Gordan have left 0 GB to roll over to the next billing cycle at the end of the four weeks.
What is Addition?
The sum of all the numbers are called the Addition of numbers.
Given that;
Gordin has 4.1 GB of data in one 4-week billing cycle on his cell phone.
And, The table shows how much data Gordon uses each week before his next billing cycle as;
WEEK = 1 2 3 4
DATA USAGE = 0.8 1.3 0.9 1.1
Now,
Since, Gordin has 4.1 GB of data in one 4-week billing cycle on his cell phone.
And, The table shows how much data Gordon uses each week before his next billing cycle.
So, We can add all the given data usage in 1 to 4 week as;
Data usage = 0.8 + 1.3 + 0.9 + 1.1
= 4.1 GB
Thus, Gordan have left 0 GB to roll over to the next billing cycle at the end of the four weeks.
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The length of time (T) in seconds it takes the pendulum of a clock to swing through one compete cycle is givenby the formulaT= 2T✔️L/32 Where L is the length, in feet, of the pendulum, and is pie approximately 22/7. How long must the pendulum be of one complete cycle takes 2 seconds? Answer as a fraction or round to at least 2 decimal places.The pendulum must be__ feet.
we have the formula
[tex]T=2\pi\sqrt{\frac{L}{32}}[/tex]For T=2 seconds
substitute in the given formula
[tex]\begin{gathered} 2=2\pi\sqrt{\frac{L}{32}} \\ \\ 1=\frac{22}{7}\sqrt{\frac{L}{32}} \\ \\ squared\text{ both sides} \\ \\ (\frac{7}{22})^2=\frac{L}{32} \\ \\ L=\frac{7^2*32}{22^2} \\ \\ L=3.24\text{ ft} \end{gathered}[/tex]what must be a factor if the polynomial function f(x) graphed ib the coordinate plane below ?
Solution
The question gives us a graph that crosses the x-axis at 3 points: x = 1, x = 2, and x = -3. We are asked to find which of the factors on the graph is in the options given.
- Whenever a graph crosses the x-axis at a point "a", it implies that x = a is a root of the graph and as a result, (x - a) must be a factor of the graph.
- We can apply this to the question and derive the factors of the graph as follows:
[tex]\begin{gathered} \text{ When }x=-3\colon \\ x=-3 \\ \text{Add 3 to both sides} \\ x+3=0 \\ \\ \text{Thus, }(x+3)\text{ is a factor of the graph.} \\ \\ \\ \text{When }x=1\colon \\ x=1 \\ \text{Subtract 1 from both sides} \\ x-1=0 \\ \\ \text{Thus, }(x-1)\text{ is a factor of the graph} \\ \\ \\ \text{When }x=2\colon \\ x=2 \\ \text{Subtract 2 from both sides} \\ x-2=0 \\ \\ \text{Thus, (}x-2)\text{ is a factor of the graph.} \\ \\ \\ \text{Thus, we can conclude that the 3 factors of the graph are:} \\ (x+3),(x+1),\text{ and }(x-2) \end{gathered}[/tex]- Going through the options, we can see that only (x - 1) is present in the options.
- Thus, (x - 1) is the answer
Final Answer
(x - 1) is the answer (OPTION B)
Find the slope of the line that contains the two points.ROUND YOUR ANSWER TO TWO DECIMAL PLACES.
The slope of a line is given by the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where (x1,y1) and (x2,y2) are the coordinates of the given points. Replace the given values and solve for m:
[tex]m=\frac{8-(-4)}{-6-0}=\frac{8+4}{-6}=\frac{12}{-6}=-2[/tex]The slope of the line that contains the two given points is -2.
What is the slope of the line passing through the points (−1, 7) and (4, −1)? −5/62−8/5−2
Given the points:
(−1, 7) and (4, −1)
The slope of the line passing through the points is given by:
[tex]slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-7}{4-(-1)}=\frac{-8}{5}[/tex]So, the answer will be Slope = -8/5
Use the rectangle at the right to answer the following questions. a. Find the area of the entire rectangle. Show your work. b. Calculate the perimeter of the figure. Show your work.
