An object is dropped from 27 feet below the tip of the pinnacle atop a 1471-ft tall building. The height h of the object after t seconds is giveh= - 16t^2 + 1444. Find how many seconds pass before the object reaches the ground.How many seconds pass before the object reaches the ground

Answers

Answer 1

The Solution:

Given:

[tex]h=-16t^2+1444.[/tex]

We are required to find t when h = 0.

[tex]\begin{gathered} -16t^2+1444=0 \\ \\ -16t^2=-1444 \end{gathered}[/tex]

Divide both sides by -16.

[tex]t^2=\frac{-1444}{-16}=90.25[/tex][tex]\begin{gathered} t=\sqrt{90.25} \\ \\ t=9.5\text{ or }t=-9.5 \end{gathered}[/tex]

Thus, the correct answer is 9.5 seconds.


Related Questions

The lengths of adult males' hands are normally distributed with mean 189 mm and standard deviation is 7.4 mm. Suppose that 15 individuals are randomly chosen. Round all answers to 4 where possible.
a. What is the distribution of ¯x? x¯ ~ N( , )
b. For the group of 15, find the probability that the average hand length is less than 191.
c. Find the first quartile for the average adult male hand length for this sample size.
d. For part b), is the assumption that the distribution is normal necessary? No Yes

Answers

Considering the normal distribution and the central limit theorem, it is found that:

a) The distribution is: x¯ ~ N(189, 1.91).

b) The probability that the average hand length is less than 191 is of 0.8531 = 85.31%.

c) The first quartile is of 187.7 mm.

d) The assumption is necessary, as the sample size is less than 30.

Normal Probability Distribution

The z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]. The mean is the same as the population mean.For sample size less than 30, such as in this problem, the assumption of normality is needed to apply the Central Limit Theorem.

The parameters in this problem are given as follows:

[tex]\mu = 189, \sigma = 7.4, n = 15, s = \frac{7.4}{\sqrt{15}} = 1.91[/tex]

Hence the sampling distribution of sample means is classified as follows:

x¯ ~ N(189, 1.91).

The probability that the average hand length is less than 191 is the p-value of Z when X = 191, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

Z = (191 - 189)/1.91

Z = 1.05

Z = 1.05 has a p-value of 0.8531, which is the probability.

The first quartile of the distribution is X when Z has a p-value of 0.25, so X when Z = -0.675, hence:

[tex]Z = \frac{X - \mu}{s}[/tex]

-0.675 = (X - 189)/1.91

X - 189 = -0.675 x 1.91

X = 187.7 mm.

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tim wants to order pizza for 22 employees.Each employee should get 1/4 of a pizza.How many pizzas should tim order ?

Answers

Tim should order approximately 6 pizza.

Define division.

Division in mathematics is the process of dividing an amount into equal parts. For instance, we may split a group of 20 people into four groups of 5, five groups of 4, and so on. One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division. The other operations are multiplication, addition, and subtraction. Mathematicians use addition, subtraction, multiplication, and division as their four fundamental arithmetic operations. The division is one of these four operations that we employ most frequently in our daily work. It involves dividing a huge group into equally sized smaller units. Divide 25, for instance, by 5.

Given Data

Number of employees = 22

Slice of pizza one should get = 1/4

Dividing 22 by 1/4

[tex]\frac{22}{4}[/tex]

5 and [tex]\frac{1}{2}[/tex]

Tim should order approximately 6 pizza.

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In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 4 boys and 5 girls are competing, how many different ways could the six medals possibly be given out?

Answers

ANSWER

1,440

EXPLANATION

We have that 4 boys are competing and also 5 girls are competing. 3 medals are given to the boys and 3 medals are given to the girls.

