Hector is thirsty and opens up the refrigerator and finds a half full gallon of milk. Hector drinks 2/5 of the milk Later kevin opens up the refrigerator and finds some milk left in the gallon. He drinks 1/3 of what is left. Draw a picture of the situation above. Include the amount of milk before hector drank any, after hector drank some, and then after kevin drank some. What fraction is the entire gallon did kevin drink What fraction of the entire gallon is left after both hector and kevin drink some milk?
Answers
When Hector opens up the refrigerator he finds the next :
He drinks 2/5 of the milk he found, then he drank:
[tex]\frac{1}{2}\times\frac{2}{5}=\frac{1\times2}{2\times5}=\frac{2}{10}=\frac{1}{5}gallon[/tex]And he left in the bottle of milk:
[tex]\frac{1}{2}-\frac{1}{5}=\frac{5-2}{2\times5}=\frac{3}{10}gallons\text{ of milk}[/tex]And after that Kevin open up the refrigerator and finds the next:
Kevin drinks 1/3 of what is left, then he drinks:
[tex]\frac{3}{10}\times\frac{1}{3}=\frac{3\times1}{10\times3}=\frac{3}{30}=\frac{1}{10}\text{gallon of milk}[/tex]And then he left:
[tex]\frac{3}{10}-\frac{1}{10}=\frac{3-1}{10}=\frac{2}{10}=\frac{1}{5}[/tex]And the milk he left in the bottle is:
Related Questions
Hi, can you help me answer this question please, thank you!
Answers
The sample size given in the question is
[tex]n=37[/tex]The mean weight is
[tex]\bar{x}=50[/tex]The standard deviation is
[tex]\sigma=8.4[/tex]The margin of error is calculated using the formula below
[tex]\text{MOE = Z-score(90\% C.I)}\times\frac{\sigma}{\sqrt[]{n}}[/tex]Using the Z-score table, the Z-score for the 90% confidence interval is
[tex]=1.645[/tex]By substituting the values in the formula above, we will have
[tex]\begin{gathered} \text{MOE = Z-score(90\% C.I)}\times\frac{\sigma}{\sqrt[]{n}} \\ \text{Margin of error(MOE)} \\ =1.645\times\frac{8.4}{\sqrt[]{37}} \\ =\frac{13.818}{\sqrt[]{37}} \\ =\pm2.272\text{ounces} \end{gathered}[/tex]Hence,
The final answer is = ±2.272 ounces
select all of the following equations which represent a function?
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To verify that something is a function, we use the horizontal line rule. That is, if the horizontal line passes through two points, then the graph is not a function, like this:
Then the circles and the ellipses are not functions. Then the functions in the problem would be:
1, 3 and 6.
-Given that f(x) = 6(x - 1). Choose the correct statement. A. f-1(12) = 3.5 B. f-1(3) = 1 c. f-16) = 3 D. f-1(9) = 2.5
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Given that function is f(x) = 6(x - 1).
Let y = 6(x - 1). Replace x with y and then solve for y.
[tex]\begin{gathered} x=6(y-1) \\ \Rightarrow x=6y-6 \\ \Rightarrow6y=x+6 \\ \Rightarrow y=\frac{x+6}{6} \end{gathered}[/tex]Thus, f^-1(x) = (x + 6)/6.
[tex]f^{-1}(12)=\frac{12+6}{6}=3[/tex][tex]f^{-1}(3)=\frac{3+6}{6}=1.5[/tex][tex]f^{-1}(6)=\frac{6+6}{6}=2[/tex][tex]f^{-1}(9)=\frac{9+6}{6}=2.5[/tex]Thus, option D is correct.
Jordan plotted the graph below to show the relationship between the temperature of his city and the number of cups of hot chocolate he sold daily:A scatter plot is shown with the title Jordans Hot Chocolate Sales. The x axis is labeled High Temperature and the y axis is labeled Cups of Hot Chocolate Sold. Data points are located at 20 and 20, 30 and 18, 40 and 20, 35 and 15, 50 and 20, 45 and 20, 60 and 14, 65 and 18, 80 and 10, 70 and 8, 40 and 2.Part A: In your own words, describe the relationship between the temperature of the city and the number of cups of hot chocolate sold. (2 points)Part B: Describe how you can make the line of best fit. Write the approximate slope and y-intercept of the line of best fit. Show your work, including the points that you use to calculate the slope and y-intercept. (3 points)
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A.
