3.00 B $3.50C $4.00D $4.50
Total bill = $29
Tip left = 15%
The valu of the tip = 15% of $29
[tex]\begin{gathered} \frac{15}{100}\text{ x 29} \\ \\ =\text{ \$4.35} \end{gathered}[/tex]The value of the tip = $4.35
Let us consider the options given
$4.35 - $3 = $1.35
$4.35 - $3.5 = $0.85
$4.35 - $4 = $0.35
$4.5 - $4.35 = $0.15
Looking t the deviation from the real value of the tip ($4.35), the least deviation is $0.15. Hence, we can conclude that $4.5 is the closest to the tip.
The answer is option D ($4.50)
Solve and graph on a number line. 2(x-1) 4 or 2 (x-1)>4
The given inequality is:
2 (x - 1
