Eriq, a chemist, is running tests with four unknown elements. He has found that they all bond the same way, so he knows that they are in the same group on the periodic table of elements.

The table shows other properties that Eriq observed.These four elements are most likely in group

15.
16.
17.
18.

The given statement exists as false. The temperature at which a liquid's vapor pressure equals the pressure of the gas above it exists comprehended as the boiling point of the liquid.

The temperature at which a liquid's vapor pressure equals the pressure around it and the liquid transforms into a vapor is known as the boiling point of a substance. A liquid's boiling point varies depending on the atmospheric pressure in the area.

The temperature at which a liquid's vapor pressure equals the pressure of the gas above it exists comprehended as the boiling point of the liquid. The temperature at which a liquid's vapor pressure equals one atmosphere is considered the liquid's typical boiling point (760 torr).

The element with the lowest temperature at which an element would smolder is helium, and the element with the highest temperature is tungsten. The melting point is measured in degrees Celsius (C).

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Glyceryl tributyrate will react with 3 mol of water and form a glycerol and 3 mol of carboxylic acid.

The volume of the standardized base used in the titration was 23.43 mL.

When performing titration, the volume of the standardized base titrant used in the burette is read first (this value doesn't have to be 0, as it depends on the titrator filling the burette). In this case, this value is 2.75 mL.

During the titration, the titrant level in the burette goes down, and when the endpoint is reached, this level can be read. In this experiment, the final volume is 26.18 mL.

The volume used in the titration is obtained by subtracting the starting value from the final volume:

26.18 mL - 2.75 mL = 23.43 mL

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Melting and boiling points of a pure liquid are intensive physical quantities whereas mass and volume are fundamental physical quantities.

The typical definition of the melting point is the temperature at which a substance transforms from a solid to a liquid.

The temperature at which a liquid under atmospheric pressure changes from a solid to a liquid is known as its melting point. Here, both the liquid and solid phases coexist in equal amounts. The substance's melting point is listed under standard pressure, although it varies with pressure as well.

The temperature at which a liquid's vapour pressure equals the surrounding atmosphere is known as the boiling point of the liquid. This temperature causes the liquid to become a vapour.

The boiling point of the liquid is influenced by the atmospheric pressure. When a liquid is at high pressure, its boiling point is higher than when it is at atmospheric pressure. Different liquids have variable boiling points at a specific pressure. The standard boiling point of a liquid was established by IUPAC in 1982 as the temperature at which a liquid starts to boil at a pressure of one bar.

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In this question, we need to determine what will be the nuclear equation for the Beta decay of Lead - 210.

Beta decay is a type of radioactive decay in which we will have either a neutron becoming a proton, this will be called Beta-minus decay or a proton becoming a neutron, this will be called a Beta-plus decay

In the case of Pb-210, we will have a Beta-minus decay, and one neutron will become a proton:

210/82 Pb ---> 210/83 Bi + electron

Lead - 210 will become Bismuth - 210

The element that forms a yellowish gas, often used as a disinfectant, and forms a nasty gas with ammonia would be chlorine.

Chlorine is an element with a valence electron of 7. It forms a greenish-yellow gas that is 2 to 5 times denser than air. The element belongs to a group of elements on the periodic table known as halogen.

Chlorine is used as a disinfectant. It is utilized in the treatment of water for domestic use. It has the ability to kill harmful microbes off surfaces. It is also used in the manufacturing of textile products, paper bleaching, and several other industrial uses.

Chemically, chlorine is highly reactive. It reacts with ammonia to form a toxic gas known as chloramine. The gas affects the throat, lungs, and eyes of humans and in high doses, can cause outright death.

Thus, the element in question that form yellowish gas, is used as a disinfectant, and forms nasty gas with ammonia would be chlorine.

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The reaction is exothermic as it involves a bond-forming process

when the liquids are mixed temperature of the reaction between the mixture increases.

There are small and large clusters in the mixture

The exothermic reaction involves the formation of new bonds which involves a combination of the bonds to form a new compound in our case water has hydroxy ions that bond with those of ethanol.

Mixing ethanol and water in volumetric glassware reduces the volume and increases the temperature.

The numerical example

Fill two 250 mL graduated cylinders to the line with water and ethanol pure temperature sensor shows both at room temperature. Next, move the temperature probe to an empty 500 mL graduated cylinder and pour the contents of the two smaller cylinders simultaneously and mix well.

