of the compounds below, a 0.1 m aqueous solution of ________ will have the highest ph.

Answers

Answer 1

Of the compounds below, a 0.1 M aqueous solution of KCN, Ka of HCN = 4.0 × 10⁻¹⁰ will have the highest pH.

The pH is given as :

pH = pka + log [base] / [acid]

ka for the HCN is 4.0 × 10⁻¹⁰ , the pka = -log ka.

pka = - log (4.0 × 10⁻¹⁰)

pka = 9.30

pH = pka + log [KCN ] / [HCN]

The KCN  is the salt of the strong base and the weak acid. The salt of the weak acid and the strong base will have the highest pH . so among the given option , the salt of weal acid and the strong base is the KCN, Ka of HCN = 4.0 × 10⁻¹⁰.

The question is incomplete, the complete question is :

Of the compounds below, a 0.1 m aqueous solution of ________ will have the highest ph.

NaOAc, Ka of HOAc = 1.8 × 10⁻⁵

NaClO, Ka of HClO = 3.2 × 10⁻⁸

NH₄NO₃, Kb of NH3 = 1.8 × 10⁻⁵

KCN, Ka of HCN = 4.0 × 10⁻¹⁰

NaHS, Kb of HS- = 1.8 × 10⁻⁷

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Related Questions


3. How many grams of oxygen gas are required to produce 2.9 moles of water?
4C5H₁1NH₂ + 370₂ → 20CO₂ + 26H₂O +

Answers

the answer to your mathematical highschool question is 46.3942

Students at allendale high school were tardy most often for fourth hour, right after lunch. therefore, the administration decided to close campus for lunch. as a result, the number of students tardy for fourth hour drastically decreased. when questioned, the principal could say that open campus lunch was a contributing factor to student tardiness.
a. True
b. False

Answers

True: when questioned, the principal could say that open campus lunch was a contributing factor to student tardiness.

There are various techniques for determining whether a claim is true. When questioned, the principal could confirm that the claim that open campus lunch contributed to student tardiness was accurate. This is due to the fact that when they removed the open campus for lunch, student tardiness reduced.

Children are expected to arrive at school by the scheduled start time. Children are also expected to stay until the day is over. Coming to school after the start of the school day is being tardy. There are various definitions and procedures for tardiness in schools.

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Answer:

The answer is true :)

Explanation:

Use the drag and drop options to label each reaction type in the table below.

Answers

The first general equation represents a synthesis reaction and the second one is decomposition. Third equation represents a single displacement reaction and the last one is a double displacement reaction.

What is synthesis reaction?

There are different types of reactions. The combination of two species A and B giving a single product is called a synthesis reaction.

Hence, A  + B ⇒ C is a synthesis reaction.

In decomposition reaction, one compound breakes into its constituent groups or elements.

AB ⇒ A + B  is a decomposition reaction.

In a single displacement reaction, one element or group from a reactant is displaced by the other.

AB + C ⇒ AC + B is  a single displacement reaction.

In double displacement reactions, two groups or elements are displaced by other two groups.

AB + CD ⇒ AD + BC is a double displacement reaction.

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When water is lost, but electrolytes are retained, the first thing that happens is that

O both the ECF and the ICF become more dilute.
O there is an increase in the volume of the ECF.
O the osmolarity of the ECF falls.
O osmosis moves water from the ICF to the ECF.
O aldosterone is secreted.

Answers

When water is lost, but electrolytes are retained, the first thing that happens is that moves water from the ICF to the ECF.

About Intracellular Fluid (ICF)

The fluid inside of cells, also called the cytoplasm or cytosol, makes up about 60% of the water in the human body, totaling about 7 gallons. Organelles like the nucleus, endoplasmic reticulum, mitochondria, lysosomes, and Golgi apparatus are suspended in and supported by the ICF. Also found in the ICF are cellular building blocks like sugars, proteins, carbohydrates, and lipids.

