In QRS, s=4.2 cm, R-160° and S-8°. Find the length of r, to the nearest 10th of
a centimeter.

The inequalities that represent Chocolate and Saffron in a gift bag are

x + 2y<7 and x + y <5.

In mathematics, inequalities specify the connection between two non-equal numbers. Equal does not imply inequality. Typically, we use the "not equal sign ()" to indicate that two values are not equal. But several inequalities are utilized to compare the numbers, whether it is less than or higher than.

Given, To'ak Chocolate is the rarest chocolate in the world with a cost of $5 per gram. Saffron is a spice used for flavoring and coloring foods and costs $10 per gram.

Let x be the number of grams of chocolate and y be the number of grams of saffron

Hence,

Cost of chocolate = 5x

Cost of spices = 10y

Also given She has to keep the cost to less than $35

Thus, the Linear equation

5x + 10y < 35

Divide by 5 into both sides

x = 2y < 7

Also given, A party planner for a celebrity event wants to include no more than 5 grams (g) of To'ak Chocolate and Saffron in a gift bag.

Thus, x + y < 5

therefore, The inequalities x + 2y < 7 and x + y < 5 depict the combination of chocolate and saffron in a gift bag.

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Complete question:

To'ak Chocolate is the rarest chocolate in the world with a cost of $5 per gram. Saffron is a spice used for flavoring and coloring foods and costs $10 per gram. A party planner for a celebrity event wants to include no more than 5 grams (g) of To'ak Chocolate and Saffron in a gift bag. She has to keep the cost to less than $35. Write a system of inequalities where x is the number of grams of To’ak Chocolate and y is the number of grams of Saffron in each gift bag.

If a man has a collection of stamps made up of 5 cent stamps and 8 cent stamps and there are three times as many 8 cent stamps as 5 cent stamps. The number of each stamp he have is: 5 cent stamp is 12, 8 cent stamp is 36.

Let x represent 5 cent =  0.05x + 0.08 = 3.48

Let y  represent 8 cent = 3x

Hence,

0.05x + 0.08(3x)= 3.48

0.05x + 0.24x = 3.58

Combine like terms

0.29x = 3.58

Divide both side by 0.29x

x = 3.58/0.29

x =12 (5 cent stamps)

Now let solve for y

y =3x

y =3(12)

y = 36 (8 cent stamps)

Therefore the number of each stamp he have is: 5 cent stamp is 12, 8 cent stamp is 36.

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All the measures of central tendency are, The median, The mode, and The mean.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

There are some measures,

A. The median

B. A sample statistic

C. The mode

D. The lowest value

E. The mean

We know that;

The four measures of central tendency are mean, median, mode and the midrange.

Here, mid-range or mid-extreme of a set of statistical data values is the arithmetic mean of the maximum and minimum values in a data set.

Hence, All the measures of central tendency are, The median, The mode, and The mean.

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Answer:

w(n)= -20

Step-by-step explanation:

w(9)=-2(9)-2

= -18-2

=-20

Answer:

w(9) = -20

Step-by-step explanation:

w(n) = −2n – 2

w(9) = −2(9) – 2

w(9) = -18 - 2

w(9) = -20

Answer: below :)

Step-by-step explanation:

1. Line AB

2. Ray AB

3. Line segment AB

4. Ray BA

Answer:

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 2 gives the next term.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The percentage of pink is 13%.

There are 28 numbers in total that are odd numbers greater than 500 with no digit being repeated.

First, there are 18 odd numbers with four digits, and all of them are greater than 500. To see that, starting from the end of the number, there are 3 options for the last digit, 3 for the second last, 2 for the second digit, and 1 for the first digit. Multiplying one gets 3*3*2*1=18.

Second, for numbers with 3 digits, in order to be greater than 500, it must start either with 5 or with 6. If it starts with 5, there are 2 options for the last digit and 2 options for the second digit.

