Solution
For this case we can model the problem with a geometric series given by:
[tex]a_n=600(1+0.2)^{n-1}[/tex]And we can find the value for n=23 and we got:
[tex]a_{23}=600(1.2)^{23-1}=33123.69[/tex]And rounded to the neares whole number we got 33124
and using the sum formula we got:
[tex]S_{23}=\frac{600(1.2^{23}-1)}{1.2-1}=195742[/tex]1. The figure shows the regular triangular pyramid SABC. The base of the pyramid has an edge AB = 6 cm and the side wall has an apothem SM = √15 cm. Calculate the pyramid: 1) the base elevation AM; 2) the elevation SO; 3) the area of the base; 4) the area of the side surface; 5) the total surface area; 6) volume.
Given:
• AB = 6 cm
,• SM = √15 cm
Let's solve for the following:
• 1) the base elevation AM.
Given that we have a regular triangular pyramid, the length of the three bases are equal.
AB = BC = AC
BM = BC/2 = 6/2 = 3 cm
To solve for AM, which is the height of the base, apply Pythagorean Theorem:
[tex]\begin{gathered} AM=\sqrt{AB^2-BM^2} \\ \\ AM=\sqrt{6^2-3^2} \\ \\ AM=\sqrt{36-9} \\ \\ AM=\sqrt{27} \\ \\ AM=5.2\text{ cm} \end{gathered}[/tex]The base elevation of the pyramid is 5.2 cm.
• (2)., The elevation SO.
To find the elevation of the pyramid, apply Pythagorean Theorem:
[tex]SO=\sqrt{SM^2-MO^2}[/tex]Where:
SM = √15 cm
MO = AM/2 = 5.2/2 = 2.6 cm
Thus, we have:
[tex]\begin{gathered} SO=\sqrt{(\sqrt{15})^2-2.6^2} \\ \\ SO=\sqrt{15-6.76} \\ \\ SO=2.9\text{ cm} \end{gathered}[/tex]Length of SO = 2.9 cm
• (3). Area of the base:
To find the area of the triangular base, apply the formula:
[tex]A=\frac{1}{2}*BC*AM[/tex]Thus, we have:
[tex]\begin{gathered} A=\frac{1}{2}*6^*5.2 \\ \\ A=15.6\text{ cm}^2 \end{gathered}[/tex]The area of the base is 15.6 square cm.
• (4). Area of the side surface.
Apply the formula:
[tex]SA=\frac{1}{2}*p*h[/tex]Where:
p is the perimeter
h is the slant height, SM = √15 cm
Thus, we have:
[tex]\begin{gathered} A=\frac{1}{2}*(6*3)*\sqrt{15} \\ \\ A=34.86\text{ cm}^2 \end{gathered}[/tex]• (5). Total surface area:
To find the total surface area, apply the formula:
[tex]TSA=base\text{ area + area of side surface}[/tex]Where:
Area of base = 15.6 cm²
Area of side surface = 34.86 cm²
TSA = 15.6 + 34.86 = 50.46 cm²
The total surface area is 50.46 cm²
• (6). Volume:
To find the volume, apply the formula:
[tex]V=\frac{1}{3}*area\text{ of base *height}[/tex]Where:
Area of base = 15.6 cm²
Height, SO = 2.9 cm
Thus, we have:
[tex]\begin{gathered} V=\frac{1}{3}*15.6*2.9 \\ \\ V=15.08\text{ cm}^3 \end{gathered}[/tex]The volume is 15.08 cm³.
ANSWER:
• 1.) 5.2 cm
,• 2.) 2.9 cm
,• 3.) 15.6 cm²
,• 4.) 34.86 cm²
,• (5). 50.46 cm²
,• 6). 15.08 cm³.