About Extracellular Fluid (ECF)

ECFs are any body fluids that are not inside cells. The two main components of ECF are plasma and interstitial fluid (IF). The balance consists of cerebrospinal fluid, lymph, the synovial fluid in the joints, pleural fluid in the pleural cavities (lungs), pericardial fluid around the heart, peritoneal fluid in the peritoneal cavity (abdomen), and the aqueous humor of the eye. In mammals, milk is also considered an extracellular fluid.

The Movement of Solutes Between Compartments

The ICF has higher amounts of potassium, phosphate, magnesium, and protein compared to the ECF. The plasma has high concentrations of sodium, chloride, and bicarbonate, but lower levels of protein as compared to the ICF. While water moves passively via osmosis, sodium and potassium ions move in and out of cells using active transport ion pumps. The pumps are powered by adenosine triphosphate (ATP) to provide the energy to move the ions against their concentration gradients (i.e. sodium moves out of the cell and potassium is pumped in) and maintain the gradients inside and outside the cell.

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how many kcal are produced when 32.0 g of ch4 react? ch4 + 2o2 → co2 + 2h2o + 218 kcal

Answers

To find the number of kcal produced when 32.0 g of CH4 react, we need to first convert the given mass of CH4 to moles. To do this, we can use the molar mass of CH4, which is 16.0 g/mol.

32.0 g CH4 / 16.0 g/mol = 2.0 mol CH4

We can then use the balanced chemical equation to determine that for every mole of CH4 that reacts, 218 kcal are produced.

Therefore, when 32.0 g of CH4 react, 2.0 mol of CH4 react and produce 2.0 mol * 218 kcal/mol = <<2*218=436>>436 kcal.

How is ph important during digestion? a. digestion needs a constant ph to take place. b. different foods have different ph values. c. enzymes react best with acids. d. different enzymes work best at different ph values.

Answers

The value of pH is important during digestion because d. different enzymes work best at different pH values.

What is a protein enzyme molecule?

A protein enzyme molecule is a biomolecule used during digestion to carry out the chemical reaction in order to break down foods into smaller particles, which are well known to lower the activation energy requires to produce such reactions.

Protein enzyme molecules are well known to act under certain conditions and the maximum work rate of an enzyme depends on the environment which involves the pH value associated with the presence of hydrogen protons that are able to interact with the substrates of different digestive enzymes.

Therefore, with this data, we can see that protein enzyme molecules are able to lower the activation energy of a given chemical reaction and they work under specific environmental conditions including the pH of the media.

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Considering the following reaction
Pt²⁺(aq) + 2Br⁻(aq) ⇄ Pt(s) + Br₂(l) K=5.3 × 10³
if the concentration of Pt²⁺(aq) is 2.0 × 10⁻² M and the concentration of Br⁻(aq) is 2.0 × 10⁻² M
which of the following is true?
Question 5 options:
• Q > K reactants will form more products as the system reaches equilibrium.
• Q > K products will form more reactants as the system reaches equilibrium.
• Q < K reactants will form more products as the system reaches equilibrium.
• Q < K products will form more reactants as the system reaches equilibrium.
• Q = K the system is at equilibrium.

Answers

Q > K products will form more reactants as the system reaches equilibrium. Is true.

What is reaction quotient?

The ratio of products to reactants in a process at any particular moment is measured by the reaction quotient Q.By dividing the concentrations of the reactants raised to the power of their stoichiometric coefficients by the concentrations of the products raised to the power of their stoichiometric coefficients, the reaction quotient (Q) is computed.

Q = [Pt(s)][Br₂(1)] / [Pt²+(aq)][Br¯(aq)]²

And if initial concentrations of both Pt²+(aq) and Br-(aq)

is 2.0× 10-² M,

Therefore Q = (1)(1)/(2.0×10-²)³

Since this reaction's equilibrium constant (K) is 5.3 x 103, Q > K suggests that as the system achieves equilibrium, more reactants will be formed from the products.

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A 1.00 L solution saturated at 25∘C with lead(II) iodide contains 0.54 g of PbI2.
Calculate the solubility-product constant for this salt at 25∘C.

