Given,
The expression is,
[tex]\lbrace x|x\ge-3\rbrace[/tex]Required:
The graph of the line.
The interval notation is [-3, infinity).
The line of the inequality is,
Hence, the graph of the line is obtained.
which statement is true of the system of equations shown below
3x + 7y= 14
3x+7y= 10
Subtract the second equation to the first.
3x +7y= 14
-
3x + 7y= 10
_________
0x +0y = 4
0 = 4
0 is no
I need help with this practice Having trouble solving it The subject is trigonometry
To solve the problem, we will make use of the identity:
[tex]\cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{}[/tex]ANGLE α
The angle lies in the second quadrant. The only positive ratio is the sine.
If we have that:
[tex]\tan \alpha=-\frac{12}{5}[/tex]Displaying this on a triangle for ease of working, we have:
Therefore, the length of the hypotenuse will be:
[tex]\begin{gathered} x=\sqrt[]{12^2+5^2}=\sqrt[]{144+25}=\sqrt[]{169} \\ x=13 \end{gathered}[/tex]Therefore, we have that:
[tex]\begin{gathered} \sin \alpha=\frac{12}{13} \\ \cos \alpha=-\frac{5}{13} \end{gathered}[/tex]ANGLE β
This angle lies in the fourth quadrant. Only the cosine ratio is positive in this quadrant.
We are given in the question:
[tex]\cos \beta=\frac{3}{5}[/tex]Displaying this on a triangle for ease of working, we have:
Therefore, using the Pythagorean Triplets, we have that:
[tex]y=4[/tex]Therefore, we have that:
[tex]\sin \beta=-\frac{4}{5}[/tex]SOLVING THE IDENTITY
Applying the identity quoted earlier, we have:
[tex]\begin{gathered} \cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{} \\ \cos (\alpha-\beta)=(-\frac{5}{13})(\frac{3}{5})+(\frac{12}{13})(-\frac{4}{5}) \\ \cos (\alpha-\beta)=-\frac{63}{65} \end{gathered}[/tex]Find the annual fixed expense for car insurance if John makes
six payments in a year at $174.45 each?
The annual fixed expense for car insurance is $ 1,046.70.
It is given in the question that John makes six payments in a year at $174.45 each.
We have to find the annual fixed expense for car insurance.
We know that,
The annual fixed expense for the car insurance will be 6 times the individual payment given in the question.
Hence, by simple multiplication, we can write,
Annual fixed expense for the car insurance = 6*174.45 = $ 1,046.70
Car insurance
Car insurance is a type of financial protection that covers the cost of another driver’s medical bills and repairs if you cause an accident with your car, or in case your car is stolen or damaged some other way.
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what is the range of the number of goals scored?
The minimum number of goals scored is 0 and maximum number of goals scored is 7. The range is equal to difference between maximum number of goals and minimum number of goals.
Determine the range for the goals scored.
[tex]\begin{gathered} R=7-0 \\ =7 \end{gathered}[/tex]So answer is 7.
a. What is the value of f(1.2)?f(1.2) =b. What is the largest value of x for which f(x) = 1.5?x =
In order to find the value of f(1.2), we just need to find the value of f(x) in the graph that corresponds to x = 1.2.
Looking at the graph, when x = 1.2, the function f(x) is equal to 2.
Then, to find the largest value of x for which f(x) = 1.5, we look for the value 1.5 in the vertical axis, then find the corresponding value of x.
For this value, we have two possible values of x: 1.2 and 3.6.
So the largest value is x = 3.6
There are 2 liters of soda left after a class party. Laura, Gavin, Anita, Emmett, and Rebecca are on the clean-up crew, and decide to split the soda equally.
How much soda does each student get?
Write your answer as a proper fraction or mixed number.
0.4 liters or 2/5
Step-by-step explanation:
Dividing the soda equally, Each student would get 0.4 liters or 2/5
A choir concert platform consists of 6 rows. The number of performers increases by 2 witheach successive row. How many performers are there in all if the back row has 36performers?A 48B 84C 186D 372
In this problem, we have the sequence
inverse sequence
36,34,32,30,28,26
The sum is equal to
S=36+34+32+30+28+26
S=186
The answer is option CIn this problem, we have the sequence
inverse sequence
36,34,32,30,28,26
The sum is equal to
S=36+34+32+30+28+26
S=186
The answer is option C7 1/3 × 2 2/11 3/5 × 6 2/34 1/5 × 1 1/14
It is easier to perform the operations if you convert the mixed fractions into improper fractions.
