The minimum distance such that the grocery bag does not slide off when the brake force applied is 25.43 m
The grocery bag will start to slide off if the force exerted by the brake is equal to the maximum static friction force.
Let:
Fs = static friction force
F = force exerted by the brake
m = mass of the grocery bag
v = velocity
μs = static coefficients of friction
g = gravitational acceleration = 9.8 m/s²
Then,
Fs = - μs . m. g
F = m . a
Fs = F
- μs . m. g = m . a
a = μs . g = 0.65 . 9.8 = - 6.37 m/s²
With this deceleration, the distance (s) will be:
v² = u² + 2 . a. s
Where v = 0 (since vehicle stops), u = 18 m/s
0 = 18² + 2 . (- 6.37 ) . s
s = 25.43 m
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a 60- kg mountain climber moves 10 m up a vertical slope. if the muscles in her body convert chemical energy into gravitational potential energy with an efficiency of no more than 5%, what is the chemical energy used to climb the slope?
120000 Joules of Chemical Energy is used by the climber to climb the rope.
As the climber is moving up, its gravitation potential energy energy (G) will be given by,
Gravitational potential Energy = MgH
G = MgH
Where,
M is mass of climber which is 69 Kg,
g is acceleration due to gravity which is 10m/s².
H is the height above the earth's surface which is 10 meters.
It is provided that the chemical energy is converted to gravitational energy at a rate of 5%.
So, we can write,
5% Chemical energy (C) = Gravitational potential energy (G)
So,
5%C = MgH
Putting all the values,
5C/100 = 60(10)(10)
C = 120000 Joules.
The used chemical energy is 120000 Joules.
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which of the following statements is correct: a. venturi meter is a common device for quantifying flow rate q based on differences in pressure. b. hot-wire anemometers measure fluid velocity based on effectiveness of heat transfer away from a heated wire. c. rotameters use drag on a floating object in equilibrium with its weight and buoyancy to indicate volume flow rate by position of the float. d. all of the above statements are correct.
Option D is correct. In venturi meter a converging section of a pipe is used to increase the flow velocity and corresponding pressure drop, from which the fluid flow rate is calculated using Bernoulli's equation.
A venturimeter is a flow measurement device. The meter is connected between two sections of the pipe; the cross-sectional area A of the meter's entrance and exit corresponds to the cross-sectional area of the pipe. The fluid flows from the pipe with speed V between the entrance and exit, and then through a narrow throat with cross-sectional area a with speed v. A venturi works by measuring the difference in pressure between two points. The pressure difference is created by narrowing the pipe, causing the fluid to flow faster. In the larger section of the venturi, the fast moving fluid has a lower pressure than the slower fluid.
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rocky the flying squirrel is carrying a nut of mass 0.5 kg while flying horizontally at a height of 15 m above the ground at a speed of 12 m/s. bullwinkle is eagerly awaiting the delivery of the nut on the ground. rocky releases the nut as he is directly above bullwinkle. how far from bullwinkle will the nut land if bullwinkle does not move
The nut distance from the Bullwinkle after uniform motion is 21 m.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, the parameters given are
m = 0.5 kg
s = 15 m
vx = 12 m/s
vo = 0 m/s
a = g = 9.8 m/s²
Find the time taken of the nut for landing
s = vo . t + 1/2 . a . t²
15 = 0 + 1/2 . 9.8 . t²
t² = 3.06
t = 1.75 s
Find the distance of nut in horizontal direction
vx = x / t
12 = x / 1.75
x = 12 . 1.75
x = 21 m
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what is the force of an object that has a mass of 20 kg and is accelerating at a rate of 15 m/s/s
hii i am satyam from India and i m having doubt in this question according to me answer should be 20 % but in answer key it's 21 % how??