Overall it has a relation that there are more sold cups when the temperature is lower. On the other hand, based on the 40 degrees part, that have to different values of two different days, we can say is not the only factor.
B.
The best lineal approach is the line created with the points at 20 and 80 degrees. First the slope:
[tex]m=\frac{y1-y2}{x1-x2}=\frac{20-10}{20-80}=\frac{10}{-60}=-\frac{1}{6}[/tex]Now the intercept with y axis, b:
[tex]\begin{gathered} y=mx+b \\ 20=20(-\frac{1}{6})+b \\ 20+\frac{20}{6}=b=23.33=\frac{70}{3} \end{gathered}[/tex]The final line formula is:
[tex]y=-\frac{x}{6}+\frac{70}{3}[/tex]How many tiles of 8 cm² is needed to cover a floor of dimension 6 cm by 24 cm? A. 6 B. 12 C. 18 D. 24
Answers
Answer:
18 tiles.
Step-by-step explanation:
24x6= 144
144/8= 18
vote for brainliest and have a nice day
Solve graphically by the intersection method. Give the solution in interval notation.5x+2<2x−4
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The green line represents 5x + 2
The purple line represents 2x - 4
The orange-colour line represents the intersection of the lines above, which is the solution to the inequality:
5x + 2 < 2x - 4
The intersection is represented by a broken line, to signify the strict < in the equation
The answer for the bottom question need a fast quick answer
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Area of a circle is
[tex]A=\pi\cdot r^2[/tex][tex]\begin{gathered} d=2r \\ d=22 \\ r=\frac{22}{2} \\ r=11 \end{gathered}[/tex][tex]\begin{gathered} A=\pi(11)^2 \\ A=380.133ft^2 \end{gathered}[/tex]The area of the garder is 380.13 square footsIf a square foot cost $ 1.25
[tex]\begin{gathered} 1ft^2\to1.25\text{dollars} \\ 380.13ft^2\to x \\ x=\frac{380.13ft^2\cdot(1.25dollar)}{1ft^2} \\ x=475.16\text{dollar} \end{gathered}[/tex]To cover the garden they need to buy $475 in mulchfind the other binomial p squared -13 p +36 =(p-9)
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To find the other factor of the polynomial
[tex]p^2-13p+36[/tex]We need to find two integers which multiplication gives 36 and addition is -13.
This integers would be -9 and -4, then we have
[tex]p^2-13p+36=p^2-9p-4p+36[/tex]now we factor the right term using common factors:
[tex]\begin{gathered} p^2-9p-4p+36=p(p-9)-4(p-9) \\ =(p-9)(p-4) \end{gathered}[/tex]Hence:
[tex]p^2-9p-4p=(p-9)(p-4)[/tex]Therefore, the other binomial we are looking for is (p-4).
Find the domain of the function. Write the domain in interval notation.
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The domain of a function is the possible values of "t" that the given function can take.
Since the variable "t" is in the denominator, the denominator cannot be equal to zero because it would make the function undefined.
Hence, t - 4 must be greater than zero. For t - 4 to be greater than zero, the value of t must be greater than 4.
In addition, since the variable is inside the radical sign, then the function itself cannot be negative.
Hence, the domain of this function must be greater than 4. In interval notation, it is (4, ∞).
i need help solving this with the statements and reasons
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Given that:
[tex]\bar{AB}\mleft\Vert \mright?\bar{DC}[/tex]To prove that:
[tex]\Delta ABE\cong\Delta\text{CDE}[/tex]We know that congruent parts of congruent triangles are congruent
[tex]\angle\text{AEB }\cong\angle CDE\text{ (vertically opposite angles)}[/tex]Given that E is the midpoint of AC, therefore,
[tex]\begin{gathered} EA=EC\text{ } \\ EB=ED \end{gathered}[/tex]By the SAS congruency theorem as illustrated above, it is sufficient to prove that the triangles are congruent
Ms. Mistovich and Ms. Nelson are having a competition to see who can get morestudents to bring in extra tissues for their classroom. Ms. Mistovich starts with 4 boxesand each week she gets two more boxes from her students. Ms. Nelson starts with 1box and each week she gets 3 more boxes from her students. Write a system ofequations to represent the situation. (1 pt)y=2x+4y=3x+1Ooy=2x+4y=2x+3y=4x+2y=3x+1y=2x+3y=4x+1o
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To write an equation, it is enough to know the rate of change (slope) and the initial value (y-intercept).
