Given that p = 6 and q = 2, which yields a quotient greater than -9? ОА -3 a -р B 3 O a O С Зр. (-9) (0) D (-p) (-39)

Given That P = 6 And Q = 2, Which Yields A Quotient Greater Than -9? -3 A - B 3 O A O . (-9) (0) D (-p)

Answers

Answer 1
[tex]\begin{gathered} \frac{(-p)}{(-3q)}=\frac{-6}{-3(2)}=\frac{-6}{-6}=1>-9 \\ \text{Hence the correct option is D} \end{gathered}[/tex]


Related Questions

The height of a triangle is 4x more than the base, and the area of the triangle is 6 square units. Find the length of the base. Let x =the length of the base.
Write a quadratic equation in factored form. Write entire equation

Answers

Answer:

The length of the base is:

3 units

The resulting quadratic is

x² - 3= 0

Step-by-step explanation:

Base = x

Height = 4x

Area, A = 1/2* base * Height

           A = (1/2) * (x) * (4x)

          A = 2x²           (1)

But,    A = 6              (2)

Since (1) = (2);

2x²= 6

x²= 3

Resulting quadratic:

x² - 3= 0

For the difference between 2 squares:

a² - b² = (a-b)(a+b)

Using that identity, we can factorize our quadratic:

(x-3)(x+3) = 0

So, we have 2 roots:

x = 3 and x = -3

Now, noting that length must take a positive value, we go for the first:

x = 3

CONCLUSION:

The length of the base is:

3 units

The resulting quadratic is

x² - 3= 0

Find The distance DB from Cassini yo Tethys when AD is tangent to the circular orbit. Round to the nearest kilometer

Answers

we have that

triangle ABD is a right triangle , because AD is a tangent

so

Apply the Pythagorean Theorem

DB^2=AB^2+AD^2

we have

AB is a diameter (two times rhe radius)

AB=2*295,000=590,000 km

AD=203,000 km

substitute

DB^2=590,000^2+203,000^2

DB=623,946 km

How long does it take Tina to type 864 words, if she took 15 minutes to type out an assignment that comprised 720 words?

Answers

Given data:

The given time taken by Tin to type 720 words is t=15 min.

The given expression can be wriiten as,

720 word=15 min

720 words= 15(60 sec)

720 words= 900 sec

1 word = 900/720 sec

=1.25 sec

Multiplying the above equation with 864 on both sides .

864 words= 864(1.25) sec

= 1080 sec

=1080/60 min

= 18 min.

Thus, the time taken bby Tine to type 864 words is 18 min.

Represent each sum as a single rational number. -14+(-8/9) due tomorrow pls answer

Answers

the given expression is

-14 + (-8/9)

so,

[tex]\begin{gathered} =-14+\frac{-8}{9} \\ =-14-\frac{8}{9} \end{gathered}[/tex][tex]\begin{gathered} =\frac{-126-8}{9} \\ =-\frac{134}{9} \end{gathered}[/tex][tex]=-\frac{134}{9}=-14\frac{8}{9}[/tex]

so the answer is -14 8/9 or -134/9

Find the volume of a pyramid with a square base, where the side length of the base is19.3 ft and the height of the pyramid is 16.2 ft. Round your answer to the nearesttenth of a cubic foot.

Answers

Find the volume of a pyramid with a square base, where the side length of the base is

19.3 ft and the height of the pyramid is 16.2 ft. Round your answer to the nearest

tenth of a cubic foo

Remember that

the volume of the pyramid is equal to

[tex]V=\frac{1}{3}\cdot B\cdot h[/tex]

where

B is the area of the base

h is the height

step 1

Find out the area of the base

B=19.3^2

B=372.49 ft2

h=16.2 ft

substitute the given values in the formula

[tex]V=\frac{1}{3}\cdot372.49\cdot16.2[/tex]V=2,011.4 ft3

if f(x)=3x-2/x+4 and g(x)=4x+2/3-x,prove that f and g are inverses of each other

Answers

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How many soultions?x + 3 = 2x - 18A single solutionInfinite solutionsNo solution

Answers

The given equation is expressed as

x + 3 = 2x - 18

Subtracting x from both sides of the equation, it becomes

x - x + 3 = 2x - x - 18

3 = x - 18

Adding 18 to both sides of the equation, it becomes

3 + 18 = x - 18 + 18

21 = x

x = 21

Since there is only one value for x, the correct option is

a. A single solution

Rewrite the expression 3(12 - 10) using the distributive property of multiplication over subtraction.

