Answer:
barycenter is the center of mass of two or more bodies that orbit one another and is the point about which the bodies orbit. It is an important concept in fields such as astronomy and astrophysics. The distance from a body's center of mass to the barycenter can be calculated as a two-body problem.
Explanation:
Dennis the Menace is shooting a rock with his slingshot with an initial height of 5 feet. The height in feet, of the rock above the ground is given by s(t)=-16t^2+44t+5, where t is time in seconds and t is >= 0. At what time will the rock be 15 ft above the ground?
Answer: 32
The average velocity of the rock would be 32 ft per second.
The rock will be 15ft above the ground 0.25 and 2.5secs after
The height of the rock above the ground is expressed according to the expression [tex]s(t)=-16t^2+44t+5[/tex]
In order to get the time the rock will be 15ft above the ground, we will substitute s(t) = 15 ft into the formula above;
[tex]15= -16t^2+44t+5\\-16t^2+44t = 15 -5\\-16t^2+44t = 10\\-16t^2+44t- 10 = 0\\16t^2-44t+10=0[/tex]
Factorize the expression to get the value of "t"
2(4t−1)(2t−5) = 0
4t - 1 = 0
4t = 1
t = 0.25secs
Similarly 2t - 5 =0
2t = 5
t = 5/2 = 2.5secs
This shows that the rock will be 15ft above the ground 0.25 and 2.5secs after
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Rob is a high school student taking both algebra and geometry. Last night he had 27 homework problems combined from the two classes, and he took a total of 90 minutes to do them. If each algebra problem took him 2 minutes and each geometry problem took him 5 minutes, how many algebra problems did he have for homework?
Answer:
The answer is D
Explanation:
The number of algebra problems did he have for homework is 15.
The calculation is as follows:Here we assume x represent the number of algebra problems. So, the number of geometry problems was 27-x and the total working time was ...
2x +5(27 -x) = 90
-3x = 90 -135
-3x = -45
x = 15
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What is the eccentricity of an ellipse with a foci distance of 50,000,000 km and
a major axis of 100,000,000 km. (Picture not to scale)
Answer:
25,000,000 Km ;)
Explanation:
which two factors affect the amount of thermal energy an object has?
Answer:
Its The average kinetic energy and the number of particles.
Explanation:
The amount of thermal energy of the object depends on the average kinetic energy of the particles and the total number of particles in the system.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
As given in the problem statement we have to find out the two factors that affect the amount of thermal energy of the object,
The total amount of thermal energy = The average kinetic energy ×number of particles
The average kinetic energy of the particles in the system and the overall number of particles affect the object's thermal energy.
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Calculate the amount of energy a 3 kg ball on top of 10 m hill will have. Show your work with the correct ending units.
Answer:
This question is hard I will edit my answer when I find the answer
Explanation:
Do heavier bowling balls go faster than lighter ones?
Answer:
lighter ones will go faster
Explanation:
assuming you throw both bolwing ball with 10N of force. one is 3kg and the other is 5kg.
by using the equation: F = ma
a = F/m
a = 10/5 = 2m/s^2
a = 10/3 = 3.33333 m/s^2
If you kick a soccer ball and a bowling ball with the sarne force, the soccer ball
will travel farther because
1- a body at rest tends to stay at rest while a body in motion tends to stay in motion unless acted in by an unbalanced force
2- as mass increases, acceleration decreases
3- for every action, there is an equal and opposite reaction.
The mass of the bowling ball is more hence the acceleration would be less for the bowling ball so, option 2 is correct.
What is Force?In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).
Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.
The mass of the bowling ball is more hence the vertical force is more on the bowling ball thus, it will travel less in the horizontal direction.
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A clock which has brass pendulum beats seconds correctly when the temperature of the room is 30° C. how many seconds will it gain or lose per day when the temperature of the room falls to 10° C?
Answer:A::C
Solution :
ΔT=
1
2
TαΔθ
rArr Δt=
ΔT
T1t
But T′≈T
∴Δt=
1
2
αΔθ(t)
=
1
2
×0.000012×20×24×3600
=10.37s
At higher temperture, length of pendulum clock will be more. So, time period will be more and it will lose the time.
