To determine the better buy you have to calculate how much one package costs in each shop.
1) 6 packages cost $15.00
If you use cross multiplication you can determine how much 1 package costs:
6 packs ______$15.00
1 pack _______$x
[tex]\begin{gathered} \frac{15.00}{6}=\frac{x}{1} \\ x=\frac{15}{6}=\frac{5}{2}=2.5 \end{gathered}[/tex]Each package costs $2.5
2) 5 packages cost $13.25
5packs_____$13.25
1 pack______$x
[tex]\begin{gathered} \frac{13.25}{5}=\frac{x}{1} \\ x=\frac{13.25}{5}=2.65 \end{gathered}[/tex]Each package costs $2.65
For the second purchase each package cost $0.15 more than in the first purchase.
Is best to buy the 6 packages at $15.00
Statistics: a professor recorded 10 exam grades but one of the grades is not readable. if the mean score on the exam was 82 and the mean of the 9 readable scores is 84 what is the value of the unreadable score?
To mean of a set is given by the sum of all values in the data-set divided by the number of values.
We have that the mean of the whole set is 82.
The mean of the 9 readable scores is 84.
So:
[tex]\begin{gathered} \frac{x}{9}=84 \\ x=84\cdot9 \\ x=756 \end{gathered}[/tex]So, we 9 readable scores add up to 801. If we add 756 to a number, y, and divide by 10, we'll have the mean score of the exam, 82.
[tex]\begin{gathered} \frac{756+y}{10}=82 \\ 756+y=820 \\ y=820-756 \\ y=64 \end{gathered}[/tex]So, the grade of the unreadable score was 64.
Someone help me please
Approximately 5 meters long.
ocupo encontrar la x con procedimiento
les regalare coronas!!!!
La variable x asociada al sistema geométrico con dos ángulos alternos externos es igual a 23.
¿Cómo determinar la variable asociada a dos ángulos alternos externos?
En esta pregunta tenemos un sistema geométrico conformado por dos líneas paralelas atravesadas por una tercera línea. Este conjunto incluye dos ángulos alternos externos, que guardan la siguiente relación según la geometría euclídea:
6 · x - 28 = 4 · x + 18
A continuación, despejamos la variable x:
6 · x - 4 · x = 28 + 18
2 · x = 46
x = 23
El valor de la variable x es 23.
ObservaciónNo existen preguntas en español sobre ángulos alternos externos, por lo que se añade una pregunta en inglés.
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Find the midpoint M of the line segment joining the points R = (-5. -9) and S = (1. -1).
Answer:
(-2,-5)
Step-by-step explanation:
(-5+1÷2, -9+(-1)÷2)
=(-4÷2, -10÷2)
=(-2,-5)
Plot ( 0 -5/8) on the coordinate axes. Where is it located? State the axis or the quadrant.
We need to plot the coordinate (0, -5/8).
An ordered pair (x, y) represents the location of the point in the coordinate plane. Based on the given, we have x = 0 and y = -5/8. No movement will happen around the x-axis since we have x = 0. Since y is a negative number, we will go down on the y axis from the origin depending on the value of y.
We see that our y value is equal to -5/8. What we can do first is to represent each grid to be equal to 2/8. There are 4 grids that we will encounter before going to -1. At the second grid, the value is (2/8)*2 = 4/8. At the third grid, we have (2/8)*3 = 6/8. The middle term for these two fractions is equal to 5/8, hence, the plot of (0, -5/8) will be around:
Based on the plot above, the coo
Find the slope and the x- & y-intercepts of x + 2y = 6(5 pts) (Show work for finding X- & y-intercepts)
First, we need to write our equation in standard form — the y should be on the left- hand - side and the x should be on the right- hand side.
The first step is to subtract x from both sides, doing this we get:
[tex]2y=6-x[/tex]Now we divide both sides of the equation by 2 (this isolates the y on LHS), doing this gives us:
[tex]y\text{ = }\frac{6-x}{2}[/tex]which can also be written as
[tex]y=\frac{-x}{2}+3[/tex]The y-intercept is the point at which the line described by our equation intersects the y-axis. This intersection happens when x = 0; therefore, the y-intercept is
[tex]y=\frac{-0}{2}+\text{ 3}[/tex][tex]y=0\text{.}[/tex]The x-intercept is the point at which the line intersects the x-axis. This happens when y =0; therefore, the x-intercept is
[tex]0=\frac{-x}{2}+3[/tex][tex]-3\text{ = }\frac{-x}{2}[/tex][tex]x\text{ = 6.}[/tex]Now we see that the slope of the equation is -1/2 (the coefficient of x ). The y-intercept is y = 3 and the x-intercept is 6.
