Answer:
There were 378 students who chose to study French their freshman year. This means that 72% of the total number of students chose to study French their freshman year. Therefore, the total number of students must be 378 / 0.72 = 527.5. This means that there were 148.5 students who chose not to take French their freshman year.
Step-by-step explanation:
Find The measure of the indicated to the nearest angle
The given figure is a right triangle, then we can apply the sine function to find the missing angle, so:
[tex]\sin\theta=\frac{opposite}{hypotenuse}[/tex]The opposite side to the angle measures 17, and the hypotenuse measures 19.
By replacing these values, we can find the angle:
[tex]\begin{gathered} \sin\theta=\frac{17}{19} \\ \\ \theta=\sin^{-1}(\frac{17}{19}) \\ \\ \theta=63.47 \\ \theta\approx64\degree \end{gathered}[/tex]The answer is 64°.
Can someone explain how I would know the difference between a 2:7 ratio and 7:2 ratio when a point partitions the line? Thank you!
Solution
For this case we can do the following:
We can understand 7/2 as the reciprocal of 2/7 and we can create the following diagram
Which function rule would help you find the values in the table?J K2 -124 -246 -368 -48A k=-12jB k=-6jC k=j - 12D k=j - 6
Solution
As seen from the table
For each values of the table
We define the variation from K to J
[tex]\begin{gathered} K\propto J \\ K=cJ\text{ (where c is constant of proportionality)} \end{gathered}[/tex]When J = 2, K = -12
[tex]\begin{gathered} K=cJ \\ -12=c(2) \\ 2c=-12 \\ c=-\frac{12}{2} \\ c=-6 \end{gathered}[/tex]Therefore, the formula connecting them will be
[tex]k=-6j[/tex]Option B
A baker need 2/3 cup of sugar,but he can only find a 1/2 cup measure,so he decides to estimate, Which of the following would result in the correct amount of sugar?A)One Full scoop plus 1/3 of a scoopB)One Full scoop plus 1/2 of a scoop C) Two ScoopsD)3/4 of a scoop
He needs 2/3 cup of sugar . But he can only find 1/2 cup measures.
I need help on thisChange the equation into a equivalent equation written in the Slope-intercept form. x -7y + 5 =0
The slope-intercept form is an equation as follows:
[tex]y=mx+b[/tex]Then, we need to change the original equation in this equivalent:
[tex]-7y=-5-x\Rightarrow-7y=-x-5\Rightarrow7y=x+5[/tex]Dividing the total equation by 7, we have:
[tex]\frac{7}{7}y=\frac{x}{7}+\frac{5}{7}\Rightarrow y=\frac{1}{7}x+\frac{5}{7}[/tex]Therefore, the slope-intercept form is:
[tex]y=\frac{1}{7}x+\frac{5}{7}[/tex]if the probability of drawing an A or B is 9/25, what is the probability of the complementary event?
If an event has a probability of "A", then the complementary event will have a probability of "1 - A".
Given, the probability of an event is 9/25, we can easily find the probability of the complementary event. Shown below:
[tex]\begin{gathered} 1-\frac{9}{25} \\ =\frac{25}{25}-\frac{9}{25} \\ =\frac{16}{25} \end{gathered}[/tex]The correct answer is:
[tex]\frac{16}{25}[/tex]3x - 4y = 65x + 8y = -1
Write an expression for the sequence of operations described below.1)) multiply 7 by 8, then divide f by the resultDo not simplify any part of the expression.Submit
We need to write an expression for the operations:
[tex]\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}[/tex]The first operation (multiplication) can be represented as:
[tex]7\cdot8[/tex]The second operation (the division of f by the previous result) can be represented as:
[tex]f\div(7\cdot8)[/tex]Notice that we need the parenthesis to indicate that the product is the first operation to be done.
