A train leaves a station and travels north at a speed of 175 km/h. Two hours later, a second train leaves on a parallel track and travels north at 225 km/h. How far from the station will theymeet?The trains will meet (?) away from the station(Type an integer or a decimal.)

Answers

Answer 1

Given,

The speed of first train is 175km/h.

The speed of second train is 225 km/h.

Consider, the time taken by first train to meet is x h.

The time taken by the second train to meet is (x-2) h.

The distance is calculated as,

[tex]\text{Distance}=\text{speed}\times time[/tex]

At the meeting point the distance covered by both train is same,

So, taking the distance equation of both trains in equal,

[tex]\begin{gathered} 175\times x=225\times(x-2) \\ 175x=225x-450 \\ -50x=-450 \\ x=9 \end{gathered}[/tex]

The first train meet to second train after distance,

[tex]d=175\times9=1575\text{km}[/tex]

The second train meet to first train after distance,

[tex]d=225\times(9-2)=1575\text{ km}[/tex]

Hence, both train meet after 1575 km from the station.


Related Questions

it says i need to find the shortest distance between the point and the line for geometry honors, how would i figure it out

Answers

The given line equation is,

[tex]3x-y=-6[/tex]

The given point is ,

[tex](5,1)[/tex]

The graph will look like this,

let us rewrite the line equtaion as ,

[tex]3x-y+6=0[/tex]

now, let us compare with the general equation of line,

[tex]Ax+By+C=0[/tex]

then, A= 3,B=-1 and c= 6.

let us use the formula,

[tex]\begin{gathered} d=\frac{|Ax+By+c|}{\sqrt[]{A^2+B^2}} \\ d=\frac{|3\times5+(-1)\times1+6|}{\sqrt[\square]{3^2+(-1)^2}} \\ d=\frac{|15-1+6|}{\sqrt[\square]{9+1}} \\ d=\frac{20}{\sqrt[\square]{10}} \\ d=6.32 \end{gathered}[/tex]

The shortest distance is 6.32 .

which number is divisible by "644532"

Answers

Answer:

2

Step-by-step explanation: 2 can be divided by 644532

Find the total amount in the compound interest account $2650 is compounded annually at a rate of 11% for 1 year

Answers

The compound interest formula is:

[tex]A\text{ = P}(1+i)^t[/tex]

where:

A is the final amount including the principal

P is the principal amount

i is the interest rate (as a decimal)

t is time in years

Replacing with P = $2650, i = 0.11, and t = 1, we get:

A = 2650*(1 + 0.11)

A = 2650*1.11

A = $2941.5

A survey stopped men and women at random to ask them where they purchased groceries, at a local grocery store or online.Grocery OptionsStoreOnlineTotalWomen231235Men221537Total452772What percent of the people surveyed shop at a local grocery store? Round your answer to the nearest whole number percent

Answers

Given:

A survey stopped men and women at random to ask them where they purchased groceries, at a local grocery store or online. Grocery Options

Store Online Total

Women 23 12 35

Men 22 15 37

Total 45 27 72

Required:

To find the percentage of the people surveyed shop at a local grocery store.

Explanation:

The total number of people is 75.

And the total number of people surveyed shop at a local grocery store is 45.

Now the percentage of the people surveyed shop at a local grocery store is,

[tex]=\frac{45}{72}\times100[/tex][tex]\begin{gathered} =62.5\% \\ \\ \approx63\% \end{gathered}[/tex]

Final Answer:

63% of the people surveyed shop at a local grocery store.

18. Yvonne paid $18.72 for 8 gallons of gas. How much would she have spent on gas if she had only needed 5 gallons of gas?

Answers

As given by the question

There are given that $18.72 for 8 gallons of gas.

Now,

Since, $18.72 for 8 gallons of gas;

Then,

First calculate the price of one-gallon gas

So,

[tex]\frac{18.72}{8}=2.34[/tex]

The price og one g

Exercise 2 Find a formula for Y in terms of X

Answers

Given:

y is inversely proportional to square of x.

The equation is written as,

[tex]\begin{gathered} y\propto\frac{1}{x^2} \\ y=\frac{c}{x^2}\ldots\ldots\ldots c\text{ is constant} \end{gathered}[/tex]

Also y = 0.25 when x = 5.

[tex]\begin{gathered} y=\frac{c}{x^2} \\ 0.25=\frac{c}{5^2} \\ 25\times0.25=c \\ c=\frac{25}{4} \end{gathered}[/tex]

So, the equation of y interms of x is,

[tex]y=\frac{25}{4x^2}[/tex]

When x increases,

[tex]\begin{gathered} \lim _{x\to\infty}y=\lim _{x\to\infty}(\frac{25}{4x^2}) \\ =\frac{25}{4}\lim _{x\to\infty}(\frac{1}{x^2}) \\ =0 \end{gathered}[/tex]

Hence, the value of x increases then y decreases.

