Determine the effect on the graph of the parent f(x)=x

Determine The Effect On The Graph Of The Parent F(x)=x

Answers

Answer 1

To answer this question we first graph the parent function

Now we compare the two graphs. We notice that the graph shown is translated two units up.

To translate the graph of function we have to add the ammount we want to translate, then in this case

[tex]g(x)=f(x)+2[/tex]

Therefore the answer is J.

Determine The Effect On The Graph Of The Parent F(x)=x

Related Questions

factor completely5r^3-10r^2+3r-6

Answers

You have the following polynomial:

5r³ - 10r² + 3r - 6

In order to factorize the given polynomial, use synthetic division:

5 -10 3 -6 | 2

10 0 6

5 0 3 0

The remainder is zero in the previous division, then, r - 2 is a factor of the given polynomial, the other factor is formed with the coefficients of the division, just as follow:

5r³ - 10r² + 3r - 6 = (r - 2)(5r² + 3)

Hence, the factor are (r - 2)(5r² + 3)

Answer:(r-2) x (5r^2+3)

Step-by-step explanation:

Tents-R-Us makes and sells tents. Tents-R-Us' motto is“Keep It Simple.” The company decides to makes justthree sizes of tents: the Mini, the Twin, and theFamily-Size. All the tents they make have equilateraltriangular ends as shown at right.1. For the Twin, each edge of the triangle will be 8 ft. Find the heightof the tent at the center, correct to the nearest inch. One way to findthis height is to make an accurate scale drawing and measure.

Answers

The company decides to make just three sizes of tents: the Mini, the Twin, and the Family-Size.

The shape of these tents is an equilateral triangle.

Part 1:

For the Twin, each edge of the triangle will be 8 ft.

The height of the tent is given by

[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]

Where a is the length of the edge of the triangle.

Since we are given that a = 8 ft

[tex]\begin{gathered} h=a\cdot\frac{\sqrt[]{3}}{2} \\ h=8\cdot\frac{\sqrt[]{3}}{2} \\ h=4\sqrt[]{3} \\ h=6.9\: ft \end{gathered}[/tex]

Therefore, the height of the Twin tent at the center is 6.9 ft

Part 2:

The Mini tent will have edges 5 ft long.

The height of the tent is given by

[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]

Where a is the length of the edge of the triangle.

Since we are given that a = 5 ft

[tex]\begin{gathered} h=a\cdot\frac{\sqrt[]{3}}{2} \\ h=5\cdot\frac{\sqrt[]{3}}{2} \\ h=4.3\: ft \end{gathered}[/tex]

Therefore, the height of the Mini tent at the center is 4.3 ft

Part 3:

The Family-Size tent will have a height of 10 ft at the center.

Recall that the height of the tent is given by

[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]

Re-writing the formula for edge (a)

[tex]a=h\cdot\frac{2}{\sqrt[]{3}}[/tex]

Since we are given that h = 10 ft

[tex]\begin{gathered} a=h\cdot\frac{2}{\sqrt[]{3}} \\ a=10\cdot\frac{2}{\sqrt[]{3}} \\ a=\frac{20}{\sqrt[]{3}} \\ a=11.6\: ft \end{gathered}[/tex]

Therefore, the length of edges of the Family-Size tent is 11.6 ft

Solve the following system of linear equations using elimination.
x – y - 3z = 4

2x + 3y – 3z = -2

x + 3y – 2z = -4

Answers

By applying the elimination method, the solutions to this system of three linear equations include the following:

x = 2.y = -2.z = 0.

How to solve these system of linear equations?

In order to determine the solutions to a system of three linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

x – y - 3z = 4                .........equation 1.

2x + 3y – 3z = -2          .........equation 2.

x + 3y – 2z = -4            .........equation 3.

From equation 1 and equation 3, we would eliminate x as follows:

x – y - 3z = 4

x + 3y – 2z = -4

-4y - z = 8                  .........equation 4.

Next, we would pick a different pair of linear equations to eliminate x:

(x – y - 3z = 4) × 2   ⇒ 2x - 2y - 6z = 8

2x - 2y - 6z = 8

2x + 3y - 3z = -2

-5y - 3z = 10                ........equation 5.

