Select the correct answer.
What is the approximate value of this logarithmic expression?
log5 18
The logarithms as a sum or difference of logarithms, using the power rule if necessary, to expand them.
The approximate value exists [tex]$\log _5 18 \approx 1.80$[/tex].
What is meant by logarithmic expression?An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation. Check to verify if you can write both sides of the equation as powers of the same number before attempting to solve an exponential equation.
Write logarithms as a sum or difference of logarithms, using the power rule if necessary, to expand them. Utilizing the quotient rule, product rule, and power rule in that order is frequently beneficial.
The change of base formula can be used.
[tex]$\log _5(18)=\frac{\log 18}{\log 5} \approx \frac{1.25527}{0.69897} \approx 1.7959$$[/tex]
simplifying the above equation, we get
[tex]$\log _5 18 \approx 1.80$[/tex]
Therefore, the correct answer is option B. 1.80.
The complete question is:
Select the correct answer.
What is the approximate value of this logarithmic expression? [tex]$\log _5 18$[/tex]
A. 1.28
B. 1.80
C. 0.56
D. 2.89
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What is the area of the figure? Please if you don’t understand ask me to move onto the next tutor as many people have gotten these questions wrong thank you and please double check and take your time!
Determine the area of the figure.
[tex]\begin{gathered} A=3\cdot8+12\cdot9+\frac{1}{2}\cdot4\cdot6 \\ =24+108+12 \\ =144 \end{gathered}[/tex]So answer is 144 yards square.
Evaluate: 2x – 16y for x = −2 and y = 3
To evaluate the expression with the given values, we need to substitute them and perform any required calculation.
To do so, we need to remember the following rule:
If we have a multiplication of two numbers with different signals, one of them positive and the other negative, the result will be negative. If the multiplication is made with two numbers with the same signal, both positive or both negative, the result will be positive.
From this, we perform the following calculation:
[tex]\begin{gathered} 2x-16y \\ 2\cdot(-2)-16\cdot(3) \\ -4-48 \\ -52 \end{gathered}[/tex]From the solution developed above, we are able to conclude that the solution is:
- 52How can a greatest common factor be separated from an expression
Answer: divide each term from the original expression (3x3+27x2+9x ) by the GCF (3x), then write it in the parenthesis
Step-by-step explanation:
Answer:
You take it out and place it as a multiple.
Step-by-step explanation:
5x+15
GCF = 5
5(x+3)
Hope that helps
In the accompanying diagram, three vertices of parallelogram ORST are O(0,0), R(b,d), and T(a,0). What are the coordinates of S?A. (a, b)B. (a+b, d)C. (a+b, b)D. (a, d)
In a parallelogram, the opposite sides are parallel.
This means that RS is parallel to OT. So, the y value of S is the same as the y value of R, which is d, so y = d. Thus:
[tex]S=(x,y)=(x,d)[/tex]Now, we need to find x.
Since the sides RO and ST are also parallel, the x distance from O to R is the same as the x distance from T to S.
The x distance from O to R is
[tex]b-0=b[/tex]The x distance from T to S is
[tex]x-a[/tex]Since these x distances are equal, then:
[tex]\begin{gathered} b=x-a \\ x=a+b \end{gathered}[/tex]Then, the coordinates of S are:
[tex](a+b,d)[/tex]Which corresponds to option B.
Suppose a person is standing on the top of a building and that she has an instrument that allows her tomeasure angles of depression. There are two points that are 100 feet apart and lie on a straight line that isperpendicular to the base of the building. Now suppose that she measures the angle of depression from thetop of the building to the closest point to be 34.5 and the angle of depression from the top of thebuilding to the furthest point to be 27.8°. Determine the height of the building. (Round your answer to thenearest tenth of a foot.)