For point 1. Make the mixed fractions improper first
[tex]7\frac{1}{3}=\frac{3\cdot7+1}{3}=\frac{21+1}{3}=\frac{22}{3}[/tex][tex]2\frac{2}{11}=\frac{11\cdot2+2}{11}=\frac{22+2}{11}=\frac{24}{11}[/tex]Now, the multiplication of fractions is done like this
[tex]\frac{a}{b}\cdot\frac{c}{d}=\frac{a\cdot c}{b\cdot d}[/tex]Then, you have
[tex]7\frac{1}{3}\cdot2\frac{2}{11}=\frac{22}{3}\cdot\frac{24}{11}=\frac{528}{33}=16[/tex]For point 2.
[tex]6\frac{2}{3}=\frac{3\cdot6+2}{3}=\frac{18+2}{3}=\frac{20}{3}[/tex]Now multiplying the improper fractions you have
[tex]\frac{3}{5}\cdot6\frac{2}{3}=\frac{3}{5}\cdot\frac{20}{3}=\frac{60}{15}=4[/tex]Finally for point 3.
[tex]4\frac{1}{5}=\frac{5\cdot4+1}{5}=\frac{20+1}{5}=\frac{21}{5}[/tex][tex]1\frac{1}{14}=\frac{14\cdot1+1}{14}=\frac{14+1}{14}=\frac{15}{14}[/tex]Now multiplying the improper fractions you have
[tex]\begin{gathered} 4\frac{1}{5}\cdot1\frac{1}{14}=\frac{21}{5}\cdot\frac{15}{14}=\frac{315}{70}=\frac{35\cdot9}{35\cdot2}=\frac{9}{2} \\ 4\frac{1}{5}\cdot1\frac{1}{14}=\frac{9}{2} \end{gathered}[/tex]Dante is arranging 11 cans of food in a row on a shelf. He has 7 cans of beans, 3 cans of peas, and 1 can of carrots. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical (not distinct)?
Given:
The number of cans of food =11
The number of cans of beans=7
the number of cans of peas=3
the number of cans of carrots=1
Condition : two cans of the same food are considered identical.
To arrange the n objects in order,
[tex]\begin{gathered} \text{Number of ways= }\frac{n!}{r_1!r_2!r_3!} \\ =\frac{11!}{7!3!1!} \\ =\frac{39916800}{30240} \\ =1320 \end{gathered}[/tex]Answer: the number of ways are 1320.
4 boxes of crayons cost $12.50 How much would 16 boxes cost? (Show work) Thank you!
Answer:
$50.08
Step-by-step explanation:
Find the unit rate.
[tex]\frac{12.50}{4}[/tex] Each box cost $3.125. We cannot have .125 cents, so round up to 3.13
3.13 x 16 = $50.08
A particular lawn requires 6 bags of fertilizer. A lawn next door requires 4 bags of fertilizer. How big is the lawn next door?A. 10 feet square feetB. 24 feet square feetC. 50 feet square feetD. Not enough information is given
Answer:
D. Not enough information is given
Explanation:
To know the size of the lawn next door, we would need a relation between the square feet and the number of bags of fertilizer.
Since all we know is the bags of fertilizer for the particular lawn and the lawn next door, we can say that we didn't have enough information to answer the question.
Therefore, the answer is:
D. Not enough information is given
You start at (9,2). you move left 9 units. where do you end
If you start at (9,2) and then move left 9 units, you'll end up at (0, 2)
l show how the distributive property can make the arithmetic simpler in the following problems5(108)
Firstly Example of Distributive property can be shown below.
GIiven: 6(9 - 4)
6 x 9 - 6 x 4
54 - 24 = 30
a) 3(50.15)
3(50 + 0.15)
3x50 + 3 x0.15
150 + 0.45 = 150.45
(b) 5(108)
5(100 + 8)
5x100 + 5x8
500 + 40 = 540
find the values of x and y that maximize the objective function c = 3x + 4y for the graph
Answer: The correct answer is x=0 and y=4 or (0,4) per the graph
Step-by-step explanation:
To find the maximum value, we must test each point using the equation:
Check for (0,4):
C=3x+4y
C=3(0)+4(4)
C=16
Check for (2,2):
C=3(2)+4(2)
C=6+8
C=14
Check for (4,0):
C=3(4)+4(0)
C=12
Answer:
Step-by-step explanation:
help meeeeeeeeee pleaseee !!!!!
