To find the missing numerator si that both fractions are equivalent, you have to multiply both sides of the equal sign by 72:
[tex]\begin{gathered} 72\cdot\frac{7}{8}=72\cdot\frac{?}{72} \\ 63=\text{?} \end{gathered}[/tex]The missing numerator is 63
The equivalent fractions are:
[tex]\frac{7}{8}=\frac{63}{72}[/tex]3 * 10 ^ - 6 = 4.86 * 10 ^ - 4 in scientific way
Answer:
3*10=30
10^-6=1^-6. (10 raised to the power of-6)
therefore 3*1^-6=3
is equal to
4.86*10=48.6
10^-4=1^-4
therefore 48.6*1^-4=48.6
b. Write
√x
as a single radical in simplest form.
5√x
Answer:
(tenth root of x to the third power)
see image
Step-by-step explanation:
To do this problem you need to know how to convert radicals to an expression with a fraction exponent(and back to radicals again), ALSO exponent rules for division ALSO subtracting fractions.
Square root x can be written as x^ 1/2
fifth root x can be written as x^ 1/5
When you are dividing expressions with the same base, exponent rules say to SUBTRACT the exponents.
1/2 - 1/5 change to common denominator
5/10 - 2/10
= 3/10
x^1/2 / x^1/5 =
x^ (1/2 - 1/5) =
x^ (5/10-2/10) =
x^ 3/10
Then change back to a radical. Remember "down and out" or "roots are down" and "up, up, up" or "exponents are up"
the number down below goes out (outside) the radical. And the number up top is up and exponents are up, up, up
see image.
x^3/10 =
tenth root (x^3)
see image.
i need help with my homework PLEASEMCHECK WORK WHEN FINISHED
Given:
The population of a town increases by 9 % annually.
The current population is 4,500.
Required:
We need to find the equation that gives the population of the town.
Explanation:
The population can be found by the following equation.
[tex]Th\text{e population =4500+9 \% of 4500}[/tex]Let now be the current population of the town =4500.
Let Next be the population of the town.
The population can be found by the following equation.
[tex]Next\text{ =Now+9\% of Now.}[/tex][tex]Next\text{ =Now+}\frac{9}{100}\times\text{Now.}[/tex]Take the common term now out.
[tex]Next\text{ =Now\lparen1+}\frac{9}{100})[/tex][tex]Use\text{ }\frac{9}{100}=0.09.[/tex][tex]Next\text{ =Now\lparen1+0.09})[/tex][tex]Next\text{ =Now\lparen1.09})[/tex][tex]Next\text{ =Now}\times\text{1.09}[/tex]Final answer:
[tex]Next\text{ =Now}\times\text{1.09}[/tex]HELP PLEASE!
Dave has a piggy bank which consists of dimes, nickels, and pennies. Dave has seven
more dimes than nickels and ten more pennies than nickels. If Dave has $3.52 in his piggy bank, how many of each coin does he have?
Dave has 17 nickels, 24 dimes and 27 pennies in his piggy bank.
According to the question,
We have the following information:
Dave has 7 more dimes than nickels and 10 more pennies than nickels.
Now, let's take the number of nickels to be x.
So,
Dimes = (x+7)
Pennies = (x+10)
Now, Dave has $3.52 in his piggy bank.
We will convert nickels, dimes and pennies into dollars.
We know that 1 nickel = 0.05 dollars, 1 dime = 0.1 dollars and 1 pennies = 0.01 dollars.
Now, we will convert the given numbers of nickel, dime and pennies into dollars.
x Nickels in dollars = $0.05x
(x+7) dimes in dollars = $0.1(x+7)
(x+10) pennies in dollars = $0.01(x+10)
Now, we will them.
0.05x + 0.1(x+7) + 0.01(x+10) = 3.52
0.05x + 0.1x + 0.7 + 0.01x + 0.1 = 3.52
0.16x + 0.8 = 3.52
0.16x = 3.52-0.8
0.16x = 2.72
x = 2.72/0.16
x = 17
Now, we have:
Number of nickels = 17
Number of dimes = (17+7)
Number of dimes = 24
Number of pennies = (17+10)
Number of pennies = 27
Hence, the number of nickels, dimes and pennies are 17, 24 and 27 respectively.
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If you are given odds of 5 to 6 in favor of winning a bet, what is the probability of winning the bet?