Your friend Pat bought a fish tank that has a volume of 175 liters. The brochure for Pat's tank lists a "fun fact that it would take 7.43 x 1018 tanks of that sizeto fill all the oceans in the world. Pat thinks the both of you can quickly calculate the volume of all the oceans in the world using the fun fact and the size ofher tankPart a.) Given that 1 liter = 1.0 x 10-12 cubic kilometers, rewrite the size of the tank in cubic kilometers using scientific notation.b) Determine the volume of all the oceans in the world in cubic kilometers using the "fun fact"
The tank has a volume of 175 liters
Fun fact: it would take 7.43*10¹⁸ tanks that size to fill all the oceans in the world.
a) Using the convertion 1 liter = 1.0*10⁻¹²km³ you have to rewrite the size of the tank.
For this you have to use cross multiplication:
1 Lts = 1.0*10⁻¹²
175Lts=x
[tex]x=175\cdot1.0\cdot10^{-12}=1.75\cdot10^{-10}[/tex]The volume of the tank is equal to 1.75*10⁻¹⁰ km³
b)
You know that one tank has a volume of 1.75*10⁻¹⁰ km³
To know what volume would 7.43*10¹⁸ tanks of the same size have, multiply the volume of one tank by the number of tanks.
[tex]1.75\cdot10^{-10}\cdot7.43\cdot10^{18}=1300250000\operatorname{km}^3[/tex]Using the fun fact, the determined volume of all oceans in the world is 1300250000km³
Line k contains the points (-9,4) and (9,-8) in the xy-coordinate plane. What are the two other points that lie on line k?
Answer
D. (-3, 0) and (3, -4)
Explanation
Let the coordinate of the points be A(-9, 4) and B(9, -8).
We shall look for the gradient m of line using
m = (y₂ - y₁)/(x₂ - x₁)
Substitute for x₁ = -9, y₁ = 4, x₂ = 9 and y₂ = -8
m = (-8 - 4)/(9 - -9) = -12/18 = -2/3
From option A - D given, only C and D would have the same gradient of -2/3 as line AB
To know the correct option, we shall look for the equation of the line AB, that is,
(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)
(y - 4)/(x - -9) = (-8 - 4)/(9 - -9)
(y -4)/(x + 9) = -12/18
(y - 4)/(x + 9) = -2/3 -----------*
Between option C and D, only D satisfies the equation *
That is, using (-3, 0), we have (0 - 4)/(-3 + 9) = -4/6 = -2/3
Also, using (3, -4), we have (-4 - 4)/(3 + 9) = -8/12 = -2/3
4 5 3 7 89 65Each time, you pick one card randomly and then put it back.What is the probability that the number on the card you pickfirst time is odd and the number on the second card you take isa multiple of 2? Keep your answers in simplified improperfraction form.Enter the answer
We have a total of 8 cards, where 3 of them are a multiple of 2, and 5 is an odd number. Consider that event A represents the probability of picking an odd number and event B is picking a multiple of 2. We know that the events are independent (because we put the cards back), therefore the probability of A and B can be expressed as
[tex]P(A\text{ and }B)=P(A)\cdot P(B)[/tex]Where
[tex]\begin{gathered} P(A)=\frac{5}{8} \\ \\ P(B)=\frac{3}{8} \end{gathered}[/tex]Therefore
[tex]P(A\text{ and }B)=\frac{5}{8}\cdot\frac{3}{8}=\frac{15}{64}[/tex]The final answer is
[tex]P(A\text{ and }B)=\frac{15}{64}[/tex]Consider the graph shown. Which ordered pairs are on the inverse of the function? Check all that apply.
