Answer:d to reproduce
Explanation:
I took the test
Answer:
c
Explanation:
Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Answer:
Mass is the quantitative measure of inertia of any object.
Explanation:
The object that have largest mass will have largest inertia as well as largest momentum.
Real-world efficiencies are generally very high, in the 90 percent range. Please select the best answer from the choices provided. T F
Answer:
t
Explanation:
Answer: true
Explanation:
What is the definition of force according to the Newton first law of motion?
Answer:
A force is any interaction that, when unopposed, will change the motion of an object
Explanation:
One consequence of Newton's third law of motion is that __________. A. every object that has mass has inertia B. a force acting upon an object increases that objects acceleration C. all actions have equal and opposite reactions D. none of the above
Answer:
C i think
Explanation:
One consequence of Newton's third law of motion is that all actions have equal and opposite reactions. that means net force on body is zero.
What is force?A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.
If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object.
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How is electrolysis used in order to prevent materials from corrosion or rusting?
Answer:
We use electrolysis to prevent a material from rusting,
The metal forms a coating around the material and hence prevents any contact between the material and the environment
This process also gives us the physical strength of the material and the aesthetic properties of the coated metal
the metal commonly used to coat the object is Zinc and the process is called galvanisation
Pots A and B both have plain soil, bean seeds, and the same amount of light. Pot B receives more water (see table). After 50 days the plants are measured. Based on the data, what is the correct conclusion?
The amount of water affects the mass and the height of the plants.
What is the correct conclusion from the data obtained?The correct conclusion is the conclusion which the data obtained supports.
Plants need both water and sunlight to grow.
The variation the amount of water or sunlight that a plant receives will affect the growth rate of the plant.
Based on the data obtained from the experiment where Pots A and B both have plain soil, bean seeds, and the same amount of light, while Pot B receives more water, the amount of water affects the mass and the height of the plants.
In conclusion, plants need both water and sunlight for growth.
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most of our brains activity is:
A bug walking on the circular rim of a flower
pot completes one lap around the planter in
8.667 s.
If the radius of the planter is 13.9 cm, how
fast was it traveling?
Given parameters;
Time taken to complete a lap = 8.667s
Radius of flower = 13.9cm
convert to SI unit of m, 100cm = 1m
13.9cm gives [tex]\frac{13.9}{100}[/tex] = 0.139m
Unknown = speed
To solve this problem, we need to first find the circumference of the flower.
Circumference of the circular flower = 2 π r
where r is the radius of the flower;
Circumference = 2 x 3.142 x 0.139 = 0.87m
Now to find the how fast the bug is travelling,
Speed = [tex]\frac{distance}{time}[/tex]
Since the bug covered 1 lap, the distance is 0.87m
Now input the parameters and solve for speed;
Speed = [tex]\frac{0.87}{8.667}[/tex] = 0.1m/s
The bug is travelling at a speed of 0.1m/s
8432.0 L = ? ML (Megaliters)
Answer:
0.008432 ML
Hope this helps!
Halfway through Mila's run, when the music stopped playing, was there energy in Mila's phone? What is your
evidence?
Answer:
No energy
Explanation:
Use the picture to answer the question.
A red striped bowling ball with 3 finger holes.
Name at least three physical properties of the bowling ball.
Answer:
The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different shape. That is the physical properties of a bowling ball.
Explanation:
Answer: The bowling ball is round in shape and red in color. The bowling ball is smooth and hard.
Explanation:
did it on edge
Identify the atom
Ве
C
H
Не
Answer:
Be: Beryllium
C: Carbon
H: Hydrogen
He: Helium
The USC Trojan football team bus is heading to an away game, traveling on a long, straight road at a constant speed of 28.0 m/s. All of a sudden, at t = 0, a car full of students from the opposing team cuts in front of the bus, at a mere distance of 70.0 m ahead of the bus, moving in the same direction with a constant velocity of 6.00 m/s. The panic brake deceleration of the bus is 3.00 m/s2 . a) (10 Points) If the bus begins braking at t = 0, how much time will elapse until the bus and car collide? b) (5 Points) How far down the road, from the original position of the bus, will the collision occur? c) (10 Points) What would the acceleration of the bus have to be for the collision to be avoided?
Answer:
a. 17.34 s. b. 104.51 m c. -7.16 m/s²
Explanation:
a. The distance, d moved by the car at constant speed v = 6.00 m/s in time t which they collide is d = vt. The distance d' moved by the bus from its initial position 70 m away from the car with a constant velocity u = 28.0 m/s and deceleration a = -3.00 m/s² is d' = 70 + ut + 1/2at².
