The magnitude of electromotive force is 0.13 volt.
We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by
ε = N dΦ / dt
where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.
From the question above, the parameters given are
B1 = 3T
B2 = 6T
dt = 2 s
N = 17
A = 50 cm² = 5 x 10¯³ m²
Find the change in magnetic flux
dΦ = (Φ2 - Φ1)
dΦ = (B2 . A - B1 . A)
dΦ = A (B2 - B1)
dΦ = 5 x 10¯³(6 - 3)
dΦ = 15 x 10¯³ Tm²
By substituting the given parameters, we can calculate electromotive force
ε = N . dΦ / dt
ε = 17 . 15 x 10¯³ / 2
ε = 0.13 volt
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Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
The magnitude and direction of the net force are:
A: the net force is 3N in the downward direction,
B: the net force is zero,
C: The net force is 5N in the downward direction,
D: The net force is 4N in the right direction.
What is the net force?The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.
The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.
The mathematical expression can be written for the net force as:
[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]
For figure (A), the net force is equal to :
F = (2N - 2N) + (2N - 5N) = - 3N
So the magnitude of the force is 3N in the downward direction.
For figure (B), the net force is equal to :
F = (2N - 2N) + (5N - 5N) = 0
So the magnitude of the net force is equal to zero.
For figure (C), the net force is equal to :
F = (5N - 5N) + (5 N) = 5 N
So the magnitude of the net force is 5N in the downward direction.
For figure (D), the net force is equal to :
F = (2N - 2N) + (7N - 3N) = 4N
So the magnitude of the net force is 4N towards the right direction.
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he radius of a circular oil slick expands at a rate of 4 m/min. (a) how fast is the area of the oil slick increasing when the radius is 58 m? (use symbolic notation and fractions where needed.)
It is 24 pi fast area of oil sick increasing when the radius is 60m.
This question we are given the rate of change is the radius T. R. D. T. Is equal to two m per minute. And we know that the area since we're talking about the radius theory of the seco which is pi R squared. And our D A t. R. Would be the first derivative of A. That will be two pi R. And our D A D. T. Would be equal to T. A. T. R. Multiplied by the era T. T. And already we can plug in our numbers. Here we have two pi R. A. Multiplied by two and we get four pi hi and this season meters squared per minute.
Now we want to find the value of our rate of change of area with time At R. A. is equal to 56. And therefore our D. A. T. T. At our escort 56 is equal to four pi my play by 56. And here we get 224 pi square meters per minute. This is our answer to part A no for part B. We are giving that At time is equal to zero is equal to zero. And our rate of change of radius the time is still equal to two meters per minute and Therefore from 0 to 3 we have a tiara Is equal to two d. T. And we integrate Both sides from 0 to 3. So on the left hand side we have our era on the right hand side we have to t From 0 to 3 and here we get six So our radius is six m.
Therefore our D a t t will be a quarter full pie. Sarah it R is equal to six and Plugging. In our 6th year. We have four pay And our era is six. We get 24 pi in this season square meters per minute. That's it. We had them.
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it takes 5 seconds to change his velocity from 30 m/s to 40 m/s, what is his acceleration? 8) jack and tom are skiing down two separate incline planes. jack is a better skier, so he is on the incline making a larger angle to the horizontal. who experiences more acceleration along the slope? (ignore friction)
In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. The acceleration is 8.
What is acceleration?In mechanics, acceleration is the rate at which an object's velocity varies with respect to time. They are vector quantities and accelerations. The acceleration of an object is determined by the direction of the net force acting on it.Acceleration is the rate at which the speed and direction of a moving object change over time. Acceleration is defined as the rate at which something moves faster or slower. Because the direction of motion on a circle changes all the time, even when the speed remains constant.Acceleration is defined as the rate at which velocity changes over time. It is also known as an increase in velocity per second. The SI unit of acceleration is the meter per second squared, abbreviated as ms2.Therefore,
Acceleration = 40/5 = 8
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a satellite moves in a circular earth orbit that has a radius of 8.75 x 106 m. a model airplane is flying on a 20.3-m guideline in a horizontal circle. the guideline is nearly parallel to the ground. find the speed of the plane such that the plane and the satellite have the same centripetal acceleration.
