Answer:
6 m/s
Explanation:
The equation that relates time, distance, and acceleration is:
a = (vf - vi)/t
where a is acceleration (m/s^2), time is time (seconds) and vf and vi are the initial (vi) and final (vf) velocities (m/s).
Average velocity is (vf + vi)/2
We are given that:
vi = 3 m/s
vf = 9 m/s
Average velocity for the wagon is thus:
is (9 + 3)/2 = 6 m/s
the temperature of the earth is determined by the amount of solar radiation received, the amount of solar energy reflected, and the amount of heat retained by the what?
The temperature of the Earth is determined by the amount of solar radiation received, the amount of solar energy reflected, and the amount of heat retained by the atmosphere.
What is temperature?
The physical concept of temperature expresses in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined various reference points as well as thermometric substances. The most popular scales are the Celsius scale, also known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), as well as the Kelvin scale (K), with the latter being primarily used for scientific purposes. One of the International System of Units' seven base units is the Kelvin (SI).
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A race car speeds up from 0 m/s to 40.0 m/s in 4 seconds. What is the vehicle's acceleration?
A. 16 m/s²
B. 10.0 m/s²
C. 4.0 m/s²
D. 8.0 m/s²
Answer: b) 10.0 m/s
Explanation: Acceleration = [tex]\frac{v-u}{t}[/tex]
V-U
T
v= final velocity
u= initial velocity
t= time in secs
Answer:
ur mom go study nerd u for real
a 2 900-kg truck moving at 11.0 m/s strikes a car waiting at a traffic light, hooking bumpers. the two continue to move together at 7.00 m/s. what was the mass of the struck car?
The mass of the car that was stuck is 1657 Kg.
What is the mass of the struck car?We know that we have to use the laws of the conservation of the linear momentum here. It is known that the momentum before collision must be equal to the total momentum that we have after collision.
In this case, we have;
m1u1 + m2u2 = m1v1 + m2v2
m1 = mass of the truck
m2 = mass of the car
u1 and v1 = the initial and final velocities of the truck
u2 and v2 = initial and final velocities of the car
Again we are told that the two continue to move together hence v1 + v2 = v
m1u1 + m2u2 = (m1 + m2) v
(2900 * 11.0) + 0 = (2900 + m2) 7
31900 = 20300 + 7m2
31900 - 20300 = 7m2
m2 = 31900 - 20300 /7
m2 = 1657 Kg
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1. PE = ?
m = 0.6 kg
g= 9.8 m/s²
h = 35 m
WORKS
Answer:
Explanation:
Potential Energy = m * g * h = .6 * 9.8 * 35 = 205.8 J
While in a park, you walk west for 52 m, then you walk 31.1° north of west for 40 m, and finally you walk due north for 25 m. Find the components of your final displacement (in m), from your initial to final point, along the north and west directions.
The components of the final displacement (in m), from the initial to final point, along the north and west directions is given as:
88m west and 50m north
What is displacement?The displacement of an object is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
we will find the components of each vector in x and y:
For Vector 1:
Fx = 52m
Fy = 0m
for Vector 2:
Fx = 40m*cos31.1
Fy = 40m * cos 31.1
For Vector 3:
Fx = 0m
Fy = 25m
we will then find the components of the final displacement acting in x and y:
For west direction:
Rx = 52m + 40m*cos31.1 + 0
Rx = 90m
For north direction:
Ry = 0 + 40m*sin31.1 + 25m
Ry = 12m.
In conclusion, displacement is a vector quantity that refers to how far out of place an object is. Displacement is known to be the object's overall change in position.
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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14. suppose there is a 10 mbps microwave link between a geostationary satellite and its base station on earth. every minute the satellite takes a digital photo and sends it to the base station. assume a propagation speed of 2.4 x 108 m/s and the distance between satellite and station is 3.6 x 107 m. what is the propagation delay of the link?
The propagation delay of the link due to time dilatationis 1.152 x 10¹⁶ s.
