Answer:
q1: 0.5m/s2
Explanation:
What is the speed of a helicopter that traveled 1500 miles in 7 hours?
A softball player swings a bat, accelerating it from rest to 2.2 rev/srev/s in a time of 0.20 ss . Approximate the bat as a 2.3-kgkg uniform rod of length 0.96 mm , and compute the torque the player applies to one end of it.
Answer:
83.168 Nm
Explanation:
I=mass of bat* ( length )^2 /3
Moment of inertia from one end = 2.2 * (0.96)^2 / 3.
Ang. acc. = 2.2×2 pi / 0.2 = 22pi
Torque = 2.3 * (0.96)^2 / 3 * 22 pi = 83.168 Nm SI units
What is the relationship between a planet’s distance from the sun and the length of its year? Explain.
Answer:
Planets that are close to the sun have shorter years, and planets that are farther have longer years, because of how fast/slow it orbits the sun.
Explanation:
A neutron star consists of neutrons at approximately nuclear density. Estimate, for a 10-km-diameter neutron star its mass number, its mass, the acceleration of gravity at its surface.
Answer:
a) 7.2*10^55
b) 1.2*10^29 kg
c) 3.2*10^11 m/s
Explanation:
Given a diameter of 10 km, that's a radius of 5 km.
We first attempt to find its mass number
A = (r/1.2*10^-15)³
A = (5/1.5*10^-15)³
A = 7.2*10^55
This gotten mass number is then multiplied by the mass of each neutron in the star. With each neutron being, 1.7*10^-27
M = 7.5*10^55 * 1.7*10^-27
M = 1.2*10^29 kg
And finally, using the formula
g = GM/r², we can find its acceleration due to gravity.
g = (6.67*10^-11 * 1.2*10^29) / 5000²
g = 8*10^18 / 2.5*10^7
g = 3.2*10^11 m/s
If a boat and its riders have a mass of 1100 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it
Answer:
-929.5Joules
Explanation:
To get the work done by sam, we will calculate the kinetic energy of sam expressed as;
KE = 1/2mv²
m is the mass = 1100kg
v is the velocity = 1.3m/s
KE = 1/2(1100)(1.3)²
KE = 550(1.69)
KE = 929.5Joules
Since Sam is opposing the direction of movement, work done by him will be a negative work i.e -929.5Joules
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. The proton must impact the nucleus with a kinetic energy of 2.30 MeV. Assume the nucleus remains at rest. With what speed must the proton be fired toward the target?
Answer:
[tex]V_1= 3.4*10^7m/s[/tex]
Explanation:
From the question we are told that
Nucleus diameter [tex]d=5.50-fm[/tex]
a 12C nucleus
Required kinetic energy [tex]K=2.30 MeV[/tex]
Generally initial speed of proton must be determined,applying the law of conservation of energy we have
[tex]K_2 +U_2=K_1+U_1[/tex]
where
[tex]K_1[/tex] =initial kinetic energy
[tex]K_2[/tex] =final kinetic energy
[tex]U_1[/tex] =initial electric potential
[tex]U_2[/tex] =final electric potential
mathematically
[tex]U_2 = \frac{Kq_pq_c}{r_2}[/tex]
where
[tex]r_f[/tex]=distance b/w charges
[tex]q_c[/tex]=nucleus charge [tex]=6(1.6*10^-^1^9C)[/tex]
[tex]K[/tex]=constant
[tex]q_p[/tex]=proton charge
Generally kinetic energy is know as
[tex]K=\frac{1}{2} mv^2[/tex]
Therefore
[tex]U_2 = \frac{Kq_pq_c}{r_2} + K_2=\frac{1}{2} mv_1^2 +U_1[/tex]
Generally equation for radius is [tex]d/2[/tex]
Mathematically solving for radius of nucleus
[tex]R=(\frac{5.50}{2}) (\frac{1*10^-^1^5m}{1fm})[/tex]
[tex]R=2.75*10^-^1^5m[/tex]
Generally we can easily solving mathematically substitute into v_1
[tex]q_p[/tex][tex]=6(1.6*10^-^1^9C)[/tex]
[tex]K_1=9.0*10^9 N-m^2/C^2[/tex]
[tex]U_1= 0[/tex]
[tex]R=2.75*10^-^1^5m[/tex]
[tex]K=2.30 MeV[/tex]
[tex]m= 1.67*10^-^2^7kg[/tex]
[tex]V_1= (\frac{2}{1.67*10^-^2^7kg})^1^/^2 (\frac{(9.0*10^9 N-m^2/C^2)*(6(1.6*10^-^1^9C)(1.6*10^-^1^9C)}{2.75*10^-^1^5m+2.30 MeV(\frac{1.6*10^-^1^3 J}{1 MeV}) }[/tex]
[tex]V_1= 3.4*10^7m/s[/tex]
Therefore the proton must be fired out with a speed of [tex]V_1= 3.4*10^7m/s[/tex]
Unpolarized light with intensity 300 W/m^2 passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity 121 W/m^2. What is the angle from vertical of the axis of the second polarizing filter?