The speed of the plane is 32.519 m/s
Given radius of satellite orbit is [tex]r_{1} = 8.75[/tex] × [tex]10^{6} m[/tex]
Also, Orbital velocity is given by
[tex]v = \sqrt{\frac{GM}{r} }[/tex]
where M is the mass of the earth which is equal to [tex]5.98[/tex] × [tex]10^{24}[/tex] kg
G = [tex]6.67[/tex] × [tex]10^{-11}[/tex]
[tex]v = \sqrt{\frac{(6.67 * 10^{-11} )(5.98*10^{24}) }{8.75 * 10^{6} } }[/tex]
[tex]v=21.35[/tex] × [tex]10^{3}[/tex] m/s
Centripetal acceleration is given as
[tex]a_{c} = \frac{v^{2} }{r}[/tex]
[tex]a_{c} = \frac{(21.35 * 10^{3} )^{2} }{8.75 * 10^{6} }[/tex]
[tex]a_{c} = 52.094 m/s^{2}[/tex]
For model airplane
[tex]a_{c} = \frac{v^{2} }{r}[/tex]
[tex]52.094 = \frac{v^{2} }{20.3}[/tex]
v = 32.519 m/s
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a pellet gun fires ten 3.0 g pellets per second with a speed of 400 m/s. the pellets are stopped by a rigid wall. what is the magnitude of the average force on the wall from the stream of pellets?
Use this diagram to calculate the magnitude of the block's acceleration.
A. 0.50 m/s2
B. 2.0 m/s2
C. 9.8 m/s2
D. 32 m/s2
The mass of the block is 4 kg and the force applied on the block is 8 N. So, the acceleration of the block will be 2 m/s².
What is acceleration?The rate at which an object's velocity varies with respect to time is referred to as acceleration in mechanics. accelerations' magnitude as a vector. Depending on which way the net force is pulling on an object, it will accelerate in that direction.
Acceleration has a magnitude and a direction, making it a vector quantity. Vessel quantities include velocity as well. The definition of acceleration is the change in the vector of velocity over a time interval divided by the time interval.
According to the question, the given values are :
Block mass, m = 4 kg
Force applied on the block, f = 8 N
[tex]Force = mass *acceleration[/tex]
a = 8/4
a = 2m/s².
Hence, the acceleration of the block will be 2m/s².
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A girl on a bridge throws a rock
straight down at -12.5 m/s. It hits
the ground 38.4 m below.
How much time did it take?
(Unit = s)
answer is: 1.80 as time
Vf = -30.1
The time that is taken for the rock to land on the ground from the given height is 1.8 seconds.
What is the time taken?We know that we can be able to obtain the time that have been taken from the equations of kinematics. In this case, we have to consider the equations of kinematics which have occurred under gravity.
Let us recall that we have the fact the equation that ought to be used here is;
h = ut + 1/2gt^2
u = initial velocity
h = the height attained
t = time taken
g = acceleration due to gravity
We know that in this case, we have to use the equations of the kinematics that we can apply to the rock that is moving under the influence of gravity as to obtain the tome that it would take the rock to be able to land on the ground from the height that we have been given in the question.
Having listed out these parameters;
38.4 = -12.5t + (0.5 * 9.8 * t^2)
38.4 = -12.5t + 4.9t^2
Hence;
4.9t^2 - 12.5t + 38.4 = 0
t = 1.80 s
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Your community is considering building a dam on a nearby river to reduce flooding. Would you support this proposal? Explain
Yes I would support the proposal of building a dam on a nearby river to reduce flooding.