The formula relating kinetic energy and momentum of a particle is expressed as
KE = p^2/2m
let the actual momentum be p. Since the error measurement is 10%, the measurement of the momentum would be
p + 0.1p = 1.1p
Percentage error in the measurement of the kinetic energy is obtained by the formula,
% error = (KEf - KEi)/KEi x 100
where
KEf is the final kinetic energy measured error
KEi is the initial kinetic energy measured without error
Thus,
% error = [(1.1p)^2/2m - p^2/2m)]/p^2/2m x 100
% error = p^2/2m(1.1^2 - 1)/(p^2/2m) x 100
% error = 100(1.1^2 - 1)
% error = 21%
How is the amplitude of a
longitudinal wave measured?
A. the distance between two rarefactions
B. the distance between two compressions
C. It is measured by how close together or spread
apart the compressions and rarefactions are.
if this wire is used as a heating element, how much time is required for this wire to raise the temperature of 25.0 g of water from 27.0 o c to 60.0 o c? the wire is completely submerged in the water and all the energy dissipated in the wire is absorbed by the water.
The time required to gain the thermal energy is 3465/P second.
We need to know about thermal energy to solve this problem. The total heat received by the system will equal to total heat released by objects. It should follow
Q released = Q received
The heat can be defined by
Q = m . c . ΔT
where Q is thermal energy, m is mass, c is the specific heat constant and ΔT is the change in temperature.
The given parameters are
m = 25 g = 0.025 kg
c = 4200 J/kgK
ΔT = 60 ⁰C - 27 ⁰C = 33 ⁰C
The thermal energy released by the heating element per second is equal to the power. Let's assume that the heating element has the power of P
Find the thermal energy received by the water
Q = m . c . ΔT
Q = 0.025 . 4200 . 33
Q = 3465 joule
Find the time required to raise the temperature
P = Q / t
P = 3465 / t
t = 3465 / P second
where P is power in the watt unit.
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PLEASE HELP ASAP!!! A high school athlete is in the weight room training for wrestling season. He is trying to bench press a bar loaded with 100
kg. How much force must he exert to lift the loaded bar and overcome the force of gravity?
Remember that a= 9.8 m/s² (1 point)
O 10.2 N
O 9800 N
O 980 N
109.8 N
Answer:
980N
Explanation:
100kg times 9.8m/s2
The force the high school athlete must exert to lift the loaded bar of mass 100 kg and overcome the force of gravity is 980 N
F = m a
F = Force
m = Mass
a = Acceleration
m = 100 kg
a = 9.8 m / s²
F = 100 * 9.8
F = 980 N
The equation used to solve the given problem is derived from the Newton's second law of motion. The law states that the force is the rate of change of momentum.
Therefore, the force the high school athlete must exert is 980 N
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A 0. 20-kg baseball is struck with a force of 100 n from a 0. 94-kg baseball bat. What will be the acceleration of the ball and the bat, in that order, while the bat and ball are in contact?.
The acceleration of the baseball is 500 m/s².
A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull.
The mass of the baseball, m = 0.2 kg
The force acting on the baseball is 100 N.
By Newton's second law of motion,
F = ma
Substituting the values in the above equation,
100 N = 0.2 kg × a
a = 100 / 0.2
a = 500 m/s²
The total mass when the baseball and baseball bat are in contact is:
m = 0.2 + 0.94 = 1.14 kg
Then the acceleration will be:
F = ma
100 = 1.14 × a
a = 87.7 m/s²
The acceleration of the ball after the contact is 500 m/s².
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27. Beyond "c", the speed of the rocket is;
(A) constant.
(B) continuously increasing.
(C) continuously decreasing.
(D) increasing for a while and constant thereafter.
(E) constant for a while and decreasing thereafter.
Beyond "c", the speed of the rocket is; (D) increasing for a while and constant thereafter.
How quickly does a rocket move?The space shuttle must accelerate from zero to 8,000 metres per second (nearly 18,000 miles per hour) in eight and a half minutes to reach the minimum height necessary to circle the Earth.
The orbital velocity is 7.9 kilometres per second, which translates to more than 20 times the speed of sound. A rocket attaining orbital velocity (1st cosmic velocity) will enter orbit around the Earth (C), whereas a faster rocket would follow an elliptical trajectory (D).
