Find the volume of this triangular prism.Be sure to include the correct unit in your answer.8 cm7 cm→5 cm
Answers
The formula to find the volume of a triangular prism is the following:
[tex]V=\frac{1}{2}h\cdot b\cdot w[/tex]where:
h - height
b - base length
w - width
for this problem:
h = 8 cm
b = 5 cm
w = 7 cm
then
[tex]V=\frac{1}{2}8\cdot5\cdot7[/tex]solving this, we obtain that the volume of the triangular prism is 140 cm^3 or cubic centimeters
Related Questions
Find the measures of the sine and cosine of the following triangles
Answers
Let x be the side opposite to angle 62 degrees
Let y be the adjacent angle.
The sine of the angle is given as follows:
[tex]\begin{gathered} \sin62=\frac{Opposite}{Hypotenuse}=\frac{x}{10} \\ \end{gathered}[/tex]The cosine is given as:
[tex]\cos62=\frac{Adjacent}{Hypotenuse}=\frac{y}{10}[/tex]Need help figuring out if the following is Real or Complex Question number 10
Answers
Explanation:
We have the expression:
[tex]i^3[/tex]where i represents the complex number i defined as follows:
[tex]i=\sqrt{-1}[/tex]To find if i^3 is real or complex, we represent it as follows:
[tex]i^3=i^2\times i[/tex]And we find the value of i^2 using the definition of i:
[tex]i^2=(\sqrt{-1})^2[/tex]Since the square root and the power of 2 cancel each other
[tex]\imaginaryI^2=-1[/tex]And therefore, using this value for i^2, we can now write i^3 as follows:
[tex]\begin{gathered} \imaginaryI^3=\imaginaryI^2\times\imaginaryI \\ \downarrow \\ \imaginaryI^3=(-1)\times\imaginaryI \end{gathered}[/tex]This simplifies to -i
[tex]\imaginaryI^3=-\imaginaryI^[/tex]Because -i is still a complex number, that means that i^3 is a complex number.
Answer: Complex
A certain marine engine has cylinders that are 5.25 cm in diameter and 5.64 cm deep.Find the total volume of 4 cylinders (to the nearest hundredth). Use 3.14 as the approximate value of
Answers
Given:
A cylinder is given with 5.64 cm deep and 5.25 cm diameter.
Required:
Total volume of 4 cylinders.
Explanation:
Diameter of cylinder d = 5.25 cm
Height of cylinder or deepness of cylinder h = 5.64 cm
Radius r of cylinder is
[tex]r=\frac{d}{2}=\frac{5.25}{2}=2.625\text{ cm}[/tex]volume of cylinder is
[tex]v=\pi r^2h=3.14*2.625^2*5.64=122.03\text{ cm}^3[/tex]here we need volume of 4 cylinder
for this we just multiply v with 4
[tex]V=4v=4*122.03=488.121\text{ cm}^3[/tex]Final Answer:
The volume of 4 cylinder is 488.121 cube cm
quadrilateral WXYZ is reflected across the line y=x to create quadrilateral W’X’Y’Z'. What are the coordinates of quadrilateral W’X’Y’Z'.
Answers
Explanation
We are required to determine the coordinates of W’X’Y’Z' when WXYZ is reflected across the line y = x.
This is achieved thus:
From the image, we can deduce the following:
[tex]\begin{gathered} W(-7,3) \\ X(-5,6) \\ Y(-3,7) \\ Z(-2,3) \end{gathered}[/tex]We know that the following reflection rules exist:
Therefore, we have:
[tex]\begin{gathered} (x,y)\to(y,x) \\ W(-7,3)\to W^{\prime}(3,-7) \\ X(-5,6)\to X^{\prime}(6,-5) \\ Y(-3,7)\to Y^{\prime}(7,-3) \\ Z(-2,3)\to Z^{\prime}(3,-2) \end{gathered}[/tex]Hence, the answers are:
[tex]\begin{gathered} \begin{equation*} W^{\prime}(3,-7) \end{equation*} \\ \begin{equation*} X^{\prime}(6,-5) \end{equation*} \\ \begin{equation*} Y^{\prime}(7,-3) \end{equation*} \\ \begin{equation*} Z^{\prime}(3,-2) \end{equation*} \end{gathered}[/tex]This is shown in the graph bwlow for further undertanding:
Try This question out and I’ll give you brainliest no links or I will report you
Answers
Answer: ∠ABD = 19°
Step-by-step explanation:
The angle formed by ABC is a complementary angle. This means the sum of both angles adds up to 90 degrees.