A bucket can hold 26 litres of water when it is 8/9 full. How many litres can it hold when it is full?
Answer:
[tex]29.25\text{ liters}[/tex]Explanation:
Here, we want to know the amount of water the bucket can hold when full
Let us have the volume as x liters
Mathematically:
[tex]\begin{gathered} \frac{8}{9}\times x\text{ = 26} \\ \\ 8x\text{ = 9 }\times\text{ 26} \\ x=\text{ }\frac{9\times26}{8} \\ \\ x\text{ = 29.25 liters} \end{gathered}[/tex]Solve for y.
|6y + 12| = -18
Answer: y=-5
Step-by-step explanation:
12-12=0
-18-12=-30
6y=-30
y=-5
resents "three lessWrite the expression -- 5x(4 + 3x) using words,the sum of negative five times a number andfour minus three times the numberthe product of negative five times a numberand the quantity four plus three times thenumberthe product of three times a number plus thequantity four and five times the numberpresents "thetwo less than theDONE
Given:
[tex]=-5x(3x+4)[/tex]Sol:.
The product of negative five times a number and the quantity four plus three times the number.
simplify 5(3c-4d)-8c
Answer:
7c - 20d
Step-by-step explanation:
5(3c - 4d) - 8c ← distribute parenthesis by 5
= 15c - 20d - 8c ← collect like terms
= 7c - 20d
Cindy eats 12 oz of candy in 4 days how long will it take her to eat 1 pound of candy
We should know that:
1 pound = 16 oz
given Cindy eats 12 oz in 4 days
She will eat 1 pound in x days
So, we need to find the number of days to eat 1 pound which is equal to 16 oz
Using the ratio and proportion
12 : 4 = 16 : x
[tex]\begin{gathered} 12\colon4=16\colon x \\ \frac{12}{4}=\frac{16}{x} \\ x=\frac{4\cdot16}{12}=\frac{16}{3}=5\frac{1}{3} \end{gathered}[/tex]so, the number of days = 5 1/3
Are the two triangles similar? If so, state the reason and the similarity statement
Two sides are in same proportion and the included angle is common as per SAS. Therefore, both the triangles are similar.
Triangle:
A triangle is the three-sided polygon, which has three vertices. The three sides are interconnected with each other end to end at a point, which forms the angles of the triangle.
Here there are two triangles KLP and KMN. And the sum of all three angles of the two triangle is equal to 180 degrees.
Given,
Here we have the two triangle and we need to find that they are similar or not.
For that we have to calculate the total length of the sides of the triangle,
That,
KM = KL + LM
KM = 8 + 2 = 10
Similarly,
KN = KP + PN
KN = 12 + 3 = 15
In triangles KLP & KMN,
KL/KP = 8/12 = 2/3
Similarly, for the triangle KMN,
KM/KN = 2/3
Here the angles have the same values so they are parallel. Which states that, Angle O is common in both the triangles.
Therefore, the two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar.
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Use the formula for the probability of the complement of an event.A single card is drawn from a deck. What is the probability of not drawing a 7?
occur
the answer is 12/13 or 0.932
Explanation
when you have an event A, the complement of A, denoted by.
