Binomial distribution formula:
[tex]P(x)=\frac{n!}{(n-x)!x!}*p^{`x}*q^{n-x}[/tex]For the gien situations:
* n=15, p=0.4, find P(4 successes)
[tex]\begin{gathered} n=15 \\ p=0.4 \\ q=1-p=1-0.4=0.6 \\ x=4 \end{gathered}[/tex][tex]P(4)=\frac{15!}{(15-4)!4!}*0.4^4*0.6^{15-4}[/tex][tex][/tex](3,-8),(-2,5) write an equation for the line in point slope form .Then rewrite the equation in slope intercept form
The equation for the line in point-slope form is:
[tex]y-y_1=m(x-x_1)[/tex]Where m is the slope and (x1, y1) is a point of the line. If we have two points (x1,y1) and (x2, y2), the slope is equal to:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, replacing (3, -8) and (-2, 5), we get that the slope and the equation of the line are:
[tex]m=\frac{5-(-8)}{-2-3}=\frac{5+8}{-5}=\frac{-13}{5}[/tex][tex]\begin{gathered} y-(-8)=\frac{-13}{5}(x-3) \\ y+8=-\frac{13}{5}(x-3) \end{gathered}[/tex]Therefore, the equation in slope-intercept form is calculated as:
[tex]\begin{gathered} y+8=-\frac{13}{5}x-\frac{13}{5}\cdot(-3) \\ y+8=-\frac{13}{5}x+\frac{39}{5} \\ y=-\frac{13}{5}x+\frac{39}{5}-8 \\ y=-\frac{13}{5}x-\frac{1}{5} \end{gathered}[/tex]Answer: Point-slope form:
[tex]y+8=-\frac{13}{5}(x-3)[/tex]slope-intercept form:
[tex]y=-\frac{13}{5}x-\frac{1}{5}[/tex]Eddie has already written 23 pages, and he expects to write 1 page for every additional hour spent writing. After spending 21 hours writing this week, how many pages will Eddit have written in Total?
EXPLANATION
Eddie has written ----->23 pages
He expects to write---> 1 page/additional hour
After spending 21 hours writing this week:
Eddy will have written:
Total pages are written =
Pages already written + Total additional hours*Pages/hours
Total pages written = 23 + 21 hours * 1 page/hour
Total pages written = 23 + 21
Total pages written = 44 pages
Answer: Eddie will have written 44 pages this week.
Find the sum of the first 7 terms of the following sequence. Round to the nearest hundredth if necessary.5,−2,45,...5,−2, 54 ,...Sum of a finite geometric series:Sum of a finite geometric series:Sn=a1−a1rn1−rS n = 1−ra 1 −a 1 r n
Solution:
Given:
[tex]5,-2,\frac{4}{5},\ldots[/tex]To get the sum of the first 7 terms, the formula below is used;
[tex]S_n=\frac{a_1-a_1r^n}{1-r}[/tex]where;
[tex]\begin{gathered} n=7 \\ a_1\text{ is the first term = 5} \\ r\text{ is the co}mmon\text{ ratio=}\frac{-2}{5} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} S_n=\frac{a_1-a_1r^n}{1-r} \\ S_7=\frac{5-5(-\frac{2}{5})^7}{1-(-\frac{2}{5})} \\ S_7=\frac{5-5(-0.4)^7}{1+\frac{2}{5}} \\ S_7=\frac{5-5(-0.0016384)}{1+0.4} \\ S_7=\frac{5+0.008192}{1.4} \\ S_7=\frac{5.008192}{1.4} \\ S_7=3.57728 \end{gathered}[/tex]Therefore, the sum of the first 7 terms is 3.57728
2000.5 - 351.748 +62.1
Given the expression :
[tex]2000.5-351.748+62.1[/tex]At first make all the decimal digits equally for all terms
The maximum decimal is 3 so, add 00 to the first and the last terms
So,
[tex]\begin{gathered} 2000.5-351.748+62.1 \\ =2000.500-351.748+62.100 \\ =1710.852 \end{gathered}[/tex]So, the answer is : 1,710.852
$85000 is invested at 7.5% per annum simple interest for 5 years. Calculate the simple interest.