On Earth, air tends to prevent exhaust gases from exiting the engine. This lessens the thrust. However, because there is no atmosphere in space, the exhaust gases may depart considerably more easily and quickly.
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in february 1955, a paratrooper fell 370 m from an air- plane without being able to open his chute but happened to land in snow, suffering only minor injuries. assume that his speed at im- pact was 56 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the magnitude of the force on him from the www.engineeringbookspdf problems 249 12.0 m/s and angle u1 35.0. just after, it is traveling directly upward with velocity of magnitude 10.0 m/s. the duration of the collision is 2.00 ms. what are the (a) magni- v : 2 snow was at the survivable limit of 1.2 105 n. what are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
(a)1.1 m is the minimum depth of snow that would have stopped him safely. (b)The magnitude of the impulse on him from the snow[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] -4.8 * 10³ kg. m/s.
What is magnitude ?A key concept in science is magnitude, which is employed in physics. Magnitude describes a general amount or a distance. We can relate magnitude to size and speed of the object is motion while considering the aspects of movement. The magnitude of the an object is defined by it's own size or quantity.
Briefing:We choose +y upward, which implies a>0 (the acceleration is upward since it represents a deceleration of his downward motion through the snow).
a) The maximum deceleration a[tex]_m_a_x[/tex] of the paratrooper (of mass m and initial speed ν=56m/s ) is found from Newton’s second law
F[tex]_s_n_o_w[/tex]−mg=ma[tex]_m_a_x[/tex]
where we require F[tex]_s_n_o_w[/tex] =1.2×10⁵N . Using Eq. 2 −15ν² =2a max d , we find the minimum depth of snow for the man to survive :
[tex]\mathrm{d}=\frac{v^2}{2 \mathrm{a}_{\text {max }}}=\frac{\mathrm{m} v^2}{2\left(\mathrm{~F}_{\text {snow }}-\mathrm{mg}\right)} \approx \frac{(85 \mathrm{~kg})(56 \mathrm{~m} / \mathrm{s})^2}{2\left(1.2 \times 10^5 \mathrm{~N}\right)}=[/tex]1.1 m.
(a) He experiences a change in momentum during his brief journey through the snow.
[tex]\Delta \overrightarrow{\mathrm{p}}=\overrightarrow{\mathrm{p}}_{\mathrm{f}}-\overrightarrow{\mathrm{p}}_{\mathrm{i}}[/tex] = 0 - (85 kg)(-56m/s)= -4.8 * 10³ kg. m/s.
or[tex]|\Delta \overrightarrow{\mathrm{p}}|[/tex] = -4.8 * 10³ kg. m/s.
Because downward is the negative direction, the starting velocity has a negative value. This equals the impulse caused by the net force F[tex]_s_n_o_w[/tex]−mg according to the impulse-momentum theorem, but since F[tex]_s_n_o_w[/tex] ≫mg we can approximate this as the impulse on him just from the snow.
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The complete question is -
In February 1955, a paratrooper fell 370m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 56m/s (terminal speed), that his mass (including gear) was 85kg, and that the magnitude of the force on him from the snow was at the survivable limit of 1.2×10⁵ N. What are (a) the minimum depth of snow that would have stopped him safely and (b) the magnitude of the impulse on him from the snow?
Imagine a black hole lacking any accretion disk whatsoever. Would this black hole produce any light? why?.
Once a beam of light enters a black hole, it can never exit.
Moreover, A black hole is a region where space-time is so curved that every possible path that light could take eventually curves back inside the black hole. As a result, once a beam of light enters a black hole, it can never exit. Because of this, a black hole is truly black and never emits light. It appears as a dark circle silhouetted by an orbiting disk of hot, glowing matter. The supermassive black hole is located at the heart of a galaxy called M87, located about 55 million light-years away, and weighs more than 6 billion solar masses.
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a ball is thrown upward with initial velocity of 20 m/s. (a) how long is the ball in the air? (b) what is the greatest height reached by the ball? (c) when is the ball 15 m above the ground?
a) t = 4.08 s
b) Response = 20.39m
c) t = 0.991 and 3.087 seconds.
