Boxes A and B are in contact on a horizontal, frictionless surface. Box A has mass 20.0 kg and box B has mass 5.0 kg. A horizontal force of 100 N is exerted on box B. What is the magnitude of the force that box B exerts on box A

Answer:

False

Explanation:

Charges only be transferred from one system to another. Materials that permit electrons to move freely through them, such as most metals

khanacademy

The change in momentum of the object between 0 and 4s is 40 Ns.

The momentum of an object is determined from the product of mass and velocity of the object.

The change in momentum of an object is equal to the impulse received by the object.

ΔP = J = Ft

where;

The change in momentum of the object between 0 and 4s is calculated as follows;

ΔP = Ft

ΔP = 10 x 4

ΔP = 40 Ns

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Answer:

lil durk a goat

Explanation:

Answer:

10,100 N

Explanation:

m - 1 ton = 1,000 kg

v₀ = 40 m/s, v = 0

d = 80 m

f = 100 N

Net force = F + f = ma

v² - v₀² = 2ad, so a = (v² - v₀²)/(2d) = (0 - 40²)/(2*80) = -10 m/s²

F = ma - f = 1,000*(-10) - 100 = -10,100 N

negative sign means opposite to the driving direction

This depends on how big the bag is. Most commonly, the bag weighs 2 kg to 10 kg or more. With this range of weight, Siobhan should use a balance to measure the mass of the flour and record the mass in kilograms. Thus, the answer is the first choice

Answer:

A weighing scale

Explanation:

A weighing scale graduated in grams or kilograms can be used.

The magnitude of the tension in the string is 9.31 N.

The magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;

T = Fcos(θ)

where;

[tex]T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N[/tex]

Thus, the magnitude of the tension in the string is 9.31 N.

The complete question is below:

A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.

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Answer:

B. 2.3 x 10⁶

Explanation:

To calculate scientific notation for the number 2,300,000, we have to follow this notation

Step 1 :

To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.

Step 2 :

Now, to find b count how many numbers of digits are there to the right of the decimal.

Hence, there are 6 digits to the right of the decimal.

Step 3 :

Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.

a = 2.3

b = 6

Therefore, option b is correct.

T sin θ = M g = W     cable supporting weight

T = 100 * 9.8 / sin 40 = 1525 N

T cos θ = Th horizontal force due to cable

Th = 1525 cos 40 = 1168 N

The maximum velocity of the collar is 0.335 m/s.

The maximum velocity of a simple harmonic motion occurs when the object is in equilibrium position.

K.E = U

¹/₂mv² = ¹/₂kx²

mv² = kx²

where;

[tex]v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{316.36 \times 0.0254^2}{1.81} }\\\\v = 0.335 \ m/s[/tex]

Thus, the maximum velocity of the collar is 0.335 m/s.

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Answer:

8.0 rad/s

Explanation:

I₁ = 1.0 kgm², ω₁ = -20.0 rad/s (clockwise is positive direction)

I₂ = 4.0 kgm², ω₂ = 15.0 rad/s

Angular momentum conservation:

I₁ω₁ + I₂ω₂ = (I₁ + I₂)ω

1.0 x (-20.0) + 4.0 * 15.0 = (1.0 + 4.0)ω

40.0 = 5.0ω

so ω = 8.0 rad/s

Answer:

true,because when the gravity of an object is changed the motion of the object changes

The athlete must leave the ground with a speed of 6.33m/s.

To calculate the initial speed, with the information of height and final speed, we can use the following expression that uses the kinetic energy and potential energy:

                               [tex]mgh_1 + \frac{1}{2}mv_1^{2}= mgh_2 + \frac{1}{2}mv_2^{2}[/tex]    

Applying the values ​​given by the statement we have:

                           [tex]9.81\times 0 + \frac{1}{2}v_1^{2} = 9.81 \times 2 + \frac{1}{2}(0.95)^{2}[/tex]      

                                             [tex]v_1 = 6.33m/s[/tex]

So, the athlete must leave the ground with a speed of 6.33m/s.

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Answer:

The frequency and wavelength of a wave are related. When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases.

Explanation:

Answer: The waves travel at the same speed, but the observed frequency depends on any relative motion between the observer and source. When the observed frequency changes, so does the wavelength. If the observer and source are moving toward each other, then the frequency increases and the wavelength decreases.

Explanation: I hope this helped you understand

The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m²

Pressure can be defined as the force acting perpendicular per unit area on the surface of a body. The S.I unit of pressure is N/m²

To calculate the pressure of the wheel of the tricycle, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m².
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The final momentum of the ball is 3.8 kgm/s.

The impulse received by the ball is equal to change in momentum of the ball.

J = ΔP

where;

ΔP = P₂ - P₁

P₂ = ΔP + P₁

The final momentum of the ball is calculated as follows;

P₂ = 8 + (- 0.1 x 42)

P₂ = 8 - 4.2

P₂ = 3.8 kgm/s

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The location of  image and the height of the image is mathematically given as

di = -40 cm

h=8 cm

upright and enlarged

Question Parameters:

Generally the equation for the   is mathematically given as

using mirror equation

1/f = (1/do) + (1/di)

Therefore

1/40 = (1/20) + (1/di)

di = -40 cm

Therefore, Magnification

m = -di/do = hi/h\

m = 40/20 = hi/4

m = 2 = hi/4

image height is

hi = 4*2

h=8 cm

upright and enlarged

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The tension in the connecting string is 14.7 N.

