The value of x = 1/M-1 , x = -1/M+1
What is Graph?
The graph of a function f is the set of ordered pairs where "displaystyle f(x)=y" exists. In the common scenario when x and f(x) are real integers, these pairings represent Cartesian coordinates of points in two-dimensional space and hence constitute a subset of this plane.
M(x) = |x + 1|
|x + 1| = M(x)
x + 1 = M(x)
x + 1 = -M(x)
Adding (-x) both side
x + 1 + (- x) = M(x) + (- x)
x + 1 + (- x) = -M(x) + (- x)
x + 1 - x = M(x) - x
x + 1 - x = -M(x) - x
1 = M(x) - x
1 = -M(x) - x
M(x) - x = 1
-M(x) - x = 1
x(M-1) = 1
x(-M-1) = 1
Dividing both side with (M - 1) and (-M - 1)
x(M-1)/(M - 1) = 1/(M - 1)
x(-M-1)/(-M - 1) = 1 /(-M - 1)
x = 1/(M - 1)
x = 1/(-M - 1)
Hence, x = 1/M-1 , x = -1/M+1
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what is y= –12x–6 on a graph
The graph of the equation y = –12x – 6 is attached in the solution.
We can find the x and y intercept of the line to find make the graph.
Putting x = 0 in the given equation, we get:-
y = -12(0) - 6 = 0 - 6 = -6
Hence, the x -intercept is (0,-6).
Putting y = 0 in the given equation, we get:-
0 = -12x - 6
6 = -12x
x = 6/(-12)
x = -1/2
Hence, the y -intercept is (-1/2,0).
We can find another point on the line.
Putting x = -1 in the given equation, we get:-
y = -12(-1) - 6
y = 12 - 6 = 6
y = 6
Hence, another point on the line is (-1,6).
Plotting these points we can graph the equation of the line.
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Simplify the expression.
2/5y−4+7−9/10y =
Answer:
[tex]\frac{1}{2}[/tex] y +3
Step-by-step explanation:
You want to combine like terms
[tex]\frac{2}{5}[/tex] y and [tex]\frac{-9}{10}[/tex] y are like terms because they both have a variable y
-4 and + 7 are like terms because they are both constants. (numbers without letters)
We combine these
[tex]\frac{4}{10}[/tex] means the same as [tex]\frac{2}{5}[/tex] I just multiplied the numerator (top) and the denominator (bottom) by 2. I did this so that I could add it to [tex]\frac{-9}{10}[/tex]
[tex]\frac{4}{10}[/tex]y - [tex]\frac{9}{10}[/tex]y = [tex]\frac{-5}{10}[/tex] y (4-9 = -5) or [tex]\frac{-1}{2}[/tex] y simplified
-4 + 7 = 3
A magical basket of pennies doubles every day. If the basket if full on the 15th day, on what day was the basket one-quarter full?
The basket of pennies will be 1/4 full on the 13th day
How to determine the day?From the question, the given parameters are:
Rate of change, r = 2 i.e. doubleFull basket, = 15th dayThe above parameters illustrate an exponential function
An exponential function is represented as
A(n) = A * (r)ⁿ⁻¹
Where
A represents the initial value
It is full on the 15th day
So, we have
1 = A *(2)¹⁵⁻¹
Evaluate
1 = A *(2)¹⁴
Divide by (2)¹⁴
A = (2)⁻¹⁴
Substitute A = (2)⁻¹⁴ in A(n) = A * (r)ⁿ⁻¹
A(n) = (2)⁻¹⁴ * (2)ⁿ⁻¹
When it is one-quarter full, we have
1/4 = (2)⁻¹⁴ * (2)ⁿ⁻¹
Multiply by (2)¹⁴
(2)¹² = (2)ⁿ⁻¹
By comparison, we have
n - 1 = 12
Add 1 to both sides
n = 13
Hence, the basket will be one-quarter full on the 13th day
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2x^2-5x-11=1
factor pls
Answer:
(2x+3)(x-4) = 0
Step-by-step explanation:
A flagpole cast a shadow that is 15 feet long. The angle of elevation at this time is 40 degrees . How tall is the flag pole?
Flag pole is 12585 feet long.