Answer:
[tex]f\div(7\cdot8)[/tex]I need to order the numbers least to greatest for the numbers: sq root of 144 234/3 and 68.12
So, the order would be 8.25, 8.832 and 12
Select three equations that could represent a step in solving this system using the substitution method. 4x+y = 6 x = 8 0.00 0:52 9 1x 2 4(8)+y=6 o y = 18
the first step is replacing x=8 on the first equation, so
[tex]4(8)+y=6[/tex]the second step is do the multiplication
[tex]\begin{gathered} 32+y=6 \\ y+32=6 \end{gathered}[/tex]and the last step is place the 32 on the other side substracting
[tex]\begin{gathered} y=6-32 \\ y=-26 \end{gathered}[/tex]. Identify the difference. -2-(-6)
In this case,
This difference is made this way:
-2 - (-6) =
-2 +6 = 4
So there we have this identity. The minus before the parentheses turns the minus into plus sign.
Find the percent markdown. Cost of a pants $36.95, selling price $24.02
Answer:
35%
Explanation:
Given cost of a pant = $36.95 and selling price = $24.02.
Let the markdown percent be y.
To determine the markdown percent, we'll use the below formula;
Sale Price = Original Price x (1 - Markdown% in decimal)
So let's go ahead and substitute the given values into the equation;
[tex]\begin{gathered} 24.02=36.95\ast(1-y) \\ 24.02=36.95-36.95y \\ -12.93=-36.95y \\ y=\frac{-12.93}{-36.95} \\ y=0.35 \\ \therefore y=35percent \end{gathered}[/tex]So the markdown percent is 35%
Solve the following system of linear equations using elimination.
x – y - 3z = 4
2x + 3y – 3z = -2
x + 3y – 2z = -4
By applying the elimination method, the solutions to this system of three linear equations include the following:
x = 2.y = -2.z = 0.How to solve these system of linear equations?In order to determine the solutions to a system of three linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.
Given the following system of linear equations:
x – y - 3z = 4 .........equation 1.
2x + 3y – 3z = -2 .........equation 2.
x + 3y – 2z = -4 .........equation 3.
From equation 1 and equation 3, we would eliminate x as follows:
x – y - 3z = 4
x + 3y – 2z = -4
-4y - z = 8 .........equation 4.
Next, we would pick a different pair of linear equations to eliminate x:
(x – y - 3z = 4) × 2 ⇒ 2x - 2y - 6z = 8
2x - 2y - 6z = 8
2x + 3y - 3z = -2
-5y - 3z = 10 ........equation 5.
From equation 4 and equation 5, we would eliminate z to get the value of y:
(-4y - z = 8) × 3 ⇒ -12y - 3z = 24
-12y - 3z = 24
-5y - 3z = 10
-7y = 14
y = 14/7
y = -2.
For the value of z, we have:
-4y - z = 8
z = -4y - 8
z = -4(-2) - 8
z = 8 - 8
z = 0
For the value of x, we have:
x – y - 3z = 4
x = 4 + y + 3z
x = 4 - 2 + 3(0)
x = 2
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CS 18 and 105 calories in each juice box The rules for two horseback riding packages are shown below. Go Galloping Horseback Rides $6 equipment fee plus S10 per hous hours horseback riding and let yepresent the total cost of the package. Write a system of equations to represent this situation let x represent the number of Lucky Horseshoe Stables $12 equipment fee plus hour 259 Calories What is the solution to the system of equations? What does the solution represent?
8A) Let x represent the number of hours of horseback riding.
Let y represent the total cost of the package
If Lucky horseshoe stables is used for x hours, the equation for the total cost would be
y = 7x + 12
If Go galloping horseshoe rides is used for x hours, the equation for the total cost would be
y = 10x + 6
Thus, the equations are
y = 7x + 12
y = 10x + 6
B) To solve the system of equations, we would substitute the first equation into the second equation. It becomes
7x + 12 = 10x + 6
10x - 7x = 12 - 6
3x = 6
x = 6/3
x = 2
y = 7x + 12 = 7 * 2 + 12
y = 14 + 12
y = 26
The solution of the system of equations is (2, 26)
Given that angle A lies in Quadrant IV and cos(A)= 7/10, evaluate sin(A).
