Find the area of each circle to the nearest tenth.Use 3.14
Answer:
153.86
Step-by-step explanation:
Area = Pi*R^2
Or
3.14xRadiusx Radius= Area
so 3.14*7*7=153.86
If this helps can I get Brainliest pls.
ayúdenme a calcular el valor de x
Answer:
12m,
Step-by-step explanation:
A customer will borrow $12,000 to buy a car. Which loan option would allow
the customer to pay the least amount of interest?
A 4-year loan with a 5.2% annual simple interest rate
A 5-year loan with a 4.2% annual simple interest rate
A 6-year loan with a 4.7% annual simple interest rate
O
A 3-year loan with an 8.4% annual simple interest rate
Answer:
number one is the best one
The loan option that will allow the customer to pay the least amount of interest is 4-year loan with a 5.2% annual simple interest rate.
Calculation of loan with least simple interest rateFormula for simple interest = P ×T × R/100
P = Principal amount borrowed ($12,000)
T = Time in various years given
R = Rate of simple interest generated
To determine which loan option that would allow the customer to pay the least amount of interest, the simple interest of each option is calculated below
Simple interest of a 4 years loan = 12000×4×5.2/100
= $2,496
Simple interest of a 5 years loan= 12000×5×4.2/100
= $2,520
Simple interest of a 6 years loan= 12000×6×4.7/100
= $3,384
Simple interest of a 5 years loan= 12000×3×8.4/100
= $ 18,144
Therefore, the loan option that will allow the customer to pay the least amount of interest is 4-year loan with a 5.2% annual simple interest rate.
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what is 3x10)+(3456/3629) + (2341x123) + (123 infinity x 90) i will give branliest
Answer:
∞
Step-by-step explanation:
I assume you meant 3×10 + 3456/3629 + 2341×123 + 123 ∞×90 and x is multiplication and not a variable.
A scientist poured 2/3 of a liter of water into a cup and 3/10 of a liter of water into a jar. Which comparisons are true about the amounts of water the scientist poured?
Answer:
Step-by-step explanation:
The cup has 33.(66)% more liters than the jar.
The cup has more water than the jar.
The cup has 11/30 more liters of water than the jar.
What’s the answer mines not correct
Answer:
v=72 in3
sa=104 in2
Step-by-step explanation:
hope this helps!
Use the image below to find the angles assuming is parallel to F.
81
W
E
Q
F
C
P
Find all angles congruent to ZGPC.
The angles congruent to Z GPC are (select)
simplify each expression
Solution (5):
Simplifying the expression.
(8x + 1) + (-x + 7)=> 8x + 1 - x + 7=> 7x + 8Solution (6):
Simplifying the expression.
(8x - 3) - (3x + 1)=> (8x - 3) + (-3x - 1)=> 8x - 3 - 3x - 1=> 5x - 4Solution (7):
Simplifying the expression.
(2x + 7) + (4x - 10)=> 2x + 7 + 4x - 10=> 6x - 3Solution (8):
Simplifying the expression.
(-7x + 2) - (3x - 3)=> (-7x + 2) - 3x + 3=> -7x + 2 - 3x + 3=> -10x + 5[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's solve ~
First ~[tex]\qquad \sf \dashrightarrow \: (8x + 1) + ( - x + 7)[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x + 1 - x + 7[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - x + 1 + 7[/tex]
[tex]\qquad \sf \dashrightarrow \: 7x + 8[/tex]
Second ~[tex]\qquad \sf \dashrightarrow \: (8x - 3) - (3 x + 1)[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - 3 - 3x - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - 3x - 3 - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 5x - 4[/tex]
Third ~[tex]\qquad \sf \dashrightarrow \: (2x + 7) + (4x - 10)[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x + 7 + 4x - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x + 4x + 7 - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: 6x - 3[/tex]
Fourth ~[tex]\qquad \sf \dashrightarrow \: (- 7x + 2) - (3x - 3)[/tex]
[tex]\qquad \sf \dashrightarrow \: - 7x + 2 - 3x + 3[/tex]
[tex]\qquad \sf \dashrightarrow \: - 7x - 3x + 2 + 3[/tex]
[tex]\qquad \sf \dashrightarrow \: - 10x + 5[/tex]
A rectangle has a perimeter of 48 ft. The length and width are scaled by a factor 1.5.
What is the perimeter of the resulting rectangle?
Answer:96+ a factor of 3
Step-by-step explanation:
48+48=96
1.5+1.5=3
A school held a special math event for parents. On the first night, 150 parents attended, which was 40% below the expected attendance. On the second night, 210 parents attended, exceeding the expected attendance by 40% . By what percent did the actual attendance at the special math event exceed or fall below the expected attendance for both nights?
Answer:
10.429% exceed
Step-by-step explanation:
expected:
150x [100+40]/100=210 parents were expected on first night
210x60/100=126 parents expected on the second night
210+126=326 expected
percentage difference=
210+150=360
360/326 x 100=110,429%
110,429%-100%=10,429% exceed
A rectangle has a length of 5.5 units and a width of 6 units.