What is flooding?Flooding is defined as the over spreading of water beyond the banks of a water body or the covering of a large area of land with uncontrolled flow of water.
A dam is a structure that is usually constructed over a flowing water body such as a river, to withhold water which can be diverted for the generation of electricity.
The construction of dam over a water body that usually overflows and floods an area can help control water spread as it's diverts the excess water for other purposes.
Therefore, I would support the proposal that a dam on the nearby river should be constructed.
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two boys hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angle of 30 degree above the horizontal. one boy, with a mass of 50.00 kg, is hanging 1.40 m along the branch from the tree trunk. the other boy, with a mass of 33.00 kg, is hanging 2.10 m from the tree trunk. what is the magnitude of the net torque exerted on the branch by the children? assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.
Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
Calculation Magnitude?Magnitude offers products that automate and provide insights throughout the whole supply chain. Determine and emphasize any bottlenecks, potential delays, and urgent.
The size of the undertaking would have discouraged a regular man due to its importance.
Magnitude is a way to gauge a star's brightness.
inclination of tree from horizontal =30°
mass of first child m[tex]1[/tex]=50kg
distance of first child r[tex]1[/tex]=1.4
mass of first child m[tex]2[/tex]=33kg
distance of first child r[tex]2[/tex]=2.10
Torque exerted by first child
T[tex]1[/tex]=m[tex]1[/tex] cos 0*r1
T1=50*9.8 cos27*2*1.4
=489.7513N-M
Torque exerted by second child
T2=m2 cos0*r2
T2=33 *9.8cos27*2
=292.7374
Both torques are in same sense therefore
T[tex]net[/tex]=T1+T2
T[tex]net[/tex]=489.75+292.73
T[tex]net[/tex]=782.48N-m
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7. Using Analogies Explain how the behavior
of popcorn in a popcorn popper can be used
as an analogy for the motion of gas particles.
The relative motion of gaseous particles increases with increase in the temperature of the gas molecules just like the motion of popcorn in a popper increases when heat is applied to the popper.
What is kinetic theory of gas?The kinetic theory of gases or matter states that matter consists of tiny particles which are constant motion, colliding with one another and with walls of the containing vessels.
Just like a popcorn in a popcorn popper pops when heat is applied to the popper, gases contained in a cylinder increases their speed when they acquire more kinetic energy as the temperature of the cylinder increases.
Thus, the motion of gas particles depends on the temperature of the containing vessel so also does the random motion of popcorn depends on the temperature of the popper.
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you press a book perpendicularly against a vertical wall with a force of 27 n . the coefficient of static friction is 0.70 between your hand and the book and 0.50 between the book and the wall. what is the maximum book mass you can hold this way and keep from slipping?
1.926kg is the maximum book mass you can hold this way and keep from slipping.
This book with 27 N, so Normal rection force N = 27N.
let mass of brook = m Kg
here gravitational force acting downwards which tend book to more downwards and frictional force moving is acting vertically upwards to held
frictional force a must be equal to gravitational force here frictional force
fr = μN
so for body to be rest fr = mg
μN = mx 9.81
m = μN / 9.81
here maximum value of coefficient static friction μ = 0.70
m = 0.70x 27/9.81
m = 1.926kg
What is frictional force?
Friction is the force that opposes motion when the surface of one object comes into contact with the surface of another. The mechanical advantage of the machine is reduced by friction, in other words, the ratio of power to input decreases due to friction. A car uses a quarter of its energy to limit friction. However, the friction of the tires also allows the car to stay on the road, and the friction of the clutch allows it to drive. From matches to machines and molecular structures, friction is one of the most important phenomena in the physical world.
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A spring scale is a device that uses a spring with a known spring constant to measure the weight of objects. You have a spring scale with a spring constant of 13 Nm. How much will the spring stretch when a 12-N weight is hung from one end?
Answer:
It would stretch about 6 inches, but it depends on the metal.