Length of the entire rectangle = 12 + 5 = 17
Width of the entire rectangle = 6+4 = 10
Part a
Area of rectangle = Length x width
Area of the entire rectangle = 17 x 10 = 170 square units
Part b
Perimeter of rectangle = 2( length + width )
Perimeter of the entire rectangle = 2(17 + 10 )
=2 (27) = 54
Perimeter of the entire rectangle = 54 units
Length of the entire rectangle = 12 + 5 = 17
Width of the entire rectangle = 6+4 = 10
Part a
Area of rectangle = Length x width
Area of the entire rectangle = 17 x 10 = 170 square units
Part b
Perimeter of rectangle = 2( length + width )
Perimeter of the entire rectangle = 2(17 + 10 )
=2 (27) = 54
Perimeter of the entire rectangle = 54 units
he two-way frequency table given shows the results from a survey of students who attend the afterschool program.
Takes Art Class Doesn't Take Art Class Total
Plays a Sport 45 120
Doesn't Play a Sport 45
Total 225
Does the data show an association between taking an art class and playing a sport?
There is a strong, positive association.
There is a strong, negative association.
There is a weak, positive association.
There is a weak, negative association.
The association between the variables art class and playing a sport is classified as follows:
There is a strong, negative association.
What is the association between the two variables?The association between variables can be classified either as positive or as negative, as follows:
Positive: both variables behave similarly, either both increases or both decreasing.Negative: the variables behave in an inversely manner, with one increasing and the other decreasing, or vice-versa.In the context of this problem, it is found that of the students that take art class, the majority do not play a sport, while among those who do not take art class, the majority play a sport, hence there is a strong and negative association between the two variables.
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The number of algae in a tub in a labratory increases by 10% each hour. The initial population, i.e. the population at t = 0, is 500 algae.(a) Determine a function f(t), which describes the number of algae at a given time t, t in hours.(b) What is the population at t = 2 hours?(c) What is the population at t = 4 hours?
a) Let's say initial population is po and p = p(t) is the function that describes that population at time t. If it increases 10% each hour then we can write:
t = 0
p = po
t = 1
p = po + 0.1 . po
p = (1.1)¹ . po
t = 2
p = 1.1 . (1.1 . po)
p = (1.1)² . po
t = 3
p = (1.1)³ . po
and so on
So it has an exponential growth and we can write the function as follows:
p(t) = po . (1.1)^t
p(t) = 500 . (1.1)^t
Answer: p(t) = 500 . (1.1)^t
b)
We want the population for t = 2 hours, then:
p(t) = 500 . (1.1)^t
p(2) = 500 . (1.1)^2
p(2) = 500 . (1.21)
p(2) = 605
Answer: the population at t = 2 hours is 605 algae.
c)
Let's plug t = 4 in our function again:
p(t) = 500 . (1.1)^t
p(4) = 500 . (1.1)^4
p(4) = 500 . (1.1)² . (1.1)²
p(4) = 500 . (1.21) . (1.21)
p(4) = 500 . (1.21)²
p(4) = 732.05
Answer: the population at t = 4 hours is 732 algae.
a test has 20 Questions worth 100 points the test consists of true or false questions worth 3 points each and multiple choice questions worth 11 points each how many multiple choice questions are on the test
A test is to be conducted with certain types of questions and each type of question weighs certain number of points.
A test would consist of two types of questions. These two types will be assigned variables that will denote the number of questions respectively as follows:
[tex]\begin{gathered} \text{True and False: x} \\ \text{MCQS : y} \end{gathered}[/tex]We are given that the entire test will consits of 20 questions. We can express the total number of questions on the test in terms of number of True and False questions ( x ) and number of MCQS ( y ) as follows:
[tex]\begin{gathered} \text{Total number of Questions = True and False + MCQS} \\ \textcolor{#FF7968}{20}\text{\textcolor{#FF7968}{ = x + y }}\textcolor{#FF7968}{\ldots Eq1} \end{gathered}[/tex]Further information is given to us in the questions regarding the number of points aloted to each type. The total weightage of each type of question on the test can be expressed as a product of ( number of each type * point weight of each type ).
The point weights for each type of questions are:
[tex]\begin{gathered} \text{True and False ( x ) : 3 points each} \\ \text{MCQs ( y ) : 11 points each} \end{gathered}[/tex]The total weights of each types of questions are:
[tex]\begin{gathered} \text{True and False ( points ) = 3}\cdot x \\ \text{MCQS ( points ) = 11}\cdot x \end{gathered}[/tex]We are given that the entire test is worth ( 100 points ). We express the total number of points of the test in terms of total weight of each type of question as follows:
[tex]\begin{gathered} test\text{ points = True and False ( points ) + MCQS ( points )} \\ \textcolor{#FF7968}{100}\text{\textcolor{#FF7968}{ = 3}}\textcolor{#FF7968}{\cdot x}\text{\textcolor{#FF7968}{ + 11}}\textcolor{#FF7968}{\cdot y\ldots}\text{\textcolor{#FF7968}{ Eq2}} \end{gathered}[/tex]We have two equations that express the total number of questions ( Eq 1 ) and total points ( Eq2 ) of the test in terms of number of True and False questions ( x ) and number of MCQs on the test ( y ).
