Madeline is a salesperson who sells computers at an electronics store. She makes a base pay of $80 each day and then is paid a $20 commission for every computer sale she makes. Make a table of values and then write an equation for P, in terms of x, representing Madeline's total pay on a day on which she sells x computers.
I need the Equation.
Answers
The linear equation that gives the values of P in terms of x which is Madeline's total pay on a given day is; P + 20·x + 80
What is an equation in mathematics?An equation consists of two expressions that are joined by an equal to sign to complete a mathematical statement.
The given parameters are:
Madeline's daily base pay = $80
Madeline's commission for each computer sold = $20
The given table of values is presented as follows:
Daily pay, in Dollars, P; [tex]{}[/tex] 80, 100, 120, 140
Number of computers sold, x; [tex]{}[/tex] 0, 1, 2, 3
From the above table of values, given that the independent variable, x, is increasing at a constant rate, and that the first difference is constant, we have that the relationship is a linear relationship, that has an equation of the form; P = m·x + c
Where:
m = The slope
c = The y-intercept
The slope which gives the ratio of the rise to the run of the graph is given by the equation; [tex]m = \dfrac{100-80}{1-0} =20[/tex]
The equation in point and slope form is therefore: P - 80 = 20·(x - 0) = 20·x
P - 80 = 20·x
P = 20·x + 80
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Related Questions
what is the probability that a student will be in both chemistry and math but not Spanish round to three decimal places
Answers
Answer :
3/13
Explanation :
The probablity of an event = favourable outcome / total outcomes
Now in our case,
favorable outcome = 60
Total number of outcomes = 5 + 70 + 5 + 85 + 60 + 15 + 3 + 17 = 260
Therefore,
probablity = 60 / 260
= 3 /13
f(x) = x^3- 9x^2 + 10.c ) list the x values of all the inflection points of F
Answers
To find the inflection points the first step we have to follow is to find the second and third derivatives of the function:
[tex]\begin{gathered} f\mleft(x\mright)=x^3-9x^2+10 \\ f^{\prime}\left(x\right)=3x^2-18x \\ f^{\prime}^{\prime}\left(x\right)=6x-18 \\ f^{\prime}^{\prime}^{\prime}\left(x\right)=6 \end{gathered}[/tex]Now, find the values of x for which the second derivative is 0:
[tex]\begin{gathered} 0=6x-18 \\ 18=6x \\ x=\frac{18}{6} \\ x=3 \end{gathered}[/tex]Evaluate the third derivative at this values of x, if the third derivative is different from 0, then that value is an inflection point:
[tex]f^{\prime}^{\prime}^{\prime}\left(3\right)=6[/tex]It means that there is an inflection point at x=3.
The Entertainment Center accumulates the following cost and net realizable value (NRV) data at December 31.
Inventory
Cost
Categories Data
Camera
Camcorders
DVDs
$11,600 $10,100
8,500
8,000
Market
Data
13,500
12,900
What is the lower-of-cost-or-net-realizable-value of the inventory?
Lower-of-cost-or-net-realizable-value $
Answers
The lower-of-cost-or-net-realizable-value of the inventory is $31000.
Define net-realizable-value.An asset's worth is often assessed using the net realizable value (NRV) approach for inventory accounting. It is discovered by calculating the difference between the asset's anticipated selling price and all of the expenses related to the asset's eventual sale. The cash sum that a corporation anticipates receiving is known as net realizable value (NRV). Consequently, net realizable value is also known as cash realizable value. The terms "net realizable value" and "current assets" are frequently used in relation to inventory and accounts receivable.
Given,
Camera
Cost = 11600
Market value = 10100
(Market value is less. so 10100.)
Camcorders
Cost = 8500
Market value = 8000
( Market value is less so 8000)
DVD
Cost = 13500
Market value = 12900
(Market value is less, so 12900)
the lower-of-cost-or-net-realizable-value of the inventory:
= 10100 + 8000 + 12900
= 31000
The lower-of-cost-or-net-realizable-value of the inventory is $31000.
