The work done by gas in adiabatic process is calculated by
W = [tex]\int\limits^{v_2}_{v_1} {pdV} \, dx[/tex]
where
W is the work done
dV is the change in volumes
P is said to be the pressure of the ideal gas
V1 and V2 are said to be volumes of two different gases
When an ideal gas is compressed adiabatically (Q=0), work is done on it, which raises its temperature; when the gas is expanded adiabatically (Q=0), work is done on it, which lowers its temperature. The cylinders of an automobile truly experience adiabatic compressions because the gas-air combination is compressed there so quickly that there is no time for the mixture to exchange heat with the air around it.
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The work done by gas in adiabatic process is calculated by W = [tex]\int\limits^v_{v2} _ \, pdv dx[/tex]
where W is the work done, dv is the change in volumes, P is said to be the pressure of the ideal gas, V1 and V2 are said to be volumes of two different gases.
The work done by gas in adiabatic process is calculated by W = [tex]\int\limits^v_{v2} _ \, pdv dx[/tex]
where W is the work done, dv is the change in volumes, P is said to be the pressure of the ideal gas, V1 and V2 are said to be volumes of two different gases. When an ideal gas is compressed adiabatically (Q=0), work is done on it, which raises its temperature; when the gas is expanded adiabatically (Q=0), work is done on it, which lowers its temperature. The cylinders of an automobile truly experience adiabatic compressions because the gas-air combination is compressed there so quickly that there is no time for the mixture to exchange heat with the air around it. Adiabatic process is in the process of thermodynamics and it is related to the transfer of the heat part in the thermodynamics section. In this process the heat is transferred in the process without the changing of the any other physical quantity.
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A very light small ball (with a speed of 5m/s) collides with a bowling ball that is at rest. The small ball bounces back, and the bowling ball moves very slowly. Which one, small ball or bowlling ball experiences the greater magnitude impulse during the collision
The bowling ball experiences the greater magnitude impulse during the collision since it is initially at rest and is given the momentum of the small ball which has a speed of 5m/s.
The impulse of the bowling ball can be calculated using the equation impulse = change in momentum = mvf - mvi, where m is the mass of the bowling ball, vf is its final velocity, and vi is its initial velocity.
Since the bowling ball is initially at rest (vi = 0), the impulse can be calculated as mvf = m(5m/s) = 5m^2/s. The impulse of the small ball can be calculated in the same way, giving an impulse of 5m^2/s. Therefore, the bowling ball experiences a greater magnitude impulse during the collision.
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in a three-wire system, how large should the neutral wire be when compared with the hot wires?
In a three-wire system, neutral wire should be the same size as the phase conductors.
What is neutral wire?In alternating current electrical systems, the circuit conductors ground and neutral are employed. The neutral circuit is often connected to ground, while the ground circuit is connected to the earth.
Ground and neutral are closely related because the neutral point of an electrical supply system is frequently connected to earth's surface.
Under specific circumstances, a conductor that is used to connect to the system neutral can also be used to earth (or ground) machinery and buildings.
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The magnetic field in the figure is decreasing at the rate 0.6 T/s . (Figure 1) Part A What is the magnitude of the acceleration of a proton at rest at point a? Part C What is the magnitude of the acceleration of a proton at rest at point b? Part E What is the magnitude of the acceleration of a proton at rest at point c? Part G What is the magnitude of the acceleration of a proton at rest at point d?