From the statement of the problem we know that:
• the principal amount of money invested is P = $85000,
,• the rate per year is 7.5%, in decimals r = 0.075,
,• the time is t = 5 years.
The interest earnt I is equal to the difference between the total accrued amount A and the principal amount P:
[tex]I=A-P=P(1+r\cdot t)-P=P\cdot r\cdot t.[/tex]Replacing by the data of the problem we find that the simple interest is:
[tex]I=85000\cdot0.075\cdot5=31875.[/tex]Answer
The simple interest is $31875.
can you explain what the 8th question is asking then answer it please
Answer:
Options A and C
Explanation:
We want to find out which arithmetic sequence(s) contain the term 34.
For an arithmetic sequence to contain the term, 34, the corresponding n-value must be an integer.
Option A
Set tn = 34
[tex]\begin{gathered} t_n=6+(n-1)4 \\ 34=6+(n-1)4 \end{gathered}[/tex]Solve for n:
[tex]\begin{gathered} 34-6=4n-4 \\ 28=4(n-1) \\ n-1=\frac{28}{4}=7 \\ n-1=7 \\ n=7+1 \\ n=8 \end{gathered}[/tex]The 8th term of this sequence is 34.
Option B
[tex]\begin{gathered} t_n=3n-1 \\ 34=3n-1 \\ 34+1=3n \\ 35=3n \\ n=\frac{35}{3}=11\frac{2}{3} \end{gathered}[/tex]A sequence cannot have a decimal nth term, therefore, the sequence does not contain 34.
Option C
T1 = 12, d=5.5
[tex]\begin{gathered} 12+5.5(n-1)=34 \\ 5.5(n-1)=34-12 \\ 5.5(n-1)=22 \\ n-1=\frac{22}{5.5} \\ n=4+1 \\ n=5 \end{gathered}[/tex]The 5th term of this sequence is 34, therefore, it contains the term 34.
Option D
3,7,11,...
[tex]\begin{gathered} t_1=3 \\ d=7-3=4 \end{gathered}[/tex]Using the nth term of an arithmetic sequence formula:
[tex]\begin{gathered} t_n=t_1+(n-1)d \\ 34=3+4(n-1) \\ 34-3=4(n-1) \\ 31=4(n-1) \\ n-1=\frac{31}{4} \\ n-1=7\frac{3}{4} \\ n=8\frac{3}{4} \end{gathered}[/tex]A sequence cannot have a decimal nth term, therefore, the sequence does not contain 34.
The sequences in Options A and C contain the term 34.
The table of values represents a quadratic function.What is the average rate of change for f(x) from x=−10 to x = 0?Please help me with this problem so that my son can understand better. Enter your answer in the box.xf(x)−10184−5390−654910204
We are given a quadratic function and the rather than the equation for this function we already have the outputs at each given input as shown in the table provided. This means, for example, for the function given, when the input is -10, the output is 184. Thus the table includes among other values;
[tex]x=-10|f(x)=184[/tex]To calculate the average rate of change we shall apply the formula for the slope (which is also the average rate of change). This is given below;
[tex]\text{Aerage Rate of Change}=\frac{f(b)-f(a)}{b-a}[/tex]Note that the variables are;
[tex]\begin{gathered} f(a)=\text{first input value} \\ f(b)=\text{second input value} \end{gathered}[/tex]The first input value is -10 and the function at that value is 184
The second input value is 0 and the function at that value is -6
We now have;
[tex]\begin{gathered} a=-10,f(a)=184 \\ b=0,f(b)=-6 \end{gathered}[/tex]We can now substitute these into the formula shown nearlier and we'll have;
[tex]\begin{gathered} \text{Ave Rate Of Change}=\frac{f(b)-f(a)}{b-a} \\ =\frac{-6-184}{0-\lbrack-10\rbrack} \end{gathered}[/tex][tex]\begin{gathered} =\frac{-190}{0+10} \\ \end{gathered}[/tex][tex]=\frac{-190}{10}[/tex][tex]\text{Average Rate of Change}=-19[/tex]ANSWER:
The average rate of change over the given interval is -19
Which of the equations below could be the equation of this parabola? A. y = 1/2 x² B. x-1/2 y2 c. y = -1/2 x² D. x = 1/2 y2SUBMIT
The equation of the parabola is given as;
[tex]y=\frac{1}{2}x^2[/tex]The correct answer is option A.
