The magnitude of smaller and larger radius is 45mm and 90mm respectively.
Using lens makers formula:
1/f = (n-1) (1/ [tex]r_{1}[/tex] - 1/ [tex]r_{2}[/tex])
where n is the index of refraction, [tex]r_{1}[/tex] and f is the focal length and the curvature's radius of the first surface the light touches, and [tex]r_{2}[/tex] is the second's radius of curvature. The radius of one surface is two times that of the other, such that one is concave to the incoming light and the other is convex.
Plugging in the values we get:
1/f = (n-1) (1/ [tex]r_{1}[/tex] + 1/ [tex]2r_{1}[/tex]) = 3(n-1) / 2[tex]r_{1[/tex]
(a) For magnitude of smaller radius:
3(n-1)f / 2 = 3(1.5-1)(60) / 2 = 45mm
(b) For larger radius:
[tex]r_{2} = 2r_{1}[/tex] = 90mm
Therefore, the magnitude of smaller and larger radius is 45mm and 90mm respectively.
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L=0.7m
m=2kg
Calculate the frequency of the pendulum
According to the given data the frequency of the pendulum is 0.595 Hz.
What is frequency and Hz?Frequency is defined as the rate of changes in current direction per second. It is given in hertz (Hz), an internationally recognised unit of measurement. One cycle per second is equal to one hertz. Cycles per second are represented by the unit hertz (Hz). A cycle is a full cycle of an opposing current or voltage wave.
What makes frequency important?The time rate of change observed in cyclical and periodic phenomena, such as mechanical motion, audio signals (sound), radio waves, and light, is specified by the frequency, an essential parameter in science and engineering.
Briefing:Calculate the period of oscillations formula is
T = 2π√(L/g)
T = 2 * π * √(0.7/9.80665)
T= 1.678 s
Then the frequency as the reciprocal of the period
f = 1/T
f =1/1.678
f = 0.595 Hz.
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A golfer takes three strokes to putt a golf ball into a hole. On the first stroke, the ball moves 5.1 m due east. On the second, it moves 1.8 m at an angle 20° north of east. On the third, it moves 0.50 m due north. If the golfer had instead hit the ball directly into the hole on the first stroke, what would have been the magnitude (in m) and direction of the ball's displacement? Give the direction as a positive angle measured counterclockwise from due east.
The three strokes to put the golf ball into a hole is given. we have to find the overall displacement of the golf ball and its direction measured counterclockwise due east. So, we take due east as 0°, north as 90°, and so on.
For 1st stroke, the ball moves 5.1m due east means 5.1m at 0°.
The displacement along x- direction for 1st stroke = 5.1m × cos 0° = 5.1m, and y-displacement = 5.1m × sin 0° = 0m.
For 2nd stroke, the ball moves 1.8m at an angle 20° north of east.
Its x-displacement = 1.8m × cos (20°) = 1.691m, and y-displacement = 1.8m × sin (20°) = 0.6156m.
For third stroke, the ball moves 0.50m due north, means 0.50m by 90°.
Its x-displacement = 0.5m × cos (90°) = 0m, and y-displacement = 0.5m × sin(90°) = 0.5m.
The overall x- and y- displacements of the ball are:
x = 5.1 + 1.691 + 0 m = 6.791 m, and
y = 0 + 0.6156 + 0.5 m = 1.1156 m, respectively.
And its direction is θ = y/x = 1.1156 ÷ 6.791 = 0.164° due east.
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A force of 30.ON is acted on a block of mass 15.0kg placed on a horizontal surface but the boxdoes not move. Calculate the magnitude of the frictional force between the surfaces when theapplied force is along the horizontal and when it makes angle 60° with the horizontal.
We will have the following:
1. In the first case, we will calculate the normal force:
[tex]N=(15\operatorname{kg}\cdot9.8m/s^2)\Rightarrow N=147N[/tex]Then, we will have that the fricion coefficient will be:
[tex]\mu_f=\frac{30.0N}{147N}\Rightarrow\mu_f=\frac{10}{49}\Rightarrow\mu_f\approx0.20[/tex]So the magnitude of the friccional force when applied horizontally will be of 30.0N.