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Use (60° - 45°) = 15° to find the exact value of cos 15º.vaV2 + V6V-V6(b)(c)4(d)4+ V62
Answers
Answer;
[tex]B\text{. }\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]Explanation;
Given that;
[tex](60^0-45^0)=15^0[/tex]Hence;
[tex]\text{Cos 15}^0=Cos(60^0-45^0)[/tex]According to trigonometry identity;
[tex]\begin{gathered} Cos(60^0-45^0\text{) = Cos60 Cos45 + Sin60Sin45} \\ Cos(60^0-45^0\text{) }=\frac{1}{2}(\frac{1}{\sqrt[]{2}})+\frac{\sqrt[]{3}}{2}(\frac{1}{\sqrt[]{2}}) \end{gathered}[/tex]Evaluate the result by finding the LCM
[tex]Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}[/tex]Rationalize;
[tex]\begin{gathered} Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}\times\frac{\sqrt[]{2}}{\sqrt[]{2}} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}(1+\sqrt[]{3})}{2\cdot2} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}+\sqrt[]{6}}{4} \end{gathered}[/tex]Hence the required reusult is;
[tex]\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]a motorboat travels 456 km in 8 hours going upstream and 783 km in 9 hours going downstream. what is the rate of the boat in still water and what is the rate of current?
Answers
To produce a textbook, suppose the publisher spent $110,000 for typesetting and $7.50 per book for printingand binding. The total cost to produce and print n books can be written asC = 110,000+ 7.51a. Suppose the number of books printed in the first printing is 10,000. What is the total cost?The total cost is $b. If the average cost is the total cost divided by the number of books printed, find the average cost of producing10,000 textbooks.The average cost of producing 10,000 textbooks is $c. Find the cost to produce one more textbook when you have already produced 10,000 textbooks.If you have already produced 10,000 textbooks, it'll cost you $ to produce one more.
Answers
The given equation is
[tex]C=110000+7.5n[/tex]a)
The number of books=10000
Substitute n=10000 in the given equation, we get
[tex]C=110000+7.5\times10000[/tex][tex]C=185000[/tex]The total cost is $185,000.
b)
[tex]\text{Average cost =}\frac{185000}{10000}=18.5[/tex]The average cost of producing 10,000 textbooks is $18.5.
c)
If we need to produce one more after producing 10000 books.
substitute n=10001 in the given equation, we get
[tex]C=110000+7.5(10001)=185007.5[/tex][tex]\text{One book cost after printed 10000 book=cost of 10000 books-cost of 10001 books}[/tex][tex]\text{One book cost after printed 10000 book=1}85000-185007.5=7.5[/tex]
If you have already produced 10,000 textbooks, it'll cost you $7.5 to produce one more.
Why can the big candy makers produce candy that is less expensive per piece
Answers
Answer:
Step-by-step explanation:
The reason behind the big candy makers producing candy that is less expensive per price is that the cost that they have to bear for production will be less in comparison to small candy makers.
bc a lot of people buy their products, so they have enough money to make a profit even if they sell it at a lower cost.
I need help with this practice problem solving. It is trigonometry It asks to graph the function, if you can.. use Desmos to do so..
Answers
Notice that f(x) is
[tex]h(x)=\cos (x)[/tex]translated π/6 to the left.
Now, recall that the period of the cotangent is
[tex]\pi\text{.}[/tex]Since f(x) is just a translation, both functions have the same period.
Answer:
f(x) =-x² + 2x + 6
Find f(-7)
Answers
320000 in decimal form
Answers
Answer:
320×10³
Step-by-step explanation:
This is the standard form for the number 320000
hope it helps
please mark brainliest
2.05x0.004 I know the answer is 0.0082 but when I multiply it myself I get 0.08200?
Answers
2 . 0 5 0
0 . 0 0 4
---------------------------------
8 2 0 0
+ 0 0 0 0
0 0 0 0
0 0 0 0
------------------------------
0 . 0 0 8 2 0 0 =
-----------------------------
The data below show the number of hits on a website per week over a random sample of five weeks. Compute the followingstatistics.
Answers
We have a sample that is:
[tex]115,39,160,240,176[/tex]a) We can find the median by first sorting the sample:
[tex]39,115,160,176,240[/tex]The median is the value that has 50% of the values below its values.
In this case, this value is in the third place of the sorted sample and has a value of 160.
b) We have to find the mean.
