Explanation
To begin with, we will first have to obtain the length of side VX
[tex]VX^2=WX^2+VW^2-2\times WX\times VWcosw[/tex]In our case
[tex]\begin{gathered} WX=28t \\ VW=95t \\ w=94^0 \end{gathered}[/tex]Thus
[tex]\begin{gathered} VX^2=(28t)^2+(95t)^2-2\times(28t\times95t)cos94 \\ \\ VX^2=784+9025+371.104 \\ VX^2=100180.10 \\ \\ VX=100.90t \end{gathered}[/tex]Next, we will determine the angles at V and X
using sine rule
[tex]\begin{gathered} \frac{sin94}{100.9t}=\frac{sinV}{28t} \\ \\ sinV=\frac{28t\times sin94}{100.9t} \\ \\ sinV=0.27683 \\ \\ V=16.07^0 \\ \end{gathered}[/tex]Then, we will get the measure at X
[tex]180^0-16.07^0-94=69.93^0[/tex]Therefore, the order from smallest to largest angles will be
m
OR
m
in a triangle one angle is three times the smallest angle and the third angle is 45 more than twice the smallest angle. find the measure of all 3 angles. Hint: the angles of a triangle add up to 180.
Please show me full steps. I need help.
The angles are 22.5°, 67.5° and 90°.
How to calculate the angle?Let the smallest angle = x
Total angles in a triangle = 180°
One angle is three times the smallest angle. This will be 3x.
The third angle is 45 more than twice the smallest angle. This will be:
= (2 × x) + 45
= 2x + 45
The angles will be:
x + 2x + 45 + 3x = 180
6x + 45 = 180
Collect like terms
6x = 180 - 45
6x = 135
Divide
x = 135 / 6
x = 22.5°
Smallest angle = 22.5°
The other angles will be calculated by substitutibg 22.5° for x. This will be:
3x = 3 × 22.5 = 67.5°
Also, 2x + 45 = 2(22.5) + 45 = 90°
This illustrates the concept for angles in a triangle.
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Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
we have that
F=m*a
we have
m=30 kg
F=60 N
substitute in the formula
60=30*a
solve for a
a=60/30
a=2 m/s^2
therefore
the answer is 2 meters per second squaredUse the pythagorean theorem to find the distance between (2,8) and (-8,2) A. 16.0 B. 4.0 C. 12.3 D. 11.7
Using the Pythagorean theorem, the distance between two points (x1, y1) and (x2, y2) is gotten as follows:
[tex]\begin{gathered} d^2=(x_2-x_1)^2+(y_2-y_1)^2 \\ \text{Thus:} \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}[/tex]Since we have the two coordinates: (2, 8) and (-8, 2)
where:
(x1, y1)= (2, 8)
(x2, y2) = (-8, 2)
Therefore, the distance between them is:
[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{((-8)_{}-2_{})^2+(2-8)^2} \\ d=\sqrt[]{((-10_{})^2+(-6)^2} \\ d=\sqrt[]{100+36} \\ d=\sqrt[]{136} \\ d=11.66 \\ d=11.7\text{ (to one decimal place)} \end{gathered}[/tex]Therefore, the distance between the two p is: 11.7
Correct option is: Option D
Which options show polynomial 1 bring divided into polynomial 2? SELECT ALL THAT APPLY
Hello. This is an exercise about polynomials.
In this specific question, we will see about the division of polynomials:
We have two polynomials:
• First: 2x
,• Second: 6x²-10x
Now, we'll have to divide the first by the second. We have some ways to write this:
The third and fourth options are wrong because it divides the second polynomial by the first, while the question asks the first divided by the second.
Find the coordinates of the vertex of the graph of y=4-x^2 indentify the vertex as a maximum or minimum point A.(2,9);maximumB.(0,4);minimumC.(0,4);maximum D.(2,0);minimum
Let's begin by identifying key information given to us:
[tex]\begin{gathered} y=4-x^2 \\ y=-x^2+4 \\ a=-1,b=0,c=4 \\ x_v=-\frac{b}{2a}=-\frac{0}{2(-1)}=0 \\ y_v=-\frac{b^2-4ac}{4a}=-\frac{0^2-4(-1)(4)}{4(-1)} \\ y_v=-\frac{0+16}{-4}=\frac{-16}{-4}=4 \\ y_v=4 \\ \\ \therefore The\text{ vertex of the equation is }(0,4) \end{gathered}[/tex]To know if the vertex is the maximum or minimum point, we will follow this below:
[tex]\begin{gathered} y_v=4 \\ \Rightarrow This\text{ is a minimum point} \end{gathered}[/tex]Hence, the answer is B.(0,4); minimum
Given AFGH ~ ALMN, which must be true? Select all that apply.A.FGLMFHLNB. FH ~ LNC.mZFmZLmZGmZMD. GHMNE. mZH ^mZN
My answer is correct or no please check
Answer:
D) 5 minus a number M
hope this helps!
