Given
n= 5
p = 0.7
Find:
a. mean
b. variance
sol:
Mean d
[tex]\begin{gathered} mean\text{ =n}\times\text{p} \\ \\ \text{ = 5}\times\text{0.7} \\ \\ \text{ =3.5} \end{gathered}[/tex][tex]\begin{gathered} variance=np(1-p) \\ \\ =\text{ }5\times0.7(1-0.7) \\ \\ =3.5(0.3) \\ \\ =1.05 \\ \\ \end{gathered}[/tex]Solve the equation for w.
4w + 2 + 0.6w = −3.4w − 6
No solution
w = 0
w = 1
w = −1
Answer:
w = -1
Step-by-step explanation:
Given equation:
[tex]4w + 2 + 0.6w=-3.4w-6[/tex]
Add 3.4w to both sides:
[tex]\implies 4w + 2 + 0.6w+3.4w=-3.4w-6+3.4w[/tex]
[tex]\implies 4w + 2 + 0.6w+3.4w=-6[/tex]
Subtract 2 from both sides:
[tex]\implies 4w + 2 + 0.6w+3.4w-2=-6-2[/tex]
[tex]\implies 4w +0.6w+3.4w=-6-2[/tex]
Combine the terms in w on the left side of the equation and subtract the numbers on the right side of the equation:
[tex]\implies 8w=-8[/tex]
Divide both sides by 8:
[tex]\implies \dfrac{8w}{8}=\dfrac{-8}{8}[/tex]
[tex]\implies w=-1[/tex]
Therefore, the solution to the given equation is:
[tex]\boxed{w=-1}[/tex]
Given that,
→ 4w + 2 + 0.6w = -3.4w - 6
Now the value of w will be,
→ 4w + 2 + 0.6w = -3.4w - 6
→ 4.6w + 2 = -3.4w - 6
→ 4.6w + 3.4w = -6 - 2
→ 8w = -8
→ w = -8/8
→ [ w = -1 ]
Hence, the value of w is -1.
change this standard form equation into slope intercept form. 4x-5y= -17
The slope-intercept form is
[tex]y=mx+b[/tex]We have
[tex]4x-5y=-17[/tex]so we need to isolate the y
[tex]-5y=-4x-17[/tex][tex]y=\frac{-4}{-5}+\frac{-17}{-5}[/tex]We simplify
[tex]y=\frac{4}{5}x+\frac{17}{5}[/tex]ANSWER
The equation in slope-intercept form is
[tex]y=\frac{4}{5}x+\frac{17}{5}[/tex]
Consider the function f(x) =cotx. Which of the following are true? 2 answers
Graphing the function f(x) = cot(x) we have the following
We can observe that the function cot(x) has an asymptote at x = 0, and that it has a period of π.
The ship leaves at 18 40 to sail to the next port.
It sails 270 km at an average speed of 32.4 km/h
Find the time when the ship arrives.
Answer:
Step-by-step explanation:
Given:
t₁ = 18:40 or 18 h 40 min
S = 270 km
V = 32.4 km/h
____________
t₂ - ?
Ship movement time:
t = S / V = 270 / 32.4 ≈ 8.33 h = 8 h 20 min
t₂ = t₁ + t = 18 h 40 min + 8 h 20 min
40 min + 20 min = 60 min = 1 h
18 h +8 h = 26 h = 24 h + 2 h
2 h + 1 h = 3 h
t₂ = 3:00
The ship will arrive at the destination port at 3:00 the next day.
Answer:
32.4 - 27.0 = 5.4
18.40 + 54 =
7hrs:34mins
The ship arrived at
7:34pm
The ratio of the volume of two spheres is 8:27. What is the ratio of their radii?
We have that the volume of the spheres have a ratio of 8:27.