The value of the trigonometric function is; sin(A) =√51/10.
What are trigonometric identities?Trigonometric identities are the functions that include trigonometric functions such as sine, cosine, tangents, secant, and, cot.
We have been given that angle A lies in Quadrant IV and cos(A)= 7/10 then;
cos(A)= 7/10
Hence, base = 7
hypotenuse = 10
Therefore, perpendicular
h² = b² + p²
10² = 7² + p²
100 = 49 + p²
p = √51
Then sin(A = perpedicular/ hypotenuse
sin(A) = √51/10
Hence, the value of the trigonometric function is; sin(A) =√51/10.
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A game fair requires that you draw a queen from a deck of 52 ards to win. The cards are put back into the deck after each draw, and the deck is shuffled. That is the probability that it takes you less than four turns to win?
The probability (P) is winning in less than four turns can be decomposed as the following sum:
The probability of winning in one turn is
[tex]P(\text{Winning in turn 1})=\frac{\#Queens}{\#Cards}=\frac{4}{52}.[/tex]The probability of winning in the second turn is
[tex]\begin{gathered} P(\text{ Winning in the second turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Winning (in turn 2)}), \\ \\ P(\text{ Winning in the second turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the second turn})=\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]The probability of winning in the third turn is
[tex]\begin{gathered} P(\text{ Winning in the third turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Lossing (in turn 2)})\cdot P(\text{ winning (in turn 3)}), \\ \\ P(\text{ Winning in the third turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the third turn})=\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]Adding all together, we get
[tex]\begin{gathered} P(\text{ Winning in less than four turns})=\frac{4}{52}+\frac{48}{52}\cdot\frac{4}{52}+\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}, \\ \\ P(\text{ Winning in less than four turns})=\frac{469}{2197}, \\ \\ P(\text{ Winning in less than four turns})\approx0.2135, \\ \\ P(\text{ Winning in less than four turns})\approx21.35\% \end{gathered}[/tex]AnswerThe probability of winning in less than four turns is (approximately) 21.35%.
Solve for "x":3x - 5 < -14 or 2x - 1 > 7
We are given the following inequalities:
[tex]\begin{gathered} 3x-5<-14,(1)\text{ or} \\ 2x-1>7,(2) \end{gathered}[/tex]First, we will solve for inequality 1. To do that we will add 5 to both sides:
[tex]3x-5+5<-14+5[/tex]Solving the operations:
[tex]3x<-9[/tex]Now we divide both sides by 3:
[tex]\frac{3x}{3}<-\frac{9}{3}[/tex]Solving the operations:
[tex]x<-3[/tex]Now we solve for "x" in inequality (2). To do this we will add 1 to both sides:
[tex]2x-1+1>7+1[/tex]Solving the operations:
[tex]2x>8[/tex]Now we divide both sides by 2:
[tex]\frac{2x}{2}>\frac{8}{2}[/tex]Solving the operations:
[tex]x>4[/tex]Therefore, the solution to the system is:
[tex]x<-3\text{ or x > 4}[/tex]The height of a tree is x feet. If it grows ½ times the original height, choose the correct expression that denotes the situation.
ANSWER
1.5(x)
EXPLANATION
The tree is originally x feet tall. If it grows 1/2 this height it means that now it is 1/2x taller, or we can express this as a decimal, 0.5x. If we add these two heights we'll have the new height of the tree:
[tex]x+0.5x=(1+0.5)x=1.5x[/tex]What was the initial population at time t=0?Find the size of the bacterial population after 4 hours.
