Let's begin by listing out the information given to us:
Line AB is parallel to Line CD; this implies that the angle formed by the two lines are right angles (90 degrees)
E is the intersecting point of both lines AB & CD (figure attached)
Let us put this into its mathematical form:
[tex]\begin{gathered} m\angle AED=(6x-24)=90^{\circ} \\ 6x-24=90\Rightarrow6x=90+24 \\ 6x=114\Rightarrow x=19 \\ x=19 \\ m\angle CEB=(4y+32)=90^{\circ} \\ 4y+32=90\Rightarrow4y=90-32 \\ 4y=58\Rightarrow y=17 \\ y=17 \end{gathered}[/tex]The length of the diagonal of a Rectangle is 14cm,and it forms a 30 degree angle in one corner of the rectangle.What is the area of the rectangle.(A=LxW)Just number 20
Explanation
Step 1
draw the rectangle
here we have a rigth triangle,then
Let
[tex]\begin{gathered} hypotenuse=14 \\ agle=30\text{ \degree} \\ \text{adjacent side= length= l} \end{gathered}[/tex]so, we need a function that relates those values
[tex]\cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}[/tex]replace and solve for length
[tex]\begin{gathered} \cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\cos \Theta=adjacent\text{ side} \\ 14\text{ cm }\cdot\cos 30=l \\ 12.12435\text{ cm=l} \end{gathered}[/tex]Step 2
width
similarity, we need a function that relates
[tex]\sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}}[/tex]let
[tex]\text{opposite side= width=w}[/tex]replace and solve for w
[tex]\begin{gathered} \sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\sin \Theta=opposite\text{ side} \\ 14\text{ cm }\cdot\sin \text{ 30=w} \\ 7cm=w \end{gathered}[/tex]Step 3
finally, the area of a rectangle is given by
[tex]\begin{gathered} \text{Area}=\text{ length }\cdot width \\ \text{replacing} \\ \text{Area}=(12.12\cdot7)(cm^2) \\ \text{Area}=84.87(cm^2) \end{gathered}[/tex]therefore, the answer is
[tex]\text{Area}=84.87(cm^2)[/tex]I hope this helps you
Find percent change of 50 to 43
Answer:
-14.00%
Step-by-step explanation:
((43-50)/50)*100 = -14.00%
Use the table to find the slope of the line.Round your answer out to two decimal places
Given:
The points are (8, -3) and (-5, 1).
To find the slope of the line:
The slope formula is,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{1-(-3)}{-5-8} \\ =\frac{1+3}{-13} \\ =-\frac{4}{13} \\ =-0.30769 \\ \approx-0.31 \end{gathered}[/tex]Hence, the slope of the line is -0.31 (rounded to the nearest two decimal places).
I was doing this with a tutor but there was a connection problem.
ANSWER:
[tex](x-3)^2+(y+7)^2=113[/tex]The point (7,6) is not on the circle
STEP-BY-STEP EXPLANATION:
(a)
The equation of the circle is given as follows:
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{ where (h,k) is the center and r is the radius } \end{gathered}[/tex]We replace to calculate the radius of the circle, like this:
[tex]\begin{gathered} \mleft(-4-3\mright)^2+\mleft(1-\mleft(-7\mright)\mright)^2=r^2 \\ (-7)^2+(8)^2=r^2 \\ r^2=113 \end{gathered}[/tex]Therefore, the equation would be:
[tex](x-3)^2+(y+7)^2=113[/tex](b)
We replace the point, and if the value is greater than the radius, it means that this point is not on the circle:
[tex]\begin{gathered} (x-3)^2+(y+7)^2\le113 \\ \text{ replacing:} \\ \mleft(7-3\mright)^2+\mleft(6+7\mright)^2\le113 \\ 4^2+13^2\le113 \\ 16+169\le113 \\ 185\le113 \end{gathered}[/tex]Therefore, the point (7,6) is not on the circle
Which interval notation represents a function with a domain of all real numbers greater than or equal to 4?A.) -35 D.) y>0 E.) Y<4
If the domain is all real numbers greater than or equal to 4, the interval will be
[tex]x\ge4[/tex]Write the complex number in polar form with argument theta between 0 and 2 pie
The answer in polar form:
[tex]=\text{ 7}\sqrt[]{2}\lbrack cos(tan^{-1}(-1)\text{ + isin}(tan^{-1}(-1)\text{ \rbrack}[/tex]←
In a test of a sex-selection technique, results consisted of 284 female babies and 15 male babies. Based on this result, what is the probability of a female being born to
a couple using this technique? Does it appear that the technique is effective in increasing the likelihood that a baby will be a female?
