Roots spreading far and wide

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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Answer: Snakes are reptiles

Explanation: All reptiles are ectothermic (they obtain body heat from their environment).

As snake belongs to secondary consumer, it get  less amount of energy in food cycle. If producer (grass) get 100 unit of energy, according to food chain snakes only gets one unit of energy.

The sequence of events in an ecosystem known as a "food chain" occurs when one live organism eats another organism, which is then eaten by a larger organism. A food chain is created by the transfer of nutrients and energy from one creature to another at various trophic levels.

The feeding habits or connections between living things are also explained by the food chain. Trophic level is the term used to describe the orderly phases in a food chain, from producers at the bottom through primary, secondary, and tertiary consumers. A trophic level is any position along a food chain.

A food chain demonstrates the interdependence of all living things on one another. The direction of energy flow within an ecosystem is described by the food chain.

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Answer:

Explanation:

Moment of inertia of toy top = 3 x 10⁻²   kgm²

Torque created = F x r

= .30 x 2.5 x 10⁻² N m

Torque = moment of inertia x angular acceleration

angular acceleration = .3 x 2.5 x 10⁻² / 3 x 10⁻²

α = .25 radian /s²

Angular displacement in 5 revolution θ = 5 x 2π = 10π radian

θ = ω₀t + 1/2 α t²

initial angular velocity ω₀ = 0

10π = 1/2 α t² = .5 x .25 t²

t² = 251.2

t = 15.85 s

Answer: 7

Explanation: 7 is the superior number

Answer:

1,269 N

Explanation:

I guessed and got the question right on CK-12's work practice.

Answer:

What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)

Answer:

[a]. South direction

(b). 1.354 × 10^14 m/s^2

Explanation:

In order to to be able to solve this question effectively, one must be familiar with physics concepts such as kinetic energy[1/2 ×mass × velocity,v²], magnetic force[ magnetic force = charge × velocity × magnetic field × sin Ф] and Newton's law of motion especially the second law of Newton[ Force = mass × acceleration].  

(a). The direction are the electrons deflected by this field component = q( v × B) = - (  i × -k) = -( - ( i × k) = - (- (- j) = -j. The -j is in the south direction.

Note that  i × k is being replaced by -j.

(b). In order to determine the magnitude of the acceleration of an electron in part (a), the first thing to do is to calculate the velocity from the equation for kinetic energy.

Thus, velocity = √ [(2 × 2.7 × 10⁻¹⁵) ÷ 9.1 × 10⁻³¹] = 7.7 × 10^7 m/s.

The next thing is to determine the net force.

Therefore, the net force = 1.6 × 10^-19 × 7.7 × 10^7 m/s × 1 × 10^-15 sin 90°.

= 1.232 × 10^ -16N.

Hence, Net Force = mass × acceleration.

1.232 × 10^ -16N = 9.1× 10^-31 × acceleration.

The acceleration = 1.232 × 10^ -16N/ 9.1× 10^-31 = 1.354 × 10^14 m/s^2.

Answer:

The most common and important application of a diode is the rectification of AC power to DC power. Using the diodes, we can construct different types of rectifier circuits. The basic types of these rectifier circuits are half wave, full wave center tapped and full bridge rectifiers.

Explanation:

Here ya go <3

Answer:

A = 4.49

α = 57.72°

Explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

[tex]A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49[/tex]

The angle tangent can be used to determine the angle.

[tex]tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)[/tex]

Answer:

1)   [tex]kinectic energy=7.26*10^-^2^0J[/tex]

2)  [tex]V= 2.0m/s[/tex]

3)  [tex]T=3.5*10^3K[/tex]

4)  The Molecules do not burn because of the presences of hydrogen bond in place

Explanation:

From the question we are told that

latent heat of vaporization for water at room temperature is 2430 J/g.

1)Generally in determining the molar mass of water evaporated we have that

-One mole (6.02 x 10. 23 molecules)

-Molar mass of water is 18.02 g/mol

Mathematically the mass of water is give as

  [tex]M=\frac{18.02}{6.02*10^-^2^6}[/tex]

  [tex]M=3*10^-^2^3g[/tex]

Therefore

  [tex]kinectic energy=2430J/g*3*10^-^2^3g[/tex]

 [tex]kinectic energy=7.26*10^-^2^0J[/tex]

b)Generally the evaporation speed V is given as[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]

Mathematically derived from the equation

[tex]\frac{1}{2} mv^2 =K.E[/tex]

To Give

[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]

[tex]V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }[/tex]

[tex]V= 2.0m/s[/tex]

c)Generally the equation for velocity   [tex]Vrms=\sqrt{\frac{3RT}{M} }[/tex]

Therefore

Effective temperature T is given by

      [tex]T=\frac{\sqrt{v}*m}{R}[/tex]

where

     [tex]T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}[/tex]

     [tex]T=3.5*10^3K[/tex]

4) The Molecules do not burn because of the presences of hydrogen bond in place

Answer:

0.71 m/s

Explanation:

We find the time it takes the stone to hit the water.

Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.

So, substituting the values of the variables into the equation, we have

y = ut - 1/2gt²

82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²

82.2 m = 0 + (4.9 m/s²)t²

82.2 m =  (4.9 m/s²)t²

t²  = 82.2 m/4.9 m/s²

t² = 16.78 s²

t = √16.78 s²

t = 4.1 s

This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.

Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s

Answer:

Space technology is technology developed by space science for use in astronautics, for purposes such as spaceflight or space exploration. Space technology includes spacecraft, satellites, space stations, and support infrastructure equipment, and procedures and space warfare.

Explanation:

[tex]miles \: to \: km \\ = 1.2 \: miles \times \frac{1 \: km}{1.6093 \: miles} \\ = 0.7457 \\ \\ km \: to \: feet \\ = 1.8 \: km \times \frac{3280 \: ft}{1 \: km} \\ = 5904 \: ft[/tex]

Answer:

4.80 m

Explanation:

We are given the mass of the high jumper, its initial velocity, and the acceleration of gravity. We are trying to find the vertical displacement of the high jumper.

Let's set the upwards direction to be positive and the downwards direction to be negative.

List out the relevant known variables.

We still need one more variable in order to use the constant acceleration equations. Since we are trying to find the max height of the jumper, we can use the fact that at the top of its trajectory, its final velocity will be 0 m/s.

    4. v = 0 m/s

Using these four variables, let's find the constant acceleration equation that contains these variables:

Substitute the known values into the equation and solve for Δx.

The high jumper can jump to a max height of 4.80 m.

Answer:

6.309573e+16 joule is released by an earthquake of magnitude 8

Answer:

An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.

Explanation:

An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.

Answer:

5.6875 × 10^(10) electrons

Explanation:

To some this we will use the formula;

q = ne

Where;

q is charge

n is number of electrons

e is electron charge = 1.6 × 10^(-19) C

We are given q = -9.10 nc

1 nc = 10^(-9) C

Thus;

q = -9.1 × 10^(-9) C

Since q is negative, then e = -1.6 × 10^(-19) C

Thus;

-9.1 × 10^(-9) = n(-1.6 × 10^(-19))

n = -(9.1 × 10^(-9))/(-1.6 × 10^(-19))

n = 56875000000 electrons = 5.6875 × 10^(10) electrons

Answer:

1)   A> B, 2)  A = B,  3)    A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

        A> B

2) decalration A

         2,567 + 3,146 = 5,713

with two figures it remains

             5.7

statement B

         2.6 + 3.1 = 5.7

 A = B

3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

   2.536 * 1.4 = 3.6

  statement B

    2.536 * 1.41 = 3.58

          A> B

Answer:

4)

Explanation:

Efficiency is calculated by dividing the energy out by energy in, not multiplying

No machines are 100% Efficient

No machines are frictionless

4) is true

Answer:

54m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time taken  = 6s

Final velocity  = 18m/s east

Unknow:

How far did the object travel  = ?

Solution:

To solve this problem, we use one of the kinematics equation:

 We first find the acceleration which is the change in velocity

So;

        S  = [tex](\frac{v - u}{2} ) t[/tex]    

    S is the distance  

    v is the final velocity

    u is the initial velocity

    t is the time taken

  Therefore;

       S = [tex]\frac{18 - 0}{2}[/tex]  x 6  = 54m

Answer:

they are identical.

Explanation:

use coulomb law. the size of that line is just to confuse students because some sick teacher gets off on making you miss points. coulombs law says the magnitude of electric field is proportional to the size of the charge. here they are all +/-1 they are the same.

The true statement is "The electric force between A and B is greater than the electric force between C and D." The correct answer is B.

Electric force, also known as Coulomb force, is the attraction or repulsion between electrically charged particles. It is a fundamental force of nature that arises from the interaction of charged particles with each other. Electric force is described mathematically by Coulomb's law, which states that the magnitude of the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The direction of the force depends on the sign of the charges, with like charges repelling each other and opposite charges attracting each other.

