Which is the primary lunar phase that takes place one week after the first quarter.

at the same distance behind the mirror

They realized this as result of the number of sunspots getting larger and smaller over the course of the years .

This is defined as a temporary phenomena on the Sun's photosphere that appear as spots darker than the surrounding areas.

The presence of these sunspots is what gave Astronomers the idea of the Sun having varying levels of activities over the years.

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The term cause and effect relationship relates to a situation where an effect is directly traceable to a cause.

The term cause and effect relationship relates to a situation where an effect is directly traceable to a cause. The question is incomplete and the article was not mentioned.

A typical example of cause and effect relationship is that increased fossil  fuel use is leading to a rise in the average temperature of the planet.

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Answer:

Measurement is called the process of finding exact quantity of a substances.

Answer:

1st blank: warmer    2nd blank: cooler

Explanation:

Heat energy always flows from the warmer object to the cooler object.

Heat always transfers from substances with high thermal energy to substances with low thermal until both substances reach the maximum temperature

Answer:

Because Studying helps us for a better life.

Explanation:

If we study well enough we can pass entrance exams for really nice colleges and universities, from that we can learn med school IIT, etc.

From doing that we can get a stable job and earn money then in the end, relax :)

The radius of the track in the circular motion is 0.164 mm.

The magnetic force of the charge is calculated as follows;

F = qvB

The centripetal force experienced by the charge is calculated as follows;

[tex]F = \frac{mv^2}{r}[/tex]

[tex]qvB = \frac{mv^2}{r} \\\\qB = \frac{mv}{r} \\\\r = \frac{mv}{qB} \\\\[/tex]

The radius of the track is calculated as follows;

[tex]r = \frac{9.1 \times 10^{-31} \times 5.5 \times 10^6}{1.6 \times 10^{-19} \times 0.19} \\\\r = 1.64 \times 10^{-4} \ m\\\\r = 0.164 \times 10^{-3} \ m\\\\r = 0.164 \ mm[/tex]

Thus, the radius of the track in the circular motion is 0.164 mm.

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This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the number density of all ideal gasses at SATP is the same, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

[tex]PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}[/tex]

And plug in the numbers we are given:

[tex]\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3[/tex]

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

[tex]2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}[/tex]

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Answer:

initial KE = final PE

1/2 m v^2 = m g h

h = v^2 / (2 * g) = 3.2^2 / (2 * 9.8) = .52 m    height of ramp

Answer:

The magnetic field strength of an electromagnet is therefore determined by the ampere-turns of the coil with the more turns of wire in the coil the greater will be the strength of the magnetic field

Explanation:

Answer:

inertia

Explanation:

law of inertia describe it

It is the inertia of the body which describes the existing state of rest or uniform motion in a straight line.

The inertia of the body is defined as If the body is at rest then it will be at the same state until an external force is not applied to it.

Similarly, If the body is in motion then it will remain in motion until and unless an external effort is not applied to stop it.

For example, if the football is placed at the rest on the ground it will never move from the same position until an external force is not applied.

Similarly, if the car is moving at a certain speed then it will only stop if the brakes are applied and if there is not any friction it will never stop.

Thus the inertia of the body describes the existing state of rest or uniform motion in a straight line.

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Answer:

Heat flows from hot to cold objects. When a hot and a cold body are in thermal contact, they exchange heat energy until they reach thermal equilibrium, with the hot body cooling down and the cold body warming up. This is a natural phenomenon we experience all the time.

Explanation:

Answer:

b

Explanation:

because it has the biggest number

Answer: A watt unit is equal to 1 joule/sec.

Explanation:  So you have a lightbulb with 50% efficiency, so it turns half the energy it consumes into light energy.

5 answers

Answer:

Approximately [tex]1.1 \times 10^{4}\; {\rm Pa}[/tex] and [tex]8.0 \times 10^{3}\; {\rm Pa}[/tex], respectively (assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].)

The [tex]55.5\; {\rm kg}[/tex] box exerts more pressure than the [tex]65.5\; {\rm kg}[/tex] box.

Explanation:

Let [tex]m[/tex] denote the mass of the [tex]55.5\; {\rm kg}[/tex] box.

The weight of that box would be: [tex]W = m\, g[/tex].

The normal force [tex]N[/tex] that this box exerts on the ground would be the same as its weight: [tex]N = W = m\, g[/tex].

If the contact area between the box and the ground is [tex]A[/tex], the pressure [tex]P[/tex] that this box exerts on the ground would be [tex]N / A[/tex]. That is:

[tex]\displaystyle P = \frac{N}{A}= \frac{m\, g}{A}[/tex].