Define Tangent.The straight line that "just touches" the curve at a given location is referred to as the tangent line to a plane curve in geometry. It was described by Leibniz as the path connecting two points on a curve that are infinitely near together. A line that only touches a circle or an ellipse at one point is said to be tangential in geometry. If a line contacts a curve at point P, that point is referred to as the point of tangency. In other words, it is described as the line that, at that particular location, indicates the slope of a curve.
Given Data
Angle of elevation = 40°
Adjacent = 15 feet
Let height of opposite be x
tan(A) = [tex]\frac{opposite}{adjacent}[/tex]
tan(A) = [tex]\frac{x}{15}[/tex]
x = 15tan(40)
x = 15(0.839)
x = 12,585
Flag pole is 12585 feet long.
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-0.5f - 4.52 = -25.52 + f HELP PLEASE
Answer:
-0.5f - 4.52 = -25.52 + 1f
-1.5f = 21
f = 14
Answer:
14
Step-by-step explanation:
-4.52 + 25.52 = f + 0.5f
21 = 1.5f
f = 14
Two observers are standing on shore 20 mile apart at points A and B and measure the angle to a sailboat at a point C at the same time. one observer is 10 miles from the sailboat and the other observer is 25 miles from the sailboat. round to the nearest degree
Using the law of sines, supposing C = 30º, the angle of each observer with the sailboat is:
Observer A: 136º.Observer B: 14º.What is the law of sines?Suppose we have a triangle in which:
The length of the side opposite to angle A has length a.The length of the side opposite to angle B has length b.The length of the side opposite to angle C has length c.The lengths and the sine of the angles are related according to the following rule:
[tex]\frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}[/tex]
The measure of angle B is found as follows:
sin(B)/10 = sin(C)/20
sin(B)/10 = 0.5/20 (sin(C) = 0.5)
sin(B) = 5/20
sin(B) = 0.25
B = arcsin(0.25)
B = 14º.
The measure of angle A is found as follows:
sin(A)/25 = sin(C)/20
sin(A)/25 = 0.5/20 (sin(C) = 0.5)
sin(A) = 12.5/20
sin(A) = 0.625
A = arcsin(0.625)
A = 136º.
Missing informationThe problem is incomplete, hence we suppose that the angle C is of 30º and problem asks for the angle measure of each angle.
(drawing is not to scale).
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Robert gets a loan from the bank. agrees to borrow 6000 , his interest rate is 7 %. he agrees to pay back over a 10 year period. how much money wil he have paid back by then?
The amount to be paid after paying interest of 7% for 10 years is 10,2000
The amount to be borrowed from the bank = 6000
Interest rate for the amount per year = 7%
The total time period of the loan = 10 years
Thus , the final amount can be calculated by using the formula
A = P(1 + rt)
where A is the final amount
P is the principal amount to be borrowed
r is the rate of interest
t is the time period
Now, let us substitute the known values in the above equation , we get
A = 6000 ( 1 + 0.07 x 10)
= 6000 (1 + 0.7)
= 6000 (1.7)
A = 10,200
Therefore , the final amount to be paid is 10,200
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What is one solution of this system?
Answer:
C (0,3)
Step-by-step explanation:
Plot the two equations and the points. See the attached graph. The blue area reflects the inequality of y+3x<=8: many points satisfy this equation and they are all blue.
The red line is equation y-3=x. There is only one point on this line that is also in the blue area: (0.3). The other three points (A, B, and D) do not satisfy either equation. The metric term for them is losers.
Find length between AC-3,8) and B(5,-4) in simplest radical form:
The Points are in the form (x,y), and they are A(-3,8) and B(5,-4).
The length between two points is:
[tex]\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]In this case:
[tex]\text{length = }\sqrt[]{(-3-5)^2+(8-(-4))^2}=\sqrt[]{(-8)^2+(12)^2}=\sqrt[]{64+144}[/tex][tex]\text{length =}\sqrt[]{208}\text{ = }\sqrt[]{16\cdot13}=4\sqrt[]{13}[/tex]The correct anser is:
[tex]\text{length = 4}\sqrt[]{13}[/tex]PLEASE HELP
50 POINTS
Answer:
9. [tex]256u^8 v^{16}[/tex]
10. [tex]-32x^{10} y^{35}[/tex]
11. [tex]-x^{12}y^{20}[/tex]
12. 1
13. [tex]\frac{2}{3xy^3}[/tex]
14. [tex]\frac{h^8}{3j^6k^6}[/tex]
15. [tex]\frac{1}{4z}[/tex]
Answer:
9. 256u^8 v^16
10. -32x^10 y^35
11. x^12 y^21
12. 1
Step-by-step explanation:
If you can, please give me a Brainliest; thank you! I put a lot fo times to solve it !