Answer:
Yep. You got it right. Good job!
Step-by-step explanation:
One package of markers has dimensions 6"×8"×1"what are the dimensions of the box that will hold 30 packages of markers and use the LEAST amount of cardboard? A. 6"×8"×30" B. 6"×16"×15" C. 10"×10"×10"D. 12"×8"×15" E. 18"×8"×10
The required Dimensions are 6'' x 8'' x 30'' , That is option A
A population forms a normal distribution with a meanof μ = 85 and a standard deviation of o = 24. Foreach of the following samples, compute the z-score forthe sample mean.a. M=91 for n = 4 scoresb. M=91 for n = 9 scoresc. M=91 for n = 16 scoresd. M-91 for n = 36 scores
In this problem, we have a population with a normal distribution with:
• mean μ = 85,
,• standard deviation σ = 24.
We must compute the z-score for different samples.
The standard deviation of a sample with mean M and size n is:
[tex]σ_M=\frac{σ}{\sqrt{n}}.[/tex]The z-score of the sample is given by:
[tex]z(M,n)=\frac{M-\mu}{\sigma_M}=\sqrt{n}\cdot(\frac{M-\mu}{\sigma})[/tex]Using these formulas, we compute the z-score of each sample:
(a) M = 91, n = 4
[tex]z(91,4)=\sqrt{4}\cdot(\frac{91-85}{24})=0.5.[/tex](b) M = 91, n = 9
[tex]z(91,9)=\sqrt{9}\cdot(\frac{91-85}{24})=0.75.[/tex](c) M = 91, n = 16
[tex]z(91,16)=\sqrt{16}\cdot(\frac{91-85}{24})=1.[/tex](d) M = 91, n = 36
[tex]z(91,9)=\sqrt{36}\cdot(\frac{91-85}{24})=1.5.[/tex]Answera. z = 0.5
b. z = 0.75
c. z = 1
d. z = 1.5
Write in terms of confunction of a complementary angle:tan 26°
ANSWER
The cofunction of tan 36 degrees is cot 54 degrees
STEP-BY-STEP EXPLANATION
Given information
[tex]\text{tan 26}\degree[/tex]Co function of tan can be written below as
[tex]\begin{gathered} \tan \text{ }(A)\text{ = cot (B)} \\ \text{if, A + B = 90} \end{gathered}[/tex][tex]\begin{gathered} \text{tan 36 = cot (90 - 36)} \\ \tan \text{ 36 = cot 54} \end{gathered}[/tex]Therefore,
tan 36 = 0.7265
cot 54 = 0.7265
Hence, the cofunction of tan 36 is cot 54
For these problems, please show your algebraic work using logarithms. 1. Determine the doubling time for each situation listed below. a. A population is growing according to P = P_0e^0.2t b. A bank account is growing by 2.7% each year compounded annually.
Answer: We need to find the doubling time for population growth:
Population growth is given by
[tex]P=P_oe^{(0.2)t}[/tex]Where:
[tex]\begin{gathered} P\rightarrow\text{final} \\ P_o\rightarrow I\text{nitial} \end{gathered}[/tex]For the population to double, it implies that:
[tex]P=2P_o[/tex]Therefore:
[tex]\frac{P}{P_o}=\frac{2P_o}{P_o}=2=e^{(0.2)t}[/tex]Solving for time "t" gives:
[tex]2=e^{(0.2)t}\rightarrow\ln (2)=(0.2)t\rightarrow t=\frac{\ln (2)}{(0.2)}=3.46u[/tex]740In the table on the right there are grades that were earned by students on a midtermbusiness math exam What percent of the students earned a grade below 80?83977084986685687783958879648890859396The percent of students with grade below 80 is(Round to the nearest whole number as needed)
Notice that the number of students that got a grade below 80 is:
[tex]7,[/tex]and the total number of students is:
[tex]20.[/tex]Therefore, we have to determine what percentage 7 represents from 20. To determine the percentage that x represents from y, we can use the following expression:
[tex]\frac{x}{y}*100.[/tex]Finally, we get that 7 represents the
[tex]\frac{7}{20}*100=35\%,[/tex]of 20.
Answer:
[tex]35\%.[/tex]Use the fact that 521•73=38, 033.Enter the exact product of 5.21•7.3
Answer: 38.033
5.21 x 7.3
= 38.033
Find decimal notation for 100%
The decimal notation of percentage is the quotient of the percentage divided by 100.