Answers

The solubility-product constant for this salt at [tex]25^{0}[/tex] C is 6.4 × [tex]10^{-9}[/tex]

The solubility product, or Ks, of an ionic compound is the quantity of ions in a saturated solution that are in equilibrium with the solid.

The term "solubility product" refers to the ability of a substance to dissolve as a solute in a solvent to form a solution. The solubility of the ionic compounds that break down in water to form cations and anions varies significantly.

Moles of dissolved [tex]PbI_{2}[/tex] = 0.54 g /461.05 g/mol =0.00117

concentration of dissolved [tex]PbI_{2}[/tex] = 0.00117 mol / 1.0 L = 0.00117 M

Concentration [tex]Pb^{2+}[/tex] = 0.00117 M

Concentration [tex]I^{-}[/tex]  = 2 x 0.00117 =0.00234 M

[tex]K_{sp}[/tex] = 0.00117[tex](0.00234)^{2}[/tex]  = 6.4 x [tex]10^{-9}[/tex].

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The presence or absence of a solute in the filtrate depends on _______.
the pore size of the membrane
The molecular weight and size of the solute as well as the MWCO and pore size of the membrane.
the MWCO of the membrane
the size of the solute
the molecular weight of the solute

Answers

The presence or absence of a solute in the filtrate depends on The molecular weight and size of the solute as well as the MWCO and pore size of the membrane.

The presence and the absent of the solute in the filtrate will depends on the molecular weight and the size of the solute as well as the MWCO that molecular weight cut off and pore size of the membrane. The molecular weight cut - off is the lowest molecular weight of the solute from which the 90% of the it is retained by membrane . The MWCO is important in the filtration.

The MWCO describes the pore size. it will describe the rejection capability of the membrane.

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Which is found inside the stem of a plant?
A. epidermis
B. root hairs
C. xylem
D. leaves

Answers

root hairs are found at the stem of a plant

Please Help Quick ASAP Hurry Chemistry Unit 4 Review Sheet
4. If 65.8 grams of SO3 are produced in the unbalanced reaction below, how many grams of oxygen reacted?
SO2(g) + O2(g) → SO3(g)

Work:
Ans:_________

Answers

Taking into account the reaction stoichiometry, if 65.8 grams of SO₃ are produced, a mass of  13.16 grams of oxygen reacted.

Reaction stoichiometry

In first place, the balanced reaction is:

2 SO₂ + O₂  → 2 SO₃

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

SO₂: 2 molesO₂: 1 moleSO₃: 2 moles

The molar mass of the compounds is:

SO₂: 64 g/moleO₂: 32 g/moleSO₃: 80 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

SO₂: 2 moles× 64 g/mole= 128 gramsO₂: 1 mole× 32 g/mole= 32 gramsSO₃: 2 moles× 80 g/mole= 160 grams

Mass of O₂ required

The following rule of three can be applied:If 160 grams of SO₃ are produced by 32 grams of O₂, 65.8 grams of SO₃ are produced by how much mass of O₂?

mass of O₂= (65.8 grams of SO₃× 32 grams of O₂)÷ 160 grams of SO₃

mass of O₂= 13.16 grams

Finally, 13.16 grams of oxygen reacted.

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A 5.0g sample of a hydrate of BaCl₂ was heated, and only 4.3g of the anhydrous salt remained.
What percentage of water was in the hydrate?

Answers

The percentage composition  of water in a hydrate of BaCl₂ is 14 %.

What is percent composition?

Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of element/mass of compound ×100.

It provides quantitative information about the compound and helps in it's analysis.

Percent composition helps in elemental analysis in compound .In the given compound, mass= 5 g and mass of anhydrous salt= 4.3 g , mass of water=5-4.3=0.7 g .

Therefore, percent composition is, 0.7/5×100=14 %.