The temperature of the mixture will rise by about 8 °C and the volume will decrease to 480 this indicates that the reaction is exothermic as the temperature rises and volume reduces

yes, clusters are present as ethanol falls between the spaces left by water as it has small molecules than that of water.

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The percent composition of (NH₄)₂CO₃ is 99.999 % ≈ 100 %.

To calculate percent composition of the elements in a compound,

the molar mass of element is divided by the molar mass of the compound and then, it is multiplied by 100.

We know that,

Molar mass of (NH₄)₂CO₃ is 96.086 g/mol.

Molar mass of each element of compound is-

Nitrogen = 2 × 14.007 g/mol = 28.014 g/mol

Hydrogen = 8 × 1.008 g/mol = 8.064 g/mol

Carbon = 1 × 12.011 g/mol = 12.011 g/mol

Oxygen = 3 × 15.999 g/mol = 47.997 g/mol

Now,

We will calculate the percent composition -

% composition of nitrogen = 28.014 g/mol × 100 = 29.155%

                                               96.086 g/mol

% composition of hydrogen = 8.064 g/mol × 100 = 8.392%

                                                96.086 g/mol

% composition of carbon = 12.011 g/mol × 100 = 12.500%

                                            96.086 g/mol

% composition of oxygen = 47.997 g/mol × 100 = 49.952 %

                                             96.086 g/mol

We will add the percentage to calculate % composition of (NH₄)₂CO₃ -

29.155 % + 8.392 % + 12.500 % + 49.952 % = 99.999% ≈ 100 %

Therefore, % composition is 99.999 % ≈ 100 %

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The electron configuration for a neutral atom of chlorine is 1s² 2s² 2p⁶ 3s² 3p⁵.

Atomic number of Chlorine  is 17. to write the electronic configuration of chlorine we need to know the number of electrons in chlorine atom. the atomic number of chlorine is 17 therefore there are 17 electrons. the first two electron enter in 1s since s can hold only 2 electrons then next two electron will enter in 2s . the next six electrons will enter in 2p since p can hold six electrons . and next two electron in 3s now reaming 5 will enter in 3p. therefore the  electron configuration for a neutral atom of chlorine is 1s² 2s² 2p⁶ 3s² 3p⁵.

Thus, the  electron configuration for a neutral atom of chlorine is 1s² 2s² 2p⁶ 3s² 3p⁵

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Applying too much sample to the TLC (thin layer chromatography) plate results in reduced separation between the spots.

When performing thin layer chromatography it is necessary to not apply too much of the sample onto the plate. Once the elution solvent starts climbing up the plate, all the components of the sample will be separated along the plate according to the intensity of their interactions with the plate and the solvent (quantified as the Rf value - retention factor).

In a sample that is too concentrated or too much of it has been applied, the separation will be negatively affected because the huge spots originating from the sample components will overlap, making Rf determination difficult, if not impossible.  

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After calculating the percent error and rounding it to two decimal places, the result obtained is 18.20%.

To calculate the percent error we need to calculate the absolute error first. This is done by subtracting the actual value (1000 mg) from the measured value (0.818 g = 818 mg):

818 mg - 1000 mg = -182 mg

We then divide the absolute value of that difference (182 mg) by the actual value (1000 mg).

182 mg / 1000 mg = 0.182

This result is then multiplied by 100 percent and rounded to two decimal places:

0.182 * 100% = 18.20%

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The volume at which the pH can be used to determine the pKa of the acid is 7.40 ml if the equivalence point occurred at 14.81 ml of added sodium hydroxide.

The weak acid and the conjugate base will have an equal number of moles at the half-equivalence point as the number of moles of sodium hydroxide will neutralize half of the number of moles of the weak acid which will then produce more conjugate base.

The chemical reaction can be given as;

HA = (H^+) + A^-

Calculation of pKa:

pH = pKa + log[A^-]/[HA]

At half equivalence point, pH = pKa

As, ka = 10^-pka

Therefore, ka = 10^-pH

Volume is given which is 14.81 ml. Therefore, the volume that is used to determine the pKa of the acid can be calculated as follows;

14.81/2 = 7.40 ml

Therefore the volume used to determine the pKa of the acid is calculated to be 7.40 ml

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Answer:

1H2+1O2—>H2O2

Explanation:

Use the integer+1

The classification of the given processes as either physical changes (PC), chemical changes (CC), physical properties (PP), and chemical properties (CP): is as follows:

Physical changes are changes that occur in a substance that are easily reversible and only affect the physical properties of that substance.

In physical changes, no new substances are formed.