For the boys, the gold medal can be awarded to one of 4 boys, then the silver medal can be awarded to 3 boys because 1 of them already got the gold medal. Finally, the bronze medal can be awarded to one of 2 boys, since the gold and silver medals are already taken. The number of ways the medals can be given to the boys is,

[tex]permutations_{boys}=4\cdot3\cdot2=24[/tex]

This situation is similar for the girls, but in this case, there are 5 girls in total,

[tex]permutations_{girls}=5\times4\times3=60[/tex]

The total ways the six medals can be given is,

[tex]permutations_{boys}\times permutations_{girls}=24\times60=1,440[/tex]

Hence, there are 1,440 ways to give the six medals to the 4 boys and 5 girls.

one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours. how long will it take the pipe to fill the pool if the drains left open

Answers

The time that it will take the pipe to fill the pool if the drains left open is 10 hours.

How to calculate the value?

From the information, one inlet pipe can fill an empty pool in 6 hours and a drain can empty the pool in 15 hours.

The information illustrated that the input pipe gills 1/6 if the pool and the drain empties 1/15 in the pool every hour

The required time taken will be:

= 1/6 - 1/15

= 5/30 - 2/30

= 3/30

= 1/10

Therefore, the time taken is 10 hours.

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suppose g(x) = f(x - 3) - 4. I need the graph of g(x) with the graph of f(x)

Answers

In order to graph g(x) with the graph of f(x), first we need a translation of 3 units to the right, because of the term f(x - 3)

Then, we need a translation of 4 units down, because of the term -4.

So the movements are: translations of 3 units right and 4 units down.

Simplify (v2 + 10v + 11)(v2 + 3v – 4) using the distributive property of multiplication ove addition(DPMA)

Answers

Given:

[tex](v^2+10v+11)(v^2+3v-4)[/tex]

To find- the simplification.

Explanation-

We know that the distribution property of multiplication over addition says

[tex]a(b+c)=ab+ac[/tex]

Use this property to simplify, and we get

[tex]\begin{gathered} =(v^2+10v+11)(v^2+3v-4) \\ =v^2(v^2+3v-4)+10v(v^2+3v-4)+11(v^2+3v-4) \end{gathered}[/tex]

Multiply by opening the bracket, and we get

[tex]=(v^4+3v^3-4v^2)+(10v^3+30v^2-40v)+(11v^2+33v-44)[/tex]

Now, open the bracket and combine the like terms.

[tex]\begin{gathered} =v^4+3v^3-4v^2+10v^3+30v^2-40v+11v^2+33v-44 \\ =v^4+(3v^3+10v^3)+(11v^2-4v^2+30v^2)-40v+33v-44 \end{gathered}[/tex]

On further solving, we get

[tex]=v^4+13v^3+37v^2-7v-44[/tex]

Thus, from the distributive property of multiplication over addition, we get v⁴+13v³+37v²-7v-44.

The answer is v⁴ + 13v³ + 37v² - 7v - 44.

coupon A 45% off of a $73 jacket coupon B $30 rebate on a $73 Jacket

Answers

To be able to determine which among the coupon gives a lower price, let's determine what is 45% of $73 so that we could compare it with the $30 rebate. The highest amount among the two coupons will give you a lower price.

Let's determinte the 45% of 73:

[tex]\text{73 x }\frac{45\text{\%}}{100\text{\%}}\text{ }\rightarrow\text{ 73 x 0.45}[/tex][tex]\text{ = \$32.85}[/tex]

Coupon A gives you $32.85 dollar off of a $73 Jacket.

Coupon A will give you a lower price compared to Coupon B. The price of the jacket will be $2.85 lesser than using Coupon B.

Write the expression as a sum and/or difference of logarithms. Express powers as factors

Answers

We will have the following:

[tex]\begin{gathered} ln(x^3\sqrt{6-x})=ln(x^3)+ln(\sqrt{6-x}) \\ \\ =3ln(x)+\frac{1}{2}ln(6-x) \end{gathered}[/tex]

Find the y-intercept and slope of the line below. Then write the equation is slope intercept form (y=mx+b).

