A dog walks 15 meters to the east and then 20 meters back to the west
the dig would -5 from where he first started.
A 0.18 kg baseball moving at +21.80 m/s is slowed to a stop by a catcher who exerts a constant force of -360 N.
How long does it take this force to stop the ball?
___s
How far does the ball travel before stopping?
___m
Answer:
hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.
It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.
What is force?To find the time it takes for the catcher to stop the ball, you can use the equation:
time = distance / velocity
In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:
time = 0 / 21.80
time = 0 s
So, it takes 0 seconds for the catcher to stop the ball.
To find the distance the ball travels before stopping, you can use the equation:
distance = 1/2 * acceleration * time^2
In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:
distance = 1/2 * (-2000 m/s^2) * (0 s)^2
distance = 0 m
So, the ball travels 0 meters before stopping.
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(b) Which statement about beta radiation is true?
Tick one box
It is the fastest moving type of radiation.
It is the type of radiation with a negative charge.
It is the type of radiation with the greatest mass.
It is the type of radiation with the greatest range in air.
Answer:
is the fastest moving type of radiationhe
Two blocks, M = 14.2 kg and m = 4.73 kg, are connected via a massless rope. They are being pushed up a frictionless hill, with a slope of 15.80, with a constant force in the direction of the incline, such that there is a total acceleration of 2.53 m/s2 for the system
Slope is rise over run, meaning the ratio of the change in height to the change in horizontal distance. So a slope of 15.80 corresponds to an angle of ascension θ of
tan(θ) = 15.80 → θ ≈ 86.38°
The order of the blocks (i.e. whether the large one is pulling the smaller one up or vice versa) does not matter, since friction is not a concern. So if we take the connected blocks as a single mass, by Newton's law we have a net force acting parallel to the incline of
∑ F = P - (M + m) g sin(θ) = (M + m) a
(see the attached free body diagram)
where
P = magnitude of the push
g = 9.80 m/s²
a = 2.53 m/s²
and M and m are the given masses.
Then the system requires a push of
P = (M + m) (a + g sin(θ))
P = (14.2 kg + 4.73 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
P ≈ 233 N
If you have to find the tension in the rope, consider the free body diagram for one of the blocks. By Newton's second law, the net parallel force acting on, say, the larger block (if it's being pulled by the rope) is
∑ F = T - M g sin(θ) = M a
where
T = tension in the rope
Then
T = M (a + g sin(θ))
T = (14.2 kg) (2.53 m/s² + (9.80 m/s²) sin(86.38°))
T ≈ 175 N
What is the loudness, in decibels, of a sound 1 trillion times as loud as the softest audible sound?
The loudness of this sound in decibels is _________ dB. (Type an integer or a decimal.)
Answer:
What is the loudness, in decibels, of a sound 100 trillion times as loud as the softest audible sound? The loudness of this sound in decibels is dB. (Type an integer or a decimal.)
Which of the following statements is true?
1)Efficiency is calculated by multiplying work input and work output.
2)a few machines are 100 percent efficient.
3) Some machines are frictionless.
4)The ratio of work output to work input is always less than one.
Answer:
4)
Explanation:
Efficiency is calculated by dividing the energy out by energy in, not multiplying
No machines are 100% Efficient
No machines are frictionless
4) is true
In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number presented in statement B.
1. Statement A: 2.567 km, to two significant figures.
Statement B: 2.567 km, to three significant figures.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
2. Statement A: (2.567 km+ 3.146 km), to two significant figures.
Statement B: (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
3. Statement A: Area of a rectangle with measured length = 2.536 m and width = 1.4 m.
Statement B: Area of a rectangle with measured length = 2.536 m and width = 1.41 m.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
Answer:
1) A> B, 2) A = B, 3) A> B
Explanation:
When a figure is given the number of significant figures to determine the precision or uncertainty the number
1) the uncertainty in the number with three significant figures is less than the number with two significant figures
statement A 2.6
statement B 2.57
A> B
2) decalration A
2,567 + 3,146 = 5,713
with two figures it remains
5.7
statement B
2.6 + 3.1 = 5.7
A = B
3) for the product the result is with the number that has the least significant figures
statement A
rectangles area
2.536 * 1.4 = 3.6
statement B
2.536 * 1.41 = 3.58
A> B
The latent heat of vaporization for water at room temperature is 2430 J/g.
1. How much kinetic energy does each water molecule that evaporates possess before it evaporates?
2. Find the pre-evaporation rms speed of a water molecule that is evaporating.
3. What is the effective temperature of these molecules (modeled as if they were already in a thin gas)?
4. Why do these molecules not burn you
a. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy decreases.
b. These molecules got to be slow-moving in collisions that made other molecules fast-moving; the average molecular energy is unaffected.
c. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy is unaffected.
d. These molecules got to be fast-moving in collisions that made other molecules slow-moving; the average molecular energy increases.