[tex]A^{-1}[/tex]consists of all the outcomes in wich the event A does NOT ocurr
it is given by:
[tex]P(A^{-1})=1-P(A)[/tex]Step 1
find the probability of event A :(P(A)
The probability of an event is the number of favorable outcomes divided by the total number of outcomes possible
[tex]P=\frac{favorable\text{ outcomes}}{\text{total outcomes}}[/tex]so
let
favorable outcome = 4 (there are four 7 in the deck)
total outcomes=52
hence,replacing
[tex]\begin{gathered} P=\frac{4}{52}=\frac{1}{13} \\ P(A)=\frac{1}{13} \end{gathered}[/tex]Step 2
now, to find the probability that the event does NOT ocurrs ( not drawing a 7)
let's apply the formula
[tex]P(A^{-1})=1-P(A)[/tex]replace
[tex]\begin{gathered} P(A^{-1})=1-\frac{1}{13} \\ P(A^{-1})=\frac{13-1}{13}=\frac{12}{13} \\ P(A^{-1})=0.923 \end{gathered}[/tex]therefore, the answer is 12/13 or 0.932
I hope this helps you
f(x)=3x-4g(x)=-x^2+2x-5h(x)2x)^2+1j(x)=6x^2-8xk(x)=-x+7calculate (g+j)(x)
To calculate (g+j)(x) we need the function:
[tex]\begin{gathered} g(x)=-x^2+2x-5 \\ j(x)=6x^2-8x \end{gathered}[/tex]and we can made the addition so:
[tex]\begin{gathered} (g+j)(x)=g(x)+j(x) \\ (g+j)(x)=-x^2+2x-5+6x^2-8x \end{gathered}[/tex]and we can simplify
[tex](g+j)(x)=5x^2-6x-5[/tex]In a blood testing procedure, blood samples from 6 people are combined into one mixture. The mixture will only test negative if all the individual samples are negative. If the probability that an individual sample tests positive is 0.11. What is the probability that the mixture will test positive?
From the information available, the mixture will test negative if all 6 samples are negative.
The probability of each is independent of the other for all 6 samples.
The probability of a sample testing positive is 0.11. That means the probability of a sample testing negative would be
[tex]\begin{gathered} P\lbrack neg\rbrack=1-P\lbrack pos\rbrack \\ P\lbrack\text{neg\rbrack}=1-0.11 \\ P\lbrack\text{neg\rbrack}=0.89 \end{gathered}[/tex]However, for all 6 samples, the probability of having a negative result would be a product of probabilities, that is;
[tex]\begin{gathered} P\lbrack tests\text{ negative}\rbrack=0.89\times0.89\times0.89\times0.89\times0.89\times0.89 \\ P\lbrack\text{tests negative}\rbrack=0.89^6 \\ P\lbrack\text{tests negative\rbrack}=0.4969 \end{gathered}[/tex]Therefore if we have the probability of the mixture testing negative as
[tex]P_{\text{neg}}=0.4969[/tex]The probability of the mixture testing positive would be;
[tex]\begin{gathered} P_{\text{pos}}=1-P_{\text{neg}} \\ P_{\text{pos}}=1-0.4969 \\ P_{\text{pos}}=0.5031 \end{gathered}[/tex]ANSWER:
The probability that the mixture will test positive is 0.5031
Rounded to 2 decimal places,
[tex]P_{\text{pos}}=0.50[/tex]Which of the following actions will best help her find out whether the two equations in the system are in fact parallel
Check to see whether the slope of both lines are the same (option A)
Explanation:[tex]\begin{gathered} \text{Given} \\ y\text{ - x = }21 \\ 2y\text{ = 2x + 16} \end{gathered}[/tex]When two system of equations do not intersect, the lines are said to be parallel lines.
This means there is no solution.
To determine if the lines are trully parallel, the slope of each equation need to be determined.
For parallel lines, the slope will be the same
The best action to help her find out whether the two equations are inded parallel, Check to see whether the slope of both lines are the same (option A)
Reduce the rational expression to lowest terms. If it is already in lowest terms, enter the expression in the answerbox. Also, specify any restrictions on the variable.a²-3a-4/a² + 5a + 4Rational expression in lowest terms:Variable restrictions for the original expression: a
Factorize both quadratic polynomials, as shown below
[tex]\begin{gathered} a^2-3a-4=0 \\ \Rightarrow a=\frac{3\pm\sqrt{9+16}}{2}=\frac{3\pm\sqrt{25}}{2}=\frac{3\pm5}{2}\Rightarrow a=-1,4 \\ \Rightarrow a^2-3a-4=(a+1)(a-4) \\ \end{gathered}[/tex]Similarly,
[tex]\begin{gathered} a^2+5a+4=0 \\ \Rightarrow a=\frac{-5\pm\sqrt{25-16}}{2}=\frac{-5\pm3}{2}\Rightarrow a=-1,-4 \\ \Rightarrow a^2+5a+4=(a+1)(a+4) \end{gathered}[/tex]Thus,
[tex]\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{(a+1)(a-4)}{(a+1)(a+4)}[/tex]Therefore, since the denominator cannot be equal to zero.