Explanation:
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supppose object a has double the specific heat and triple the mass of object b. if the same amount of heat is applied to both objects, how will the temperature changes of a be related to the temperature change of b?
The given problem is related to the calorimetry. The definition of calorimetry states that, "Calorimetry is the science of determining the change in energy of a system by measuring the heat exchange of the system with the surroundings". According to this, the temperature change of A will be one sixth of the temperature change of B. Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Temperature change of A related to the temperature change of B
In this case, for object A:
QA = cA× mA× (ΔT)A
and for object B:
QB = cB× mB× (ΔT)B
You know:
Object A has double the specific heat of object B. ⇒ cA= 2× cB
Object A has triple the mass of object B. ⇒ mA= 3× mB
If the same amount of heat is applied to both objects ⇒ QA= QB
Then:
cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B
2× cB × 3× mB× (ΔT)A= cB× mB× (ΔT)B
Solving:
6× cB × mB× (ΔT)A= cB× mB× (ΔT)B
(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)
(ΔT)A= (ΔT)B
Finally, the temperature change of A will be one sixth of the temperature change of B.
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A ball is shot 58m/s at 40 degrees to the ground. What is the magnitude of the vertical component of the velocity of the plane?
The magnitude of vertical component of the velocity of the plane when a ball is shot 58 m/s at 40 degree to the ground is 37.28 m/s.
What is velocity?
Velocity can be defined as the rate of change of displacement, The S.I unit of velocity is m/s.
To calculate the magnitude of the vertical component of the velocity, we use the formula below.
Formula:
Vy = Vsin∅.............. Equation 1Where:
Vy = Vertical component of the velocityV = Velocity of the ball∅ = Angle the ball makes with the groundFrom the question,
Given:
V = 58 m/s∅ = 40°Substitute these values into equation 1
Vy = 58(sin40°)Vy = 58×0.6428Vy = 37.28 m/sHence, The magnitude of the vertical component of the velocity is 37.28 m/s.
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Help show how you got answers
The speed at which a wave of frequency of 14 Hz and a wavelength of 3 m will travel is 42 m / s
v = λ / T
f = 1 / T
v = f λ
v = Wave speed
λ = Wavelength
T = Time period
f = Frequency
f = 14 Hz
λ = 3 m
v = 14 * 3
v = 42 m / s
Frequency is the number of time an event occurs repeatedly in an unit amount of time. Its unit is hertz which in terms of SI unit is [tex]s^{-1}[/tex].
Therefore, the speed at which the wave will travel is 42 m / s
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take the mass of the earth to be 5.974x1024 kg, the mass of the sun to be 1.989x1030 kg, the radius of the earth to be 6.378x106 m, and the distance from the (surface of the) earth to the (center of the) sun to be 1.49x1011 m. what is the gravitational force of the sun on the earth? enter your answer to three significant figures.
The magnitude of the Gravitational Force between the Sun and The earth is nearly 3.557 x 10²² Newtons.
The total gravitational force between two objects is given by the formula,
F = GMm/R²
G is the universal gravitational constant and it's value is 6.67408x10⁻¹¹
M is the mass of one body,
m is the mass of the other body,
R is the centre to centre distance between the two objects,
Here,
Mass of sun is 1.989x10³⁰ kg and the mass of earth is 5.974x10²⁴.
The centre to centre distance R of sun and earth = (Radius of earth + distance between the sun's centre and earth's surface)
So,
R = (1.49x10¹¹ + 6.378x10⁶)m
Now, putting all the values in the formula,
F = (6.67408x10⁻¹¹)(1.989x10³⁰)(5.974x10²⁴)/(1.49x10¹¹ + 6.378x10⁶)²
Solving further,
F = 3.557 x 10²²N
So, the gravitational force between sun and earth is 3.557 x 10²²N.