The equation of a line of slope m and y-intercept b is:
[tex]y=mx+b[/tex]For Ms. Mistovich, the initial value is 4 and the rate of change is 2.
For Ms. Nelson, the initial value is 1 and the rate of change is 3.
Therefore, the equations that model this situation, are:
[tex]\begin{gathered} y=2x+4 \\ y=3x+1 \end{gathered}[/tex]Brenda is preparing food for a picnic. She must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich
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For 6 sandwiches and 3 dozen cookies, the total time taken by Brenda would be 33 minutes.
What is a mathematical function, equation and expression?function : In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.expression : A mathematical expression is made up of terms (constants and variables) separated by mathematical operators.equation : A mathematical equation is used to equate two expressions.equation modelling : Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis and results of the given problemGiven is Brenda who must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich, and 45 minutes to make a dozen cookies.
If she makes [x] sandwiches and [y] dozen cookies, then the total time she would take to make them can be written as -
t = 4x + 3y
For 6 sandwiches and 3 dozen cookies, we can write -
t(6, 3) = 4 x 6 + 3 x 3 = 24 + 9 = 33 minutes
t(6, 3) = 33 minutes
Therefore, for 6 sandwiches and 3 dozen cookies, the total time taken by Brenda would be 33 minutes.
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{Complete question is given below -
She must make at least 6 sandwiches and at least 3 dozen cookies. It takes her 4 minutes to make a sandwich, x, and 45 minutes to make a dozen cookies, y.}
estimate 794 divided by 18=?
Answers
Answer:
C 40
Step-by-step explanation:
794 is about 800
18 is about 20
800/20=40
Which point is part of the solution of the inequality y ≤ |x+2|-3A.(-1,-1)B.(1,0)C.(0,0)D.(0,1)
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We are going to test all options to see which is true and false.
The one that is true will be the point that is part of the solution.
[tex]\begin{gathered} A) \\ (-1,-1) \\ y\leq\lvert x+2\rvert-3 \\ -1\leq\lvert-1+2\rvert-3 \\ -1\leq\lvert1\rvert-3 \\ -1\leq1-3 \\ -1\leq-2 \\ \text{Not true, so the point (-1,-1) is not a part of the solution} \end{gathered}[/tex]We will move to the next option and test:
[tex]\begin{gathered} B) \\ (1,0) \\ y\leq\lvert x+2\rvert-3 \\ 0\leq\lvert1+2\rvert-3 \\ 0\leq\lvert3\rvert-3 \\ 0\leq3-3 \\ 0\leq0 \\ \text{The above solution is true, so it is a point that is part of the solution.} \\ \text{The correct answer is option B.} \end{gathered}[/tex]Price of PensWhat is the slope ofthe line?Price ($)0-NW A o ovo2Give your answer asa fraction in simplestform.11 2 3 4 5 6 7 8 9Number of Pens
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Solution
For this case we can select the following two points:
(0,0) and (4,6)
We can find the slope using this formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{6-0}{4-0}=\frac{3}{2}[/tex]then the answer after simplify would be:
3/2
Consider the following relation. y= 2x-4
Find four points contained in the inverse. Express your values as an integer or simplified fraction.
ASAP PLEASE¡
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Four points that are contained in the inverse function include the following:
Point = (0, 4).Point = (1, 4.5).Point = (2, 5).Point = (4, 6).What is an inverse function?An inverse function refers to a type of function that is obtained by reversing a mathematical operation in a given function (f(x)).