The variable restrictions for the original expression are a≠-1,-4Then, provided that a is different than -1,
[tex]\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{x-4}{x+4}[/tex]The rational expression in the lowest terms is (x-4)/(x+4)18
If p percent of an adult's daily allowance of
potassium is provided by x servings of Crunchy
Grain cereal per day, which of the following
expresses p in terms of x ?
Express p in terms of x : p = 5x
What is Percent?
A percentage is a figure or ratio stated as a fraction of 100 in mathematics. Although the abbreviations "pct.", "pct.", and occasionally "pc" are also used, the percent symbol, "%," is frequently used to indicate it. A % is a number without dimensions and without a measurement system.
If 5% of an adult's daily potassium requirement is provided by each serving of Crunchy Grain cereal, then x servings will offer x times 5%.
Five times as many servings, or p, of potassium are required for an adult's daily requirement.
As a result,
p = 5x can be used to describe the proportion of potassium in an adult's daily allotment.
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in ️RST, RS ~=TR and m
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
ΔRST
RS ≅ TR
∠ T = 15
∠ S = ?
Step 02:
We must apply the properties of isosceles triangles.
∠ T = ∠ S = 15
The answer is:
∠ S = 15 °
In a data set, the median is less than the mean. What does that indicate about the data?A.It is skewed to the right.B.It is skewed to the left.C.It is symmetric.D.It is bell-shaped.
SOLUTION:
Step 1:
In this question, we are given the following:
In a data set, the median is less than the mean. What does that indicate about the data?
A. It is skewed to the right.
B. It is skewed to the left.
C. It is symmetric.
D. It is bell-shaped.
Step 2:
The diagram that explains the question above is:
A left-skewed distribution has a long left tail. Left-skewed distributions are also called negatively-skewed distributions. That’s because there is a long tail in the negative direction on the number line. The mean is also to the left of the peak.
A right-skewed distribution has a long right tail. Right-skewed distributions are also called positive-skew distributions. That’s because there is a long tail in the positive direction on the number line. The mean is also to the right of the peak.
Back to the question, in a data set, the median is less than the mean
It indicates that:
It is skewed to the right ( OPTION A )
You need to measure the depth of a large lake. Since the sonar equipment is very expensive, you decide to use your friend's boat. The boat has an anchor on a 100 ft line. You take the boat out to the middle of the lake on a
windy day. You drop the anchor and let the wind push the boat until the anchor line is tight. Your GPS tells you that the boat has moved 82 feet. Assuming the bottom of the lake is flat, what is the depth of the lake?
Using the Pythagorean Theorem, the depth of the lake is 57.24 feet.
What is the depth?According to the Pythagorean Theorem, the depth or height is the difference between the squared root of the hypothenuse and the base.
The Pythagorean Theorem Formula is as follows:
a² + b² = c²
Where:
a = side of the right triangle (height, depth, or perpendicular)
b = side of the right triangle (the base)
c = hypotenuse (the longest part or hypothenuse)
Therefore, the depth is:
a² = c² - b²
a² = 100² - 82²
a² = 10,000 - 6,724
a² = 3,276
a = √3,276
a = 57.24
= 57.24 feet
Thus, assuming a flat-bottom lake, its depth is 57.24 feet.
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what is the answer and how do i solve it?
EXPLANATION
Since we have the expression:
[tex]\frac{x}{x^2+x-6}-\frac{2}{x+3}[/tex]First, we need to find the least common multiplier as follows:
Least common multiplier of x^2 + x - 6, x+3: (x-2)(x+3)
Ajust fractions based on the LCM:
[tex]=\frac{x}{\left(x-2\right)\left(x+3\right)}-\frac{2\left(x-2\right)}{\left(x-2\right)\left(x+3\right)}[/tex][tex]\mathrm{Apply\: the\: fraction\: rule}\colon\quad \frac{a}{c}-\frac{b}{c}=\frac{a-b}{c}[/tex][tex]=\frac{x-2\left(x-2\right)}{\left(x-2\right)\left(x+3\right)}[/tex][tex]Expand\text{ x-2(x-2)}[/tex][tex]=\frac{-x+4}{\left(x-2\right)\left(x+3\right)}[/tex]The final expression is as follows:
[tex]=\frac{-x+4}{(x-2)(x+3)}[/tex]
Professor Torres is stucked in a burning building. He is leaning to the window on the 5th floor which is 60feets above the ground. For stability, the firefighter have to place the bottom of their ladder 15feet from the wall of the building. How long does the ladder needs to be to reach the window on the 5th floor and save professor Torres? round to 2 decimal place
The situation forms the right triangle above:
Where x is the length of the ladder.