Completely the instructions to move from one point to another along the line y = 2/3x+1. Down 4 units then. Units.
The parent function given is,
[tex]y=\frac{2}{3}x+1[/tex]We were told the parent function was translated 4 units down, which means
[tex]\begin{gathered} y=\frac{2}{3}x+(1-4) \\ y=\frac{2}{3}x-3 \end{gathered}[/tex]Hence, the transformed function would be,
[tex]y=\frac{2}{3}x-3[/tex]Let us now plot the graph of the parent function and the transformed function in order to compare the two graphs.
From the graph above, the parent function is represented in the green line while the transformed function is represented in the black line.
Therefore, the answer is
Down 4 units, then left 6 units.
Please help with this question
The average velocities of the stone are: i) 12.96 m / s, ii) 13.20 m / s, iii) 13.20 m / s, iv) 13 m / s. The instantaneous velocity is approximately equal to 13 meters per second.
How to find the average velocity and the instantaneous velocity of a stone
The average velocity (u), in meters per second, is the change in the height (h), in meters, divided by the change in time (t), in seconds. And the instantaneous velocity (v), in meters per second, is equal to the average velocity when the change in time tends to zero.
a) Then, the average velocities are determined below:
Case i)
u = [f(1.05) - f(1)] / (1.05 - 1)
u = (18.748 - 18.1) / 0.05
u = 12.96 m / s
Case ii)
u = [f(1.01) - f(1)] / (1.01 - 1)
u = (18.232 - 18.1) / 0.01
u = 13.20 m / s
Case iii)
u = [f(1.005) - f(1)] / (1.005 - 1)
u = (18.166 - 18.1) / 0.005
u = 13.20 m / s
Case iv)
u = [f(1.001) - f(1)] / (1.001 - 1)
u = (18.113 - 18.1) / 0.001
u = 13 m / s
The fourth option offers the best estimation for the instantaneous velocity at t = 1 s. Then, the instantaneous velocity is approximately equal to 13 meters per second.
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Go on the head 120 eggs delivered to her bakery she used to 98 eggs to bake cakes which equation can she use find the number of eggs r she has left
Yolanda has 120 eggs, but she used 98 eggs
r represents the equation for the number of eggs that she left:
To find this, subtract the total of eggs by the eggs used
Then, r = 120 - 98
Harriet found the number of At-Bats (AB) using the formula below
Here, we want to get what should have been written as step 1
As we can see from what is presented, she went directly to step 2 without writing out the individual product and summing them
So, we have the step 1 correctly written as;
[tex]0.520\text{ = }\frac{(28)\text{ + (94) +(3) + 240}}{AB}[/tex]Given the diagram below which could be used to calculate AC
Cos a = adjacent side / hypotenuse
Where:
a= angle = 37°
adjacent side = 20
Hypotenuse = x (the longest side , AC)
Replacing:
Cos (37)=20/ x (option B)
m^3n^-6p^0 i dont understand how to solve this problem it has exponents
ANSWER:
[tex]\frac{m^3}{n^6}[/tex]STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]m^3n^{-6}p^0\:\:[/tex]We simplify as follows:
[tex]\begin{gathered} a^{-b}=\frac{1}{a^b}\rightarrow n^{-6}=\frac{1}{n^6} \\ \\ p^{0}=1 \\ \\ \text{ We replacing:} \\ \\ m^3n^{-6}p^0\:\:=m^3\cdot\frac{1}{n^6}\cdot\:1=\frac{m^3}{n^6} \end{gathered}[/tex]Solve the system. Is the answer (3,0) or (0, -1) or no solution or infinitely many solutions?
Given:
[tex]\begin{gathered} \frac{1}{3}x+y=1\ldots..(1) \\ 2x+6y=6\ldots\text{.}(2) \end{gathered}[/tex]Solve the system of equations.