Answers

[tex]y\text{ = }\frac{-3}{2}x\text{ + 6}[/tex]

Explanation:

The y-intercept is the value of y when x = 0

To identify y-intercept on a graph, we will check for the the value of y when the line crosses the y axis

From the graph, the line crosses the y axis at y = 6

Hence, the y-intercept is 6

To get the slope, we will pick any two points on the line.

Using points (0, 6) and (4, 0)

Applying the slope formula:

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} x_1=0,y_1=6,x_2=4,y_2\text{ = }0 \\ m\text{ = }\frac{0\text{ - 6}}{4\text{ - 0}} \\ m\text{ = }\frac{-6}{4} \\ m\text{ = slope = -3/2} \end{gathered}[/tex]

NOTE: the slope is negative because it is going from up to down (moving downwards)

The equation of slope in intercept form: y = mx + b

m = slope = -3/2

b = y-intercept = 6

The equation in y-intercept becomes:

[tex]y\text{ = }\frac{-3}{2}x\text{ + 6}[/tex]

find the missing values in the figure below ( I need help as soon as possible only have 5 minutes available)

Answers

You can see in the figure attached that there are two Right triangles.

By definition, Right triangles are those triangles that have an angle that measures 90 degrees.

The larger triangle is the triangle ABC, but you only know the lenght of the side BC, which is:

[tex]BC=15m+2.5m=17.5m[/tex]

And for the smaller triangle you only know the side whose lenght is 2.5 meters.

Therefore, since the exercise does not provide any other lenght and it does not provide another angle, you can conclude that the missing values cannot be determine with the given information.

So, the answer is OPTION D.

A rectangle is bounded by the x-axis and the semicircle
y = 49 − x2 What length and width should the rectangle have so that its area is a maximum?

Answers

The length and width of the rectangle are 4.04 and 32.67 respectively for which the area is a maximum.

What is mean by Rectangle?

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

The rectangle is bounded by the x - axis and the semicircle y = 49 - x².

Since,

The area of rectangle with sides x and y is,

Area = x × y

A = xy

Since, The equation of the semicircle is;

y = 49 - x².

Substitute the values of y in equation (i), we get;

A = x (49 - x²)

A = 49x - x³

Now, Find the derivative and equate into zero,

A' = 49 - 3x²

A' = 0

49 - 3x² = 0

49 = 3x²

x² = 49/3

x = 7/√3

x = 7/1.73

x = 4.04

Hence, y = 49 - x²

y = 49 - (4.04)²

y = 49 - 16.3

y = 32.67

Since, The area is maximum when we can multiply x by y as;

Maximum area = 4.04 x 32.67

Maximum area = 132

Hence, The length and width of the rectangle are 4.04 and 32.67 respectively for which the area is a maximum.

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Find (and classify) the critical points of the following function and determine if they are local max, local min, or neither: f(x) =2x^3 + 3x^2 - 120x

Answers

As given by the question

There are given that the function:

[tex]f(x)=2x^3+3x^2-120x[/tex]

Now,

To find the critical point, differentiate the given function with respect to x and put the result of function equal to zero

So,

[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f^{\prime}(x)=6x^2+6x-120 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} f^{\prime}(x)=0 \\ 6x^2+6x-120=0 \\ x^2+x-20=0 \\ x^2+5x-4x-20=0 \\ x(x+5)-4(x+5) \\ (x-4)(x+5) \\ x=4,\text{ -5} \end{gathered}[/tex]

Now,

To find the y-coordinate, we need to substitute the above value, x = 4, -5, into the function f(x)

So,

First put x = 4 into the given function:

[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(4)=2(4)^3+3(4)^2-120(4) \\ =128+48-480 \\ =-304 \end{gathered}[/tex]

And,

Put x = -5 into the function f(x):

[tex]\begin{gathered} f(x)=2x^3+3x^2-120x \\ f(-5)=2(-5)^3+3(-5)^2-120(-5) \\ =-250+75+600 \\ =425 \end{gathered}[/tex]

Hence, the critical point is, (4, -304) and (-5, 425).