0.0080 ×10 8 m/s² is the magnitude of the acceleration of a proton at rest at point c
0.016×10 8 m/s² is the magnitude of the acceleration of a proton at rest at point d
We apply here faraday, law,
∮C→E⋅d→l=dϕmdt
For a uniform electric field;
∮C→E⋅d→l=E(2πr)∮
Here,
r = radius of the circle
Since we see that the magnetic field is perpendicular to the area of the circle, then the magnetic flux will be,
ϕm=2πrB (B= magnetic field)
E=r/2 dB/dt
Now, the force on the proton will be at distance r from the center of the circle ,
F=qE=ma
Written as,
a=qEm
Here,
q=1.6×10−19 C ( charge of the proton)
m=1.67×10−27 kg ( mass of the proton)
Thus,
a=qr/2m dB/dt
to find at point C,
we know that
r=1 cm=0.01 m
a=1.6×10−19 C X 0.01 m X 0.6 T/s / 2 ×1.67×10−27 kg
=0.0080 ×10⁸ m/s2
At the point D,
We know that,
r=2 cm = 0.02 m
Then,
a=1.6×10−19 C×0.02 m×0.6 T/s / 2×1.67×10−27 kg
=0.016×10⁸ m/s2
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What is the porosity of the gravel sample?(the sediment volume for each sample is 400ml.) a. 23.75% b. 28.75% c. 55.75% d. 81.75% please select the best answer from the choices provided a b c d
d. 81.75% is the porosity of the gravel sample.
How porous is the sediment in the sand sample?According to an examination of published data, the average sand porosity for packed, natural (in situ), and loose packing conditions, respectively, over a range of sorting coefficients and grain sizes, was found to be 37.7%, 42.3%, and 46.3%.
Clay is the least permeable sediment while having the greatest pores. Water movement is typically impeded by clay, which functions as an aquitard. The porous and permeable qualities of gravel and sand make them suitable materials for aquifers. The most permeable substance is gravel.
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A frog leaps 2 feet horizontally. The highest point in the jump is 12 foot. Assume the frog starts at (0, 0). What quadratic function models the path of the jump?.
The quadratic function that models the path of the jump is [tex]f(x)=-\frac{1}{8} (x-2)^{2}+\frac{1}{2}[/tex]
It is discovered that, given the vertex, the quadratic model is provided by different equations and the condition given is the parabolic so, the equation that we will use will be the parabolic equation that will derive into quadratic equation.
The following is the equation for a parabola with vertex (h,k):
[tex]f(x)=a (x-h)^{2}+k[/tex]
In this issue:
Leaps 2 feet horizontally, therefore the vertex's x-coordinate is 2, or
it is given by h=2.
The vertex's y-coordinate is because the highest point is half a foot high, or it is given by k=[tex]\frac{1}{2}[/tex]
Then:
[tex]f(x)=a (x-2)^{2}+\frac{1}{2}[/tex]
begins at (0,0), or the moment when x=0 and y=0, and this is utilized to find a.
[tex]0=a (0-2)^{2}+\frac{1}{2}[/tex]
[tex]4a=-\frac{1}{2}[/tex]
[tex]a=-\frac{1}{8}[/tex]
The equation is then:
[tex]f(x)=-\frac{1}{8} (x-2)^{2}+\frac{1}{2}[/tex]
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The quadratic function models the path of the jump as f(x) = -1/8(x-2)² + 1/2
The parabola's general equation is given as,
f(x) = a ( x - h )² + k
Given that,
Leaps horizontally 2 ft, means that, x-coordinate of the vertex is 2, h = 2.
The highest point is half a foot, y- coordinate of the vertex is 1/2, k = 1/2.
Then, f (x) = a(x-2)² + 1/2
By placing, x(0,0), we can find a.
0 = a(0-2)² + 1/2
4a = -1/2
a = -1/8
Thus, the equation is, f(x) = -1/8 (x-2)² + 1/2
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is god real why or why not and what proof to back that up?
The concept of "God" means different things to different people, so it's difficult to provide a definitive answer to this question. Some people believe in a specific deity or deities, while others believe in a more abstract or universal concept of divinity. Still others do not believe in any kind of higher power at all. There is no single piece of evidence that can definitively prove or disprove the existence of God, as people's beliefs about God are often based on faith, personal experiences, and philosophical arguments. Ultimately, the question of whether God exists is a matter of personal belief and interpretation.