At collision, s = d
vt = 70 + ut + 1/2at²
substituting the values of the variables, we have
6t = 70 + 28t + 1/2(-3)t²
6t = 70 + 28t - 1.5t²
collecting like terms, we have
1.5t² + 6t - 28t - 70 = 0
1.5t² - 22t - 70 = 0
using the quadratic formula to find t, we have
[tex]t = \frac{-(-22) +/- \sqrt{(-22)^{2} - 4 X -70 X 1.5} }{2 X 1.5} \\t = \frac{22 +/- \sqrt{484 + 420} }{3} \\\\t = \frac{22 +/- \sqrt{904} }{3} \\\\t = \frac{22 +/- 30.01 }{3} \\\\t = \frac{22 - 30.01 }{3} or \frac{22 + 30.01 }{3} \\t = \frac{-8.01 }{3} or \frac{52.01 }{3} \\\\t = -2.67 s or 17.34 s[/tex]
We take the positive value.
So t = 17.34 s.
So, 17.34 s elapses before the bus and car collide.
b. Since the distance covered by the bus is d' = 70 + ut + 1/2at², this is how far down the road the collision occurs.
Substituting the values of the variables, we have
d' = 70 + 28 m/s × 17.34 s + 1/2(-3 m/s²)(17.34)²
d' = 70 + 485.52 - 451.01
d'= 104.51 m
c. To just avoid the collision, the bus must decelerate in the distance of 104.51 m from the car to the speed of the car. So using
v² = u² + 2ad' where v = 6.00 m/s, u = 28.0 m/s and d' = 104.51 m
the acceleration is thus
a = (v² - u²)/d'
a = ((6 m/s)² - (28 m/s)²)/104.51 m
a = (36 m²/s² - 784 m²/s²)/104.51 m
a = -748 m²/s² ÷ 104.51 m
a = -7.16 m/s²
C. 5 mi., North is it a scalar or vector
Answer:
Vector.
Explanation:
A vector has both magnitude and direction.
A scalar has just magnitude.
You and your friend Peter are putting new shingles on a roof pitched at 25 ∘ . You're sitting on the very top of the roof when Peter, who is on the edge of the roof, 5.4 m away, asks you for the box of nails. Rather than carry the 2.4 kg box of nails down to Peter, you decide to give the box a push and have it slide down to him. Part A If the coefficient of kinetic friction between the box and the roof is 0.51, with what speed should you push the box to have it gently come to rest right at the edge of the roof?
Answer:
Explanation:
Frictional force acting on the box = mg cos 25 x μ where μ is coefficient of friction
= 2.4 x 9.8 x cos 25 x .51 = 10.87 N
Weight of the box acting along the incline = mg sin 25 = 9.94 N
Net force = 10.87 - 9.94 = .93 N . It will create a deceleration of .93 / 2.4
= .3875 m /s² in the box.
v² = u² - 2 a s
v = 0 , a = .3875 , s = 5.4 m
= = u² - 2 x .3875 x 5.4
u = 2.045 m /s
question 8 how to do
Answer:
We know that the resistance of a material is its length divided by its cross-sectional area and all that multiplied by its resistivity
Hence, resistance = ρ * length(in m) / Cross-sectional area
(ρ = constant of resistivity)
If you do not understand cross-sectional area, comment on this answer
since both the wires are made of the same substance, both their resistivity will be the same
since we are told that both the wires have the same resistance,
(ρ * length 1) / cross-sectional area 1 = (ρ * length 2) / cross-sectional area 2
since they both have the same resistivity, both the ρ will cancel out
length 1 / cross-sectional area 1 = length 2 / cross-sectional area 2------(1)
Calculating the cross-sectional area
To simplify it , the cross-sectional area is the area of the circle you can currently see on either of the wire
let the radius of wire 1 = 2r
then, the radius of wire 2 = r
Cross-sectional area 1 = π (2r)^2 = 4πr^2
Cross-sectional area 2 = π (r)^2
Now, using these values in (1)
l / 4πr^2 = l' / πr^2
l / l' = 4πr^2/πr^2
l / l' = 4 / 1
the length of rod 'P' is l
from the equation, we can simplify:
l (length of rod 'P') = 4 l'(length of rod 'Q')
Therefore, we can say that the length of rod 'P' is 4 times the length of rod 'Q'
"How did your current and voltage measurements differ between the series and parallel circuits you created
Answer:
Series circuit:
The voltage that is measured across the circuit is different.
The current measured in a series circuit remains the same at all points in the circuit.
Parallel circuit:
The current measured across each resistor varies
The voltage measured across a parallel circuit will remain the same
Explanation:
Series and parallel circuits behave differently when it comes to the circulation of current and the interaction with a potential difference.