What is the area of the rectangle?
Answer:
A =33 units^2
Step-by-step explanation:
The area of a rectangle is found by
A = l*w where l is the length and w is the width
A = 5.5* 6
A =33 units^2
Triangle ABC is similar to triangle DEF find the value of "X" and "y". What is the sum of
the perimeters of the triangles?
Tickets to a football match cost €8, €15 or €20 each. The number of €15 tickets sold was double the number of €8 tickets sold. 6000 more €20 tickets were sold than €15 tickets. If the gate receipts totaled €783 000, how many of each type of ticket were sold?
Answer:
8 -9788.8
15-273+4+484
The sum of 8 terms of an A.P. is 12, and the sum of 16 terms is 56.
Find the AP
Answer:
Step-by-step explanation:
[tex]S_{n}=\dfrac{n}{2}(2a + (n-1)*d)[/tex]
Here, n- number of terms ; d - common difference ; a - first term
[tex]S_{8}=12\\\\\dfrac{8}{2}[2a+(8-1)*d]=12\\\\4[2a+7d]=12\\\\2a + 7d = \dfrac{12}{4}\\\\\\2a + 7d = 3 \ -----------------------(i)[/tex]
[tex]S_{16}=56\\\\\dfrac{16}{2}(2a+15d)=56\\\\\\8(2a+15d)=56\\\\2a + 15d=\dfrac{56}{8}\\\\\\[/tex]
2a + 15d = 7 ----------------(ii)
Subtract (i) from equation (ii)
(ii) 2a + 15d = 7
(i) 2a + 7d = 3
- - -
8d = 4
d = 4/8
d = 1/2
Plugin d = 1/2 in equation (i)
[tex]2a +7*\dfrac{1}{2}=3\\\\\\2a = 3 -\dfrac{7}{2}\\\\\\2a =\dfrac{6}{2}-\dfrac{7}{2}\\\\\\2a=\dfrac{-1}{2}\\\\\\a=\dfrac{-1}{2*2}\\\\\\a=\dfrac{-1}{4}[/tex]
Second term = first term + d
[tex]=\dfrac{-1}{4}+\dfrac{1}{2}=\dfrac{-1}{4}+\dfrac{2}{4}=\dfrac{1}{4}[/tex]
[tex]Third \ term =\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{2}{4}=\dfrac{3}{4}\\\\\\Fourth \ term =\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{3}{4}+\dfrac{2}{4}=\dfrac{5}{4}\\\\[/tex]
AP is :
[tex]\dfrac{-1}{4}; \dfrac{1}{4};\dfrac{3}{4};\dfrac{5}{4}.......[/tex]
i need help please thanks
Answer: You simply need to match each fraction to where they belong
Step-by-step explanation:
Kim worked 9 hours and completed 3/4 of a project
of a project. If she continues to work at the same rate, how many more hours will she need to complete the project?
✨✨
My bad for not paying attention in class lol
Answer:
She'll need 3 more hours to complete the project
Step-by-step explanation:
Because (3/4) × (4/3) = 1, you can multiply 9 by 4/3 to find the total amount of time needed for the project. You'll get a total time of 12 hours. To find how many more hours needed you would do 12 - 9 = 3 hours
if y = lim [-3x^3+2x^2-4x+5] when x--> -2
In this case to calculate the limit, you simply plug the x value of -2 into the function
[tex]y = \lim_{x \to \--2}( -3x^3+2x^2-4x+5) = 24 + 8+8+5 = 45\\[/tex]
So the limit equals 45.
Hope that helps!
Answer:
[tex]\displaystyle y = 45[/tex]
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle y = \lim_{x \to -2} \big[ -3x^3 + 2x^2 - 4x + 5][/tex]
Step 2: Find Limit
[Limit] Limit Rule [Variable Direct Substitution]: [tex]\displaystyle y = -3(-2)^3 + 2(-2)^2 - 4(-2) + 5[/tex]Evaluate: [tex]\displaystyle y = 45[/tex]∴ the limit as x approaches -2 of the given function -3x³ + 2x² - 4x + 5 is equal to 45.
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---
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
What is 5.316 - 1.942 btw (show ur work) :)
Answer:
3.374
Step-by-step explanation:
[tex]\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}[/tex]
[tex]\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}[/tex]
[tex]\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}[/tex]
[tex]\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}[/tex]
[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4\\[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}\\[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{7}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&11&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&\linethrough{1}&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{3}&7&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}[/tex]
=3.374
Please help I’m not really sure what the answer is :£)
What is the value of the expression ( 4 + 5 ) 2 ÷ ( 2 4 − 7 ) ?
Answer: n
Step-by-step explanation:
18/17 ≈1.058823529
PLEASEEEE HELPPPPPPPP ASAPPPPPP
Answer:
y=2.75x+3
Step-by-step explanation:
$2.75 per sandwich (coefficient)
Solid $3 fee (y-intercept)
y=mx+b ---> y=2.75x+3
HELP PLEASE
ITS NOT D
9.
