Solve the system of equations below using any method you learned in this unit. Show all work (even if you are using your calculator).
Answers
Given the system of equations
[tex]\begin{gathered} x+4y-z=20-----1 \\ 3x+2y+z=8-----2 \\ 2x-3y+2z=-16-----3 \end{gathered}[/tex]We can solve for x, y and z below.
Explanation
Step 1: Find the value of z using the substitution method
[tex]\begin{gathered} \begin{bmatrix}x+4y-z=20\\ 3x+2y+z=8\\ 2x-3y+2z=-16\end{bmatrix} \\ Isolate\text{ for x in equation 1} \\ x=20-4y+z \\ \mathrm{Substitute\:}x=20-4y+z\text{ in equation 2 and 3} \\ \begin{bmatrix}3\left(20-4y+z\right)+2y+z=8\\ 2\left(20-4y+z\right)-3y+2z=-16\end{bmatrix} \\ sinplify \\ \begin{bmatrix}-10y+4z+60=8 \\ -11y+4z+40=-16\end{bmatrix} \\ Isolate\text{ for y in}-10y+4z+60=8 \\ -10y=8-4z-60 \\ y=\frac{8-4z-60}{-10} \\ y=\frac{-4z-52}{-10} \\ y=\frac{2\left(z+13\right)}{5} \\ \mathrm{Substitute\:}y=\frac{2\left(z+13\right)}{5}\text{ in }-11y+4z+40=-16 \\ \begin{bmatrix}-11\cdot \frac{2\left(z+13\right)}{5}+4z+40=-16\end{bmatrix} \\ simplify \\ \begin{bmatrix}\frac{-2z-286}{5}+40=-16\end{bmatrix} \\ multiply\text{ through by 5} \\ -2z-286+200=-80 \\ isolate\text{ for z} \\ -2z=-80-200+286 \\ -2z=6 \\ z=\frac{6}{-2} \\ z=-3 \end{gathered}[/tex]Step 2: Find y
[tex]\begin{gathered} \mathrm{Substitute\:}z=-3\text{ in}\mathrm{\:}y=\frac{2\left(z+13\right)}{5} \\ y=\frac{2(-3+13)}{5} \\ y=\frac{2(10)}{5} \\ y=4 \end{gathered}[/tex]Step 3: Find z
[tex]\begin{gathered} \mathrm{Substitute\:}z=-3,\:y=4\text{ in }x=20-4y+z \\ x=20-4\cdot \:4-3 \\ x=1 \end{gathered}[/tex]Answer: The solutions to the system of equations are
[tex]x=1,\:z=-3,\:y=4[/tex]Related Questions
Solve the system of two linear inequalities graphicallySysx-2y) -5x + 10Step 1 of 3: Graph the solution set of the first linear inequalityAnswerKeypadKeyboard ShortcutsThe line will be drawn once all required data is provided and will update whenever a value is updated. The regions will be added once the line is drawn.Enable Zoom/PanChoose the type of boundary line:Solid (-) Dashed (-)Enter two points on the boundary line:10-Select the region you wish to be shaded:Submit Answer
Answers
Given:
[tex]\begin{gathered} y\leq x-2 \\ \\ y>-5x+10 \end{gathered}[/tex]Find-: Solution set of the first linear inequality.
Sol:
Graph of first inequality is:
Graph of inequality of:
[tex]y>-5x+10[/tex]Graph of the given inequality is:
The solution of inequality is:
[tex]\begin{gathered} x=2 \\ y=0 \end{gathered}[/tex]Multiply.(2x + 4)(2x - 4)A. 4x2 + 16x- 16B. 4x2 - 16C. 4x2 - 16x - 16D. 4x2 + 16
Answers
We have to multiply the expression (2x + 4)(2x - 4):
[tex]\begin{gathered} \left(2x+4\right)\left(2x-4\right) \\ 2x\cdot2x+2x\cdot(-4)+4\cdot2x+4\cdot(-4) \\ 4x^2-8x+8x-16 \\ 4x^2+(8-8)x-16 \\ 4x^2-16 \end{gathered}[/tex]The answer is:
B. 4x^2 - 16
Please help me and tell me the process I have a test in an hour.Value of x.