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Cellulose is a polysaccharide which has O only 8-1,4-bonds between glucose units O only a-1,4-links bonds glucose units O both a-1,4-and a-1,6-bonds between glucose units O hemiacetal links joining glucose units O carbon-carbon bonds joining glucose units

Answers

In the polysaccharide cellulose, large numbers of monosaccharides are linked together through glycosidic linkages.

What is cellulose a polysaccharide of?

TPolysaccharides, which are the most ubiquitous carbohydrates in nature, serve a number of functions, including energy storage and incorporation into plant cell walls.

Tens to thousands of monosaccharides are joined together via glycosidic linkages to form large polymers known as polysaccharides. The three most frequent polysaccharides are starch, glycogen, and cellulose. They are collectively referred to as homopolymers because, after complete hydrolysis, each of these three exclusively yields one type of monosaccharide (glucose).

Heteropolymers may also comprise sugar acids, amino sugars, or non-carbohydrate substances in addition to monosaccharides. Polysaccharides, a class of non-reducing carbohydrates, are not sweet and do not change. 

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1s2 2s2 2p6 3s2 3p6 4s1 3d5 is the electronic configuration of
a. Cr2+
b. Cu
c. Cu2+
d. Cr

Answers

1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ is the electronic configuration of Cr. the correct answer is D.

There are 24 electrons in all, according to the electron arrangement. A neutral atom will contain 24 protons if it has 24 electrons. The element is determined by its proton count. Chromium, symbol Cr, is the 24th element.

Since Cr contains 24 protons and the +2 charge would result in the nucleus having 26 protons, Cr²⁺ is invalid.  Cu is made up of 29 protons. The copper would be Cu⁵⁺ as there are only 24 electrons. Cu²⁺ was rejected for the same reason.

Therefore, 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁵ is the electronic configuration of Cr.

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London-type smog results from the burning of a. forests b. gasoline c. coal d. hydrogen please select the best answer from the choices provided a b c d

Answers

Coal burning is the result of London-type smoge (option C)

A serious case of air pollution known as the Great Smog of London, or Great Smog of 1952, struck London, England, in December 1952. The city was covered in a thick layer of smog due to an extended period of exceptionally cold weather, an anticyclone, and windless circumstances. The majority of the airborne pollutants were caused by the usage of coal. From Friday, December 5, until Tuesday, December 9, 1952, it persisted before dispersing fast as the weather altered.

Significant disruption was caused by the smog, which was far worse than past "pea-souper" pollution storms in that it reduced visibility and even entered indoor spaces. In the weeks that followed the incident, government medical studies suggested that up to 4,000 people had died directly as a result of the pollution and that 100,000 more had become ill as a result.

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Drag each process to the correct category. determine whether heating or cooling takes place during each process. evaporation condensation freezing melting sublimation deposition

Answers

Heating occurs in the following categories- Heating , Condensation and deposition.

Cooling occurs in Cooling, Freezing and sublimation

The temperature change of a given volume of water as heat is applied at a constant pace is depicted by the heating curve for water. The temperature of the water doesn't fluctuate throughout a phase shift, creating a plateau on the graph.A substance's cooling curve is a graph representing the variation in temperature over time as it is allowed to cool. The gradient of the cooling curve is influenced by the heat capacity, thermal conductivity, and ambient temperature of the material.

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Draw the Lewis structure of CH3OH2+.Draw the Lewis dot structure of CH3OH2+.

Answers

The lone pairs or valence electrons represented by the dots. The valence electron of carbon is the first to be evaluated for each element.

What formal charge does the carbon and oxygen have in ch3oh2?

The oxidation number of O in [CH3OH2]+ is determined to be -2 based on the discussion that has been provided above. O has a formal charge of 1 and a partial charge that is negative. As a result, choice E is the right response. The CH3OH2Lewis +'s process involves the following steps: H |..plus H - H - O - H | | H H

The specified molecule is CH3OH2+.

What number of valence electrons does ch2n2 have?

16 valence electrons make up CH2N2. The carbon in concentration levels has 4 valence electrons, 2 nitrogen atoms offer different 5 valence shell, 2 hydrogen ions each have electron configuration, and so on.