A 2 kg block is at rest on the top of a 20 m long rough ramp inclined at 20° with a
coefficient of kinetic friction of 0.6. If an albino Alabaman accordion player does 40 J of
work on the block down the ramp over 12 nm, how far down the ramp does the block
slide?
The block slides 2.37 meters down the ramp.
What is friction?The force preventing solid surfaces, fluid layers, and material components from sliding past one another is known as friction.
The mass of the block: m = 2 kg.
Height of the ramp: h = 20 meter.
Angle of the ramp: α = 20°
coefficient of kinetic friction: μ = 0.6
Hence, frictional force f= μmg cosα = 0.6 × 2 × 9.8 × cos20° N = 10.18 N.
Total work done in sliding a distance l is = mglsinα + fl
= ( 2 × 9.8 × sin20° + 10.18) l
= 16.88 l joule.
But work done is 40 J.
Hence, the distance slides by the ramp = 40/16.88 meter = 2.37 meters.
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The proportion between the friction force and the normal force that a body travelling on a dry, uneven surface experiences is known as the kinetic friction coefficient (k). A very clever process may be used to determine k with a high degree of accuracy.
What role of coefficient of kinetic friction?We may use the equation for work to determine how far the block travels down the ramp. Which is W = Fd, where W is the amount of work completed, F is the amount of force used, and d is the length of time the force was used.
The equation can be used to determine the force in this situation, which is the force of kinetic friction. The formula for kinetic friction is kinetic friction = uk * N, where N is the normal force and uk is the coefficient of kinetic friction.
The normal force is equal to the weight of the block, which is mg, where m is the mass of the block and g is the acceleration due to gravity.
Substituting these values into the equation for work and rearranging to solve for d, we get:
d = W / (kinetic friction× cos(θ))
= 40 J / [(0.6 × 2 kg * 9.8 m/s^2) * cos(20°)]
= 40 J / [(11.76 N) * cos(20°)]
= 40 J / 10.45 N
= 3.84 m
Therefore, the block slides a distance of approximately 3.84 meters down the ramp.
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a uniform ladder weighing 480 n rests against a frictionless wall. the ladder makes a angle with the horizontal. find the horizontal force the ground exerts on the base of the ladder when an 800 n firefighter is from the bottom.
Given that static friction is defined as F equal to the sum of a coeffficient for static friction as well as the normal response N, we obtain the following value: 0.297
Is the wind an horizontal force?Because different sections of the Earth are heated differently by the sun, resulting in pressure differences, solar sun is the primary source of pressure differences that cause winds to occur.
Why does horizontal pressure exist?After being projected onto a nearby horizontal plane, the pressure gradient results in a two-dimensional vector known as the horizontal pressure gradient. This force of the horizontal pressure gradient is directed from higher pressure toward lower pressure very close to the Earth's surface.
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The 90 degree angle solar rays are striking the Tropic of Cancer on _____.
A. June 21
B. March 21
C. December 21
D. September 21
On June 21, the sun will be at a 90-degree angle as it crosses the Tropic of Cancer.
When does the Tropic of Cancer experience 90 degrees of sun radiation?The Sun's perpendicular rays shine down at 23.5° N latitude on June 21 and 22, as seen by the Sun's noontime position at 90°. (Tropic of Cancer). b. The migration of the Sun's perpendicular rays from 23.5o N latitude to the equator occurs between June and September 21. (0o latitude).
Where does the Earth receive direct 90-degree sunlight?Every region of the Earth experiences 12 hours of daylight and 12 hours of darkness, with the circle of illumination passing through the poles, the Sun's rays striking the equator at a 90-degree angle.
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you are taking a bath in a 1.5 m tub during a small earthquake. the water sloshes up and down at the ends of the tub but remains still in the center. you observe that the water goes through 10 oscillations in 22 s. what is the wavelength of the surface wave in m?