[tex]undefined[/tex]This means that the relation between linear measures, like the radii, will be the cubic root of that ratio
Question 2 1 Simplify. DO NOT PUT ANY SPACES IN YOUR ANSWER. Keep you answer in fraction form. -2/5t - 6+ 2/3t + 15
-2/5t - 6 + 2/3t + 15
Combining similar terms
(-2/5t + 2/3t) + (-6 + 15)
4/15t + 9
There are 6 dogs and 2 mice. Write a ratio for the number of ears to th number of paws. * 6:2 3 people are in a room. Write a ratio to represent the number of finger
each dog has 4 paws, then 6 dogs have 6*4 = 24 paws
each mouse has 4 paws, then 2 mice have 2*4 = 8 paws
Total number of paws: 24 + 8 = 32 paws
each dog has 2 ears, then 6 dogs have 6*2 = 12 ears
each mouse has 2 ears, then 2 mice have 2*2 = 4 ears
total number of ears: 12 + 4 = 16 ears
The ratio for the number of ears to the number of paws: 16/32 = 1/2 or 1:2
I need your help know
Given the following data
Base area of the cone = 6cm
Height of the cone = 9 cm
The volume of a cone is given as
[tex]\begin{gathered} V\text{ = }\frac{1}{3}\cdot\text{ }\pi\cdot r^2\cdot\text{ h} \\ \text{where }\pi\text{ = 3.14},\text{ r = 6cm , and h = 9cm} \\ V\text{ = }\frac{1}{3}\cdot\text{ 3.14 }\cdot6^2\cdot\text{ 9} \\ V\text{ = }\frac{1}{3}\text{ x 3.14 x 36 x 9} \\ V\text{ = }\frac{3.14\text{ x 36 x 9}}{3} \\ V\text{ = }\frac{1017.36}{3} \\ V=339.1cm^3 \end{gathered}[/tex]If each quadrilateral below is a square, find the missing measure
ANSWER
[tex]x=11[/tex]EXPLANATION
The figure given is a square.
Each angle in a square is 90 degrees and the diagonals bisect each angle.
This means that :
[tex]\begin{gathered} 6x-21=45 \\ \text{Collect like terms:} \\ 6x=45+21 \\ 6x=66 \\ \text{Divide through by 6:} \\ x=\frac{66}{6} \\ x=11 \end{gathered}[/tex]That is the value of x.
Solve this system of linear equations. Separatethe x- and y-values with a comma.18x - 10y = 749x - 9y = 45
Given,
[tex]\begin{gathered} \text{The system of pair of linear equation is,} \\ 18x-10y=74\ldots\ldots\ldots\ldots\ldots.\ldots.(i) \\ 9x-9y=45\ldots\ldots\ldots..\ldots\ldots\ldots.(ii) \end{gathered}[/tex]Multiplying equation (ii) by 2 as it make the coefficent of x in both equation equal.
[tex]\begin{gathered} 18x-10y=74\ldots\ldots\ldots\ldots\ldots.\ldots.(i) \\ 18x-18y=90\ldots\ldots\ldots..\ldots\ldots\ldots.(iii) \\ \end{gathered}[/tex]Substracting equation (i) from equation (iii) then we get,
[tex]\begin{gathered} 18x-18y-(18x-10y)=90-74 \\ 18x-18y-18x+10y=16 \\ -8y=16 \\ y=-2 \end{gathered}[/tex]The value of y is -2.
Substituting the value of y in equation (i) then,
[tex]\begin{gathered} 18x-10y=74 \\ 18x+20=74 \\ 18x=54 \\ x=3 \end{gathered}[/tex]Hence, the solution of the linear pair (x, y) is (3, -2).
What is the equation of the line that is parallel to the graph of y = 2x - 5 and passes through the point (8, 10)?
We know that the equation of a line is given by
[tex]y-y_1=m(x-x_1)[/tex]To find it we need the slope m and a point that the line passes thorugh. In this case we have the point (8,10) but we don't know the slope. What we know is that the line we are looking for is parallel to the line
[tex]y=2x-5[/tex]We also know that for two lines to be parallel they have the same slope. Then, if we fin the slope of the line y=2x-5, we have the slope of the line we are looking for. To find the slope of the line y=2x-5 we note that it is written in the slope-intercept form
[tex]y=mx+b[/tex]From this we know that the slope is multiplying the x variable when it is written in that form. Hence m=2.