Explanation:
balance of chemical equations
Answer:
an equation is balanced when the same number of each element is represented on the reactant and product sides. equations must be balanced to accurately reflect the law of conservation of matter.
unicellular
organism are
Explanation:
Its organism are one cell I think
HALP i offer lots plz answer both questions
+brainlyest
+points
Answer:
D
Explanation:
B: false
mass of 25 kg and a KE of 450 J.
Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has
How fast is the first kid running?
answer =
Answer:
6m/s
Explanation:
high pressure
system the air moves (up/down) and brings
(good/bad) weather
Answer:
high pressure system in the air moves up and brings good weather
give me thanks >:(
the difference between endothermic and exothermic reaction
Define Work And its types
Positive Work.
Negative Work.
Case of zero work done.
Displacement at an angle to the force.
Energy.
Kinetic Energy.
work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement.
Lab partner says in newton second law by pushing a 10 KG object with 10 N and then pushed a 20 KG object with 20 in. They wanted to see effect of doubling the force of an object which choice explains why this I cannot be used to show the effect of
Answer:
must double the force, with the same masses you get twice the acceleration.
Explanation:
Newton's second law establishes a relationship between force and acceleration where the constant of proportionality is mass
F = m a
To prove these relationships you must double the force, with the same masses you get twice the acceleration.
2F = m 2a
The downside is that if you double the mass, the acceleration stays the same.
2F = 2m a
What is the chemical formula for Tetrasulfur pentoxide
( explain)
Answer:
s4n4 the chemical formula
The chemical formula of tetrasulfur pentoxide is S₄O₅, as it has four sulfur atoms and five oxygen atoms.
What is chemical formula ?Chemical formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols of elements. It also makes use of brackets and subscripts.
Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form is called empirical formula.
It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.
There are four types of chemical formula:
1)empirical formula
2) structural formula
3)condensed formula
4)molecular formula
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what is lever? state the principal of liver.
An 8.0 kg object starts from rest and is pushed with a horizontal 24.N force for 10. s on a surface with negligible friction. Then the applied force is removed and the object then encounters a rough surface and slows to a stop in an additional 10. seconds.
a) What TOTAL distance did the object cover?
The 24 N force applies an acceleration a₁ such that
24 N = (8.0 kg) a₁
a₁ = (24 N) / (8.0 kg)
a₁ = 3.0 m/s²
Starting from rest, the object accelerates at this rate for 10 s, so that it reaches a velocity v of
v = (3.0 m/s²) (10 s)
v = 30 m/s
and in these 10 s, the object travels a distance d₁ of
d₁ = 1/2 (3.0 m/s²) (10 s)²
d₁ = 150 m
When it hits the rough surface, it slows to a stop in 10 s, so that its accleration a₂ during this time is such that
0 = 30 m/s + a₂ (10 s)
a₂ = - (30 m/s) / (10 s)
a₂ = -3.0 m/s²
so that it covers an additional distance d₂ such that
d₂ = 1/2 (-3.0 m/s²) (10 s)²
d₂ = 150 m
So the object travels a total distance of d₁ + d₂ = 300 m.
Alternatively, once we find the accelerations during both 10 s intervals and the velocity after the first 10 s, we get
(30 m/s)² - 0² = 2 (3.0 m/s²) d₁
d₁ = (30 m/s)² / (6.0 m/s²)
d₁ = 150 m
and
0²- (30 m/s)² = 2 (-3.0 m/s²) d₂
d₂ = (30 m/s)² / (6.0 m/s²)
d₂ = 150 m
so that, again, d₁ + d₂ = 300 m.
Answer:
300 m
Explanation:
Displacement in the first 10 seconds:We can find the acceleration of the object by using Newton's 2nd Law: F = ma.
24 N = (8 kg) * aDivide both sides by 8.
a = 3 m/s²We can find the final velocity (v) using the acceleration since a = v/t.
3 m/s² = v/10 sMultiply 10 to both sides.
v = 30 m/sList out the variables we have for the object during its first 10 seconds in motion.
v_f = 30 m/sa = 3 m/s² t = 10 sv_i = 0 m/sWe want to solve for the displacement in the x-direction during the first 10 seconds, so we can use this constant acceleration kinematics equation:
Δx = v_0 t + 1/2at²Plug in known values into the equation.