Some physical properties that may change in physical changes are color, taste, volume, mass, physical state, etc.

Chemical changes are changes that occur in a substance that are not easily reversible and which affect the chemical properties of that substance.

In chemical changes, new substances are formed.

Some chemical properties that may change in physical changes are oxidation state, combustibility, etc.

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Magnetic property of iron will help in seperating iron from rest of the materials.

Iron is a metal and have magnetic property. Magnetic property is property of metal in which metal has the attraction power to attract other metal. Iron is ferromagnetic but it requires certain temperature and certain conditions. It occurs below 770°C, which is curie temperature.

There are 5 magnetic properties

 types of magnetic materials

Diamagnetic Material,Paramagnetic Materials,Ferromagnetic Materials,Antiferromagnetic Materials,Ferrimagnetic Materials.

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The final pressure of the ideal gas is 23.47 atm.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

V1 = 120 L

P1 = 18 atm

T1 = 310 K

V2 = 95 L

T2 = 320 K

When the initial and final gas is the same, we can use the ratio of the ideal gas as

(P2 . V2) / (P1 . V1) = T2 / T1

(P2 . 95) / (18 . 120) = 320 / 310

P2 = 23.47 atm

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The empirical formula of the compound is C3H4O as the mole ratio is 3 : 4 : 1

1) Mass of carbon (C) in 3.190 g of carbon dioxide (CO₂)

atomic mass of C: 12.0107 g/mol

molar mass of CO₂: 44.01 g/mol

Setting up proportion as:

12.0107 g of C / 44.01 g of CO₂ = x / 3.190 g of CO₂

x  = 0.87057 g of C

2) Mass of hydrogen (H) in 0.9360 g of water (H₂O)

atomic mass of H: 1.00784 g/mol

molar mass of H₂O: 18.01528 g/mol

Setting up proportion as:

2 × 1.00784 g of H / 18.01528 g of H₂O = x / 0.9360 g of H₂O

x = 0.10472 g of H

3) Mass of oxygen (O) in 1.0857 g of pure sample

Mass of O = mass of pure sample - mass of C - mass of H

Mass of O  = 0.38397 g O ≈ 0.3840 g

4) Mole calculations

C:  0.87057  g / 12.0107 g/mol = 0.07248 mol

H: 0.10472 g / 1.00784 g/mol = 0.10390 mol

O: 0.3840 g / 15.999 g/mol = 0.02400 mol

So, to find empirical formula the mole ratios are:

C: 3

H:  4

O:  1

Thus the mole ratio is 3 : 4 : 1, and the empirical formula is: C3 H4 O

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Answer:

The attraction is a hydrogen bonding.

Explanation:

Based on the information on intermolecular forces, when a Hydrogen is specifically bonded with a Nitrogen, Oxygen or Fluorine, their bonding is called a hydrogen bond.

The list that consists of elements that have the most similar chemical properties is caesium, sodium and potassium (option D).

Periodic table is the tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).

The periodic table is made up of chemical elements arranged in groups and periods. Chemical elements in the same group possess similar chemical properties.

According to this question, the following elements are in the same group 1:

Therefore, Cs, K and Na will have the most similar chemical properties because they belong to the same group.

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The [tex]K_{a}[/tex] of phenylacetic acid is  4.76008×[tex]10^{-5}[/tex], when the pH of the solution is 2.62.

As we know,

pH = -log[[tex]H^{+}[/tex]]

[[tex]H^{+}[/tex]] = [tex]10^{-pH}[/tex]

[[tex]H^{+}[/tex]] = [tex]10^{-2.62}[/tex]

[[tex]H^{+}[/tex]] = 2.39×[tex]10^{-3}[/tex]

Also to find [tex]K_{a}[/tex] of phenylacetic acid we know another relation as:

[[tex]H^{+}[/tex]] = [tex]\sqrt{K_{a} .c}[/tex]

2.39×[tex]10^{-3}[/tex] =  [tex]\sqrt{K_{a} .0.12}[/tex]

[tex]K_{a}[/tex] = 4.76008×[tex]10^{-5}[/tex]

Therefore, the [tex]K_{a}[/tex] of phenylacetic acid is  4.76008×[tex]10^{-5}[/tex], when the pH of the solution is 2.62.

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Answer:

145,000 meters

Explanation:

1 kilometer = 1000 meter

145 kilometer = 145 times 1000 meters

so:

145 × 1000 = 145,000 meters

Given the symbol Cl-37, the element is Cl, but there is no information about its charge. When this is like that, it is implicit it is an atom, that is, it is neutral, its charge is 0.