Answers

The resulting expression using the distributive property of multiplication over subtraction is 3(12) - 3(10).

What is distributive property of multiplication?

The distributive property of binary operations extends the distributive law, which states that in elementary algebra, equality is always true.

For instance, given the expression;

A(B - C)

We will have to distribute A over B and C to have;

A(B - C) = AB - AC

Applying the rule to the given expression

3 (12 - 10)

3(12) - 3(10)

This shows that the given expression can also be written as 3(12) - 3(10)

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Rationalize the denominator and simplify the expression below. Show all steps and calculations to earn full credit. You may want to do this work by hand and upload an image of that written work rather than try to type it all out. \frac{8}{1- \sqrt[]{17} }

Answers

The Solution:

The given expression is

[tex]\frac{8}{1-\sqrt[]{17}}[/tex]

Rationalizing the expression with the conjugate of the denominator, we have

[tex]\frac{8}{1-\sqrt[]{17}}\times\frac{1+\sqrt[]{17}}{1+\sqrt[]{17}}[/tex]

This becomes

[tex]\frac{8(1+\sqrt[]{17})}{1^2-\sqrt[]{17^2}}[/tex][tex]\frac{8+8\sqrt[]{17}}{1-17}=\frac{8(1+\sqrt[]{17})}{-16}=-\frac{1+\sqrt[]{17}}{2}[/tex]

Thus, the correct answer is

[tex]-\frac{1+\sqrt[]{17}}{2}[/tex]

2. Write a story that can be represented by the equation y = x + 1/4 x.Question 2 On a hot day a football team drank an entire 50-gallon cooler of water and half as much again. How much water did they drink? Create an equation to represent this situation.

Answers

y= x+ 1/4 x

Y = dependent variable

x= independent variable

Jenny has a bank account. In the first month, she deposits a certain amount of money (x), and in the month after she deposits 1/4 of that amount.

Find the total amount of money deposited (y).

What is the value of x in the equation7 (4x + 1) – 32 5.7 · 13?X=

Answers

Given

[tex]\begin{gathered} 7(4x+1)-3x=5x-13 \\ 28x+7-3x=5x-13 \\ 25x-5x=-13-7 \\ 20x=-20 \\ x=-1 \end{gathered}[/tex]

I'm having a problem with this logarithmic equation I will include a photo

Answers

[tex]f(x)=\log (x-8)[/tex]

For the vertical asymptotes, we set the argument of the logarithm to be zero. Therefore,

[tex]\begin{gathered} x-8=0 \\ x-8+8=0+8 \\ x=8 \\ \text{Vertical asymptotes: x = 8} \end{gathered}[/tex]

The domain of the function can be found below

[tex]\begin{gathered} x-8>0 \\ solve\text{ the inequality to obtain the domain} \\ x>8 \\ solve\text{ for x to obtain the domain: x>8 or interval form :(8, }\infty\text{)} \end{gathered}[/tex]

The functions f(m) = 18 + 0.4m and g(m) = 11.2 + 0.54m give the lengths of two differentsprings in centimeters, as mass is added in grams, m, to each separately.

Answers

STEP - BY - STEP EXPLANATION

What to do?

Graph each equation on the same set of axis.

Determine the mass that makes the spring the same length.

Determine the length of that mass.

Write a sentence comparing the two springs.

Given:

f(m) = 18 + 0.4m and g(m) = 11.2 + 0.54m

Step 1

Find the x and y-intercept of both function.

f(m) = 18 + 0.4m

f(0) = 18+0.4(0) = 18

0 = 18 + 0.4m

0.4m = -18

m=-45

The x and y -intercept of the function f(m) are (0, 18) and (-45, 0) respectively.

g(m) = 11.2 + 0.54m

g(0) = 11.2 + 0.54(0)

g(0) = 11.2

0 = 11.2+ 0.54m

0.54m = -11.2

m=20.7

The x and y - intercepts are (0, 11.2) and (20.7, 0).

Step 2

Graph the function.

Below is the graph of the function.

Observe from the graph that that the mass that makes the spring the same length is approximately 48.5 grams.

The length at that point is 37.4 centimeters.

Comparison between the two strings.