The wavelength of the surface wave in 1.2 m
Calculation-(a)since there are two antinodes and one node(where water is motionless), This is the first mode of a pipe open at both ends
so \lambda= 2L
\lambda=2(1.3)
\lambda=2.6m
(c)frequency= 10/22=0.455 Hz
v= f\lambda
v=0.455(2.6)
\lambda=1.2 m/s
What does the term "surface wave" mean?Surface waves are typically lower frequency than body waves and move through Earth's surface material more slowly. On a seismogram, they may be easily differentiated. Deeper earthquakes result in weaker surface waves, which are stronger as the earthquake depth increases.
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An object is shot vertically upward into the air with a positive initial velocity.
According to the vector study, the upward direction is taken as positive, and the downward direction is taken as negative.
in the same manner, the rightward direction is taken as positive span the leftward direction is taken as negative.
As the object is hot vertically upwards so now the direction of velocity is taken as positive as given in the question.
(Because it is direction is in the direction of the center of the Earth). until the object reaches its maximum height where the speed is zero and then it begins to fall until it hits the ground.
At the maximum height, the velocity is zero.
The acceleration acting on the object is acceleration due to gravity which is always acting downwards so it is taken as negative.
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What is a current density?
Answer:
The amount of electric current traveling per unit cross-section area
Explanation:
It is denoted in Amperes per square meter. The more the current is in a conductor, the higher the current density. The electric current generates a magnetic field
In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 1.20×104 m/s . The spaceship is approximately 274 m long, but part of it is packed with gunpowder, so it accelerates over a distance of only 211m.
What was the acceleration (in m/s2 ) experienced by the occupants of the spaceship during launch? (Though the novel’s author realized that the “travelers would … encounter a violent recoil,” he probably didn’t know that people generally lose consciousness if they experience accelerations greater than about 7g∼70m/s2. )
Answer:341232 m/s^2
Explanation: you are given velocity, 1.20x10^4
distance, 211m (the 274m don't matter here)
with this information, you use the 3rd kinematic equation, vf^2-vi^2=2a(xf-xi)
vf and vi can just combine to become V (same with x)
divide ay on both sides to make a stay by itself
you are left with a=V^2/2x
plugin, 1.20x10^4/2x211
put it through a calculator and you get 341232 m/s^2
and I'm assuming you are doing MasterPhysics since I just did mine there so the answer for you is either 340000 m/s^2 or 3.4x10^5 m/s^2
A car speedometer has a 3% uncertainty. What is the range of possible speeds (in km/h) when it reads 120 km/h
Answer:
The range of possible real speeds is:
[tex]x\ -\ the\ actual\ speed \\116.4 < x < 123.6[/tex]
Explanation:
If we know that the certainty of a measurement is 3% - we refer that to the measured value - we calculate how much is 3% of 120:
[tex]120 * 3\% = 3.6[/tex]
To calculate the lower limit - we subtract the given value from the measurement value and to calculate the upper limit - we have to add.
A substance having low specific heat capacity on with equal. gets heated faster than another mass and having high specific head capacity? why?
Heat capacity of a substance is the amount of heat energy required to raise the temperature of that substance by one degree celcius. Specific heat capacity of a substance is the amount of heat energy required to raise the temperature of a unit mass by one degree celcius.
We can look into the question by using the examples of water and oil.Specific heat capacity of water is 4184 JKg⁻¹K⁻¹.This means the amount of heat energy required to raise the temperature of 1 Kg water by 1 degree celcius is 4184K.Whereas,specific heat capacity of oil is 2100 JKg⁻¹K⁻¹.Hence oil needs only 2100 J to increase its temperature by one degree celcius which is half than that of water.
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A human being can be electrocuted if a current as small as 50 mA passes near the heart. An electrician working with sweaty hands makes good contact with the two conductors he is holding. If his resistance is 2200 , what might the fatal voltage be
If his resistance is 2200 Ohm , the fatal voltage is 110 Volt.