From equation 4 and equation 5, we would eliminate z to get the value of y:

(-4y - z = 8) × 3 ⇒ -12y - 3z = 24

-12y - 3z = 24

-5y - 3z = 10

-7y = 14

y = 14/7

y = -2.

For the value of z, we have:

-4y - z = 8

z = -4y - 8

z = -4(-2) - 8

z = 8 - 8

z = 0

For the value of x, we have:

x – y - 3z = 4

x = 4 + y + 3z

x = 4 - 2 + 3(0)

x = 2

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Use U-Subscription to solve the following polynomial. Compare the imaginary roots to the code breaker guide. Hi this is a project and this is one of the questions, I have the guide so ignore the code piece part.

Answers

We will substitute the variable x with the variable u using the following relation:

[tex]u=x^2[/tex]

Then, we can convert the polynomial as:

[tex]4x^4+2x^2-12=4u^2+2u-12[/tex]

We can use the quadratic equation to calculate the roots of u:

[tex]\begin{gathered} u=\frac{-2\pm\sqrt[]{2^2-4\cdot4\cdot(-12)}}{2\cdot4} \\ u=\frac{-2\pm\sqrt[]{4+192}}{8} \\ u=\frac{-2\pm\sqrt[]{196}}{8} \\ u=\frac{-2\pm14}{8} \\ u_1=\frac{-2-14}{8}=-\frac{16}{8}=-2 \\ u_2=\frac{-2+14}{8}=\frac{12}{8}=1.5 \end{gathered}[/tex]

We have the root for u: u = -2 and u = 1.5.

As u = x², we have two roots of x for each root of u.

For u = -2, we will have two imaginary roots for x:

[tex]\begin{gathered} u=-2 \\ x^2=-2 \\ x=\pm\sqrt[]{-2} \\ x=\pm\sqrt[]{2}\cdot\sqrt[]{-1} \\ x=\pm\sqrt[]{2}i \end{gathered}[/tex]

For u = 1.5, we will have two real roots:

[tex]\begin{gathered} u=1.5 \\ x^2=1.5 \\ x=\pm\sqrt[]{1.5} \end{gathered}[/tex]

Then, for x, we have two imaginary roots: x = -√2i and x = √2i, and two real roots: x = -√1.5 and x = √1.5.

Answer:

Let u = x²

Equation using u: 4u² + 2u - 12

Solve for u: u = -2 and u = 1.5

Solve for x: x = -√2i, x = √2i, x = -√1.5 and x = √1.5

Imaginary roots: x = -√2i and x = √2i

Real roots: x = -√1.5 and x = √1.5

Simplify the expression by combing like terms.21v + 8 - 12v - 7 + 3t - t

Answers

We need to simplify the like terms.

"The like terms are whose with the same variable and exponent"

Therefore, the like terms are:

21v - 12v = 9v

8 - 7 = 1

3t - t = 2t

Now, the result is :

9v + 2t + 1

Hence, the correct answer is option D.

Assume that Jim Bruce and Valerie are 3 of the 17 members of the​ class, and that of the class members will be chosen randomly to deliver their reports during the next class meeting. What is the probability that Jim Bruce and Valerie are selected in that​ order?

Answers

The probability that Jim, Bruce and Valerie are selected in that​ order is P = 1/680

Given,

Number of students in a class = 17

Jim, Bruce and Valerie are 3 of the 17.

Three of students from the class are randomly chosen to deliver their reports during the next class meet.

We have to find the probability that Jim, Bruce and Valerie are selected in that​ order;

Here,

The total number of possible selection;

S = ⁿCr

Where, n = 17 and r = 3

Then,

S = ¹⁷C₃

S = 17! / 14! x 3!

S = 680

Therefore,

The probability that Jim, Bruce and Valerie are selected in that​ order is P = 1/680

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the length of a rectangle is 2 inches more than the width. The area is 24 square inches. Find the dimensions

Answers

Given:

length(l) = width(w) + 2

[tex]\text{Area}=24[/tex][tex]l\times w=24[/tex][tex](w+2)w=24[/tex][tex]w^2+2w-24=0[/tex][tex](w+6)(w-4)=0[/tex][tex]w=4\text{ or -6}[/tex]

Negative not possible.