Then the line we are looking for has an slope of 2 and passes through the point (8,10). Pluggin the values in the equation of a line we have.
[tex]y-10=2(x-8)[/tex]Writting it in the slope intercept form we have
[tex]\begin{gathered} y-10=2(x-8) \\ y-10=2x-16 \\ y=2x-16+10 \\ y=2x-6 \end{gathered}[/tex]Then the line parallel to y=2x-5 and passes through the point (8,10) is
[tex]y=2x-6[/tex]the equation 5x+7=4x+8+x-1 is true for all real numbers substitute a few real numbers for x to see that this is so and then try solving the equation
The equation 5x+7 = 4x+8+x-1 is true for all real numbers.
Solution for the equation is 5x + 7 = 5x + 7.
Given,
The equation; 5x+7 = 4x+8+x-1
We have to find the solution for this equation.
Here,
5x + 7 = 4x + 8 + x - 1 = 5x + 7
The equation is true for all real numbers;
Lets check;
x = 65 x 6+7 = 4 x 6 + 8 + 6 - 1
30 + 7 = 24 + 13
37 = 37
x = 155 x 15 + 7 = 4 x 15 + 8 + 15 - 1
75 + 7 = 60 + 22
82 = 82
That is,
The equation 5x + 7 = 4x + 8 + x - 1 is true for all real numbers.
The solution for the equation is 5x + 7 = 5x + 7.
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To prepare for disinfection of hard nonporous surfaces against canine parvovirus, mix a solution of bleach in 2.5 gallons of water at the rate of ¾ cup of bleach per 1 gallon of water. What is the volume of bleach added to the 2.5 gallons of water? a. 30 fl. oz b.15 fl. oz c.1 ¾ cups d.1 ½ cups and 2 tbsp
Answer:
b. 15 fl. oz
Explanation:
From the question, we are told that 3/4 cup of bleach is needed per 1 gallon of water.
Thus:
[tex]\begin{gathered} 1\text{ gallon of water requires }\frac{3}{4}\text{ cup of bleach} \\ \implies2.5\text{ gallons will require }\frac{3}{4}\times2.5\text{ cups of bleach} \\ \frac{3}{4}\times2.5=1\frac{7}{8}\text{ cups} \end{gathered}[/tex]Next, we represent the result in the form of the given options:
Using the standard rate of conversion: 1 cup = 8 fl. oz
[tex]\begin{gathered} 1\text{ cup}=8\text{ fl.oz} \\ \implies1\frac{7}{8}\text{ cups}=8\times1\frac{7}{8}floz=8\times\frac{15}{8}=15fl.oz \end{gathered}[/tex]The volume of bleach added to 2.5 gallons of water is 15 fl. oz.
2x + 4x = 3x + 3x Solve for x.
You have the following expression:
2x +4x = 3x + 3x
in order to solve for x, proceed as follow:
2x +4x = 3x + 3x simplify like terms both sides
6x = 6x
Due to the previous result is the trivial solution, it means that the equation has infinite solutions.
9. The Elite Vacuum Company has determined its cost for making vacuums to beC = 24V + 1000, where C is the cost in dollars and V is the number of vacuums.If the cost must be between $49,000 and $121,000, how many vacuums can they makeper week? (You must set up and solve an inequality.)