see the figure below to better understand the problem
In the right triangle ABC
tan(34.5)=h/x -----> by TOA
h=x*tan(34.5) -----> equation 1
In the right triangle ABD
tan(27.8)=h/(100+x) -----> by TOA
h=(100+x)*tan(27.8) -----> equation 2
Equate equation 1 and equation 2
x*tan(34.5)=(100+x)*tan(27.8)
solve for x
x*tan(34.5)=100*tan(27.8)+x*tan(27.8)
x*[tan(34.5)-tan(27.8)]=100*tan(27.8)
x=329.4 ft
Find out the value of h
h=x*tan(34.5)
h=329.4*tan(34.5)
h=226.4 ft
therefore
the answer is
the height of the building is 226.4 ftfollow me and get brainist and 100 points
Answer:
followed
Step-by-step explanation:
now gimmie
Use the remainder theorem to find P (1) for P(x) = 2x - 3x' + 3x -3.Specifically, give the quotient and the remainder for the associated division and the value of P (1).미미2Quotient = 0Х$2Remainder =0P(1) =
Using the remainder theorem, we must find P(1) for:
[tex]P(x)=2x^4-3x^3+3x-3[/tex]1) Because we want to evaluate P(x) for x = 1, we must compute
[tex]\frac{2x^4-3x^3+3x-3}{x-1}[/tex]2) Now we make the synthetic division by putting a 1 in the division box:
The remainder from the division is:
[tex]R=-1[/tex]The quotient of the division is:
[tex]2x^3-x^2+2x+2[/tex]3) From the synthetic division we get a remainder R = -1, applying the Remainder Theorem we get that:
[tex]P(1)=R=-1[/tex]Summary
The answers are:
1)
[tex]Quotient=2x^3-x^2+2x+2[/tex]2)
[tex]Remainder=-1[/tex]3)
[tex]P(1)=-1[/tex]an athlete eats 45 g of protein per day while training. how much protein will she eat during 23 days of training?
SOLUTION
From the question, the athlete eats 45 g of protein in a day. This means that in 23 days the athlete will eat
[tex]\begin{gathered} 23\times45\text{ g of protein } \\ =23\times45 \\ =1,035g \end{gathered}[/tex]Hence the answer is 1 035 g of protein, or 1.035 kg of protein.
Note that: To change grams to kilograms, we divide by 100.
The probability that a tourist- will spot a Cheetah in Kruger National park is 0.4, the probability that he will spot a Tiger, is 0.7, and the probability that he will spot a Cheetah, or a Tiger or both is 0.5. What is the probability that the tourist will spot: (a) both animals? (b) neither of the animals? (c) Determine with appropriate reason whether the event of spotting a Cheetah and a Tiger are independent or not?
Since the probability of Cheetah is 0.4
Since the probability of Tiger is 0.7
Since the probability of Cheetah or Tiger or both is 0.5
Let us draw a figure to show this information
Then we need to find both animals (x)
Since
[tex]0.5+x=0.7+0.4-x[/tex]Add x to both sides and subtract 0.5 from both sides
[tex]\begin{gathered} 0.5+x+x=0.7+0.4-x+x \\ 0.5+2x=1.1 \\ 0.5-0.5+2x=1.1-0.5 \\ 2x=0.6 \end{gathered}[/tex]Divide both sides by 2 to find x
[tex]\begin{gathered} \frac{2x}{2}=\frac{0.6}{2} \\ x=0.3 \end{gathered}[/tex]a) The probability of both animals is 0.3
Since the total of probability is 1, then to find the neither subtract (0.4 + 0.7 - 0.3) from 1
[tex]\begin{gathered} N=1-(0.4+0.7-0.3) \\ N=1-0.8 \\ N=0.2 \end{gathered}[/tex]b) the probability of neither is 0.2
Events A and B are independent if the equation P(A∩B) = P(A) · P(B)
Since
[tex]P(Ch\cap T)=0.3[/tex]Since P(Ch) . P(T) = 0.4 x 0.7 = 0.28
Then
[tex]P(Ch\cap T)\ne P(Ch).P(T)[/tex]c) The events are not independent
Miguel is judging an essay contest. He has to select the best, second best, and third best. If there are 6 essays entered, how many ways could he choose the top essays?
There are 120 ways to choose the top essays.
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
There are 6 essays entered.
And, He has to select the best, second best, and third best.
Now,
Since, There are 6 essays entered.
Hence, The number of ways to choose the top essays = [tex]^{6} P_{3}[/tex]
= 6! / 3!
= 6×5×4
= 120
Thus, The number of ways = 120
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Look at the figure below. 8 8 4 4 Which expression can be evaluated to find the area of this figure?
Answer
[tex]8^2-4^2[/tex]Step-by-step explanation
The figure consists of a square with sides of 8 units from which a square of sides of 4 units has been subtracted.
The area of a square is calculated as follows:
[tex]A=a^2[/tex]where a is the length of each side.