Δx = (0 m/s)(10 s) + 1/2(3 m/s²)(10 s)²Remove units to make it easier to read.
Δx = (0)(10) + 1/2(3)(10)²0 * 10 cancels out, and we are left with:
Δx = 1/2(3)(10)²Simplify this equation.
Δx = 1.5 * 100Δx = 150 mThe displacement in the x-direction is 150 m during the first 10 seconds of the object's motion.
Displacement in the last 10 seconds:Now we want to solve for the acceleration during the last 10 seconds while the object is slowing down and stopping.
Since the object stops, the final velocity is 0 m/s. We know the final velocity of the first 10 seconds is the initial velocity of the last 10 seconds.
Let's use this constant acceleration equation to solve for a:
v = v_0 + atPlug in known variables:
0 = 30 m/s + a(10 s)Subtract 30 from both sides of the equation.
-30 = 10aDivide both sides of the equation by 10.
a = -3 m/s²List out known variables for the last 10 seconds of the object in motion:
v_f = 0 m/sa = -3 m/s² t = 10 sv_i = 30 m/sLet's use the same equation we used for the first 10 seconds since we have the same known variables:
Δx = v_0 t + 1/2at²Plug in known values:
Δx = (30 m/s)(10 s) + 1/2(-3 m/s²)(10 s)²Remove units to make the equation easier to read.
Δx = (30)(10) + 1/2(-3)(10)²Simplify this equation.
Δx = 300 - 1.5(100) Δx = 300 - 150Δx = 150 mThe displacement in the x-direction for the last 10 seconds is equal to the displacement for the first 10 seconds.
Let's add these together:
150 m + 150 m = 300 mThe total distance the object covered is 300 meters.
An Austin volleyball player bumps a 5 kg ball into the air. It reaches a height of 2.8 meters. How fast was the ball going as it got bumped into the air?
O 137.2 m/s
O 7.4 m/s
O 19.6 m/s
O 14 m/s
Answer:
v = 7.4 m/s
Explanation:
Given that,
Mass if a volleyball, m = 5 kg
The ball reaches a height of 2.8 m
We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :
[tex]mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 2.8} \\\\=7.4\ m/s[/tex]
So, the required speed is 7.4 m/s. Hence, the correct option is (b).
An object falls freely from rest through a vertical distance off 44.0m in a time of 3.0s. What value should be quoted for the acceleration of free fall?
Answer:
9.8m\sec
Explanation:
free falling neglecting the air drag so its acceleration will be the acceleration due to gravity
13. Suppose you have an object tied to a rope and are rotating it over your head in uniform circular motion. If you increase the
length of the rope, would you have to apply more or less force to maintain the same speed?
a. More force is required, because the force is inversely proportional to the radius of the circular orbit.
b. More force is required because the force is directly proportional to the radius of the circular orbit.
c. Less force is required because the force is inversely proportional to the radius of the circular orbit.
d. Less force is required because the force is directly proportional to the radius of the circular orbit.
Answer:
The correct option is (c).
Explanation:
When an object tied to a rope and we rotate it, the centripetal force acting on it. This force acts towards the center of the circle. The magnitude of the force is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
Where,
m is mass, v is speed and r is radius of path
If the length of the rope is increased, it means it will make a large circle i.e. large radius.
As we can see that force is inversely proportional to the radius of circle. It means less force is required because the force is inversely proportional to the radius of the circular orbit. Hence, the correct option is (c).
To move an object at a constant speed after increasing the length of the rope, less force is required because the force is inversely proportional to the radius of the circular orbit. Thus option C is correct.
The force applied to the object moving in a circular motion can be given by:
[tex]\rm Force\;=\;\dfrac{mass\;\times\;(speed)^2}{radius}[/tex]
From the equation, it is evident that force has been inversely proportional to the radius of the circular path. Since the length of the rope is doubled, the radius the circular path has also been doubled.
If we apply the same unit of force, the speed of the motion will increase, as speed has been directly proportional to the force applied.
Thus, to maintain the object at a constant speed, the force applied to the object has been reduced.
So, in order to move an object at a constant speed after increasing the length of the rope, less force is required because the force is inversely proportional to the radius of the circular orbit. Thus option C is correct.