The probability that a female will be born using this technique is approximately
(Type an integer or decimal rounded to three decimal places as needed.)
Does the technique appear effective in improving the likelihood of having a female baby?
O No
The probability of being a girl child to a couple is 0.9498
Yes, this technique appear effective in improving the likelihood of having a female baby
Given,
In a sex selection technique,
The number of female babies in the result = 284
The number of male babies in the result = 15
Total children = 284 + 15 = 299
We have to find the probability of being a girl child;
Probability;
Probability refers to potential. Probability values are limited to the range of 0 to 1. Its fundamental notion is that something is probable to occur. It is the proportion of favorable events to all other events.
Here,
The probability of being a girl child, P = 284/299 = 0.9498
That is,
The probability of being a girl child to a couple is 0.9498
Yes, this technique appear effective in improving the likelihood of having a female baby
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find the midpoint of PQ. P(6,4) and Q(4,3)
the midpoint between two points has the following formula
[tex](\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]replace in the formula using P as point 1 and Q as point 2
[tex]\begin{gathered} (\frac{6+4}{2},\frac{4+3}{2}) \\ (\frac{10}{2},\frac{7}{2}) \\ (5,\frac{7}{2}) \\ (5,3.5) \end{gathered}[/tex]This is Calculus 1 Problem! MUST SHOW ALL THE JUSTIFICATION!!!
Given: A surveyor standing 50 feet from the base of a large tree measures the angle of elevation to the top of the tree as 75.8 degrees.
Required: To determine how accurately the angle must be measured if the percent error in estimating the tree's height is less than 5%.
Explanation: To estimate the angle, we will use the trigonometric ratio
[tex]tanx=\frac{h}{50}\text{ ...\lparen1\rparen}[/tex]where h is the tree's height, and x is the angle of elevation to the top of the tree.
Hence we get
[tex]\begin{gathered} h=50\cdot(tan75.8\degree) \\ h=197.59\text{ feet} \end{gathered}[/tex]Now differentiating equation 1, we get
[tex]sec^2xdx=\frac{1}{50}dh[/tex]We can write the above equation as:
[tex]sec^2x\cdot\frac{xdx}{x}=\frac{h}{50}\cdot\frac{dh}{h}\text{ ...\lparen2\rparen}[/tex]Also, it is given that the error in estimating the tree's height is less than 5%.
So
[tex]\frac{dh}{h}=0.05[/tex]Also, we need to convert the angle x in radians:
[tex]x=1.32296\text{ rad}[/tex]Putting these values in equation (2) gives:
[tex]\frac{dx}{x}=\frac{197.59}{50}\cdot\frac{cos^2(1.32296)}{1.32296}\cdot0.05[/tex]Solving the above equation gives:
[tex]\begin{gathered} \frac{dx}{x}=3.9518\cdot0.04548551012\cdot0.05 \\ =0.008987\text{ radians} \end{gathered}[/tex]Let
[tex]d\theta\text{ be the error in estimating the angle.}[/tex]Then,
[tex]\lvert{d\theta}\rvert\leq0.008987\text{ radians}[/tex]Final Answer:
[tex]\lvert{d\theta}\rvert\leq0.008987\text{ radians}[/tex]Correctz is jointly proportional to x and y. If z = 115 when x = 8 and y = 3, find z when x = 5 and y = 2. (Round off your answer to the nearest hundredth.)