Notice that the graph of the function is a cubic polynomial. Also, the graph is moved one unit upwards, then, the function f(x) is:
[tex]f(x)=x^3+1[/tex]now, we can see from the y and x intercepts, that if we evaluate x= 0 and x = 1, we get:
[tex]\begin{gathered} f(0)=-1 \\ f(1)=0 \end{gathered}[/tex]then, applying the inverse function on both sides (we can do this since f(x) is a polynomial function and they always have inverse function), we get the following:
[tex]\begin{gathered} f^{-1}(f(0))=f^{-1}(-1) \\ \Rightarrow0=f^{-1}(-1) \end{gathered}[/tex]we can see that the first point that is on the graph of the inverse function is (-1,0). Doing the same on the second equation, we get:
[tex]\begin{gathered} f^{-1}(f(1))=f^{-1}(0) \\ \Rightarrow f^{-1}(0)=1 \end{gathered}[/tex]thus, the points that lie on the inverse function are (-1,0) and (0,1)
follow me and get brainist and 100 points
Answer:
followed
Step-by-step explanation:
now gimmie
8. Here is a graph of the equation 3x - 2y = 12.
Select all coordinate pairs that represent a solution to
the equation.
A. (2,-3)
B. (4,0)
C. (5,-1)
D. (0, -6)
E. (2,3)
Answer:
A,B,D
Step-by-step explanation:
By replacing the points in the current equation you can get true statements which are correspondent to answer A,B,D
Crystal's favorite playlist has 80 rock songs, 40 jazz songs, 25 country songs, 30 hip hop songs, and 45 classical music songs. Which of thesestatements is true?
This problem tests the knowledge of the probability of a random event occuring: of playing a type of song from a variety of different song types
Thus, we have to compute the probability that each type of song is played.
To do this, we need to obtain the total number songs, as follows:
80 + 40 + 25 + 30 + 45 = 220
Thus, the probabilities are now easily computed as follows:
P(rock) = 80/220
P(jazz) = 40/220
P(country) = 25/220
P(hip hop) = 30/220
P(classical) = 45/220
Now:
Option 1 (the first statement in the options) claims that : P(rock) = 2 * P(hip hop)
However, 2 * P(hip hop)
A shellfish absorbed 40% of the heavy metals in the water in and just the concentration of heavy metals is 0.0002 mg/m³ .The shellfish ingests 4 L of water per hour. How many heavy metal does it absorb in 3 months? (Assume there are 30 days in a month there are 1000 L in one cubic meter)
Answer:
Step-by-step explanation:
May I ask a question?if I have a 10 girls in a class and the total number of students in the class are 30, what's the percentage of the total amount of girls?
Given:
The number of girls =10 and the total number of students =30.
The percentage of the total amount of girls is
[tex]=\frac{The\text{ number of girls}}{\text{The total number of students}}\times100[/tex][tex]=\frac{10}{30}\times100[/tex][tex]=33.33[/tex]Hence the percentage of the total amount of girls is 33.33 %.
help meeeeeeeeee pleaseee !!!!!
The values of the functions evaluated are:
a. (f + g)(x) = 9x + 1
b. (f + g)(x) = -7x + 1
c. (f * g)(x) = 8x² - 55x - 72
d. (f/g)(x) = (x - 8)/(8x + 9)
How to Evaluate Functions?To evaluate a function expression, we are to input the given value of x and solve by combining like terms and simplifying to find the value of the given function expression.
Given the functions:
f(x) = x - 8
g(x) = 8x + 9
a. Find (f + g)(x): This implies that we are to add the two functions f(x) and g(x) together.
(f + g)(x) = x - 8 + 8x + 9
(f + g)(x) = 9x + 1
b. Find (f - g)(x): This implies that we are to subtract g(x) from f(x).
(f - g)(x) = x - 8 - 8x + 9
(f + g)(x) = -7x + 1
c. Find (f * g)(x): This implies that we are to multiply the functions, g(x) and f(x) together.
(f * g)(x) = (x - 8) * (8x + 9)
(f * g)(x) = 8x² - 55x - 72
d. Find (f/g)(x): This implies that we are to find the quotient of the functions, f(x) and g(x).