Equation (2) can be simplified as,
[tex]\begin{gathered} 2x+6y=6 \\ \text{Divide by 6 on both sides} \\ \frac{2x}{6}+\frac{6y}{6}=\frac{6}{6} \\ \frac{1}{3}x+y=1\text{ which represents the equation (1)} \end{gathered}[/tex]Moreover, the slope and y-intercept of both the equation of lines are the same.
It shows that the lines are coincident.
The system has an infinite number of solutions. Also, point (3,0) is one of the solutions.
How much will the account be worth in 46 months?
In the question we are given the following parameters
Principal = $5100
Rate = 16.87% compounded semi-annually
Time = 46 months = 3yrs 10 months = 3 5/6 years
Explanation
We can solve the question using the formula below
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]"nt" is the number of months the principal accrues interest twice a year.
Therefore we have;
[tex]\begin{gathered} A=5100(1+\frac{16.87\div100}{2})^{\frac{23}{6}\times2} \\ A=5100(1+0.08435)^{\frac{23}{3}} \\ A=5100(1.08435)^{\frac{23}{3}} \\ A=9488.62 \end{gathered}[/tex]Answer:$9488.62
The volume of a square-based rectangular cardboard box needs to be at least 1000cm^3. Determine the dimensions that require the minimum amount of material to manufacture all six faces. Assume that there will be no waste material. The Machinery available cannot fabricate material smaller than 2 cm in length.
We have to find the dimensions of a box with a volume that is at least 1000 cm³.
We have to find the dimensions that require the minimum amount of material.
We can draw the box as:
The volume can be expressed as:
[tex]V=L\cdot W\cdot H\ge1000cm^3[/tex]The material will be the sum of the areas:
[tex]A=2LW+2LH+2WH[/tex]Since the box is square-based, the width and length are equal and we can write:
[tex]L=W[/tex]Then, we can re-write the area as:
[tex]\begin{gathered} A=2L^2+2LH+2LH \\ A=2L^2+4LH \end{gathered}[/tex]Now, we have the area expressed in function of L and H.
We can use the volume equation to express the height H in function of L:
[tex]\begin{gathered} V=1000 \\ L\cdot W\cdot H=1000 \\ L^2\cdot H=1000 \\ H=\frac{1000}{L^2} \end{gathered}[/tex]We replace H in the expression for the area:
[tex]\begin{gathered} A=2L^2+4LH \\ A=2L^2+4L\cdot\frac{1000}{L^2} \\ A=2L^2+\frac{4000}{L} \end{gathered}[/tex]We can now optimize the area by differentiating A and then equal the result to 0:
[tex]\begin{gathered} \frac{dA}{dL}=2\frac{d(L^2)}{dL}+4000\cdot\frac{d(L^{-1})}{dL} \\ \frac{dA}{dL}=4L+4000(-1)L^{-2} \\ \frac{dA}{dL}=4L-\frac{4000}{L^2} \end{gathered}[/tex][tex]\begin{gathered} \frac{dA}{dL}=0 \\ 4L-\frac{4000}{L^2}=0 \\ 4L=\frac{4000}{L^2} \\ L\cdot L^2=\frac{4000}{4} \\ L^3=1000 \\ L=\sqrt[3]{1000} \\ L=10 \end{gathered}[/tex]We now can calculate the other dimensions as:
[tex]W=L=10[/tex][tex]H=\frac{1000}{L^2}=\frac{1000}{10^2}=\frac{1000}{100}=10[/tex]Then, the dimensions that minimize the surface area for a fixed volume of 1000 cm³ is the length, width and height of 10 cm, which correspond to a cube (all 3 dimensions are the same).
Answer: the dimensions are length = 10 cm, width = 10 cm and height = 10 cm.
How many values does the expression 6+(x+3)^2 have?
The solution of a quadratic equation is imaginary.
What are the solutions of a quadratic function?
A quadratic equation with real or complex coefficients has two solutions, called roots.
These two solutions may or may not be distinct, and they may or may not be real.
The solution of the given quadratic function is calculated as follows;
6 + (x + 3)² = 0
subtract 6 from both sides of the equation;
6 + (x + 3)² - 6 = 0 - 6
(x + 3)² = - 6
take square root of both sides
x + 3 = √-6
x + 3 = 6i
x = 6i - 3
Thus, the solution of a quadratic equation can be determined solving for the value of unknown in the equation.