Initially, the vertical speed was 20 m/s.
(a) how long is the ball in the air?
The ball is tossed upward, rises to its highest point, and then hits the ground again.
Consequently, the end height will be equal to the starting height.
h = h o = Om
Use the equation s= ut + -at.
2764 – An = 14
Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.
Om = t - 0.5 * 9.81 m/s * 20 m/s
0 = 20 *t - 0.5 * 9.81 *t
20 *t=0.5*9.81 *t
20 = 0.5 * 9.81 *t
20 0.5*9.81
Answer (a): t = 4.08 s
(b) what is the greatest height reached by the ball?
Vertical velocity for the ball decreases to zero when it reaches its highest point.
Use the equation 2-u=295
-2ghmas for - u
(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *
02 – 20= -2*9.81 *
-20% = -2 *9.81 *
202 = 2 * 9.81 *
b) RESPONSE: H = 20.39m
(c) when is the ball 15 m above the ground?
The ball will be 15 meters above the earth on two separate occasions.
1. When climbing
2. When descending
Use the equation s= ut + -at.
2,264 – fn = 4
0.5 * 9.81 m/s * 15m = 20 m/s*t
15 = 20 *t - 0.5 * 9.81 *t
15 = 20t – 4.9057
4.905 – 20t + 15 = 0
Calculator-based quadratic equation solution
(c) t = 0.991 and 3.087 seconds.
Hence the answers are,
a) t = 4.08 s
b) RESPONSE: Hmar = 20.39m
c) t = 0.991 and 3.087 seconds.
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Can someone help me pls, i have like another 3 questions like this :')
an apple drops from a tree and hits the ground in 1.4 s how far does it fall?
It falls 9.8m far for the apple to drop from tree in 1.4sec.
Apple fall time t = 1.4 s
The free fall distance in time t is given by
d = 1/2at²
where a = g = 10 m/s² = free fall acceleration
calculation:
Using the above formula and the values given, the distance the apple will fall free in 1.4 seconds is
d = 1/2(10)(1.4)²
= 9.8 m
Therefore the distance um the apple will fall is 9.8 m.
Isaac Newton formulated gravitational theory in 1665 or 1666 after watching an apple fall. An apple falling from a tree is an example of Straight-line motion because gravity causes it to fall vertically in a straight line.
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What is "velocity"?
A. Velocity is a scalar quantity that tells the acceleration of an object over a period of time.
B. Velocity is a vector quantity that tells the distance an object has traveled over a period of time.
C. Velocity is a vector quantity that tells the force of an object over a period of time.
D. Velocity is a scalar quantity that tells the distance an object has traveled over a period of time.
Answer:
The answer is the letter B
Explanation:
Because velocity is a vector quality since to define it is necessary to specify its size (equivalent to speed) and its direction and the letter B tells then velocity is a vector quality that tells the distance an object has traveled over a period of time.
I think than is the letter B
Velocity is a vector quantity that tells the distance an object has traveled over a period of time. So, option (B) is correct.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.
Hence, velocity is a vector quantity which can tell displacement of a body , that is, distance between initial and final position - which is equal to from the distance an object has traveled over a period of time.
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question 1 what is the main source of kinetic energy of the electrons? the high temperature of the glowing filament. the potential difference between the two ends of the glowing filament. the potential difference between the filament and the cylindrical anode.
The main source of the kinetic energy of the electrons is the potential difference between the two ends of the glowing filament.
When an electron is launched out from a metal surface it has kinetic energy.
The sum of active energy the electron has depends on the contrast between the energy of the photon and the work of the metal. The kinetic energy of the electron is rise to the energy of the photon short the work of the metal.
Kinetic energy has permitted us to create power through combustion turbines, development for automobiles, and vitality sources such as wind control and hydro control.
All kinetic energy starts as potential vitality within the frame of either physical objects found in particular places, chemical potential vitality, or atomic potential energy.
An electron does bit have kinetic energy as a molecule property. It depends on any molecule on how quickly it is moving. Typically, the complete relativistic energy. It is the vitality of movement — in which the complete energy shorts the rest of the energy.
