Answer:
d = 8 [m]
Explanation:
To solve this problem we must use the principle of conservation of energy, where the mechanical energy in a state plus the work done on the body, must be equal to the mechanical energy in the state Y. This can be easily represented in the following equation.
[tex]E_{x}+W_{x-y}=E_{y}[/tex]
where:
Ex = Mechanical energy in X [J]
Wx-y = Work among states x and y [J]
Ey = Mechanical energy in Y [J].
The key to being able to understand this problem is that in state X, we only have kinetic energy, while the energy in state Y is equal to zero (there is no movement). The work is equal to the product of force by distance, as work acts in the opposite direction to movement, this has a negative sign.
[tex]800 - F*d = 0\\100*d = 800\\d = 800/100\\d = 8 [m][/tex]
An 8.00- W resistor is dissipating 100 watts. What are the current through it and the difference of potential across it?
Answer:
I= 3.5 amps
Explanation:
Step one:
given data
rating of resistor R= 8 ohms
power P= 100W
Required
The current I
Step two
Yet this power is also given by
[tex]P = I^2R[/tex]
make I subject of the formula we have
[tex]I= \sqrt{\frac{P}{R} }[/tex]
substitute
[tex]I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps[/tex]
the maximum value of magnetic in an electric field 3.2 *10^4
Answer:
the answer is 12 because if your magnetic value and Electric field is 3.2 the answer will be 12
A 2.0 m conductor is formed into a square and placed in the horizontal A magnetic field is oriented above the horizontal with a strength of 1.0 T. What is the magnetic flux through the conductor
Answer:
4.0Wb/m²Explanation:
Magnetic flux Ф is expressed using the formula;
Ф = BA
B is magnetic field
A is the area of the square conductor
Given
B = 1.0T
A =L²
Area A = 2.0² = 4.0m²
Get the magnetic flux
Ф = 1.0 * 4.0m²
Ф = 4.0Wb/m²
Hence the magnetic flux through the conductor is 4.0Wb/m²
Which tool would you choose to create a storyboard, and why?
Answer:
Canva. Although Canva's free storyboard app for iOS and Android is targeted more at video production, it still provides animators and UX designers everything they need.
Explanation:
An auto, moving too fast on a horizontal stretch of mountain road, slides off the road, falling into deep snow 43.9 m below the road and 87.7 m beyond the edge of the road. How fast was it going when it left the road?
The speed with which the auto was going when it left the road will be 29.3 m/s.
What is Acceleration?Acceleration is the rate of change of velocity of an object. Acceleration is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second square.
From the given question, we can deduce that the only force which will be acting on the car is the gravitational force and as such the acceleration during free fall of the object will be equal to the acceleration due to gravity acting on the object however, this will be negative since it is towards the ground surface.
Thus, acceleration of the auto = - 9.8 m/s²
The time in which the auto falls will be,
t² = 2 × s/ a
t² = 2 × -43.9/ -9.80
t² = 8.95
t =[tex]\sqrt{8.95}[/tex]
t = 2.99 seconds
The velocity with which the auto will be going when it left the road will be,
Velocity = Displacement/ Time
Velocity = 87.7/ 2.99
Velocity = 29.3 m/s
Therefore, the velocity with which the auto will be moving when it left the road will be 29.3 meters per second.
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What is the period of a pendulum near Earth’s surface that is 130 cm long?
Question 1 options:
2.3 s
0.83 s
9.1 s
22.9 s
Answer:
A). 2.3 s
Explanation:
Given that,
Length of the string = 130cm or 1.3 m
g near Earth's surface = 9.8 [tex]ms^{-2}[/tex]
To determine the period of a pendulum near Earth’s surface;
T = 2 π [tex]\sqrt{\frac{L}{g} }[/tex]
T = 2π[tex]\sqrt{\frac{1.3}{9.8} }[/tex]
T = 2.3 sec
Therefore, the period of the pendulum near the earth's surface is 2.3 sec.