In a series circuit, the resistances are connected end to end. As a result, the voltage that is measured across the circuit is different once resistance is encountered. However, the current measured in a series circuit remains the same at all points in the circuit.
A parallel circuit behaves in an exactly opposite manner to the series circuit. In a parallel circuit, the resistances are connected side by side. As a result of this, the current measured across each resistor varies as there are circuit branches through which electric current can flow into. On the other hand, the voltage measured across a parallel circuit will remain the same
When the driver in the car moving with a speed of 15 ms-1 increases the
speed at a constant rate of 5 ms-2 . Calculate the speed attained by the
car, at the end of 5 s.
Sandstone is a sedimentary rock. Which two processes cause sand particles to form sandstone?
1. cementation and cooling
2.compaction and cementation
3.cooling and erosion
4.erosion and heating
Answer:
Compaction and cementation
Explanation:
Cementation: As ions are deposited by fluids to form a compound that hardens loose sedimentary rocks.
Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.
Answer:
number 2 is correct
Explanation:
cementation as icons are deposited by fluids to form a compound that hardens looses sedimentary rocks .
compaction is the density of sedimentary rocks on edge of them, are forced together though sediments mark me brainest add and follow me
A Tennis ball falls from a height 40m above the ground the ball rebounds
with 0.5 of the velocity with which it strikes the ground. If the ball rebound
with 1/2 of the velocity with which the balls strike the ground any time the
ball striked the ground. Calculate
[i] the position of the ball after 5s from the ground
[iiafter how many bounds will the ball remain on the ground
(iii) what is the time interval between the third and fourth bounds
(iii) predicts the velocity of the ball after 6s
If the ball is dropped with no initial velocity, then its velocity v at time t before it hits the ground is
v = -g t
where g = 9.80 m/s² is the magnitude of acceleration due to gravity.
Its height y is
y = 40 m - 1/2 g t²
The ball is dropped from a 40 m height, so that it takes
0 = 40 m - 1/2 g t²
==> t = √(80/g) s ≈ 2.86 s
for it to reach the ground, after which time it attains a velocity of
v = -g (√(80/g) s)
==> v = -√(80g) m/s ≈ -28.0 m/s
During the next bounce, the ball's speed is halved, so its height is given by
y = (14 m/s) t - 1/2 g t²
Solve y = 0 for t to see how long it's airborne during this bounce:
0 = (14 m/s) t - 1/2 g t²
0 = t (14 m/s - 1/2 g t)
==> t = 28/g s ≈ 2.86 s
So the ball completes 2 bounces within approximately 5.72 s, which means that after 5 s the ball has a height of
y = (14 m/s) (5 s - 2.86 s) - 1/2 g (5 s - 2.86 s)²
==> (i) y ≈ 7.5 m
(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But y will converge to 0 as t gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.
During the first bounce, the ball starts with velocity 14 m/s, so the second bounce begins with 7 m/s, and the third with 3.5 m/s. The ball's height during this bounce is
y = (3.5 m/s) t - 1/2 g t²
Solve y = 0 for t :
0 = (3.5 m/s) t - 1/2 g t²
0 = t (3.5 m/s - 1/2 g t)
==> (iii) t = 7/g m/s ≈ 0.714 s
As we showed earlier, the ball is in the air for 2.86 s before hitting the ground for the first time, then in the air for another 2.86 s (total 5.72 s) before bouncing a second time. At the point, the ball starts with an initial velocity of 7 m/s, so its velocity at time t after 5.72 s (but before reaching the ground again) would be
v = 7 m/s - g t
At 6 s, the ball has velocity
(iv) v = 7 m/s - g (6 s - 5.72 s) ≈ 4.26 m/s
A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?
Answer:
Explanation:
2.1 km = 2100 m
1.68 km = 1680 m
a ) Time taken by wild beast to travel 1680 m
= 1680 / 19 = 88.42 s
Time taken by wild beast to travel 2100 m
2100 / 19 = 110.52 s
distance travelled by chicken in 88.42 s
= 88.42 x 3.3 = 291.78 s
Its distance from the end point
= 2100 - 291.78 = 1808.22m
b ) Time taken by chicken to travel 2100 m
= 2100 / 3.3 = 636.36 s
Both reach simultaneously so , time of resting by wild beast
= 636.36 - 110.52 = 525.84 s .
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
there was a baboon on the tree which is 3m tall, if the baboon falls exactly on
the back of the horse and sped away with baboon at its back.
Calculate
I) how far was the horse from the tree and the time the baboon
falls on the horse.