Answer:
1) [tex]kinectic energy=7.26*10^-^2^0J[/tex]
2) [tex]V= 2.0m/s[/tex]
3) [tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place
Explanation:
From the question we are told that
latent heat of vaporization for water at room temperature is 2430 J/g.
1)Generally in determining the molar mass of water evaporated we have that
-One mole (6.02 x 10. 23 molecules)
-Molar mass of water is 18.02 g/mol
Mathematically the mass of water is give as
[tex]M=\frac{18.02}{6.02*10^-^2^6}[/tex]
[tex]M=3*10^-^2^3g[/tex]
Therefore
[tex]kinectic energy=2430J/g*3*10^-^2^3g[/tex]
[tex]kinectic energy=7.26*10^-^2^0J[/tex]
b)Generally the evaporation speed V is given as[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
Mathematically derived from the equation
[tex]\frac{1}{2} mv^2 =K.E[/tex]
To Give
[tex]V= \sqrt{\frac{K.E*2}{m} }[/tex]
[tex]V= \sqrt{\frac{7.26*10^-^2^0J*2}{3*10^-^2^3g} }[/tex]
[tex]V= 2.0m/s[/tex]
c)Generally the equation for velocity [tex]Vrms=\sqrt{\frac{3RT}{M} }[/tex]
Therefore
Effective temperature T is given by
[tex]T=\frac{\sqrt{v}*m}{R}[/tex]
where
[tex]T=\frac{\sqrt{2.0m/s}*6.02*10^-^2^6}{0.082057 L atm mol-1K-1}[/tex]
[tex]T=3.5*10^3K[/tex]
4) The Molecules do not burn because of the presences of hydrogen bond in place
what is physical quantity
Answer:
a physical quantity is any physical property that can be quantified, that is, be measured using numbers.
Answer: A physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed as the combination of a numerical value and a unit. For example, the physical quantity mass can be quantified as n kg, where n is the numerical value and kg is the unit.
4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle that A makes with the x axis
Answer:
A = 4.49
α = 57.72°
Explanation:
Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.
[tex]A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49[/tex]
The angle tangent can be used to determine the angle.
[tex]tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)[/tex]
How much energy, in joules, is released by an earthquake of magnitude 8?
______________ joules
(Use scientific notation. Use the multiplication symbol in the math palette as needed.)
Answer:
6.309573e+16 joule is released by an earthquake of magnitude 8
Answer:
An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.
Explanation:
An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.
what happens to the orbit time as the distance increases.
Roots spreading far and wide
Answer:
₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₮₣ ₣5₣ đ₮ɽ ₮₣ ₮ɽ
The electrons in the beam of a television tube have a kinetic energy of 2.70 10-15 J. Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 1.00 10-5 T.
A) In what direction are the electrons deflected by this field component?
B) What is the magnitude of the acceleration of an electron in part (a)?
Answer:
[a]. South direction
(b). 1.354 × 10^14 m/s^2
Explanation:
In order to to be able to solve this question effectively, one must be familiar with physics concepts such as kinetic energy[1/2 ×mass × velocity,v²], magnetic force[ magnetic force = charge × velocity × magnetic field × sin Ф] and Newton's law of motion especially the second law of Newton[ Force = mass × acceleration].
(a). The direction are the electrons deflected by this field component = q( v × B) = - ( i × -k) = -( - ( i × k) = - (- (- j) = -j. The -j is in the south direction.
Note that i × k is being replaced by -j.
(b). In order to determine the magnitude of the acceleration of an electron in part (a), the first thing to do is to calculate the velocity from the equation for kinetic energy.
Thus, velocity = √ [(2 × 2.7 × 10⁻¹⁵) ÷ 9.1 × 10⁻³¹] = 7.7 × 10^7 m/s.
The next thing is to determine the net force.
Therefore, the net force = 1.6 × 10^-19 × 7.7 × 10^7 m/s × 1 × 10^-15 sin 90°.
= 1.232 × 10^ -16N.
Hence, Net Force = mass × acceleration.
1.232 × 10^ -16N = 9.1× 10^-31 × acceleration.
The acceleration = 1.232 × 10^ -16N/ 9.1× 10^-31 = 1.354 × 10^14 m/s^2.
What type of metals are known as ferromagnetic metals
Answer:
those who are attracted to magnets. ex: iron, cobalt and nickel
how is space Technology different from space exploration
Answer:
Space technology is technology developed by space science for use in astronautics, for purposes such as spaceflight or space exploration. Space technology includes spacecraft, satellites, space stations, and support infrastructure equipment, and procedures and space warfare.
Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be treated as particles and are fixed with a certain separation. (a) For what value of q/Q will the electrostatic force between the two spheres be maximized? What are the (b) smaller and (c) larger values of q/Q that give a force magnitude that is 75% of that maximum?