The components of vectors A and B are given as follows:
Ax = 7.6
Bx = -5.1
Ay = -9.2
By = -6.8
What is the magnitude of the vector difference B - À?
Answer:
|B - A| = 12.92 units
Explanation:
In order to find the magnitude of B-A vector, we first write A and B in Vector Notation:
A = Aₓ i + Ay j
A = 7.6 i - 9.2 j
B = Bₓ i + By j
B = -5.1 i - 6.8 j
So, there difference will be:
B - A = (-5.1 i - 6.8 j) - (7.6 i - 9.2 j)
B - A = -12.7 i + 2.4 j
Now, the magnitude of this vector can be found out by using the formula:
|B - A| = √[(x-component)² + (y-component)²]
|B - A| = √[(-12.7)² + (2.4)²]
|B - A| = 12.92 units
We will see that the magnitude of the difference of the vectors is 12.92
How to get the difference of two vectors?
Here we have two vectors:
A = <7.6, -9.2>
B = <-5.1, -6.8>
To get the difference we just subtract the correspondent components:
B - A = <Bx - Ax, By - Ay> = <-5.1 - 7.6, -6.8 - (-9.2)> = <-12.7, 2.4>
The magnitude of that vector is just:
[tex]M = \sqrt{(2.4)^2 + (-12.7)^2} = 12.92[/tex]
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In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 480 nm, how much thicker is the air wedge at the 16th dark fringe than it is at the 6th dark fringe
Answer:
The thickness is [tex]\Delta y = 2.4 *10^{-6} \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 480 \ nm = 480*10^{-9} \ m[/tex]
The first order of the dark fringe is [tex]m_1 = 16[/tex]
The second order of dark fringe considered is [tex]m_2 = 6[/tex]
Generally the condition for destructive interference is mathematically represented as
[tex]y = \frac{m \lambda}{2}[/tex]
Here y is the path difference between the central maxima(i.e the origin) and any dark fringe
So the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as
[tex]y_1 - y_2 = \Delta y = \frac{m_1 \lambda}{2} - \frac{m_2 \lambda}{2}[/tex]
=> [tex]y_1 - y_2 = \Delta y = \frac{16 *480*10^{-9}}{2} - \frac{6 *480*10^{-9}}{2}[/tex]
=> [tex]y_1 - y_2 = \Delta y = 5 (480*10^{-9})[/tex]
=> [tex]\Delta y = 2.4 *10^{-6} \ m[/tex]
A rocket takes off against the force of gravity. Consider this a non-isolated system. Derive the rocket equation formula relating velocity to the mass of the rocket and time. Let the velocity of the rocket be v(t) and the relative speedof the ejected fuelrelative to the moving rocket be u. Ignore air drag.
Answer:
Explanation:
The solution of the question has been put in attachment.
ball a 0.604 kg moving right at 11.6 m/s makes a head-on collision with ball B at rest. after, ball A moves right at 2.09 m/s, and ball B moves right at 5.03 m/s. what is the mass of ball B? unite=kg
Answer:
1.142
Explanation:
A standing wave with a fundamental frequency 1.25x10 2 Hz is set up on a string of length 0.750 meters. What is the frequency of the third harmonic?
Answer:
500Hertz
Explanation:
Given the fundamental frequency of the string given as 1.25x10²Hz
Harmonics are integral multiples of the fundamental frequency.
In strings, the third harmonic F3 is expressed in terms of the fundamental frequency expressed as;
F3 = 4F0
F0 is the fundamental frequency;
Given
F0 = 1.25x10²Hz
F3 = 4(1.25x10²)
F3 = 4(125)
F3 = 500Hz
Hence the frequency of the third harmonic is 500Hertz
If the equal tensions T in the pulley cable are 300 N, express in vector notation the force R exerted on the pulley by the two tensions. Determine the magnitude of R.