Here in the Question,

The electric force between two charged objects depends on the magnitude of the charges and the distance between them. In this case, object A has a positive charge and object B has a negative charge, so there is an attractive force between them. Object C also has a positive charge, but it is separated by a larger distance from the negative charge at point D, so the electric force between C and D is weaker than the force between A and B.

Option A is not true because the distance between A and B is smaller than the distance between C and D, so the forces cannot be identical in magnitude.

Option C is not true because, as explained above, the force between A and B is greater than the force between C and D.

Option D is not true because the forces between A and B and between C and D are not opposite in direction, so they cannot cancel each other out.

Therefore, The correct answer is B. The electric force between A and B is greater than the electric force between C and D.

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Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of

tan(θ) = 15.80   →   θ ≈ 86.38°

The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of

∑ F = P - (M + m) g sin(θ) = (M + m) a

(see the attached free body diagram)

where

P = magnitude of the push

g = 9.80 m/s²

a = 2.53 m/s²

and M and m are the given masses.

Then the system requires a push of

P = (M + m) (a + g sin(θ))

P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

P ≈ 233 N

If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is

∑ F = T - M g sin(θ) = M a

where

T = tension in the rope

Then

T = M (a + g sin(θ))

T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))

T ≈ 175 N

Answer:

2. Smaller value of q = 1/4Q

3. Larger value of q = 3/4Q

Explanation:

1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.

2. The smaller value is

F = 75% = 75/100

= 3/4 * Q²/16piEod² ---3

When we equate 1 and 3

We get 3Q²/16 = Qq - q² from here we cross multiply to get

3Q² = 16(Qq-q²)

3Q² = 16Qq-16q²

16q² - 16Qq + 3Q² = 0

When solve this out using the quadratic equation formula, we have:

Q/2 +- 2Q/8

We can get the smaller value of q as

Q/2-2Q/8

Solve using LCM we get

2Q/8 = 1/4Q = Q/4

C. The larger value of q

Q/2+2Q/8

= 6Q/8

= 3Q/4

Please use the attachment it will guide you to understand this better.

Answer:

ω = 0.05 rad/s

Explanation:

We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,

[tex]Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\[/tex]

where,

ω = angular velocity of cylinder = ?

g = required acceleration = 9.8 m/s²

r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m

Therefore,

[tex]\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\[/tex]

ω = 0.05 rad/s

Answer:

those who are attracted to magnets. ex: iron, cobalt and nickel

the dig would -5 from where he first started.

Answer:

0.74 m/s

Explanation:

From the question,

We apply the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0

0 = Total momentum after collision

(m+M)V + m'v = 0

Where m = mass of the  skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v =  velocity of the brick

make V the subject of the equation above

V = -m'v/(m+M)................... Equation 1

Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.

Substitute these values into equation 1

V = -(2.5×21)/(68+2.5)

V = 52.50/70.5

V = 0.74 m/s

Answer: the mass is 1.60 kg and the acceleration on the rocket is...

58.4 m/s with a Power of Two

Explanation:

A model rocket lifting off from the launch pad is a good example of this principle. Just prior to engine ignition, the velocity of the rocket is zero and the rocket is at rest. If the rocket is sitting on its fins, the weight of the rocket is balanced by the re-action of the earth to the weight as described by Newton's third law of motion. There is no net force on the object, and the rocket would remain at rest indefinitely. When the engine is ignited, the thrust of the engine creates an additional force opposed to the weight. As long as the thrust is less than the weight, the combination of the thrust and the re-action force through the fins balance the weight and there is no net external force and the rocket stays on the pad. When the thrust is equal to the weight, there is no longer any re-action force through the fins, but the net force on the rocket is still zero. When the thrust is greater than the weight, there is a net external force equal to the thrust minus the weight, and the rocket begins to rise. The velocity of the rocket increases from zero to some positive value under the acceleration produced by the net external force. But as the rocket velocity increases, it encounters air resistance, or drag, which opposes the motion and increases as the square of the velocity. The thrust of the rocket must be greater than the weight plus the drag for the rocket to continue accelerating. If the thrust becomes equal to the weight plus the drag, the rocket will continue to climb at a fixed velocity, but it will not accelerate.

Answer:

is the fastest moving type of radiationhe

Answer:

We don't promote laziness here, my dear child. :)