We need to know about the time dilatation to solve this problem. Time dilatation represents that time is relative between the moving and static objects. From a static objects point of view, the time should be
t' = t / √(1 - v²/c²)
where t' is the interval time based on the static object, t is the interval time based on the moving object, v is velocity and c is the speed of light (3 x 10⁸ m/s),
From the question above, the given parameters are
v = 2.4 x 10⁸ m/s
D = 3.6 x 10⁷ m
Find the time taken based on moving objects
t = 2D . v
t = 2 . 3.6 x 10⁷ . 2.4 x 10⁸
t = 1.728 x 10¹⁶ s
Find the time interval based on static objects
t' = t / √(1 - v²/c²)
t' = 1.728 x 10¹⁶ / √(1 - (2.4 x 10⁸)²/(3 x 10⁸)²)
t' = 2.88 x 10¹⁶ s
Hence, the delay time is
Δt = t' - t
Δt = 2.88 x 10¹⁶ - 1.728 x 10¹⁶
Δt = 1.152 x 10¹⁶ s
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If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)
Given:
The mass of the system is m' =m/2
The net force acting on it is F' = 2F
To find the acceleration.
Explanation:
The acceleration will be
[tex]\begin{gathered} a^{\prime}=\frac{F^{\prime}}{m^{\prime}} \\ =\frac{2F}{\frac{m}{2}} \\ =\frac{4F}{m} \\ a^{\prime}=4a \end{gathered}[/tex]Thus, the acceleration would be quadrupled(x4).
You are visiting a friend from elementary school who now lives in a small town. One local amusement is the ice-cream parlor, where Stan, the short-order cook, slides his completed ice-cream sundaes down the counter at a constant speed of 2.0 m/s to the servers. (The counter is very well polished for this purpose.) If the servers catch the sundaes 7.0 cm from the edge of the counter, how far do they fall from the edge of the counter to the point at which the servers catch them?
The edge counter is 0.0060 meters or 0.60 cm far as they fall from the edge of the counter to the point at which the servers catch them.
What is Potential energy?Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. When stretched or squeezed, a spring has higher potential energy.
When lifted above the ground, a steel ball has more potential energy than when it is brought to rest on the ground. It is capable of performing more work in the increased position.
From the given data of the question,
x = v/t
t = x/v (1)
y = -1/2gt²
Substitute value of t from (1)
y = -1/2 g(x/v)²
y = -1/2 (9.8)(0.70/2.0)²
y = 0.0060 meters, or,
y = 0.60 cm.
Therefore, it is 0.60 cm far from the edge of the counter.
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what is the loudness and softness of music related to specifically? multiple choice question. beats of two tones that are similar in frequency tone color of the instrument producing the sound frequency of the vibration that produces the sound amplitude of the vibration that produces the sound
The correct answer choice from above among loudness and softness of music in a wave system is connected by means of amplitude of the vibration that produces the sound.
The correct answer choice is option d.
How the loudness and softness of music is linked with amplitude.In general, the amplitude of a wave of a music is related to how soft or loud a music is as this depends largely on that force of vibration in the the musical system. For instance, when you hit the the wooden or iron door of a building, a soft sound is produced. This happens simply because amplitude.
Be that as it may, a wave is referred to as a disturbance which travels through a particular medium, transferring energy from one point to another point.
So therefore, the amplitude of a wave goes a long way to determine the loudness and softness of music.
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suppose you observe a small star orbiting a much larger star. you observe that the small star is orbiting at a distance of 20 au (in terms of the semi-major axis of its orbit), and with an orbital period of 2 years. how massive is the large star? (hint: for this problem you can assume that the small star has a much smaller mass than the large star.)
The mass of the large star based on orbital period is 6912 x 10³⁰ kg.
We need to know about the orbital period to solve this problem. The orbital period depends on the semi-major axis, gravitational constant, and the mass of the massive object. It can be written as
T² = 4π².a³ / GM
where T is the orbital period, a is the semi-major axis, G is the gravitational constant and M is the mass.
From the question above, the given parameters are
a = 24 au = 24 . ³√(G.Msun yr²/ 4π²)
T = 2 years
Msun = 2 x 10³⁰ kg
By substituting the given parameters, we get
T² = 4π².a³ / GM
2² = 4π². (24 . ³√(G.Msun yr²/ 4π²))³ / GM
4 = 13824 Msun / M
M = 6912 x 10³⁰ kg
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Please I need at least 3 differences between high and low specific heat capacity I will mark you brainliest
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| Specific Heat Capacity |"What Is It and What Are Some Differences Between High and Low Specific Heat Capacity?"
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Hello! Today, let's begin with discussing what specific heat capacity is.