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Given the following information, determine which lines, if any, are parallel. State the converse that justifies your answer.
1. angle j and k.
Due to the Converse of Corresponding Angles Postulate, j || k.
2. Angles 2 and 5 are the alternating inner angles of the lines j and k. Given that angle 2 = angle 5,
The Converse of Alternate Interior Angles Theorem states that j || k.
J || K converse alternative interior angles.
what are parallel angles?similarly
3. angle 3 = angle 10 The exterior angles of the lines l and m, respectively, are angle 3 and angle 10. Since the Converse of Alternate Exterior Angles Theorem states that angle 3= angle 10, l || m.
converse alternative exterior angles l || m.
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how much is 2 gallons in quarts
how much is 2 gallons in quarts
Answer:
8 quarts
The height of a pole is 15 feet. A line with banners is connected to the top of the poleto a point that is 8 feet from the base of the pole on the ground. How long would theline with banners need to be in order for the pole to be at a 90° angle with the ground?Explain your reasoning.
In order to have a 90º angle (right angle) the length of the line with banners needs to fullfit the Pythagorean theorem: In a right triangle the squared hypotenuse is equal to the sum of the legs squared:
[tex]h^2=l^2+l^2[/tex]In the given situation the hypotenusa is the line with banners, and the legs are the pole and the 8ft ground from the base of the pole to the end of the line with banners:
h= x
l= 15ft
l= 8ft
[tex]x^2=(15ft)^2+(8ft)^2[/tex]Solve the equation to find the value of x:
[tex]\begin{gathered} x^2=225ft^2+64ft^2 \\ x^2=289ft^2 \\ x=\sqrt[]{289ft^2} \\ x=17ft \end{gathered}[/tex]Then, to make a right triangle the length of the line witg banners need to be 17ft4x+10=30
solve it please
Answer:
x = 5
Step-by-step explanation:
4x + 10 = 30 ( subtract 10 from both sides )
4x = 20 ( divide both sides by 4 )
x = 5
Answer:
x = 5
Step-by-step explanation:
4x + 10 = 30
Step 1:
30 - 10 = 4x
20 = 4x
Step 2:
20/4
x=5
Step 3: Prove your answer correct
4(5) + 10 = 30
20 + 10 = 30
x = 5
Use the Distributive Property to rewrite each product below. Simplify your answer.
A.) 28 · 63
B.) 17 (59)
C.) 458 (15)
As per the concept of distributive property, the values of
A.) 28 · 63 = 1768
B.) 17 (59) = 1003
C.) 458 (15) = 6870
Distributive property:
Distributive property states that, " multiplying the sum of two or more addends by a number produces the same result as when each addend is multiplied individually by the number and the products are added together."
It can be written as expression like the following,
A( B + C) = AB + AC
Given,
Here we have the expressions,
A.) 28 · 63
B.) 17 (59)
C.) 458 (15)
Now, we have to find the solution for this by using the distributive property.
Now, we have to expand the given expressions by using the distributive property then we get,
A) 28. ( 60 + 3) = (28 x 63) + (28 x 3)
=> 1680 + 84
=> 1768
Similarly, we have simplify the next expression as,
B) 17 (59) = 17 x (50 + 9)
As per the distributive property,
17 x (50 + 9) = (17 x 50) + (17 x 9)
=> 850 + 153
=> 1003
Finally, applying the distributive law, we get,
C) 458 (15) = (450 + 8) x 15
=> (450 x 15) + (8 x 15)
=> 6750 + 120
=> 6870
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Rosa receives money from her relatives every year on her birthday. Last year, she received a total of $350. This year, she received $441. What is the percent of increase in Rosa’s annual birthday money?
Answer:
26%
Step-by-step explanation:
use a online percentage calculator
This is lines, functions and systems. Graph the line with slope 2/3 passing through the point (2, 1).