Answer;
[tex]\begin{gathered} a)\text{ 195 bacteria} \\ b)\text{ 3,291,055,916 bacteria} \end{gathered}[/tex]Explanation;
a) We want to get the initial population of the bacteria
We start by writing a formula that links the initial bacteria population to a later bacteria population after time t
[tex]A(t)=I(1+r)^t[/tex]where A(t) is the bacteria population at time t
I is the initial bacteria population
r is the rate of increase in population
t is time
Now, let us find r
At t = 10; we know that A(t) = 2I
Thus, we have it that;
[tex]\begin{gathered} 2I=I(1+r)^{10} \\ (1+r)^{10}\text{ = 2} \\ 1+r\text{ = 1.0718} \\ r\text{ = 1.0718-1} \\ r\text{ = 0.0718} \end{gathered}[/tex]Now, let us find I, since we have r. But we have to make use of t= 80 and A(t) = 50,000
Thus, we have;
[tex]\begin{gathered} 50,000=I(1+0.0718)^{80} \\ I\text{ = }\frac{50,000}{(1+0.0718)^{80}} \\ I\text{ = 195} \end{gathered}[/tex]The initial population is 195 bacteria
b) For after 4 hours, we have to convert to minutes
We know that there are 60 minutes in an hour
So, in 4 hours, we have 4 * 60 = 240 minutes
Now, we proceed to use the formula above with I = 195 and t = 240
We have that as;
[tex]\begin{gathered} A(240)=195(1+0.0718)^{240} \\ A(240)\text{ = 3,291,055,916 bacteria} \end{gathered}[/tex]1 What is the volume of a triangular pyramid with thesame base and height dimensions of the prism below?5.5 in.13 in.7 in.
volume of a triangular pyramid = 1/3 * base area (triangle) *height
triange area= 1/2 base * height
triegle area= 1/7 in * 5.5 in = 38.5 in^2
Volume = 1/3 * 38.5 in^2 * 3 in
Volume = 38.5 in^3
___________________
Answer
choice b)
The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?
Answer:
A lot
Step-by-step explanation:
use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.
what is the length of the dominant line in the time graph below? l leave your answer in simplest radical form.
Let's first calculate the lenght of the side of the rectangle.
[tex]l=\sqrt[]{8^2+5^2}=\sqrt[]{64+25}=\sqrt[]{89}[/tex]so we get that the dotted line is:
[tex]d=\sqrt[]{2^2+89}=\sqrt[]{93}[/tex]so the answer is square root of 93
4) Math Club members want to advertise their fundraiser each week in the school paper. They knowthat a front-page ad is more effective than an ad inside the paper. They have a $30 advertisingbudget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertiseat least 20 times. a) Write and graph a system of inequalities to model the number of advertisements the club canpurchase to stay under budget. Be sure to label all parts of your graph.b) State one solution that would work. How much money will remain in the club's budget?
Problem:
Math Club members want to advertise their fundraiser each week in the school paper. They know that a front-page ad is more effective than an ad inside the paper. They have a $30 advertising budget. It cost $2 for each front-page ad and $1 for each inside page ad. The club wants to advertise at least 20 times.
a) Write and graph a system of inequalities to model the number of advertisements the club can purchase to stay under budget. Be sure to label all parts of your graph.
Solution:
Let us denote the number of front-page ads by x, and the number of inside ads by y:
x = number front-page ads
y= number of inside ads
Now, because they have a $30 advertising budget and It cost $2 for each front-page ad and $1 for each inside page ad, the first inequality that we have is:
[tex]2x+\text{ y }\leq30[/tex]If we represent the graph of the equality (line) 2x+y = 30, we have:
On the other hand, because the club wants to advertise at least 20 times, the second inequality that we have is:
[tex]x+y\ge20[/tex]If we represent the graph of the equality (line) x+y = 20, we have:
Now, the intersection point of the above lines, that is 2x+y = 30 and x+y = 20 is found as follows:
we have
y = 30 - 2x
and
y = 20-x
then
30-2x = 20-x
and
30-20 = 2x-x
that is
10 = x
when x = 10 then y = 20-x = 20-10 = 10
without dividing, how can you tell which quotient is smaller, 30:5 or 30:6 ? eXPLAIN
Without dividing, we can tell that 30:6 has smaller quotient between 30:5 and 30:6.