Since angle DBC is 71 degrees, 90 - 71 equals ∠ABD
90 - 71 = 19
Therefore ∠ABD = 19°
Answer:
m∠ABD = 19°
Step-by-step explanation:
Hello!
Recall that all angles of a rectangle are 90° in measure.
Angle B is 90°, and is made up of angles ABD and DBC.
We know the measure of angle DBC, it's given as 71°. We can find the measure of ABD by subtracting 71° from 90°.
Find ABDABC = ABD + DBC90 = ABD + 7119 = ABDSo the measure of angle ABD is 19°.
A tourist from the U.S. is vacationing in China. One day, he notices that has cost 6.84 yuan per liter. On the same day, 1 yuan is worth 0.14 dollars. How much does the gas cost in dollars per gallon? Fill in the two blanks on the left side of the equation using two of the ratios. THEN WRITE THE ANSWER ROUNDED TO THE NEAREST HUNDREDTH. Will send pic of question.
Answers
Solve:
[tex]\frac{6.84\text{ yuan}}{1\text{ L}}\times\frac{0.14\text{ dollars}}{1\text{ yuan}}\times\frac{3.79\text{ L}}{1\text{ gal}}=3.63\frac{dollars}{gal}[/tex]1) There is a proportional relationship between the number of months a person has had a streaming movie subscription and the total amount of money they have paid for the subscription. The cost for 6 months is $47.94. The point (6,47.94) is shown on the graph below. 180 160 140 120 100 cost (dollars) 80 60 (6, 47.94) 40 20 16 18 8 20 22 2. 4 6 10 12 14 time (months)
Answers
Given:
The point which describes the relationship between the months and total amount is, (6, 47.94).
a) To find the constant proportionality:
6 months =47.94
Then, for 1 month,
[tex]\frac{47.94}{6}=7.99[/tex]Hence, the constant proportionality is $7.99.
b) The constant proportionality tells that, if the month is increased then the cost is also increased by $7.99.
c) To find the three more points and label it:
For the month, m=1, then the cost c=$7.99
For the month, m=2, then the cost c=$15.98
For the month m=3, then the cost c=$23.97
Therefore, the three points are (1, 7.99), (2,15.98) and (3, 23.97).
The graph is,
d) The relationship between the months and the cost is,
C=7.99 m
What kind of transformation converts the graph of f(x)=(5x+6)^2 into the graph of g(x)=-(5x+6)^2
Answers
In order to get from
[tex]f(x)=(5x+6)^2[/tex]To
[tex]f(x)=-(5x+6)^2[/tex]You have to reflect across the x-axis.
Remember that the x-axis is the line with equation
[tex]y=0[/tex]Answer: Option A
3) Describe what ALL graphs of proportional relationships have in common
Answers
SOLUTION
What all graphs of proportional relationships have in common is a straight line.
This line is straight, no curves or bends. This straight line passes through the origin at an intersection of
[tex](0,0)[/tex]Hence, the answer is "A straight line that passes through the origin and goes at a constant rate".
the equation of line u is y=2x+8/9. line v includes the point (7,9) and is parallel to line u. what is the equation of.line v
Answers
The linear equation parallel to line u that passes through (7,9) is y = 2x - 5
How to find the equation of line V?