Now,

To find the local maxima and local minima, we need to find the second derivative of the given function:;

So,

[tex]\begin{gathered} f^{\prime}(x)=6x^2+6x-120 \\ f^{\doubleprime}(x)=12x+6 \end{gathered}[/tex]

Now,

The put the value from critical point into the above function to check whether it is maxima or minima.

So,

First put x = 4 into above function:

[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(4)=12(4)+6 \\ f^{\doubleprime}(4)=48+6 \\ f^{\doubleprime}(4)=54 \\ f^{\doubleprime}(4)>0 \end{gathered}[/tex]

And,

Put x = -5 into the above function

[tex]\begin{gathered} f^{\doubleprime}(x)=12x+6 \\ f^{\doubleprime}(-5)=12(-5)+6 \\ f^{\doubleprime}(-5)=-60+6 \\ f^{\doubleprime}(-5)=-54 \\ f^{\doubleprime}(-5)<0 \end{gathered}[/tex]

Then,

According to the concept, if f''(x)>0 then it is local minima function and if f''(x)<0, then it is local maxima function

Hence, the given function is local maxima at (-5, 425) and the value is -54 and the given function is local minima at point (4, -304) and the value is 54.

Write a sine function that has a midline of 4 , an amplitude of 3 and a period of 2/3

Answers

Given a midline of 4, an amplitude of 3 and a period of 2/3 we are asked to write a sine function.

Explanation

The equation of a sine function is given as

[tex]y=Asin(\frac{2\pi x}{T})+B[/tex]

Where A is the amplitude, T is the period and B is the midline of the sine function.

Therefore, we will have;

[tex]\begin{gathered} y=3sin(2\pi x\div\frac{2}{3})+4 \\ y=3sin(2\pi x\times\frac{3}{2}_)+4 \\ y=3s\imaginaryI n(3\pi x)+4 \end{gathered}[/tex]

Answer:

[tex]y=3s\imaginaryI n(3\pi x)+4[/tex]

Imagine you are four years old. A rich aunt wants to provide for your future. She hasoffered to do one of two things.Option 1: She would give you $1000.50 a year until you are twenty-one.Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amounteach year until you were 21.If you only received money for ten years, which option would give you the most money?

Answers

Given the situation to model the arithmetic and the geometric sequences.

Imagine you are four years old. A rich aunt wants to provide for your future. She has offered to do one of two things.

Option 1: She would give you $1000.50 a year until you are twenty-one.

This option represents the arithmetic sequence

The first term = a = 1000.50

The common difference = d = 1000.50

The general formula will be as follows:

[tex]\begin{gathered} a_n=a+d(n-1) \\ a_n=1000.50+1000.50(n-1) \\ \end{gathered}[/tex]

Simplify the expression:

[tex]a_n=1000.50n[/tex]

Option 2: She would give you $1 this year, $2 next year, and so on, doubling the amount each year until you were 21.

This option represents the geometric sequence

The first term = a = 1

The common ratio = r = 2/1 = 2

The general formula will be as follows:

[tex]\begin{gathered} a_n=a\cdot r^{n-1} \\ a_n=1\cdot2^{n-1} \end{gathered}[/tex]

Now, we will compare the options:

The first term of both options is when you are four years old that n = 1

you only received money for ten years so, n = 10

So, substitute with n = 10 into both formulas:

[tex]\begin{gathered} Option1\rightarrow a_{10}=1000.50(10)=10005 \\ Option2\rightarrow a_{10}=1\cdot2^{10-1}=2^9=512 \end{gathered}[/tex]

So, the answer will be:

For ten years, the option that gives the most money = Option 1

The width of a rectangle is 6x + 8 and the length of the rectangle is 12x + 16 determine the ratio of the width to the perimeter.Supply the following:Perimeter = 21 + 2w = Ratio= w/p Final answer in simplest form:

Answers

Solution:

For this case we know that the width is given by:

w = 6x +8

The lenght is given by:

l= 12x +16

And the perimeter would be given by:

P= 2l +2w = 2(12x+16)+ 2(6x+8)= 24x+32 +12x+16=36x + 48

And then the ratio would be:

[tex]\text{ratio}=\frac{6x+8}{36x+48}=\frac{3x+4}{18x+24}[/tex]

Company A has a monthly budget of 2 x 10^4 dollars. Company B has
a monthly budget of 5 x 10^8 dollars. How many times greater is the
monthly budget for company B than for company A?