Answer:
[tex]R=519.61N[/tex]
Explanation:
From the question we are told that
Tension T on a cable are T=300N
Generally the tensions on a pulley is
[tex]\sum f_x=T+T*cos(\theta)[/tex]
Therefore
[tex]\sum f_x=300+300*cos(60)[/tex]
[tex]\sum f_x=300 *1.5[/tex]
[tex]\sum f_x=450N[/tex]
Hence
[tex]T*sin(60) = 259.81N[/tex]
[tex]R= 450\=i +259.81\=i[/tex]
[tex]R=\sqrt{450^2+259.8^2}[/tex]
[tex]R=519.61N[/tex]
he mass of the moon is 1/81 of the mass of the earth. Compared to the gravitational force that the earth exerts on the moon, the gravitational force that the moon exerts on the earth is
Answer:
It is the same in magnitude and opposite in direction.
Explanation:
According Newton's Universal Law of Gravitation, the force that any mass exerts on any other one, is proportional to the product of their masses, inversely proportional tho the square of the distance between their centers, and acts along the line that joins both points.At the same time, this force is part of a action-reaction pair, according to Newton's 3rd Law, that states that for a force that one body exerts upon another, there exists an equal and opposite force exerted by the other body on the former one.So, we conclude that the gravitational force that the earth exerts on the moon is equal in magnitude and opposite in direction to the one that the moon exerts on the earth.The gravitational force the moon and the earth exert on each other are equal.
According to Newton's third law of motion, action and reaction are equal and opposite.
The gravitational force the earth exerts on the moon is equal in magnitude but opposite in direction to the gravitational force the moon exerts on the earth.
The magnitude of the gravitational force between the moon and the earth is calculated as follows;
[tex]F = \frac{GM_e M_m}{R^2}[/tex]
Thus, the gravitational force the moon and the earth exert on each other are equal.
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A solid cube of aluminum (density of 2.7 g/cm³) has a volume of 0.9 cm³. how many atoms are contained in the cube?
Answer:
[tex]0.542*10^{23}\ Aluminum\ Atoms[/tex]
Explanation:
[tex]We\ are\ given:\\Density\ of\ aluminum=2.7\ g/cm^3\\Volume\ of\ aluminum-cube=0.9\ cm^3\\Hence,\\As\ we\ know\ that,\\Density=\frac{Mass}{Volume}\\Mass=Density*Volume\\Hence,\ here,\\Mass\ of\ the\ solid\ iron\ cube=2.7*0.9=2.43\ g\\Now,\\We\ also\ know\ that,\\Gram\ Atomic\ mass\ of\ Aluminum = 26.98 \approx 27\ g\\Hence,\\No.\ of\ particles=\frac{Mass}{GAM}*Avagadro's Constant\\Hence,\ here\\No.\ of\ Aluminum\ atoms=\frac{2.43}{27}*6.022*10^{23} \approx 0.542*10^{23}\ Aluminum\ Atoms[/tex]
Martin needs to push a box up a ramp.
Which force will make it hard for him to push the box?
friction
inertia
magnetism
Which of following is true statement of self-efficiency
Explanation:
Which of the following best defines self-efficacy? The belief in one's ability to cause an intended event to happen. ... If Bobby does not value athletic skill, his lack of talent will have less impact on his self-esteem than if he highly values athleticism.
how was fibre optics made
what is Newton's Laws
Answer:
Explanation:
Newton's laws of motion are three physical laws that, together, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. “
If ball 4 has a mass of 2 kg and it is 5m high, what will be its gravitational potential energy? (g=10 N/kg) *
Explanation:
Gravitational potential energy
= mgh
= (2kg)(10N/kg)(5m)
= 100J.
Answer:
[tex]\boxed {\boxed {\sf 100 \ Joules}}[/tex]
Explanation:
Gravitational potential energy can be found using the following formula.
[tex]E_p=m*g*h[/tex]
where m is the mass, g is the gravitational acceleration, and h is the height.