2. And the magnitude when applied horizontal but the block is on an inclined surface of 60°, we will have that:
[tex]F=(10/49)(15.0\operatorname{kg}\cdot9.8m/s^2)\cos (60)\Rightarrow F=15N[/tex]So, the friction force when the force is applied, is 15N.
Now assume that a satellite of mass m is orbiting the earth at a distance r from the center of the earth with speed ve. A satellite of mass 2m is orbiting mars, also at a distance r from the center of mars, with a speed vm. What is the ratio tmte , the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution? the mass of the earth is me and the mass of mars is mm.
The ratio of the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution is (Rm/Re)^3/2.(Me/Mm)^1/2
The orbital velocity of the satellite is given by,
V = √(GM/R)
Where,
V is orbital velocity,
G is gravitational constant,
M is the mass of planet,
R is the distance from the centre of the planet to the satellite.
According to given condition,
Ve = √(GMe/Re)
Ve it the orbital velocity of earth,
Me is mass of the earth,
Re is the radius of the earth.
Also,
Vm = √(GMm/Rm)
Vm it the orbital velocity of mars,
Mm is mass of the mars,
Rm is the radius of the mars.
We know, time period of revolution,
T = distance/velocity
Time period od revolution of satelite of earth,
Te = 2πRe/√(GMe/Re)
Time period of revolution of satelite of mars,
Tm = 2πRm/√(GMm/Rm)
Now, dividing the time time period of revolution of mars by time period of revolution of earth,
Te/Tm = [2πRe/√(GMe/Re)]/[2πRm/√(GMm/Rm)]
Te/Tm = (Rm/Re)^3/2.(Me/Mm)^1/2
So the final ratio of both the time periods is (Rm/Re)^3/2.(Me/Mm)^1/2.
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A runner is initially going 5 m/s to the right when she slows down at to 2 m/s over 10
seconds.
a) What is her acceleration?
b) How far does she travel in these 10 seconds?
Answer:
acceleration =-0.3
distance =0.16m
Explanation:
the runner was initially moving with a velocity of 5mls and attained a final velocity of 2mls because it decelerated. therefore to find its acceleration you can go by the formula a=v-u÷t
the distance can be found by the formula v²=u²+2as
A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision
The magnitude of their common velocity if they move together after collision is 12.9 m/s.
What is the final velocity after collision?
The final velocity after collision is calculated by applying the principle of conservation of linear momentum as shown below.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
m₁ is the mass of the carm₂ is the mass of the pedestrianu₁ is the initial velocity of the caru₂ is the initial velocity of the pedestrianv is the their common velocity after collision(20)(16) + (5)(0.5) = v(20 + 5)
322.5 = 25v
v = 322.5/25
v = 12.9 m/s
Thus, the car and the pedestrian moved together after the collision suggestion an inelastic collision.
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The complete question is below:
A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision if the mass of the pedestrian is 5 kg.
If a car of mass 20 kg with a velocity of 16 m/s collides with a pedestrian, then the magnitude of common velocity, if they move after the collision of masses, is 12.9 m/s.
What is Collision?Any situation in which two or more bodies quickly exert forces on one other is referred to be a collision. The most common usage of the word "collision" relates to instances where two or more objects collide violently, while the scientific usage of the word does not refer to the amount of force involved.
According to the question, the given values are :
Mass of the car, m = 20 kg
The velocity of the car, u₁ = 16 m/s
The velocity of the pedestrian, u₂ = 0.5 m/s.
m₁ u₁ + m₂ u₂ = v (m₁ + m₂)
(20) × (16) + (5) × (0.5) = v(20 + 5)
322.5 = 25 × v
v = 322.5/25
v = 12.9 m/s
Hence, the magnitude of common velocity is 12.9 m/s.
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The complete question is :
A car of mass 20 kg moving with a velocity of 16 m/s collides with a pedestrian moving at a velocity of 0.5 m/s in the same direction, calculate the magnitude of their common velocity if they move together after a collision if the mass of the pedestrian is 5 kg.
Describe and explain a danger to a driver of not wearing a safety belt during a sudden stop.