Thus, there are 4 different numbers in this case. Finally, if it starts with 6, then there are 3 options for the last digit and 2 options for the second digit. Thus, there are 6 different numbers in this case.

Complete question: How many different odd numbers greater than 500 can be made using some or all of the digits 1,3,5 and 6 with no digit being repeated?

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As per the permutations, there as 36 three digit numbers that are greater than 500 and which are odd one also.

The term permutation in math is defined as the way of arranging objects or numbers in order.

Here we have given that we have to identify the 3 digit numbers greater than 500 are odd

Let us make three digit numbers 1st

Here we know that if we want odd number at end then one number from three numbers can come there so

=> 3P1

Then the rest of the two numbers don't matter so

Then it can be written as

=> 3P2

Then the overall combination is written as

=> 3P1 * 3P2=18

Here now let us make four digit numbers

Then the digit odd again and it can be written as

=> 3P1

Here also the rest of the order Doesn't matter so

then it can be written as

=> 3P3 =6

Then the four digit value is

=> 3p1 * 3p3= 18

Therefore, the overall count is written as

=> Overall = 18+18= 36

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Answer:

6.45 kg

Step-by-step explanation:

250 g is equal to 0.25 kg, so the pumpkin weighs [tex]2+0.25=2.25[/tex] kg.

Thus, the combined weight is [tex]2.25+4.2=6.45[/tex] kg.

Answer:

Step-by-step explanation:

(-5,7)

The maximum possible outcome for the situation is 36.

The number of favorable events to all the events in an experiment is the ratio that makes up the probability formula. Theoretical probability, Experimental probability, and Axiomatic probability are the three categories into which probability can be divided.

We have been Given that Ruby is designing a new board game and is trying to figure out all the possible outcomes.

Ruby flips a coin, rolls a fair die in the shape of a cube that has six sides labeled 1 to 6, and spins a spinner with three equal-sized sections labeled Walk, Run, Stop.

we know that there are 3 things happening simultaneously and favorable moments will be chosen by all three.

Thus, Maximum possible outcome are;

2 x 6 x 3 = 36

Therefore, For the given, 36 outcomes are available in total.

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Answer:

$142.2

Step-by-step explanation:

First we know that we have $112

Then we calculate 112+27% and we get 142.24

Round that up and you get $142.2

Answer: -4(a+3)

Step-by-step explanation:

You can take out -4 from -4 and -12

Answer:

-4(a+3)

Step-by-step explanation:

Right on edge!

Answer: The quarter

Step-by-step explanation:

The quarter is larger and there are more quarters than there are any other coins in her pocket.

Answer:

$29.88

Step-by-step explanation:

We first would need to figure out what 20% of $37.35 is.

0.2 (or 0.20) × 37.35 = 7.47

This means that the discount price is $7.47

Now subtract that from the total.

37.35 - 7.47 = 29.88

Therefore, his total in dollars and cents after the discount and before tax is twenty-nine dollars and eighty-eight cents.

The trigonometric ratios are;

We know that the trigonometric ratios would have to do with the ratios such as the sine the cosine and the tangent of the angle. In This case, we would need to obtain the side AB and this is by the Pythagoras theorem;

/AB/^2 = /AC/^2 + /BC/^2

/AB/ = √ /AC/^2 + /BC/^2

/AB/ = √(9)^2 + (12)^2

/AB/ = 15

Then;

Sin A = 12/15

Cos A = 9/15

Tan A = 9/12

These are the ratios for the right angle triangle

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A. The coefficient of x^4y^{12} in the expansion of (-4x+2y)^{16} is -8192.

B. The coefficient of x^4y^8z^7 in the expansion of (-4x+2y-1z)^{19} is -134217728.

For the first question, we can use the binomial theorem to expand the expression. The binomial theorem states that

(a+b)^n = C(n,0)a^nb^0 + C(n,1)a^{n-1}b^1 + C(n,2)a^{n-2}b^2 + ... + C(n,n)a^0b^n

Where C(n,k) = n!/(k!(n-k)!)