The net force of the masses is calculated as follows;

[tex]F_{net} = Mgsin(\theta)+ Mg[/tex]

The acceleration of the masses is calculated as follows;

[tex]a = \frac{F_{net}}{M+ M} = \frac{M(gsin\theta + g)}{2M} = \frac{gsin\theta + g}{2} \\\\a = \frac{9.8sin(30) \ + \ 9.8}{2} = 7.35 \ m/s^2[/tex]

The tension in the connecting string is calculated as follows;

[tex]mg - T = ma\\\\T = mg - ma\\\\T = m(g - a)\\\\T = 6(9.8 - 7.35)\\\\T = 14.7 \ N[/tex]

Thus, the tension in the connecting string is 14.7 N.

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Answer:

It does not affect. The closest nebula is the Orion Nebula at more than 1300 light years from Earth. It is so remote that nothing that happens there can influence the Earth. The only influence is to have beautiful colors and shapes and to let us dream one day to go there and explore them.

Explanation:

Answer: Can't see clearly.

Explanation:

Hi there!

Informative writing has the intent to inform or educate us on a particular topic or event. It gives us more information and insight onto something.

Persuasive writing has the intent of convincing us to believe in a certain idea or to perform a certain action. For instance, advertisements have a persuasive intent; they are persuading us to buy a product or service.

Argumentative writing is similar to persuasive writing in the sense that they are persuading us to believe a certain idea. However, they are often based on logic and fact rather than opinions.

Let's look at the first excerpt.

This morning at 9 a.m., a school bus collided with a car at the intersection of Osmena and Cabrera streets. The passengers were not injured, but the medical personnel checked each student as well as the driver before they were transported to their school.

This text doesn't try to convince us in believing something. It doesn't argue anything and it only tries to give us more insight onto the event, which is a car accident. No opinions are stated and only events are given.

Therefore, this excerpt uses an informative writing technique.

Answer:

1. Informative
2. Persuasive
3. Informative
4. Persuasive
5. Argumentative

Explanation:

Informative is a way to inform the audience on a particular topic throughout the reading. Common examples of an informative paragraph would be to inform people on different situations around the world or a news outlet some would say.

Persuasive is a way to convince one to change/commit an act of sorts. Through persuasion you can convince your audience to look at a situation from a different perspective and perhaps convince the person to be more willing to do change the way they do something else. Common example of a persuasive paragraph would be trying to persuade someone to use less water through telling them the importance of water conservation and how water is a nonrenewable source.

Argumentative somewhat similar to persuasive but is more assertive you are trying to convince the audience why the side you're apart of is more better then the opposite side through a means of ethos, pathos, and logos. Common example of a argumentative paragraph would be something like why pizza is better then hamburgers.

Now that we know this information it's time to answer:

Excerpt one:
Excerpt one is known "informative excerpt" because we are informing the readers about how a school bus collided with a car nearby, and how thankfully none of the passengers were injured.

Excerpt two:
Excerpt two would be known as a "persuasive writing." We aren't trying to convince the audience on our side of donating blood so this won't be an argumentative writing, we are trying to persuade them by saying the benefits of how donating blood can save a person's life.

Excerpt three:
Excerpt three would be known as an "informative writing." We aren't trying to persuade or convince we are trying to inform the audience of the dangers of drinking while in high school by listing all the negative effects drinking has on a highschooler like unsafe encounters.

Excerpt four:
Excerpt four would be known as an "persuasive writing." This writing is trying to convince the reader about how the death penalty is a good punishment for criminals because the bible says an eye for an eye and how we should keep it on the books.

Excerpt five:
The final excerpt will be known as an "argumentative writing." This writing is again assertive, and it lists both sides of the spectrum how parents won't let their children study abroad because of how expensive it costs for things like tuition, food, shelter along with other necessities. It even goes as far as stating it's own position by saying how it's expensive to study abroad.

Hope this helps.

Answer:

by increasing the distance through which force is applied, by multiplying force of speed to the energy applied

The first user who answer is correct :)

A fundamental frequency of 60 Hz, attached mass of 1 kg., rod length of

0.3 m gives the mass of the part of the string as 3.245 × 10⁻³ kg.

Response:

The given parameters are;

Mass of the sphere, M = 1.00 kg

Length of the rod, L = 0.300 m

Angle the string makes with the rod, θ = 35°

The fundamental frequency of the standing wave in the portion of the

string above the rod, f₁ = 60.0 Hz

Required;

The mass of the portion of the string above the rod

Solution:

The fundamental frequency in a string is given as follows;

Where;

T = The tension in the string

m = The mass of the string

l = The length of the string

Which gives;

[tex]T= \mathbf{\dfrac{1 \times 9.81}{sin(35)}} \approx 17.1[/tex]

The tension in the string, T ≈ 17.1 N

Therefore;

[tex]l=\dfrac{0.300}{cos \left(35^{\circ} \right)} \approx 0.366[/tex]

Therefore;

[tex]60.0 = \mathbf{\dfrac{\sqrt{\dfrac{17.1}{m/0.366} } }{2 \times 0.366}}[/tex]

Which gives;

[tex]m = \dfrac{17.1}{(60.0 \times 2 \times 0.366)^2} \times 0.366 \approx 3.245 \times 10^{-3}[/tex]

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Answer:

It's is c coz the weight is equal to the normal force

Answer:

Juan Pablo Duarte was a Dominican military leader, writer, activist, and nationalist politician who was the foremost of the founding fathers of the Dominican Republic.