5 to 6 odds means that, out of 11 possible outcomes, odds are that there will be 5 of one kind of outcome and 6 of another kind of outcome.
In this case, you are given 5 to 6 odds, which means that out of 11 possible outcomes you will win a bet 5 times, and lose it 6.
In fraction, it will look like this:
[tex]\frac{11}{11}\text{ \lparen these are all the possible outcomes, which equals 1\rparen = }\frac{5}{11}(the\text{ outcomes in which you win, which equals .4545, so 45.45\%\rparen + }\frac{6}{11}\text{ \lparen the outcomes in which you lose, which equals 0.5454, so 54.54\% \rparen}[/tex]Because of that, the probability of winning the bet is 45.45%, and in a fraction, it is 5/11, which means you will win in 5 out of 11 scenarios.
Interpreting the parameters of a linear function that models a real-world situation
SOLUTION
The equation relating x and y is
[tex]\begin{gathered} y=27x+600 \\ \text{Where } \\ x=\text{Total number of minutes } \\ y=\text{Total amount of water in the pond} \end{gathered}[/tex]The equation connecting x and y is an equation of the form
[tex]\begin{gathered} y=mx+c \\ \text{Where m is the slope or chnages betwe}enx\&y\text{ } \\ \end{gathered}[/tex]Since slope is also refers to as changes between two variables,
Hence
Cmparing with the equation given,
[tex]\begin{gathered} m=27 \\ \text{Slope}=27 \end{gathered}[/tex]Therefore,
The change per minute in the total amount of water in the pond is 27 litres
The starting amount ot water is when the time is at 0 minutes .
Hence, substite x=0 into the equation given and obtain the value of y which stands for the amount of water at the begining.
[tex]\begin{gathered} y=27x+600 \\ \text{put x=0} \\ y=27(0)+600 \\ y=0+600 \\ \text{Then } \\ y=600 \end{gathered}[/tex]Therefore,
The starting amount of water is 600 litres
Answer: A) 27 litres B). 600 litres
Writing and evaluating a function modeling continuous exponential growth or decay given two outputs
Explanation
The model has the form
[tex]y=ae^{-kt}[/tex]Where a=initial amount
y= final amount
K= growth rate constant
t= time
When 140 kg of substance is left after 7 hours, the formula can be remodeled to be.
[tex]\begin{gathered} 140=400e^{-7k} \\ e^{-7k}=\frac{140}{400} \\ e^{-7k}=\frac{7}{20} \\ \ln (e^{-7k})=\ln (\frac{7}{20}) \\ -7k=\ln (\frac{7}{20}) \\ k=\frac{\ln(\frac{7}{20})}{-7} \\ \therefore k=\frac{\ln (\frac{20}{7})}{7} \end{gathered}[/tex]Therefore, the first solution is
[tex]y=400e^{-\ln (\frac{20}{7})\frac{t}{7}}[/tex]For part b we have 16 hours.
[tex]\begin{gathered} y=400e^{-\ln (\frac{20}{7})\frac{t}{7}}=400e^{-\ln (\frac{20}{7})\frac{16}{7}} \\ y=36.302\approx36\operatorname{kg}\text{ (To the nearest whole number)} \end{gathered}[/tex]Thus, the answer is 36kg
I NEED HELP ASAP Which of these data sets could best be displayed on a dot plot?721, 722, 722, 723, 724, 724, 724, 725, 727, 728, 73016, 29, 31, 37, 44, 49, 58, 63, 69, 70, 83, 971.3, 1.9, 2.5, 2.7, 2.7, 3.5, 4.8, 5.3, 7.9, 9.00.012, 0.078, 0.093, 0.147, 0.187
Take into account that dop plots are usefull for small or moderate sized data sets, and also they are suefull for data with big gaps.
Based on the previous description, you can conclude that the best option for a dot plot is:
16, 29, 31, 37, 44, 49, 58, 63, 69, 70, 83, 97
in comparisson with the other data sets, the elements of the rest of data sets are closer to each other.
See attached pic for problem. Only need help with part D
For the given question, we will use the formula from part (b) to answer part (d)
The given function is as follows:
[tex]S=260.4914\cdot A^{0.2051}[/tex]We will find the number of species (S) When A = 813
so, substitute with A = 813, then find S
[tex]S=260.4914\cdot813^{0.2051}\approx1029.563[/tex]Rounding the answer to the nearest 10 species
So, the answer will be:
[tex]S=1030[/tex]A circle has a diameter of 12 inches. Find its exact and approximate circumference and area.