We can calculate it as:
[tex]\begin{gathered} \bar{x}=\frac{1}{n}\sum_{n\mathop{=}1}^5x_i \\ \\ \bar{x}=\frac{1}{5}(115+39+160+240+176) \\ \\ \bar{x}=\frac{1}{5}(730) \\ \\ \bar{x}=146 \end{gathered}[/tex]c) We have to calculate the variance. To find its value we will use the mean value we have just calculated:
[tex]\begin{gathered} s^2=\frac{1}{n}\sum_{n\mathop{=}1}^5(x_i-\bar{x})^2 \\ \\ s^2=\frac{1}{5}[(115-146)^2+(39-146)^2+(160-146)^2+(240-146)^2+(176-146)^2] \\ \\ s^2=\frac{1}{5}[(-31)^2+(-107)^2+(14)^2+(94)^2+(30)^2] \\ \\ s^2=\frac{1}{5}(961+11449+196+8836+900) \\ \\ s^2=\frac{1}{5}(22342) \\ \\ s^2=4468.4 \end{gathered}[/tex]d) We have to calculate the standard deviation. As we have already calculated the variance, we can calculate it as:
[tex]\begin{gathered} s=\sqrt{s^2} \\ s=\sqrt{4468.4} \\ s\approx66.85 \end{gathered}[/tex]e) We now have to find the coefficient of variation:
[tex]CV=\frac{s}{\bar{x}}=\frac{66.85}{146}\approx0.457876\cdot100\%\approx46\%[/tex]Answer:
a) 160
b) 146
c) 4468.4
d) 66.85
e) 46%
y=6/5x+9 how would I graph it
Answers
To graph this linear function, we can find both intercepts of the function. To achieve this, we need to solve the equation when y = 0 (for this function) (this will be the x-intercept), and then we need to solve the resulting equation for this function when x = 0 (this will be the y-intercept). Then, we will have two points for which we can graph the function - we need to remember that a line is defined by two points.
Then, we can proceed as follows:
1. Finding the x-intercept[tex]y=\frac{6}{5}x+9,y=0\Rightarrow0=\frac{6}{5}x+9[/tex]Then, we have:
a. Add -9 to both sides of the equation:
[tex]\frac{6}{5}x=-9[/tex]b. Multiply both sides of the equation by 5/6:
[tex]\frac{5}{6}\frac{6}{5}x=-9\cdot\frac{5}{6}\Rightarrow x=-\frac{45}{6}=-\frac{15}{2}=-7.5[/tex]Therefore, the x-intercept is (-7.5, 0).
2. Finding the y-interceptWe have that x = 0 in this case. Then, we have:
[tex]y=\frac{6}{5}x+9\Rightarrow y=\frac{6}{5}(0)+9\Rightarrow y=9[/tex]Therefore, the y-intercept is (0, 9).
Now, we have the points (-7.5, 0) and (0, 9), and we can draw both points on the coordinate plane. The line will pass through these two points:
I am going to have to send you a photo of the problem during the session because it is to large to crop here.
Answers
Direct variations have an special characteristic: they can be represented on a plane by a line paassing through the origin (0,0).
The equation of a line has the following shape:
[tex]y=mx+b[/tex]Where x is the slope, and b is the y intercept.
For direct variations, the line passes through the origin; then, the y intercept is 0, therefore b=0.
For direct variations, we can have an associated line with the following shape:
[tex]y=mx[/tex]We can find the value for m knowing 2 points of the line and calculating the slope. One point is (-1,-4); and the other is the origin (0,0).
Now we can calculate the slope by dividing y distance of the points by the x distance of the points:
[tex]m=\frac{0-(-4)}{0-(-1)}=\frac{0+4}{0+1}=\frac{4}{1}=4[/tex]We have calculated the slope to be 4, then the equation representing the direct variation is:
[tex]y=4x[/tex]Any pair of points x,y that satisfy the equation will an element of the direct variation.
Now, we can try each:
With 8,0:
[tex]\begin{gathered} 0=4\cdot8 \\ 0=16 \end{gathered}[/tex]8,0 does not satisfy, therefore it is not an element of the direct variation.
2,8:
[tex]\begin{gathered} 8=4\cdot2 \\ 8=8 \end{gathered}[/tex]2,8 is element of the dierct variation
-2,0:
[tex]\begin{gathered} 0=4\cdot(-2) \\ 0=-8 \end{gathered}[/tex]-2,0 is not part
4,-1:
[tex]\begin{gathered} -1=4\cdot4 \\ -1=16 \end{gathered}[/tex]4,-1 is not part
8,-1:
[tex]\begin{gathered} -1=4\cdot8 \\ -1=32 \end{gathered}[/tex]8,-1 is not part
-2,-8:
[tex]\begin{gathered} -8=4\cdot(-2) \\ -8=-8 \end{gathered}[/tex]-2,-8 is part.
Finally, we can say points (-4,-1), (2,8) and (-2,-8) are part of the direct variation.