Note that the slope is expressed as :
[tex]\text{slope}=\frac{\text{rise}}{\text{run}}[/tex]From the given, the slope is 2/3
[tex]\text{slope}=\frac{\text{rise}}{\text{run}}=\frac{2}{3}[/tex]So it means that from the point (2,1)
You need to rise 2 units upward and run 3 units to the right
It will be look like this :
Next step is to connect these two points by drawing a line.
That's it, the line is in blue line.
Solve the system of two linear inequalities graphically.Sy < -2x + 3y > 6x – 9Step 1 of 3: Graph the solution set of the first linear inequality.
The red graph represents y < -2x + 3
The blue graph represents y > 6x - 9
The solutions of the system of inequalities lie on the red-blue shaded
The part which has two colors
Since the first inequality is y < -2x + 3, the shaded is under the line
Since the second inequality is y > 6x - 9, the shaded is over the line
The common shaded of the two colors represents the area of the solutions of the 2 inequalities
The type of boundary lines is dashed
The points on the boundary lines are
For the red line (0, 3) and (4, 0)
For the blue line (0, -9) and (1, -3)
There is a common point on the two lines (1.5, 0)
Find the equation of the line with slope = 5 and passing through (-7,-29). Write your equation in the form
y = mz+b.
Answer:
[tex]y =5x+6[/tex]
Step-by-step explanation:
In the equation, [tex]y=mx+b[/tex], the "m" represents the slope, and the b represents the y-intercept.
We know the slope is 5, so we already know part of the equation: [tex]y=5x+b[/tex]
To solve for the "b" part or y-intercept, we can simply plug in a known point on the line, which was given to be (-7, -29)
This gives us the following equation:
[tex]-29 = 5(-7) + b\\\text{simplify}\\-29 = -35 + b\\\text{add 35 to both sides}\\6=b[/tex]
Answer: y = 5x + 6
Step-by-step explanation:
1. Do point-slope formula {(y - y1) = m(x - x1})
(y - 29) = 5(x - 7)
Distribute
(y - 29) = 5x - 35
Subtract 29 on both sides
Cancel out y - 29 - 29
y = 5x + 6
Carrie sold 112 boxes of cookies, Megan sold 126 boxes of cookies, Julie sold 202 boxes of cookies, and Ashton sold 176 boxes of cookies. what was the average number of boxes of cookies sold by each individual
Answer:
154 boxes.
Explanation:
To calculate the average number of boxes of cookies sold by each individual, we use the formula:
[tex]\text{Average=}\frac{\text{Sum of all boxes sold}}{\text{Number of individuals}}[/tex]This gives:
[tex]\begin{gathered} \text{Average}=\frac{112+126+202+176}{4} \\ =\frac{616}{4} \\ =154\text{ boxes} \end{gathered}[/tex]The average number of boxes of cookies sold by each individual was 154 boxes.
Paola says that when you apply the Distributive Property to multiply (3j+6) and (-5j), the result will have two terms. Is she correct?
Explain.
Choose the correct answer below.
A. No, because there will be one j-term
B. Yes, because there will be a j-term and a j²-term
C. Yes, because there will be a j-term and a numeric term
D. No, because there will be one j2-term
The Distributive Property to multiply (3j+6) and (-5j), the result will have two terms because there is a j-term and a j²-term.
What is distributive property of multiplication over addition ?
If we multiply a number by the sum of more than two, we use the distributive property of multiplication over addition.
Here the expression given is :
(3j+6) and (-5j)
and it is to multiply using Distributive Property of multiplication :
now, applying that ;
(3j+6) x (-5j)
= 3j x (-5j) + 6 x (-5j)
= -15j² - 30j
It is seen from the above expression that the Distributive Property to multiply (3j+6) and (-5j), the result will have two terms because there is a j-term and a j²-term.
Therefore, option B is the correct answer.
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1 3/8 × 3 2/3=answer must be in simplest fraction form
EXPLANATION
Given the fractions 1 3/8 and 3 2/3
First we need to turn both fractions into improper ones
[tex]1\frac{3}{8}=\frac{11}{8}[/tex][tex]3\frac{2}{3}=\frac{11}{3}[/tex]Now, multiplying both fractions:
[tex]\frac{11}{8}\cdot\frac{11}{3}=\frac{121}{24}[/tex]The answer is 121/24