"What is Specific Heat Capacity?"
It is the amount of heat per unit required to increase the temperature by 1°C. Most of the time, specific heat is used for determining the processing temperatures as well as amount of heat that is necessary for processing. It is helpful in differentiating between that of two polymeric composites.XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
"What is High and Low Specific Heat Capacity?"
Now, this specific situation is asking a question regarding the differences between high and low specific heat capacity. When the specific heat capacity is high, this means that it takes more energy to either increase or decrease its temperature. Take water for instance; water has a high specific heat, meaning it will take more energy to increase the temperature of the liquid compared to other substances. That's why when you are boiling water in a pot, the water needs time to absorb heat before it begins to boil at the increase in temperature.On the other hand, when the specific heat capacity is low, this means that it doesn't take as much energy to increase or lower as high SHC does. For example, any metals such as iron have low specific heat. It doesn't take long for the substance's energy to increase the temperature. The same thing occurs when you place a spoon in a cup of hot coffee. It is said that even other substances like sand have relatively low specific heat.______________________________________________________
Hopefully this sort of helps you have a better understanding of what specific heat is, as well as the differences between that of high and low specific heat capacity. Also, if this is a write your answer response, it is better to dive further into your studies and notes regarding this topic so you can properly answer the question and follow the guidelines. Anyways, I wish you the best of luck on your assignment. Thanks for reading!
PLEASE ANSWERRRRRRRRRRRRRR
Law of Reflection :
The law of reflection states that when light rays strike a smooth surface, the angle of reflection equals the angle of incidence, and the incident ray, reflected ray, and normal to the surface all lie in the same plane.
Here, let us consider, the ray A as the normal , as it is perpendicular to the surface of the plane mirror. When the incident ray hits the plane mirror at an angle say, θ with the normal ( here, incident ray A) , then, θ will be the angle of reflection.
Now if we consider all the incident rays A, B, C and D. Among them, let the ray C make an angle Θ, with the normal ( here, incident ray A).
Therefore, from the image given, clearly, θ = Θ, hence Θ is the angle of reflection, thus ray C best represents the reflected ray.
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An experiment was performed to determine how the amount of coffee grounds could affect the taste of coffee. The same amount and type of water, the same perking time, and the same electrical sources were used. What is a constant?
A constant in the experiment performed to determine how the amount of coffee grounds could affect the taste of coffee is amount of water.
What is constant in an experiment?Experiment is a test under controlled conditions made to either demonstrate a known truth, examine the validity of a hypothesis, or determine the efficacy or likelihood of something previously untried.
An experiment is conducted using variables such as;
Independent variableDependent variableControlled variable or constantA controlled variable or constant is a factor that is kept constant in a series of experiments in which other factors are varied.
According to this question, in an experiment that was performed to determine how the amount of coffee grounds could affect the taste of coffee, the same amount and type of water, the same perking time, and the same electrical sources were used.
This suggests that the amount of water is a constant in this experiment.
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What is the equation for momentum (p)?
Answer:
p(momentum) = mass(kg) x velocity (m/s)
the cliff divers of acapulco push off horizontally from rock platforms about 35 m above the water, but they must clear the rocky outcrops at water level that extend out into the water 5 m from the base of the cliff directly under their launch point. what minimum speed is necessary to clear the rocks? how long are they in the air?
The minimum speed necessary for the diver to clear the rocks 10.59m/s and the diver will be in air for about 2 seconds.
From the provided situation, we can analyze that the path of travel of the diver will be a projectile.
The maximum horizontal range is 35 meters.
And the height required is 5 meters.
We know, for a projectile,
Horizontal range R is given by U²sin(2A)/g
The height H attained is given by U²sin²A/2g
Dividing the height by range,
H/R = tanA/4
TanA = 20/7
Now, we can find,
SinA = 21.18
We know,
H = U²sin²A/2g
U²=2Hg/Sin²A
U²=2(5)(10)/(20/21.18)²
U = 10.59m/s.
The diver should start with speed of 10.59m/s to clear the rocks.
The time of flight is given by,
T = 2UsinA/g
Putting the values,
T = 2(10.59)(20/21.18)/10
T = 2 seconds.
The diver will be in air for 2 seconds.