We are given the relationship between the cost in dollars (C) and the number of vacuums (V) to be:
[tex]C\text{ = 24V + 1000}[/tex]From the constraint, we have that the cost(C) must be greater than $49000 and less than $121000
Writing this as inequality:
[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000 } \\ 24V\text{ + 1000 }\leq\text{ 121000} \end{gathered}[/tex]Solving the linear inequalities for V:
[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000} \\ 24V\text{ }\ge\text{ 49000 - 1000} \\ 24V\text{ }\ge\text{ 48000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\ge\text{ }\frac{48000}{24} \\ V\text{ }\ge\text{ 2000} \end{gathered}[/tex]Similarly for the second inequality:
[tex]\begin{gathered} 24V\text{ + 1000 }\leq\text{ 121000} \\ 24V\text{ }\leq121000\text{ - 1000} \\ 24V\text{ }\leq\text{ 120000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\leq\text{ }\frac{120000}{24} \\ V\text{ }\leq5000 \end{gathered}[/tex]Hence, the number of vacuums they can make per week can be between 2000 and 5000 or in inequality:
[tex]2000\text{ }\leq\text{ V }\leq\text{ 5000}[/tex]Answer:
Between 2000 and 5000 vacuums
Find functions f and g such that (f o g)(x) = [tex] \sqrt{2x} + 19[/tex]
We have the expression:
[tex](fog)(x)=\sqrt[]{2x}+19[/tex]So:
[tex]g(x)=2x[/tex][tex]f(x)=\sqrt[]{x}+19[/tex]***
Since we want to get the function g composed in the function f, and the result of this is:
[tex](fog)(x)=\sqrt[]{2x}+19[/tex]When we replace g in f, we have to get as answer the previous expression. And by looking at it the only place where we will be able to replace values is where the variable x is located. The function f will have the "skeleton" or shape of the overall function and g will be injected in it.
From this, we can have that f might be x + 19 and g might be sqrt(2x), but the only options that are given such that when we replace g in x of f, are f = sqrt(x) + 19 and g = 2x.
the ratio of red candies to Blue candies is 5:4 in the bag if there are 20 blue candies in the bag how many rare candies are there
The ratio of Red candies to Blue candies is 5:4 in the bag.
Ben has a collection of 15 coins and quarters and dimes there's seven quarters in the collection. describe ratio that compares the coins that compare the whole coin collection part of it then write the ratio and at least two different ways
Since the collection contains quarters and dimes, we are going to compare the whole collection to the quarters (7),
We can represent a ratio, like:
15:7 or 15/7
On its website a tv station displays temperature data for each hour during the past 24 hours. The data are displayed as using two different functions on a line graph. One function shows the current temperature and the other function shows the historical average. Which quantities are represented by the y-values on the line graph
, Given the question, we are asked to find which of the quantities are represented by the y-values on the line graph .
Explanation
In the question, we are told that the tv station displays temperature data using two different functions on a line graph. One of the functions shows the current temperature and the other function shows the historical average.
A function, by definition, can only have one output value(y) for any input value. In this case the input values are the time the temperature which we result in the output value of the historical average and temperature.
Therefore,
Answer
Option D
The half-life of radium is 1690 years. If 70 grams are present now, how much will be present in 570 years?
Solution
Given that
Half life is 1690 years.
Let A(t) = amount remaining in t years
[tex]\begin{gathered} A(t)=A_0e^{kt} \\ \\ \text{ where }A_{0\text{ }}\text{ is the initial amount} \\ \\ k\text{ is a constant to be determined.} \\ \end{gathered}[/tex]SInce A(1690) = (1/2)A0 and A0 = 70
[tex]\begin{gathered} \Rightarrow35=70e^{1690k} \\ \\ \Rightarrow\frac{1}{2}=e^{1690k} \\ \\ \Rightarrow\ln(\frac{1}{2})=1690k \\ \\ \Rightarrow k=\frac{\ln(\frac{1}{2})}{1690} \\ \\ \Rightarrow k=-0.0004 \end{gathered}[/tex]So,
[tex]A(t)=70e^{-0.0004t}[/tex][tex]\Rightarrow A(570)=70e^{-0.0004(570)}\approx55.407\text{ g}[/tex]Therefore, the answer is 55.407 g
11. Suppose that y varies inversely with x. Write a function that models the inverse function.x = 1 when y = 12- 12xOy-y = 12x
We need to remember that when two variables are in an inverse relationship, we have that, for example:
[tex]y=\frac{1}{x}[/tex]In this case, we have an inverse relationship, and we have that when x = 1, y = 12.
