Answer:
As Per Given Information
20x objective lens was used by specimen
10x ocular lens was also used by him.
we have to find the total magnification.
For calculating the total magnification we 'll simply do multiplication
Total Magnification = 20x × 10x
Total Magnification = 200x
So , the total magnification will be 200x .
The total magnification is 200 X
What is Magnification of lens ?
Magnification of lens simply means enlarging or diminishing the image of an object form by the lens used.
Given Information in the question :
Magnification of objective lens used by specimen = 20x
Magnification of ocular lens used by him = 10x
Now the total magnification of lens is calculated below :
[tex]\begin{aligned}\text{Total magnification} &= \text{Objective magnification} \times \text{ocular magnification}\\&=20\times \cdot 10\times\\&= 200\times\end{aligned}[/tex]
Therefore, The total magnification is 200 X which means image will appears 200 times larger then the original object.
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A cell phone uses a 3. 0 V battery. The circuit board it uses needs a 0. 05 A current. What size resistor is needed to generate this current?.
The value of resistance will be 60 ohms. Resistance is the ratio of the voltage to the electric current passing through the wire.
What is a resistor?A resistor is a two-terminal passive electrical component that acts as a circuit element by implementing electrical resistance.
Resistors are used to limit current flow, alter signal levels, divide voltages, bias active devices, and complete transmission lines in electronic circuits.
The given data in the problem is;
V is the voltage = 3. 0 V
I is value of current= 0. 05 A
R is the resistance=?
According to ohm's law, the potential difference between the two ends of the conductor is equal to the product of electric current and the resistance generated.
So from the ohm law;
V= IR
[tex]\rm R = \frac{V}{I} \\\\ \rm R = \frac{3}{0.05} \\\\ \rm R =60 \ ohm[/tex]
Hence the value of resistance will be 60 ohms.
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25. A wave has a frequency of 46 Hz and a wavelength of 1.7 meters. What is the speed of this wave?
Answer:
78.2 m/time
Explanation:
Wavelength =Speed/Frequency
Speed = 46 x 1.7 =78.2 m/time.
3.
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a
mass of 0.025 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a
collision with puck B, which has a mass of 0.050 kg and is initially at rest. The collision is
not head-on. After the collision the two pucks fly apart with the angles shown in the
drawing. Find the final speed of (a) puck A and (b) puck B. (Cutnell 7.30) 3.4 m/s, 2.6 m/s
+5.50
The final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.
Conservation of linear momentum
The final speed of the pucks is determined by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.025(5.5) + 0.05(0) = 0.025v₁ + 0.05v₂
0.1375 = 0.025v₁ + 0.05v₂
One direction linear velocityu₁ + v₁ = u₂ + v₂
5.5 + v₁ = 0 + v₂
v₁ = v₂ - 5.5
0.1375 = 0.025(v₂ - 5.5) + 0.05v₂
0.1375 = 0.025v₂ - 0.1375 + 0.05v₂
0.275 = 0.075v₂
v₂ = 0.275/0.075
v₂ = 3.7 m/s
v₁ = 3.7 - 5.5
v₁ = -1.8 m/s
Thus, the final speed of puck A is 1.8 m/s and the final speed of puck B is 3.7 m/s.
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The volume of helium in a blimp is 6. 28 × 109 milliliters. The density of helium in the blimp is 0. 1786. Find the mass of the helium in the blimp. (Hint: 1,000 L = 1 cubic meter. ) A. 1,120 kg B. 1. 12 kg C. 3. 52 × 107 kg D. 2,840 kg.
Density is defined as the ratio of the mass per unit volume. Its unit is kg/m³. the mass of the helium in the blimp is 1.22 × 10⁻³ kg.
What is density?Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
The mass and density relation is given as
mass = density × volume
The given data in the problem as ;
v is the volume of gas=-6.28 × 109 ml =6.8452 × 10⁻³ cubic centimeter
ρ is the density = 0.1786 kg/cm³
m is the mass of helium gas =?
The mass and density relation is given as
mass = density × volume
m=ρv
m=0.1786 ×( 6.8452 × 10⁻³)
m=1.22 × 10⁻³ kg
Hence the mass of the helium in the blimp is 1.22 × 10⁻³ kg.
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When the rocket launched the astronauts aboard experienced an acceleration of 32 m/s^2. If one of the astronauts had a mass of 65 kg, what net force in newtons did the astronaut experience?
Answer:
The question is somewhat vague in that acceleration is not exactly defined:
Usually a = (v2 - v1) / t which would imply that
a = 32 / g = 32 / 9.8 = 3.27 the acceleration due to change in speed of the rocket
One can also say that the astronaut experiences an acceleration of 9.8 m/s^2 just by being motionless on the surface of the earth.
Then a = (32 - 9.8) / 9.8 = 2.27 due to the acceleration of the rocket
If we assume the first condition then
F = 65 kg * 3.27 * 9.8 m/s^2 = 2083 N
a car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105m. what was its acceleration
Answer:
3.088 m/s²
Explanation:
Let's see which variables we are given in this problem.
Δx = -105 mv₀ = -27.7 m/sv = -10.9 m/sa = ?The kinematics equation that includes these four variables is:
v² = v₀² + 2aΔxSubstitute the known variables into the equation and solve for a.
(-10.9)² = (-27.7)² + 2a(-105)118.81 = 767.29 - 210a -648.48 = -210a a = 3.088 m/s²The car's acceleration while slowing down from 27.7 m/s to 10.9 m/s in 105 m is 3.088 m/s².
This type of bike tire is thinner, lighter, more expensive, and punctures easily.
A. Clinches
B. Tubular
15 POINTS! I will give Brainliest.
Answer:tublar
Explanation:tublar bikes usaly cost 30-40% more
Answer:
Tubular
Explanation:
In terms of puncture resistance, tubular tyres also rank better than clincher tyres which are prone to pinch flats. However, one staple, nail, or piece of glass can be the end of your tubular tyre, whereas a punctured clincher can be reused with a new inner tube. A tubular tyre can also be ridden safely while flat