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When a red light with a wavelength of 670 nm shines on a piece of metal, an electron is ejected. What is the energy of the photon absorbed by the electron to overcome the attractive forces?.
The energy of the photon of light as we can see here is 2.9 * 10-19 J.
What is the energy of the light?We know that light has to do with any of the components of the electromagnetic spectrum. These are the kinds of radiation that are able to pass through vacuum because they do not need a medium for the propagation of the wave. We are now asked to obtain the energy of the photon based in the wavelength that we have been supplied in the question here.
We have that the wavelength of the photon from what we can see in the question have been given as 670 nm. Then;
E = hc/λ
E = energy of the light
h = Plank's constant
c = speed of light
λ = wavelength of the light
It then follows that;
E = 6.6 * 10^-34 * 3 * 10^8/670 * 10^-9
E = 2.9 * 10-19 J
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a wire having mass per unit length of 0.460 g/cm carries a 2.12 a current horizontally to the south. what are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward? magnitude
The direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward is clock wise direction and 0.245T.
What is a magnetic field?The magnetic field is the area that is affected by magnetism and is located around a magnet. The magnetic field is a valuable tool for explaining the distribution of the magnetic force within and around a magnetic object in nature.
The mass per unit length of the wire = 0.460 g/cm = 0.046 kg/m
Current in the wire, A = 2.12 A (due south)
To find,
The minimal magnetic field's magnitude as well as its direction.
F = ILB = mg
B = mg/IL
B = 0.046 × 9.8 /2
B = 0.225T
B = 0.245T.
The right hand rule specifies the magnetic field's direction, which is clockwise around the wire.
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describe the forces that are acting on the cake as it falls and when it lands on the ground.
Answer:
gravitational force
Explanation:
expressed the weight of the object.
When the cake falls into the ground gravitational force and electromagnetic forces are working on it and when it lands on the ground gravitational, electromagnetic and normal force act on it.
What is Force?Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.
Two fundamental forces are at play while the ball falls: gravity, which causes the ball to descend, and electromagnetic forces, which causes the ball to interact with the air.
The gravity force still affects the ball when it strikes the ground, but it is less significant than the electromagnetic force generated by the earth and the ball itself. The deformation and restoration of the ball's shape are caused by the EM (electromagnetic) inside the ball. The ball stops descending due to the EM force with the earth.
So the simple answer is consistent with the other answers here: the electromagnetic force is responsible for the force between the ball and the ground.
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1. A vector of 15 units acts to the left, and a vector of 3 units acts to the right. What is the resultant?
Answer: 12
Explanation:
The resultant vector is 12 unit.
What is addition of two vector?When two vectors point in the same direction, their sum is equal to the total of their respective magnitudes pointing in the same direction.
When two vectors are pointed in opposite directions, the resultant vector is pointed in the direction of the larger vector and is equal to the difference between their magnitudes.
Here, one vector of 15 unit is acting to the left and another vector of 3 unit acting rightwards. As they are acting in opposite direction, vector summation of two vector will be equal to the value of subs traction of their magnitude.
So, Resultant vector= 15 unit + (-3 unit)
= 15 unit - 3 unit
= 12 unit.
Hence, the resultant vector will be 12 unit.
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an engine flywheel initially rotates counterclockwise at 6.75 rotations/s. then, during 23.1 s, its rotation rate changes to 2.97 rotations/s clockwise. find the flywheel's average angular acceleration (including its sign) in radians per second squared. define counterclockwise rotation as positive
Flywheel's average angular acceleration is +0.42 radian per second square.
Angular acceleration is the rate of change of angular velocity and is denoted by "a".
Rate at which an object revolves or rotates about an axis is known as angular velocity and is denoted by "w".
Initial Angular velocity is denoted as w1 and final angular velocity is denoted as w2.
So, according to the equation of rotational motion,
w2= w1+at
Where t is the time
When we put the values given in this equation
= +2.97= -6.75+ a×23.1
= +2.97+6.75=a×23.1
= 9.72= 23.1×a
So, a= +0.42
Rate of change of angular velocity of flywheel is +0.42.