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calculate the relative atomic mass of an element R given that the relative abundance of 63R and 65R are 68% and 32% respectively​

Answers

The relative atomic mass of an element R with two isotopes 63R and 65R is 63.64.

How to calculate relative atomic mass?

Relative atomic mass is the ratio of the average mass per atom of the naturally occurring form of an element to 1/12 of the mass of a carbon-12 atom.

The relative atomic mass (RAM) of an element with two isotopes can be calculated by multiplying the mass of each isotope by its respective percentage abundance as follows:

63R = 68%65R = 32%

RAM = (63 × 0.68) + (65 × 0.32)

RAM = 42.84 + 20.8

RAM = 63.64

Therefore, 63.64 is the relative atomic mass of the element R.

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Help pleaseeee I dont really understand what it is asking me. This is study island btw

Answers

Answer:

Hydrogen can only have 1 proton, if it has a different number of protons then its not hydrogen, elements with the same number of protons but different numbers of neutrons are called isotopes

The boiling point of methanol (CH3OH) is 64.7 °C. The boiling point of methyl mercaptan (CH3SH) is 5.96 °C. Which one of the following statements correctly explains this difference?
a) Methanol has a higher boiling point because it has ion-dipole interactions.
b) Methanol has a higher boiling point because it has stronger dispersion forces.
c) Methanol has a higher boiling point because it can form intermolecular hydrogen bonds.
d) Methyl mercaptan has a lower boiling point because it is nonpolar.
e) Methyl mercaptan has a lower boiling point because it is more polar than methanol.

Answers

CH3CH2OH has more dispersion forces than CH3OH, so it has the highest boiling point.

What is the boiling point of methanol CH3OH?

The primary alcohol and the simplest aliphatic alcohol is methanol, which consists of a methyl and an alcohol group. It serves as an amphiprotic solvent, a fuel, a metabolite for humans, mice, Escherichia coli, and other organisms, as well as a metabolite for Mycoplasma genitalium.

It is a primary alcohol, a volatile organic chemical, a one-carbon compound, and an alkyl alcohol. The acid is a methoxide's conjugate. The strongest intermolecular hydrogen bonds are formed by water, giving it the highest boiling point.

Although ethanol and methanol also create powerful intermolecular hydrogen bonds, water has twice as many intermolecular hydrogen bonds per molecule as ethanol and methanol do. This is so because, whereas in water, 2 H atoms are bonded to an electronegative oxygen atom.

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write an arrhenius reaction to determine if Ba(OH)2 is an acid or base

Answers

Answer:

The Arrhenius theory defines an acid as a substance that increases the concentration of hydrogen ions (H+) in an aqueous solution and a base as a substance that increases the concentration of hydroxide ions (OH-) in an aqueous solution.

To determine if Ba(OH)2 is an acid or a base, we can write an Arrhenius reaction:

If Ba(OH)2 is a base, it will dissociate in water to form Ba2+ ions and OH- ions, according to the equation:

Ba(OH)2(s) → Ba2+(aq) + 2OH-(aq)

If Ba(OH)2 is an acid, it will react with water to form Ba2+ and H3O+ ions, according to the equation:

Ba(OH)2(s) + H2O(l) -> Ba2+(aq) + 2H2O(l)

As we can see, in the first reaction Ba(OH)2 is a base, it will dissociate in water to form Ba2+ ions and OH- ions. Ba(OH)2 is a strong base and it can neutralize an acid, forming water and a salt.

If 0.75 g of a monoprotic weak acid required 22.50 mL of 0.510 M NaOH to titrate it, what is the molar mass of the acid

Answers

The molar mass of the acid is 65 g/mol if 0.75 g of a monoprotic weak acid used 22.50 mL of 0.510 M NaOH to titrate it.

The quantity of a substance in a specific volume of solution is known as its molarity (M) and this is written as M = n÷V where M is molarity, V is the volume of solution in liters, and n is the number of moles.