Applying this to the given expression, we get:

(-4x+2y)^{16} = C(16,0)(-4x)^{16}(2y)^0 + C(16,1)(-4x)^{15}(2y)^1 + C(16,2)(-4x)^{14}(2y)^2 + ... + C(16,16)(-4x)^0(2y)^16

The coefficient of x^4y^{12} is the coefficient of the term -4x^42y^{12} in this expansion, which is

C(16,4)(-4)^42^{12} = C(16,4)(-256)4096 = C(16,4)(-256)*4096 = -8192

For the second question, the same logic can be applied to:

(-4x+2y-1z)^{19} = C(19,0)(-4x)^{19}(2y)^0(-1z)^0 + C(19,1)(-4x)^{18}(2y)^1(-1z)^0 + C(19,2)(-4x)^{17}(2y)^2(-1z)^1 + ... + C(19,19)(-4x)^0(2y)^0(-1z)^19

The coefficient of x^4y^8z^7 is the coefficient of the term -4x^42y^8(-1z)^7 in this expansion, which is C(19,4)(-4)^42^8*(-1)^7 = C(19,4)256256*-1 = -134217728

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Answer: nomial  data

Step-by-step explanation:

Answer: B. 128a⁶b¹³

Step-by-step explanation:

The area of the rectangle with the dimensions shown below represents :

[tex](2a^2b)^3*(4b^5)^2=\\\\2^3a^{2*3}b^3*4^2b^{5*2}=\\\\8a^6b^3*16b^{10}=\\\\(8*16)a^6b^{3+10}=\\\\128a^6b^{13}[/tex]

Answer:

1/2x - 2 = Graph D, with the x intercept as 4, and the y intercept at

Answer:

D

Step-by-step explanation:

f(x) = mx + b

f(x) = 1/2 x - 2

m is the slope (1/2) and b is the y-intercept (b) -2.

Only graphs C and D cross the y axis at -2 .  That is the point (0, -2)

The slope is 1/2.  That means a rise of 1  space up and a run of 2 spaces left.

If you start at the point (0,-2) and go up 1 space and 2 spaces right, you end up back on the line at the point (4,0).

The measures of all unknown angles and side lengths of δpqr of m∠R = 50 degrees, PR ≈ 5.74 cm, after solving the Pythagorean theorem equation, and PQ ≈ 8.53 cm, after solving the Law of Cosines equation.

In order to determine the measures of all unknown angles and side lengths of ΔPQR, we can use the properties of a triangle. In particular, we can use the fact that the sum of the angles in a triangle is 180 degrees and the Pythagorean theorem.

You can use the above information to find the value of PR and PQ using trigonometric functions and/or squares.

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The question is -

Determine the measures of all unknown angles and side lengths of ΔPQR. Round side lengths to the nearest hundredth.

m∠R =

PR ≈

PQ ≈

C is the most accurate one i guess

For f'(a) is given by f'(a) = 6a + 2 and equation of the line tangent to the graph is y = -10x - 12.

f(x) = 3x² + 2x

f'(x) = 6x + 2

So f'(a) = f'(-2) = -12+2 = -10

In order to find tangent line , we need a slope and a point. We have the x-co-ordinate for our point, so we can plug that in to find Y-coordinate.

F(-2) = 8

The slope of tangent line is the derivative at this point  , f'(-2) = -10

Equation of line tangent,

y - 8 = -10(x - (-2))

y = -10x - 12.

The limit of a function in mathematics is a key idea in calculus and analysis regarding the behavior of that function close to a specific input.

Informally, a function f gives each input x an output f(x). If f(x) approaches L as x approaches input p, we say that the function has a limit L at that location. More specifically, any input that is sufficiently close to p when f is applied forces the output value arbitrarily close to L.