(f/g)(x) = (x - 8)/(8x + 9)
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ratio problems that I am struggling with
7 out of every 500 Americans are aged 13-17 years generation are vegetarian
Thus the ratio of the vegetarian is 7 : 500
In a group of 350,
Let x be the number of people who are vegetarian
So, the ratio out of 350 who are vegetarian are : x : 350
SInce the ratio is same so:
[tex]\begin{gathered} 7\text{ : 500=x:250} \\ \frac{7}{500}=\frac{x}{250} \\ \text{ Simplify for x,} \\ x=\frac{7}{500}\times250 \\ x=\frac{7}{2} \\ x=3.5 \\ x\approx4 \end{gathered}[/tex]So, the number of people who are vegetarian out of 350 people is 4 people
The graph represents a quadratic function. Write an equation of the function in standard form.
A quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.
Given that, the graph is passing through (2, 0), (10, 0) and (6, -4).
What is a quadratic function in standard form?The standard form of a quadratic equation is given as:
ax² + bx + c = 0 where a, b, c are real numbers and a ≠ 0.
Now, the equation passes through (2, 0)
y = ax² + bx + c
0 = 4a + 2b + c ----------------(1)
The equation passes through (6, -4)
y = ax² + bx + c
-4= 36a + 6b + c ----------------(2)
The equation passes through (10, 0)
y = ax² + bx + c
0 = 100a + 10b + c ----------------(3)
Using the Gauss elimination method to solve the system of equations we get,
a = 1/4, b = -3, and c = 5
The quadratic equation will be:
y = ax² + bx + c
y = (1/4) x² - 3x + 5
Therefore, a quadratic function in standard form with the given characteristics is (1/4) x² - 3x + 5.
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21.) Determine the distance between the points (-2, 3) and (4,9).A 142B 7146C 413D 6V222.) Infigure
The distance formula can be represented below
[tex]\begin{gathered} c^{}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} c=\sqrt[]{(4+2)^2+(9-3)^2} \\ c=\sqrt[]{(6)^2+(6)^2} \\ c=\sqrt[]{36+36} \\ c=\sqrt[]{72} \\ c=\sqrt[]{36\times2} \\ c=6\sqrt[]{2} \end{gathered}[/tex]The answer is D.
Given a and b are first quadrant angles, sin a=5/13 and cos b=3/5 evaluate cos (a+b)1) 56/652) 33/653) 16/65
I need help please quickly I need help
10(2 + 3) - 8 · 3.
20+50-8 times 3
70 -24
46 is answer
Answer:
10(5)-24 ----) 50-24 -----) 26
Step-by-step explanation:
answe is 26
3.
How much greater is the surface area of the rectangular prism than the surface area of the cube?
6 cm
(1 point)
3 cm
2 cm
O 36 cm²
O 33 cm²
O 18 cm²
O 45 cm²
3 cm
The dimensions of the rectangular prism of 6 cm by 3 cm by 2 cm and the dimension of the cube of 3 cm gives the amount the surface area of the prism is greater than the cube as 18 cm²
What is a rectangular prism?A rectangular prism is a six faced solid hexahedron.
The given dimension of the rectangular prism are:
Length = 6 cm
Height = 3 cm
Width = 2 cm
The side length of the cube = 3cm
The surface area of the rectangular prism is therefore:
[tex]A_p[/tex] = 6 × 3 × 2 + 6 × 2 × 2 + 3 × 2 × 2 = 72
The surface area of the rectangular prism is 72 cm²
The surface area of the cube: [tex]A_c[/tex] = 6 × 3² = 54
The surface area of the cube, [tex]A_c[/tex] = 54 cm²
The amount by which area of the rectangular prism is greater than the area of the cube is therefore: [tex]A_p[/tex] - [tex]A_c[/tex] = 72 cm² - 54 cm² = 18 cm²
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What number is 75% of 96?