Answers
Vertical angles are congruent.
From the figure, angle 3 and angle (7x + 3) are vertical angles, therefore angle 3 is (7x + 3)
Angle 1 and 127 degrees are supplementary angles and have a sum of 180 degrees.
That will be :
[tex]\begin{gathered} \angle1+127=180 \\ \angle1=180-127 \\ \angle1=53 \end{gathered}[/tex]Angle 2 and 133 degrees are also supplementary angles and have a sum of 180 degrees.
That will be :
[tex]\begin{gathered} \angle2+133=180 \\ \angle2=180-133 \\ \angle2=47 \end{gathered}[/tex]Now we have angles 1, 2 and 3 which are angles in a triangle, and the sum of interior angles in a triangle is 180 degrees.
[tex]\begin{gathered} \angle1+\angle2+\angle3=180 \\ 53+47+(7x+3)=180 \\ \text{Solve for x :} \\ 100+7x+3=180 \\ 7x+103=180 \\ 7x=180-103 \\ 7x=77 \\ x=\frac{77}{7} \\ x=11 \end{gathered}[/tex]ANSWER :
x = 11
Jan draws a card from the set below, replaces it and then draws another card. Which of the following tree diagrams correctly shows the sample space?
Answers
Given the word problem, we can deduce the following information:
1. Jan draws a card from the set below, replaces it and then draws another card.
Based on the given information, there is a replacement happening. It means that Jan put a card back in the set before selecting another card. So the tree diagram that shows all the possible outcomes is Diagram A.
Therefore, the answer is A.
Hello Professor i was confused in this question, will appreciate if u could help me with it!
Answers
The hypotenuse is 20 V 3
Explanation:Given that longer leg = 30
Hypotenuse is given as:
[tex]\begin{gathered} 2\times\frac{30}{\sqrt[]{3}} \\ \\ =\frac{60}{3}\sqrt[]{3} \\ \\ =20\sqrt[]{3} \end{gathered}[/tex]It takes a hose 3 minutes to fill a rectangular aquarium 8 inches long, 10 inches wide, and 14 inchestall. How long will it take the same hose to fill an aquarium measuring 23 inches by 25 inches by 26inches?minutesEnter an integer or decimal number [more..]Round your answer to the nearest minuteSubmit
Answers
Answer:
[tex]40\text{ minutes}[/tex]Explanation:
Firstly, we have to calculate the rate at which the hose works
We can get that by dividing the volume of the first aquarium by the time taken to fill it
The volume of the first aquarium can be calculated using the formula:
[tex]V\text{ = L}\times B\times H[/tex]Where:
L is the length of the aquarium
B is its width
H is its height
The volume of the first aquarium is thus:
[tex]V\text{ = 8}\times10\times14\text{ = 1120 in}^3[/tex]We have the filling rate as:
[tex]\frac{1120}{3}\text{ in}^3\text{ per minute}[/tex]Now, let us get the volume of the second aquarium
We use the same formula as the first
We have the volume as:
[tex]23\times25\times26\text{ = 14,950 in}^3[/tex]Now, to get the time taken, we divide the volume of the second aquarium by the rate of the first
Mathematically, we have that as:
[tex]14950\text{ }\times\frac{3}{1120}\text{ = 40 minutes approximately}[/tex]Describe the difference on table, graph and equation between discrete and continuous functions.
Answers
REmember that
A continuous function allows the x-values to be ANY points in the interval, including fractions, decimals, and irrational values
A discrete function allows the x-values to be only certain points in the interval, usually only integers or whole numbers.
Discrete functions have scatter plots as graphs and continuous functions have lines or curves as graphs
Write an equation that represents a reflection in the y-axis of the graph of g(x)=|x|.
h(x)= ?
Answers
the reflection of the function g(x)=|x| in the y-axis will be h(x) = |x|
What is reflection in coordinate geometry ?
this represents the flip or mirror image of transformation about the given axis.