I need help with this and it is delivered at 3:30 pm and sadly I did not understand almost anything and I am confused.Problem 1
Answers
Reflection across the y-axis transforms the point (x,y) into (-x, y)
Applying this rule to points A, B, and C, we get:
A(-5, 6) → A'(5, 6)
B(3, 6) → B'(-3, 6)
C(-3, 2) → C'(3, 2)
Given that figure ABC was reflected, then figure A'B'C' is congruent with figure ABC
How much water must be evaporated from 8 grams of a 30% antiseptic solution to produce a 40% solution?
Answers
Answer:
Step-by-step explanation:
8 grams of 30% --> 2.4 grams of AS For 2.4 grams to be 40% --> 6 grams of solution Evaporate 2 grams of water
-14.4 + x = -8.2what does x equal?I NEED ANSWERS ASAPi will give brainliest
Answers
the given expression is,
-14.4 + x = -8.2
x = 14.4 - 8.2
x = 6.2
thus, the answer is x = 6.2
A table is in the shape of a regularhexagon. The perimeter of the table is 12 ftfeet. What is the length of each side ofthe tableA 1 ftB 2 ftC 3 ftD 4 ft
Answers
Solution:
Given the shape of a hexagon;
The perimeter, P, of a hexagon is;
[tex]\begin{gathered} P=6s \\ \\ \text{ Where }s=side\text{ length} \end{gathered}[/tex]Given;
[tex]\begin{gathered} P=12ft \\ \\ s=\frac{12}{6}ft \\ \\ s=2ft \end{gathered}[/tex]CORRECT OPTION: B
The following table represents C, an appliance repairman’s charges based on t, the hours it takes to make a repair.Which of the following equations could be used to determine the repairman’s charges for a repair?A: C=27t +3B: C=27tC: C=35tD: C=35t + 2
Answers
Given the table below
To find the equation of the values of the table, we will first calculate the rate of change, then use a point and the rate of change calculated fo find the equation for the repairman's charges for the repair
To find the rate of change we have
[tex]\text{ Point 1}\Rightarrow(1,62)\Rightarrow t_1=1,c_1=62[/tex][tex]\text{ Point 2}\Rightarrow(3,116)\Rightarrow t_2=3,c_2=116[/tex]The rate of change formula is
[tex]m=\frac{c_2-c_1}{t_2-t_1}=\frac{116-62}{3-1}=\frac{54}{2}=27[/tex]Having calculated the rate, we can use slope and one point form equation of a line to get the desired equation. This is given below:
[tex]c-c_1=m(t-t_1)[/tex]Substitute the given values of t and c and the rate in the formula above
[tex]\begin{gathered} c-62=27(t-1) \\ c-62=27t-27 \\ c=27t-27+62 \\ c=27t+35 \end{gathered}[/tex]Hence, the repairman's charges for a repair is given as C = 27t + 35
Write the number 0.2 in the form a over b using integers to show that it is a rational number
Answers
Hello! Let's solve this exercise:
We have some ways to show it, look:
[tex]\begin{gathered} \frac{a}{b}=0.2 \\ \\ \frac{1}{5}=0.2 \\ \\ \frac{2}{10}=0.2 \end{gathered}[/tex]So, as it can be written as a fraction, is a rational number.
has overdrawn his bank account Jim has overdrawn his bank account and has a balance of -$3.47.he received a paycheck of $292.54 he deposits $163.93 of his paycheck into his account how much does Jim have in his bank account after the deposit is made
Answers
Since Jim deposits $ 163.93 of his paycheck into his account and there has a balance of - $ 3.47, then he has in his account:
[tex]\text{\$}$163.93$-\text{\$}3.47=\text{ \$}160.46[/tex]Therefore, Jim has $ 160.46 in his bank account after the deposit is made.
If a number with two places to the right of the decimal place is added to a number with three places to the right of thedecimal place then the answer should be reported as having how many numbers to the right of the decimal place
Answers
Let the number with two places to the right of the decimal place be represented as 20.45 and the number with three places to the right of the decimal place be 20.456
Required:
When we add the two numbers, how many numbers to the right of the decimal place is it going to have?
We can know this by adding the two fictitious numbers:
[tex]20.45\text{ + 20.456 = 40.906}[/tex]Here we can see that
Fiona is making a banner in the shape of a triangle for a school project. She graphs the banner on a coordinate plane with vertices at P(0, 4) , Q(2, 8) , and R(−3, 6) . She wants to reflect the banner over the line x=1. Identify the image of the banner reflected in the line x=1.