The string with the function f(m) started out longer, but does not stretch as quickly as the other spring with the function g(m).

ANSWER

b) 48.6 grams

c) 37.4 centimeters

d) The string with the function f(m) started out longer, but does not stretch as quickly as the other spring with the function g(m).

a sociology Professor assigns letter grades on a test according to the following scheme Scores on the test are normally distributed with the meaning of 67.2 and a standard deviation of 8.5Find the minimum score required for an a grade. Round your answer to the nearest whole number if necessary

Answers

In order to have grade A, the score needs to be in the top 9%.

Since the scores are normally distributed, the top 9% scores correspond to 91% of the area under the normal curve. That means we need to find a value of z in the z-table that corresponds to the value 0.91 (that is, 91%).

Looking at the z-table, the value of z for a probability of 0.91 is z = 1.34.

Now, to find the score that this value of z represents, we can use the formula below:

[tex]\begin{gathered} z=\frac{x-\mu}{\sigma}\\ \\ 1.34=\frac{x-67.2}{8.5}\\ \\ x-67.2=11.39\\ \\ x=11.39+67.2\\ \\ x=78.59 \end{gathered}[/tex]

Rounding to the nearest whole number, the minimum score for grade A is 79.

Yea I think and her dad is doing great so

Answers

Given the following function:

[tex]tan\text{ }\theta=\frac{10}{y}[/tex]

Both θ and y are functions of the time (t)

We will find the derivatives of θ and y with respect of the time (t) as follows:

[tex]sec^2θ*\frac{dθ}{dt}=-\frac{10}{y^2}*\frac{dy}{dt}[/tex]

Now, we will find dy/dt when θ = π/6 and dθ/dt = π/12

First, we need to find the value of y when θ = π/6

[tex]\begin{gathered} tan(\frac{\pi}{6})=\frac{10}{y} \\ \frac{1}{\sqrt{3}}=\frac{10}{y} \\ \\ y=10\sqrt{3} \end{gathered}[/tex]

so, we will substitute the values to find dy/dt as follows:

[tex]\begin{gathered} sec^2(\frac{\pi}{6})*\frac{\pi}{12}=-\frac{10}{(10\sqrt{3})^2}*\frac{dy}{dt} \\ \\ so,\frac{dy}{dt}=-\frac{(10\sqrt{3})^2}{10}*sec^2(\frac{\pi}{6})*\frac{\pi}{12}=-10.4719755 \end{gathered}[/tex]

Rounding to 2 decimal places

So, the answer will be:

[tex]\frac{dy}{dt}=-10.47\text{ feet/hour}[/tex]

how do you find a point slope in geometry

Answers

see explanation below

Explanation:

To find the point slope form of an equation, we will apply the formula:

[tex]y-y_1=m(x-x_1)[/tex]

Given two points, we will be able to find the slope = m

for example: (1, 2), (2, 4)

m = slope = change in y/ change in x

m = (4-2)/(2-1)

m = 2/1

m = 2

Then, we will pick any of the points and insert into the formula for the point slope.

Let's assume we are using point (1, 2) = (x1, y1)

inserting into the formula together with the slope gives:

y - 2 = 2(x - 1)

The above is a point slope for the points given.

Can you help me please and thank you very much

Answers

Answer:

∠ FAE = 120°

Step-by-step explanation:

4x and 2x are a linear pair and sum to 180° , that is

4x + 2x = 180

6x = 180 ( divide both sides by 6 )

x = 30

then

∠ FAE = 4x = 4 × 30 = 120°

A bank offers a CD that pays a simple interest rate of 8.0%. How much must you put in this CD now in order to have $2500 for a home-entertainment center in 3 years.

Answers

Okay, here we have this:

Considering that the formula for the simple interest rate is:

A = P (1 + rt)

In this case A is equal to $2500, P is the value we need to find, r is the interest rate (in decimal) 0.08, and t is the time, so it's 3 years, replacing we obtain:

2500=P(1+0.08*3)

Now, let's clear P:

2500=P(1+0.24)

2500=P(1.24)

2500/1.24=P

P=2016.13

Finally we obtain that the bank must put $ 2016.13 on a CD to get $ 2,500 in three years.

use the above diagram to answer the following questions.