The relation between resistance, voltage, and current is given by the Ohm law:
V = I R
Where:
V = voltage
I = current
R = resistance
Parameters from the problem are:
I = current = 50 mA = 0.05 A
R = resistance = 2200 Ohm
Hence,
V = IR
= 0.05 x 2200 = 110 Volt
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Describe the energy of a car driving up a hill. a. entirely kinetic b. entirely potential c. both kinetic and potential d. gravitational e. elastic Explain why
The kinetic energy of the moving car is converted from potential energy.
What type of energy does a car have when it is being driven up a hill?An easy illustration is a car that is parked at the top of a hill. The car gains more kinetic energy and loses more potential energy as it goes down the slope, increasing its kinetic energy. The car transforms kinetic energy into potential energy as it ascends the hill back to the top.
When climbing a hill, what happens to kinetic energy?The marble moves from kinetic energy to gravitational potential energy as it ascends the small hill, then backwards as it descends the hill on the opposite side.
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Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart
at a speed of 2 meters per second each way. Which is the best prediction? (1 point)
When it was full, the cart had less kinetic energy.
The cart had the same kinetic energy going each way.
The cart's kinetic energy depends on Mr. Starr's mass.
When it was empty, the cart had less kinetic energy.
The best prediction, in this case, is - When it was empty, the cart had less kinetic energy.
On which variables Kinetic Energy of a particle depends?Kinetic energy is expressed by the following formula
[tex]K.E. = \frac{1}{2} mv^{2}[/tex]
where m and v represent the mass and the velocity of the particle respectively.
As the cart was moved at a constant rate of 2 meters per second in both directions, we can safely consider velocity to be constant.
Hence, the only variable element is the mass of the cart. Initially, the cart was full of groceries, hence it had more mass compared to the later scene when the cart was empty.
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Answer:
(Question) A city gets its electricity from a dam, where water is stored in a reservoir. How does the water provide the city with its power?
(Answer) Potential energy in the water becomes kinetic energy as it moves through turbines, which turn kinetic energy into mechanical energy that spins a generator, which changes mechanical energy into electricity.
(Question) An acorn rolls off a roof and falls to the ground. Which statement best describes the change in energy?
(Answer) The acorn’s potential energy decreases as its kinetic energy increases.
(Question) An airplane carries 320 passengers from Phoenix to Los Angeles flying at an average speed of 490 miles per hour. On the return flight, the plane carries 164 passengers and travels at the same average speed. What happens to the plane’s kinetic energy?
(Answer) On the return flight, the plane has less kinetic energy.
(Question) A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?
(Answer) 90,480.6 J
(Question) Which object has kinetic energy?
(Answer) balloon rising in the sky
(Question) Mr. Starr pushed a cart full of groceries to his car. After emptying the cart, he pushed it back to the store. He pushed the cart at a speed of 2 meters per second each way. Which is the best prediction?
(Answer) When it was empty, the cart had less kinetic energy.
(Question) A student fires a toy rocket into the sky. When does the rocket have the most potential energy?
(Answer) when the rocket reaches its highest point
(Question) What is the best description of one billiard ball hitting a second billiard ball?
(Answer) Most of the kinetic energy in the first ball is transferred to the second ball.
(Question) A roller-coaster car is at the top of a hill. The car and its passengers have a combined mass of 1,088 kilograms. If the hill is 62 meters tall, how much potential energy does the car have?
(Answer) 661,068.8 J
(Question) A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?
(Answer) 592,416 J
(Question) A diagram is drawn showing a swing set with a swing pulled backward prior to release. The diagram shows how the swing will move forward and then backward after it is initially released. At which point in the diagram is all of the energy gravitational potential energy?
(Answer) when the swing is pulled back prior to release
(Question) essay
(Answer) good luck
(Question) essay
(Answer) good luck
Explanation:
I just completed the assignment. UwU
What are the 4 characteristics of a concave mirror?