STEP 1:
We write out the formulas and the necessary values
[tex]\begin{gathered} \text{Area of circle =}\pi r^2 \\ \text{circumference of circle = 2}\pi r \\ \text{radius =}\frac{diameter}{2}=\frac{12}{2}=6\text{ inches} \end{gathered}[/tex]STEP 2
We substitute the values into the formula
[tex]\begin{gathered} \text{Area of the circle = 3.14 x 6 x 6} \\ Exactvalue=113.04\text{ square inches and Approx}imate\text{ value =113} \\ \text{circumference of the circle= 2 x 3.14 x6} \\ Exactvalue=37.68\text{ inches and approx}imate\text{ value = 38inches} \\ \end{gathered}[/tex]Leila runs at 12 mph find the number of miles she can travel if she runs for 2 hours
20 POINTS ANSWER I WILL MARK BRAINLIEST!!!!!!!!!!
Answer: 24 mph
Step-by-step explanation:
If she can run 12 mph/ 12 miles per hour
She runs for 2 hours
12 · 2 = 24
What is your answer? estion 3 Why is this your answer? 60 40 20 Which is the correct answer? 4 5 6 Time (seconds) Why is this the correct answer? statement is TRUE about the motion of this object as shown in the graph? The object was accelerating from t = 1 tot = 3 The object was slowing down from t = 4.5 to t= 6. © The object returned to its original location by t = 6 seconds. The object was traveling at a constant speed from t = 3 to t = 45 seconds
As we can see in the graph the object returned to its original position in t=6.
It's not accelarating because acceleration is the second derivate of the position, and the position is determined by a linear equation.
The answer is C.
please solve quickly and give solution first then explain if possible
Solution
[tex]undefined[/tex]The final answer
[tex]x=10[/tex]Angles of Polygons The figure below is a pentagon whose interior angles have the same measure.What is the sum of the measures of these 5 angles?
Given the number of sides of a pentagon:
Number of sides = 5
Let's find the sum of the measures of the 5 equal angles.
To find the sum of the measures of interior angles of a polygon, apply the formula:
[tex]S=(n-2)*180[/tex]Where:
n is the number of sides = 5
Thus, we have:
[tex]\begin{gathered} S=(5-2)*180 \\ \\ S=(3)*180 \\ \\ S=540^o \end{gathered}[/tex]Therefore, the sum of the interior angles of the pentagon is 540 degrees.
ANSWER:
540°
What is the domain of F
If the function be [tex]$\frac{x^3-3 x+1}{8 x-5}$[/tex] then the domain of the function exists
[tex]$\left[\begin{array}{ccc}\text { Solution: } & x < \frac{5}{8} & \text { or } \quad x > \frac{5}{8} \\ \text { Interval Notation: } & \left(-\infty, \frac{5}{8}\right) \cup\left(\frac{5}{8}, \infty\right)\end{array}\right]$[/tex]
What is meant by domain of a function?The collection of all potential inputs for a function is its domain.
Consider the function y = f(x), which has the independent variable x and the dependent variable y. A value for x is said to be in the domain of a function f if it successfully allows the production of a single value y using another value for x.