Answers

The budget is 20000 times greater.

What are basic arithmetic?

Mathematics' fundamentals are arithmetic operations. Addition, subtraction, multiplication, and division are the main operations that make up this concept. The phrase "mathematical operations" also refers to these.

The math operation of subtracting two integers reveals the difference between them. The '-' sign is used to indicate it. In math, subtraction is the process of taking one number away from another to determine what is left over after something has been taken away. Rational number operations are equivalent to those performed on whole numbers. The main distinction is that rational numbers take the form p/q, where p and q are integers and q is not equal to 0. It is necessary to take the LCM of the numerators when adding or subtracting two rational integers.

Here we are discussing the four basic rules of arithmetic operations for all real numbers.

Addition (sum; ‘+’)Subtraction (difference; ‘-’)Multiplication (product; ‘×’ )Division (÷)

Company A = $2 × [tex]10^{4}[/tex]e

Company B = $ 5 × [tex]10^{8}[/tex]

The difference = $2 × [tex]10^{4}[/tex]

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Please help me i have been struggling for two days

Answers

we have the equation

[tex]\log _5(x+1)-\log _2(x-2)=1[/tex]

using a graphing tool

see the attached figure

The solution is x=2.90

Consider function f, where B is a real number.
f(z) = tan (Bz)
Complete the statement describing the transformations to function f as the value of B is changed.
As the value of B increases, the period of the function
When the value of B is negative, the graph of the function
shy
and the frequency of the function

Answers

If the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B is negative, the graph of the function reflects over the y-axis.

How to estimate the graph and the frequency of the function?

Let the tangent function be f(z) = tan (Bz)

The period exists [tex]$P=\frac{\pi}{|B|}$[/tex]

The frequency exists [tex]$F=\frac{1}{P}=\frac{|B|}{\pi}$[/tex].

The period exists inversely proportional to B, therefore, as B increases, the period decreases.

Frequency exists inversely proportional to the period, therefore, as the period decreases, the frequency increases.

When B is negative, we get f(z) = tan -Bz = f(-z), therefore, the function exists reflected over the y-axis, as the graph at the end of the answer shows, with f(z) exists red(B positive) and f(-z) exists blue(B negative).

As the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B exists negative, the graph of the function reflects over the y-axis.

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what angle is Supplementary to angle 2 and what are the Verticle angles in this picture?

Answers

Suplementary angle = 180° - angle 2

is Angle 1,

because Angle 2 + Angle 1 = 180°

Part 2. Vertical angles are

Angles 2 and 5

G(x) = 1/x^10 g’(x)=

Answers

Differentiation - The value of g'(x) = [tex]\frac{1}{10}x^{-9}[/tex].


What is a differentiation?

Apart from integration, differentiation is among the two key ideas in calculus. A technique for determining a function's derivative is differentiation. Mathematicians use a process called differentiation to determine a function's instantaneous rate of change predicated on one of its variables. The most typical illustration is velocity, which is the rate at which a distance changes in relation to time. Finding an antiderivative is the opposite of differentiation. The rate of change of signal with respect to y has been given by dy/dx if x and y are two variables. The general representation of a function's derivative is given by the equation f'(x) = dy/dx, where y = f(x) is any function.

Given that,

G(x) = [tex]\frac{1}{x^{10} }[/tex]

g’(x)=?

g’(x) is the derivative of g(x).