Therefore, we have that the correct relationship is:
[tex]y=\frac{12}{x}[/tex]In this relationship, if we have that x = 1, then, we have that y = 12:
[tex]x=1\Rightarrow y=\frac{12}{1}\Rightarrow y=12[/tex]Therefore, the correct option is the second option: y = 12/x.
Convert 7 liters into gallons using measurement conversion 1 liter= 1.0567 quarts. Round to two decimals
Convert 7 liters into gallons
We have the measurement conversion 1 liter= 1.0567 quarts
and the gallons = 4 quarts
So, 7 liters = 7 * 1.0567 quarts = 7.3969 quarts
We will convert from the quarts to gallons as follows:
1 gallons = 4 quarts
x gallons = 7.3969 quarts
so, the value of x will be:
[tex]x=\frac{7.3969}{4}=1.849225[/tex]Round to two decimals
so, the answer will be 1.85 gallons
Give a number in scientific notation that isbetween the two numbers on a number line.71 X 103 and 71,000,000
For this problem we have the following two numbers
[tex]71x10^3[/tex][tex]71000000[/tex]Let's convert the two numbers with scientific notation
[tex]71x10^3=71000=7.1x10^4[/tex][tex]71000000=7.1x10^7[/tex]Now we just need to find a number between the two given we know that:
[tex]7.1x10^4<7.1x10^7[/tex]The final answer for this case would be any number between these two numbers and it could be:
[tex]7.1x10^6[/tex]also it could be:
[tex]9.5x10^5[/tex]Or any number between the two given
Answer:
The answer is B,D, And F
Step-by-step explanation:
7.1 × 103 = 7,100
7.1 × 105 = 710,000
Because 7,100 < 710,000 < 71,000,000 then 7.1 × 105 falls between 7.1 × 103 and 71,000,000
Chloe deposits $2,000 in a money market account. The bank offers a simple interest rate of 1.2%. How much internet she earn in 10 years?
Given data:
deposits = $2,000
simple interest rate =1.2%
time =10 years
The formula to find the amount is,
[tex]A=\frac{\text{p}\cdot\text{n}\cdot\text{r}}{100}[/tex][tex]\begin{gathered} A=\frac{2000\cdot10\cdot1.2}{100} \\ A=\frac{24000}{100} \\ A=\text{ 240} \end{gathered}[/tex]The intrest she earn in 10 years is $240.A coordinate grid is shown from negative 6 to 6 on both axes at increments of 1. Figure ABCD has A at ordered pair negative 4, 4, B at negative 2, 2, C at negative 2, negative 1, D at negative 4, 1. Figure A prime B prime C prime D prime has A prime at ordered pair 4, 0, B prime at 2, negative 2, C prime at 2, negative 5, D prime at 4, negative 3.
Part B: Are the two figures congruent? Explain your answer.
The two figures ABCD and A'B'C'D' are congruent .
In the question ,
it is given that the coordinates of the figure ABCD are
A(-4,4) , B(-2,2) , C(-2,-1) , D(-4,1) .
Two transformation have been applied on the figure ABCD ,
First transformation is reflection on the y axis .
On reflecting the points A(-4,4) , B(-2,2) , C(-2,-1) , D(-4,1) on the y axis we get the coordinates of the reflected image as
(4,4) , (2,2) , (2,-1) , (4,1) .
Second transformation is that after the reflection the points are translated 4 units down .
On translating the points (4,4) , (2,2) , (2,-1) , (4,1) , 4 units down ,
we get ,
A'(4,0) , B'(2,-2) , C'(2,-5) , D'(4,-3).
So , only two transformation is applied on the figure ABCD ,
Therefore , The two figures ABCD and A'B'C'D' are congruent .