[tex]\text{width(w)}=4\text{ inches}[/tex][tex]\text{length(l)}=w+2[/tex][tex]\text{length of the rectangle=4+2}[/tex][tex]\text{length of the rectangle=}6\operatorname{cm}[/tex]

Describe and justify the methods you used to solve the quadratic equations in parts A and B.

Answers

We know that give any pair of real numbers A and B, the following statement will be true:

[tex]A\cdot B=0[/tex]

if, and only if

[tex]\begin{gathered} A=0 \\ or \\ B=0 \end{gathered}[/tex]

Now, if we factor a quadratic equation into two factors A and B, and use the fact we've just mentioned, we can then equal each factor to zero, solve for x and get the solutions to said quadratic equation.

Irlene has just returned from a business trip in Britain with £200 of uncashed traveller's cheques. How much would she receive from the bank when she converts the currency back to Canadian dollars, assuming that the bank offers an exchange rate of C$1.00 = £0.5544 and charges a 0.65% fee to convert the traveller's cheques to Canadian funds? For full marks your answer(s) should be rounded to the nearest cent.

Answers

The converted money in Canadian dollars is $111.6.

Given that, Irlene has just returned from a business trip in Britain with £200 of uncashed traveler's cheques.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the converted Canadian dollars be x.

x = 200 × 0.5544 + 0.65% of 200 × 0.5544

= 110.88 + 0.0065 × 110.88

= 111.60072

≈ 111.6

Therefore, the converted money in Canadian dollars is $111.6.

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Write an expression for the sequence of operations described below.1)) multiply 7 by 8, then divide f by the resultDo not simplify any part of the expression.Submit

Answers

We need to write an expression for the operations:

[tex]\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}[/tex]

The first operation (multiplication) can be represented as:

[tex]7\cdot8[/tex]

The second operation (the division of f by the previous result) can be represented as:

[tex]f\div(7\cdot8)[/tex]

Notice that we need the parenthesis to indicate that the product is the first operation to be done.

Answer:

[tex]f\div(7\cdot8)[/tex]

Find the percent markdown. Cost of a pants $36.95, selling price $24.02

Answers

Answer:

35%

Explanation:

Given cost of a pant = $36.95 and selling price = $24.02.

Let the markdown percent be y.

To determine the markdown percent, we'll use the below formula;

Sale Price = Original Price x (1 - Markdown% in decimal)

So let's go ahead and substitute the given values into the equation;

[tex]\begin{gathered} 24.02=36.95\ast(1-y) \\ 24.02=36.95-36.95y \\ -12.93=-36.95y \\ y=\frac{-12.93}{-36.95} \\ y=0.35 \\ \therefore y=35percent \end{gathered}[/tex]

So the markdown percent is 35%

I need help with this practice problem Having a tough time solving properly

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

r = 7 sin (2θ)

Step 02:

polar equation:

r = 7 sin (2θ):

r = a sin nθ

n odd ==> n petals

n even ===> 2n petals

n = 2 ===> 2*2 petals = 4 petals

graph:

length of the petals:

r = 7 sin (2θ)

θ = 45°

r = 7 sin (2*45°) = 4.95

The answer is:

4.95

I need to order the numbers least to greatest for the numbers: sq root of 144 234/3 and 68.12

Answers

[tex]\sqrt[]{144}=12[/tex][tex]\sqrt[]{\frac{234}{3}}=\sqrt[]{78}=8.832[/tex][tex]\sqrt[]{68.12}=8.25[/tex]

So, the order would be 8.25, 8.832 and 12

3x - 4y = 65x + 8y = -1

Answers

[tex]\begin{gathered} 3x-4y=6 \\ 5x+8y=-1 \\ 3x=6+4y \\ x=2+\frac{4}{3}y \\ \\ 5(2+\frac{4}{3}y)+8y=-1 \\ 10+\frac{20}{3}y+8y=-1 \\ \frac{20y+24y}{3}=-11 \\ \frac{44y}{3}=-11 \\ 44y=-33 \\ y=\frac{-33}{44} \\ y=-\frac{3}{4} \\ \\ 3x-4(-\frac{3}{4})=6 \\ 3x+3=6 \\ 3x=3 \\ x=1 \end{gathered}[/tex]

Sydney is making bracelets, 3 bracelets require 21 beads. The number of braclets varies directly with the number of beads.
Write an equation in the form of y = ax then find the amount o
beads needed for 32 bracelets.