Answers

Remember that the sum of the interior angles is 180. Then, we have the following equation:

[tex]55^{\circ}+65^{\circ}\text{ + }\angle M\text{ = 180}[/tex]

This is equivalent to:

[tex]120^{\circ}\text{ + }\angle M=180^{\circ}[/tex]

solve for M-angle:

[tex]\text{ }\angle M=180^{\circ}-\text{ 120}^{\circ}=60^{\circ}[/tex]

Then, te correct answer is :

[tex]\text{ }\angle M^{}=60^{\circ}[/tex]

Answer A= f(x)>0 on the interval x <0 Answer B=f(x)>0 on the interval x<0 Answer C=is f(x)<0 on the interval 00 on the interval 00 on the interval 1

Answers

EXPLANATION

Given the function f(x)= -x ²+4x - 3, the statements that apply are:

A) TRUE

B) FALSE

C) TRUE

D) FALSE

E) FALSE

F) TRUE

G) TRUE

H) FALSE

Jacob took a taxi from his house to the airport. The taxi company charged a pick-upfee of $1.30 plus $5 per mile. The total fare was $16.30, not including the tip. Writeand solve an equation which can be used to determine , the number of miles in the

Answers

Let the total number of fare be f and total number of miles be m.

Therefore, the total fare f is given by:

[tex]f=1.30+5m[/tex]

Substitute f = 16.30 into the equation:

[tex]\begin{gathered} 16.30=1.30+5m \\ 16.30-1.30=5m \\ 15=5m \\ \frac{15}{5}=\frac{5m}{5} \\ 3=m \\ m=3 \end{gathered}[/tex]

Therefore, the required number of miles is 3.

help meeeee pleaseeeee!!!





thank you

Answers

The values of the given polynomial are:-

f(0) = 12

f(2) = 28

f(-2) = 52

Given polynomial:-

[tex]f(x)=-x^3+7x^2-2x+12[/tex]

We have to find the values of f(0), f(2) and f(-2).

Putting x = 0 in f(x), we get,

[tex]f(0)=-(0)^3+7(0)^2-2(0)+12[/tex]

f(0) = 0 +0 - 0 + 12 = 12

Hence, the value of f(0) is 12.

Putting x = 2 in f(x), we get,

[tex]f(2)=-(2)^3+7(2)^2-2(2)+12[/tex]

f(2) = -8 + 28 - 4 + 12 = 28

Hence, the value of f(2) is 28.

Putting x = -2 in f(x), we get,

[tex]f(-2)=-(-2)^3+7(-2)^2-2(-2)+12[/tex]

f(-2) = 8 +28 + 4 +12 = 52

Hence, the value of f(-2) is 52.

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you randomly select one card from a 52 card deck. find the probability of selecting a black three or a red jack

Answers

Answer:

Probability of selecting a black three or a red jack = 1/13

Explanations:

There are a total of 52 cards in a deck of cards

Total number of ways of selecting one card from 52 cards = 52C1 = 52 ways

There are two red jacks in a deck of cards

Number of ways of selecting a red jack = 2C1 = 2 ways

There are two blacks 3s in a deck of cards

Number of ways of selecting a black three = 2C1 = 2 ways

[tex]\begin{gathered} \text{Probablity of selecting a black 3 = }\frac{2}{52}=\text{ }\frac{1}{26} \\ \text{Probability of selecting a red jack = }\frac{2}{52}=\frac{1}{26} \end{gathered}[/tex]

Probability of selecting a black three or a red jack = (1/26) + (1/26)

Probability of selecting a black three or a red jack = 2/26 = 1/13

what's the answer for proportions 4/n+2=7/n

Answers

[tex]x=-\frac{14}{3}[/tex]

Explanation

[tex]\frac{4}{n+2}=\frac{7}{n}[/tex]

we need to solve for n

Step 1

cross multiply

[tex]\begin{gathered} \frac{4}{n+2}=\frac{7}{n} \\ 4\cdot n=7(n+2) \\ 4n=7n+14 \\ \end{gathered}[/tex]

Step 2

subtract 4n in both sides

[tex]\begin{gathered} 4n=7n+14 \\ 4n-4n=7n+14-4n \\ 0=3n+14 \end{gathered}[/tex]

Step 3

subtract 14 in both sides,

[tex]\begin{gathered} 0=3n+14 \\ 0-14=3n+14-14 \\ -14=3n \end{gathered}[/tex]

Step 4

Finally, divide both sides by 3

[tex]\begin{gathered} \frac{-14}{3}=\frac{3n}{3} \\ n=-\frac{14}{3} \end{gathered}[/tex]

I hope this helps you

How many area codes of the form (XYZ) are possible if the digit 'X' and 'Y' can be any number ( through 9 but they can't repeat and the digit 7 can be any number 1 through 9?