The mass of the ball is 2 kilograms, its height is 5 meters, and the acceleration due to gravity is 10 Newtons per kilogram.
[tex]m= 2 \ kg \\h= 5 \ m \\g= 10 \ N/kg[/tex]
Substitute the values into the formula.
[tex]E_p=(2 \ kg)(10 \ N/kg)(5 \ m)[/tex]
Multiply the first 2 numbers. The kilograms (kg) will cancel out when multiplying.
[tex]E_p=(20 \ N)(5 \ m)[/tex]
Multiply again.
[tex]E_p=100 \ N*m[/tex]
1 Newton meter is equal to 1 Joule Therefore, 100 N*m= 100 J[tex]E_p= 100 \ J[/tex]
The gravitational potential energy of the ball is 100 Joules.
I WILL NEVER USE THIS APPP AGAIN I JUST GOT A 63 PPERCENT OFF PEOPLES ANSWERS AND GOT A 63% WHAT IS THAT
Answer:
You should still use the app if you need it, but you definitely shouldn't rely on it. It's really good for what it is, but it's not an alternative to actually taking the test, just imagine what you would have gotten if you didn't use this
Explanation:
I don't understand your statement but, are you saying that you just got 63% positive rating of your answer to people's answers? Maybe you answer is either correct or somehow incorrect or maybe others answer is more applicable answer compared to yours BUT thanks for the free points! Btw could you mark this as brainliest? Thanks
Witch force is represented by arrow at c?
Answer:
did u know there's no such thing as "pear cider."
Explanation:
Calculate the magnitude of the normal force acting on a 20 kg block the block is resting on the surface of an elevator accelerating 2.5m/s
Answer:
Fn = 246.2 N
Explanation:
I assume you meant meters per second squared for acceleration of the elevator. All you have to after your picture/free-body diagram is made is add the forces together. You could do this by finding them separately like I did or use Fn = m(Fg + Fe). I just calculated magnitude and didn't worry about signs.
An object has more momentum if it has which of the following?
Answer:
C.) A high velocity and Large mass.
Explanation:
Momentum of any object is defined by following formula
Here : m = mass of object
v = velocity of object
now we know that since momentum is product of mass and velocity
So in order to have more momentum we need the value of this product to be more. So this product will me large is both the physical quantity will be more in magnitude. So if mass is large and velocity will be more then the product of them will be large and hence the momentum of object will be more. Btw I had that question too.
who win tug of war with what net force
Answer:
The force on rope is equal for both of them at any time.
For winning the game the force on ground is responsible.
Explanation:
Callisto is a moon of Jupiter (mass = 1.90 x 1027 kg), which orbits the planet with a period of 16.9 days. What is the radius of its orbit?
The radius of its orbit = 8.27 x 10¹³ m
Further explanationGiven
mass Jupiter=1.9 x 10²⁷ kg
T = 16.9 days=1.46 x 10⁶ s
Required
the radius =r
Solution
To hold the moon in its orbit, the gravitational force between two objects (jupiter and moon) will be equal to the centripetal force
[tex]\tt G\dfrac{M.m}{r^2}=m.\dfrac{v^2}{r}\rightarrow v=\dfrac{2.\pi.r}{T}\\\\M=\dfrac{r^3.4\pi^2}{T^2.G}\rightarrow r^3=\dfrac{GMT^2}{4\pi^2}[/tex]
G = 6.67 x 10⁻¹¹ N/m²kg²
Input the value :
[tex]\tt r^3=\dfrac{6.67\times 10^{-11}\times 1.9\times 10^{27}\times (1.46\times 10^6)^2}{4\pi^2}\\\\r^3=6.85\times 10^{27}\rightarrow r=8.27\times 10^{13}[/tex]
Answer:
1.9 x [tex]10^{9}[/tex]
Explanation:
Which of these quantities impact centripetal force?