[tex]\begin{gathered} \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ + y = 20 }}\textcolor{#FF7968}{\ldots Eq1} \\ \textcolor{#FF7968}{3x}\text{\textcolor{#FF7968}{ + 11y = 100 }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq2}} \end{gathered}[/tex]We will solve the above two equations simultaneously using Elimination method.
Step1: Multiply Eq1 with ( -3 )
[tex]\begin{gathered} -3\cdot\text{ ( x + y ) = -3}\cdot20 \\ \textcolor{#FF7968}{-3x}\text{\textcolor{#FF7968}{ - 3y = -60 }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq3}} \end{gathered}[/tex]Step2: Add Eq 3 into Eq 2
[tex]\begin{gathered} -3x\text{ - 3y = -60 } \\ 3x\text{ + 11y = 100} \\ =========== \\ 8y\text{ = 40 } \\ \textcolor{#FF7968}{y}\text{\textcolor{#FF7968}{ = 5}} \\ =========== \end{gathered}[/tex]Step3: Back susbtitue the value of ( y ) into ( Eq1 )
[tex]\begin{gathered} x\text{ + ( 5 ) = 20 } \\ \textcolor{#FF7968}{x}\text{\textcolor{#FF7968}{ = 15 }} \end{gathered}[/tex]Therefore, the number of each type of questions that must be put on the test should be.
[tex]\begin{gathered} \text{\textcolor{#FF7968}{True and False ( x ) = 15}} \\ \text{\textcolor{#FF7968}{MCQs ( y ) = 5}} \end{gathered}[/tex]Find the length of the missing side. Round answers to the nearest tenth if necessary. * S sva Your answer
Question:
Solution:
Notice that the angle between the sides of the square is 90 degrees:
Therefore, the angle of the vertex of the triangle measures 45 degrees:
thus, we obtain the following right triangle:
Now, apply the following trigonometric identity:
[tex]\cos \text{ (45) = }\frac{s}{5\sqrt[]{2}}[/tex]solving for s, we get:
[tex]s\text{ = cos(45) . 5 }\sqrt[]{2}\text{ = 5}[/tex]then, we can conclude that the correct answer is:
[tex]s\text{ = 5}[/tex]Express $20.35 as an equation of working h hours, when I equals income
Let
I ------> income in dollars
h -----> number of hours
$20.35 is the hourly pay
so
the linear equation that represent this situation is
I=20.35*hWrite the equation as an exponential equationlog_9(2x – 7) = 2x – 3
Examine this lable of points, which are all on a certain line. 8 What is the slope of this line? Enter your answer as a number, like this 42 Or, if the slope is undefined. enter a lowercase letter "u. like this. u
The formula for determining slope, m is expressed as
slope, m = (y2 - y1)/(x2 - x1)
y1 represents initial value of y
y2 represents final value of y
x1 represents initial value of x
x2 represents final value of x
From the table,
y2 = - 8
y1 = 0
x2 = - 1
x1 = - 5
Slope, m = (0 - - 8)/(- 1 - - 5)
Slope, m = (0 + 8)/(- 1 + 5)
Slope, m = 8/4
Slope = 2
Find the equation of the line. Use exortumbers. st V = 2+ 9 8- 6+ 5+ -4 3+ 2+ 1+ T + -9-8-7-65 2 3 5 6 7 8 9 4 -3 -2 -2 + -3+ -4+ -5* -6+ -7+ -8+
We can see that the line passes by the points (0, -5) & (5, 0), using this information we proceed as follows:
1st: We find the slope(m):
[tex]m=\frac{0+5}{5-0}\Rightarrow m=1[/tex]2nd: We use one of the points from the line and the slope to replace in the following expression:
[tex]y-y_1=m(x-x_1)[/tex]That is (Using point (0, -5):
[tex]y+5=1(x-0)[/tex]Now, we solve for y:
[tex]\Rightarrow y=x-5[/tex]And that is the equation of the line shown.
A long distance runner runs 2⁵ miles one week and 2⁷ miles the next week. How many times farther did he run in the second week than the first week?