The derivative of [tex]x^{n} = nx^(n-1)[/tex]

[tex]x^{10} = 10x^(10-1)[/tex]

[tex]x^{10}= 10x^9[/tex]

Then,

[tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex]

Hence, The derivative of g(x) is [tex]\frac{1}{x^{10} }[/tex] = [tex]\frac{1}{10}x^{-9}[/tex].


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While at college orientation, Kate is buying some cans of juice and some cans of soda for the dorm. The juice is $0.60 per can while the soda is $0.75. Kate has $24 of dorm funds all to be spent. What is an equation that represents all the different combinations of juice and soda Kate can buy for $24 and how many different combinations of drinks are possible?

Answers

From the question the following can be derived:

(a)

Let x cans of juice and y cans of soda be purchased for the dorm. Then the cost of the juice and soda is 0.60x + 0.75y. The equation of all the combinations of juice and soda is 0.60x + 0.75y = 24.

(b)

The cost of exactly 24 cans of juice is $24 * 0.60 = $14.40. After this purchase, the remaining sum of money available is $24 - $14.40 = $9.60. This will suffice to buy 12 cans of soda, leaving a balance of $0.80. Thus. the entire money cannot be spent if exactly 24 cans of juice are purchased.

(c)

Below is a graph of the line 0.6x + 0.75y = 24 or 4x + 5y = 160 is plotted. All possible cimbinations of juice and soda will lie on this line. The x-intercept is 40 and the y-intercept is 32. Since neither of x and y can be negative, hence the lower and upper bounds for x are 0 and 40 and the lower ad upper bounds for y are 0 and 32. Also , x has to be multiple of 5 and y has to be a multiple of 4. As may be observed from the graph, only 9 combinations are possible which are (x, y):

(0, 32), (5, 28), (10, 24), (15, 20), (20, 16), (25, 12), (30, 8), (35, 4), (40, 0).

Graph:

decide wether the following sides are acute obtuse or a right triangle.

Answers

The acute triangle is defined by the condition,

[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]

Here, we have,

[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]

Thus, the triangle is an obtuse triangle.

Write each ratio using the given figure. If necessary, find the missing side.Tan P = ___________Answer?

Answers

Hello!

First, let's analyze the figure and write each side:

Analyzing it, we don't have enough information yet to calculate the tangent (because we don't know the measurement of P).

So, let's calculate the opposite side (by Pithagoras):

[tex]\begin{gathered} a^2=b^2+c^2 \\ 41^2=40^2+c^2 \\ 1681=1600+c^2 \\ 1681-1600=c^2 \\ c^2=81 \\ c=\sqrt{81} \\ c=9 \end{gathered}[/tex]

As we know the opposite side, we can calculate the tangent of P, look:

[tex]\begin{gathered} \tan(P)=\frac{\text{ opposite}}{\text{ adjacent}} \\ \\ \tan(P)=\frac{9}{40} \\ \\ \tan(P)=0.225 \end{gathered}[/tex]

Curiosity: using the trigonometric table, this value corresponds to approximately 13º.

Answer:

The tangent of P is 0.225.

Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other. Which of the following equations depicts the given situation?A. x/2 = 10B. x + 2 = 10C. 2x + 2 = 10D. None of the choices

Answers

Given:

Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other.

Required:

Which of the following equations depicts the given situation?

Explanation:

Let 10 feet long piece of wood cut into two pieces of length x(smaller piece) and

x+2 larger piece.

So, the equation will be

x + x + 2 =10

2x + 2=10

Answer:

Option C is correct.

You borrow 200 from a friend you repay the loan in two weeks and agreed to pay eight dollars for interest what is the annual percentage rate? Round your answer to the nearest 10th of a percent

Answers

10% dad, her friend owes

pls help fast I have to submit this soon!! :)

Answers

Since the rectangles are similar, that means their sides are proportional.

Since the bigger rectangle has a base of 24cm and the smaller one's base is 20cm, the proportion the sides hold is

[tex]\frac{24}{20}=1.2[/tex]

This means the sides of the larger rectangle are 1.2 times larger than those of the smaller one.