Answer:The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°
Explanation:
What are electromagnetic waves?
Answer:
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields. They are also perpendicular to the direction of the EM
Explanation:
If you apply an equal force to a larger mass, it will take longer to accelerate.
Tru or false
Answer:
true
Explication:
The acceleration of an object depends on the mass of the object, and the amount of force applied
I WILL GIVE YOU BRIANLIEST PLEASE HELP!!!!!!
A small plane starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds. What is the plane’s acceleration?
An elf pushes a sleigh with force of 9N over a distance of 11m. How much work did the elf. Do on the sleigh
Answer:
99 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 9 × 11
We have the final answer as
99 JHope this helps you
Difference between compressions and rarefactions
Answer:
Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart.
Answer:
please mark as brainliest!!!!
Explanation:
Compression- a region in a longitudinal (sound) wave where the particles are closest together.
Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart.
How does air resistance affect how fast a feather falls?
Answer: Ain't its because how light the feather is ? It's not as heavy.
Explanation: With air resistance, acceleration throughout a fall gets less than gravity (g) because air resistance affects the movement of the falling object by slowing it down. ... Usually, resistance is not very high at low speed or for small or sharp objects (Google Source if needed to prove yours answer)
i need help with the one someone?
Answer:A road sign gives drivers informaton about traffic on busy highways. One sign shows 15 miles in 20 minutes. What is this speed in miles per hour?
Explanation:
What is the conflict in this passage?
Tony worries about how to fight Felix without hurting him.
Tony cannot figure out how to get down from the roof.
Tony no longer wants to be friends with Felix.
Tony wants to figure out a way for both of them to win.
Answer:
the conflict in this passage is
Tony worries about how to fight Felix without hurting him.
it right i just took the test
The conflict sentence in the passage is, Tony worries about how to fight Felix without hurting him.
What is meant by conflict?Conflict can be meant as clash happened between one another of different individuals and they used to arise out for one's own process, their way of understanding and their interests and also it depends upon everyone's perception. Also, conflicts leads to physical abuse.
In the given sentences,
A. Tony worries about how to fight Felix without hurting him.
Here, there is a point to thinking about no physical abuses and loss of peace and harmony.
B. Tony cannot figure out how to get down from the roof.
In the above sentence Tony was just thinking an idea about how to come down from the roof. There will not be any clashes.
C. Tony no longer wants to be friends with Felix.
The above sentence was only about the relationship of Tony and Felix.
D. Tony wants to figure out a way for both of them to win.
This sentence is completely in the positive approach to attain success.
So, the correct answer is option A.
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Can you find two ways that carbon can get from the ocean to the lithosphere?
Answer:
Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.
Hope that helps!
what does this weather map symbol represent, and what type of weather can typically
be expected when this symbol is shown?
A blue "H" means a center of high pressure (usually calm, sunny weather). A red "L" means low pressure (which can mean storminess). Most fronts extend from low-pressure centers.
The weather symbol blue 'H' represents high pressure while red 'L' represents Low pressure.