For every point in the plane (x, y), a 90° rotation can be described by the transformation P(x, y) → P'(-y, x). We can achieve this same transformation by performing two reflections.
Here, the given function is :
g(x)=|x|
Now, the reflection in the y-axis will be same that is :
h(x)= g(x)
h(x) = |x|
Therefore, the reflection of the function g(x)=|x| in the y-axis will be h(x) = |x|
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PLEASE HELP!!
Ninas math class is 6 and 4/5 meters long and 1 and 3/8 meters wide. What is the area of the classroom?
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Answer: 374/40 or 9.35 or 9 and 7/20
Step-by-step explanation: see photo for explanation
A whole pizza is cut into twelfths. If Dexter eats 1/2 of the pizza and Landry eats 1/3 of the pizza, then 3 what fraction of the pizza remains?
Answers
Explanation
Step 1
Let
A whole pizza = 1 pizza
Dexter eats 1/2
Landry eats 1/3
x= fraction of the pizza remains
Step 2
the r
Dunoga cycled 15.26 kilometres and then ran 740 metres. What was the total distance he covered in kilometres?
Answers
Answer:16 Kilometers
Step-by-step explanation:15.26km+.74km
Dunoga covered a distance of 16 km in total.
What is unit conversion?A unit conversion expresses the same property as a different unit of measurement.
For instance, time can be expressed in minutes instead of hours, while distance can be converted from miles to kilometers, or feet, or any other measure of length.
Given that, Dunoga cycled 15.26 kilometers and then ran 740 meters. We need to find the distance he covered in kilometers,
To find the total distance, we will add the distance he covered by cycle and by running,
But the units of both the distances are not same and to add we need to convert the units,
Since, the answer required in kilometers, so we will convert meter into kilometers,
1 km = 1000 m
Therefore,
740 m = 740 / 1000 = 0.74 km
Therefore, the distance he covered in kilometers = 0.74+15.26
= 16 km
Hence, Dunoga covered a distance of 16 km in total.
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Write the slope-intercept form of the equation of the line with the given characteristics. Perpendicular to y = -5x + 2 and passing through (3,-1).
Answers
The slope intercept form of a line can be expressed as,
[tex]y=mx+c[/tex]Here, m is the slope of the line and c is the y intercept.
Comparing the above equation with the given equation of a line y=-5x+2, we get
m=-5.
The slope of a line perpendicular to line with slope m is -1/m.
Hence, the slope of line perpendicular to y=-5x+2 is,
[tex]m_1=\frac{-1}{m}=\frac{-1}{-5}=\frac{1}{5}[/tex]The new line is given to be passing through point with coordinates (x1, y1)=(3, -1).
The point slope form of a line passing through point with coordinates (x1, y1)=(3, -1) and having slope m1 is,
[tex]\begin{gathered} y-y_1=m_1(x-x_1) \\ y-(-1)=\frac{1}{5}(x-3) \\ y+1=\frac{1}{5}x-\frac{3}{5} \\ y=\frac{1}{5}x-\frac{3}{5}-1 \\ y=\frac{1}{5}x-\frac{3-5}{5} \\ y=\frac{1}{5}x-\frac{8}{5} \end{gathered}[/tex]Therefore, the slope-intercept form of the equation of the line perpendicular to y = -5x + 2 and passing through (3,-1) is,
[tex]y=\frac{1}{5}x-\frac{8}{5}[/tex]6+|2x-11|=-37
Solve for x
Answers
Answer:
X=16 and X=21
Step-by-step explanation:
6 + 2x-11 = -37
-6 -6 2x-11 =-43
+11 +11 2x =32
x=16
6+ 2x- 11 = 37
2x-11=31
+11 +11 2x=42
x =21
A) equation in center radius form B) equation in general form
Answers
The equation of a circle in center-radius form, is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]-Where the coordinates of the center of the circle are (h,k) and the radius of the circle is r.