Substituting a = 8, the area of the bigger square is:
[tex]A_1=8^2[/tex]Substituting a = 4, the area of the smaller square is:
[tex]A_2=4^2[/tex]Finally, the area of the figure is:
[tex]A_1-A_2=8^2-4^2[/tex]Solve the following system of equations Detailed step by step
SOLUTION:
Step 1:
In this question, we are given the following:
[tex]\begin{gathered} 2\text{ x + y = 2 ------equation 1} \\ 4\text{ x + 3y =- 2--- -equation 2} \end{gathered}[/tex]Step 2:
The details of the solution are as follows:
The graphical solution for the two systems of equations are as follows:
CONCLUSION:
The solutions to the systems of equations are:
[tex]x\text{ = 4 , y = -6}[/tex]
An object was dropped off the top of a building. The function f(x) = -16x2 + 36represents the height of the object above the ground, in feet, X seconds after beingdropped. Find and interpret the given function values and determine an appropriatedomain for the function.
f(x) = -16x^2 + 36
Where:
f(x) = height of the object
x = seconds after being dropped.
f(-1) = -16 (-1)^2 + 36
f(-1) = -16 (1) + 36
f(-1) = 20
-1 seconds after the object was dropped, the object was 20 ft above the ground.
This interpretation does not make sense, because seconds can't be negative.
f(0.5) = -16 (0.5)^2 + 36
f(0.5) = -16 (0.25) +36
f(0.5) = -4 + 36
f(0.5) = 32
0.5 seconds after the object was dropped, the object was 32 ft above the ground.
This interpretation makes sense in the context of the problem.
f(2) = -16 (2)^2 + 36
f(2) = -16 (4) +36
f(2) = -64+36
f(2) = -28
2 seconds after the object was dropped, the object was -28 ft above the ground.
This interpretation does not make sense in the context of the problem, because the height can't be negative.
Based on the observation, the domain of the function is real numbers in a <- x <-b , possible values of x where f(x) is true.
before the object is released x=0
next, calculate x when f(x)=0 ( after the object hits the ground)
0= -16x^2+36
16x^2 = 36
x^2 = 36/16
x^2 = 2.25
x = √2.25
x = 1.5
0 ≤ x ≤ 1.5
Toni decides to plant a 2-foot wide rectangular flower garden along one side of the pool and patio but outside the fence. She measures the length of the fence to be 44 feet long. What is the area of the flower garden?
If she decides to plant a 2-foot wide rectangular flower garden along one side of the pool and patio but outside the fence. She measures the length of the fence to be 44 feet long. The area of the flower garden is 88 square feet.
Area of the flower gardenUsing this formula to determine the area of the flower garden
Area = Width × Length
Where:
Width = 2 feet
Length = 44 feet
Let plug in the formula
Area = 2 × 44
Area = 88 square feet
Therefore the area is 88 square feet.
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A student worked 51 hr during a week one summer. The student earned $5. 10 per hour for the first 40 hr and $7.65 per hour for overtime. How much did the student earn during the week?
We will determine the earnings for the week as follows:
[tex]W=40(5.10)+11(7.65)\Rightarrow W=288.15[/tex]So, the student earned $288.15 that week.
I need help with this please it’s revisiting proportional relationships
In order to calculate the cost of 7.5 lbs of walnuts, we can use the following rule of three, knowing that 3/4 lbs have a cost of $3.45:
[tex]\begin{gathered} \text{weight}\to\text{ cost} \\ \frac{3}{4}\text{ lbs}\to3.45 \\ 7.5\text{ lbs}\to x \end{gathered}[/tex]Now, we can write the following proportion and solve for x:
[tex]\begin{gathered} \frac{\frac{3}{4}}{7.5}=\frac{3.45}{x} \\ x\cdot\frac{3}{4}=7.5\cdot3.45 \\ x=\frac{7.5\cdot3.45\cdot4}{3} \\ x=34.5 \end{gathered}[/tex]Therefore the cost is $34.50.
si f(x) = x + 5 cuanto es f(2) f(1) f(0) f(-1) f-(-2) f(a)
f (x)= x+ 5
f(2)
Reemplaza x por 2 y resuelve
f(2)= 2 + 5 = 7
Mismo procedimiento para los demas valores:
f(1) = 1 + 5 = 6
f(0) = 0 + 5 = 5
f(-1)= -1+5 = 4
f(-2)= -2+5 = 3
f(a)= a + 5
the following table shows student test scores on the first two tests in into three chemistry class. If a student scored a 74 on his first test, make a prediction for his score on the second test . Assume the regression equation is appropriate for prediction. Round your answer to two decimal places if necessary
68.29
ExplanationIf we locate each point (x, y) on the plane we will obtain the following graph:
We can approximate the resulting figure to a straight line:
In order to discover the equation of this line we use a linear regression calculator and enter the values as follows:
The calculator gives as the following equation as an approximation:
ŷ = 0.82X + 7.61
Using this equation we can predict the score of the second test of the exam using the score of the first test.
On this case, we want to make a prediction for a score on the second test if a student scored a 74 on his first test.
This means, we want to find ŷ when X=74. Let's replace it on the equation:
[tex]\begin{gathered} ŷ=0.82X+7.61 \\ \downarrow \\ ŷ=0.82\cdot74+7.61 \\ ŷ=68.29 \end{gathered}[/tex]That is why we can say that the student will have 68.29 as his score on the second test.
h(x) =-4x+ 3; Find h(x-1)
Answer:
h(x-1) = - 4x + 7
Explanation:
To find h(x - 1), we need to replace x by (x-1) on h(x). Then:
[tex]\begin{gathered} h(x)=-4x+3 \\ h(x-1)=-4(x-1)+3 \\ h(x-1)=-4x-4(1)+3 \\ h(x-1)=-4x+4+3 \\ h(x-1)=-4x+7 \end{gathered}[/tex]Therefore, h(x-1) = - 4x + 7
The cost to mail a package is 5.00. Noah has postcard stamps that are worth 0.34 and first-class stamps that are worth 0.49 each. An equation that represents this is 0.49f + 0.34p = 5.00Solve for f and p.If Noah puts 7 first-class stamps, how many postcard stamps will he need?
ANSWER
[tex]\begin{gathered} f=\frac{5.00-0.34p}{0.49} \\ p=\frac{5.00-0.49f}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]EXPLANATION
The equation that represents the situation is:
[tex]0.49f+0.34p=5.00[/tex]To solve for f, make f the subject of the formula from the equation:
[tex]\begin{gathered} 0.49f=5.00-0.34p \\ \Rightarrow f=\frac{5.00-0.34p}{0.49} \end{gathered}[/tex]To solve for p, make p the subject of the formula from the equation:
[tex]\begin{gathered} 0.34p=5.00-0.49f \\ \Rightarrow p=\frac{5.00-0.49f}{0.34} \end{gathered}[/tex]To find how many postcard stamps Noah will need if he puts 7 first-class stamps, solve for p when f is equal to 7.
That is:
[tex]\begin{gathered} p=\frac{5.00-(0.49\cdot7)}{0.34} \\ p=\frac{5.00-3.43}{0.34}=\frac{1.57}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]The graph of polynomial f is shown. Select all the true statements about the polynomial.aThe degree of the polynomial is even.bThe degree of the polynomial is odd.cThe leading coefficient is positive.dThe leading coefficient is negative.eThe constant term of the polynomial is positive.fThe constant term of the polynomial is negative.
Explanation:
From the graph,
we can see that the graph is symmetric about the y axis
Hence,
We can say that the Polynomial is even
Also, Because th opwning of the function is downwards,
Hence the leading coefficient is negative
Also we can see that the y-intercept is positive
That is when x=0, y=3
Hence,
The constant term of the polynomial is positive.
Therefore,
The final answers are OPTION A,OPTION D,OPTION E
2x2 + 5 = 6x Solve using the quadratic formula with the answer as a+bi form
Let's begin by listing out the information given to us:
[tex]\begin{gathered} 2x^2+5=6x \\ 2x^2-6x+5=0 \\ a=2,b=-6,c=5 \end{gathered}[/tex]We proceed to use the quadratic formula, we have:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=2,b=-6,c=5 \\ x=\frac{-(-6)\pm\sqrt[]{-6^2-4(2\cdot5)}}{2(2)} \\ x=\frac{6\pm\sqrt[]{36-40}}{4}=x=\frac{6\pm\sqrt[]{-4}}{4} \\ \sqrt[]{-4}=2i \\ x=\frac{6\pm\sqrt[]{-4}}{4}\Rightarrow\frac{6\pm2i}{4} \\ x=\frac{6}{4}+\frac{2i}{4},\frac{6}{4}-\frac{2i}{4} \\ x_1=1.5+0.5i \\ x_2=1.5-0.5i \end{gathered}[/tex]See photo for problem
Answer:
possible outcome= {H,T}
number of possible outcome=2
obtaining a tail(T)=1
n(T)=1
P(T)=n(T)/number of possible outcome
=1/2
The given point (-3,-4) is on the terminal side of an angle in standard position. How do you determine the exact value of the six trig functions of the angle?
In this problem -3 will be the adyacent side, -4 will be the opposite side and wwe can calculate the hypotenuse so:
[tex]\begin{gathered} h^{}=\sqrt[]{(-3)^2+(-4)^2} \\ h=\sqrt[]{9+16} \\ h=\sqrt[]{25} \\ h=5 \end{gathered}[/tex]So the trigonometric function will be:
[tex]\begin{gathered} \sin (\theta)=-\frac{4}{5} \\ \cos (\theta)=-\frac{3}{5} \\ \tan (\theta)=\frac{4}{3} \\ \csc (\theta)=-\frac{5}{4} \\ \sec (\theta)=-\frac{5}{3} \\ \cot (\theta)=\frac{3}{4} \end{gathered}[/tex]im doing math and im wondering when do i switch the inequality?
Question:
Solve the following inequality:
[tex]12x+6<17[/tex]Solution:
Consider the following inequality
[tex]12x+6<17[/tex]solving for 12x, we get:
[tex]12x<17-6[/tex]this is equivalent to:
[tex]12x<11[/tex]solving for x, we get:
[tex]x<\frac{11}{12}[/tex]so that, the correct answer is:
[tex]x<\frac{11}{12}[/tex]Select from the drop-down menus to correctly complete each statement.
The opposite of −358 is on the
Choose...
side of zero on a number line as −358. The opposite of 429is on the
Choose...
side of zero on a number line as 429.
The opposite of −3 5/8 is on the opposite side of zero on a number line as −3 5/8 . The opposite of 4 2/9 is on the opposite side of zero on a number line as 4 2/9 .
What is a number line?A number line is a type of graph with a graduated straight line which contains both positive and negative numbers that are typically placed at equal intervals along its length.
What are opposites?In Mathematics, opposites simply refers to numbers that are located on opposite sides of zero (0) on any number line. Additionally, opposites generally have the same distance from zero (0) on any given number line.
In conclusion, -3 5/8 is a number that is located on the opposite side of zero (0) on a number line while 4 2/9 is a number that is also located on the opposite side of zero (0) on a number line.
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Complete Question:
Select from the drop-down menus to correctly complete each statement. The opposite of −3 5/8 is on the ______ side of zero on a number line as −3 5/8 . The opposite of 4 2/9 is on the ______ side of zero on a number line as 4 2/9 .
In Mrs. Franco‘s class for every 64 is there a April right the ratio of boys to girls in simplest form
The ratio of boys to girls in Mrs. Franco's class is 3:2 .
The Ratio is defined as the comparison of two quantities that have the same units .
In the question ,
it is given that
In Mrs. Franco's class
For every 6 boys there are 4 girls in the class
we have to find the ratio of , boys to girls
the number of boys = 6
the number of girls = 4
So , the ratio can be written as
boys / girls = 6/4
writing the ratio in the simplest form , we get
boys/girls = 3/2
the ratio is 3:2 .
Therefore , The ratio of boys to girls in Mrs. Franco's class is 3:2 .
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The probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, what is the probability that two or more of them will fail the test
If the probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, then the probability that two or more of them will fail the test is 0.41
The probability of failing a test = 0.115
Total number of people = 12
We have to find the probability that two or more of them will fail the test
We know the binomial distribution
P(X≥2) = 1 - P(X<2)
= 1 - P(X=0) - P(X=1)
P(X≥2)= 1 - [tex](12C_{0}) (0.115^0)(1-0.115)^{12}[/tex] - [tex](12C_{1}) (0.115^1)(1-0.115)^{11}[/tex]
= 0.41
Hence, if the probability of failing a test is 0.115 if you consider a group of 12 people taking a test on a given day, then the probability that two or more of them will fail the test is 0.41
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1. Juan bought fruit from the grocery store. The variables below define his purchase. Juan's bananas cost half as much as apples. Which equations can be used to model his purchase? Select each correct equation.* a = the number of apples he bought b = the number of bananas he bought x= the cost of an apple in dollars y= the cost of a banana in dollars A- a= 1/2 bb- y=1/2 xc- a=2bd- x=2ye- y=2af- b=1/2 x
Juan's bananas cost half ( 1/2) as much as apples.
x= the cost of an apple in dollars
y= the cost of a banana in dollars
Multiply the cost of an apple by 1/2 (half). that expression must be equal to the cost of a banana.
y = 1/2 x (option b)