The value of the composition (g ° f) (x) between the linear equation g(x) and the quadratic equation f(x) evaluated at x = 5 is equal to 6.
How to find and evaluate a composition between two functions
In this problem we find a quadratic equation f(x) and a linear equation g(x), of which we must derive a composition consisting in substituting the input variable of the linear equation with the quadratic equation. Later, we evaluate the resulting expression at x = 5.
Now we present the complete procedure:
(g ° f) (x) = - 2 · (x² - 6 · x + 2)
(g ° f) (x) = - 2 · x² + 12 · x - 4
(g ° f) (5) = - 2 · 5² + 12 · 5 - 4
(g ° f) (5) = - 50 + 60 - 4
(g ° f) (5) = 6
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the scale of a map is 1cm: 7milesthe distance between two cities is 102.2 miles.find the distance between the two cities on the map
Ok, so:
We know that the scale given is the next one:
1cm = 7miles.
Now, let me draw something here below:
So, the cities are separated by a distance of 102.2 miles.
If 1 cm = 7 miles,
Then, we're going to convert 102.2 miles to our map scale.
102.2 miles * ( 1cm / 7 miles).
And we obtain:
14.6cm
Write an equation for a rational function with:
Vertical asymptotes at x = -5 and x =
-6
x intercepts at x = -3 and x = -4
y intercept at 4
Equation for a rational function is 10(x2 + 7x + 12) / (x2 + 11x + 30) = 0.
What is Rational Function?
Any function that can be expressed mathematically as a rational fraction—an algebraic fraction in which both the numerator and the denominator are polynomials—is referred to as a rational function. The polynomials' coefficients don't have to be rational numbers; they can be found in any field K.
So this will be a rational function with the vertical asymptotes given by the denominators:
(x + 5) and (x + 6).
The x-intercepts will be provided by the numerator,
which will be:
a(x + 3)(x + 4)
The letter an is a constant.
Given that (0,4) is the y intercept, we have:
4 = a(0+3)(0+4) / (0+5)(0+6)
4= 12a / 30
12a = 120
now,
a = 120/12,
a = 10,
and a = 1.
Now,
a(x+3)(x+4) / (x+5)(x+6) = 0
10 (x^2 + 7x + 12) / (x^2 + 11x + 30) = 0
Hence, We have the following equation for a rational function:
10 (x2 + 7x + 12) / (x2 + 11x + 30) = 0.
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f(t) = 2t-3g(t) = t^3 + tFind (f •g)(0)
1) Given those functions, f(t) and g(t) let's find the composite function, for (f(g(0)) or (f •g)(0)
2) Let's pick the function f(t)
f(t) = 2t-3
And plug into that g(t), like this
f(g(t))= 2(t³ +t) -3
3) Finally, let's plug the value 0 into that composite function:
f(g(t))= 2(t³ +t) -3
f(g(0))= 2(0³ +0) -3 ⇒f(g(0))= 2(0) +3
f(g(0))= 3
(f •g)(0)=3
The total fixed costs of producing a product is $36,000 and the variable cost is $124 per item. If the company believes they can sell 1,800 items at $170 each, what is thebreak-even point?667 items695 items705 items783 itemsNone of these choices are correct.
When finding the height of a triangle, you need to find the equation of the lineperpendicular to the base of the triangle that passes through the vertex opposite thebase and then find the point of the intersection of the base and the perpendicular line. True Or False?
EXPLANATION:
Given;
We are given the step by step procedure to find the height of a triangle.
Required;
We are required to determine if the step by step solution is true or false.
Solution/Explanation;
When finding the height of a triangle, we may use the Pythagoras theorem or we may use trigonometric ratios for right angled triangles.
Note that the Pythagoras' theorem is also used only for right angled triangles and one of the three sides will be the height of the triangle.
When required to calculate the the height of a triangle given a line perpendicular to the base (that is, at a 90 degree angle with the base), and passing through the vertex opposite the base, the triangle can be effectively split into two parts along the perpendicular and the perpendicular line will then become the height. Also depending on the amount of information available, we may use the Pythagoras' theorem (if the other two sides are given). Alternatively we may use the trigonometric ratios if one other side and one of the angles is given.
