The atomic masses of 35Cl (75.53 percent) and 37Cl 17 17 (24.47 percent) are 34.968 amu and 36.956 amu, re- spectively. Calculate the average atomic mass of chlorine. The percentages in parentheses denote the relative abundances.

Answers

Answer 1

Explanation:

the average atomic mass of chlorine= (34.968 x 0.7553) + ( 36.956 x 0.2447) = 35.4545

Ca % = 100x (5 x 40/502 ) = 39.84 % ( where 502 is molar mass of comp)

P% = 3 x 30.97367 x 100/502 = 18.51 %

O % = (100x13x16)/502 = 41.434

H % = 100-39.84-18.51-41.434 = 0.216 %

% Ca = 100 x40/( 116) = 34.483 %

% Si = 100 x28/116 = 24.14 %

% O = 100-34.483-24.14 = 41.38 %


Related Questions

How much
much hydrogen gas evolved
when 1.5 current is passed through water for 1.5 hours?​

Answers

0.042 moles of Hydrogen evolved

Further explanation

Given

I = 1.5 A

t = 1.5 hr = 5400 s

Required

Number of Hydrogen evolved

Solution

Electrolysis of water ⇒ decomposition reaction of water into Oxygen and Hydrogen gas.

Cathode(reduction-negative pole) : 2H₂O(l)+2e⁻ ⇒ H₂(g)+2OH⁻(aq)

Anode(oxidation-positive pole) : 2H₂O(l)⇒O₂(g)+4H⁻(aq)+4e⁻

Total reaction : 2H₂O(l)⇒2H₂(g)+O₂(g)

So at the cathode H₂ gas is produced

Faraday : 1 mole of electrons (e⁻) contains a charge of 96,500 C

[tex]\tt mol~e^-=\dfrac{Q}{96500}[/tex]

Q = i.t

Q = 1.5 x 5400

Q = 8100 C

mol e⁻ = 8100 : 96500 = 0.084

From equation at cathode , mol ratio e⁻ : H₂ = 2 : 1, so mol H₂ = 0.042

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