In order to determine the inverse of the given function, we would interchange both the input value (x) and output value (y) as follows:
y = 2x - 4
x = 2y - 4
Subtracting 4 from both sides, we have:
x + 4 = 2y - 4 + 4
2y = x + 4
Dividing both sides by 2, we have:
y = (x + 4)/2
y = x/2 + 4
When x = 0, we have:
y = x/2 + 4
y = 0/2 + 4
y = 4
Point = (0, 4).
When x = 1, we have:
y = x/2 + 4
y = 1/2 + 4
y = 4.5
Point = (1, 4.5).
When x = 2, we have:
y = x/2 + 4
y = 2/2 + 4
y = 5
Point = (2, 5).
When x = 4, we have:
y = 4/2 + 4
y = 0/2 + 4
y = 6
Point = (4, 6).
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hey i need help giving 10 points
Answers
Answer:
B(2) = -1
Step-by-step explanation:
Assuming each division on the grid is 1 unit
Locate 2 on the x-axis. That is two divisions to the right of the origin. The y value corresponding to this is -1
Hello, I need some assistance with this precalculus question, please?HW Q8
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STEP - BY - STEP EXPLANATION
What to find?
• The system of equation of the argumented matrix.
,• The resultant after the given row operations.
Given:
The system of equation is:
7x - 7y + z = -5
3x - 3y + 8z = -5
-6x + y + 3z = 7
Hence, the correct option is D
The following row operations are to be performed;
[tex]\begin{gathered} R_1=-2r_2+r_1 \\ \\ R_3=2r_2+r_3 \end{gathered}[/tex]The first row operation implies that you will multiply row 2 by -2 and then add to row. The resultant gives a new row 1.
This means that the elements in row 1 becomes:
Row 1 : 1 -1 - 15 | 5
Row 2: 3 -3 8 | -5
As for row 3, we will multiply row 2 by 2 and then add to row 3 to get a new row 3.
That is;
Row 3 : 0 -5 19 | -3
ANSWER
Option D
Part B
[tex]\begin{bmatrix}{1} & {-1} & {-15\text{\mid}} & {5} \\ {3} & {-3} & {8\text{ }}| & {-5} \\ 0{} & -5{} & {19\text{ }|} & {-3} \\ {\placeholder{⬚}} & {\placeholder{⬚}} & {\placeholder{⬚}} & {\placeholder{⬚}}\end{bmatrix}[/tex]1 -1 - 15 | 5
3 -3 8 | -5
0 -5 19 | -3
How many solutions will each equation have?x^2+6x+5
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To solve the quadratic equation, factor the expression and then clear x from each of the factors obtained.
[tex]\begin{gathered} x^2+6x+5=0 \\ (x+5)(x+1)=0 \\ x+5=0 \\ x=-5 \\ x+1=0 \\ x=-1 \end{gathered}[/tex]This equation has 2 solutions which are -5 and -1.
Find the x-intercepts and y-intercept of the following
function.
f(x) = (x+7) (x + 1)(x − 2)
Write your answer in coordinate pairs of the form (x, y).
Provide your answer below:
x-intercept: ().(
]).() and
y-intercept:
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Step-by-step explanation:
there are 3 x-intercepts (the x- values when y = 0). because y is only 0, when one of the 3 factors is 0.
and that is the case for
x = -7
x = -1
x = 2
so, formally, the x- intercepts are
(-7, 0), (-1, 0), (2, 0)
the y intercept is the y- value when x = 0.
(0 + 7)(0 + 1)(0 - 2) = 7×1×-2 = -14
the y-intercept is formally
(0, -14)
Which of the following are equal to sec x? Choose all that apply. 3 answers
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Verify each option
A ---> 1/sinx=cscx -----> is not the answer
B ---> 1/cosx=secx ----> is the answerC ---> cosx/tanx=cosx/(sinx/cosx)=cos^2x/sinx -----> is not the answer
D ---> tanx/sinx=(sinx/cosx)/sinx=1/cosx=secx -----> is the answerE ---> cotxsinx=(cos/sinx)sinx=cosx ----> is not the answer
F ----> tanxcscx=(sinx/cosx)(1/sinx)=1/cosx=secx ----> is the answertherefore
The answer is
options B, D and FAnswer:
B, D, E.