Concave mirrors can create both actual and virtual pictures. Mirrors can be enlarged, shrunk, or the exact size as the item. They can just be upright (if online) or reversed (unless real); front of the glass (unless real); or behind the glass (if virtual).
What distinguishes a convex mirror?Convex mirrors are not utilized to focus light since they diverge light rays by reflecting light outward. Virtual, upright, and initially smaller than the item, the image grows to a maximum size equal to the thing as it approaches the mirror. Diverging mirrors are another name for such mirrors.
What features distinguish concave?Spherical mirrors include both concave and convex mirrors.
Property 1: The incoming ray that is perpendicular to the main axis travels through the concave mirror's focus.
Property 2: The incident light will be reflected parallel toward the major axis if it passes through the focus.
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A 560-g squirrel with a surface area of 144cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a drag coefficient for a horizontal skydiver.) What will be the velocity of a 56-kg person hitting the ground, assuming no drag contribution in such a short distance
Answer:
To estimate the terminal velocity of the squirrel, we need to consider the forces acting on it: its weight, the force of gravity, and the drag force. The terminal velocity is the velocity at which the sum of these forces is zero, meaning that the squirrel is no longer accelerating.
The weight of the squirrel is given by:
W = m * g
where m is the mass of the squirrel and g is the acceleration due to gravity (9.8 m/s^2).
The force of gravity is given by:
F_g = W
The drag force is given by:
F_d = (1/2) * C * rho * A * v^2
where C is the drag coefficient, rho is the density of air, A is the surface area of the squirrel, and v is its velocity.
The equation for terminal velocity can be written as:
0 = W - F_d
= m * g - (1/2) * C * rho * A * v^2
Solving for v, we get:
v = sqrt((2 * m * g) / (C * rho * A))
Plugging in the values for the squirrel, we get:
v = sqrt((2 * 560 g * 9.8 m/s^2) / (1.28 * 1.225 kg/m^3 * 144 cm^2))
= 15.4 m/s
Therefore, the terminal velocity of the squirrel is approximately 15.4 m/s.
To calculate the velocity of a person hitting the ground, we can use the same formula as above, but with the mass and surface area of the person.
Plugging in the values for the person, we get:
v = sqrt((2 * 56 kg * 9.8 m/s^2) / (1.28 * 1.225 kg/m^3 * 5000 cm^2))
= 51.5 m/s
Therefore, the velocity of the person hitting the ground would be approximately 51.5 m/s, assuming no drag contribution in such a short distance.
What are the two steps required to charge an object without any physical contact between charged objects
There are two main methods for charging an object without any physical contact between charged objects namely induction and Coulombic attraction/repulsion.
Induction is a process by which a charged object can influence the distribution of charges in a nearby conductor without actually touching it. When a charged object is brought near a conductor, it causes the electrons in the conductor to rearrange themselves in an effort to balance out the overall charge distribution. This can result in one end of the conductor becoming positively charged and the other end becoming negatively charged.
Coulombic attraction/repulsion is a phenomenon that occurs when two charged objects are brought close together. According to Coulomb's Law, if the two objects have opposite charges (e.g. one is positive and the other is negative), they will experience a force of attraction. If the two objects have the same charge (e.g. both are positive or both are negative), they will experience a force of repulsion.
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Your question seems incorrect, but I assume the correct question was:
"What are the two main methods to charge an object without any physical contact between charged objects?"
How much work must be done to accelerate a 704.15 kg car from 15.28 m/s to 32.48 m/s?