Answers
The coordinates of the banner after the reflection across x = 1 is P'(2, 4), Q'(0, 8), and R'(5, 6)
How to determine the coordinates of the banner after the reflection?From the question, the coordinates are given as
P(0, 4), Q(2, 8), and R(−3, 6)
The line of reflection is given as
x = 1
The rule of reflection across the line x = 1 is represented as
(x, y) = (-x + 2, y)
When the above rule is applied, we have
P'(2, 4), Q'(0, 8), and R'(5, 6)
This means that the coordinate of the image are P'(2, 4), Q'(0, 8), and R'(5, 6)
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Check each answer to see whether the students evaluated the expression correctly. If the answer is incorrect cross out the answer and write the correct answer. 8(x+2)when x= 68(6+2) = 48 +2 = 50
Answers
The answer is not correct. There is a mistake applying the distributive property.
The distributive property says:
[tex]a(b+c)=ab+ac[/tex]But in this case, the 8 only multiplies the 6, and not the 2. The correct procedure is:
[tex]8(6+2)=8\cdot6+8\cdot2=48+16=64[/tex]The correct answer is 64
Select all the correct locations on the image.Which statements are logically equivalent to (p q)?
Answers
-(p ∧ q ) is logically equivalent to
-pv-q
plot the graph f on the graphf(x)=|1/2x-2|
Answers
• We will determine the domain, range and x ;y intercept then plot the graph
1. The domain is given by :
[tex]\begin{gathered} \text{Domain = }x<0\text{ = (-}\infty\text{ },\text{ 0) } \\ \text{ x >0 = ( 0 },\infty)\text{ } \\ \text{ =(-}\infty;0)\text{ U ( 0 ;}\infty) \end{gathered}[/tex]2. Range is given by :
[tex]\begin{gathered} \text{Range = f(x) }\ge0\text{ } \\ \text{ =}\lbrack0;\infty) \end{gathered}[/tex]3. x - and y -intercept :
[tex]x\text{ - intercept = ( }\frac{1}{4};\text{ 0) }[/tex]4. asymptote :
[tex]\begin{gathered} \text{vertical : }x\text{ = 0 } \\ \text{horizontal : y = 2 } \end{gathered}[/tex]Now that we have the necessary points to plot the f(x) = | 1/2x -2 | , the graph will look as follows :The half life of titanium - 44 , a radioactive isotope, is 63 years. If a substance starts out with 1000 kg of titanium- 44( round all the answers to the nearest hundredth of a kilogram or year) A) how much titanium- 44 will remain after 441 years ? B) how long will it be before there is only 1 kg of titanium- 44 ?
Answers
a)
Every 63 years, the amount of titanium halves.
441 years later means how many halving?
441/63 = 7 halving
We start off with 1000 and do 7 halving to get the amount of Titanium-44 after 441 years.
[tex]\begin{gathered} 1000(\frac{1}{2})^7 \\ =7.8125 \end{gathered}[/tex]after 441 years, the amount of titanium remaining would be 7.8125 kg
b)
Let's find the point where the remaining titanium would be 1 kg.
That would be:
[tex]1=1000(\frac{1}{2})^t[/tex]t is the time we are looking for. We can solve this using Ln(natural log):
[tex]\begin{gathered} 1=1000(\frac{1}{2})^t \\ 0.001=\frac{1}{2}^t \\ ln(0.001)=\ln (\frac{1}{2}^t) \\ \\ t=\frac{\ln (0.001)}{\ln (\frac{1}{2})} \\ t=9.965 \end{gathered}[/tex]There is basically 9.965 halving. That would make the years approximately:
9.965 * 63 (half life) = 627.795 years (approx)
Pls help & also give an easy explanation thank youuuuu
Answers
Given
A digital picture frame with a border of 3 cm. The actual length of the frame is x
Answer
a) The actual side of the picture is x-3
Area of picture
[tex]=(side)^2=(x-3)^2[/tex]b) Area of frame
[tex]x^2[/tex]c) Area of border = Area of frame - area of picture
[tex]x^2-(x-3)^2[/tex]I need help with this practice I am new to this subject of mathematics (algebra) Can you show me how to solve this STEP-BY-STEP?
Answers
Given:
[tex]4+x+8=24[/tex]Required:
To find the correct one.
Explanation:
The given quation is:
4 + x +8 =24
Subtract 8 on both sides
4 + x +8 - 8 = 24 -8
4 + x = 16
Final Answer:
Thus the first option is the correct answer.
2 is less than or equal to y
Answers
Solution
[tex]2\leq y[/tex]