Step-by-step explanation:
B: [tex]\frac{1}{cos(x)}[/tex]
D: [tex]\frac{tan(x)}{sin(x)}[/tex]
E: [tex]tan(x) csc (x)[/tex]
Given a regular octagon and a regular nonagon, which one has the greater interior angle?(Type your answer as the name of the polygon)
Answers
Answer:
Nonagon
Explanation:
Each of the interior angles of a polygon is calculated using the formula:
[tex]\frac{180^0\mleft(n-2\mright)}{n}[/tex]An Octagon has 8 sides, therefore:
[tex]\begin{gathered} Each\; \text{Interior Angle=}\frac{180^0(8-2)}{\square} \\ =\frac{180\times6}{8} \\ =\frac{1080^0}{8} \\ =135^0 \end{gathered}[/tex]A Nonagon has 9 sides, therefore:
[tex]\begin{gathered} Each\; I\text{nterior Angle=}\frac{180^0(9-2)}{9} \\ =\frac{180\times7}{9} \\ =\frac{1260^0}{9} \\ =140^0 \end{gathered}[/tex]Therefore, the nonagon has a greater interior angle.
STATEMENTREASON1. DBC - RST1. Given2. ZABC - ZDBC+ ABD2. Angle addition therom3.3. Ifa=b+cand c>0,thena > b4. ABC > RST4. SubstitutionWhich of the following statements would complete the proof in line 3?O ZABC> ZABDO LABC> DBCO ZDBC> ZABD
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Answer
Option B is correct.
Angle ABC > Angle DBC
Explanation
Since it's been proven that
Angle ABC = Angle ABD + Angle DBC
Since Angle ABD > 0,
Angle ABC > Angle DBC is the part that completes the proof that
Angle ABC > Angle RST
Hope this Helps!!!
74. Noam wants to put a fence around his rectangular garden. His garden measures 35 feet by 50 feet. Thegarden has a path around it that is 3 feet wide. How much fencing material does Noam need to enclose thegarden and path?A. 97 ftB. 194 ftC. 182 ftD. 146 ft
Answers
Given:
The length of the rectangular garden, l=50 feet.
The breadth of the rectangular garden, b=35 feet.
The width of the path around the garden, w=3 feet.
The figure can be drawn as,
So, the length of the fence, L=l+2w.
The breadth of the fence, B=b+2w
The perimeter of the fence can be calculated as,
[tex]\begin{gathered} P=2(L+B) \\ =2(l+2w+b+2w) \\ =2(l+b+4w) \\ =2(50+35+4\times3) \\ =2(50+35+12) \\ =2\times97 \\ =194\text{ ft} \end{gathered}[/tex]Therefore, the perimeter of the fence is 194 ft.
Option B is correct.
Find the 100-th term of the following sequence
3, 10, 17, 24, …
Also find the sum of the first 100 terms.
Answers
Answer:
696
Step-by-step explanation:
*nth term = 7n - 4
n = 100
7 × 100 - 4 = 696
So the 100th term of the following sequence is: 696
*To find the nth term:
They all increase by 7 so it is 7n3 - 7 = -4 so then it is 7n - 4Answer:
Below in bold.
Step-by-step explanation:
This is an arithmetic sequence with a1 = 3 and d = 7.
So, 100th term
= a1 + d(n - 1)
= 3 + 7(100-1)
= 696.
Sum (100) =
(n/2)[2a1 + d(n - 1)]
= 50(6 + 99*7)
= 50 * 699
= 34950.