The horse's position on the ground at time t is
x = (20 m/s) t
The baboon's height from the ground at time t is
y = 3 m - 1/2 g t²
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.
The baboon falls and lands on the horse, so that the two animals meet when the baboon's height is 2 m from the ground, which happens after
2 m = 3 m - 1/2 g t²
1/2 g t² = 1 m
t² = (2 m) / (9.80 m/s²)
t ≈ 0.452 s
In this time, the horse reaches the tree, so its distance from it is
(20 m/s) * (0.452 s) ≈ 9.04 m
An example of a Natural electric field is
Answer:
Lightning
Explanation
Which parts of the graph represents the object moving at a constant, positive acceleration?
Answer:
W and X
Explanation:
They are both straight lines and face upwards on the graph, this means it is a positive acceleration because upwards on the graph is a higher velocity. And a constant acceleration because the line is straight.
Also it can't be Z because Z is negative acceleration because the line goes down. and it can't be Y because there is no acceleration at Y because in the graph it shows it stays at 20 m/s. That leaves W and X.
The parts of the graph that represents the object moving at a constant, positive acceleration are W and X.
How to find the function which was used to make graph?A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
It cannot be Z because Z is negative acceleration because the line goes down. and Y because there is no acceleration at Y because in the graph it shows it stays at 20 m/s.
That leaves W and X.
W and X are both straight lines and face upwards on the graph, this means it is a positive acceleration because upwards on the graph is a higher velocity.
Also, a constant acceleration because the line is straight.
The parts of the graph that represents the object moving at a constant, positive acceleration are W and X.
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Jason took 6 hours to travel 540 km. For the first 140 km, he
took 2 hours. What was his average speed for the rest of the
journey?
km/h
Answer: 100
Explanation:
A roller coaster containing four cars is accelerating at 15 m/s2 before it comes to an abrupt stop at the end of the ride. The mass of one car is 200 kg. How much force was exerted on the roller coaster to bring it to a stop?
Answer: 12,000 Newton’s
Explanation: multiply by the number of cars the 200 kg.
The force exerted on the roller coaster to bring it to stop is 12000 N.
Given data:
The magnitude of acceleration of car is, [tex]a = 15 \;\rm m/s^{2}[/tex].
The mass of each car is, m = 200 kg.
As per the Newton's second law, the force is given as the product of acceleration and the mass of object. Then the force exerted on each car is,
F = ma
And the force exerted on the roller coaster is,
F' = 4F
F' = 4ma
Solving as,
[tex]F' = 4 \times 200 \times 15\\\\F' = 12000\;\rm N[/tex]
Thus, we can conclude that the force exerted on the roller coaster to bring it to stop is 12000 N.
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What is the displacement of a student who walks 12 m North, 5 m West, 3 m South,
and finally 6 m West to get to his next class?
When you draw all 4 of those moves, you see that he winds up 9m North and 11m West of where he started.
So the magnitude of his displacement is
D = √(9² + 11²) m²
D = √(81 + 121) m²
D = √(202) m²
D = 14.2 m
The direction is arctan(-11/9) = 50.7° west of North
Determine an example of a social influence.
a brother or sister
your best friend
a community leader
All are social influences.
Answer:
all are social influences
A certain lightning bolt moves 50.0 C of charge. How many units of fundamental charge is this?
A ball is thrown vertically upward from the surface of the earth. The ball rises to some maximum height and falls back toward the surface of the earth. Which one of the following statements concerning this situation is true if air resistance is neglected? a) As the ball rises, its acceleration vector points upward. b) The ball is a freely falling body for the duration of its flight. c) The acceleration of the ball is zero when the ball is at its highest point. d) The velocity and acceleration of the ball always point in the same direction.
Answer:
b) The ball is a freely falling body for the duration of its flight.
Explanation:
When an object is thrown upwards, it moves against the direction of gravity. Its velocity decreases with respect to its motion, and zero at the maximum height. After which it falls back to the surface of the earth.
Since the ball moves initially against the force of gravity, its acceleration would be -9.8 m/[tex]s^{2}[/tex] at its highest point. Thus since acceleration is constant, the ball is a freely falling body for the duration of its flight.
The correct option is option (b)
The ball is a freely falling body for the duration of its flight.
Freefall:If the ball is thrown upwards, it moves against the force of gravity. The gravitational acceleration is opposite to its motion.
The velocity of the ball decreases as it moves up, and zero at the maximum height since the gravitational acceleration is opposite to the motion. After which it falls back to the surface of the earth.
After reaching the highest point, the ball returns and falls back under the influence of gravity.
Any object which experiences only the gravitational force while falling down to the surface is the freely falling body.
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