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Two uniform cylinders are machined out of solid aluminum. One has twice the radius of the other. If both are placed at the top of the same ramp and released, which is moving faster at the bottom?.
Both cylinders will reach the same speed since speed is independent of mass and radius.
Radius of smaller cylinder = R1
Radius of bigger cylinder = R2
their masses = m1/m2 = [tex]\frac{R1}{2R1} ^{2}[/tex]
From law of conservation of energy we have
[tex]mv^{2} /2 + Iw^{2}[/tex] = mgh
[tex]1/2 mv^{2}[/tex] + [tex]m\frac{R}{L}[/tex] × [tex]\frac{x}{y}[/tex] = mgh
3/4 v2 = gh
v= [tex]\sqrt{4/3gh}[/tex]
Since from the above relation, speed is independent of mass and radius, so both cylinders have same speed.
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Neither of the two cylinders moves faster at the bottom. Both cylinders move with the same velocity at the bottom.
By the formula for conservation of energy, for a solid cylinder placed at the top of a ramp and rolling down to the bottom, we have
The kinetic energy of linear motion + rotational kinetic energy = potential energy (1)
Kinetic energy due to linear motion (of the center of mass of cylinder)= [tex]\frac{1}{2} mv^{2}[/tex]
Rotational kinetic energy = [tex]\frac{1}{2}Iw^{2}[/tex]
m = mass of cylinder, v = velocity of the center of mass of the cylinder
I = moment of inertia of solid cylinder = [tex]\frac{1}{2}mR^{2}[/tex] (R = radius of cylinder)
angular velocity w = v/R
g = acceleration due to gravity, h= height of the ramp
From equation (1)
[tex]\frac{1}{2}mv^{2}+ \frac{1}{2}Iw^{2} = mgh[/tex]
⇒[tex]\frac{1}{2}mv^{2}+\frac{1}{2}(\frac{1}{2}mR^{2}* \frac{v^{2} }{R^{2} } ) = mgh[/tex]
⇒[tex]\frac{1}{2}mv^{2}+\frac{1}{4}mv^{2}=mgh[/tex]
⇒[tex]\frac{3}{4}[/tex][tex]mv^{2} =mgh[/tex]
⇒v=√(4gh/3) (cancel m on both sides)
Thus we see the velocity at the bottom of the sloping ramp that is v is independent of the mass or radius of the solid cylinders and only depends on the height of the ramp and acceleration due to gravity.
Thus both cylinders reach the bottom with the same velocity.
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A forklift raises a crate weighing 8.35 × 102 newtons to a height of 6.0 meters. What amount of work does the forklift do?
Answer:5110.2 joule
Explanation:Weight of the crate:- 8.35 x 102 N
Height to which the forklift lift the crate:- 6.0 M
Work done by the forklift=F.d
F=Gravitational Force =m.g
d=height=h
Work w=m.g.h
m.g=8.35 x 102 N
h=6.0 M
w=8.35x102N x 6.0M
w=5110.2NM
w=5110.2joule
at the spinal tap concert in deware fieldhouse, nigel turns his guitar amp up to 11, blowing out the inductor on the subwoofer. what value of inductor would you grab from the lab if the speaker resistance is 4ohms and only frequencies below 250hz are desired? the speaker is a resistor.
The load a speaker provides on an amplifier is referred to as speaker impedance. That is, in fact, the result of speaker impedance.
Speaker impedance is defined as the "resistance" a speaker provides to the current delivered by an amplifier in technical terms.
The resistance is known as impedance because an amp's output current is AC (as opposed to DC, like from a battery), not DC. To be completely technical, impedance is the result of adding any reactance present in an AC circuit to DC resistance.
Just keep in mind that speaker impedance impacts how much current is drawn from the amplifier without getting too technical.
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when resistors 1 and 2 are connected in series, the equivalent resistance is 13.6. when they are connected in parallel, the equivalent resistance is 2.40. what are (a) the smaller resistance and (b) the larger resistance of these two resistors?
The larger resistance is R₂ =12Ω.
Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.
series connection:- R equivalent = R₁ + R₂
R₁ + R₂ = 13.6 Ω
R₁ = 13.6 Ω - R₂
parallel connection:- R equival;ent = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / 13.6 Ω
R₁R₂ = 2.40 × 13.6 Ω
R₁R₂ = 32.64 Ω
2.40 = R₁R₂ / R₁ + R₂
R₁ + R₂ = 32.64 Ω / 2.40 Ω
R₁ + R₂ = 13.6.
must be 4.0Ω and 13.6Ω, respectively.
(a) The smaller resistance is R₁ =4.0Ω
(b) The larger resistance is R₂ =12Ω
An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.
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PLEASE HELP
Question: How would the paths of motion of the planets change if the gravitational force of the sun were to suddenly disappear?
The planets currently move in ___ paths. Newton observed that objects always move in straight paths unless ____. This means that removing the force of gravity would cause them to ____.
The paths of motion of the planets, if the gravitational force of the sun were to suddenly disappear will be a straight line.
The orbits in which the planets revolve around the Sun is elliptical in shape. Johannes Kepler was the first to discover the elliptical shape of orbits which was called as Kepler's laws of planetary motion.
According to Newton's first law of motion, objects always move in straight paths unless acted upon by an external force. This means that removing the force of gravity would cause them to move a straight line tangential to the orbit that it was revolving about.
Therefore,
The planets currently move in elliptical pathsNewton observed that objects always move in straight paths unless acted upon by an external forceThis means that removing the force of gravity would cause them to move a straight lineTo know more about Kepler's laws of planetary motion
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1. The subatomic particle with no electrical charge is the
2. The subatomic particle with a positive charge is the
3. The subatomic particle with a negative charge is the
4. There are the same number of these two particles in an atom
&
5. The atomic number is the same as the number of
To understand the questions, one should know the structure of an atom.
An atom is made up of some subatomic particles. These particles are positively charged, negatively charged and neutral particles.
The positive and negative charged particles neutralize the atom and the neutral subatomic particles are neutrons.
The answer to the questions are as follows:
1. The subatomic particle with no electrical charge is the "neutron".
2. The subatomic particle with a positive charge is the "proton".
3. The subatomic particle with a negative charge is the "electrons".
4. There are the same number of these two particles in an atom are "electrons" & "protons".
5. The atomic number is the same as the number of "protons" in an atom.
To sum up, an atom has different particles such as protons, electrons and neutrons. With protons being the positively charged, electrons are negatively charged and neutrons are neutral. Neutrons and protons are found in the nucleus and the electrons are spread around the nucleus.
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A student placed two magnets 5cm apart for a lab experiment. after completing two trials of the experiment, she leaves. when she returned, she noticed her magnets were moved just a little but decided to continue working with them anyway. after trying her 3rd trial of the lab, her magnets did not work. what happened?
The third trial of the lab experiment did not work out because in most probability the magnets lost their magnetic properties or got demagnetized.
Demagnetization is the phenomenon by which magnets lose their magnetic property or are weakened. We see that the magnets moved just a little after she left them after the first two trials of her experiment. It is possible that because the magnets moved a little they repelled each other and this only happens when like poles face each other.
The demagnetizing field of one magnet will affect the other and vice versa because their magnetic fields are opposite in direction. Consequently, magnetic field strength weakens gradually. Thus the magnets did not work after the 3rd trial.
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If a batter can apply the same amount of maximum force from their hands to each bat to swing it, why
would the speed of the bat swing decrease as the mass of the bat increases?
If a batter can apply the same amount of maximum force from their hands to each bat to swing it , the speed of the bat swing decrease as the mass of the bat increases because of greater moment of inertia .
Moment of inertia is directly proportional to the mass , hence if mass of the bat increased , moment of inertia will also increase and it will be more difficult to swing the bat .
hence , the speed of the bat swing decrease as the mass of the bat increases
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its hard it have time help
Answer:
i think it's a
Explanation:
A cat wakes up in its bed and visits its food dish to the left of its bed. Positions to the right of its bed are assigned a negative value and positions to the left of its bed are assigned a positive value. Where did the cat begin and end its journey?