Answer:
To calculate the amount of work required to accelerate a car from 15.28 m/s to 32.48 m/s, you can use the following formula:
Work = Force * Distance
In this case, the force is the accelerating force on the car, and the distance is the change in velocity of the car. The accelerating force can be calculated using the formula:
Force = Mass * Acceleration
To find the acceleration of the car, you can use the formula:
Acceleration = Change in Velocity / Time
The time it takes for the car to accelerate can be calculated using the formula:
Time = Distance / Velocity
Substituting these formulas into the original equation, we get:
Work = Mass * (Change in Velocity / Time) * (Time)
Plugging in the given values, we get:
Work = 704.15 kg * (32.48 m/s - 15.28 m/s) / (32.48 m/s - 15.28 m/s) * (32.48 m/s - 15.28 m/s / 32.48 m/s)
Simplifying this equation, we get:
Work = 704.15 kg * (17.2 m/s)^2
Work = 704.15 kg * 295.04 m^2/s^2
Work = 207,764.79 kg*m^2/s^2
So the total amount of work required to accelerate the car from 15.28 m/s to 32.48 m/s is 207,764.79 kg*m^2/s^2.
Explanation:
find all the second partial derivatives. f(x, y) = (sin(mx + ny))2
The second partial derivatives of f(x, y) = (sin(mx + ny))² are:
∂²f/∂x² = -m²(sin(mx + ny))²∂²f/∂y² = -n²(sin(mx + ny))²∂²f/∂x∂y = ∂²f/∂y∂x = mn(sin(mx + ny))²Second Derivatives PartialThe reason these are the second partial derivatives is because we are taking the derivative of the function twice with respect to x and y.
The first partial derivative with respect to x is:∂f/∂x = ∂/∂x (sin(mx + ny))² = ∂/∂x (sin²(mx + ny)) = 2sin(mx + ny)cos(mx + ny) * ∂/∂x (mx + ny) = m cos(mx + ny)sin(mx + ny)
The second partial derivative with respect to x is:∂²f/∂x² = ∂/∂x (m cos(mx + ny)sin(mx + ny)) = -m²sin²(mx + ny)
Similarly, the second partial derivative with respect to y is :∂²f/∂y² = ∂/∂y (n cos(mx + ny)sin(mx + ny)) = -n²sin²(mx + ny)
And lastly, the partial derivative with respect to x and y is :∂²f/∂x∂y = ∂/∂y(m cos(mx + ny)sin(mx + ny)) = mn cos(mx + ny)sin(mx + ny)
So, all these second derivatives are the result of applying the chain rule and the product rule several times.
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What did Harrison realize after getting a watch made for himself?
Harrison realized that the watch had the potential to be the timekeeping solution to the longitude problem with a few tweaks.
Realizing this led to the creation of H4, which has a diameter of just 13 centimeters. One of the upgrades Harrison made was a larger than usual balance wheel, which is a feature of most pocket watches. It had a greater frequency, pulsing five times per second, or 18,000 times each hour. The watch had a tiny remontoir and a revised version of Harrison's temperature compensation from H3.
The only issue, if you can even call it that, was that H4 needed oiling. However, Harrison used a creative approach to reducing friction by installing jeweled bearings at various points.
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The heating curve shows temperature verses energy gain. Which parts of the curve represent a gain in potential energy?.
The two parts which are along x axis and have some constant value along the y axis i.e. horizontal parts represents a gain in potential energy.
In the heating curve shown in the question, these are gain in potential energy because they have constant temperature referred to the gain.he work done by a force on an object between two points does depend on the path taken by the object between the two points. For the special case of conservative forces, we have seen that the work does not depend on the path.
Therefore, we can define, for conservative forces, an associated potential energy that, for a given object, depends only on its location. In particular, when a conservative force acts on an object as it moves between two points, we define the define the change in potential energy associated with that force as minus the work done by that force between those two points.
Whatever kinetic energy the ball gains is exactly equal to the potential energy that the ball loses. If we define the total mechanical energy of an object as the sum of its kinetic and potential energy, then, in this case, we see that the total mechanical energy of the ball was conserved.
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Potential energy is increased by the two horizontal components that are along the x axis and have some constant value along the y axis.