What is a weather symbol?Weather symbols can be described as symbols with which meteorologists indicate various atmospheric and natural conditions on special weather maps such as temperature, pressure, precipitation, wind, or the percentage of cloud coverage in the sky. These maps can be used to be paper maps or digital.
Warm fronts can be described as indicated by curved red lines with red semicircles. Cold fronts can be curved blue lines with blue triangles. Stationary fronts exhibit alternating red curves with semicircles and blue curves with triangles. There are 99 present weather symbols used in meteorology.
The eight elements observed by meteorologists for creating weather forecasts are air temperature, humidity, wind speed, wind direction, visibility, clouds, precipitation, and atmospheric pressure.
On weather maps, readings are represented as a red “L” for low pressure or a blue “H” for high pressure.
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Two particles each with a charge -Q are fixed a distance L apart . Each particle experiences a net electric force F. A particle with a charge +q is now fixed midway between the original two particles. As a result, the net electric force experienced by each negatively charged particle is reduced to F/2. The value of q is:_________.
A. Q
B. Q/2
C. Q/4
D. Q/8
E. Q/16
Answer:
B. Q/2
Explanation:
Given;
charge of the two particles, = -Q
distance between the two charges, r = L
the net force experienced by each charge = F
Apply coulomb's force between two charged particles;
[tex]F = \frac{KQ^2}{r^2} = \frac{kQ^2}{L^2}[/tex]
when
+q is introduced midway between the charges, the net force is reduced by 2
[tex]\frac{F}{2} = \frac{kQq}{L^2} \\\\ \frac{1}{2}(\frac{kQ^2}{L^2} ) = \frac{kQq}{L^2}\\\\\frac{kQ^2}{2L^2} =\frac{kQq}{L^2} \\\\\frac{Q}{2} = q[/tex]
Thus, The value of q is Q/2
The value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.
Given here,
-Q = charge of the two particles
r = distance between the two charges = L
F = net force on each charge
From coulomb's force between two charged particles;
[tex]\bold{F = \dfrac {KQ^2}{r^2} =\dfrac {kQ^2}{L^2} }[/tex]
If +q is bring at mid point between the charges, the net force is reduced by 2
Thus, q = Q/2
Therefore, the value of q is Q/2, when the net electric force experienced by each negatively charged particle is reduced to F/2.
For what absolute value of the phase angle does a source deliver 71 % of the maximum possible power to an RLC circuit
Answer: the absolute value of the phase angle is 28°
Explanation:
taking a look at expression for the instantaneous electric power in an AC circuit;
P = VI -------let this be equation 1
p is power, v is voltage and I is current;
for maximum power
P_max = V_rms × I_rms --------let this be equ 2
where P_max is the maximum power, V_rms is the rms value of voltage and I_rms is the rms value of current.
Also for average electric power in an AC circuit
P_avg = V_rms × I_rms × cos²∅ -------let this be equ 3
where P_avg is the average power and cos∅ is the power factor
now from equation 2; P_max = V_rms × I_rms
so p_max replaces V_rms × I_rms in equation 3
we now have
P_avg = P_max × cos²∅
so we substitute
expression for the given value of the average power is
P_avg = P_max × 75%
p_avg = P_max.78/100
for the expression of the average electricity in an AC circuit
P_max.78/100 = P_max × cos²∅
78/100 = cos²∅
to get the absolute value of phase angle
∅ = cos⁻¹ ( √(78/100))
∅ = cos⁻¹ ( 0.8832)
∅ = 27.969 ≈ 28°
Therefore the absolute value of the phase angle is 28°
We have that for the Question "For what absolute value of the phase angle does a source deliver 71 % of the maximum possible power to an RLC circuit"
It can be said that
[tex]45^o[/tex] of the phase angle is required to deliver 71 % of the maximum possible power
Power delivered to RLC circuit is given by
[tex]P = \frac{V^2}{Z}cos\theta\\\\P = I^2Zcos\theta[/tex]
Therefore,
[tex]Z = \sqrt{R^2 + (X_L-X_C)^2}[/tex]
Power delivered is maximum, therefore,