Let the function be [tex]$\frac{x^3-3 x+1}{8 x-5}$[/tex]
Domain of [tex]$\frac{x^3-3 x+1}{8 x-5}$[/tex] :
[tex]$\left[\begin{array}{ccc}\text { Solution: } & x < \frac{5}{8} & \text { or } \quad x > \frac{5}{8} \\ \text { Interval Notation: } & \left(-\infty, \frac{5}{8}\right) \cup\left(\frac{5}{8}, \infty\right)\end{array}\right]$[/tex]
Range of [tex]$\frac{x^3-3 x+1}{8 x-5}:\left[\begin{array}{cc}\text { Solution: } & -\infty < f(x) < \infty \\ \text { Interval Notation: } & (-\infty, \infty)\end{array}\right]$[/tex]
Axis interception points of [tex]$\frac{x^3-3 x+1}{8 x-5}[/tex]
X Intercepts: [tex]$(0.34729 \ldots, 0),(1.53208 \ldots, 0)$[/tex], [tex]$(-1.87938 \ldots, 0)$[/tex],
Y Intercepts: [tex]$\left(0,-\frac{1}{5}\right)$[/tex]
Asymptotes of [tex]$\frac{x^3-3 x+1}{8 x-5}: \quad$[/tex]
Vertical: [tex]$x=\frac{5}{8}$[/tex]
Extreme Points of [tex]$\frac{x^3-3 x+1}{8 x-5}$[/tex]
Minimum [tex]$(-0.54351 \ldots,-0.26422 \ldots)$[/tex]
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Find the length of the segment indicated. Round to the nearest tenth if necessary. Note: One segment of each triangle is a tangent line
Given
A circle with a tangent drawn to it forming one side of a triangle
Required
we need to find the diameter of the circle
Explanation
clearly it is a right angled triangle as radius through point of contact is perpendicular to the tangent. let the lenght of missing side be d
Therefore
[tex]d^2+12^2=20^2[/tex]or
[tex]d^2=400-144[/tex]or
[tex]d^2=256[/tex]or d=16
Help I have use the calculator in degree mode for this problem
SOLUTION
The figure above consists of a triangle and a semi-circle.
Area of the figure = Area the of triangle + Area of the semi-circle
[tex]\begin{gathered} \text{Area of triangle = }\frac{1}{2}\times base\text{ }\times height\text{ } \\ \text{base of the triagle = 15 ft} \\ \text{height = }15\text{ ft } \\ \text{Area of triangle = }\frac{1}{2}\times15\text{ }\times15 \\ \text{Area of triangle = 112.5 ft}^2 \end{gathered}[/tex][tex]\begin{gathered} \text{Area of the semi circle = }\frac{1}{2}\times\pi r^2 \\ r,\text{ radius = }\frac{diameter}{2}\text{ = }\frac{15}{2}\text{ = 7.5} \\ \text{Area of semi-circle = }\frac{1}{2}\times3.14\times7.5^2 \\ \text{Area of semi-circle = }\frac{1}{2}\text{ }\times3.14\times56.25\text{ = 88.3125} \end{gathered}[/tex]Area of composite figure = 112.5 + 88.3125 = 200.8125
Therefore the Area of the figure = 200.81 squared feet to the nearest hundredth
11-3x75-1 what is the answer?
Answer:
Step-by-step explanation:
-215
Answer:
-215
Step-by-step explanation:
the answer to 11-3x75-1 is -215
2. What is an algebraic expression for each phrase?a. the product of 9 and a number tb. the difference of a number x and 1/2c. the sum of a number m and 7.1 d. the quotient of 207 and a number n
The algebraic expression for each phrase would be the following:
a. the product of 9 and a number t would be expressed as:
9*t
b. the difference of a number x and 1/2 would be expressed as:
x - 1/2
c. the sum of a number m and 7.1 would be expressed as:
m + 7.1
d. the quotient of 207 and a number n would be expressed as:
207 / n
One function has an equation in slope-intercept form: y = x + 5. Another function has an equation in standard form: y + x = 5. Explain what must be different about the properties of the functions. See if you can determine the differences without converting the equation to the same form.
Without converting the equations to the same form, the property that must be different in the functions is the slope
How to determine the difference in the properties of the functions?From the question, the equations are given as
y = x + 5
y + x = 5
From the question, we understand that:
The equations must not be converted to the same form before the question is solved
The equation of a linear function is represented as
y = mx + c
Where m represents the slope and c represents the y-intercept
When the equation y = mx + c is compared to y = x + 5, we have
Slope, m = 1
y-intercept, c = 5
The equation y = mx + c can be rewritten as
y - mx = c
When the equation y - mx = c is compared to y + x = 5, we have
Slope, m = -1
y-intercept, c = 5
By comparing the properties of the functions, we have
The functions have the same y-intercept of 5The functions have the different slopes of 1 and -1Hence, the different properties of the functions are their slopes
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Plot the ordered pair (-4,-1) state which quadrant or on which axis the point lies
Answer:
Th
Explanation:
Given the ordered pair (-4, -1), we have that x = -4 and y = -1. Plotting this point, we'll have;
Quadrants are labeled in an anti-clockwise direction with the top right portion of the graph being the 1st quadrant. Looking at the plotted point, we can see that the point is in the 3rd quadrant.