The number 96 is equivalent to the 100%. So we can state the following rule of three:
[tex]\begin{gathered} 96\text{ ------ 100 \%} \\ x\text{ -------- 75 \%} \end{gathered}[/tex]By cross-multiplying these numbers, we have
[tex]\text{ (100\%)}\times x=(96)\times\text{ (75 \%)}[/tex]So, x is given by
[tex]\begin{gathered} x=\frac{(96)\times\text{ (75 \%)}}{\text{ 100\%}} \\ x=72 \end{gathered}[/tex]Therefore, the answer is 72
In a survey, 12 people were asked how much they spent on their child's last birthday gift. The results wereroughly bell-shaped with a mean of $39.1 and standard deviation of $17.4. Estimate how much a typical parentwould spend on their child's birthday gift (use a 99% confidence level). Give your answers to 3 decimal places.Express your answer in the format of ī + Error.$£ $
Given:
number of people (n) = 12
mean = 39.1
standard deviation = 17.4
99% confidence level
Using the confidence level formula, we can find the estimate of how much a typical parent would spend on their child's birthday:
[tex]\begin{gathered} CI\text{ = x }\pm\text{ }\frac{z\varphi}{\sqrt[]{n}} \\ \text{where x is the mean} \\ z\text{ is the z-score at 99\% confidence interval} \\ \varphi\text{ is the standard deviation} \\ n\text{ is the number of people asked} \end{gathered}[/tex]The z-score at 99% confidence level is 2.576
Substituting, we have:
[tex]\begin{gathered} CI\text{ = 39.1 }\pm\text{ }\frac{2.576\text{ }\times\text{ 17.4}}{\sqrt[]{12}} \\ =26.161\text{ and 52}.039 \end{gathered}[/tex]Hence, a typical parent would spend between $26.161 and $52.039 or :
[tex]39.1\text{ }\pm\text{ 12.939}[/tex]Jina spends $16 each time she travels the toll roads. She started the month with $240 in her toll road account. The amount, A (in dollars), that she has left in the account after t trips on the toll roads is given by the following function.=A(t)=240-16tAnswer the following questions.(a)How much money does Jina have left in the account after 11 trips on the toll roads?$(b)How many trips on the toll roads can she take until her account is empty?trips
GIVEN:
We are told that Jina had an opening balance of $240 in her toll road account.
Also, we are told that the amount left in the toll road account is given by the function;
[tex]A(t)=240-16t[/tex]Required;
(a) To find how much money she has left in her acount after 11 trips.
(b) To find out how many trips she can take until her account is empty.
Step-by-step solution;
We first take note of the variable t, which represent the number of trips taken. Also, the function shows how many trips multiplied by 16 would be subtracted from the opening balance. The result would be how much amount (variable A) would be left in her account.
Therefore;
(a) After 11 trips, Jina would have;
[tex]\begin{gathered} A(t)=240-16t \\ \\ A(11)=240-16(11) \\ \\ A(11)=240-176 \\ A(11)=64 \\ \end{gathered}[/tex]For the (A) part, the answer is $64.
(b) For her account to be empty, then the function given would be equal to zero. That is, after an unknown number of trips, the balance would be zero. We can now re-write the function as follows;
[tex]\begin{gathered} A(t)=240-16t \\ \\ 0=240-16t \end{gathered}[/tex]Add 16t to both sides of the equation;
[tex]\begin{gathered} 16t=240-16t+16t \\ \\ 16t=240 \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }16: \\ \\ \frac{16t}{16}=\frac{240}{16} \\ \\ t=15 \end{gathered}[/tex]This means after 15 trips she would have emptied her toll road account.
ANSWER:
[tex]\begin{gathered} (A)=\text{\$64} \\ \\ (B)=15\text{ }trips \end{gathered}[/tex]A classic car is now selling for $2000 more than two times its original price. If the selling price is now $12,000, what was the car's original price?
The domain of f(g(x)) is:
Answer:
x ≥ 0
Explanation:
Given the function f(x) and g(x) defined below:
[tex]f(x)=3x-1,g(x)=\sqrt{x}[/tex]The composite function f(g(x)) is:
[tex]f(g(x))=3\sqrt[]{x}-1[/tex]The domain of the function is the value at which the value under the square root sign is non-negative.
Therefore:
[tex]\text{Domain of f(g(x)): }x\ge0[/tex]The first option is correct.