From the given graph, we can see that the coordinates of the center are (-2,4) and the radius of the circle is 2.
a)
To determine the equation of the circle in center-radius form, replace h=-2, k=4 and r=2
[tex]\begin{gathered} \Rightarrow(x-(-2))^2+(y-(4))^2=2^2 \\ \Rightarrow(x+2)^2+(y-4)^2=4 \end{gathered}[/tex]Therefore, the equation of the circle in center-radius form is:
[tex](x+2)^2+(y-4)^2=4[/tex]b)
To find the equation of the circle in general form, expand the parentheses and take all the terms to the left member:
[tex]\begin{gathered} (x+2)^2+(y-4)^2=4 \\ \Rightarrow x^2+2(2)(x)+(2)^2+y^2-2(4)(y)+4^2=4 \\ \Rightarrow x^2+4x+4+y^2-8y+16=4 \\ \Rightarrow x^2+4x+y^2-8y+20=4 \\ \Rightarrow x^2+4x+y^2-8y+20-4=0 \\ \Rightarrow x^2+4x+y^2-8y+16=0 \end{gathered}[/tex]Write the quadratic terms first:
[tex]\Rightarrow x^2+y^2+4x-8y+16=0[/tex]Therefore, the equation of the circle in general form, is:
[tex]x^2+y^2+4x-8y+16=0[/tex]If f (x) = 3x2 - 2x + 1, select all of the following that are TRUE?f(-1) = 6f(1) = 0f (2) = 9f(0) = 1Previous
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The function is:
[tex]f(x)=3x^2-2x+1[/tex]to check witch is true we have to evaluate the function in -1, 1, 1 and 0 so:
for
Write an equation of the line with the given slope and y-intercept.
Slope
1
6
, y−intercept (0, −2)
Answers
The equation of line is [tex]6y=6x$-$12[/tex].
The given slope is [tex]\frac{1}{6}[/tex].
The [tex]y $-$[/tex]intercept is [tex](0, $-$2)[/tex].
We have to write the equation of line using the given slope and [tex]y $-$[/tex]intercept.
The equation of line with the slope m and [tex]y $-$[/tex]intercept of [tex](0,a)[/tex] is [tex]y=mx+a[/tex].
From the question,
The value of [tex]m=\frac{1}{6}[/tex]
The value of [tex]a= $-$2[/tex]
Now putting the value of [tex]m[/tex] and [tex]a[/tex] in the equation of line.
[tex]y=\frac{1}{6}x+( $-$2)\\y=\frac{1}{6}x$-$2[/tex]
Multiply by [tex]6[/tex] on both side
[tex]y\times6=6\times(\frac{1}{6}x$-$2)\\6y=6\times\frac{1}{6}x$-$6\times2\\6y=6x$-$12[/tex]
The equation of line is [tex]6y=6x$-$12[/tex].
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Hello. I think I have this one correct but I'm not 100% sure. Would you mind helping me work this through?
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1) To better set the measurements in that picture, we need to consider that parallel line segments in this picture have the same measurements.
2) Based on that, we can look at that picture this way:
And set the following equation, given that Perimeter is the sum of all lengths of a polygon:
[tex]\begin{gathered} P=2+2+1+2+3+3+1+1+1+1+4+3 \\ P=24\:cm \end{gathered}[/tex]If mZABD = 70°, what are mZABC and mZDBC?
mZABC=
mZDBC=
(6x+3) D
B
(9x-8)
Please help me
Answers
Answer:
Step-by-step explanation:
ABD = ABC + DBC
Eqivalent to:
78 = (5x + 3) + (5x - 5)
78 = 5x + 5x + 3 - 5
78 = 10x - 2
80 = 10x (move -2 to the left side and get 78 + 2 = 80)
8 = x (80/10 = 8)
With x = 8,
ABC = 5x - 5 = 8*5 - 5 = 40 - 5 = 35
DBC = 5x +3 = 8*5 + 3 = 40 + 3 = 43
A middle schooler is H inches tall at the beginning of the school year is the height of the middle school at the end of the year can be represented by the expression H + 0.02h, which statement is true?