Two lines are parallel if have the same slope, we know that line V is parallel to:
y = 2x + 8/9
Then line V will be of the form:
y = 2x + c
To find the value of c, we use the fact that the line passes through (7, 9), replacing these values we get:
9 = 2*7 + c
9 = 14 + c
9 - 14 = c
-5 = c
The linear equation is y = 2x - 5
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what is the slope of any line is perpendicular to the equation y=1/2x-7
Answers
The slope = -2
Explanations:The given equation is:
[tex]y\text{ = }\frac{1}{2}x\text{ - 7}[/tex]This is of the form y = mx + c
where the slope, m = 1/2
The equation perpendicular to the equation y = mx + c is:
[tex]y-y_1=\frac{-1}{m}(x-x_1)[/tex][tex]\begin{gathered} \text{The slope = }\frac{-1}{m} \\ \text{The slope = }\frac{-1}{\frac{1}{2}}=\text{ -2} \end{gathered}[/tex]The slope = -2
Find the variance for the set of data: 22, 26, 17, 20, 20.The variance is
Answers
The variance of a given data set with size N is given by the formula:
[tex]\begin{gathered} \sigma=\sqrt{\frac{1}{N}\sum_{i=1}^N(x_i-\mu)^2} \\ Var(X)=\sigma^2 \end{gathered}[/tex]Then, for the data set {22, 26, 17, 20, 20} and N = 5, we have:
[tex]\begin{gathered} \mu=\frac{22+26+17+20+20}{5}=21 \\ \sigma=\sqrt{\frac{1^2+5^2+(-4)^2+(-1)^2+(-1)^2}{5}}=\sqrt{\frac{44}{5}}=2\sqrt{\frac{11}{5}} \\ \therefore Var(X)=\frac{44}{5}=8.8 \end{gathered}[/tex]The period T(In seconds) of a pendulum is given by T=2PI(Square root of L/32) Where L stands for length (in feet) of the pendulum If pi =3.14 and the period is 6.28 what is the length
Answers
Let me check your question
[tex]T\text{ = 2}\cdot\text{ 3.14}\cdot\text{ }\sqrt[]{L/\text{ 32}}[/tex][tex]\frac{T}{2\cdot\text{ 3.14}}\text{ = }\sqrt[]{L/\text{ 32}}[/tex]T= the period = 6.28
[tex]\frac{6.28}{6.28}\text{ = }\sqrt[]{L/\text{ 32}}[/tex][tex]L/32=1^2[/tex][tex]L=32[/tex]_________________
Answer
L= 32
Referring to the table in question 14, how would you graph the solution set representing students that do not receive a note sent home to parents?Draw points on the integers to the left of, and including, 0.Draw points on the integers to the right of, and including, 0.Draw points on the integers to the left of 0.Draw points on the integers to the right of 0.
Answers
According to the table, the statement "note sent to parents" is represented by the following inequality:
[tex]points\text{ < 0}[/tex]this can be represented as all integers less than zero. That is all integers to the left of 0.
We can conclude that the correct answer is:
Answer:Draw points on the integers to the left of 0.
which of the following are the coordinates of point B on the directed line segment AC, such that AB is 1/5 of AC?
Answers
Answer:
The coordinates of point B is;
[tex](5,-7)[/tex]Explanation:
Given the attached image;
The coordinate of point A is;
[tex](8,-8)[/tex]The coordinate of point C is;
[tex](-7,-3)[/tex]If AB is 1/5 of AC;
[tex]\Delta x_{AB}=\frac{1}{5}(\Delta x_{AC})_{}_{}_{}_{}_{}_{}[/tex]So; let (x,y) represent the coordinates of B;
[tex]\begin{gathered} (8-x)=\frac{1}{5}(8-(-7)) \\ 8-x=\frac{1}{5}(15) \\ 8-x=3 \\ x=8-3 \\ x=5 \end{gathered}[/tex]The same applies to y coordinate;
[tex]\Delta y_{AB}=\frac{1}{5}(\Delta y_{AC})_{}[/tex]So;
[tex]\begin{gathered} (-8-y)=\frac{1}{5}(-8-(-3)) \\ -8-y=\frac{1}{5}(-8+3) \\ -8-y=\frac{1}{5}(-5) \\ -8-y=-1 \\ y=-8+1 \\ y=-7 \end{gathered}[/tex]Therefore, the coordinates of point B is;
[tex](5,-7)[/tex]Amplitude, period, and phase shift of sine and cosine functions
Answers
We are given that
[tex]y=-2+2\cos (2x-\frac{\pi}{3})[/tex]Note: Given the cosine function
[tex]y=a\cos (bx-c)+d[/tex]then
[tex]\begin{gathered} Amplitude=a \\ Period=\frac{2\pi}{b} \\ PhaseShift=\frac{c}{b} \\ VerticalShift=d \end{gathered}[/tex]Comparing the question with what is written in the note
We have
[tex]\begin{gathered} a=2 \\ b=2 \\ c=\frac{\pi}{3} \\ d=-2 \end{gathered}[/tex]We want to find
(a). Amplitude
From the given question, the amplitude (a) is
[tex]\begin{gathered} a=2 \\ Amplitude=2 \end{gathered}[/tex](b).Period
From the given question, the period is
[tex]\begin{gathered} Period=\frac{2\pi}{b} \\ Period=\frac{2\pi}{2} \\ Period=\pi \end{gathered}[/tex](c). Phase Shift
From the given question, the phase shift is
[tex]\begin{gathered} PhaseShift=\frac{c}{b} \\ PhaseShift=\frac{\pi}{3}\times\frac{1}{2} \\ PhaseShift=\frac{\pi}{6} \end{gathered}[/tex]your card gives you a bonus of 0.4%. what is your actual bonus if you charge $3,397.75 on your credit card?