You go to a candy store and want to buy a chocolate
To find the amount of servings, we just need to divide the entire bar weight by the serving weight. Solving this calculation, we have
[tex]\frac{14.8}{2.4}=\frac{37}{6}=6.166666666..\text{.}[/tex]Write an explicit rule for the following arithmetic sequence: 28, 38, 48, 58,
When you have an arithmetic sequence you can use the next general formula to get the explicit formula:
[tex]a(n)=a(1)+d(n-1)[/tex]Where a(1) is the first term in the sequence, d is the difference between each term in the sequence, and n is the nth term
You have the sequence: 28,38,48,58
The difference in this sequence is d=10
The first term is: a(1)=28
Then:
[tex]a(n)=28+10(n-1)[/tex][tex]a(n)=28+10n-10[/tex][tex]a(n)=18+10n[/tex]Then, the explicit rule for the given arithmetic sequence is: a(n)=18+10nCan you please help with 44For the following exercise, sketch a graph of the hyperbola, labeling vertices and foci
We have the following equation of a hyperbola:
[tex]4x^2+16x-4y^2+16y+16=0[/tex]Let's divide all the equations by 4, just to simplify it
[tex]x^2+4x-y^2+4y+4=0[/tex]Just to make it easier, let's put the term if "x" isolated
[tex]x^2+4x=y^2-4y-4[/tex]Now we can complete squares on both sides, just remember that
[tex]\begin{gathered} (a+b)^2=a^2+2ab+b^2 \\ \\ (a-b)^2=a^2-2ab+b^2 \end{gathered}[/tex]Now let's complete it!
[tex]\begin{gathered} x^2+4x=y^2-4y-4\text{ complete adding 4 on both sides} \\ \\ x^2+4x+4=y^2-4y-4+4 \\ \\ (x+2)^2=y^2-4y \\ \end{gathered}[/tex]We already completed one side, now let's complete the side with y^2, see that we will add 4 again, then
[tex]\begin{gathered} (x+2)^2=y^2-4y \\ \\ (x+2)^2+4=y^2-4y+4 \\ \\ (x+2)^2+4=(y-2)^2 \end{gathered}[/tex]And now we can write it using the standard equation!
[tex]\begin{gathered} (y-2)^2-(x+2)^2=4 \\ \\ (y-2)^2-(x+2)^2=4 \\ \\ \frac{(y-2)^2}{4}-\frac{(x+2)^2}{4}=1 \end{gathered}[/tex]And now we can graph it like all other hyperbolas, the vertices will be:
[tex](-2,4)\text{ and }(-2,0)[/tex]And the foci
[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ c^2=2^2+2^2 \\ \\ c^2=2\cdot2^2 \\ \\ c^{}=2\, \sqrt[]{2} \end{gathered}[/tex]Then the foci are
[tex](-2,2+2\, \sqrt[]{2})\text{ and }(-2,2-2\, \sqrt[]{2})[/tex]Now we can plot the hyperbola!
The electronics company makes two types of switches. Type a takes 4 minutes to make and requires $3 worth of materials.Type b takes 5 minutes to make and requires $5 of materials. In the latest production bath, it took 32 hours to make these switches and the materials cost 1740. How many of each type of switch was made?
Let
x ------> number of switch type A
y -----> number of switch type B
so
Remember that
1 hour=60 min
32 hours=32*60=1,920 minutes
4x+5y=1,920 -------> equation 1
3x+5y=1,740 ------> equation 2
Solve the system of equations
Solve by graphing
using a graphing tool
see the attached figure
Solution is
x=180
y=240
therefore
the number of switch type A was 180the number of switch type B was 240Minnesota fell from 48 degrees to -12 degrees over a 24 hour period. what was the average temperature change per hour?
We have to calculate the average temperature change per hour.
We know that the temperature drops from 48 degrees to -12 degrees in 24 hours.
To calculate the average change, in degrees per hour, we calculate the ratio between the variation of the temperature and the interval of time.
We can expres this as:
[tex]v=\frac{\Delta T}{t}=\frac{T_f-T_i}{t}=\frac{-12-48}{24}=\frac{-60}{24}=-2.5[/tex]Answer: The average change in temperature is -2.5 degrees per hour.
how do I do domin and range on a graph
Consider that the domain are the set of x values with a point on the curve.