What is the rate of decay, r (expressed as a decimal), for data best modeled by the exponential function y equals 3.31 left parenthesis 0.87 right parenthesis superscript x baseline?
r = 0.13
r = 0.87
r = 2.88
r = 3.31
The rate of decay r is -0.139.
What is a function?A function has an input and an output.
A function can be one-to-one or onto one.
It simply indicated the relationships between the input and the output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
The exponential function [tex]y = 3.31(0.87)^x[/tex] can be written in the form
[tex]y = ab^x,[/tex]
where a = 3.31 and b = 0.87.
The formula for the rate of decay for an exponential function in the form
[tex]y = ab^x[/tex]is r = ln(b)
where ln is the natural logarithm.
In this case,
r = ln(0.87) ≈ - 0.139.
Since r represents the rate of decay as a decimal, the answer is r = - 0.139.
Thus,
The rate of decay r is - 0.139.
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Please help me! I'm stuck! If you answer both a and b, you get brainliest and points!
Beth is filling a small backyard pool with a garden hose. The pool holds 30 gallons of water. After 5 minutes, the pool is about one fourth full.
a. Assuming that the water is flowing at a constant rate, about how much water is going into the pool each minute?
b. About how long will it take to fill the pool?
The water is flowing into the pool at 1.5 gallons per minute and it would take 20 minutes to be filled.
What is an EquationAn equation is used to show the relationship between two or more numbers and variables.
The pool holds 30 gallons of water. After 5 minutes, the pool is about one fourth full. Hence:
Time to full the pool = 5 minutes * 4 = 20 minutes
Rate of water flow = 30 gallons/20 minutes = 1.5 gallons per minute
The water is flowing into the pool at 1.5 gallons per minute and it would take 20 minutes to be filled.
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Stan had a personal best one mile run time
of 6 minutes and 35 seconds. After his last
run, his new personal best is 6 minutes and 20
seconds.
The time difference computed from the personal best given shows that Stan was 15 seconds faster.
How to calculate time?From the information given, Stan had a personal best one mile run time of 6 minutes and 35 seconds. After his last run, his new personal best is 6 minutes and 20 seconds.
Therefore, the difference in time till be:
= 6.35 - 6.20
= 15 seconds.
Therefore, Stan was 15 seconds faster.
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A right cylinder has a radius of 3 cm and a height of 7 cm.
(a) Find the Surface Area of the cylinder.
(b) Find the Volume of the cylinder.(c) If you wanted more volume in your cylinder, which of these two ideas would give the most Volume?
1. Doubling the radius to 6 cm, while the height remains 7 cm.
-OR-
2. Tripling the height to 21 cm, while the radius remains 3 cm.
Answer:
a) 188.4955592
b) 197.9203372
c) 1
Step-by-step explanation:
The product of two numbers is 10 times the value of
6 × 8. Which expression shows the two numbers?
Answer:
8 x 60
Step-by-step explanation:
Hope it helps.
Use the qoutation below as your guide in giving example of situation on how you are going to apply your significant learnings about properties of parallel lines in real life.
"The road of life twists and turns and no two directions are ever the same. Yet our lessons come from the journey, not the destination.” - Don Williams, Jr.
Calculate the probability of randomly selecting a vehicle with an engine size greater than 3. 9 L.
The probability we consider factors that decide what engine is chosen and the odds of choosing an engine size greater than 3.9 L
Probability of choosing an engine sizeAn engine size greater than 3.9 L
Generally, This can be defined as the possibility of an event occurring with respect to other possible outcomes.
Probability looks at calculating the possibility of a given event's occurrence.
To determine the possibility of selecting an engine size greater than 3.9 L, we consider factors than decide what engine is chosen and the odds of choosing an engine size greater than 3.9 L
Hence, the probability we consider factors that decide what engine is chosen and the odds of choosing an engine size greater than 3.9 L
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1. Solve for x = 9/36 x/48
12
192
28
6.8
Answer:
x = 12
Step-by-step explanation:
I am unable to decipher what "x = 9/36 x/48" means.
I'll assume that the question is to find a value of x such that:
x/48 = 9/36
If so, cross multiply:
36x = (48*9)
36x = 432
x = 12
please solve for X!!
Since Angle XYZ equals 70 degrees, thus the sum of the Angle XYW and Angle WYZ equal 70 degrees
Angle XYW + Ange WYZ = 70
50 + (3x + 14) = 70
3x + 14 = 20
3x = 6
x = 2
Hope that helps!
Answer:
x = 2
Step-by-step explanation:
m<XYZ = 70 and
m<XYZ = m<XYW + m<WYZ
So we can conclude 50 + 3x + 14 = 70 add like terms
64 + 3x = 70 subtract 64 from both sides
3x = 6 divide both sides by 3
x = 2