Answers

Start to see the possible options

[tex]XYZ=-\cdot-\cdot-_{}[/tex]

The first digit will have 10 possible numbers to choose from 0 to 9, however in the second digit since it cannot repeat there will be only 9 possible to choose from. As for ther third number 0 is not an option meaning that there are 9 to choose as well.

[tex]\begin{gathered} XYZ=10\cdot9\cdot9 \\ XYZ=810 \end{gathered}[/tex]

Paolo noticed that Channel 8 devoted 1/6 hour to news story and Channel 12 devoted 1/8 to the same story. Which channel devoted more time? How much more time?

Answers

the channel that devoted more time was channel 8, because since 6<8 then it follows thay 1/6>1/8 (the inequiality changes), channel 8 devoted

[tex]\frac{1}{6}-\frac{1}{8}=\frac{8-6}{6(8)}=\frac{2}{48}=\frac{1}{24}\text{more time}[/tex]

Point A is shown on the complex plane.What is the standard form of the complex number that point A represents?

Answers

Hello there. To solve this question, we have to remember some properties about the representation of a complex number in the complex or Argand-Gauss plane.

Given the complex plane with the point A representing a complex number:

We have to remember that in the complex plane, a complex number z:

[tex]z=a+ib[/tex]

has coordinates

[tex](a,\,b)[/tex]

And it is more commonly represented by a vector starting at the origin and with the tip on this point.

In this case, we find that the coordinates of the point A are:

[tex]A=(-5,\,3)[/tex]

Which means that the complex number is

[tex]-5+3i[/tex]

And this is the answer contained in the last option.

Evaluate 7a - 5b when a = 3 and b = 4 .

Answers

[tex]\begin{gathered} \text{ When evaluating, just substitute the values given assigned to the variable} \\ a=3,b=4 \\ 7a-5b \\ =7(3)-5(4) \\ =21-20 \\ =1 \end{gathered}[/tex]


Help!
find all zeros of p(x). include any multiplicities greater than one.

Answers

The most appropriate choice for polynomial will be given by

1) Zeroes of P(x) = 2, [tex]\frac{2 + \sqrt{2}i}{3}[/tex], [tex]\frac{2 - \sqrt{2}i}{3}[/tex]

where [tex]i = \sqrt{-1}[/tex]

2) Zeroes of P(x) = 3, 2i, -2i

3) Roots are 2i, -2i, [tex]\frac{3}{2}[/tex]

4) Roots are 0, 1, [tex]2 + \sqrt{5}[/tex], [tex]2 - \sqrt{5}[/tex]

What is a polynomial?

An algebraic expression of the form [tex]a_0 + a_1x +a_2x^2 + a_nx^n[/tex] is called a polynomial of degree n.

[tex]1) P(x ) = 3x^3 -10x^2 + 10x -4\\P(2) = 3(2)^3 - 10(2)^2 +10(2) - 4\\[/tex]

        [tex]= 24 -40 + 20 -16\\= 0[/tex]

(x - 2)  is a factor of P(x)

[tex]P(x) = 3x^2(x - 2) -4x(x - 2) +2(x-2)\\[/tex]

        = [tex](x - 2)(3x^2 - 4x + 2)[/tex]

        [tex]=(x-2)(x -a)(x - b)[/tex]

where,

[tex]a = \frac{-(-4)+\sqrt{(-4)^2 - 4\times 3\times 2}}{2\times 3}\\a =\frac{ 4 + \sqrt{-8}}{6}\\a = \frac{4 + 2\sqrt{2} i}{6}\\a = \frac{2(2 + \sqrt{2}i)}{6}\\a = \frac{2 + \sqrt{2}i}{3}[/tex]

[tex]b = \frac{-(-4)-\sqrt{(-4)^2 - 4\times 3\times 2}}{2\times 3}\\b =\frac{ 4 -\sqrt{-8}}{6}\\b = \frac{4 - 2\sqrt{2} i}{6}\\b = \frac{2(2 - \sqrt{2}i)}{6}\\b = \frac{2 - \sqrt{2}i}{3}[/tex]