According to the question,
We have the following two expressions:
30:5 and 30:6
Now, we can easily find which expression has a smaller quotient when the dividend is the same. We need to look at the divisor. If the dividend is the same then the quotient will be smaller for the one with the greater divisor.
In this case, 30:6 has a greater divisor than 30:5 (6 is larger than 5). So, it will have smaller quotient.
Now, we can prove this by dividing both the expressions.
30/6 = 5
(So, it has smaller quotient.)
30/5 = 6
Hence, 30:6 has smaller quotient than 30:5.
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Can you help me with #7? X^3-2x^2+3x-6 = 0Please follow prompt b
Given:
The polynomial is given as,
[tex]x^3-2x^2+3x-6=0[/tex]The objective is to factor the polynomial completely.
Explanation:
Consider x = 2 in the given equation.
[tex]\begin{gathered} f(2)=2^3-2(2)^2+3(2)-6 \\ =8-8+6-6 \\ =0 \end{gathered}[/tex]Thus, (x -2) is a factor of the polynomial.
Now, using synthetic division,
Thus, the polynomial equation will be,
[tex]x^2+3=0\text{ . . . . .(1)}[/tex]On factorizing the equation (1),
[tex]\begin{gathered} x^2=-3 \\ x=\pm\sqrt[]{-3} \\ x=\pm i\sqrt[]{3} \\ x=i\sqrt[]{3},-i\sqrt[]{3} \end{gathered}[/tex]Hence, the factors of the polynomial are (x-2), (x+i√3), (x-i√3).
the perimeter of a rectangle is a rational number. the length of a rectangle is 6 units. the width of a rectangle must be a/an rational/irrational (circle one) number.
A rational number
Explanations:The perimeter of a rectangle is given by the formula:
Perimeter = 2(Length + Width)
The Length = 6 units
Perimeter = 2 (6 + Width)
Perimeter = 12 - 2 Width
2 Width = 12 - Perimeter
Width = (12 - Perimeter)/2
Note that a rational number is a number that can be written as a fraction of two integers.
Since the perimeter is said to be a rational number, any rational number substituted into the formula equation for the width above will give a rational number.
The width of the rectangle is therefore a rational number
Angles A and B are supplementary angles. The measure of angle A is
73∘
What is the measure of angle B?
Answer:
17
Step-by-step explanation:
73+b=90
b=90-73
b=17
You go to the pet store with $25. You decide to buy 2 fish for $3.69 each and fish foos for $4.19. Rounded tanks are $11.48 square-shaped tanks are $14.89. Estimate your total cost to find which tank you can can buy. About how much money will you have left?
Answer: you will only have enough money for the rounded tank, after buying everything you will have 9 cents left
Step-by-step explanation: two $3.69 fish, $4.19 fish food. 2x3.69=7.38+4.19=11.57
25-11.57=13.43
13.43+11.48=24.91
25-24.91=0.09
the length of a rectangle is 2 inches more than the width. The area is 24 square inches. Find the dimensions
Given:
length(l) = width(w) + 2
[tex]\text{Area}=24[/tex][tex]l\times w=24[/tex][tex](w+2)w=24[/tex][tex]w^2+2w-24=0[/tex][tex](w+6)(w-4)=0[/tex][tex]w=4\text{ or -6}[/tex]Negative not possible.
[tex]\text{width(w)}=4\text{ inches}[/tex][tex]\text{length(l)}=w+2[/tex][tex]\text{length of the rectangle=4+2}[/tex][tex]\text{length of the rectangle=}6\operatorname{cm}[/tex]All lines that cross the x-axis are vertical lines.A. TrueB. False
Given:
All lines that cross the x-axis are vertical line.
Required:
To find whether the given statement is true or false.
Explanation:
A vertical line is one the goes straight up and down, parallel to the y-axis of the coordinate plane.
The x-intercept is the point at which the graph crosses the x-axis.
Here all lines are not vertical lines.
Therefore the given statement is false.
Final answer:
False.