The contact area between the ground and this [tex]55.5\; {\rm kg}[/tex] box is [tex]A = 0.25\; {\rm m} \times 0.20\; {\rm m}[/tex]. Substitute in these values and evaluate to find the pressure:

[tex]\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{55.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.25\; {\rm m} \times 0.20\; {\rm m}} \\ & \approx 1.1 \times 10^{4}\; {\rm Pa}\end{aligned}[/tex].

Similarly, for the [tex]65.5\; {\rm kg}[/tex] box:

[tex]\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{65.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.20\; {\rm m} \times 0.40\; {\rm m}} \\ & \approx 8.0 \times 10^{3}\; {\rm Pa}\end{aligned}[/tex].

Thus, the [tex]55.5\; {\rm kg}[/tex] box exerts greater pressure on the ground than the [tex]65.5\; {\rm kg}[/tex] box.

If we pass light through two narrow slits. then a double-slit interference pattern will form.

When light is passed through two narrow slits, an interference pattern will be formed on a distant screen. This is known as the double-slit interference pattern.

The interference pattern is formed because the light passing through each slit interferes with the light passing through the other slit. The light waves can either reinforce or cancel each other out, depending on the phase relationship between them.

On the screen, there will be alternating bright and dark fringes, with the brightest fringes corresponding to constructive interference, where the waves are in phase, and the darkest fringes corresponding to destructive interference, where the waves are out of phase.

The pattern will have a series of bright bands, called interference maxima, where the bright fringes occur, separated by dark bands, called interference minima, where the dark fringes occur. The position of the maxima and minima will depend on the wavelength of the light, the distance between the slits, and the distance between the slits and the screen.

This interference pattern is a classic example of the wave nature of light, and it played an important role in the development of quantum mechanics.

Hence, when we pass the light through two narrow slits a double-split interference is formed.

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Answer:

there are some ups and downs in life and particle is describing it as a result of happiness

The value of the electric force acting on the charge will be 0.9 N.The electric force is the product of the charge and the electric field strength.

What is electric force?

The electric force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is;

q is the  charge = 4. 5 × 10⁻⁵ C

E is the electric field strength.=2.0 ×10⁴

F is the electric force=?

The electric force is given as;

[tex]\rm F = qE \\\\ \rm F = 4.5 \times 10^{-5} \times 2.0 \times 10^4 \\\\ \rm F =0.9 \ N[/tex]

Hence the value of the electric force acting on the charge will be 0.9 N.

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Answer:

11-false

12-false

13-false

14-false

15-false

Explanation:

11- Magnets only attract metal

12- They will repel not pull together

13- The magnet on the horseshoe is only magnetic to the hoof

14-Two opposites on a magnet will attract  eachother

15-NOOO

Answer: It is the act of measuring internal resistance.

Explanation:

It should be understood that when that action is exhibited, it is towards of measuring the internal resistance.

And it should be noted that, no matter how much or little load we attach to the battery, the voltage at the source's terminals will always stay the same.

Ф = E S is the total flux

Assuming the charge is at the origin-

The flux will be the same for all sides

The total area is 6 m^2

Ф = 6 * 1 N-m^2 / C = 6 N-m^2 / C

The total charge in the box is then 6 C (oulombs)

(Remember F = Newtons = E Q so E is in N/C

The astronomical event corresponds to the passage of 1 year is the Earth making one revolution about the Sun.

"Astronomical events" refers to occurrences that astronomy examines, such as eclipses or novae, whereas astronomy events refers to meetings, conferences, and other significant astronomy-related events.

In conclusion, The earth revolves the sun in one year

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Explanation:

An object which moves 10 km in 30 minutes .

we have to find the average speed of the object .

Changing unit of time into hour

Time = 30/60 hour

Time = 1/2 hour

Time = 0.5 hour

Now let's calculate the average speed

[tex] \rm\bf \: Average \: speed \: = \frac{Total \: distance}{Total \: time \: } [/tex]

Put the value we get

[tex] \dashrightarrow \sf \: Average \: speed \: = \frac{10}{0.5} \\ \\ \dashrightarrow \sf \: Average \: speed \: = \frac{100}{5} \\ \\ \dashrightarrow \sf \: Average \: speed \: = \cancel \frac{100}{5} \\ \\ \dashrightarrow \sf \: Average \: speed \: =20km {hr}^{ - 1} [/tex]

So, the average speed is 20km/hr

The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

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Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

XO

also i ate a apple