First, let's write the balanced equation is,

[tex]\mathrm{HA + NaOH \rightarrow NaA + H_2O}[/tex]

Now, we can calculate the number of moles of HA from the above formula,  

[tex]\begin{aligned}n&=\text{molarity}\times\text{volume}\\&=0.51\times2.25\times10^{-2}\\&=\mathrm{1.147\times10^{-2}\;mol}\end{aligned}[/tex]

By balanced chemical equation, the number of moles of NaOH is calculated as follows,

[tex]\begin{aligned}\text{moles of NaOH reacted }&= \frac{1}{1} \times\text{moles of HA}\\&=\frac{1}{1}\times1.147\times10^{-2}\\&=\mathrm{1.147\times10^{-2}\;mol}\end{aligned}[/tex]

Then, the molar mass of the acid is,

[tex]\begin{aligned}\text{number of moles (n)}&=\mathrm{\frac{mass}{molar\;mass}}\\\text{molar mass}&=\mathrm{\frac{mass}{n}}\\&=\mathrm{\frac{0.75\;g}{1.147\times10^{-2}\;mol}}\\&=\mathrm{0.6539\times10^{-2}\;g/mol}\\&=\mathrm{65.39g/mol}\\&\approx\mathrm{65\;g/mol}\end{aligned}[/tex]

The required answer is 65 g/mol.

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List all soluble salt

Answers

Answer:

Calcium, potassium, aluminum, chlorine, bromine

Explanation:

I do not know all of them, but here are some.

Rank the following in order of decreasing the rate of effusion. F2 SF6 He Ar a. He > F2 > SF6 > Ar b. He > F2 > Ar > SF6 c. Ar > He > SF6 > F2 d. SF6 > Ar > F2 > He e. OF2 > Ar> He > SF6

Answers

He> F2 > Ar > SF6.

How may effusion rates be compared?

A square root of a gas's molecular weight has an inverse relationship with the rate for effusion of that gas.A gas will effuse faster when it is lighter and more slowly when it is heavier.

N2 or O2: which has a greater effusion rate?

In comparison to oxygen, nitrogen has a smaller molar mass.As a result, the rate of nitrogen effusion is greater than that of oxygen effusion.

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"Choose the correct condensed structure from the name: hexene. O CH3​CHCHCHCH3​ O CHCCH2​CH3​ O CH3​CH2​CH2​CH2​CH2​CH3​ O CH3​CH2​CHCHCH2​CH3​"

Answers

The correct condensed structure of hexene is CH₃CH₂CH=CHCH₂CH₃.

A condensed structural formula also termed as semi-structural formula and it is used to describe the organic compounds in a line of text. They will be illustrated in a single line of text and specifies the atoms in the order which are located in a molecule.

Hexene is a hydrocarbon having chemical formula C₆H₁₂. It s used as a comonomer in the production of the polyethylene. There are several number of isomers in hexene, depending on the geometry and position of the double bond in the chain. One of the most common useful of isomers is 1-hexene as well as an alpha-olefin.

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Using the formula ln(p1/p2)=(delta H/R)(1/T2-1/T1)
The normal boiling point of benzene is 80.1°C, and the heat of vaporization is AHvap 30.7 kJ/mol. What is the boiling point of benzene in "C on the top of Mt. Everest where P 260 mmHg?

Answers

The entropy of vaporization of benzene is 86.7 J/mol.K. where the normal boiling point of benzene is 80.1°C, and the heat of vaporization is AHvap 30.7 kJ/mol.

T(benzene - C₆H₆) = 80.1 °C = 80.1 + 273.15 = 353.25 K.

ΔHvap(C₆H₆) = 30.7 kJ/mol.

ΔSvap(C₆H₆) = ?

ΔS(C₆H₆) = ΔH ÷ T

ΔS(C₆H₆) = 30.7 kJ/mol ÷ 353.25 K

ΔS(C₆H₆) = 0.087 kJ/mol·K = 86.7 J/mol·K.

ΔS - entropy of vaporization.