Answers
Answer:
$13.591
Explanation:
To know your actual bonus, we need to find what is 0.4% of $3,397.75 as follows
[tex]3,397.75\times\frac{0.4}{100}=13.591[/tex]Therefore, your actual bonus is $13.591
I need help to know how to solve graphing a system of inequalities2x - 3y > -12x + y ≥ -2
Answers
Answer
2x - 3y > -12 (in red ink)
x + y ≥ -2 (in black ink)
The solution region is the region that the two shaded regions have in common.
Explanation
When plotting the graph of linear inequality equations, the first step is to first plot the graph of the straight line normally, using intercepts to generate two points on the linear graph.
If the inequality sign is (< or >), then the line drawn will be a broken line.
If the inequality sign is (≤ or ≥), then the line drawn is an unbroken one.
Step 1
For this question, we easily see that the first inequality will have a broken line and the second one will have an unbroken line.
To plot each of the lines, we will use intercepts to obtain the coordinates of two points on each line
Recall, we will first plot the lines like they are equations of a straight line.
To plot the graph
2x - 3y = -12
when x = 0,
2(0) - 3y = -12
-3y = -12
Divide both sides by -3
(-3y/-3) = (-12/-3)
y = 4
First point on the line is (0, 4)
when y = 0
2x - 3(0) = -12
2x = -12
Divide both sides by 2
(2x/2) = (-12/2)
x = -6
Second point on the line is (-6, 0)
For the second line,
To plot the graph,
x + y = -2
when x = 0
0 + y = -2
y = -2
First point on the line is (0, -2)
when y = 0
x + 0 = -2
x = -2
Second point on the line is (-2, 0)
So, for the plotting, we connect the two points for each of the lines.
Step 2
The shaded region now depends on whether the inequality sign is facing y or not.
If the inequality sign is facing y, it means numbers above the line plotted are the wanted region and the upper part of the graph is shaded.
If the inequality sign is not facing y, it means numbers below the line plotted are the wanted region and the lower part of the graph is shaded.
2x - 3y > -12
Can be rewritten as
-3y > -2x - 12
Divide through by -3 (this changes the inequality sign)
y < (2x/3) + 4
Here, we see that the inequality sign is not facing y, hence the numbers below the broken line plotted are the shaded region (in red ink)
x + y ≥ -2
We can rewrite this as
y ≥ -x - 2
Here, we see that the the inequality sign is facing y, hence, the numbers above the unbroken line plotted are the shaded region (in black ink)
The graph of this system of inequalities is presented above under 'Answer'
Hope this Helps!!!
Professor Ahmad Shaoki please help me! The length of each side of a square is extended 5 in. The area of the resulting square is 64 in,2 Find the length of a side of the
original square. Help me! From: Jessie
Answers
The length of the original square must be equal to 3 inches.
Length of the Original SquareTo find the length of the original square, we have to first assume the unknown length is equal x and then use formula of area of a square to determine it's length.
Since the new length is stretched by 5in, the new length would be.
[tex]l = (x + 5)in[/tex]
The area of a square is given as
[tex]A = l^2[/tex]
But the area is equal 64 squared inches; let's use substitute the value of l into the equation above.
[tex]A = l^2\\l = x + 5\\A = 64\\64 = (x+5)^2\\64 = x^2 + 10x + 25\\x^2 + 10x - 39 = 0\\[/tex]
Solving the quadratic equation above;
[tex]x^2 + 10x - 39 = 0\\x = 3 or x = -13[/tex]
Taking the positive root only, x = 3.
The side length of the original square is equal to 3 inches.
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Casey's Cookie Company opened with 24 cupcakes in the store display case. By noon, therewere only 15 cupcakes left. Was there a percent increase or decrease in the amount ofcupcakes? What was the increase or decrease amount?