The odds in favor of a horse winning a race are 7:4. Find the probability that the horse will win the race.A. 7/12B. 4/7C. 7/11D. 4/11

Answers

We have a reason for 7:4,

i.e. the total probability of winning is 7+4=11

If the horse has a probability of winning of 7 between 11

We can say that the Pw of the horse is as follows

[tex]\frac{7}{11}[/tex]

The answer is the option C

tell whether you can prove that each quadrilateral is a parallelogram. Explain.

Answers

WE know that in any quadrilateral the interior sum of its angles is 360. The missing angle in this case is:

[tex]360-121-59-59=121[/tex]

Now, we also know that if the oposite angles in a quadrilateral are equal then the quadrilateral is a parallelogram.

Therefore the figure shown is a parallelogram.

Simplify the numerical expression (3^2 * 5^-1)^2

Answers

Simplify the numerical expression

[tex](3^2\cdot5^{-1})^{2}[/tex][tex]\begin{gathered} (9\cdot\frac{1}{5})^{2}= \\ (\frac{9}{5})^{2}= \\ \frac{81}{25} \end{gathered}[/tex]

A car used 15 gallons of gasoline when driven 315 miles. Based on this information, which expression should be used to determine the unit rate of miles per gallon of gasoline?

Answers

Given trhat a car used 15 gallons of gasoline to cover 315 miles.

The expression that will be used to determine the unit rate of miles per gallon of gasoline is:

[tex]\frac{315\text{ miles}}{15\text{ gallons}}[/tex]

ANSWER:

[tex]\frac{315\text{ miles}}{15\text{ gallons}}[/tex]

I need help with this practice problem solving It is trigonometry I will send another picture with the graph that is included in the problem, it asks to use the graph to solve

Answers

Given the function

[tex]f(x)=\sin (\pi x+\frac{\pi}{2})[/tex]

The graph of the function is as shown below:

A random variable X follows a normal distribution with a mean of 150 and a standard deviation of sigma. If we know that P(120 < X < 180) = 0.95, then, according to the 68-95-99.7 rule, the value of sigma is approximately:


a.
20


b.
15


c.
40


d.
30


e.
60

Answers

The value of sigma according to the 68-95-99.7 rule is 15.

What is the 68-95-99.7 rule?

This is the informal term that is used in statistics to remember the percentage of values that are in the interval of a distribution in statistics.

We have the mean = 150

the interval is given as  P(120 < X < 180)

based on this rule, 95 percent of the data lies in the u - 20 and u + 20 region

Such that we would have

u - 2α < x < u + 2α = 0.95

we have

u - 2α = 120

150 - 2α = 120

2α = 150 - 120

2α = 30

divide through by 2

α = 15

Sigma is given as 15

Read more on normal distribution here:

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Find the area of the triangle. 30 cm 15 cm cm2

Answers

Area of the triangle is 225 sq. cm.

Given:

The base of the triangle is, b = 30cm.

The height of the triangle is, h = 15cm.

The objective is to find the area of the triangle.

The formula to find the area of the triangle is,

[tex]A=\frac{1}{2}\times b\times h[/tex]

Now, substitute the given values in the above formula.

[tex]\begin{gathered} A=\frac{1}{2}\times30\times15 \\ A=225cm^2 \end{gathered}[/tex]

Hence, the area of the triangle is 225 sq. cm.

The cost of 5 gallons of ice cream has a varianceof 36 with a mean of 36 dollars during the summer.What is the probability that the samplean would differ from the true mean by more than 0.6 dollars if a sample of 107 5-gallon pails is randomly selected? Roundyour answer to four decimal places.

Answers

Given:

[tex]\begin{gathered} Variance=36 \\ mean=36 \end{gathered}[/tex]

To Determine: The samplean would differ from the true mean by more than 0.6 dollars

Solution

Please note that standard deviation is the square root of variance

[tex]\begin{gathered} SD=\sqrt{Variance} \\ SD=Standard-deviation \\ SD=\sqrt{36}=6 \end{gathered}[/tex][tex]\begin{gathered} S.E=\frac{SD}{\sqrt{n}} \\ S.E=Standard-Error \\ n=107 \\ S.E=\frac{6}{\sqrt{107}}=0.5800 \end{gathered}[/tex]

Please note that Z is the number of SE(standard error away from the mean. Therefore

[tex]\begin{gathered} Z=\frac{0.6}{0.5800} \\ Z=1.0345 \end{gathered}[/tex][tex]P(|Z|<1.0345)[/tex][tex]P(|Z|<1.0345)=1-P(Z<-1.0345)=1-0.1515=0.8485[/tex]

Hence the probability is 0.8485

Find the quotient.8 / (1 1/3) (Type a whole number or a fraction.)