Compare and contrast an active solar heating system with a radiator system
There are two types of solar system was there:
Active solar systemPassive solar system.What is solar system?One system that is energies with sunlight. In other words which convert the sun energy in other energy is called solar system. It made with silicon.
What is the difference between an active solar heating system with a radiator system?As we mentions earlier there are two types of solar system was their,
Active solar system.Passive solar system.Active solar system: This system made with silicon bar which excites by absorb the sunlight and excites by it. It can change energy between any energies and help others to grow more. It helps to make machines to make hot water and electricity and many more. It is not cost friendly. The costs for such custom systems range from $3,000 to $10,000 depending on the size of the space.
Passive solar system: This system is very much cost sufficient solar energy generator. This energy displace the extra things like electricity, natural gas, or other systems. It so cost friendly that by installing big windows and tress it can hold energy in day and release energy at night. This is called the radiator system as it radiates energy at night.
According to the discussion, this is the main difference between the an active solar heating system with a radiator system.
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line spectra from all regions of the electromagnetic spectrum, including the paschen series of infrared lines for hydrogen, are used by astronomers to identify elements present in the atmospheres of stars. calculate the wavelength of the photon emitted whe
The wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
From the Rydberg's formula;
1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex])
R = 1.097 ×[tex]10^{7} m^{-1}[/tex]
nfinal = 3
ninitial = 5
Calculating the wavelength of the photon by substituting values, in equation 1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex]) , we get:
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/[tex]3^{2}[/tex] - 1/[tex]5^{2}[/tex])
1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/9 - 1/25)
λ = 1.282 × [tex]10^{-6}[/tex] m
λ = 1282 nm
Therefore, the wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.
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If a tenth planet were to be discovered with a sidereal period of 125 years, what would be the radius or the orbit (distance from the Sun)? In your answer you need to have the number in the first blank and the correct abbreviated units in the second blank.
From the computation and the use of the Kepler's law, the period of the orbit is period of the orbit is 25 AU.
What is Kepler's law?The term Kepler's law has to do with the relationship between the relationship between the period of the satellite and the radius of the orbit in which the satellite is found.
According to the Kepler's law, we know that the square of the period of the satellite is directly proportional to the cube of the radius of the orbit. Having said this, we need to find the radius of the orbit and we have been told from the question as we have it above that the period of the satellite that is under consideration is 125 years.
Now;
T^2 = r^3
Given that;
T = period
r = radius of the orbit
Then;
r = T^2/3
r = (125)^2/3
r = 25 Au
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a navy blue car and a mint green cars drive on two different lanes of the same same very curved road. the radius of curvature of the path of the navy blue car, which has a mass of 1616 kg, is approximately 4/5 of that of the mint green car, which instead has a mass of 1818 kg. assume that neither car skids on the road. how do the static friction forces on the two cars compare, if the drivers are on the same street, both going at the local speed limit?
The friction force ratio between navy blue car and mint green car due to the centripetal force is 10/9.
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
The friction force is proportional to the centripetal force
From the question, we know that
mblue = 1616 kg
mgreen = 1818 kg
Rblue = 4/5 Rgreen
vblue = vgreen
Find the centripetal force ratio
Fcblue / Fcgreen = (mblue . vblue² / Rblue) / (mgreen . vgreen² / Rgreen)
Fcblue / Fcgreen = (1616 / 4/5 Rgreen ) / (1818 / Rgreen)
Fcblue / Fcgreen = 10 / 9
Hence, the tension in the cord is 32 newton.
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would not be an indication of a car getting ready to pull into your lane. a. a turn signal b. a hand signal c. wheels turned toward the street d. an open car door
The option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).
Option A is an indication of a car getting ready to pull into your lane because a turn signal is an indicator installed in the car to indicate the change of lanes. Option C is an indication of a car getting ready to pull into your lane, but it is not a 100% indication, because not every driver is going to notice if your wheels are turned or not.
Option B is an indication of a car getting ready to pull into your lane during day time because during day time the turn signal might not be bright enough to see. So one probably uses hand signal to make sure that other drivers see clearly that you are about to change lanes.
Therefore, the option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).