A.mass and speed only
B.mass and radius only
C.speed and radius only
D.mass, speed, and radius all impact centripetal force
Answer: D) Mass, speed and radius all impact the centripetal force
Explanation:
If we change either the mass, speed, and/or radius, then the centripetal force will be different. Though on rare occasions we could change the variables together in a way to have the centripetal forces line up, but in general the before and after forces will likely be different. Changing one variable at a time only will definitely result in a different centripetal force.
This is because the centripetal force F is determined by the formula
F = (m*v^2)/r
where,
m = mass
v = velocity
r = radius
What are electromagnetic waves?
Answer:
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields. They are also perpendicular to the direction of the EM
Explanation:
what is the maximum powr of a module in Watts to the nearest whole Watt?
Complete question is;
You are looking at a module specification
sheet that has the table of information
below. What is the maximum power of this
module in Watts to the nearest whole Watt?
Value
Polycrystalline si
Characteristic
Cell Type
Cell
Configuration
Voc
160 in series
137.2 V
V_imp: 29.3 V
Ilsc: 8.60 A
I_Imp: 8.02 A
Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"
Weight: 10 kg / 22 lbs
Answer:
P ≈ 235 Watts
Explanation:
Formula for power is;
P = IV
Now, for maximum power, we will make use of I_imp and V_imp given
Thus, P = I_imp × V_imp
We are given;
V_imp: 29.3 V
I_Imp: 8.02 A
Thus: P = 8.02 × 29.3 = 234.986 Watts
We are to approximate to the nearest whole watt.
Thus: P ≈ 235 Watts
5.
The diagram below shows two forces applied to a 2.0-kilogram block on a frictionless, horizontal surface.
F = 8.0 N
2.0 kg
F2 = 3.0 N
Frictionless Surface
What is the acceleration of the block?
A 4.0 m/s2 to the left
B.O 2.5 m/s2 to the right
C.O 2.5 m/s2 to the left
D. 1.5 m/s2 to the right
Answer:2.5m/s^2 to the left
Explanation:
The acceleration of the block is "2.5 m/s² to the left"
Given,
Force,
[tex]F_1 = 8 N[/tex][tex]F_2 = 3 \ N[/tex]Mass,
[tex]m = 2 \ kg[/tex]Considering equilibrium of forces on block,
then,
→ [tex]F_1 -F_2 = ma[/tex]
By substituting the values, we get
→ [tex]8-3 = 2a[/tex]
→ [tex]5 = 2a[/tex]
[tex]a = \frac{5}{2}[/tex]
[tex]a = 2.5 \ m/s^2[/tex] (to the left)
Thus the above answer i.e., option C is right.
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n a double-slit experiment, the slit separation is 6.03x10-5 meters. The slits are illuminated with a laser beam of wavelength 5.37x10-7 meters. A screen is located 2.14 m from the slits. Calculate the distance on the screen from the first dark fringe on one side of the central maximum to the second dark fringe on the other side.
Answer:
D = 3.81 x 10⁻² m = 3.81 cm
Explanation:
We can use the formula of fringe spacing from Young's Double Slit experiment to answer this question:
[tex]\Delta x = \frac{\lambda L}{d}\\[/tex]
where,
Δx = distance between two consecutive dark fringes
λ = wavelength of light beam = 5.37 x 10⁻⁷ m
L = Distance between screen and slits = 2.14 m
d = slit separation = 6.03 x 10⁻⁵ m
But, we need the distance between first dark fringe on 1 side to 2nd dark fringe on other side. It means we need twice the distance between two dark fringes:
[tex]D = 2\Delta x = 2\frac{\lambda L}{d}\\[/tex]
where,
D = distance between first dark fringe on one side and 2nd dark fringe on other side of central maximum = ?
Therefore,
[tex]D = \frac{(2)(5.37\ x\ 10^{-7} m)(2.14\ m)}{6.03\ x\ 10^{-5}\ m }[/tex]
D = 3.81 x 10⁻² m = 3.81 cm