Dilate this figure by a scale factor of 1.5. Is the image a stretch or compression?
Answer:
compression
Step-by-step explanation:
If b>1 then the graph will compress
suppose that the members of a student governance committee will be selected from the 40 members of the student senate. there are 18 sophomores, 12 juniors and 10 seniors who are members of the student senate. in how many ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors? assume that each of the sophomores, each of the juniors and each of the seniors is equally likely to be selected for the committee. a. 339 b. 1211760 c. 2160 d. 18643560 e. 25920
Assuming that each of the sophomores, each of the juniors and each of the seniors is equally likely to be selected for the committee, there are b. 1211760 ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors. The committee can be selected in 1,211,760 ways.
Combination formula:
Cn,x is the number of different combinations of x objects from a set of n elements, given by:
Cnₓ= n!÷ x! (n-x!)
In this problem:
2 sophomores from a set of 18.
2 juniors from a set of 12.
3 seniors from a set of 10.
They are independent, so we can just multiply them, thus:
T= C₁₈,₂ × C₁₂,₂× C₁₀,₃ = 18! ÷2!6! × 12!÷ 2!10! × 10!÷ 3!×7! = 1211760
The committee can be selected in 1,211,760 ways.
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when 9 times a number is increased by 30, the answer is the same as when 140 is decreased by the number. Find this number
Answer: 11
Step-by-step explanation:
Let the number be x.
[tex]9x+30=140-x\\\\10x=110\\\\x=11[/tex]
Can someone help me, please? its timed
The measure of the lableled angles are x = 202 and (x - 44) = 158
What are the values of the labeled angles?Before we can solve this question, we need to understand the geometry of the shape.
The shape we have here is a pentagon. The sum of angles in a pentagon is 540. The angle with a red square is a right angle and the value is 90.
Therefore:
x + 90 + 90 + (x - 44) = 540
x + 180 + x - 44 = 540
2x + 136 = 540
2x = 540 - 136
2x = 404
x = 404/2
x = 202
Also:
(x - 44) = 202 - 44 = 158
Therefore, the angles x and (x - 44) measure 202 and 158 respectively.
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The unknown value x in the polygon is equal to 112 degrees.
Sum of Angles in a PolygonThe sum of angles in the given polygon be equal to 360 degrees. This implies that when we add all the total sides together, we must have a total of 360 degrees.
Since one of the indicated sides is a right angle, we can sum everything up and solve for x
Mathematically;
[tex]90 + 90 + x +(x - 44) = 360[/tex]
Solving the equation above;
[tex]180 + x + x - 44 = 360\\180 + 2x - 44 = 360\\x = 112[/tex]
The value of x in the figure given is 112.
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4 2/15 / 3.1 (I NEED HELP NOW!!!!!!!!!!!)
Answer:
The answer would be 1.3, and the three is repeating.
Step-by-step explanation:
First, make 4 2/15 into a improper fraction.
4 2/15= 62/15
Now, when we divide fraction, use the rule Keep, Change, Flip.
Keep the 62/15.
Change the division sign into a multiplication sign.
To make the 3.1 into a fraction, put a one over it.
3.1/1
Now, flip the fraction.
3.1/1= 1/3.1
Your equation will look like this:
62/15x1/3.1
Multiply across.
62/46.5
Now simplify.
The answer would be 1.3, and the three is repeating.
The same number of guests are seated at each of 8 large tables. There are 2 guests seated at one small table. Write an equation to represent the total number of guests T and the number of people x at
each large table. If there are 82 guests, how many are seated at each large table?
Answer:
10
Step-by-step explanation:
Since there are 2 people sitting alone, we can put them aside
then we have 8 large tables, each seat x number of guests
we would have total 8x guests there
so 8x+2=82
then solve
8x=80
x=10
Use each of the three corresponding base and height pairs to find the area of the triangle. Why is the area the same for each calculation?
Answer:
The three correct corresponding pairs that gives the same area are;
[tex]\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}[/tex]The areas are the same in each case because the product of each pair is the same.