The number indicates is the mass number, so its mass is 37.

So, mass is 37 and charge is 0.

1. The number of moles of H in 5 moles of C₂H₄O is 20 moles

2. The number of atoms of H in 5 moles of C₂H₄O is 1.20×10²⁵ atoms

1. How to determine the number of mole

The number of moles of H in 5 moles of C₂H₄O can be obtained as follow:

1 mole of C₂H₄O contains 4 moles of H

Therefore,

5 moles of C₂H₄O will contain = 5 × 4 = 20 moles of H

Thus, the number of moles of H is 20 moles

2. How to determine the number of atoms

We know from the calculation made above that 20 moles of H is present in 5 moles of C₂H₄O. Thus, we can obtain the number of atoms as follow:

From Avogadro's hypothesis,

1 mole of H = 6.02×10²³ atoms

Therefore,

20 moles of H = (20 moles × 6.02×10²³ atoms) / 1 mole

20 moles of H = 1.20×10²⁵ atoms

Thus, the number of atoms of H present is 1.20×10²⁵ atoms

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Answer: The mass percent of copper in copper chloride is 47.23 %.

What is it you are making exactly? It is going to be for a recipe of some sort, like a beverage or food? If you could sort of expand on what the purpose is for, I think I may be able to help you find the best method for the extraction.

The volume of Concentrated nitric acid (16 m) required to react with 0.41 g of cu(s) if you use 1.86 ml (an excess) of hno3, what volume of 5.0m naoh will need to neutralize completely dissolved is 0.704 ml

4 HNO3(l) + Cu(s) ==> Cu(NO3)2(s and aq) + 2 NO2(g) + 2 H2O(l)

According to net Ionic equation 4 moles of HNO3 reacts with 1 mole of Cu(s)

moles of Cu in 0.36 gm of Cu = 0.36/63.5

moles = molarity*volume(L)

moles of Cu*4 =moles of HNO3

Let volume of HNO3 be x

0.36/63.5*4 = 16*x

x = 1.42 ml

c. Volume of HNO3 added = 1.64 ml

excess of HNO3 = 1.64-1.42

= 0.22 ml

Normality of NaOH and HNO3 is same i.e. equal moles of NaOH and HNO3 neutralises itself

molarity of NaOH = 5 moles/litre

moles of NaOH = Moles Of HNO3

5*x = 16*0.22

x = 0.704 ml

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If mercury (ii) oxide is heated and decomposes, the product of the reaction be 4 Hg.

Mercury is a chemical element with the atomic number 80 and the symbol Hg. Formerly known as hydrargyrum and also known as quicksilver, In order to fragment anything into smaller pieces or to break it into smaller pieces, mercury is used in thermometers, barometers, manometers, sphygmomanometers, float valves, mercury switches, mercury relays, fluorescent lights, and other devices: Methane and carbon dioxide are produced when microbes break down organic waste. staying fresh while decomposes The process of recycling nutrients that an organism (plant or animal) has utilized to develop its body begins with decomposes. It is the process by which the decomposing dead tissues transform into more basic organic forms. For a large number of the species at the base of ecosystems, these serve as a food supply.

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Answer:

1 ) They are wealthy in gases hydrogen and helium. 2 ) They are very hot and dense . 3 ) They have a solid gravitational pull.

Explanation:

Space where huge size of gaseous and dust cloud is present is called nebula. It is mainly made of hydrogen and helium. Nebula exist in the space which is between the stars and it is call as interstellar space.

Helix nebula is closest nebula which is near the earth. It’s distance from earth is about 700 light years.

Dark nebulae are very dense as well as cold. Nebula can be divided into dark nebula and bright nebula. The gas which is present between the stars is always combine with solid grains cosmic dust.

Nebulae contribute more to stellar creation than other areas of the universe for the following three reasons:

So, the correct options are A, D and E.

Huge clouds of gas and dust known as nebulae are found in space and are made up of heavier elements in the form of dust particles as well as ionized gases like hydrogen and helium.

Because the gases and dust within them have the potential to collapse under the influence of gravity and form new celestial objects, they are frequently the birthplace of stars and planetary systems. They are rich in hydrogen and helium. They have a strong gravitational pull and are hot and dense.

Hence, the correct options are A, D and E.

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Select all the correct answers. what are three reasons why nebulae contribute more to stellar formation than other regions of the universe?

Answer:

CH3

Explanation:

Hope this helps :)