These are a gain in potential energy in the heating curve depicted in the question since they have constant temperature. The work that a force performs on an object between two points depends on the path that the thing takes there. We have demonstrated that, in the exceptional case of conservative forces, the work is independent of the path.
As a result, we can define a potential energy associated with conservative forces that, for a given item, depends only on its location. In particular, we define the change in potential energy associated with a conservative force as the work done by that force between the two points when it acts on an item as it moves between them.
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How does the marine chronometer work?
The marine chronometer work by calculating the precision timepiece that is brough on a ship and implied in the determination of the ship's coordinate by celestial navigation. The invention of marine chronometer was a revolution in the age of sail.
Why was the marine chronometer important?
The Marine chronometer was important to the ship because of its accuracy in describing their longitude which is the important information to the navigator. Marine chronometer was invented by english man name John Harrison who is work as carpenter and clockmaker in the age of sail in 1761. The invention of marine chronometer is drastically increased the safety and precision are travel by the sea.
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a 2.0 kg block travels with an angular velocity of 12 rad/s around a 0.50 m radius circle. what is the angular momentum of the block?
The terms velocity and angular momentum are relevant to this query.The The size of angular momentum is "6 J.s".
What is the simple definition of velocity?The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. The displacement change rate is the issue.
What does velocity vs. acceleration mean?Velocity is the term for the rate at which a displacement changes. Acceleration is the measure of a change in velocity. Velocity is a vector quantity because it comprises both magnitude and direction. Acceleration is a vector quantity because it is the speed at which velocity varies.
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A 12 kg box is placed on the rough Surface. If a force of 20N applied at 30° to the horizontal can't move the box, Calculate the frictional Force.
The frictional force is 17.32 N.
Calculating the frictional force, we can use the equation:friction = coefficient of friction * normal force
Since the box is not moving, the frictional force must be equal to the force applied to the box.
Recall, force applied is 20 N at an angle of 30 degrees to the horizontal. We can break this force into its horizontal and vertical components using trigonometry:
horizontal force = 20 N * cos(30) = 17.32 N
vertical force = 20 N * sin(30) = 10 N
The normal force is equal to the weight of the box, which can be calculated as:
normal force = weight of box
= 12 kg * 9.8 m/s²
normal force = 117.6 N
Now we can use these values to calculate the coefficient of friction:
coefficient of friction = friction / normal force
friction = horizontal force
= 17.32 N
Coefficient of friction = 17.32 N
117.6 N
Coefficient of friction = 0.147
Hence, the frictional force is 0.147 * 117.6 N
= 17.32 N
This is the same as the horizontal component of the force applied to the box.
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A car accelerates uniformly from rest and
reaches a speed of 17.3 m/s in 6 s. The
diameter of a tire is 66.5 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev.
The energy of a photon that has a frequency of 1.821 × 1016 s-1 is ________ J. a. 5.44 × 10-18 b. 5.46 × 10-24 c. 1.99 × 10-25 d. 1.21 × 10-17 e. 3.49 × 10-48
The massless components of light are known as photons. They are the energy particles that make up the electromagnetic spectrum. A photon with a frequency of 1.821 ×10^16 s-1 has the energy of 1.21x[tex]10^{-17}[/tex]J.
The form of energy can be changed via a variety of techniques. Examples of equipment that can produce usable mechanical or electrical energy include a wide range of fuel-burning heat engines, generators, batteries, fuel cells, and magnetohydrodynamic systems.
Energy = hv
with,
h = Planck's constant
Planck's constant is the physical constant in electromagnetism's quantum theory that connects a photon's energy to its matching frequency. measured in terms of eV in the MKS system and J.s in the SI as its units of representation.
v = 1.821 x [tex]10^{16}[/tex]
we get,
energy = 6.626 x [tex]10^{-34}[/tex] x 1.821 x [tex]10^{16}[/tex]
energy= 1.21 x [tex]10^{-17}[/tex] J
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