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The main engine of an ariane v rocket produces a thrust of 1015 kN and it’s booster rockets produce a total thrust of 13300 kN. If it has a launch mass of 780 tonnes, calculate its initial acceleration.
The initial acceleration of the rocket at the given thrust is 1.3 m/s².
What is the initial acceleration of the rocket?
The initial acceleration of the rocket is determined by Newton's second law of motion. This law states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
where;
F is the applied forcem is the mass of the rocketa is the accelerationThe initial lunch force = 1015 kN = 1,015,000 N
The mass of the rocket = 780 tonnes = 780,000 kg
a = F/m
a = (1,015,000) / (780,000)
a = 1.3 m/s²
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Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2
We will have the following:
1. 143 g = 0.143 kg:
[tex]F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N[/tex]2. 110 g = 0.110 kg:
[tex]F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N[/tex]3. 410 g = 0.410 kg:
[tex]F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N[/tex]4. 46 g = 0.046 kg:
[tex]F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N[/tex]From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.
a rock of mass m is released from rest above an airless spherical planet of mass m and radius r. the rock is released from a height r above the surface of the planet (a distance 2r from the center of the planet). what is the correct expression for the final kinetic energy of the rock just before it hits the surface of the planet?
E1 = [tex]E_{f}[/tex]
[tex]\frac{-GMM}{2R}[/tex] = [tex]\frac{-GMM}{R}[/tex] + [tex]\frac{1}{2} mv^{2}[/tex]
= [tex]\frac{GMM}{2R}[/tex] = [tex]\frac{1}{2} mv^{2}[/tex]
V = [tex]\sqrt{GM/R[/tex]
By the law of conservation of energy, the initial potential energy, and the final kinetic energy are equal. When an object hits the ground, its kinetic energy is converted into heat and sound energy. Energy from motion is called kinetic energy. object in motion.
Both vertical and horizontal movement has kinetic energy. Kinetic energy depends on the mass and velocity of the object. The basic reason for the existence of halves in the kinetic energy formula actually comes from special relativity from a more complete version of the kinetic energy formula. Briefly, this ½mv2 kinetic energy formula can be viewed as an approximation of special relativity.
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It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration?
Given:
The angular displacement, θ=89.5°
Initial angular velocity, ω₀=47.8 rpm
Final angular velocity, ω=0 rad/s
To find:
The angular acceleration of the wheel.
Explanation:
The angular velocity can be converted to rad/s as,
[tex]\begin{gathered} \omega_0=\frac{47.8\times2\pi}{60} \\ =5\text{ rad/s} \end{gathered}[/tex]The angle is converted into the radians as,
[tex]\begin{gathered} \theta=\frac{89.5\times\pi}{180} \\ =1.56\text{ rad} \end{gathered}[/tex]From the equation of motion,
[tex]\omega^2-\omega^2=2\alpha\theta[/tex]Where α is the angular acceleration of the wheel.
On substituting the known values,
[tex]\begin{gathered} 0^2-5^2=2\times\alpha\times1.56 \\ \implies\alpha=\frac{-5^2}{2\times1.56} \\ =-8.01\text{ rad/s}^2 \end{gathered}[/tex]Final answer:
Thus the angular acceleration of the wheel is -8.01 rad/s²
It doesn't need arto lift off
4. What forces are acting on a book sitting on a table? Are action-reaction forces involved
in this situation?
5. If two people each standing on a scooter board push off of each other what happens
(relate to Newton's Third Law)?
6. In # 5 how would the distance moved by the scooter boards compare if one person had a
lot more mass than the other person?
7. If a person standing on a scooter board pushes off of a wall, what happens? Can this
situation be explained in terms of Newton's Third Law (action-reaction)?