Which function has a y-intercept of 4? a. f(x) = 3(1 + 0.05)* b.f(x) = 4(0.95)* c. f(x) = 5(1.1) d. f(x) = 5(0.8)
Answer:
The correct option is D
f(x) = 5(0.8)
has y-intercept of 4
Explanation:
To know which of the given functions has a y-intercept of 4, we test them one after the other.
a. f(x) = 3(1 + 0.05)
f(x) = 3.15 WRONG
b. f(x) = 4(0.95)
f(x) = 3.8 WRONG
c. f(x) = 5(1.1)
f(x) = 5.5 WRONG
d. f(x) = 5(0.8)
f(x) = 4 CORRECT
What is the product of 125 × 25
Answer:
Step-by-step explanation:
125 X 25
= 3,125
n=39; i = 0.039; PMT = $196; PV =?
Given the Present Value (PV) formula
[tex]PV=PMT\times\frac{1-(\frac{1}{(1+i)^n})}{i}[/tex]Write out the parameters
[tex]\begin{gathered} PV=\text{?} \\ n=39 \\ i=0.039 \\ \text{PMT=\$196} \end{gathered}[/tex]Substitute the following values in the present value formula to find the PV
[tex]PV=196\times\frac{1-(\frac{1}{(1+0.039)^{39}})}{0.039}[/tex][tex]PV=196\times\frac{1-0.2249021697}{0.039}[/tex][tex]PV=196\times\frac{0.7750978303}{0.039}[/tex][tex]\begin{gathered} PV=196\times19.87430334 \\ PV\approx3895.36 \end{gathered}[/tex]Hence, the Present Value (PV) is approximately $3895.36
What is the simplified form of the expression square root of -64
What is the simplified form of the expression square root of -64
we have
[tex]\sqrt[]{-64}[/tex]Remember that
64=2^6
and
i^2=-1
substitute
[tex]\sqrt[]{-64}=\sqrt[]{(-1)(2^6)}=\sqrt[]{i^2\cdot2^6}=2^3i=8i[/tex]option BIf each machine produces nails at the same rate, how many nails can 1 machine produce in 1 hour
Divide the number of nails by the number of minutes:
16 1/5 ÷ 15 = 1 2/25 per minute
48 3/5 ÷ 45 = 1 2/25 per min
59 2/5 ÷ 55 = 1 2/25 per min
We have the number of nails produced per minute, to calculate the number of nails in an hour multiply it by 60, because 60 minutes= 1 hour:
1 2/25 x 60 = 64 4/5
tom has a rectangular prism - shaped suitcase that measures 9 inches by 9 inches by 24 inches. he needs a second suitcase that has the same volume but smaller surface than his current suitcase. which suitcase size would fit Toms needs
ANSWER:
18 inches by 9 inches by 12 inches
EXPLANATION:
The volume of Tom's rectangular prism-shaped suitcase which measures 9 inches by 9 inches by 24 inches is;
[tex]\begin{gathered} Volume=l*w*h \\ \\ =9*9*24 \\ \\ =1944\text{ }square\text{ }inches \end{gathered}[/tex]So the volume of Tom's suitcase is 1944 cubic inches
The surface area will be;
[tex]\begin{gathered} SA=2(lw+wh+hl) \\ \\ =2(9*9+9*24+24*9) \\ \\ =2(81+216+216) \\ \\ =2(513) \\ \\ =1026\text{ }square\text{ }inches \end{gathered}[/tex]So the volume of the suitcase is 1026 square inches
*Let's go ahead and determine the volume and surface area of a suitcase that measures 18 inches by 18 inches by 6 inches;
[tex]\begin{gathered} Volume=l*w*h \\ \\ =18*18*6 \\ \\ =1944\text{ cubic inches} \end{gathered}[/tex][tex]\begin{gathered} Surface\text{ }Area=2(18*18+18*6+6*18) \\ \\ =2(324+108+108) \\ \\ =2(540) \\ \\ =1080\text{ square inches} \end{gathered}[/tex]We can see that the suitcase that measures 18 inches by 18 inches by 6 inches has the same volume as the first one but a higher surface area which doesn't fit Tom's needs
*Let's go ahead and determine the volume of a suitcase that measures 12 inches by 10 inches by 9 inches;
[tex]\begin{gathered} Volume=12*10*9 \\ \\ =1080\text{ cubic inches} \end{gathered}[/tex]We can see that the suitcase that measures 12 inches by 10 inches by 9 inches has a different volume from the first one which doesn't fit Tom's needs.