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There are 11 oranges, 7 apples, 9 bananas and 13 peaches in the fruit bowl. If you pick a fruit at random, what is the probability you will pick an apple or banana? (give answer as a percentage rounded to the nearest tenth) Plapple or banana)=[answer]
we get that:
[tex]\frac{7+9}{11+7+9+13}=\frac{16}{40}=\frac{2}{5}=0.4\rightarrow40\text{ \%}[/tex](6 x 10^-2)(1.5 x 10^-3 + 2.5 x 10^-3)1.5 x 10^3
Given the expression:
[tex]\left(6*10^{-2}\right)\left(1.5*10^{-3}+2.5*10^{-3}\right)1.5*10^3[/tex]Let's simplify the expression.
To simplify the expression, we have:T
[tex]\begin{gathered} (6*10^{-2})(1.5*10^{-3}+2.5*10^{-3})1.5*10^3 \\ \\ =(6*10^{-2})(4.0*10^{-3})1.5*10^3 \\ \\ =(6*4.0*10^{-2-3})1.5*10^3 \\ \\ =(24.0*10^{-5})1.5*10^3 \end{gathered}[/tex]Solving further:
Apply the multiplication rule for exponents.
[tex]\begin{gathered} 24.0*1.5*10^{-5+3} \\ \\ =36*10^{-2} \\ \\ =0.36 \end{gathered}[/tex]ANSWER:
[tex]0.36[/tex]A recent survey asked respondents how many hours they spent per week on the internet. Of the 15 respondents making$2,000,000 or more annually, the responses were: 0,0,0,0,0, 2, 3, 3, 4, 5, 6, 7, 10, 40 and 70. Find a point estimate of thepopulation mean number of hours spent on the internet for those making $2,000,000 or more.
Given
The total frequency is 15 respondents
The responses were: 0,0,0,0,0, 2, 3, 3, 4, 5, 6, 7, 10, 40 and 70
Solution
The population mean is the sum of all the values divided by the total frequency .
[tex]undefined[/tex]find the volume of a right circular cone that has a height of 4.3m and a base with a circumference of 17.6. round your answer to the nearest tenth
Answer:
Explanation:
The volume of a right circular cone can be found using the below formula;
[tex]V=\pi\times r^2\times\frac{h}{3}[/tex]where V = volume of the cone
r = radius of the base
h = height of the cone ne
Find F as a function of x and evaluate it at x = 2, x = 5 and x = 8.
Given:
[tex]F(x)=\int_2^x(t^3+6t-4)dt[/tex]Find-:
[tex]F(x),F(2),F(5),F(8)[/tex]Sol:
[tex]\begin{gathered} F(x)=\int_2^x(t^3+6t-4)dt \\ \\ \end{gathered}[/tex]Use integration then:
[tex]\begin{gathered} F(x)=\int_2^x(t^3+6t-4)dt \\ \\ F(x)=[\frac{t^4}{4}+\frac{6t^2}{2}-4t]_2^x^ \\ \\ \\ F(x)=\frac{x^4}{4}+3x^2-4x-\frac{2^4}{4}-3(2)^2+4(2) \\ \\ F(x)=\frac{x}{4}^4+3x^2-4x-8 \end{gathered}[/tex]The function value at x = 2 is:
[tex]\begin{gathered} F(x)=\frac{x^4}{4}+3x^2-4x-8 \\ \\ F(2)=\frac{2^4}{4}+3(2)^2-4(2)-8 \\ \\ F(2)=4+12-8-8 \\ \\ F(2)=16-16 \\ \\ F(2)=0 \end{gathered}[/tex]The function value at x = 5
[tex]\begin{gathered} F(x)=\frac{x^4}{4}+3x^2-4x-8 \\ \\ F(5)=\frac{5^4}{4}+3(5)^2-4(5)-8 \\ \\ F(5)=156.25+75-20-8 \\ \\ F(5)=203.25 \end{gathered}[/tex]Function value at x = 8
[tex]\begin{gathered} F(x)=\frac{x^4}{4}+3x^2-4x-8 \\ \\ F(8)=\frac{8^4}{4}+3(8)^2-4(8)-8 \\ \\ F(8)=1024+192-32-8 \\ \\ F(8)=1216-40 \\ \\ F(8)=1176 \end{gathered}[/tex]