Apply the Pythagorean theorem:
c^2 = a^2 +b^1
where:
c = hypotenuse = longest side = x
A &b = the other 2 legs of the triangle
Replacing:
x^2 = 60^2 + 15^2
Solve for x
x^2 = 3,600 + 225
x^2 = 3,825
x =√3,825
x = 61.85 ft
Converting between metric units of volume and capacityA water tower has a volume of 874 m³.Find how many liters of water it would take to completely fill thewater tower. Use the table of conversion facts, as needed.LXS?Conversion facts for volume and capacity1 cubic centimeter (cm³) = 1 milliliter (mL)1 cubic decimeter (dm³) = 1 liter (L)1 cubic meter (m³) = 1 kiloliter (KL) I need help with this math problem
Given: A water tower has a volume of 874 m³
To Determine: How many liters of water it would take to completely fill the
water tower
Solution
Please note that 1 cubic meter (m³) = 1 kiloliter (KL)
Therefore
[tex]\begin{gathered} 1m^3=1KL \\ 874m^3=xKL \\ Cross-multiply \\ x=874KL \end{gathered}[/tex]Also note that Kilo means 1000
Therefore
[tex]\begin{gathered} 874KL=874\times1000L \\ =874000L \end{gathered}[/tex]Hence, the water tower will be completely fill with 874000 liters(L)
Find the length to the nearest whole number of the diagonal (hypotenuse) of a square with 30 cm on a side. Round answers to the nearest tenth if necessary. Your answer
Notice that we can draw a triangle in the square , and that the length of the square's diagonal is the same as the length of the triangle's hypotenuse. The triangle is a right triangle therefore it satisfies the Phytagorean Theorem. To calculate for it's hypotenuse , we will use:
[tex]c^2=a^2+b^2[/tex]where c is the hypotenuse, and a, b are the other legs of the triangle.
[tex]\begin{gathered} c^2=30^2+30^2 \\ c^2=1800 \\ c=\sqrt[]{1800} \\ c=42.43 \end{gathered}[/tex]Since the hypotenuse of the triangle is 42.43 cm. Therefore, the square's diagonal is also 42.43 cm
Answer:
The square's diagonal is 42.43 cm
-Fractions-My sister needs help with this, and I totally forgot how to do fractions Mind helping out?
Because we have the same denominator we can do the subtraction
[tex]\frac{12}{10}-\frac{3}{10}=\frac{12-3}{10}=\frac{9}{10}[/tex]Paul did well the representation of the fractions in the diagram, but the operation that he made as we can see is wrong because the result is 9/10
Drag each number to the correct location on the statements. Not all numbers will be used. Consider the sequence below. --3, -12, -48, -192, ... Complete the recursively-defined function to describe this sequence. f(1) =...... f(n) = f(n-1) × .....for n = 2, 3, 4... 3, 2, 3, 4, 12, -4
ANSWER:
STEP-BY-STEP EXPLANATION:
We have the following sequence:
[tex]-3,-12,-48,-192...[/tex]f(1), is the first term of the sequence, therefore, it would be:
[tex]f(1)=-3[/tex]Now, we calculate the common ratio, just like this:
[tex]\begin{gathered} r=\frac{-192}{-48}=4 \\ \\ r=\frac{-48}{-12}=4 \\ \\ r=\frac{-12}{-3}=4 \end{gathered}[/tex]So the sequence would be:
[tex]f(n)=f(n-1)\cdot4[/tex]From question: Montell is practicing his violin. He is able to play six songs for every nine minutes he practices.*Picture has the table and other questions*
Answer:
The complete table:
6 18 2 42
9 27 3 63
Explanation:
We know that for every 9 minutes Montell practices he is able to play 6 songs. This means that the ratio between the number of minutes practices to the number of songs played is
[tex]\frac{\min}{\text{song}}=\frac{9}{6}[/tex]Therefore, if we want to solve for minutes plated, we just multiply both sides by 'song' to get
[tex]song\times\frac{\min}{\text{song}}=\frac{9}{6}\times\text{song}[/tex]which gives
[tex]min=\frac{9}{6}\times\text{song}[/tex]This means the number of minutes practised is 9/6 of the number of songs played.