Answers
Percentage is the proportion between numbers
total initial of cakes for Casey's = 24
final number of cakes = 15
find proportion 15/24 how many represents
15/24 = 5/8
now divide 100/8 = 12.5
then multiply 12.5 x 5
12.5x5= 62.5 %
Please show me how to solve this step by step im really confused
Answers
Given
[tex]-16t^2+v_0t+h_0[/tex]initial velocity = 60 feet per second
initial height = 95 feet
Find
Maximum height attained by the ball
Explanation
we have given
[tex]\begin{gathered} h(t)=-16t^2+60t+95 \\ h^{\prime}(t)=-32t+60 \end{gathered}[/tex]put h'(t) = 0
[tex]\begin{gathered} -32t+60=0 \\ -32t=-60 \\ t=\frac{60}{32}=1.875sec \end{gathered}[/tex]to find the maximum height find the value of h(1.875)
[tex]\begin{gathered} h(1.875)=-16(1.875)^2+60(1.875)+95 \\ h(1.875)=-56.25+112.5+95 \\ h(1.875)=-56.25+207.5 \\ h(1.875)=151.25 \end{gathered}[/tex]Final Answer
Therefore , the maximum height attained by the ball is 151.25 feet
Find an equation of the line.Write the equation in the standard form.Through (8,4); parallel to 7x-y= 2.
Answers
Answer:
7x-y=53
Explanation:
Given the line
[tex]7x-y=2[/tex]Making y the subject of the equation, we have:
y = 7x-2
Therefore, the slope of the line, m=7
• If two lines are parallel, their slopes are equal.
Therefore, the slope of the parallel line = 7
The equation of the parallel line through (8,4) will then be:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-4=7(x-8) \\ y-4=7x-57 \\ 7x-y=-4+57 \\ 7x-y=53 \end{gathered}[/tex]The two-way table represents the number of clubs that two hundred high school studentswere involved in.One Club Two clubsBoys 17Girls 28Total 45256893Three or more clubs Total50126292108200What is the probability that a student will be in two clubs only and a girl?
Answers
Given:
The two-way table represents the number of clubs that two hundred high school students
We will find the probability that a student will be in two clubs only and a girl
From the table, we will select the number that represents the number of girls that will be in the two clubs
so, the number = 68
the total number of students = 200
So, the probability will be =
[tex]\frac{68}{200}*100=34\%[/tex]So, the answer will be 34%
Suppose that the 99% confidence interval for the true average number of canteen operating hours is [6, 9]. Which conclusion is correct if the average number of operating hours for canteens in the region is 8 hours? a. The average number of canteen operating hours in this city is not significantly different from that of the region since 8 is not contained in the interval. b. The average number canteen operating hours in this city is not significantly different from that of the region since 8 is contained in the interval. c. The average number of canteen operating hours in this city is significantly different from that of the region since 8 is contained in the interval. d. The average number of canteen operating hours in this city is significantly different from that of the region since 8 is not contained in the interval.
Answers
Given: Suppose that the 99% confidence interval for the true average number of canteen operating hours is [6, 9].
To Determine: Which conclusion is correct if the average number of operating hours for canteens in the region is 8 hours
Solution
Given the confidence interval of [6,9]. This means that
A confidence interval indicates where the population parameter is likely to reside. For example, a 99% confidence interval of the mean [6 9] suggests you can be 99% confident that the population mean is between 6 and 9
If the average number of operating hours for canteens in the region is 8 hours, then we can conclude that
The average number canteen operating hours in this city is not significantly different from that of the region since 8 is contained in the interval, OPTION B
Identify the word described by the following statement.The type of rule in which you can find any number of term in the sequence without knowing the first or previous term.
Answers
Recursive is the type of rule in which you can find any number of term in the sequence without knowing the first or previous term.
Hence, the answer is Recursive.
Add and subtract square roots that need simplification Number 186
Answers
Hello!