In this case, based on the grap, you can notice that the domain is:
domain = (-8,2)
domain = {-8,-7,-6,-5,-4,-3,-2,-1,0,1,2}
In this case you can observe that the circle has a left limit given by x = -8 (this can be notices by the subdivisions of the coordinate system) and a right limit given by x = 2. That's the reason why it is the interval of the domain.
The range are the set of y values with a point on the curve.
range = (-3,7)
range = {-3,-2,-1,0,1,2,3,4,5,6,7}
In this case, you observe the down and up limits of the circle.
Please look at the image below. By the way this is my homework.Use the definition of congruence to decide whether the two figures are congruent. Explain your answer. Give coordinate notation for the transformations you use.
Congruent Shapes
Two congruent shapes have the same size and shape, which means all of their side lengths are equal and all of their internal angles are congruent (have the same measure),
All of the rigid transformations map the original figure to a congruent figure. One of the transformations is the reflection.
The image shows two shapes SRQP and EDCB. They seem to have the same shape and size, but it must be proven by finding the appropriate transformation used.
Comparing the corresponding vertices we can find that out. For example, the coordinates of S are (-6,4) and the coordinates of E are (4,4). The x-coordinate of the midpoint between them is
xm = (-6+4)/2 = -1
Now analyze the points P(-8,2) and B(6,2). The x-coordinate of the midpoint is:
xm = (-8+6)/2 = -1
For the points R(-4,-6) and D(2,-6):
xm = (-4+2)/2 = -1
For the points Q(-9,-4) and D(8,-4):
xm = (-9+8)/2 = -0.5
Since this last pair of corresponding points don't have the same axis of symmetry as the others, the shapes don't have the same size and angles, thus they are not congruent
For both shapes to be congruent, the coordinates of Q should have been (-10,-4)
how many millielters are in 1/5 liters
We know,
1 liter=1000 milliter.
So, millilters in 1/5 liters is,
[tex]\frac{1}{5}liter\times\frac{1000\text{ milliter}}{1\text{ liter}}=200\text{ milliter}[/tex]Therefore, there are 200 milliters in 1/5 liters.
Do the data in the table you made support the notion the arch is not a parabola? Explain why.
The parabola that has the height and width similar to the Gateway arc, gives;
(a) The quadratic equation of the parabola is presented as follows;
[tex] f(x) = -6.991 \times 10^{-3} \cdot x^2 + 4.181 \cdot [/tex]
(b) The completed table is presented as follows;
Width. Height
567. 63.12
478. 225.67
308. 459.2
What is the shape of the graph of a quadratic function?The shape of a quadratic function is a parabola, which is either upward facing or downward facing
(a) The given dimensions of the arc are;
Height = 625
Width at the base = 598
The points on the parabola are therefore;
(0, 0), (598÷2, 625) = (299, 625), (598, 0)
The equation of the parabola is of the form;
f(x) = a•x² + b•x + c, which gives;
f(0) = 0 = a×0² + b×0 + c = c
c = 0
f(299) = 625 = a×299² + b×299 + 0...(1)
f(598) = 0 = a×598² + b×598...(2
(a×598² + b×598) - 2×(a×299² + b×299) = 0 - 2×625
a•178802 = -2×625
a = -2×625 ÷ 178802
a ≈ -6.991 × 10^(-3)
b ≈ 4.181.
The equation is therefore;
[tex] f(x) = -6.991 \times 10^{-3} \cdot x^2 + 4.181 \cdot [/tex]
(b)
The table of values is completed as follows;
When the width is 567 feet, x = 299 - 567÷2 = 15.5
[tex] \displaystyle{f(15.5) = -6.991 × 10^{-3} \times 15.5² + 4.181 \times 15.5 approx 63.12} [/tex]
When the width is 478 feet, x = 299 - 478÷2 = 60
[tex] \displaystyle{f(60) = -6.991 × 10^{-3} \times 60² + 4.181 \times 60 approx 225.67} [/tex]
When the width is 308 feet, x = 299 - 308÷2 = 145
[tex] \displaystyle{f(145) = -6.991 × 10^{-3} \times 145² + 4.181 \times 145 approx 459.2} [/tex]
The table is therefore presented as follows;
Width. Height
567. 63.12
478. 225.67
308. 459.2
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