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A woman of mass 57.6 kg is standing in an elevator.If the elevator floor pushes up on her feet with a force of 395 N, what is the acceleration of the elevator? Assume the +y-direction to be up. Enter a negative answer if the acceleration is downward and a positive answer if the acceleration is upward.If the elevator maintains constant acceleration and is moving at 1.50 m/s as it passes the fourth floor on its way down, what is its speed 4.00 s later?
There are two forces acting on the woman: the normal force of the floor of the elevator and the weight of the woman.
First, find the weight of the woman by multiplying its mass times the acceleration of gravity:
[tex]\begin{gathered} W=mg \\ =(57.6\operatorname{kg})(9.8\frac{m}{s^2})=564.48N \end{gathered}[/tex]According to Newton's Second Law of Motion, the net force acting on an object relates to the acceleration of the object according to:
[tex]\Sigma F=ma[/tex]Since the normal force of the floor is exerted upwards and the weight is exerted downwards, then:
[tex]\begin{gathered} \Sigma F=N-W \\ \Rightarrow N-W=ma \end{gathered}[/tex]Isolate the acceleration from the equation:
[tex]\Rightarrow a=\frac{N-W}{m}[/tex]Replace the values of the normal force (395N), the weight and the mass of the woman to find the acceleration of the elevator:
[tex]\begin{gathered} \Rightarrow a=\frac{395N-564.48N}{57.6\operatorname{kg}}=-2.94236\ldots\frac{m}{s^2} \\ \therefore a\approx-2.9\frac{m}{s^2} \end{gathered}[/tex]Then, the acceleration of the elevator is 2.9 m/s^2 downwards.
Use the definition of acceleration to find the final speed of the elevator 4 seconds after the initial speed of 1.50 m/s downwards:
[tex]\begin{gathered} v_f=at+v_0 \\ =(-2.94\frac{m}{s^2})(4.00s)-1.5\frac{m}{s} \\ =-13.26\ldots\frac{m}{s} \\ \approx-13.3\frac{m}{s} \end{gathered}[/tex]Therefore, the answers are:
The acceleration of the elevator is 2.9 m/s^2 downwards.
The final speed of the elevator 4 seconds after it had a speed of 1.50 m/s downwards, is 13.3 m/s downwards.
a circuit consists of a 10.0-volt battery, its internal resistor of 2.00 ohms, a resistor of 4.00 ohms, and an ammeter. the battery and the resistors are connected in series in a closed loop. the ammeter is parallel to the battery and its internal resistor. part a find the reading of the ammeter.
The ammeter will read the current as 1.67 A.
An ammeter is a device that measures the current through the conductor. The reading of the ammeter depends on the resistance and voltage. Resistance can be defined as the ratio of the voltage applied to the current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
From the question above, we know that
V = 10 V
r = 2 Ω
R = 4 Ω
Find the current by substituting the given parameters
V = I . ( R + r )
10 = I ( 4 + 2 )
10 = 6 I
I = 10 / 6
I = 1.67 A
Hence, the ammeter will read the following current.
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There are two groups of earthworms on the sidewalk. One group is on a shady, moist area on the sidewalk, and they are moving. The other group is on a very sunny, dry area of the sidewalk, and none of the worms in this group are still living.
What question could be asked to investigate the reason for these observations?
A. What kind of living environment do earthworms need?
B. How do earthworms get on the sidewalk?
C. Why do earthworms crawl?
D. What kinds of birds eat earthworms?
A.
Smooth-skinned earthworms have a body made up of numerous tiny segments. The lines designating the segments are visible on the body. Each segment possesses tiny, stiff hairs that aid in the worm's movement; occasionally, the hairs are difficult to perceive. They lack a skeleton yet have a large number of muscles.
B.
Because they lack lungs, earthworms breathe through their skin. For dissolved oxygen to enter their bloodstream, their skin must be damp. The mucus-coated skin of earthworms makes them dependent on a wet, moist environment to survive.
C.
The earthworm's characteristic crawling movement is caused by the action of muscles in the body wall. These lengthen and shorten the body in wavelike motions. Four pairs of tiny hard bristles on each segment help the worm grip the ground and hold onto the side of the burrow.
D.
Blackbirds, robins, and song thrushes are ground feeders, and for them, a worm is the only food that compares to it in taste. Large eyes and powerful bills let all of them to see in the early morning light, when earthworms are most active close to the surface. Their strong bills also allow them to pull struggling earthworms from the soil.