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Compare and contrast oxygen-16 and
oxygen-17.
Answer:
oxygen 16 has 8 protons and 8 neutrons, oxygen 17 has 8 protons and 9 neutrons
Explanation:
isotope's number is equal to the sum of its protons and neutrons
Answer:Oxygen 16 is number 16 while oxygen 17 is number 17 and oxygen 16 is also oxygen like oxygen 17.
Explanation: Common Knowledge in my brain....
a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart
Answer:
The acceleration of the cart:
a = 0.82 m/s²
Explanation:
Given:
m = 2.0 kg
F = 4.0 N
μ = 0.12
g = 9.8 m/s²
___________
a - ?
Friction force:
Ff = μ·m·g
2 Newton's law:
m·a = F - Ff
The acceleration of the cart:
a = ( F - Ff) /m
a = F/m - (μ·m·g) / m
a = F/m - μ·g
a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82 m/s²
Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2. 10 m/s. If the other skater acquires a speed of 3. 81 m/s, what is her mass in kilograms?
Her mass is approximately equal to 27 kilograms.
How do you prove that?First of all, you need to understand that momentum is a conserved quantity and the solution to this problem involves elastic collision.
Momentum can be defined as p = mv where p is momentum, m is mass, and v is velocity. Just like energy, momentum is a physical quantity that is conserved in an isolated system. Momentum is conserved as a result of Newton's third law, which states that [tex]F_A=-F_B[/tex].
You are given that the ice skaters bounce off each other, meaning the collision is elastic. Remember that in an elastic collision, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ where
m₁ is the mass of the first body, m₂ is the mass of the second body,u₁ is the initial velocity of m₁,u₂ is the initial velocity of m₂,v₁ is the final velocity of m₁, andv₂ is the final velocity of m₂.Suppose that m₁ = 49 kg, m₂ = x, u₁ and u₂ = 0 m/s, v₁ = 2.1 m/s, and v₂ = 3.81 m/s. Then the mass of the other ice skater is as follows:
49 · 0 + x · 0 = 49 · 2.1 + x · 3.81
0 = 102.9 + 3.81x
3.81x + 102.9 = 0
3.81x = -102.9
x ≈ -27
Since a mass value can't be negative, the absolute value of x is 27. Therefore, it's her actual mass in kilograms.
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a spotlight on the ground is shining on a wall away. if a woman tall walks from the spotlight toward the building at a speed of how fast is the length of her shadow on the building decreasing when she is from the building?
His shadow is shortening at a rate of dy/dt = 0.6m/s at the time.
What is triangle total degrees?The triangle's three angles add up to a total of 180 degrees
The individual is standing at point D and has his head at point E at the time indicated in the problem.
At that moment, his shadow is visible on the wall at y = BC.
The two right triangles ABC and ADE both contain similar triangles. The ratios on their respective sides in the similar triangles are equal:
AD/AB = DE/BC
8/12 = 2/y
y = 3
If we suppose that the man is x distance from the building, then the distance from the spotlight to the man is 12 x.
12-x/12 = 2/y
1-1/12x = 2 1/y
Let's take derivatives of both sides:
-1/12dx = -2 .1/y²dy
Divide both sides by dt as follows.
-1/12.dx/dt = 2/y²dy/dt
At the time specified:
dx/dy = 1.6m/s
y = 3
Let's connect them
- 1/2 (1.6) = -2.9 dy/dt
dy/dt = 1.6/12×9/2 = 0.6m/s.
At the time in question, this is the pace at which his shadow's length is shortening.
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The complete question is:
"A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.6 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?"
three different-mass projectiles are launched at different angles of elevation from the top of a building. each particle has the same initial kinetic energy. which particle has the greatest kinetic energy just as it impacts with the ground?
The correct option is b. The one with the lowest mass.
An object's kinetic energy is determined by
k=1/2mv^2
where
m is the object's mass.
v is the object's speed.
The three missiles in this puzzle have varying masses but the same beginning kinetic energy.