Answer:
he ran 96 miles farther in the second week.
Explanation:
Given that A long distance runner runs 2⁵ miles one week;
[tex]2^5miles=2\times2\times2\times2\times2=32miles[/tex]And 2⁷ miles the next week;
[tex]2^7miles=2\times2\times2\times2\times2\times2\times2=128\text{ miles}[/tex]The amount of miles farther he run in the second week than the first week is;
[tex]\begin{gathered} 128-32 \\ =96\text{ miles} \end{gathered}[/tex]Therefore, he ran 96 miles farther in the second week.
Help meeeeeeeee
ASAP
Deena works at a customer service call center. She fields an average of 7 calls per hour. Employees are encouraged to field more than 280 calls per week. Deena has already fielded 112 calls this week.
How many more hours, x, does Deena need to work this week to reach the weekly goal of fielded calls if she continutes to field an average of 7 calls per hour? Select the inequality that includes the fewest number of hours Deena can work this week and still reach the weekly goal.
A.
x > 24
B.
x > 40
C.
x > 3
D.
x > 31
In the circle below, if the measure of arc ACB = 260 °, find the measure of < B.
Given:
There is a figure given in the question as below
Required:
If
[tex]arcACB=260\degree[/tex]than find the value of angle B
Explanation:
Value of arcADB is
[tex]arcADB=360\degree-arcACB=360\degree-260\degree=100\degree[/tex]Now to find the angle B
[tex]\angle B=\frac{1}{2}arcADB=\frac{1}{2}*100=50\degree[/tex]Final answer:
a
what is the x intercepts or zeros for y = x^2 - 6x + 5
Solution:
Given;
[tex]y=x^2-6x+5[/tex]The x-intercepts are the points where y=0.
Thus;
[tex]x^2-6x+5=0[/tex]Thus;
[tex]\begin{gathered} x^2-x-5x+5=0 \\ \\ x(x-1)-5(x-1)=0 \\ \\ x-1=0,x-5=0 \\ \\ x=1,x=5 \end{gathered}[/tex]ANSWER:
[tex]x=1,x=5[/tex]would this be (0, -1) since if b is greater than 1 but it is also -2
The y-intercept is the point where the graph cuts the y-axis. The y-axis is the line x = 0, therefore, to find the y-coordinate of this point we just need to evaluate x = 0 in our function.
[tex]\begin{gathered} y(x)=b^x-2 \\ y(0)=b^0-2 \end{gathered}[/tex]Any nonzero real number raised to the power of zero is one, therefore
[tex]y(0)=b^0-2=1-2=-1[/tex]The y-intercept is (0, -1).
Find the interest odf the loan using banker's ruleP - $350,- = 4.8%, t = 150 days
i = P r T
interest: i
Principal = $350
Interest rate : 4.8% (in decimal form, 4.8/100 = 0.048)
time = t = days/365 = 150/360
Replacing:
i= 350 (0.048) (150/360) = 7
1) f(x) = 60.73(0.95)x2) f(x) = 0.93(60.73)x3) f(x) = 60.04 – 8.25 ln x4) f(x) = 8.25 – 60.04 ln x
A logarithmic function is expressed as
y = a + blnx
We would substitute corresponding values of x and y into the function. This will give us two equations. We would solve the equations for a and b. We have
From the table, when x = 1, y = 60
Thus,
60 = a + b * ln1
60 = a + b * 0
60 = a
when x = 2, y = 54
Thus,
54 = a + bln2
54 = a + 0.693b
Substituting a = 60 into 54 = a + 0.693b, we have
54 = 60 + 0.693b
0.693b = 54 - 60 = - 6
b = - 6/0.693
b = - 8.65
The function would be
f(x) = 60 - 8.65lnx
Suppose you open a bank account and deposit $50. Then, every month you deposit $20. Write anequation that relates the total number of dollars deposited, T, and the month, m.Which equation below relates the total number of dollars deposited, T, and the month, m?