The area of the small rectangle is 80cm². Since

[tex]A=b\mathrm{}h[/tex]

where b is the lenght of the base and h is the lenght of the height, then

[tex]80=20\cdot h_1[/tex][tex]\frac{80}{20}=h_1=4[/tex]

So the height of the small rectangle will be 4cm. But as we previously deduced, the height of the larger rectangle will be 1.2 times larger than that of the smaller one, so it's height will be

[tex]h_2=4\cdot1.2=4.8[/tex]

And so, its are is

[tex]A_2=24\cdot4.8=115.2[/tex]

We can confirm this because

[tex]\frac{115.2}{80}=1.44=1.2^2[/tex]

which is the proportion the areas of the rectangles hold.

Find all the zeros of the following function.
f(x)=x^4+8x²-9

The zeros of the function are
(Use a comma to separate answers as needed. Express complex numbers in terms of i.)

Answers

All the zeros of following function f(x)=x4−8x2−9 are 3, -3, i, -i

What do you mean by the roots of function?

A number x that reduces the value of a function f to 0 is known as its root in mathematics: f(x) = 0.

Roots are actual objects since polynomials are functions as well.

Every polynomial with complex coefficients has at least one (complex) root, according to the fundamental theorem of algebra.

f(x)=x4−8x2−9

You should set (x4 - 8x2 - 9) to 0.

x4−8x2−9=0

Learn what x's value is.

Put u=x2 in the equation's place.

As a result, applying the quadratic formula will be straightforward.

u2−8u−9=0

Consider the equation x2+bx+c.

Write out the factored form (u-9)(u+1) = 0.

The answer is the set of all numbers that add up to (u9)(u+1)=0.

u=9,−1

If u=x2 has a genuine value, change it to x2=9,  x2= -1

In the case of these equations, x = +3, -3, and  -i, +i .

The whole solution is made of of the solution's positive and negative components.

x4- 8x2- 9 = 0 has a solution.

is x=3,−3, i,−i

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ABC is dilated by a factor of 5 produce A'B'C.What is A'C, the length of AC after the dilation? What is the measure of angle A?

Answers

We have that the scale factor is 5, then, the dilation is an enlargement.

Then, the new lengths are:

[tex]\begin{gathered} A^{\prime}C^{\prime}=5AC=5\cdot5=25 \\ A^{\prime}B^{\prime}=5AB=5\cdot4=20 \\ B^{\prime}C^{\prime}=5BC=5\cdot3=15 \end{gathered}[/tex]

therefore, A'C' =25.

Finally, the dilations don't affect the angles, therefore, angle A remains with the measure of 37°

write the equation of the line passing through the given points write your awnser in slope intercept form Y=mx+b (5 1) and (-3 17)

Answers

The given points are (5, 1) and (-3, 17).

First, we have to find the slope using the following formula.

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where,

[tex]\begin{gathered} x_1=5 \\ x_2=-3 \\ y_1=1 \\ y_2=17 \end{gathered}[/tex]

Let's use the coordinates above to find the slope.

[tex]m=\frac{17-1}{-3-5}=\frac{16}{-8}\Rightarrow m=-2[/tex]

The slope is -2.

Now, we use the point-slope formula to find the equation.

[tex]y-y_1=m(x-x_1)[/tex]

Let's use the same coordinates x_1 and y_1, and the slope m = -2.

[tex]y-1=-2(x-5)[/tex]

Now, we solve for y to express the equation in slope-intercept form.

[tex]y-1=-2x+10\Rightarrow y=-2x+10+1\Rightarrow y=-2x+11[/tex]Therefore, the slope-intercept form of the equation is[tex]y=-2x+11[/tex]

HELP PLEASEEEEE!!!!!!

Answers

Answer: D=2/7 R=4/7

Step-by-step explanation: there are 7 parts and D is the 2nd part R is the 4th part.

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