[tex]P_{max} = cos\theta\\\\71\% = cos\theta\\\\cos\theta = 0.71\\\\\theta = cos^{-1}0.71\\\\\theta = 44.76^o\\\\approximately 45^o[/tex]
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What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaires are to be installed
Complete Question
What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaries are to be installed?The lamps to be installed are rated 75 watts at 277 volts. This is NOT a continuous load so each circuit can carry 20 amps maximum
Answer:
The number is [tex]k = 11[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 20 \ A[/tex]
The voltage is [tex]V = 277 \ volt[/tex]
The power rating of each bulb is [tex]P = 75 \ W[/tex]
The total number of incandescent luminaries is [tex]n = 810[/tex]
Generally the amount of current each lamp takes is mathematically represented as
[tex]I_e = \frac{P}{ V}[/tex]
=> [tex]I_e = \frac{75}{ 277}[/tex]
=> [tex]I_e = 0.270 \ A[/tex]
Generally the number of bulb fitting(i.e bulbs ) a 20 A current can supply (i.e the bulbs the branch ) to is
[tex]N = \frac{I}{I_e}[/tex]
=> [tex]N = \frac{20 }{ 0.270 }[/tex]
=> [tex]N = 73.86[/tex]
Generally the number of 20-amp 277-volt branch circuits required is mathematically represented as
[tex]k = \frac{n}{N}[/tex]
=> [tex]k = \frac{810}{73.86}[/tex]
=> [tex]k = 11[/tex]
Help me! Btw he’s playing golf.
Answer:
Muscular energy
Explanation:
Hope it helps!!!!
If you push against the wall the wall will push back what is the name of the force that pushes back?
tension force
Оа
Ob
Ос
normal force
applied force
friction force
Od
Answer:
applied force
Explanation:
I think that's right
A projectile is fired at a speed of 125 m/s toward a tall building. The building is a horizontal distance of 75 meters from the point where the projectile is launched. The projectile strikes the building 30 meters above ground level. Find the launch angle of the projectile.
Answer:
what is 30 + 40 add
Explanation:When we walk, our legs alternatively swing forward about the hip joint as a pivot. In this motion the leg is acting approximately as a physical pendulum. Treating the leg as a thin uniform rod of length 0.80 m, find the time it takes for the leg to swing forward.
Answer:
0.3 seconds
Explanation:
When we walk, our legs alternatively swing forward about the hip joint as a pivot. In this motion the leg is acting approximately as a physical pendulum. Treating the leg as a thin uniform rod of length 0.80 m,
To find the time it takes for the leg to swing forward, where g = 9.8 m/s^2
Let's use the simple pendulum formula which says that:
T = 2π( sqrt ( L/g))
T = 2π[sqrt (0.8/9.8)]
T = 2π × 0.082
T = 0.5129
For the leg to swing forward only, the number of complete oscillations will be half.
Period T = time t ÷ number of complete oscillations. That is,
T = t ÷ 1/2
0.5129 = t ÷ 1/2
t = 0.5129 × 1/2
Time t = 0.256 seconds.
Therefore, the time it takes for the leg to swing forward is 0.3 seconds approximately
What would be harder to accelerate- a 4kg shot put ball or a 2,000 kg boulder
Answer:
2,000 kg boulderExplanation:t
The Inertial is the resistance of a body at rest to be in motion
Given the following item
1. 4kg shot put ball
2. 2,000 kg boulder
The body of greater mass has greater inertia, hence would be harder to accelerate.
An object with a small inertial mass will accelerate more than an object with a large inertial mass when acted upon by the same force.
Of the 2 items in the list, the 2,000 kg boulder has the largest mass, hence it also has the greater inertial and more difficult to accelerate.
although acceleration usually causes a change in speed what causes a change in direction?
A.centripetal force
B.angular velocity
C.radian(rad)
D.centripetal acceleration
Answer:
B.
Explanation:
4. A massless spring hangs from the ceiling, and a mass is hung from the bottom of it. The mass is supported
so that initially the tension in the spring is zero. The mass is then suddenly released. At the bottom of
its trajectory, the mass is 5 centimeters from its original position. Find its oscillation period.