Zeroes of P(x) = 2, [tex]\frac{2 + \sqrt{2}i}{3}[/tex], [tex]\frac{2 - \sqrt{2}i}{3}[/tex]

where [tex]i = \sqrt{-1}[/tex]

[tex]2) P(x) = x^3 - 3x^2+4x-12\\P(3) = (3)^3 - 3(3)^2 +4(3) -12\\ P(3) = 0[/tex]

(x - 3) is a factor of P(x)

[tex]x^2(x - 3) + 4(x - 3)\\(x - 3)(x^2 + 4)\\(x - 3)(x -a)(x-b)\\[/tex]

where,

[tex]a = \sqrt{-4}\\a = 2i[/tex]

[tex]b = -\sqrt{-4}\\a = -2i[/tex]

Zeroes of P(x) = 3, 2i, -2i

[tex]3) 2x^3 - 3x^2 +8x-12= 0\\[/tex]

x = 2 satisfies the equation

[tex]2x^2(x -\frac{3}{2}) + 8(x-\frac{3}{2})=0\\(2x^2+8)(x - \frac{3}{2}) = 0\\[/tex]

[tex]2x^2 + 8 = 0[/tex] or [tex]x - \frac{3}{2} = 0[/tex]

[tex]x^2 = -\frac{8}{2}[/tex] or [tex]x = \frac{3}{2}[/tex]

[tex]x^2 = -4[/tex] or [tex]x = \frac{3}{2}[/tex]

[tex]x = \sqrt{-4}[/tex] or [tex]x = \frac{3}{2}[/tex]

[tex]x = 2i[/tex] or [tex]x = -2i[/tex] or [tex]x = \frac{3}{2}[/tex]

Roots are 2i, -2i, [tex]\frac{3}{2}[/tex]

4)

[tex]x^4 - 5x^3 +3x^2 +x = 0\\x(x^3 -5x^2 + 3x +1) = 0\\[/tex]

[tex]x = 0[/tex] or [tex]x^3 -5x^2+3x +1 = 0[/tex]

For  [tex]x^3 -5x^2+3x +1 = 0[/tex]

x = 1 satisfies the equation

[tex]x^2(x -1) -4x(x-1)-1(x-1) = 0\\(x - 1)(x^2 - 4x -1) = 0\\[/tex]

[tex]x -1 = 0[/tex] or [tex]x^2 - 4x -1 = 0[/tex]

Roots are x = 1 or x = a or x = b

where,

[tex]a = \frac{-(-4) + \sqrt{(-4)^2 - 4\times 1 \times(-1)}}{2\times 1}\\a = \frac{4+\sqrt{20}}{2}\\a = \frac{4 + 2\sqrt{5}}{2}\\a = \frac{2(2 + \sqrt{5})}{2}\\a = 2 + \sqrt{5}[/tex]

[tex]b = \frac{-(-4) - \sqrt{(-4)^2 - 4\times 1 \times(-1)}}{2\times 1}\\b = \frac{4-\sqrt{20}}{2}\\b = \frac{4 - 2\sqrt{5}}{2}\\b = \frac{2(2 - \sqrt{5})}{2}\\b = 2 - \sqrt{5}[/tex]

Roots are 0, 1, [tex]2 + \sqrt{5}[/tex], [tex]2 - \sqrt{5}[/tex]

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Solve the system by graphing:2x – y= -14x - 2y = 6Solution(s):

Answers

To find the solution of the system by graphing we need to plot each line in the plane and look for the intersection.

First we need to write both equations in terms of y:

[tex]\begin{gathered} y=2x+1 \\ y=2x-3 \end{gathered}[/tex]

now we need to find two points for each of this lines. To do this we give values to the variable x and find y.

For the equation 2x-y=-1, if x=0 then:

[tex]y=1[/tex]

so we have the point (0,1).

If x=1, then:

[tex]y=3[/tex]

so we have the point (1,3).

Now we plot this points on the plane and join them with a straight line.

Now we look for two points of the second equation.

If x=0, then:

[tex]y=-3[/tex]

so we have the point (0,-3)

If x=1, then:

[tex]y=-1[/tex]

so we have the point (1,-1).

We plot the points and join them wiith a line, then we have:

once we have both lines in the plane we look for the intersection. In this case we notice that the lines are parallel; this means that they wont intersect.

Therefore the system of equations has no solutions.

Other Questions
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