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How much gravitational force is acting on a 5 kg bowling ball resting on the floor?
A. 0.2 N
B. 9.8 N
C. 1 N
D. 49 N
Answer:
Explanation:
F = m * a = 5 kg * 9.81 m/s^2 = ~ 49 N
What average mechanical power (in W) must a 76.5 kg mountain climber generate to climb to the summit of a hill of height 305 m in 42.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body.
Power is given by, P= W/t, where W is mechanical work done and t is time taken.
From work-energy relation, work done is equal to the change in potential or kinetic energy.
W = mg[tex]h_{2}[/tex] - mg[tex]h_{1}[/tex]
Given,
Mass of mountain climber, m =76.5kg
Height of mountain hill, [tex]h_{2}[/tex] = 305m
Time taken to climb, t = 42 min= 42×60s= 2520s.
Since climber starts from the down of hill, [tex]h_{1}[/tex] = 0m. So, [tex]h_{2} - h_{1}[/tex] = 305m.
Work done, W = 76.5kg × 9.8m/[tex]s^{2}[/tex] × 305m
⇒W = 22.866×[tex]10^{4}[/tex] J.
Average mechanical power, P = 22.866×[tex]10^{4}[/tex]J ÷ 2520s
⇒P = 90.7375 W (watt)
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a rocket started at rest.after initiating the launch,it had an acceleration of 90m/s2.how long did it take to reach a speed of 2430 m/s2
The time taken for the rocket to reach a speed of 2430m/s from rest is 27.0 seconds.
What is the time taken for the rocket to reach a speed of 2430m/s?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Since it starts from rest, Initial velocity u = 0m/sFinal velocity v = 2430m/sAcceleration a = 90m/s²Elapsed time t = ?To determine the time, substitute the given values into the formula above and solve for t.
v = u + at
2430m/s = 0 + ( 90m/s² × t )
2430m/s = 90m/s² × t
t = 2430m/s / 90m/s²
t = 27.0s
Therefore, the elapsed time is 27.0 seconds.
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A rocket launched with an acceleration of 90 m/s², and a final speed of 2430 m/s. So the time required to reach the final speed is 27 seconds.
What is acceleration?The ratio of change in velocity to time is referred to as acceleration. It has a SI unit m/s² with dimension formula MLT⁻².
According to the question, the given values are,
Final velocity, v = 2430 m/s
Initial velocity, u = 0 m/s
The acceleration is given as, a = 90 m/s².
Use the equation of motion to find the time required to reach the final speed,
v = u + at
2430 = 0 + ( 90 × t )
2430 = 90 × t
t = 2430 / 90
t = 27.0 seconds.
Hence, the time taken to reach the final speed is 27 seconds.
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a cats purple crinkle ball toy of mass 20g is throwwn straight up in the air with an initial speed of 4m/s. assume in this problem that air grad is negligible. what is the kinetic energy of the ball as it leaves the hand?
When the ball leaves the hand, it's kinetic energy is 160 Joules.
The kinetic energy of object is due to its virtue of motion. So, as the ball leaves the hand, it is in motion. The formula representing kinetic energy is: K.E. = 1/2×m×v², where K.E. is kinetic energy, m is mass and v is velocity.
Keep the values in formula to find the kinetic energy of the ball.
K.E. = 1/2×20×4²
Taking square on Right Hand Side of the equation
K.E. = 1/2×20×16
Performing multiplication and division on Right Hand Side of the equation
K.E. = 160 Joules
Thus, kinetic energy of ball is 160 Joules.
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. is a major factor in dictating how much energy the vehicle can absorb to protect the occupants. a. frictional energy b. angle of attack c. speed d. all of the above
The correct answer is option c, speed.
Speed is the rate at which someone or something moves or operate. It is measured by the velocity and time.
Velocity is the total distance in total time taken.
Speed tells the amount of energy absorbed by the vehicle. The energy is used in the movement of the vehicle and it also helps the vehicle to move accordingly.
Speed is the major factor that helps to protect the occupants.
It is speed only that we can adjust a according to the situation. This also keeps the vehicle in control. It is the main factor in any vehicle that causes the vehicle to move and also it helps to keep it in control as well. Other controls are the supporting factors that helps to keep the speed in control.
Be it the weather, the climate, roads or traffic, it is speed that helps to keep the occupants safe.