Answers

In order to calculate the result of this division, let's first convert the mixed number 1 1/3 into a fraction:

[tex]1\frac{1}{3}=1+\frac{1}{3}=\frac{3}{3}+\frac{1}{3}=\frac{4}{3}[/tex]

Now, calculating the division, we have:

[tex]\frac{8}{\frac{4}{3}}=8\cdot\frac{3}{4}=2\cdot3=6[/tex]

So the result is 6.

Solve the inequality and graph the solution set.3 ≤ 4x + 1 < 9

Answers

Okay, here we have this:

Considering the provided inequality, we are going to solve it and graph the solution set, so we obtain the following:

3 ≤ 4x + 1 < 9

3 -1≤ 4x + 1 -1< 9-1

2 ≤ 4x < 8

2/4 ≤ 4x/4 < 8/4

1/2 ≤ x < 2

In interval notation the solution set will be: [1/2, 2)

And if we plot this solution interval we get:

Where the solution set will be the purple part.

A construction crew is lengthening a road. Let y represent the total length of the road (in miles). Let x represent the number of days the crew has worked. Suppose that x and y are related by the equation y=53 + 2x. Answer the questions below. Note that a change can be increased or a decrease. For an increase, use a positive number. For a decrease, use a negative number. What was the road’s length when the crew started working?What is the change per day in the road’s length?

Answers

Given the equation:

[tex]y=53+2x[/tex]

Where y represents the total length of the road (in miles), and x represents the number of days the crew has worked.

(a) What was the road’s length when the crew started working?

When the crew started working we have x = 0. Then:

[tex]\begin{gathered} y=53+2\cdot0 \\ \therefore y=53\text{ miles} \end{gathered}[/tex]

The road's length is 53 miles.

(b) What is the change per day in the road’s length?

The change per day in the road's length is 2 miles/day.

Find the area round to two decimal places as needed

Answers

To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:

[tex]A=\frac{b\cdot h}{2}[/tex]

The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:

[tex]\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}[/tex]

The area of the triangle is 28 square miles.

calculate the slope of a line passing through the given points (5,-2) and (5,-3)

Answers

Given the points (5,-2) and (5,-3), we can find the slope of the line that passes through them with the following formula:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{-3-(-2)}{5-5}=\frac{-1}{0} \end{gathered}[/tex]

since we have that the slope is not defined, the line that passes through the points (5,-2) and (5,-3) is the vertical line x=5

you have a table that shows a linear relationship, when can you read the value for b,in y = mx + rectly from the table without drawing a graph or doing any calculations? Complete the explanati there is a point ( (select) vy) in the table, then y = b because at the y-Intercept the value of x select) (select) 0 y

Answers

y=mx+b

Where:

m= slope

b= y-intercept

b= has coordinate points (0,y) where the line crosses the y-axis.

So:

If there is a point (0,y) in the table y=b because at the y-intercept the value of x is 0.

Rosa needs to build a wall. She has to start the wall with one postand then every 5.75 feet put another post. The wall will be166.75 feet long. How many posts will she need?

Answers

For every 5.75 feet, here is one post.

Determine the number of posts in a wall of 166.75 feet.

[tex]\begin{gathered} p=\frac{166.75}{5.75} \\ =29 \end{gathered}[/tex]

So 29 posts needed for the wall.

114. If plane X averages 800 mph and plane Y averages 400 mph, how manyhours will plane X travel before it overtakes plane Y if plane Y has a 2 hourand 30 minute head start?a.1b. 2c. 5d. 72

Answers

To determine the time taken for the plane X to travel:

If plane X averages 800 mph and plane Y averages 400 mph

Distance column is found by multiplying the rate

by time.

The time taken for plane Y to travel = 2hr 30 minutes = 2.5hrs head start

Be sure to distribute the 400(t +2.5)for Plane Y,

and Plane X to distribute 800t

As they cover the same distance

[tex]\begin{gathered} Dis\tan ce\text{ is equal ,} \\ 800t=400(t+2.5) \\ 800t=400t+1000 \\ 800t-400t=1000 \\ 400t=1000 \\ t=\frac{1000}{400} \\ t=2\frac{1}{2}hr \end{gathered}[/tex]

Therefore the plane X will travel for 2 1/2 hours

Hence the correct answer is Option B

Please tell me if these are correct if theyre not please help and tell me which ones are the right answers

Answers

Answer:

They're correct

Step-by-step explanation:

A teacher determines the linear equation y=12x + 40 best models the number of points a student should earn on a test, y, if the student studies for x hours. Which statement is true

Answers

Given the equation:

y = 12x + 40

Where x represents the number of hours and y represents the number of points the student should earn.