Benzene is a colorless or light-yellow liquid chemical. Primarily it is used as a solvent in the chemical and pharmaceutical industries, as a starting material and an intermediate in the synthesis of numerous chemicals, and in gasoline. Benzene is produced by both natural and man-made processes.

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find the limit, if it exists. (if an answer does not exist, enter dne.) lim x→−[infinity] (x6 + 2x9)

Answers

Lim x→−[infinity] (x⁶ + 2x⁹) exists, limit exists for the function x⁶ + 2x⁹ for x tends to -[infinity], and is equal to negative infinity, that is -[infinity].

To find the limit of the function as x approaches negative infinity, we need to substitute a large negative value for x and see what the function evaluates to.

However, in this case, we can see that the function is the sum of two polynomials:

x⁶ + 2x⁹

The term x⁶ becomes insignificant as x becomes very large in magnitude, as x⁶ becomes much smaller than x⁹. Therefore, the limit as x approaches negative infinity is the same as the limit of 2x⁹ as x approaches negative infinity.

Therefore, the limit is:

lim x→−[infinity] (x⁶ + 2x⁹) = lim x→−[infinity] (2x⁹)

lim x→−[infinity] (x⁶ + 2x⁹) = -2×infinity

lim x→−[infinity] (x⁶ + 2x⁹) = -infinity

So, the limit of the function (x⁶ + 2x⁹) as x approaches negative infinity is negative infinity.

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thin filaments of si may be prepared by the deomposition of sih4 to si and h2. what mass of sih4 is required to prepare 0.2173 g of si using this method

Answers

Mole of  [tex]SiH_{4}[/tex] is0.0077 and  The mass of [tex]SiH_{4}[/tex] is required to prepare is 0.2464g

The mole, abbreviated as mol, is the International System of Units' unit of material amount. How many elementary entities of a particular substance are contained in an object or sample is determined by the quantity of that material. The Avogadro number, or approximately how many nucleons (protons or neutrons) are in one gram of common matter, is the number of elementary particles in one mole. The most prevalent carbon isotope, carbon-12, weighs 12 grams, therefore the traditional definition of a mole was the quantity of elementary particles equal to that weight.

[tex]SiH_{4}\rightarrow Si+2H_{2}[/tex]

For the 0.2173g of Si , The moles of Si=[tex]\frac{Given\: mass}{Molar \:mass}[/tex]

moles of Si=[tex]\frac{0.2173}{28}[/tex]

moles of Si=0.0077

then,, According to Stoichiometry

moles of Si=moles of [tex]SiH_{4}[/tex]=0.0077

molar mass of [tex]SiH_{4}[/tex]=32g

mass of [tex]SiH_{4}[/tex]=moles of [tex]SiH_{4}[/tex] x 32g

mass of [tex]SiH_{4}[/tex]=32 x 0.0077=0.2464g

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Lewis structure, number of electron regions, hybridization, electric geometry, number of lone pairs, molecular geometry , bond angles and polar or non polar for TeO4 2-

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The Lewis structure of TeO4⁻² is: [Te]=O-O-O-O.

The number of electron regions is 8 (5 from the Oxygen atoms and 1 from the tellurium atom).

The hybridization of the Te atom is sp3.

The electron geometry is tetrahedral and the molecular geometry is also tetrahedral.

The number of lone pairs is 4 and the bond angles are 109.5 degrees.

The molecule is polar due to the difference in electronegativity between Te and O atoms.

A Lewis structure, also known as a Lewis dot diagram or electron dot diagram, is a way of representing the valence electrons of an atom in a chemical compound. The structure is named after Gilbert N. Lewis, who first proposed it in 1916. Lewis structures depict the chemical symbol of the atom in the center, with dots representing the valence electrons surrounding it. The number of dots corresponds to the number of valence electrons in the element. These dots are used to show the chemical bonds between atoms in a molecule, and can be used to predict the chemical properties and reactivity of the compound.

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in the ohio state studies, ________ refers to how strict a leader's standards are.

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Explanation:

reacting to something that has been said

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