Therefore, Speed is a major factor in dictating how much energy the vehicle can absorb to protect the occupants
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An electric drill transfers some energy wastefully. Aside from heat, what else carries the energy that it transfers wastefully?
Answer:
Explanation:
Mechanical energy
Answer:
The right answer is "sound" or "sound waves"
Explanation:
Electric drills are noisy, but this is not useful, so sound is a wasted energy transfer.
a small container of water is placed on a carousel inside a microwave oven, at a radius of 12.5 cm from the center. the turntable rotates steadily, turning through one revolution each 7.45 s. what angle does the water surface make with the horizontal?
θ = 0.0090 degree is the angle does the water surface make with the horizontal
At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.
Time for every rotation is 7.15 seconds.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2.....(1)
Gravitational force is caused by:
Fg=mg
Fg=mx9.8........(2)
Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:
tanθ=Fc/Fg
tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8
tanθ=0.0090
θ=0.0090 degree
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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.
Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.
A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.
7.15 seconds pass throughout each revolution.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)
There is a gravitational force because of:
Fg=mg
Fg=mx9.8........(2)
Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:
tanθ=Fc/Fg
tan = (m12.5x10-2(2 /7.45)/mx9.8)
tanθ=0.0090
0.09 degrees.
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24) A 0.042-kg pet lab mouse sits on a 0.35 kg air-track cart. The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of u1=0.88m/s. What is the speed v2 of the mouse and the 0.25-kg cart? |
The mass of the mouse, m₁=0.042 kg
The mass of the 1st cart, m₂=0.35 kg
The mass of the second cart, m₃=0.25 kg
The speed of the 1st car after the jump, u₁=0.88 m/s
From the law of conservation of momentum, the momentum of a system should always remain the same.
Before the mouse jumps from one cart to another, all the objects were at rest. Therefore the total momentum of the system was zero.
Thus after the mouse jumps, the total momentum of the system should be equal to zero.
Thus the momentum of the second cart and the mouse will be equal in magnitude to the momentum of the first cart but it will be in the opposite direction.
Thus,
[tex]m_2u_1=(m_1+m_3)v_2[/tex]On substituting the known values,
[tex]\begin{gathered} 0.35\times0.88=(0.042+0.25)v_2 \\ \Rightarrow v_2=\frac{0.35\times0.88}{(0.042+0.25)} \\ =1.05\text{ m/s} \end{gathered}[/tex]Thus the speed of the mouse and the second cart after the mouse jumps is 1.05 m/s
A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
pls the answer.........................................................................................................................
a) The motion of the motorcyclist is a uniform motion
b) The distance is 600 m
c) The speed is 20 m/s.
What is the motion?We now that motion has to do with the change in the position of an object with time. In this case, we have the graph that described the motion of the motorcyclist . It is clear that the distance is increasing in equal amounts, in equal time intervals thus this is a uniform motion.
Looking at the graph, we can see that the motorcyclist covers 600 meters of distance within 30 seconds.
We can obtain the speed as the ratio of the distance to the time or the slope of the graph. Hence the speed is obtained from;
Speed = distance / time
Using the slope concept;
[tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]
= 600 - 0/30 - 0
= 20 m/s
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the floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.36 with the floor. if the train is initially moving at a speed of 45 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?
24.8 m is the shortest braking distance.
On the horizontal axis, we dread the force of friction (fr) that prevents the train from moving and accelerating.
Y axis
N- W = 0
N = W = mg
explanation?
In order to fix this issue, we must apply Newton's second law to the boxes, with the norm vertically up and the weight vertically down.
Write the equation for each axis. On the horizontal axis, we dread the force of friction (fr) that prevents the train from moving and accelerating.
Y axis
N- W = 0
N = W = mg
X axis
-Fr = m a
-μ N = m a
-μ mg = ma
a = μ g
a = - 0.36
a = - 3.14 m/s²
Utilizing the kinematics equations, we determine the distance.
(Vf2 - Vo2) / 2 a = Vf2 = Vo2 + 2 an
The speed of the train is zero (Vf = 0) when it stops.
Vo=45 km/h (1000 m/km) (1 h 3600 s)= 12.5m/s
x = ( 0 - 12.5²) / 2 (-3.14)
x= 24.88.8 m
The shortest braking distance is 24.8 m
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