So it follows that :
[tex]\frac{100\%}{100}=1[/tex]The answer is 1
How many true, real number solutions does the equation n + 2 = -16-5n have?solution(s)
The equation is
n + 2 = - 16 - 5n
By collecting like terms, we have
n + 5n = - 16 - 2
6n = - 18
Dividing both sides of the equation by 6, we have
6n/6 = - 18/6
n = - 3
It has only one solution
simplify x⁹ divided by x^5
Answer:
[tex]x^{4}[/tex]
Step-by-step explanation:
Whenever it comes to the division of the same variable, we subtract their powers in order to get the correct answer:
[tex]x^{9}/x^{5}[/tex]
[tex]x^{9-5}[/tex]
[tex]x^{4}[/tex]
help me please if you can A.(0, 3)B. (-1, 5)C.(1, 1.5)
Answer:
A. (0, 3)
C. (1, 1.5)
Explanation:
A point is a solution to the system if it satisfies both inequalities.
So for each option, we get:
Replacing (x, y) = (0, 3)
y ≥ -2x + 3
3 ≥ -2(0) + 3
3 ≥ 3
y ≤ -x² - x + 4
3 ≤ -0² - 0 + 4
3 ≤ 4
Since both inequalities are satisfied, (0, 3) is a solution.
For (x, y) = (-1, 5)
y ≥ -2x + 3
5 ≥ -2(-1) + 3
5 ≥ 2 + 3
5 ≥ 5
y ≤ -x² - x + 4
5 ≤ -(-1)² - (-1) + 4
5 ≤ -1 + 1 + 4
5 ≤ 4
Since 5 is not lower than 4, (-1, 5) is not a solution
For (x, y) = (1, 1.5)
y ≥ -2x + 3
1.5 ≥ -2(1) + 3
1.5 ≥ -2 + 3
1.5 ≥ 1
y ≤ -x² - x + 4
1.5 ≤ -(1)² - (1) + 4
1.5 ≤ -1 - 1 + 4
1.5 ≤ 2
Since both inequalities are satisfied, (1, 1.5) is a solution.
Therefore, the answers are
A. (0, 3)
C. (1, 1.5)
In the diagram below , ^PQR = ^STR . Complete the statement
Given:
[tex]\Delta\text{PQR}\cong\Delta\text{STR}[/tex]Since it is given that triangles PQR and STR are congruent, the corresponding angles of the triangles are equal.
Hence,
Therefore, option D is correct.
rectangle rstw has diagonals RT and SW that intersect at Z. If RZ= 5x+8 and SW= 11x-3 find the value of x.
Answer:
19
Explanation:
We know that the diagonals of a rectangle are always equal, therefore RT = SW.
So if RZ = 5x + 8 and SW = 11x - 3, lets's go ahead and find x as shown below;
[tex]\begin{gathered} 2(5x+8)=11x-3 \\ 10x+16=11x-3 \\ 16+3=11x-10x \\ 19=x \\ \therefore x=19 \end{gathered}[/tex]Your friend says, "If a quadrilateral has a pair of opposite sides that are congruent 6 points and a pair of opposite sides that are parallel, then it is a parallelogram." What is your friend's error? Explain.
to be a parallelogram we need to have the 2 pairs of sides to be parallel so the correct option is C
What is 35% of 125?
The 35% of 125 is computed as follows:
[tex]125\cdot\frac{35}{100}=43.75\text{ \%}[/tex]How many solutions does the following equation have? - 6(x + 7) = - 4x – 2 А. No solutions B.Exactly one solution C.Infinitely many solutions
ANSWER
Exactly one solution.
EXPLANATION
We are given the equation:
-6(x + 7) = -4x - 2
To find the number of solutions, we have to solve for x:
-6x - 42 = -4x - 2
Collect like terms:
-6x + 4x = 42 - 2
-2x = 40
x = 40 / -2
x = -20
Therefore, the equation has exactly one solution.
After a translation, the image of P(-3, 5) is P'(-4, 3). Identify the image of the point (1, 6) after this same translation.
The image of the point (1, 6) after the translation is (0, 4).
What is named as translation?In geometry, translation refers to a function that shifts an object a specified distance. The object is not elsewhere altered. It has not been rotated, mirrored, or resized.Every location of the object should be relocated in the same manner and at the same distance during a translation.When performing a translation, this same initial object is referred to as the pre-image, as well as the object that after translation is referred to as the image.For the given question,
The image of point P(-3, 5) after a translation is P'(-4, 3).
In this, there is a shift of 1 units to the left of x axis and shift of 2 units up on the y axis.
Thus, do the same translation for the point (1, 6).
After translation image will be (0, 4)
Thus, image of the point (1, 6) after the translation is (0, 4).