The concept of limit is specifically used in the various definitions of continuity. Roughly speaking, a function is continuous if all of its limits agree with the values of the function. The term "limit" is also used in the definition of the mathematical term "derivative," which in one-variable calculus refers to the maximum value of the slope of secant lines on a function's graph.

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The distance between the ball and pole is divided by the time taken to travel that distance to calculate the rate of shadow travel, which is 80 fps.

The shadow of the ball is moving at a rate of 80 feet per second (fps). This can be calculated as follows:

Distance Fallen = 16t^2

Distance Fallen in 0.5 Seconds

= 16(0.5)^2

= 4 feet

Distance Between Ball and Pole

= 50 feet - 4 feet

= 46 feet

Time Taken To Travel Distance

= 0.5 Seconds

Rate of Travel = 46/0.5

= 80 fps

The shadow of the ball is moving at a rate of 80 fps. This is calculated by taking the distance between the ball and pole (50 feet-4 feet=46 feet) and dividing it by the time taken to travel that distance (0.5 seconds). This results in 80 fps.

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Alex came closer to their grade’s state record for the triple jump.

What is algebra?

The area of mathematics known as algebra is used to help express issues or circumstances into mathematical expressions.

Here, we have

Given:

Alex jumped 38 feet 11 2/3 inches the eighth-grade record is 40.17 feet.

Let's see how closer Alex jumped.

11 2/3 inches = 22* 0.083 = 1.826

38+ 1.826 = 39.826

40.17 -  39.826  = 0.344

Eric, a seventh grader, jumped 36.89 feet. The seventh-grade record is 38 feet 1 3/5 inches.

1 3/5 inches = 8/5*0.083 = 0.1328

38 + 0.1328 = 38.1328

Eric jump was

38.1328 - 36.89 = 1.2428

0.344 is smaller than 1.2428.

Hence, Alex came closer to their grade’s state record for the triple jump.

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By adding all the distances of the branches, we will conclude that Sylvester traveled a distance of 66.74 meters.

We know that Sylvester is a slug, and it travels for four branches, such that the length of each branch is:

To get the total distance that Sylvester travels, we just need to add these 4 numbers, then we will get:

Total distance = 9.01 m + 12.31m + 19.5m + 25.92m

Total distance = 66.74 meters.

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Answer:

< is angle, Dont be confused

m<1= 51

m<2=39

m<3=90

m<4=51

m<5= 17

m<6= 129

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Answer:

Below

Step-by-step explanation:

x = third part

5/9 x    + 5/9 x  + x   = 114    <=======given

19/9  x = 114

x = 114 * 9/19 = 54 cm      then the other two are 30 cm each

Answer:

The two equal parts are 30 cm, the third part is 54 cm

Step-by-step explanation:

x =  third part

(5/9)x + (5/9)x + x = 114

10/9(x) + x = 114

(19/9)x = 114

x = 114(9/19) = 54

(5/9)54 = 30

Answer:

LMNO is a parallelogram in which bisectors of the angles L, M, N, and O intersect at P, Q, R, and S to form the quadrilateral PQRS. Hence the angle bisectors of a parallelogram form a rectangle as all the angles are right angles; we conclude that it IS RECTANGLE. Hence proved.

On solving the provided question, we can say that the value of the ellipse from give data will be = 4/9 + 9/36 = OD. (-2,4±3√3)

In mathematics, an ellipse is a planar curve that encompasses two focus points and ensures that the sum of the two distances from any point on the curve to the focal points is constant. In doing so, the circle—a particular variety of ellipse with two equal focus points—is generalized. The ellipse, whose eccentricity is less than 1, indicates the area containing the points whose distances from its two foci add up to a certain amount. Running tracks in sporting arenas and 2D egg forms are two straightforward examples of ellipses in daily life.

[tex](x+2)^2/9 + (y-4)^2/ 36 = 1[/tex]

x = 0 and y = 1

4/9 + 9/36

OD. (-2,4±3√3)

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