To solve this exercise, we must simplify these square roots until we have the same square root in both numbers (by the factorization process):
[tex]3\sqrt{98}-\sqrt{128}[/tex]First, let's factorize the square root of 98:
So, we know that:
[tex]\begin{gathered} 3\sqrt{98}=3\sqrt{7^2\times2}=3\sqrt[\cancel{2}]{7\cancel{^2}\times2}=3\times7\sqrt{2}=21\sqrt{2} \\ \\ 3\sqrt{98}=21\sqrt{2} \end{gathered}[/tex]Now, let's do the same with the square root of 128:
So:
[tex]\sqrt{128}=\sqrt{2^2\times2^2\times2^2\times2}^1[/tex]Notice that it also could be written as:
[tex]\begin{gathered} \sqrt{128}=\sqrt{2\times2\times2\times2\times2\times2\times2} \\ \text{ or also} \\ \sqrt{128}=\sqrt{2^7} \end{gathered}[/tex]As we are talking about square roots, it will be easier if we group them in pairs of powers of 2, as I did:
[tex]\sqrt[2]{128}=\sqrt[2]{2^2\times2^2\times2^2\times2^1}[/tex]Now, let's analyze it:If the number inside the root has exponent 2, we can cancel this exponent and remove the number inside the root. Then, we can write it outside of the root, look:
[tex]\begin{gathered} \sqrt[2]{128}=\sqrt[2]{2^{\cancel{2}}\times2^{\cancel{2}}\times2^{\cancel{2}}\times2^1} \\ \sqrt[2]{128}=2\times2\times2\sqrt[2]{2^1} \\ \sqrt[2]{128}=8\sqrt[2]{2} \end{gathered}[/tex]Now, let's go back to the exercise:[tex]\begin{gathered} 3\sqrt{98}-\sqrt{128}\text{ is the same as } \\ 21\sqrt{2}-8\sqrt{2} \end{gathered}[/tex]So, we just have to solve it now:
[tex]21\sqrt{2}-8\sqrt{2}=\boxed{13\sqrt{2}}[/tex]Maria jogs 5 laps of a football field that
is 100 m by 50 m. How far does she jog?
Answers
Answer:
1500 m
Step-by-step explanation:
given that the field is 100m by 50m we can find that the perimeter of the field is 300m. if she jogged 300m 5 times she would have jogged 1500m
Problem solving.When two expressions are not equivalent, you can use an inequality symbol to show their relationship. Do you ever use an inequality symbol when two expressions are equivalent? Use an example in your explanation.
Answers
Explanation
When two expressions are not equivalent, you can use an inequality symbol
[tex]\begin{gathered} \leq\Rightarrow less\text{ or equal } \\ \ge\Rightarrow greater\text{ or equal } \\ >\Rightarrow greater\text{ than } \\ <\Rightarrow smaller\text{ than} \end{gathered}[/tex]
now, when comparing two expressions that are equivalent , WE CAN NOT USE an inequality simbol, instead of we need to use The equals sign or equal sign formerly known as the equality sign
[tex]=[/tex]for example
[tex]3x+19x=30x-8x[/tex]the = symbold indicates that both sides have the same value ( rigth and left)
I hope this helps you
Find the value of variable a given the transformation is an isometry.
Answers
Answer:
• a =10
,• b = 4
Explanation:
An isometry is a rigid transformation that preserves length and angle measures, as well as perimeter and area.
This means that the two right triangles are congruent.
Thus, we have that:
[tex]\begin{gathered} 3a=30 \\ 10b=40\degree \end{gathered}[/tex]Next, we solve for a and b.
[tex]\begin{gathered} 3a=30 \\ \text{Divide both sides by 3} \\ \frac{3a}{3}=\frac{30}{3} \\ a=10 \end{gathered}[/tex]Likewise:
[tex]\begin{gathered} 10b=40\degree \\ \text{Divide both sides by 10} \\ \frac{10b}{10}=\frac{40\degree}{10} \\ b=4 \end{gathered}[/tex]The values of a and b are 10 and 4 respectively.
I need to find the length x of KL
Answers
Answer:
3.6Step-by-step explanation:
We're going to use length DC and ML, along with DA and MJ
[tex]\frac{DC}{ML} = \frac{5}{6}[/tex] which is 0.833333333
now for
[tex]\frac{DA}{MJ} =\frac{7}{8.4}[/tex] which is 0.833333333 (again)
as you can see since the shapes ABCD and JKLM are similar, they have a relationship which in this case is 0.833333333
and we can use this 0.833333333 to help us find the length of KL
knowing that any length for ABCD divided by JKLM is 0.833333333
we can do
[tex]\frac{CB}{LK}=0.833333333[/tex]
since we don't know what KL is, we can switch the spots and enlongate it, to become:
[tex]\frac{CB}{0.833333333} =LK[/tex]
put in the value for CB
[tex]\frac{3}{0.833333333} =LK[/tex]
and we get 3.6
The length of x of KL is...
3.6