The three projectiles will all have the same kinetic energy when they hit the ground because mechanical energy is conserved, assuming there is no air resistance (because the potential energy that they have lost is the same, since they have been launched from the same height, and they reach the same final altitude, the ground).
hence,
K1=k2=k3
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Does anyone have an answer for this? I need it before 1:22pm (CDT)
As a scientist, you are studying the physical properties of various substances. In your line of work, how will you effectively use physical properties to identify each substance?
Answer:
I would use physical properties to identify each substance because anything with the same physical properties as previous substances in the past.
Explanation:
pls mark brainliest with the crown. I need more to level-up
Look at the diagram. Calculate the Rf value for sample 7. Give your answer to two decimal places.
The Rf value of sample 7 is 0.94.
What are Rf values?Rf (retention factor) values are values that are used to identify compounds in thin-layer chromatography.
Rf values are obtained by taking the ratio of the distance traveled by the solvent (solvent front) and that traveled by the substance or unknown compound.
Rf = distance traveled by compound / distance traveled by the solventThe Rf value of sample 7 is calculated below:
distance traveled by compound = 33 mm
distance traveled by the solvent = 35 mm
Rf value = 33 mm/ 35 mm
Rf value = 0.94
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What is the focal length of a concave lens that forms an image with a xi value of -10.0 cm when an object is 35.0 cm from the lens?
Answer:
1 / f = 1 / object + 1 / image = 1 / 35 - 1 / 10 thin lens equation
f = o * i / (o + i)
f = -10 * 35 / (-10 + 35) = -350 / 25 = -14 cm
HELP!
Mr. Mock sets up a demonstration on a moving bus. The device consists of a ball attached with a string to a magnet. He uses the magnet to hang the ball from the top of the school bus as the bus turns the corner at a constant speed. What will the ball do?
a
The ball swings backward.
b
The ball swings forward.
c
The ball swings to the outside of the curve.
d
The ball swings toward the inside of the curve
Answer:
The ball swings to the outside of the curve (assuming that the road is level.)
Explanation:
Assume that the air resistance on the ball in this question is negligible. The only forces acting on this ball will be tension that the string exerts on this ball and the weight of the ball.
Since the ball is in a centripetal motion, the net force on this ball will point directly to the center of the curve.
Refer to the diagram attached. The net force on this ball is the vector sum of weight and tension. Since weight points downwards, tension will need to point upwards to balance weight and toward the center of the curve, so that resultant force points horizontally toward the center of the curve.
The tension on the ball points along the string away from the ball (toward the ceiling.) For the tension that the string exerts on this ball to point toward the center of the curve and upwards, the ball will need to swing away from the center of the curve (as show in the diagram.)
Therefore, the ball will swing towards the outside of the curve (away from the center of the curve.)
Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]Select one:6.2 m214.4 m211.3 m218.4 m2
Apply:
C = A e0 / d
Where:
C = capacitance = 1pf = 1 x10^-12 F
A = area
ε0 = 8.85×10^-12
1 pf = 1 x 10^-12 F
A = Cd / ε0 = 1 x 10^-12 ( 1 x 10^-4 ) / 8.85×10^-12 = 1.13 x10 ^-5 m^2
I need help with question 7, I just need the answer you don’t have to explain.
Explanation
Step 1
free body diagram
so, for m1
m1= 10 kg
so,
[tex]\begin{gathered} \sum ^{forces}_{\text{ y}}=T_1-mg=ma \\ T_1=m_1(a+g)\Rightarrow equation(1) \\ T_1=10(a+g) \end{gathered}[/tex]and for m2
[tex]\begin{gathered} \sum ^{forces}_{\text{ x}}=m_2g\sin (37)-T_1=m_2a \\ \text{solve for T}_1 \\ T_1=m_2g\sin (37)-m_2a \\ \text{replace} \\ T_1=(3.6\text{ kg)(9.8 }\frac{m}{s^2})\sin 37-3.6a \\ T_1=21.23\text{ -}3.6a\Rightarrow eq(2) \end{gathered}[/tex]Step 2
now, replace in equaiotn (1) and solve for a
[tex]\begin{gathered} T_1=m_1(a+g)\Rightarrow equation(1) \\ 21.23\text{ -}3.6a=10(a+g) \\ 21.23\text{ -}3.6a=10a+10g \\ -7.2a=10a-98.1 \\ -17.2a=-98.1 \\ a=-\frac{98.1}{-17.2} \\ a=5.703\text{ }\frac{m}{s^2} \end{gathered}[/tex]finally, replace in equation (2) to find Tension
[tex]\begin{gathered} T_1=21.23\text{ -}3.6a \\ T_1=21.23\text{ -}3.6(5.703) \\ T_2=3.891\text{N} \end{gathered}[/tex]I hope this helps you
Pick the answer that correctly completes the sentence: as a sound wave approaches an observer the frequency will _____, the wavelength will____, and the speed of sound will______.A) decrease; increase; stay the same B) increase; increase; increase C) increase; decrease; stay the same D) decrease; decrease; increase
To find
Pick the answer correctly that fits the sentence.