When we have a number that is jointly proportional to two other numebrs, the formula is:
[tex]a=kcb[/tex]This means "a is jointly proportional to c and b with a factor of k"
Then, we need to find the factor k.
In this case z is jointly proportional to x² and y³
This is:
[tex]z=kx^2y^3[/tex]Then, we know that z = 115 when x = 8 and y = 3. We can write:
[tex]115=k\cdot8^2\cdot3^3[/tex]And solve:
[tex]\begin{gathered} 115=k\cdot64\cdot27 \\ 115=k\cdot1728 \\ k=\frac{115}{1728} \end{gathered}[/tex]NOw we can use k to find the value of z when x = 5 and y = 2
[tex]z=\frac{115}{1728}\cdot5^2\cdot2^3=\frac{115}{1728}\cdot25\cdot8=\frac{2875}{216}\approx13.31[/tex]To the nearest hundreth, the value of z when x = 5 and y = 2 is 13.31
-ractions:
On a website, there is an ad for jeans every 5 minutes, an ad for sneakers
every 10 minutes, and an ad for scarves every 45 minutes.
If they all appeared together at 9:00 P.M., when is
the next time they will all appear together?
ICM to solve the problem
Answer:
Step-by-step explanation:
the city pays students $50 per day to serve snow cones at the local summer festival. Analyze the potential earnings of a student who works the whole week of the festival if working partial days is not permitted. this situation can be modeled by the function f(x)=50x.What is a reasonable maximum value for the dependent variable? Explain how you arrived at your answer.
Given:
The per day earning $50
The function is
[tex]f(x)=50x[/tex]Find-:
The maximum value of earning
Explanation-:
The function is
[tex]f(x)=50x[/tex]Where,
[tex]x=\text{ Number of days}[/tex]The students work for a whole week.
[tex]1\text{ week }=7\text{ Days}[/tex]So the maximum value is
[tex]\begin{gathered} f(x)=50x \\ \\ x=7 \\ \\ f(7)=50\times7 \\ \\ f(7)=350 \end{gathered}[/tex]The maximum earning is $350
14|x + 14| + 13 =-69
Solve for x
Answer: No real solutions
Step-by-step explanation:
[tex]14|x+14|+13=-69\\\\14|x+14|=-82\\\\|x+14|=-82/14[/tex]
Since absolute value is always non-negative, there are no real solutions.
0 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 10401234 5 6 7 8 9 10OB.C.OD. +Reset Selection
Okay, here we have this:
Considering the provided inequation, we are going to identify how can be represented on a number line, so we obtain the following:
So the first thing we will do is factor to find the solution intervals, we have:
[tex]\begin{gathered} 3x^2-27x\leq0 \\ x(x-9)\leq0 \\ 0\leq x\leq9 \end{gathered}[/tex]According to this, we finally obtain that the solution interval is option D, because it satisfies the found interval and its endpoints are closed.
The total movie attendance in a country was 1.16 billion people in 1990 and 1.40 billion in 2008. Assume that the pattern in movie attendance is linear function of time. (Need to answer questions a-d for this question - pic attached)
a)
In order to find a function M(t), first let's identify two ordered pairs that are solutions to the equation.
From the given information, we have the ordered pairs (1990, 1.16) and (2008, 1.4).
Using these ordered pairs, let's find the slope-intercept form of a linear equation (y = mx + b)
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1.4-1.16}{2008-1990}=\frac{0.24}{18}=0.01333 \\ \\ y=mx+b \\ 1.16=1990\cdot0.01333+b \\ b=-25.3667 \\ \\ y=0.01333x-25.3667 \end{gathered}[/tex]So the equation is M = 0.01333t - 25.3667
The independent variable represents the year (correct option: first one)
b)
The slope represents the change in M over the change in t, that is, it represents the change in attendance over a year (correct option: first one)
c)
For t = 2015, we have:
[tex]\begin{gathered} M=0.01333\cdot2015-25.3667 \\ M=26.86-25.37 \\ M=1.49 \end{gathered}[/tex]d)
For M = 1.5, we have:
[tex]\begin{gathered} 1.5=0.01333\cdot t-25.3667 \\ 0.01333t=26.8667 \\ t=2015.5 \end{gathered}[/tex]A periodic deposit is made into an annuity with the given terms. Find how much the annuity will hold at the end of the specified amount of time. Round your answer to the nearest dollar.Regular deposit:$1300Interest rate:4.2%FrequencyannuallyTime:17 yearsFuture value: $
SOLUTION
We will use the formula
[tex]FV=P\lbrack\frac{(1+r)^n-1}{r}\rbrack[/tex]Where FV represents the future value annuity
P = Periodic payment = 1300
r = interest rate = 4.2% = 0.042
n = number of periods = 17 years.