Therefore,
ANSWER:
FALSE
express the quadratic function f(x)=3x^2 + 6x - 2 in the form a(x + h)^2 + k where a,h and k are constants
Answer:
Explanation:
Given:
[tex]f(x)=3x^2+6x-2[/tex]First, we do completing the square on the given function to express it into vertex form. So,
We write it in the form:
[tex]\begin{gathered} x^2+2ax+a^2 \\ \end{gathered}[/tex]And, factor out 3: So,
[tex]\begin{gathered} 3(x^2+2x-\frac{2}{3}) \\ \text{where:} \\ 2a=2\text{ or a=1} \\ \text{Hence} \\ 3(x^2-2x-\frac{2}{3}+1^2-1^2) \end{gathered}[/tex]Since:
[tex]\begin{gathered} x^2+2ax+a^2=(x+a)^2 \\ So, \\ x^2+2x+1^2=(x+1)^2 \end{gathered}[/tex]Then,
[tex]\begin{gathered} 3(x^2-2x-\frac{2}{3}+1^2-1^2) \\ =3((x+1)^2-\frac{2}{3}-1^2) \\ \text{Simplify} \\ f(x)=3(x+1)^2-2-3 \\ f(x)=3(x+1)^2-5 \end{gathered}[/tex]Therefore, the answer is:
[tex]f(x)=3(x+1)^2-5[/tex]Find the equation of the line described. Write your answer in standard form. Vertical and containing (10,14)
We have here a special case where the line is vertical. In this case, the line has an "infinite" slope (or it is not defined). Therefore, since the line is vertical and contains the point (10, 14), the line is given by the equation:
[tex]x=10[/tex]The standard form of the line is given by the general equation:
[tex]Ax+By=C[/tex]Then, we can rewrite the equation as follows:
[tex]x+0y=10[/tex]We can see that this line contains the point (10,14):
We can see that the vertical line, x + 0y = 10 passes through the point (10, 14).
In summary, the line is given by x + 0y = 10 (A = 1, B = 0, C = 10).
what is[tex](6 {x}^{2} - 13x + 5) [/tex]divided by[tex](2x - 1)[/tex]
1. Divide the first term of the dividend into the first term of the divisor:
[tex]\frac{6x^2}{2x}=3x[/tex]2. Multiply the result above by the divisor:
[tex]3x(2x+1)=6x^2+3x[/tex]3. Subtract the result above from the divident to get a new polynomial:
4. Repeat the process with the new polynomial:
[tex]\begin{gathered} -\frac{16x}{2x}=-8 \\ \\ -8(2x+1)=-16x-8 \end{gathered}[/tex]Then, the result of the division is:[tex]\frac{6x^2-13x+5}{2x+1}=3x-8+\frac{13}{2x+1}[/tex]Use the graph below to answer the following questionsnegative sine graph with local maxima at about (-3,55) and local minima at (3,55)1. Estimate the intervals where the function is increasing.2. Estimate the intervals where the function is decreasing.3. Estimate the local extrema.4. Estimate the domain and range of this graph.
Answer:
1. Increasing on ( -inf, -3] and ( 3, inf)
2. decreasing on (-3, 3]
3. Local maximum: 60, Local minimum: -60
4. Domain: (-inf , inf)
Range: [-60, 60]
Explanation:
1.
A function is increasing when its slope is positive. Now, in our case we can see that the slope of f(x) is postive from - infinity to -3 and then it is negatvie from -3 to 3; it again increasing from 3 to infinity.
Therefore, we c
A pool is filled to 3/4 of its capacity 1/9 of water in the pool, evaporates. If the pool can hold 24,000 gallons when it is full, how many gallons of water will have to be added in order to fill the pool?A. 6,000B. 8,000C.12,000D.16,000
First, the pool was filled to 3/4 of its capacity, which is equal to:
[tex]24000\cdot\frac{3}{4}gal=18000gal.[/tex]Then, 1/9 of the water evaporated remaining 8/9 of the 18000 gal:
[tex]18000\text{gal}\frac{8}{9}=16000gal.[/tex]Therefore, to fill the pool we need to add:
[tex]24000-16000[/tex]gallons of water.