Let:
T = Total number of dollars deposited
m = Number of months
b = Initial deposit
So:
[tex]\begin{gathered} T(m)=20m+b \\ where \\ b=50 \\ so\colon \\ T(m)=20m+50 \end{gathered}[/tex]The frequency distribution of blood groups of a sample of patients was found to be as follows:A 14B 6AB 3O 17The relative frequency of AB in this data is:Group of answer choices7.5%30.033%
we have that
the number of patients is (14+6+3+17)=40
patients AB=3
so
40 -----> 100%
applying proportion
100/40=x/3
x=3*100/40
x=7.5%13(10+2) could be used to simplify which of the following problems?A 013/20)B O13(12)C 0130(26)
Explanation:
The expression is given below as
Which tree is growing faster?Tree 2*Tree 1 is growing1.5 inches everyweek.weeks 1|2|3|4|5inches 45678tallTree ?Tree 1
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the growing rate of the first tree
Tree 1 is growing 1.5 inches every week
STEP 2: Calculate the growing rate of the second tree
This implies the slope and is calculated using the formula;
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]By substitution,
[tex]m=\frac{5-4}{2-1}=\frac{1}{1}=1[/tex]The slope of 1 means that Tree 2 is growing at a rate of 1 inch per week
Hence, the tree that is growing faster is Tree 1 with a rate of 1.5 inches per week
ANSWER:
Tree 1
A is the incenter of Triangle FHG Find the length of AT. Explain your thinking.
we have that
The incenter is the center of the triangle's incircle, the largest circle that will fit
AR=AT=AS -----> radius of the inscribed circle in the triangle
therefore
AT=3 units
Steven read a total of 8 books over 4 months. After belonging to the book club for 7 months,how many books will Steven have read in all?
If he reads 8 books over 4 months it means that he reads 2 books per month. So, if we multiply this ratio by the 7 months we would find that he reads 14 books over 7 months.
The answer is 14 books.
1.5 part 1 question 36 determine whether the graph represent a function explain your answer
Recall that for a graph to correspond to a graph it must pass the vertical line test. The vertical line test consists of drawing vertical lines and if two points of the graph are on the same vertical line then the graph does not represent a function.
Notice the following:
From the above graph, we get that points A B, and C are on the same vertical line, and the same happens for e and f, and m and n. Therefore the graph fails the vertical line test.
Answer: The graph does not represent a function.
1/2+1/9Please help me
If the fraction whose denominator are equal then they will add up
In the given fraction 1/2 +1/9, the denominator of both the fraction 1/2 & 1/9 is not same
so, to make the base same we take the LCM of the 2 & 9
[tex]\begin{gathered} \text{LCM of 2 \& 9 is 18} \\ Si,\text{ the fraction will be :} \\ \frac{1}{2}+\frac{1}{9}=\frac{9+2}{18} \\ \frac{1}{2}+\frac{1}{9}=\frac{11}{18} \end{gathered}[/tex]Answer : 11/18
a) Consider an arithmetic series 4+2+0+(-2)+.....i) What is the first term? And find the common difference d.ii) Find the sum of the first 10 terms S(10).b) Solve [tex] {2}^{x - 3} = 7[/tex]
Answer:
Explanation:
Here, we want to work with an arithmetic series
a) First term
The first term (a) of the arithmetic is the first number on the left
From the question, we can see that this is 4
Hence, 4 is the first term
To find the common difference, we have this as the difference between twwo subsequent terms, going from left to right
We have this as:
[tex]2-4\text{ = 0-2 = -2-0 = -2}[/tex]The common difference d is -2
ii) We want to calculate the sum of the first 10 terms
The formula for this is:
[tex]S(n)\text{ = }\frac{n}{2}(2a\text{ + (n-1)d)}[/tex]Where S(n) is the sum of n terms
n is the number of terms which is 10
a is the first term of the series which is 4
d is the common difference which is -2
Substituting these values, we have it that:
[tex]\begin{gathered} S(10)\text{ = }\frac{10}{2}(2(4)\text{ + (10-1)-2)} \\ \\ S(10)\text{ = 5(8+ (9)(-2))} \\ S(10)\text{ = 5(8-18)} \\ S(10)\text{ = 5(-10)} \\ S(10)\text{ = -50} \end{gathered}[/tex]In the figure below, BAC~QPR. Use this information and the diagram below to name the corresponding parts of the similar triangles
a.
∠A is the right angle of the triangle ABC, so the corresponding angle is ∠P, which is the right angle of the triangle PQR.
b.
BC is the hypotenuse of the triangle ABC, so the corresponding side is QR, which is the hypotenuse of the triangle PQR.
c.
∠C is the smaller angle of the triangle ABC, so the corresponding angle is ∠R.
d.
∠Q is the bigger angle of the triangle PQR, so the corresponding angle is ∠B.
e.
PQ is the smaller leg of the triangle PQR, so the corresponding side is AB.