Let's go ahead and determine the volume of a suitcase that measures 16 inches by 5 inches by 9 inches;
[tex]\begin{gathered} Volume=16*5*9 \\ \\ =720\text{ cubic inches} \end{gathered}[/tex]We can see that the suitcase that measures 16 inches by 5 inches by 9 inches has a different volume from the first one which doesn't fit Tom's needs.
*Let's go ahead and determine the volume and surface area of a suitcase that measures 18 inches by 9 inches by 12 inches;
[tex]\begin{gathered} Volume=l*w*h \\ \\ =18*9*12 \\ \\ =1944\text{ cubic inches} \end{gathered}[/tex][tex]\begin{gathered} Surface\text{ }Area=2(18*9+9*12+12*18) \\ \\ =2(162+108+216) \\ \\ =2(486) \\ \\ =972\text{ square inches} \end{gathered}[/tex]We can see that the suitcase that measures 18 inches by 9 inches by 12 inches has the same volume as the first one and s smaller surface area which fits Tom's needs
Suppose a person is standing on the top of a building and that she has an instrument that allows her tomeasure angles of depression. There are two points that are 100 feet apart and lie on a straight line that isperpendicular to the base of the building. Now suppose that she measures the angle of depression from thetop of the building to the closest point to be 34.5 and the angle of depression from the top of thebuilding to the furthest point to be 27.8°. Determine the height of the building. (Round your answer to thenearest tenth of a foot.)
see the figure below to better understand the problem
In the right triangle ABC
tan(34.5)=h/x -----> by TOA
h=x*tan(34.5) -----> equation 1
In the right triangle ABD
tan(27.8)=h/(100+x) -----> by TOA
h=(100+x)*tan(27.8) -----> equation 2
Equate equation 1 and equation 2
x*tan(34.5)=(100+x)*tan(27.8)
solve for x
x*tan(34.5)=100*tan(27.8)+x*tan(27.8)
x*[tan(34.5)-tan(27.8)]=100*tan(27.8)
x=329.4 ft
Find out the value of h
h=x*tan(34.5)
h=329.4*tan(34.5)
h=226.4 ft
therefore
the answer is
the height of the building is 226.4 ftHaven’t done this type of math before could use some help:)
Third row:
The balance stays the same as the previous row ($337.52).
We have 12 days between 9/7 and 9/18, so we can calculate the product/sum as:
[tex]S=12\cdot337.52=4050.24[/tex]NOTE: the product/sum will be used to calculate the average balance for the month.
Fifth row:
The balance stays the same as the previous row ($399.78).
We have 11 days between 9/20 and 9/30.
Then, the product/sum is:
[tex]S=399.78\cdot11=4397.58[/tex]Total:
The total product/sum is:
[tex]S_{\text{Total}}=1937.60+337.52+4050.24+399.78+4397.58=11122.72[/tex]Average daily balance:
We can take the total product/sum and divide by the total amount of days.
[tex]\text{average daily balance}=\frac{11122.72}{30}=370.76[/tex]Finance charge:
[tex]\text{ finance charge}=\frac{1.25}{100}\cdot370.76=4.63[/tex]New balance:
[tex]\begin{gathered} \text{New balance = previous balance - payment/credits + finance charge + new purchases} \\ \text{New balance = }387.52-50+4.63+62.26=404.41 \end{gathered}[/tex]The new balance is $404.41.