So we have
[tex]\begin{gathered} FV=P\lbrack\frac{(1+r)^n-1}{r}\rbrack \\ FV=1300\lbrack\frac{(1+0.042)^{17}-1}{0.042}\rbrack \\ FV=1300\lbrack\frac{(1.042)^{17}-1}{0.042}\rbrack \\ FV=31,341.485 \end{gathered}[/tex]Hence, the answer becomes $31,341 to the nearest dollar
Please help!
How many solutions does the following equation have?
6 (c+4) = 6c + 30
zero solutions
one solution
infinitely many
solutions
The number of solutions that this equation have is: A. zero solutions.
What are zero solution?Generally speaking, an equation is said to have zero solution or no solution when the left hand side and right hand side of the equation are not the same or equal. This ultimately implies that, an equation would have zero solution or no solution when both sides of the equal sign are not the same and the variables cancel out.
How to determine the number of solutions?In order to determine the number of solutions that this equation have, we would simplify the equation by opening the bracket and then compare both sides of the equation as follows:
6(c+4) = 6c + 30
6c + 24 = 6c + 30
6c - 6c = 30 - 24
0 = 6 (no solution).
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Complete the description of the piece wise function graphed below
Analyze the different intervals at which the function takes the values provided by the graph. Pay special attention on the circles, whether they are filled up or not.
From the graph, notice that the function takes the value of 3 when x is equal to -4, -2 or any number between them. Therefore, the condition is:
[tex]f(x)=3\text{ if }-4\leq x\leq-2[/tex]If x is greater (but not equal) than -2 and lower or equal to 3, the function takes the value of 5. Therefore:
[tex]f(x)=5\text{ if }-2Notice that the first symbol used is "<" and the second is "≤ ".Finally, the function takes the value of -3 whenever x is greater (but not equal) to 3 and less than or equal to 5. Then:
[tex]f(x)=-3\text{ if }3In conclusion:[tex]f(x)=\mleft\{\begin{aligned}3\text{ if }-4\leq x\leq-2 \\ 5\text{ if }-2The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is %180. Answer the questions below and show all work.1. What is the common difference for the deposits made each month?2. Write an explicit formula for this arithmetic sequence. 3. What is the amount of Ginny's deposit in the 12th month?4. At what month will Ginny first make a deposit that is at least $500?
SOLUTION
The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is $ 180.
Since it follows an arithmetic sequence, T n = a + ( n- 1 ) d
Month 3 , T 3 = a+ ( 3 - 1 ) d = 150
a + 2 d = 150 --------------------- equ 1
Month 5 , T 5 = a + ( 5 - 1 ) d = 180
a + 4 d = 180 ...........................equ 2
Solving the two equations, we have :
a - a + 4 d - 2 d = 180 - 150
2 d = 30
Divide both sides by 2 , we have:
d = 15
Let us put d = 15 in equ 1 , we have a + 2 d = 150
a + 2 ( 15 ) = 150
a + 30 = 150
a = 150 - 30
a = 120
From the solution,
Month 1 = 120
Month 2 = 120 + 15 = 135
Month 3 = 135 + 15 = 150
Month 4 = 150 + 15 = 165
Month 5 = 165 + 15 = 180
1. What is the common difference for the deposits made each month? d = 15
2. Write an explicit formula for this arithmetic sequence.
Recall that Tn = a + ( n - 1 ) d
Tn = 120 + ( n - 1 ) 15
Tn = 120 + 15 n - 15
Tn = 120 - 15 + 5n
Tn = 105 + 15n
3. What is the amount of Ginny's deposit in the 12th month?
Tn = 105 + 15n
T 12 = 105 + 15 ( 12 )
T 12 = 105 + 180 = 285
4. At what month will Ginny first make a deposit that is at least $500?
Using Tn = 105 + 15 n = 500
105 + 15 n = 500
15 n = 500 - 105
15 n = 395
Divide both sides by 15 , we have :
n = 26 . 33
n = 27
Find the lateral area of the cylinder .The lateral area of the given cylinder is _ M2(Round to the nearest whole number as needed .)
The lateral area of a cylinder is:
[tex]LA=2\pi rh[/tex]r is the radius
h is the height
For the given cylinder:
As the diameter is 4m, the radius is half of the diameter:
[tex]r=\frac{4m}{2}=2m[/tex]h=12m
[tex]\begin{gathered} SA=2\pi(2m)(12m) \\ SA=48\pi m^2 \\ SA\approx151m^2 \end{gathered}[/tex]Then, the lateral area of the given cylinder is 151 square metersfredrico has earned scores of 7.2, 8.4, and 8.4 on his first 3 dives he has one dive left what score must he get on his last dive to have an average of at least 7.4 on all four dives
For Fredrico to make an average of at least 7.4 on all four dives, he must get at least 5.6 in his last dive.
What is the average?The average is the mean of the total scores that Fredrico scored in his dives.
The average can be computed by dividing the total scores by the number of dives.
The average is the quotient of the division operation of the total scores and the number of dives.
The total score based on an average of 7.4 = 29.6
The total scores obtained = 24 (7.2 + 8.4 + 8.4)
The remaining score to obtain to get the average of 7.4 = 5.6 (29.6 - 24)
Thus, Fredrico needs an additional 5.6 score in the last dive to make the average.
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Fredrico needs to score at least 5.6 on his final dive in order to achieve an average of at least 7.4 on all four dives.
Let's assume the required score would be x on his final dive
Mean = ∑x/n
The average represents the mean of all of Fredrico's dive-related scores.
Here, n = 4
Sum of Observations (∑x) = 7.2 + 8.4 + 8.4 + x
∑x = x + 24
Mean = ∑x/n
Substitute the values in the above formula,
⇒ 7.4 = (x + 24) / 4
Apply the cross-multiplication operation in the above equation,
⇒ 7.4 × 4= (x + 24)
⇒ 29.6 = x + 24
⇒ x = 29.6 - 24
Apply the subtraction operation to get
⇒ x = 5.4
Therefore, Fredrico needs to score at least 5.6 on his final dive
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Find the cosine of angle R. Reduce the answer to the lowest terms.
Cosine formula
[tex]\cos (angle)=\frac{\text{ adjacent side}}{\text{ hypotenuse}}[/tex]Considering angle R, the adjacent side has a length of 9 units, and the hypotenuse of the triangle has a length of 15 units. Substituting this information into the above formula:
[tex]\cos (m\angle R)=\frac{9}{15}=\frac{\frac{9}{3}}{\frac{15}{3}}=\frac{3}{5}[/tex]Determine whether the graph shown is the graph of a polynomial function
the given graph is smooth and its domain is containing all real numbers
so it is a polynomial function.
You want to build a sandbox that can hold50,445 cubic inches of sand. If the sandbox is to be59 in. long and57 in. wide, how tall will it need to be?
Volume of sandbox (to be built) = 50,445 cubic inches
A sandbox is the shape of a cuboid and is calculated by the formula
[tex]\text{volume = length }\cdot\text{ wi}\differentialD tth\text{ }\cdot\text{ height }\Rightarrow\text{ v = l }\cdot\text{ w }\cdot\text{ h}[/tex]Volume = Length * Width * Height
Volume = 50,445 cubic inches, Length = 59 in. Width = 57 in, Height = ?