Answers

Step-by-step explanation:

"varies DIRECTLY with" means there is an y = ax relationship.

y = number of bracelets

x = number of beads

3 = a×21

a = 3/21 = 1/7

now, when we have 32 bracelets

32 = 1/7 × x

32×7 = x = 224

224 beads are needed for 32 bracelets.

4) Math Club members want to advertise their fundraiser each week in the school paper. They knowthat a front-page ad is more effective than an ad inside the paper. They have a $30 advertisingbudget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertiseat least 20 times. a) Write and graph a system of inequalities to model the number of advertisements the club canpurchase to stay under budget. Be sure to label all parts of your graph.b) State one solution that would work. How much money will remain in the club's budget?

Answers

Problem:

Math Club members want to advertise their fundraiser each week in the school paper. They know that a front-page ad is more effective than an ad inside the paper. They have a $30 advertising budget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertise at least 20 times.

a) Write and graph a system of inequalities to model the number of advertisements the club can purchase to stay under budget. Be sure to label all parts of your graph.

Solution:

Let us denote the number of front-page ads by x, and the number of inside ads by y:

x = number front-page ads

y= number of inside ads

Now, because they have a $30 advertising budget and It cost $2 for each front-page ad and $1 for each inside page ad, the first inequality that we have is:

[tex]2x+\text{ y }\leq30[/tex]

If we represent the graph of the equality (line) 2x+y = 30, we have:

On the other hand, because the club wants to advertise at least 20 times, the second inequality that we have is:

[tex]x+y\ge20[/tex]

If we represent the graph of the equality (line) x+y = 20, we have:

Now, the intersection point of the above lines, that is 2x+y = 30 and x+y = 20 is found as follows:

we have

y = 30 - 2x

and

y = 20-x

then

30-2x = 20-x

and

30-20 = 2x-x

that is

10 = x

when x = 10 then y = 20-x = 20-10 = 10

You go to the pet store with $25. You decide to buy 2 fish for $3.69 each and fish foos for $4.19. Rounded tanks are $11.48 square-shaped tanks are $14.89. Estimate your total cost to find which tank you can can buy. About how much money will you have left?

Answers

Answer: you will only have enough money for the rounded tank, after buying everything you will have 9 cents left

Step-by-step explanation: two $3.69 fish, $4.19 fish food. 2x3.69=7.38+4.19=11.57

25-11.57=13.43

13.43+11.48=24.91

25-24.91=0.09

You need to estimate the prices of the fish and food. I going to round to the whole amount. 3.69= 4.00; 4.19=4.00. 2 fish at 4.00 equals 8.00; plus the 4.00 for food equals 12.00. 25.-12=13.00. You will only have enough to buy the round tank at 11.48.
Even if you add the fish and food together minus the 25. You can still only get the round tank.

what is the length of the dominant line in the time graph below? l leave your answer in simplest radical form.

Answers

Let's first calculate the lenght of the side of the rectangle.

[tex]l=\sqrt[]{8^2+5^2}=\sqrt[]{64+25}=\sqrt[]{89}[/tex]

so we get that the dotted line is:

[tex]d=\sqrt[]{2^2+89}=\sqrt[]{93}[/tex]

so the answer is square root of 93

Can someone explain how I would know the difference between a 2:7 ratio and 7:2 ratio when a point partitions the line? Thank you!