Answers
Answer:
A
Step-by-step explanation:
h + 0.02h = (1+0.02)h = 1.02h
1.02h * 100% = 102%
102 - 100 = 2%
Please help me. Will mark most brainliest.
Matthew's Maths mark increased by a factor of 3/2 this term. His new mark is 75%. Use an equation to calculate Matthew's mark last term.
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We need to know about scale factor to solve the problem. Matthew's mark last term was 50%.
It is given that Matthew's marks increased by a factor of 3/2 this term. This means that whatever marks Matthew had received in his previous term, it was increased by 3/2 this term. If we consider his original marks to be x, then we can get the increased marks by multiplying x by 3/2. We know that the new marks is 75%, we need to find the value of x.
3x/2=75
x=75x2/3=25x2=50
Therefore the marks Matthew received in the previous term is 50%.
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What is the current population of elk at the park?
Answers
Given the following function:
[tex]\text{ f\lparen x\rparen= 1200\lparen0.8\rparen}^{\text{x}}[/tex]1200 represents the initial/current population of elk in the national park.
Therefore, the answer is CHOICE A.
It's a gross thought, but the number (N) of bacteria in refrigerated food is given by latex- 1≤T≤20 where T is the temperature of the food in degrees Celsius. When you take the food out of the refrigerator, the temperature of the food is given by T(t)=3t+2, 0≤t≤6 where t is the time in hours. Find the composition N(T(t)) and interpret what it means in this context.
Answers
Given that the concentration of bacteria in the refrigerated food is
[tex]10T^2-20T-6----\mleft\lbrace1\mright\rbrace[/tex]and the temperature of the food is given by
[tex]T(t)=3t+2-----\mleft\lbrace2\mright\rbrace[/tex]Therefore, N(T(t) is given by
[tex]N\mleft(T(t)\mright)=10(3t+2)^2-20(3t+2)^{}-6[/tex]Then,
[tex]\begin{gathered} N(T(t))=10(3t+2)^2-20(3t+2)^{}-6 \\ =10(9t^2+6t+6t+4)-60t-40-6 \\ =10(9t^2+12t+4)-60t-46 \\ =90t^2+120t+40-60t-46 \\ =90t^2+60t-6 \end{gathered}[/tex]Answer: The composition is
[tex]N(T(t))=90t^2+60t-6[/tex]It can be interpreted as the concentration of bacteria in the food when outside of the refrigerator with time.
can u help me w this i got it incorrect and can’t figure out why
Answers
1) We can see here a case in which there are two secant lines coming from a single point over that circle.
2) So, we can write out the following relation
[tex]\begin{gathered} PA\cdot PB=PC\cdot PD \\ 4(4+x)=5(5+7) \\ 16+4x=25+35 \\ 16+4x=60 \\ 16-16+4x=60-16 \\ 4x=44 \\ \frac{4x}{4}=\frac{44}{4} \\ x=11 \end{gathered}[/tex]Find a polynomial f (x) of degree 3 that has the following zeros.6 (multiplicity 2), -7Leave your answer in factored form.
Answers
If a polynomial has a zero of "a" with multilicity b, the factor would be:
[tex](x-a)^b[/tex]So, accordingly the factors would be:
[tex]\begin{gathered} (x-6)^2 \\ (x-(-7))^1 \end{gathered}[/tex]They are
[tex]\begin{gathered} (x-6)^2 \\ (x+7) \end{gathered}[/tex]We can write out the polynomial, f(x), as:
[tex]f(x)=(x-6)^2(x+7)[/tex]8.
What is the measure of angle x in the figure?