Now 9/ 6 can be simplfied by dividing both the numerator and the denominator by 3 to get
[tex]\frac{9\div3}{6\div3}=\frac{3}{2}[/tex]therefore, we have
[tex]min=\frac{3}{2}\times\text{song}[/tex]Now we are ready to fill the table.
If Montell plays 18 songs then we have
[tex]\min =\frac{3}{2}\times18[/tex][tex]\min =27[/tex]the minutes practised is 27 for 18 songs.
If Montell practices for 3 minutes then we have
[tex]3=\frac{3}{2}\times\text{song}[/tex]then the value of song must be song = 2, since
[tex]\begin{gathered} 3=\frac{3}{2}\times2 \\ 3=3 \end{gathered}[/tex]Hence, for 3 minutes of practice, Montell sings 2 songs.
Now for 42 songs, the number of minutes played would be
[tex]\min =\frac{3}{2}\times42[/tex]which simplifies to give
[tex]\min =63[/tex]Hence, for 42 songs played, the practice time is 63 minutes.
To summerise, the complete table would be
songs 6 18 2 42
minutes 9 27 3 63
help me pleaseeeeeeeee
The value of the car after 5 years is $13,500 and the value of the car after 9 years is $10,500.
According to the question,
We have the following information:
The value of the car is given by V(x) where x is the number of years.
V(x) = -1500x + 21,000
(a) Now, to find the value of car after 5 years, we will put 5 in place of x in the given expression:
V(5) = -1500*5+21000
V(5) = -7500+21000
V(5) = $13,500
(b) Now, to find the value of car after 9 years, we will put 9 in place of x in the given expression:
V(9) = -1500*9+21000
V(9) = -10500+21000
V(9) = $10,500
(c) When V(12) = 3000 then it means that the value of the car after 12 years is $3000.
Hence, the value of car after 5 years and 9 years is $13,500 and $10,500 respectively.
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Find the area of the prism in the figure shown.
TherWe are asked to determine the area of the triangular prism. To do that we will add the area of the surfaces of the prism and add them together.
we have that the front and back areas are the areas of a triangle which is given by the following formula:
[tex]A_t=\frac{bh}{2}[/tex]Where:
[tex]\begin{gathered} b=\text{ length of the base} \\ h=\text{ height of the triangle} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} b=3 \\ h=4 \end{gathered}[/tex]Substituting the values we get:
[tex]A_t=\frac{\left(3\right)\lparen4)}{2}[/tex]Solving the operations:
[tex]A_t=6[/tex]Since the front and back faces are the same triangle we can multiply the result by 2:
[tex]A_t=2\times6=12[/tex]Therefore, the areas of the front and back faces add up to 12.
Now, we determine the area of the right side. This is the area of a rectangle and is given by the following formula:
[tex]A_r=lh[/tex]Where:
[tex]\begin{gathered} l=\text{ length of the rectangle} \\ h=\text{ height of the rectangle} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} l=5 \\ h=4 \end{gathered}[/tex]Substituting the values we get:
[tex]A_r=\left(5\right)\left(4\right)[/tex]Solving the operation:
[tex]A_r=20[/tex]Now, we determine the area of the left face which is also a rectangle with the following dimensions:
[tex]\begin{gathered} h=5 \\ l=5 \end{gathered}[/tex]Substituting we get:
[tex]A_l=\left(5\right)\left(5\right)=25[/tex]Therefore, the area of the left side is 25.
The area of the bottom face is also a rectangle with the following dimensions:
[tex]\begin{gathered} h=5 \\ l=3 \end{gathered}[/tex]Substituting we get:
[tex]A_b=\left(5\right)\left(3\right)=15[/tex]Now, the total surface area is the sum of the areas of each of the faces:
[tex]A=A_t+A_r+A_l+A_b[/tex]Substituting the values we get:
[tex]A=12+20+25+15[/tex]Solving the operations:
[tex]A=72[/tex]Therefore, the surface area is 72.