Answers

Solution

For this case we can do the following:

We can understand 7/2 as the reciprocal of 2/7 and we can create the following diagram

For what values of b will F(x) = logb x be a decreasing function?A.0 < b < 1B.0 > b > -1C.b > 0D.b < 0

Answers

Given:

There is a function given as below

[tex]F(x)=\log_bx[/tex]

Required:

For what value of b the given function in decreasing

Explanation:

The given function is logarithm function

also written as

[tex]F(x)=\frac{log\text{ x}}{log\text{ b}}[/tex]

The base b is determines that if the function is increasing or decreasing

here

for

[tex]0the given function is decreasing

for

[tex]b>1[/tex]

the given function is increasing

Final answer:

[tex]0

A baker need 2/3 cup of sugar,but he can only find a 1/2 cup measure,so he decides to estimate, Which of the following would result in the correct amount of sugar?A)One Full scoop plus 1/3 of a scoopB)One Full scoop plus 1/2 of a scoop C) Two ScoopsD)3/4 of a scoop

Answers

He needs 2/3 cup of sugar . But he can only find 1/2 cup measures.

The height of a tree is x feet. If it grows ½ times the original height, choose the correct expression that denotes the situation.

Answers

ANSWER

1.5(x)

EXPLANATION

The tree is originally x feet tall. If it grows 1/2 this height it means that now it is 1/2x taller, or we can express this as a decimal, 0.5x. If we add these two heights we'll have the new height of the tree:

[tex]x+0.5x=(1+0.5)x=1.5x[/tex]

Pattern Exercise Mins Components Fitnes 0 5 1 9 2 25 3 89 4 ? What do you notice about the pattern of components from minute to minute? 2. State the value for the question mark. I E O BI

Answers

We can calculate how much each component increases, this is shown in the following image:

So we can see that the pattern in which the components increase from minute to mites is that starts by adding 4, then they add 4x4=16, then they add 16x4=64, and so on:

So the rule is that the next increase is the previous increase multiplied by 4.

Thus, the next increase in components (the question mark) should be:

The previous one +256, which gives:

[tex]?=89+256=345[/tex]

Answer: 345

. Identify the difference. -2-(-6)

Answers

In this case,

This difference is made this way:

-2 - (-6) =

-2 +6 = 4

So there we have this identity. The minus before the parentheses turns the minus into plus sign.

From least to greatest. -1.4-1.02 -1.20

Answers

We could put these values in the number line:

Therefore, the order of the numbers from least to greatest is:

-1.4 , -1.20 , -1.02

The least number between all the options given is -1.4 because if you see, all numbers are negative, so, when a negative number is greater, as the amount after the negative sign becomes greater, the number is going to be least. That's the reason of the order.

express the fuction graphed on the axes below as a piecewise function

Answers

Concept

Find the equation of line for the second line.

x1 = -2 y1 = 1

x2 = -4 y2 = 2

Next, apply equation of a line formula

[tex]\begin{gathered} \frac{y-y_1}{x-x_1\text{ }}\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{2\text{ - 1}}{-4\text{ + 2}} \\ \frac{y\text{ - 1}}{x\text{ + 2}}\text{ = }\frac{1}{-2} \\ -2(y\text{ - 1) = 1(x + 2)} \\ -2y\text{ + 2 = x + 2} \\ -2y\text{ = x} \\ y\text{ = }\frac{-1}{2}x \end{gathered}[/tex]

Final answer

The graphed as a piecewise function ​is given below

What was the initial population at time t=0?Find the size of the bacterial population after 4 hours.

Answers

Answer;

[tex]\begin{gathered} a)\text{ 195 bacteria} \\ b)\text{ 3,291,055,916 bacteria} \end{gathered}[/tex]

Explanation;

a) We want to get the initial population of the bacteria

We start by writing a formula that links the initial bacteria population to a later bacteria population after time t

[tex]A(t)=I(1+r)^t[/tex]

where A(t) is the bacteria population at time t

I is the initial bacteria population

r is the rate of increase in population

t is time

Now, let us find r

At t = 10; we know that A(t) = 2I

Thus, we have it that;

[tex]\begin{gathered} 2I=I(1+r)^{10} \\ (1+r)^{10}\text{ = 2} \\ 1+r\text{ = 1.0718} \\ r\text{ = 1.0718-1} \\ r\text{ = 0.0718} \end{gathered}[/tex]