Explanation:
Given the base and height pairs in the question.
Let us use the corresponding pairs that gives the same area.
Firstly, for the first pair;
[tex]\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times10\times7=35cm^2 \\ A=\frac{1}{2}\times10\times2.5=12.5cm^2 \end{gathered}[/tex]Secondly, the second pair is;
[tex]\begin{gathered} A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times5\times3.5=8.75cm^2 \\ A=\frac{1}{2}\times5\times2.5=6.25cm^2 \end{gathered}[/tex]Thirdly, the third pair;
[tex]\begin{gathered} A=\frac{1}{2}\times14\times3.5=24.5cm^2 \\ A=\frac{1}{2}\times14\times7=49cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}[/tex]Therefore, the three correct corresponding pairs that gives the same area are;
[tex]\begin{gathered} A=\frac{1}{2}\times10\times3.5=17.5cm^2 \\ A=\frac{1}{2}\times5\times7=17.5cm^2 \\ A=\frac{1}{2}\times14\times2.5=17.5cm^2 \end{gathered}[/tex]The areas are the same in each case because the product of each pair is the same.
What is x in this equation 6(x+7)=-12
Answer:
x = -9
6x + 42 = -12
6x = -54
x = -9
Which of the equations shown have infinitely many solutions ? Select all that apply. A. 3x-1=3x+1, B. 2x-1=1-2x, c 3x-2=2x-3, D 3(x-1)=3x-3, E. 2x+2=2(x+1), F. 3(x-2)=2(x-3)
Answer:
The equations that have infinitely many solutions are;
[tex]\begin{gathered} 3(x-1)=3x-3 \\ 2x+2=2(x+1) \end{gathered}[/tex]Explanation:
For an equation to have infinitely many solutions, the left-hand side of the equation and the right side of the equation must be equivalent/equal.
That means that the expression before the equal sign must be equivalent to the expression after the decimal.
such as;
[tex]\begin{gathered} x=x \\ x+3=x+3 \\ 2x=2(x) \\ 4x+4=4(x+1) \end{gathered}[/tex]From the given equation, the equations that have their left and right sides equivalent are;
[tex]\begin{gathered} 3(x-1)=3x-3 \\ 3x-3=3x-3 \\ \\ 2x+2=2(x+1) \\ 2x+2=2x+2 \end{gathered}[/tex]Therefore, the equations that have infinitely many solutions are;
[tex]\begin{gathered} 3(x-1)=3x-3 \\ 2x+2=2(x+1) \end{gathered}[/tex]Match the polynomial expression on the left with the simplified version on the right.
Given the following question:
First expression:
[tex]\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}[/tex]Second expression:
[tex][/tex]The stock price for JSR was $74.29 in August. In September the stock had increased by 7%, but in October the price fell by 7%. What was the price of JSR stock in October? Round your answer to the nearest cent, if necessary.
In order to find the price increase multiply by 1 and add the 7%,
[tex]\begin{gathered} 74.29\cdot(1+0.07) \\ 74.29\cdot1.07 \\ 79.4903 \end{gathered}[/tex]then, apply the same to subtract the 7%
[tex]\begin{gathered} 79.4903\cdot(1-0.07) \\ 79.4903\cdot(0.93) \\ 73.925\approx73.93 \end{gathered}[/tex]Round 3.44570830811 to the nearest hundred-thousandth
Answer:
3.44571
Step by step explanation:
3.44570830811
8 is the number next to the place value of hundred-thousandth, so we round it up to 1 and add it to 0
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Kathy and Peter both drive older cars that dont always work in the wintertime. Suppose that Kathy's car works 80% of the time and Peter's works 65% of the time. What is the probability they will both be working on any given morning?
The drivers at a warehouse need to deliver 40,000 packages each day. The warehouse has 128 trucks. Each truck has 350 packages. The drivers deliver all the packages on the trucks. Do the warehouse drivers deliver enough packages
Yes. The warehouse drivers deliver enough packages.
What is an expression?An expression is used to illustrate the information that's given.
In this case, the warehouse has 128 trucks. Each truck has 350 packages. The number of packages that van be delivered will be:
= Number of trucks × Amount in each package
= 128 × 350
= 44800
Since the drivers at a warehouse need to deliver 40,000 packages each day. this means they denied enough packages because 44800 is more than 40000.