50,445 = 59 * 57 * h
Make h the subject of the formula, we have:
h = 50445 / (59 * 57) = 15 in
In the triangle below, suppose that mZH= (6x-4)°, mZ1 = (2x-5)°, and m
Find the degree measure of each angle in the triangle.
(2x - 5) ⁰
H (6x-4)
x
mZH =
m 41 =
mZJ =
1
X
Answer: H = 122, I = 37, J = 21
Step-by-step explanation:
All the angles of a triangle add up to 180 degrees.
(6x - 4) + (2x - 5) + x = 180
Combine like terms
9x - 9 = 180
Solve for x
9x = 189
x = 21
m<H = (6*21 - 4) = 122
m<I = (2*21-5) = 37
m<J = 21
Function Notation - TransformationIll send a picture of the question
Given the vertices of the original quadilateral:
(3, 4), (5, 6), (7, 4), and (5, 3)
Vertices of the transformed quadilateral:
(-5, -6), (-3, -4), (-1, -6), and (-3, -7)
Let's describe the transformation rule used for this transformation.
To find the transformation rule, let's find the number of movements in the x-direction and y-direction that would map the original quadilateral to the transformed quadilateral by subtracting the x and y coordinates of the coresponding sides.
We have:
(x, y) ==> (-5 -3, -6 -4) ==> (-8, -10)
(x, y) ==> (-3 -5, -4, -6) ==> (-8, -10)
(x, y) ==> (-1 -7, -6 -4) ==> (-8, -10)
(x, y) ==> (-3 -5, -7 -3) ==> (-8, -10)
For all corresponding sides, we have: (x, y) ==> (-8, -10)
This means there was a shift 8 units to the left, and 10 units downwards.
Therefore, the rule for the transformation shown here is:
(x, y) ==> (x - 8, y - 10)
ANSWER:
B. f(x, y) = (x - 8, x- 10)
Plot Points & Graph Function (Table Given)
We have the next function
[tex]y=-\sqrt[]{x}+3[/tex]We need to calculate some points
x y
0 3
1 2
4 1
9 0
Let's plot the points and then we connect them in order to obtain the graph
J(-6-2)3-*NWMark this and return2--9-8-7-6-5-4-3-2-3₁ 1 2 3 4 5 61-5737-2-cd-6--7--8-2 do-9--10--11--12--13-8 9 10 11 xK(8,-9)What is the x-coordinate of the point that divides thedirected line segment from J to K into a ratio of 2:5?X == (m²²7 m )(x₂ − ×₁) + X₁m+n0 000-22Save and ExitNextSubmit
Use the given formula:
[tex]x=(\frac{m}{m+n})(x_2-x_1)+x_1[/tex]Being m: 2 and n: 5
x1: -6
x2: 8
[tex]\begin{gathered} x=(\frac{2}{2+5})(8-(-6))+(-6) \\ \\ x=\frac{2}{7}*(14)-6 \\ \\ x=4-6 \\ \\ x=-2 \end{gathered}[/tex]Then, the x-coordinate of th point that divides the directed line segment from J to K into a ratio 2:5 is -2Answer: -2How do I write down the size of Angles and marked by letters?
we can assume the lines are parallels so both triangles will have equal angles, so:
s=55° and p=x
now if we add 110 and x, we have a line this means
110+x=180
x=180-100
x=80
so p=x=80
and finally, the angles inside a triangle must add 180° so
55+p+t=180
55+80+t=180
135+t=180
t=180-135=45
So the answer is:
p=80°
s=55°
t=45°
Which of the following is the number of sides a polygon can have to form aregular tessellation?O A. 9B. 3C. 5D.7
From the image, we are asked the number of sides a polygon can have to form a regular tesselation.
The first step is to understand what a regular tessellation is;
A regular tessellation is a highly symmetric, edge-to-edge tiling made up of regular polygons, all of the same shape. There are only three regular tessellations: those made up of equilateral triangles, squares, or regular hexagons.
This implies that it could either have 3 sides(triangle), four sides(square), six sides(hexagon).
From the given options we can clearly see that 3 sides is the only available option.
ANSWER: Option B