(A) 0.05 s
(B) 0.07 s
(C) 0.31 s
(D) 0.44 s
(E) Not enough information is given.
Answer:
The correct option is C: 0.31 s.
Explanation:
When the mass is then suddenly released we have:
[tex] F = k\Delta y [/tex]
Where:
F is the force
k: is the spring constant
Δy: is the spring displacement
Since the tension in the spring is zero, the force is the weight:
[tex] F = mg [/tex]
Where:
m is the mass of the object
g is the gravity
[tex] mg = k\Delta y [/tex] (1)
The oscillation period of the spring is given by:
[tex] T = 2\pi \sqrt{\frac{m}{k}} [/tex] (2)
By solving equation (1) for "k" and entering into equation (2) we have:
[tex] T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}} [/tex]
[tex]T = 2\pi \sqrt{\frac{\Delta y}{g}}[/tex]
Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:
[tex] T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s [/tex]
Hence, the oscillation period is 0.31 s.
The correct option is C: 0.31s.
I hope it helps you!
A block has two strings attached to it on opposite ends. One string has a force of 5 N,
the other string a force of 15 N. The block is accelerating at 1 m/s2 on a horizontal surface.
A) What is the mass of the block if the friction force is 3 N?
B) What is the coefficient of friction?
Unless you have a diagram to include or any other additional info, I'll assume the block is being pulled by two opposing forces along the horizontal surface.
Horizontally, the block is under the influence of
• one rope pulling in one direction with magnitude 15 N,
• the other rope pulling in the opposite direction with mag. 5 N, and
• friction, opposing the direction of the block's motion, with mag. 3 N.
It stands to reason that the block is accelerating in the direction of the larger pulling force.
(A) By Newton's second law, we have
15 N + (-5 N) + (-3 N) = m (1 m/s²)
where m is the mass of the block. Solve for m :
7 N = m (1 m/s²)
m = (7 N) / (1 m/s²)
m = 7 kg
(B) The friction force is proportional to the normal force, so that if f is the mag. of friction and n is the mag. of the normal force, then f = µ n where µ is the coefficient of friction.
The block does not bounce up and down, so its vertical forces are balanced, which means the normal force and the block's weight (mag. w) cancel out:
n + (-w) = 0
n = w
n = m g
where g = 9.8 m/s² is the mag. of the acceleration due to gravity.
n = (7 kg) (9.8 m/s²)
n = 68.6 N
Then
3 N = µ (68.6 N)
µ = (3 N) / (68.6 N)
µ ≈ 0.044
Hi so this is 15 points :D
The layers of Earth are the crust, mantle, and core, with the core being divided into inner and outer layers. Which of the following does NOT describe the layers of the solid Earth?
(A) The core makes up the majority of Earth's volume.
(B) The mantle is composed of rocks known as silicates.
(C) The crust is extremely thin when compared to the core or mantle.
(D) The core is made up of dense elements, such as iron and nickel.
Answer:
A. The core makes up the majority of Earth's volume.
Explanation:
Although the core and mantle are about equal in thickness, the core actually forms only 15% of earth's volume whereas the mantle takes up 84%
A block has two strings attached to it on opposite ends. One string has a force of 5 N,
the other string a force of 15 N. The block is accelerating at 1 m/s2 on a horizontal surface.
A) What is the mass of the block if the friction force is 3 N?
B) What is the coefficient of friction?
Answer:
A) 7kg
B) 0.044
Explanation:
a) Accordimg to Newton's second law
\sum F = ma
Fm - Ff = ma
Fm is moving force =15-5 = 10N
Ff is fictional force = 3N
m is the mass = ?
a Is the acceleration = 1m/s²
Substitute
10-3 = 1m
7 = m
Hence the mass of the body is 7kg
b) coefficient of friction is expressed as;
n = Ff/R
R is the reaction = mg
n =Ff/mg
Substitute
n = 3/7(9.8)
n = 3/68.6
n = 0.044
Hence the coefficient of friction is 0.044