Explanation
In a doppler effect, when a sound source apporaches a observer, its frequency increases. As wavelength is inversely proportional so the wavelength decreases. Speed of sound ina given medium is constant, so the speed of sound doesnot change
Thus,
as a sound wave approaches an observer the frequency will increase, the wavelength will decrease, and the speed of sound will stay the same.
Conclusion
The correct option is C) increase; decrease; stay the same.
Arthur walks 3 km north, and then turns east and walks 4 km. What is distance traveled and his displacement?
The distance travelled by Arthur is 7 km and his displacement is 5 km.
What is the distance covered by Arthur?
The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.
Distance = 3 km + 4 km
Distance = 7 km
The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.
d = √(a² + b)
where;
a is the northward motionb is the eastward motiond = √(3² + 4²)
d = 5 km
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What are three modern inventions that could not have been invented without the earlier contributions of sir isaac newton?.
Answer:
there are the three basic
first law also called the law of inertia
the second one is the second law of motion and its equation is
F = ma
where m is the mass and a is the acceleration
its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]
the third law is called the action-reaction law
also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law
F=GmMe/[tex]R^{2}[/tex]
The G value is 6.673*10^-11
m is the mass of an object
Me is the mass of the earth in our case we consider the object and the earth.
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What conditions must be met in order for work to be done?
Check all that apply.
A. The applied force must make the object move.
B. At least part of the applied force must be in the same direction as
the movement of the object.
c. The output force must be greater than the input force.
D. The work must be greater than the momentum. you
Answer: B) force must be in the same direction as movement
Explanation:
What stage ends when the piglets
are weaned at about 2-4 weeks?
A. Farrowing
B. Loading
C. Breeding
D. Finishing
the answer to this is finishing
a propeller is modeled as five identical uniform rods extending radially from its axis. the length and mass of each rod are 0.711 m and 2.99 kg, respectively. when the propellor rotates at 569 rpm (revolutions per minute), what is its rotational kinetic energy?
The rotational kinetic energy of five identical uniform rods is 9436.21 joule.
We need to know about rotational kinetic energy to solve this problem. Rotational kinetic energy can be defined as the energy of a rotating object. The magnitude of rotational energy is
KE = 1/2 . I . ώ²
where KE is rotational kinetic energy, I is inertia and ώ is angular velocity.
From the question above, the given parameters are
L = 0.711 m
m = 2.99 kg
N = 5
ώ = 569 rpm = 59.59 rad/s
Find the total inertia of five identical rods
I = N . 1/2 . m . L²
I = 5 . 1/2 . 2.99 . 0.711
I = 5.31 kg.m²
Calculate the rotational kinetic energy
KE = 1/2 . I . ώ²
KE = 1/2 . 5.31 . 59.59²
KE = 9436.21 joule
Find more on rotational kinetic energy at: https://brainly.com/question/25803184
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A ball is thrown upward with an initial velocity of 20ft/s.
a ) What is the acceleration of the ball on its way up?
b ) what is the velocity of the ball at the very top of its path?
c) what is the acceleration of the ball on its way down?
Answer: the acceleration is 63737737ey
the velpcoty is is 7-922=2929
the acceleration down is 99102>2929<92
Explanation: because when the ball goes up it has to come down due to gravity, physics, and your very kind and nice mother. I hope this helped you! i bet you will ace this assignment.