Time (m) 1, 2, 3, 4, 5
Position (m) 0, 2, 4, -5, -10
O The cat began its journey at its food dish and ended its journey 10 meters to the right of its bed.
O The cat began its journey in bed and ended its journey 5 meters to the left of its bed.
O The cat began its journey at its food dish and ended its journey 10 meters to the left of its bed.
O The cat began its journey in bed and ended its journey 10 meters to the right of its bed.****
The cat began its journey in bed and ended its journey 10 meters to the right of its bed.
Journey is an act of travelling from one place to another.
The cat wakes up in its bed and visits its food dish to the left of its bed.
This show that the cat's journey starts from positive value and according to the position chart it travels 2 m after waking up in the bed.Next 2 m it travels again in positive direction and reaches to value 4Then it goes towards the right side of the bed and travels to -5.It's journey ends at the right side of the bed when it reaches to value as -10.Time (m) 1, 2, 3, 4, 5
Position (m) 0, 2, 4, -5, -10
The above time table shows that the journey of the cat starts from the moment it wakes up in the bed as the timer starts the moment the cat wakes up and ends at 10 in negative direction i.e. to the right side of the bed.
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a 80.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 47.0 m/s. if both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 18.0 m away?
As a result of the law of conservation of momentum, the man will recoil as far as 0.034 m.
The law of conservation of momentum:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the player and the puck are initially at rest, hence u₁ = 0, u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 80 kg
m₂ = 0.150 kg
v₂ = 47 m/s
Plug the parameters into the equation,
80 . v₁ + 0.15 . 47 = 0
v₁ = - 0.088 m/s
Time the puck reach 18 m goal:
t = distance / velocity = 18 / 47 = 0.38 s
The player will recoil:
distance = velocity x t = 0.088 x 0.38 = 0.034 m = 3.4 cm
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a driver who does not wear a seat belt continues to move forward with a speed of 18.0 m/sm/s (due to inertia) until something solid like the steering wheel is encountered. the driver then comes to rest in a much shorter distance - perhaps only a few centimeters. find the net force acting on a 65.0 kgkg driver who is decelerated from 18.0 m/sm/s to rest in 5.00 cmcm .
The net force acting on: 2.113 x 10⁵ N.
First, we need to calculate the deceleration of the driver by using 3rd equation of motion: 2as = Vf² - Vi²
where,
a = deceleration = ?
s = distance = 5 cm = 0.05 m
Vf = Final Velocity = 0 m/s
Vi = Initial Velocity = 18 m/s
Therefore,
2a(0.05 m) = (0 m/s)² - (18 m/s)²
a = (- 324 m²/s²)/0.1 m
a = - 3240 m/s²
where the negative sign represents a deceleration
From Newton's Second Law of Motion:
F = ma
F = (65 kg)(-3240 m/s²)
F = - 2.106 x 10⁵ N
So, the closest answer is:
F = 2.113 x 10⁵ N
What is force ?
In physics, a force is an effect that can change the motion of an object. A force can cause an object with mass to change speed, ie. accelerate A force can also be intuitively described as a push or a pull. A force has both magnitude and direction, so it is a vector quantity.
When a body tends to change or change its state under the influence of an external cause, it is called a force. A body can also change its shape, size and direction when a force is applied. For example, kicking a ball, pulling and pushing a door.
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a car travelling at a speed of 45km/h takes 20 minutes to reach its destination.what distance has the car travelled
First, we need to do a type conversion. Because the types of the two given quantities are different. One is in minutes. The other is in hours. A vehicle that travels [tex]45[/tex] kilometers in an hour travels how many meters in a second?
[tex]45km/h=\frac{45km}{1hour} =\frac{45km.1000}{1hour.3600} =12.5m/s[/tex]A vehicle that travels [tex]12.5[/tex] meters in a second travels how many meters in [tex]20[/tex] minutes?
[tex]1200.(12.5)=15000m=15km[/tex]