Answer: B. 8000.
in CDE, J is the centroid. If DH=72 find DJ
Answer:
DJ = 24
Explanation:
We are told from the question that J is the centroid of CDE, this means that J is the midpoint of DH, CJ and FE
If J is the centroid of DH, then 2DJ = JH
Also DJ + JH = DH
The equation becomes:
DJ + 2DJ = DH
3DJ= DH
Given
DH = 72
Hence 3DJ = 72
DJ = 72/3
DJ = 24
Hence the measure of DJ is 24
find the Medina number of campsites.9,11,12,15,17,18
To find the median of the composite numbers, we will first have to sort the numbers
We will arrange from least to greatest.
By doing so, we will obtain
[tex]9,11,12,15,17,\text{ and 18}[/tex]Next, we will find the middle number of the set.
The median will be the average of the two numbers
[tex]\frac{12+15}{2}=\frac{27}{2}=13.5[/tex]The median of the numbers is 13.5
Find (w∘s)(x) and (s∘w)(x) for w(x)=7x−2 and s(x)=x^2−7x+5
(w∘s)(x)=
The two composite functions have their values to be (w o s)(x) = 7x² - 49x + 33 and (s o w)(x) = (7x - 2)² - 7(7x - 2) + 5
How to determine the composite functions?Composite function 1
The given parameters are
w(x) = 7x - 2
s(x) = x² - 7x + 5
To calculate (w o s)(x), we make use of
(w o s)(x) = w(s(x))
So, we have
(w o s)(x) = 7s(x) - 2
Substitute s(x) = x² - 7x + 5
(w o s)(x) = 7(x² - 7x + 5) - 2
Expand
(w o s)(x) = 7x² - 49x + 35 - 2
Simplify
(w o s)(x) = 7x² - 49x + 33
Composite function 2
Here, we have
w(x) = 7x - 2
s(x) = x² - 7x + 5
To calculate (s o w)(x), we make use of
(s o w)(x) = s(w(x))
So, we have:
(s o w)(x) = w(x)² - 7w(x) + 5
Substitute w(x) = 7x - 2
(s o w)(x) = (7x - 2)² - 7(7x - 2) + 5
So, the composite functions are (w o s)(x) = 7x² - 49x + 33 and (s o w)(x) = (7x - 2)² - 7(7x - 2) + 5
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hii so i got this question wrong a while ago and im reviewing it id like some help finding out how to solve it
Answer:
Options 1, 3, and 4.
Explanation:
Given the expression:
[tex]3x\mleft(x-12x\mright)+3x^2-2\mleft(x-2\mright)^2[/tex]Step 1: The term -2(x-2)² is simplified by first squaring the expression x-2.
[tex]\begin{gathered} 3x(x-12x)+3x^2-2(x-2)^2 \\ =3x(x-12x)+3x^2-2(x-2)(x-2) \\ =3x(x-12x)+3x^2-2(x^2-2x-2x+4) \\ =3x(x-12x)+3x^2-2(x^2-4x+4) \end{gathered}[/tex]Step 2: The parentheses are eliminated through multiplication.
[tex]=3x^2-36x^2+3x^2-2x^2+8x-8[/tex]Step 3: After multiplying, the like terms are combined by adding and subtracting.
[tex]\begin{gathered} =3x^2-36x^2+3x^2-2x^2+8x-8 \\ =-32x^2+8x-8 \end{gathered}[/tex]The three options that are correct are Options 1, 3, and 4.
Help meeeee4) Consider the equation z(x)=(x-5,x s101-x+8, x > 10Note that for this problem, you do not actually have to evaluate the results. Just make sure that youexplain your choices.a. If you are trying to evaluate Z(3), which equation would you choose, and why?b. If you are trying to evaluate Z(11), which equation would you choose, and why?c. If you are trying to evaluate Z(10), which equation would you choose, and why?
4). a. If you are trying to evaluate Z(3) in order to know which equation would you choose we would have to make the following calcuations:
So, if Z(3), then:
substitute the x with the number 3
[tex]z\left(3\right)=3-5=-2,3\leq10,\text{ 1-3=-2, 3}>10[/tex]Therefore, the equation to choose if Z(3) would be x>10, because by substitute the x with the number 3 would be the largest function with a positive number and sign.