Expand the polynomial. 1. (m^2-n)(m^2+2n^2)2. (a-2)(4a^3-3a^2)
Answers
1)
The given polynomial is
[tex](m^2-n)(m^2+2n^2)[/tex]Multiply as follows:
[tex](m^2-n)(m^2+2n^2)=m^2(m^2+2n^2)-n(m^2+2n^2)[/tex][tex]=m^2\times m^2+m^2\times2n^2-n\times m^2-n\times2n^2[/tex][tex]=m^4+2m^2n^2-m^2n-2n^3[/tex]Hence the required expansion is
[tex](m^2-n)(m^2+2n^2)=m^4+2m^2n^2-m^2n-2n^3[/tex]2)
The given polynomial is
[tex](a-2)(4a^3-3a^2)[/tex]Multiply as follows:
[tex](a-2)(4a^3-3a^2)=a(4a^3-3a^2)-2(4a^3-3a^2)[/tex][tex]=a\times4a^3-a\times3a^2-2\times4a^3-(-2)\times3a^2[/tex][tex]=4a^4-3a^3-8a^3+6a^2[/tex][tex]=4a^4-11a^3+6a^2[/tex]Hence the required expansion is
[tex](a-2)(4a^3-3a^2)=4a^4-11a^3+6a^2[/tex]72bz +96b2h + 90xbz + 120xbh +
Answers
Factoring
Factor the expression:
[tex]72b^2z+96b^2h+90xbz+120xbh[/tex]Divide the expression into two halves:
[tex](72b^2z+96b^2h)+(90xbz+120xbh)[/tex]Factor b^2 from the first group and xb from the second group:
[tex]b^2(72z+96h)+xb(90z+120h)[/tex]Now find the greatest common multiple of 72 and 96:
72= 2*2*2*3*3
96=2*2*2*2*2*2*3
Now we take the common factors with their least number of repetitions:
GCF=2*2*2*3=24
Now we find the GCF of 90 and 120:
90=2*3*3*5
120=2*2*2*3*5
GCF=2*3*5=30
Taking the GCF of each group:
[tex]\begin{gathered} b^224(3z+4h)+xb30(3z+4h) \\ =24b^2(3z+4h)+30xb(3z+4h) \end{gathered}[/tex]Now we finally take out 3z+4h from both groups:
[tex]\mleft(3z+4h\mright)(24b^2+30xb)[/tex]This last expression can be further factored by taking out 6b from both terms:
[tex]6b(3z+4h)(4b+5x)[/tex]This is the final expression factored as much as possible
can you help me figure out the equation in the drop down menus
Answers
To find:
The piecewise function for the graph.
Solution:
From the graph, it is clear that when x is less than -1, the graph passes through (-1, -3) and (-2, -5).
It is known that the equation of a line passes through two points is given by:
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]So, the equation of line passing through (-1, -3) and (-2, -5) is:
[tex]\begin{gathered} y-(-3)=\frac{-5-(-3)}{-2-(-1)}(x-(-1)) \\ y+3=\frac{-2}{-1}(x+1) \\ y+3=2x+2 \\ y=2x-1 \end{gathered}[/tex]So, the first drop down is "2x - 1", and second drop down is "x is less than or equal to -1".
Now, the graph passes through (1, 5) and (2, 6). So, the equation of the line is:
[tex]\begin{gathered} y-5=\frac{6-5}{2-1}(x-1) \\ y-5=x-1 \\ y=x+4 \end{gathered}[/tex]So, the third drop down menu is "x + 4" and the fourth drop down menu is "x is greater than or equal to 1".
The figure shows the measures of various angles of a roof and it supports. Find the measure of angle 1, the angle between an eave and a horizontal support beam.
Answers
Answer:
35 degrees.
Explanation:
The figure shown is an isosceles triangle. An isosceles triangle has two of its sides and base angles to be equal.
Since the sum of the angles in a triangle is 180 degrees, hence:
110 + (base angles) = 180
110 + (<1 + <1) = 180 (since base angles are the same)
110 + 2<1 = 180
2<1 = 180-110
2<1 = 70
Divide both sides by 2
2<1/2 = 70/2
<1 = 35 degrees
Hence the angle between an eave and the horizontal support beam is 35 degrees.
5(3a-1) - 2(3a+2)=3(a+2) + vselect two expressions that are equivalent to v.
Answers
Let's solve the equation for v to identify the expressions:
[tex]\begin{gathered} 5(3a-1)-2(3a+2)=3(a+2)+v \\ 15a-5-6a-4=3a+6+v \\ 9a-9=3a+6+v \\ v=9a-3a-9-6 \\ v=6a-15 \\ v=3(2a-5) \end{gathered}[/tex]Therefore the equivalent expressions are D and E