Now, let us find I, since we have r. But we have to make use of t= 80 and A(t) = 50,000

Thus, we have;

[tex]\begin{gathered} 50,000=I(1+0.0718)^{80} \\ I\text{ = }\frac{50,000}{(1+0.0718)^{80}} \\ I\text{ = 195} \end{gathered}[/tex]

The initial population is 195 bacteria

b) For after 4 hours, we have to convert to minutes

We know that there are 60 minutes in an hour

So, in 4 hours, we have 4 * 60 = 240 minutes

Now, we proceed to use the formula above with I = 195 and t = 240

We have that as;

[tex]\begin{gathered} A(240)=195(1+0.0718)^{240} \\ A(240)\text{ = 3,291,055,916 bacteria} \end{gathered}[/tex]

A game fair requires that you draw a queen from a deck of 52 ards to win. The cards are put back into the deck after each draw, and the deck is shuffled. That is the probability that it takes you less than four turns to win?

Answers

Explanation

The probability (P) is winning in less than four turns can be decomposed as the following sum:

The probability of winning in one turn is

[tex]P(\text{Winning in turn 1})=\frac{\#Queens}{\#Cards}=\frac{4}{52}.[/tex]

The probability of winning in the second turn is

[tex]\begin{gathered} P(\text{ Winning in the second turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Winning (in turn 2)}), \\ \\ P(\text{ Winning in the second turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the second turn})=\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]

The probability of winning in the third turn is

[tex]\begin{gathered} P(\text{ Winning in the third turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Lossing (in turn 2)})\cdot P(\text{ winning (in turn 3)}), \\ \\ P(\text{ Winning in the third turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the third turn})=\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]

Adding all together, we get

[tex]\begin{gathered} P(\text{ Winning in less than four turns})=\frac{4}{52}+\frac{48}{52}\cdot\frac{4}{52}+\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}, \\ \\ P(\text{ Winning in less than four turns})=\frac{469}{2197}, \\ \\ P(\text{ Winning in less than four turns})\approx0.2135, \\ \\ P(\text{ Winning in less than four turns})\approx21.35\% \end{gathered}[/tex]

Answer

The probability of winning in less than four turns is (approximately) 21.35%.

without dividing, how can you tell which quotient is smaller, 30:5 or 30:6 ? eXPLAIN

Answers

Without dividing, we can tell that 30:6 has smaller quotient between 30:5 and 30:6.

According to the question,

We have the following two expressions:

30:5 and 30:6

Now, we can easily find which expression has a smaller quotient when the dividend is the same. We need to look at the divisor. If the dividend is the same then the quotient will be smaller for the one with the greater divisor.

In this case, 30:6 has a greater divisor than 30:5 (6 is larger than 5). So, it will have smaller quotient.

Now, we can prove this by dividing both the expressions.

30/6 = 5

(So, it has smaller quotient.)

30/5 = 6

Hence, 30:6 has smaller quotient than 30:5.

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CS 18 and 105 calories in each juice box The rules for two horseback riding packages are shown below. Go Galloping Horseback Rides $6 equipment fee plus S10 per hous hours horseback riding and let yepresent the total cost of the package. Write a system of equations to represent this situation let x represent the number of Lucky Horseshoe Stables $12 equipment fee plus hour 259 Calories What is the solution to the system of equations? What does the solution represent?

Answers

8A) Let x represent the number of hours of horseback riding.

Let y represent the total cost of the package

If Lucky horseshoe stables is used for x hours, the equation for the total cost would be

y = 7x + 12

If Go galloping horseshoe rides is used for x hours, the equation for the total cost would be

y = 10x + 6

Thus, the equations are

y = 7x + 12

y = 10x + 6

B) To solve the system of equations, we would substitute the first equation into the second equation. It becomes

7x + 12 = 10x + 6

10x - 7x = 12 - 6

3x = 6

x = 6/3

x = 2

y = 7x + 12 = 7 * 2 + 12

y = 14 + 12

y = 26

The solution of the system of equations is (2, 26)

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