To find the correct statement substitute the number of hours and points given for x and y respectively. If the left hand side of the equation equals the right hand side then the statement is the true.

We have:

1. A student who studies for 3 hours should earn about 76 points.

x = 3

y = 76

Substitute 3 for x and 76 for y.

y = 12x + 40

76 = 12(3) + 40

76 = 36 + 40

76 = 76

This statement is true.

2.

Susan has a job selling cars, and earns 1.25% commission on the first $100,000 in sales,The commission increases to 4.95% on the next $200,000. Last month her total sales were$387,000. How much was her commission if she received 7.25% for any sales over $300,000

Answers

Solution:

Susan earns a commission based on car sales made.

Given:

Total sales made for the month = $387,000

Her commission is calculated based on levels and commision rate for each level.

On the first $100,000, she earns 1.25% commission.

Total sales at this level is $100,000

[tex]\begin{gathered} \text{Commision made on the first \$100,000 is;} \\ \frac{1.25}{100}\times100000=\text{ \$1,250} \\ =\text{ \$1,250} \end{gathered}[/tex]

On the next $200,000, she earns 4.95% commission.

Total sales at this level is $300,000

[tex]\begin{gathered} \text{Commision made on the next \$200,000 is;} \\ \frac{4.95}{100}\times200000=\text{ \$9,900} \\ =\text{ \$9,900} \end{gathered}[/tex]

On the next $87,000, total sales at this level is $387,000. She earns 7.25% commission for sales above $300,000.

[tex]\begin{gathered} \text{Commision made on the next \$87,000 is;} \\ \frac{7.25}{100}\times87000=\text{ \$6,}307.50 \\ =\text{ \$6,}307.50 \end{gathered}[/tex]

Therefore, Susan's total commission received for the month is;

[tex]\begin{gathered} \text{ \$1250 + \$9900 + \$6307.50} \\ =\text{ \$17,457.50} \end{gathered}[/tex]

Hence, her commission received in total for the sales made is $17,457.50

Sketch the graph of each line.

24)

y=3/5x-4

Answers

The graph of the given line is attached below.

We are given the line:-

y = (3/5)x - 4

We will find the x and y intercepts of the line to plot in the graph.

As the equation is already in the slope intercept form, we can write,

The y-intercept of the line is -4.

Hence, the coordinates of the point will be (0,-4).

To find the x - intercept of the line we will put y = 0 in the given line.

0 = (3/5)x - 4

4 = 3x/5

x = 20/3

The coordinates of the point will be (20/3,0).

We can plot these points to get the desired graph.

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Jenny wants to earn $1,300by the end of the summer. How much more will she need to earn to meet her goal?

Answers

The most appropriate choice for subtraction of natural numbers will be given by-

Jenny needs $1172.95 to earn her goal.

What is subtraction?

At first, it is important to know about natural numbers.

Natural numbers are integers which are greater than or equal to 1

One of the operations on natural number is subtraction

The process of reducing one number from another number is called subtraction. Subtraction is used to find the difference between two numbers. The larger number is called minuend and the smaller number is called subtrehend.

Amount of money Jennyy had before = $127.05

Amount of money Jenny wants to earn = $1300

Amount of money Jenny needs to earn her goal = $(1300 - 127.05)

                                                                                 = $1172.95

To learn more about subtraction of natural numbers, refer to the link-

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Complete Question

Jenny wants to earn $1,300 by the end of the summer. How much more will she need to meet her goal?

(Jenny had $127.05 before.)

This is a non graded practice that I am doing. I don’t under these questions 5-11

Answers

7. The intersection of two intersecting lines is a point.

In the given image, we see that lines NQ and ML intersect at point P.

Therefore, the intersection of NQ and ML is P.

Find the equation of the linear function x 1 2 3 4 y 1 6 11 16

Answers

We solve as follows:

*We determine first the slope (m), that is:

[tex]m=\frac{6-1}{2-1}\Rightarrow m=5[/tex]

Now, using the slope and one point of the line, we replace in the following expression:

[tex]y-y_1=m(x-x_1)[/tex]

We can use any point of the line, but I will be using the point (1, 1), that is:

[tex]y-1=5(x-1)[/tex]

Now, we solve for y:

[tex]\Rightarrow y-1=5x-5\Rightarrow y=5x-4[/tex]

The cargo of the truck welghs no more than 2,800 pounds.Use w to represent the weight (in pounds) of the cargo.

Answers

We know that

• The truck weighs no more than 2,800 pounds.

This problem is about inequalities.

"no more" indicates an inequality sign, specifically, it shows that we should use "less than or equal to", because this sign indicates the same as the problem do.

Therefore, the expression of the truck weight is

[tex]w\leq2,800[/tex]

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