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Why did boy (the observer) hear the pitch of the sound change? What does this tell us about the frequency of the sound? Support your conclusion based on results from the experiment and your knowledge of sound waves.
Answer:
because of the doppler effect
Explanation:
Remember, the doppler effect refers to the changes in sound (frequency of sound) observed by a person who is in a position relative to the wave source.
In this example, we notice as the train comes closer to the boy, the sound becomes louder also increasing the pitch slightly, the doppler effect sets in when the train passes the boy because the boy notices a decrease in the pitch of the moving train.
We learn from the change in the observed sound of the train that the frequency of the sound is determined by the distance of the observer from the wave source.
In other words, the closer the source of the sound to the observer; the faster it travels to the observer, however, the farther it is; the lesser it is; the greater the sound heard.
an object starts from rest and travels 100 m in 10 s. what will be the velocity of the object after 10 s
Answer:
10m/s (if the velocity is constant!!)
Explanation:
v=Δx/Δt=100/10=10m/s (if the velocity is constant!!) (i dont know if the letters are right in english sorry)
What is the potential difference (voltage) if the resistance of 20 ohms produces a current of 10 amperes?
Answer:
200 volts
Explanation:
Ohm's Law: V = IR
I = 10 A
R = 20 ohms
V = (10)(20) = 200 volts
Potential difference (voltage) across a resistor of 20 ohms produces a current of 10 amperes is 200V.
What is Ohms law ?Ohm's law states that the potential difference across a conductor is directly proportional to the current flowing through it.
i.e. Voltage V [tex]\alpha[/tex] I ......Voltage is directly proportional to the current flowing through a resistance.
V = RI
where R is a constant of proportionality called as resistance of Resistor. it opposes flow of current and it is measured in ohm(Ω). ohm's law gives the voltage drop across a resistor. large resistor gives large voltage drop across it.
Given,
Resistance R = 20 Ω
Current I = 10 A
Voltage V = ?
By using formula,
V = IR
V = 10×20
V = 200V
Hence potential difference across the resistor is 200V
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A simple machine where an inclined plane is wrapped in a spiral is called a centripetal ramp.
T.
True
F.
False
Answer: False
Explanation:
Imagine a 0.2 kg ball moving at 5 m/s colliding with a 0.3 kg ball moving at 2 m/s in the same direction. After the collision the 0.2 kg green ball stops moving and the 0.3 kg purple ball continues moving in the same direction.
Answer:
[tex]m1v1 + m2v2 = m1v3 + m2v4[/tex]
[tex](0.2 x 5) + (0.3 x 2) = (0.2 x 0) + (0.3 x v4)[/tex]
[tex]1.0 + 0.6 = 0 + 0.3v4, 0.3v4 = 1.6[/tex]
[tex]v4 = 1.6/0.3 = 5.3 m/s (2 sf)[/tex]
Lab work
Part 1-Prove distance from the object to the mirror is the same as 4 trails. ??
Part 2-Show Image by Reflection and Refraction and also calculate the angle of Refraction with the help of snells law. ??
Answer:
The distance between the object and the mirror is X/2
Explanation:
If we look into a plane mirror, we see the image of our face situated behind the mirror. Now, if we move backwards, the image also moves backwards in the mirror so that it is always at the same distance behind the mirror as our face is in front of the mirror. Thus, the image I in a plane mirror is as far behind the mirror as the object O is in front of it. In other words, the distance of the image from the plane mirror is equal to the distance of the object from the plane mirror. We will prove this fact by using the laws of reflection and simple geometry.
From the second law of reflection, we have:Angle of incidence = Angle of reflection
So, NAO = NAX (angle i = angle r)
It is clear that the triangles MIA and MOA are congruent triangles and, therefore, their corresponding sides should be equal. Thus :
IM = OM
MA is a common side to both triangles
Now, OM represents the distance of object from the mirror, and IM represents the distance of image from the mirror .
So, we can now say that:
Distance of image from mirror = Distance of object from mirror
What does aerospace engineering have to do with physics
10. How does surface area affect the amount of air resistance an object experiences?
Answer:cross-sectional area, and thus surface area, increases the amount of air resistance an object experiences
Explanation:
