Find the values of w and x that makeup NOPQ a parallelogram. A. W = 1/2 X = 1/2 B. W = 3 X = 2 C. W = 2 X = 2 D. W = 3 X = 1/2 Please select the best answer from the choices Provided

Find The Values Of W And X That Makeup NOPQ A Parallelogram. A. W = 1/2 X = 1/2 B. W = 3 X = 2 C. W =

Answers

Answer 1

Solution

Step 1:

Properties of Parallelograms Explained

1. Opposite sides are parallel. ...

2. Opposite sides are congruent. ...

3. Opposite angles are congruent. ...

4. Same-Side interior angles (consecutive angles) are supplementary. ...

5. Each diagonal of a parallelogram separates it into two congruent triangles. ...

6. The diagonals of a parallelogram bisect each other.

Step 2:

The diagonals of a parallelogram bisect each other.

[tex]\begin{gathered} The\text{ }diagonals\text{ }of\text{ }a\text{ }parallelogram\text{ }bisect\text{ }each\text{ }other. \\ w\text{ + 7 = 5w - 5} \\ and \\ \frac{3}{2x}\text{ = 3} \end{gathered}[/tex]

Step 3

[tex]\begin{gathered} Solve\text{ for w:} \\ w\text{ + 7 = 5w - 5} \\ Add\text{ similar terms} \\ 7\text{ + 5 = 5w - w} \\ 12\text{ = 4w} \\ w\text{ = }\frac{12}{4} \\ w\text{ = 3} \end{gathered}[/tex]

Step 4

[tex]\begin{gathered} Solve\text{ for x:} \\ \frac{3}{2x}\text{ = 3} \\ 3\times2x\text{ = 3} \\ \\ 6x\text{ = 3} \\ \\ x\text{ = }\frac{3}{6} \\ \\ x\text{ = }\frac{1}{2} \end{gathered}[/tex]

Final answer

[tex]\text{w = 3 . x = }\frac{1}{2}[/tex]


Related Questions

Choose the best description of its solution. If applicable, give the solution.

Answers

Given:

[tex]\begin{gathered} -x-3y=-6\ldots\text{ (1)} \\ x+3y=6\ldots\text{ (2)} \end{gathered}[/tex]

Adding equation(1) and equation(2)

[tex]\begin{gathered} -x-3y+x+3y=-6+6 \\ 0=0 \end{gathered}[/tex]

The system has infinitely many solution .

They must satisfy the equation:

[tex]y=\frac{6-x}{3}[/tex]

There are four Defenders on a soccer team if this represents 20% of the players on the team which equation can be used to find the total number of players on the team

Answers

Given in the question:

a.) There are four Defenders on a soccer team.

b.) This represents 20% of the players on the team.

An empty rectangular tank measures 60 cm by 50 cm by 56 cm. It is being filled with water flowing from a tap at rate of 8 liters per minute. (a) Find the capacity of the tank (b) How long will it take to fill up (1 liter = 1000 cm

Answers

(a) The capacity of the tank is its volume, which we can calculate by multipling its sides:

[tex]V=abc=60\cdot50\cdot56=168000[/tex]

This is, 168000 cm³. It is equivalent to 168 L.

(b) If the tank is being filled at a rate of 8 liters per minute, we can find the time to fill ir by dividing its capacity by the rate:

[tex]t=\frac{168}{8}=21[/tex]

That is, it will take 21 minutos to fill it up.

The points (-6, -10) and (23, 6) form a line segment.
Write down the midpoint of the line segment.

Answers

A line segment has the endpoints at (-6, -10) and (23, 6) then the midpoints of the line segment will be (17, -2).

What is meant by line segment?

An area or portion of a line with two endpoints is called a line segment. A line segment, in contrast to a line, has a known length. A line segment's length can be estimated by utilizing either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches.

A line segment has the endpoints at (-6, -10) and (23, 6).

Mid point of the line segment is given by [tex]$\left(\frac{x_1+x_2}{2}\right),\left(\frac{y_1+y_2}{2}\right)$[/tex]

The midpoints of the line segment will be

=  [tex]$\frac{23+-6}{2}[/tex], [tex]$\frac{-10+6}{2}}[/tex]

= 17, -2

Therefore midpoints of the line segment will be (17, -2).

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given: S is the midpoint of BT ; BO || AT prove:

Answers

"S is the midpoint of BT": this is given.

BO || AT: this is given.

SB = ST: definition of midpoint.

alternate interior

vertical

ΔBOS = ΔTAS: SAS or ASA (both are right).

distance between (11,-5) and (0,1)

Answers

Here,point can be written as:

[tex]\begin{gathered} x1=11, \\ y1=-5 \\ x2=0 \\ y2=1 \end{gathered}[/tex]

The formula for the distance between the points as follows;

[tex]\begin{gathered} d=\sqrt{(x1-x2)^2+(y1-y2)^2} \\ d=\sqrt{(11-0)^2+(-5-1)^2} \\ d=\sqrt{121+36} \\ d=\sqrt{157} \\ d=12.53 \end{gathered}[/tex]

Thus, the distance between the point is 12.53.

69=2g-24 I NEED TO FIND G

Answers

G = 46.5

Add 24 to 69 to get 93. Then divide 93 by 2 to get G

what does frilling mean

Answers

Answer:

A ruffled, gathered, or pleated border or projection, such as a fabric edge used to trim clothing.

Step-by-step explanation:

Brainlest, Please!

What is the mean and median of the data set

Answers

The mean of a data set is the sum of the data divided by the total number of data.

The median of a data set is the middle number in the set (after the numbers have been arranged from least to greatest, or, if there is an even number of data, the median is the average of the two middle numbers.

You have the next data set:

[tex]\begin{gathered} \lbrace11,11,11,11,12,12,12,13,13,13,13,13,13,14,15,15,15,15,15, \\ 15,16,16,16,16,16,17,17,17\rbrace \end{gathered}[/tex]

A total of 28 data.

The mean is equal to the sum of the 28 numbers and then divided into 28:

[tex]undefined[/tex]

Question 23 of 25
What is the effect on the graph of f(x) = when it is transformed to
g(x) = +17?
A. The graph of f(x) is shifted 17 units down.
B. The graph of f(x) is shifted 17 units to the right.
OC. The graph of f(x) is shifted 17 units up.
OD. The graph of f(x) is shifted 17 units to the left.

Answers

Answer:

C. The graph of f(x) is shifted 17 units up.

Step-by-step explanation:

When + is outside the equation, it means up.

Expand the following using the suitable identity.(-x + 2y - 3z)^2

Answers

Answer: [tex]x^2+4y^2+9z^2-4xy+6xz_{}-12yz[/tex]

Explanations:

Given the expression (-x + 2y - 3z)², we are to expand it using a suitable identity.

Using the square of the sum of trinomial identity expressed as:

[tex](a+b+c)^2=a^2+b^2+c^2+2\text{ab+2ac+2bc}[/tex]

From the given expression;

[tex]\begin{gathered} a=-x \\ b=2y \\ c=-3z \end{gathered}[/tex]

Substitute the parameters into the identity to expand as shown:

[tex](-x+2y-3z)^2=(-x)^2+(2y)^2+(-3z)^2+2(-x)(2y)+2(-x)(-3z)_{}+2(2y)(-3z)[/tex]

Simplify the result to have:

[tex](-x+2y-3z)^2=x^2+4y^2+9z^2-4xy+6xz_{}-12yz[/tex]

This gives the correct expansion using a suitable identity

Benjamin mows two lawns. The first lawn is 8 meters long and 7 meters wide. The second lawn has the same length, and a width that is 6 times as much as the first one. What is the total area of the two lawns?​

Answers

Area overall is 392 square metres. The two lawns' combined area is therefore 392 square metres.

what is square ?

A square is a quadrilateral in geometry that has four equal sides and four right angles (90-degree angles). It is a unique kind of both a rhombus and a rectangle. A square is made up of four equal-length sides, two equal-length diagonals, and right-angle diagonal cuts. A square's area and perimeter can be calculated by multiplying one of its sides by itself (squared), and one of its sides by four, respectively. Because of their symmetry and regularity, squares are frequently employed in mathematics and building.

given

By multiplying the first lawn's length by its breadth, one may determine its area: 56 square metres is the size of the first lawn, which is 8 metres by 7 metres.

The second lawn's breadth is six times that of the first lawn's, so:

The second lawn's width is equal to 6 × 7 metres, or 42 metres.

The second lawn is the same length as the first one, so:

The second lawn is 8 metres long.

The second lawn's area is calculated by multiplying its length by its width:

The second lawn is 336 square metres in size (8 metres by 42 metres).

The first and second lawns' combined areas make up the overall area of the two lawns:

Total area equals the sum of the first and second lawns.

56 square metres + 336 square metres make up the total area.

Area overall is 392 square metres. The two lawns' combined area is therefore 392 square metres.

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Pour subtracted from the product of 10 and a number is at most-20,

Answers

we have

four subtracted from the product of 10 and a number is at most-20

Let

n ----> the number

so

[tex]10n-4\leq-20[/tex]

solve for n

[tex]\begin{gathered} 10n\leq-20+4 \\ 10n\leq-16 \\ n\leq-1.6 \end{gathered}[/tex]

the solution for n is the interval (-infinite, -1.6]

All real numbers less than or equal to negative 1.6

How do I find the linear equation for this? (y=mx+b)

Answers

Okay, here we have this:

Considering the provided table, we are going to find the corresponding linear equation, so we obtain the following:

To do this we will start using the information in the slope formula, then we have:

m=(y2-y1)/(x2-x1)

m=(190-(-30))/(19-9)

m=220/10

m=22

Now, let's find the y-intercept (b) using the point (9, -30):

y=mx+b

-30=(22)9+b

-30=198+b

b=-30-198

b=-228

Finally we obtain that the linear equation is y=22x-228

Answer:

Step-by-step explanation:

These are the two methods to finding the equation of a line when given a point and the slope: Substitution method = plug in the slope and the (x, y) point values into y = mx + b, then solve for b. Use the m given in the problem, and the b that was just solved for, to create the equation y = mx + b.

Use the graph of y = f (x) to find the following value of f. f(2) =

Answers

Answer:

f(2)=4

Explanation:

Consider the graph below:

When x=2, the value of f(x) = 4 (the poiny circled in blue above).

Therefore:

[tex]f(2)=4[/tex]

The value of f(2) is 4.

At a local school, 164 students play soccer and 112 students play baseball. What is the ratio of soccer players to baseball players?41:2828:4113:2828:13

Answers

Given

The number of students who play soccer is 164.

The number of students who play baseball is 112

Explanation

To find the ratio of soccer player to baseball players .

Divide the number of soccer player by the number of baseball player.

[tex]\frac{164}{112}=\frac{41}{28}[/tex]

Answer

Hence the ratio of soccer players to baseball players is

[tex]41:28[/tex]

Let log, A = 3; log, C = 2; log, D=5 D? what is the value of

Answers

Evaluate the value of expression.

[tex]\begin{gathered} \log _b\frac{D^2}{C^3A}=\log _bD^2-\log _bC^3-\log _bA \\ =2\log _bD-3\log _bC-\log _bA \\ =2\cdot5-3\cdot2-3 \\ =10-6-3 \\ =1 \end{gathered}[/tex]

So answer is 1.

A business woman buys a new computer for $4000. for each year that she uses it the value goes depreciates by $400 the equation below gives the value y of the computer after x years. What does the x intercept mean in this situation? Find the x intercept. After how many years will the value of the computer be $2000Y=-400x+4000

Answers

Step 1: Write the equation

y = -400x + 4000

Step 2:

The intercept in the equation represents time in years.

x-intercept represents the total length of time taken in years for the computer to values to depreciate to $0.

step 3: Find the x-intercept

To find the x-intercept, you will have to find the time taken for the computer value to depreciate to $0.

y = $0

[tex]\begin{gathered} \text{From the equation.} \\ y\text{ = -400x + 4000} \\ 0\text{ = -400x + 4000} \\ 400x\text{ = 4000} \\ x\text{ = }\frac{4000}{400} \\ x\text{ = 10} \end{gathered}[/tex]

The x-intercept = 10 years

Step 4:

To find the number of years take for the computer value to depreciate to $2000.

You will substitute the value of y = $2000 and find the value of x.

Therefore

[tex]\begin{gathered} y\text{ = -400x + 4000} \\ 2000\text{ = -400x + 4000} \\ 400x\text{ = 4000 - 2000} \\ 400x\text{ = 2000} \\ x\text{ = }\frac{2000}{400} \\ \text{x = 5 years} \end{gathered}[/tex]

It will take 5 years for the value of the computer to depreciate to $2000.

Question number 3: which of the following is equal to 18x*7 y*6?

Answers

Solution:

Given:

[tex]\sqrt{18x^7y^6}[/tex]

Splitting the expressions further to get the perfect squares out:

[tex]\begin{gathered} \sqrt{18x^7y^6}=\sqrt{9\times2\times(x^6\cdot x)\times(y^3)^2} \\ =\sqrt{9\times2\times(x^3)^2\cdot x\times(y^3)^2} \end{gathered}[/tex]

[tex]\begin{gathered} \sqrt{18x^7y^6}=\sqrt{9\times2\times(x^3)^2\cdot x\times(y^3)^2} \\ =3x^3y^3\sqrt{2x} \end{gathered}[/tex]

Therefore, the correct answer is:

[tex]3x^3y^3\sqrt{2x}[/tex]

NEED ASAP IF CORRECT ILL GOVE BRAINLIEST

Answers

Answer:

I believe the answer is g(x)=x+10

Step-by-step explanation:

it moves 4 units to the right making it positive, adding to the previous 6 units, making it move 10 units to the right

I think the answer is g(x) = x -10

20. Two teachers measured the shoe size of each of their students. The datawere used to create the box plots shown.Mrs. Norris's Class567891011121314Shoe SizeMrs. Ganger's Class5 6+87111213149 10Shoe SizeBased on the data, which statement about the results must be true?The average shoe size is the same for both classes.The shoe sizes 6 and 13 are outliers for both classes.© Mrs. Norris's class and Mrs. Ganger's class have the sameinterquartile range.© The median shoe size for Mrs. Norris's class is greater than forMrs. Ganger's class.

Answers

The correct answer is the last sentence.

"The median shoe size for Mrs. Norris's class is greater than for

Mrs. Ganger's class".

What value of t makes the following equation true?

5t−2=6t−7

Answers

After working out the problem, the answer is 5

Factor each polynomial by factoring out the greatest common factorminimum steps please

Answers

we are given the following expression:

[tex]12x^4+6x^3-8x^2[/tex]

The greatest common factor between 12, 6, and 8 is 2. And the greatest common factor between the variables is:

[tex]\text{GCF(x}^4,x^3,x^2)=x^2[/tex]

Therefore, the factorization is:

[tex]12x^4+6x^3-8x^2=2x^2(6x^2+3x-4)[/tex]

Find the measure of the arc or central angle indicated. Assume that lines which appear to bediameters are actual diameters.

Answers

From the given circle, the measure of the arc or the central angle indicated is as shown at the center of the circle is subtended by the arc

Hence, the measure of the arc or central angle indicated is 65° ,Option B

if Maria collected R rocks and Javy collected twice as many rocks as Maria and Pablo collected 5 less than Javy. What is the sum of rocks collected by Pablo and Maria?

Answers

This problem deals with the numbers expressed in a more general way: letters or variables

That belongs to Algebra

We know Maria collected R rocks. Let's put this in a separate line:

M = R

Where M is meant to be the number of rocks collected by Maria

Now we also know Javy collected twice as many rocks as Maria did. Thus, if J is that variable, we know that

J = 2R

Pablo collected 5 less rocks than Javy. This is expressed as

P = J - 5

or equivalently:

P = 2R - 5

since J = 2R, as we already stated

We are now required to calculate the sum of rocks collected by Pablo and Maria.

This is done by adding P + M:

P + M = (2R - 5) + (R)

We have used parentheses to indicate we are replacing variables for their equivalent expressions

Now, simplify the expression:

P + M = 2R - 5 + R

We collect the same letters by adding their coefficients:

P + M = 3R - 5

Answer: Pablo and Maria collected 3R - 5 rocks together

Question 3(Multiple Choice Worth 2 points)
(01.06 MC)
Simplify √√-72-
--6√√2
6√-2
6√√2i
061√2

Answers

Answer:

[tex]6i\sqrt{2}[/tex]

Step-by-step explanation:

Given expression:

[tex]\sqrt{-72}[/tex]

Rewrite -72 as the product of 6 · -1 · 2:

[tex]\implies \sqrt{36 \cdot -1 \cdot 2}[/tex]

Apply the radical rule  [tex]\sqrt{ab}=\sqrt{a}\sqrt{b}:[/tex]

[tex]\implies \sqrt{36} \sqrt{-1} \sqrt{2}[/tex]

Carry out the square root of 36:

[tex]\implies 6\sqrt{-1}\sqrt{2}[/tex]

Apply the imaginary number rule [tex]\sqrt{-1}=i[/tex] :

[tex]\implies 6i\sqrt{2}[/tex]

Use long division or a calculator to write 4/99 as a decimal. Then tell whether the decimal is terminating or repeating

Answers

0.0404

Repeating decimal (periodic)

1) Let's proceed with the long division of 4 by 99:

1.1) Since 4 is way smaller than 99 let's add one zero to the dividend and another for the quotient followed by a dot.

But 40 is still lesser than 99, so let's add another zero after the dot to make it 400. Now we can divide 400 by 99

1.2) Again to proceed with that division we'll need to write a zero at that 4 and another one in the quotient.

As and we can see already this a repeating decimal or periodic. This division will yield 0.0404040404.....

2) Hence, the answer is 0.0404

Help with number one a and b is both parts of number one

Answers

Solving the operation_

We are given two figures that represent a garden. We are asked to determine its areas.

The shape of figure A is a rectangle of 9 ft by 12 ft. The area of a rectangle is the product of its dimensions therefore, we have:

[tex]A_A=\left(9ft\right)\left(12ft\right)[/tex]

Solving the operations:

[tex]A_A=108ft^2[/tex]

The shape of figure B is a circle of radius 5ft. The area of a circle is:

[tex]A_B=\pi r^2[/tex]

Where "r" is the radius. Substituting we get:

[tex]A_B=\pi\left(5ft\right)^2[/tex][tex]A_B=25\pi ft^2[/tex]

In decimal notation, the area is:

[tex]A_B=78.54ft^2[/tex]

help meeeeeeeeee pleaseee !!!!!

Answers

The composition will be:

(g o h)(x) = 5*√x

By evaluating in x = 0, we get:

(g o h)(0) = 0

How to evaluate the composition?

Here we have the two functions:

g(x) = 5x

h(x) = √x

And we want to get the composition:

(g o h)(x) = g( h(x))

So we need to evaluate g(x) in h(x), we will get:

g( h(x)) = 5*h(x) = 5*√x

And now we want to evaluate this in x = 0, we will et:

(g o h)(0) = 5*√0 = 0

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Given right triangle ABC, with altitude CD intersecting AB at point D. If AD = 5 and DB = 8, find the length of CD, in simplest radical form. In your video include whether you would use SAAS or HYLLS to solve (and WHY), the proportion you would set up, how you would solve for the missing side, and how you know your answer is in simplest radical form.

Answers

First we dra a triangle:

To prove that the triangles are similar we have to do the following:

Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

[tex]\Delta ABC\approx\Delta ACD[/tex]

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

[tex]\Delta ABC\approx\Delta BCD[/tex]

With this we conclude that traingles BCD and ACD are both similar to triangle ABC, and by the transitivity property of similarity we conclude that:

[tex]\Delta ACD\approx BCD[/tex]

Now that we know that both triangles are similar we can use the following proportion:

[tex]\frac{h}{x}=\frac{y}{h}[/tex]

this comes from the fact that the ratios should be the same in similar triangles.

From this equation we can find h:

[tex]\begin{gathered} \frac{h}{x}=\frac{y}{h} \\ h^2=xy \\ h=\sqrt[]{xy} \end{gathered}[/tex]

Plugging the values we have for x and y we have that h (that is the segment CD) has length:

[tex]\begin{gathered} h=\sqrt[]{8\cdot5} \\ =\sqrt[]{40} \\ =\sqrt[]{4\cdot10} \\ =2\sqrt[]{10} \end{gathered}[/tex]

Therefore, the length of segment CD is:

[tex]CD=2\sqrt[]{10}[/tex]

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