8. How is shooting a shotgun related to Newton's Third Law?
9. Why does a rifle have less "kick" than a shotgun?
They will go off in opposite directions with the same force.
What is Newton's third law?
Newton's third law states that if object A exerts a force on object B, then object B must apply a force to object A that is equal in magnitude and directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.
Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.
Person is exiting for (describe in Newton's third law) against the wall that then has an effect on the person pushing them bac
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If a person standing on a scooter board pushes off of a wall, what happens? Can this
situation be explained in terms of Newton's Third Law (action-reaction)?
solve for x: |2x + 6| − 4 = 20 Group of answer choicesx = 9 and x = 11x = −9 and x = 15x = 9 and x = −15No solution
Given,
[tex]|2x+6|-4=20[/tex]On simplifying,
[tex]\begin{gathered} |2x+6|=20+4 \\ \Rightarrow|2x+6|=24 \\ 2x+6=\pm24 \end{gathered}[/tex]Thus,
[tex]\begin{gathered} 2x=+24-6 \\ \Rightarrow x=\frac{18}{2} \\ =9 \end{gathered}[/tex]Or
[tex]\begin{gathered} 2x=-24-6 \\ x=\frac{-30}{2} \\ =-15 \end{gathered}[/tex]Thus, x=9 and x=-15
Therefore the correct answer is the third option
a rocket accelerates vertically upward from rest with acceleration a. after 4.0 s, a small object falls from the rocket. the object strikes the ground 6.0 s later. determine the acceleration of the rocket in terms of g.
Answer:
(9/4)g
Explanation:
The distance the rocket travels is given by:
D = v*t + 1/2*a*t^2. Where v is the initial velocity, t is time, and a is the acceleration. We don;t have the distance nor the acceleration, so the best we can do is rearrange for distance, D, since we we will be able to calculate that with information about the falling rocket.
D =(1/2)a(4)^2
D = 8a
If we find D, we can calculate a, the acceleration of the rocket.
--
We are told the rocket takes 8 seconds to fall from height D, The relationship between distance and time with a falling object with force g (earth;s gravity) is:
D = v*t + 1/2*a*t^2
The initial velocity is 0 (rocket turns), the force is g, gravity, and time is 6 seconds, We can set that to the distance calculated in the first step: 8a
8a = 0*t + 1/2*g*(6)^2
8a = 1/2*g*36
a = (36/16)g
a = (9/4)g
The rocket's acceleration was (9/4)g
To which category does galaxy #2 belong? Why does it belong in this category?
Galaxy #2 belongs to spiral. This is because it has a bulge at the centre, a disk as well as the curved arms. Contains both Young and Old stars - contains gas and dust - contains more red giants and red supergiant's than disk - some regular rotation about centre.
What Is Dark Matter?Dark matter is a form of matter thought to account for approximately 85% of the matter in the world. Dark matter consists of particles that do not absorb, reflect or emit light, so they cannot be detected by observing electromagnetic radiation. Dark matter is material that cannot be directly seen. We know dark matter exists because it affects objects we can directly observe.
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a pipe that is 0.46 m long and open at both ends vibrates in the second overtone with a frequency of 1150 hz. in this situation, the distance from the center of the pipe to the nearest antinode is closest to group of answer choices zero. 7.7 cm. 15 cm. 12 cm. 3.8 cm.
The distance of the center pipe to the nearest antinode at the second harmonic frequency is closest to 12 cm.
We need to know about the harmonic frequency to solve this problem. When the string is vibrating at its second harmonic frequency, it should follow the rule
λ = L
where λ is wavelength and L is the length of the string
From the question above, we know that
f = 1150 Hz
L = 0.46 cm
Find the wavelength
λ = L
λ = 0.46 m
The distance from the center of the pipe to the nearest antidote is equal to 1/4 of the wavelength. Hence,
s = 1/4 λ
s = 1/4 . 0.46
s = 0.115 m
s ~ 12 cm
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