40°
A 69°
B 71°
C 109°
D 111°
Answers
Answer:
C 109
Step-by-step explanation:
First add all the known angles inside the triangle first to get 109°
Then since all angles in a triangle add to 180°
you take away 109 from 180 so
180-109 which equals 71
Then since all angles on a straight line add up to 180°
you take 71 from 180 so
180-71 = 109
so x = 109°
simplify 425xy⁴/25xy²
Answers
We have the expression
[tex]\frac{425xy^4}{25xy^2}[/tex]We can already simplify x because it's both on the numerator and denominator
[tex]\frac{425y^4}{25y^2}[/tex]Now we can simplify 425/25 = 17
[tex]\frac{17y^4}{y^2}[/tex]Remember that
[tex]\frac{a^n}{a^m}=a^{n-m}[/tex]Then
[tex]17y^{4-2}=17y^2[/tex]The final result is
[tex]17y^2[/tex]how to find the width to a pyramid with the volume height and length
Answers
The volume of a pyramid is given by the formula
[tex]V_{\text{pyramid}}=\frac{1}{3}\times base\text{ area}\times height[/tex]Write out the given dimensions
[tex]\begin{gathered} \text{Volume}=80\operatorname{cm}^3 \\ \text{Height}=10\operatorname{cm} \\ \text{length}=6\operatorname{cm} \\ \text{width}=\text{unknown} \end{gathered}[/tex]Since the base of the pyramid is a rectangle, the base area is
[tex]A_{\text{rectangle}}=\text{width }\times length[/tex]Substituting the given dimensions to get the value of the width\
[tex]\begin{gathered} V_{\text{pyramid}}=\frac{1}{3}\times width\times length\times height \\ 80=\frac{1}{3}\times width\times6\operatorname{cm}\times10\operatorname{cm} \end{gathered}[/tex][tex]\begin{gathered} 80\operatorname{cm}=20\times width \\ \text{width}=\frac{80}{20} \\ \text{width}=4\operatorname{cm} \end{gathered}[/tex]Hence, the width of the pyramid is 4cm
Jalisa needs to purchase a cover for her oval-shaped pool. The pool's length and width measurements, as marked by dotted lines, are 30 feet and 13 feet.If Jalisa wants the pool cover to extend one foot from the pool's edge, as shown in the drawing, what will be the area of therectangular pool cover?A. 390 square feetOB. 434 square feetOC 480 square feetD. 86 square feet
Answers
She wants to cover the pool with a rectangular pool cover that extends one foot from the pool edges in every direction.
The length of the pool is 30ft and the width is 13ft, if the pool cover must extend 1ft over the pool's edge, then you have to add 2ft to the length and 2ft to the width, as shown below:
So, the length of the pool cover will be equal to the length of the pool plus two feet:
[tex]length=30ft+2ft=32ft[/tex]And the width of the pool cover will be equal to the width of the pool plus two feet:
[tex]width=13ft+2ft=15ft[/tex]Once you determined the width and length of the rectangular pool cover, you can calculate its area:
[tex]\begin{gathered} A=wl \\ A=15*32 \\ A=480ft^2 \end{gathered}[/tex]The area of the rectangular pool cover is 480 square feet (option C)
I I need help solving problem number 8 please :)
Answers
Answer:
(8, -1)
Explanation:
Given the below system of equations;
[tex]\begin{gathered} y^2+x^2=65\ldots\ldots\ldots\text{.Equation 1} \\ y+x=7\ldots\ldots\ldots\ldots\text{.Equation 2} \end{gathered}[/tex]Let's go ahead and test each of the given solutions and see which of them is the correct one;
For (8, -1), we have x = 8 and y = -1;
Substituting the above values in Equation 1, we have;
[tex]\begin{gathered} (-1)^2+(8)^2=65 \\ 1+64=65 \\ 65=65 \end{gathered}[/tex]Substituting the values into Equation 2;
[tex]\begin{gathered} (-1)+8=7 \\ -1+8=7 \\ 7=7 \end{gathered}[/tex]We can see that (8, -1) is a solution to the given system of equations
2. A car travels a distance of 250 miles, 700 miles and 325 miles at the rate of 50
miles/hour, 35 miles/hour and 13 miles/hour respectively. Find the average speed
of the car in miles/hr.
(A) 50
(B) 42.5
(C) 30
(D) 25.5
(E) 13
Answers
Answer:a
Step-by-step explanation:can i get brainiest