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The equation of a line is given below.2x+6y=-18Find the x-intercept and the y-intercept.Then use them to graph the line.X-intercept:0Х5?ca loxy-intercept:0?
Given equation of the line is
[tex]2x+6y=-18[/tex]Dividing both sides of the above equation by -18, we get
[tex]\frac{x}{-9}+\frac{y}{-3}=1[/tex]The line cuts the x axis at (-9,0) and the y axis at (0,-3).
Therefore, the x intercept is -9 and the y intercept is -3.
The graph of the line is shown below.
Isabella is making bread. She has 7/2 cups of flour. each loaf uses 3/4 cup of flour. How many whole loaves of bread can Isabella make? will she have flour left over?
A. 5 loaves with flour left over.
B. 5 loaves with no flour left over.
C. 4 loaves with flour left over.
D. 4 loaves with no flour left over.
Please help
Answer: C. Four loaves, with flour left over.
Step-by-step explanation:
7/2 simplifies to 3 1/2
Do the math,
3/4 + 3/4 = 1 1/2 2 loaves
1 1/2 + 3/4 = 2 1/4 3 loaves
2 1/4 + 3/4 = 3 4 loaves
Now when we add 3/4 to 3, we get more than 3 1/2. Which means we do not have enough flour for another loaf of bread. So, we can make four loaves and still have some four left over. The answer is C.
Create a system of equations and use algebra to write a quadratic equation with points (-3,-4), (3,14), and (0,-4). Equations 1: -4=9a-3b+c Equation 2: 14=9a+3b+c Equation 3: -4=c
what is the resultiNg of b?
In the system of equations, the value of the variable 'b' will be 3.
What is the solution to the equation?The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.
The system of the equations is given below.
Equations 1: - 4 = 9a - 3b + c
Equation 2: 14 = 9a + 3b + c
Equation 3: - 4 = c
Put the value of c in equations 1 and 2, then we have
- 4 = 9a - 3b - 4
9a - 3b = 0 ...4
14 = 9a + 3b - 4
9a + 3b = 18 ...5
Subtract equation 4 from 5,
9a + 3b - 9a + 3b = 18 - 0
6b = 18
b = 3
In the system of equations, the value of the variable 'b' will be 3.
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NEED HELP ASAP 25 pointsWhich equation best describes the data in the table?x y-2 -41 -73 1 6 28options:a. y=x-2b. y=3x-4c. y=x^2-8d. y=2x^2-3
To determine the equation that best describe the data in the table, let us substitute the value of x given on the table into each equation and check for the equation that gives us the corresponding values of y;
for x = -2, y=-4; substituting x= -2 into each equation, we have;
[tex]\begin{gathered} a)y=x-2=-2-2=-4 \\ b)y=3x-4=3(-2)-4=-16 \\ c)y=x^2-8=-2^2-8=4-8=-4 \\ d)y=2x^2-3=2(-2)^2-3=5 \end{gathered}[/tex]From the first substitution, only equation a and c gave us the corresponding value of y.
Secondly, let's substitute another value of x into the two right right equaabove to confirm the best;
At x=1, y= -7; substituting x=1 into equation a and c we have;
[tex]\begin{gathered} a)y=x-2=1-2=-1 \\ c)y=x^2-8=1^2-8=-7 \end{gathered}[/tex]From the above only equation c gave us the corresponding value of y at x=1.
Since only equation c gave us the corresponding values of y for both substituttions. The equation that best describe the data on the table is equation cequatio
[tex]c\text{. }y=x^2-8[/tex]I haven’t came across one of these questions so not sure how to solve
m∠F = 140º
1) Since that trapezoid is a quadrilateral, then we can affirm that the Sum of their interior angles is:
[tex]\begin{gathered} S_i=180(n-2) \\ S_i=180(4-2) \\ S_i=180(2) \\ S_i=360 \end{gathered}[/tex]Note that "n" refers to the number of sides:
Notice also that angle H is a right angle since this is not an Isosceles Trapezoid
So we can write out the following
9x +14x +4x + 90 = 360º
27x = 360 -90
27x = 270
x =10
Alternatively, angles between parallel lines are supplementary
2) To find out the measure of angle ∠F We'll need to plug x=10 into that expression:
m∠F = 14x
m∠F = 140º