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The volume of a right circular cylinder with a radius of 4 in. and a height of 12 in. is ___ π in^3.
For the given right cylinder:
Radius = r = 4 in
Height = h = 12 in
The volume of the cylinder =
[tex]\pi\cdot r^2\cdot h=\pi\cdot4^2\cdot12=192\pi[/tex]So, the answer will be the volume is 192π in^3
A local band was interested in the average song time for rock bands in the 1990s. They sampled eight different rock bands and found that the average time was 3.19 minutes with a standard deviation of 0.77 minutes.
Calculate the 95% confidence interval (in minutes) for the population mean.
The 95% confidence interval (in minutes) for the population mean is of:
(2.55, 3.83).
What is a t-distribution confidence interval?The bounds of the confidence interval are given according to the following rule:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which the parameters are described as follows:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.The distribution is used when the standard deviation of the population is not known, only for the sample.
In the context of this problem, the values of the parameters are given as follows:
[tex]\overline{x} = 3.19, s = 0.77, n = 8[/tex]
The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 63 df, is t = 2.3646.
Then the lower bound of the confidence interval is calculated as follows:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 3.19 - 2.3646\frac{0.77}{\sqrt{8}} = 2.55[/tex]
The upper bound is calculated as follows:
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 3.19 + 2.3646\frac{0.77}{\sqrt{8}} = 3.83[/tex]
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identify the slope: 6x - 2y = -6
The slope = 3
Explanations:Note that:
The slope - Intercept form of the equation of a line takes the form y = mx + c
where m is the slope and
c is the intercept
The given equation is:
6x - 2y = -6
The equation can be re-written as:
2y = 6x + 6
2y / 2 = 6x/2 + 6/2
y = 3x + 3
The slope, m = 3
The intercept, c = 3
Find the area of the triangle below.9 cm6 cm2 cm
We recall that the area of a triangle is defined by the product of the triangle's base times its height divided by 2.
So we notice that in our image, we know the height (6 cm), and we also know the base of the triangle (2 cm)
Therefore the triangles are is easily estimated via the formula:
[tex]\text{Area}=\frac{base\cdot height}{2}=\frac{2\cdot6}{2}=6\, \, cm^2[/tex]Then the area is 6 square cm.
what is 9/36 simplified?
Answer:
1/4
Step-by-step explanation:
it can be simplified by dividing both the numerator and denominator with 9.
[tex] \displaystyle \large{ \sf{ \frac{9}{36}}} [/tex]
[tex]\displaystyle \large{ \sf{ \frac{9}{36} = \frac{ \cancel9}{ \cancel3 \cancel6} }}[/tex]
[tex]\displaystyle \large{ \bf{ = \frac{1}{4} }}[/tex]
simplest form is 1/4
2/(x - 1) - 1/(x + 1) - 3/(x ^ 2 - 1)
The first step to solve this problem is to solve the substraction between the first two fractions:
[tex]undefined[/tex]Write the equation for the quadratic function in vertex form & standard form with the given vertex that passes through the given point.Vertex (2, -8) through the point (4, 3)
We will have the following:
[tex]\begin{gathered} y=a(x-2)^2-8\Rightarrow3=a(4-2)^2-8 \\ \\ \Rightarrow3=4a-8\Rightarrow4a=11 \\ \\ \Rightarrow a=\frac{11}{4} \end{gathered}[/tex]So, the equation in vertex form is:
[tex]y=\frac{11}{4}(x-2)^2-8[/tex]And in standard form:
[tex]\begin{gathered} y=\frac{11}{4}(x^2-4x+4)-8\Rightarrow y=\frac{11}{4}x^2-11x+11-8 \\ \\ \Rightarrow y=\frac{11}{4}x^2-11x+3 \end{gathered}[/tex]***Explanation***
We know that the quadratic expression in vertex form follows:
[tex]y=a(x-h)^2+k[/tex]Where (h, k) is the vertex of the expression. Now, we know that the vertex is (2, -8), so we replace those values and we obtain:
[tex]y=a(x-2)^2+(-8)\Rightarrow y=a(x-2)^2-8[/tex]Now, in order to determine "a" we must replace one point (That is not the vertex) in the expression and solve for "a", and we are told that the point (4, 3) is in one of the solutions, so:
[tex]\begin{gathered} 3=a(4-2)^2-8\Rightarrow3=a(2)^2-8 \\ \\ \Rightarrow11=4a\Rightarrow a=\frac{11}{4} \end{gathered}[/tex]Thus, the expression in vertex form is then:
[tex]y=\frac{11}{4}(x-2)^2-8[/tex]And to determine the standard form, we simply expand the equation in vertex form:
[tex]y=\frac{11}{4}(x^2-4x+4)-8\Rightarrow[/tex]