Answer:
2. Smaller value of q = 1/4Q
3. Larger value of q = 3/4Q
Explanation:
1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.
2. The smaller value is
F = 75% = 75/100
= 3/4 * Q²/16piEod² ---3
When we equate 1 and 3
We get 3Q²/16 = Qq - q² from here we cross multiply to get
3Q² = 16(Qq-q²)
3Q² = 16Qq-16q²
16q² - 16Qq + 3Q² = 0
When solve this out using the quadratic equation formula, we have:
Q/2 +- 2Q/8
We can get the smaller value of q as
Q/2-2Q/8
Solve using LCM we get
2Q/8 = 1/4Q = Q/4
C. The larger value of q
Q/2+2Q/8
= 6Q/8
= 3Q/4
Please use the attachment it will guide you to understand this better.
Which of the following is an example of exothermic reaction?
Explanation:
Exothermic reaction are those in which heat releases during a reaction
Truck pull the car 2350 KG a distance of 25 m. If they car accelerates from 3M/S to 6M/S, what’s the average force exerted on the car
Answer: 7
Explanation: 7 is the superior number
Answer:
1,269 N
Explanation:
I guessed and got the question right on CK-12's work practice.
How can pressure impact the alignment of minerals within the rock
It has been suggested that rotating cylinders about 10 mi long and 5.9 mi in diameter be placed in space and used as colonies. The acceleration of gravity is 9.8 m/s 2 . What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on
Answer:
ω = 0.05 rad/s
Explanation:
We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,
[tex]Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\[/tex]
where,
ω = angular velocity of cylinder = ?
g = required acceleration = 9.8 m/s²
r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m
Therefore,
[tex]\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\[/tex]
ω = 0.05 rad/s
A woman on a bridge 82.2 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 5.04 m more to travel before passing under the bridge. The stone hits the water 2.13 m in front of the raft. Find the speed of the raft.
Answer:
0.71 m/s
Explanation:
We find the time it takes the stone to hit the water.
Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.
So, substituting the values of the variables into the equation, we have
y = ut - 1/2gt²
82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²
82.2 m = 0 + (4.9 m/s²)t²
82.2 m = (4.9 m/s²)t²
t² = 82.2 m/4.9 m/s²
t² = 16.78 s²
t = √16.78 s²
t = 4.1 s
This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.
Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s
The following diagram shows four charged objects: A, B, C, and D.
Based on the diagram, which statement is true?
The electric force between A and B is identical in magnitude to the electric force between C and D.
The electric force between A and B is greater than the electric force between C and D.
The electric force between A and B is smaller than the electric force between C and D.
The electric force between A and B is canceled by the electric force between C and D.
Answer:
they are identical.
Explanation:
use coulomb law. the size of that line is just to confuse students because some sick teacher gets off on making you miss points. coulombs law says the magnitude of electric field is proportional to the size of the charge. here they are all +/-1 they are the same.
The true statement is "The electric force between A and B is greater than the electric force between C and D." The correct answer is B.
What is electric force?Electric force, also known as Coulomb force, is the attraction or repulsion between electrically charged particles. It is a fundamental force of nature that arises from the interaction of charged particles with each other. Electric force is described mathematically by Coulomb's law, which states that the magnitude of the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The direction of the force depends on the sign of the charges, with like charges repelling each other and opposite charges attracting each other.
Here in the Question,
The electric force between two charged objects depends on the magnitude of the charges and the distance between them. In this case, object A has a positive charge and object B has a negative charge, so there is an attractive force between them. Object C also has a positive charge, but it is separated by a larger distance from the negative charge at point D, so the electric force between C and D is weaker than the force between A and B.
Option A is not true because the distance between A and B is smaller than the distance between C and D, so the forces cannot be identical in magnitude.
Option C is not true because, as explained above, the force between A and B is greater than the force between C and D.
Option D is not true because the forces between A and B and between C and D are not opposite in direction, so they cannot cancel each other out.
Therefore, The correct answer is B. The electric force between A and B is greater than the electric force between C and D.
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Starting with the definition 1 in. = 2.54 cm, find the number of (a) kilometers in 1.20 mile and (b) feet in 1.80 km.
Explanation:
[tex]miles \: to \: km \\ = 1.2 \: miles \times \frac{1 \: km}{1.6093 \: miles} \\ = 0.7457 \\ \\ km \: to \: feet \\ = 1.8 \: km \times \frac{3280 \: ft}{1 \: km} \\ = 5904 \: ft[/tex]
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 68.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 21.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.
Answer:
0.74 m/s
Explanation:
From the question,
We apply the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0
0 = Total momentum after collision
(m+M)V + m'v = 0
Where m = mass of the skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v = velocity of the brick
make V the subject of the equation above
V = -m'v/(m+M)................... Equation 1
Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.
Substitute these values into equation 1
V = -(2.5×21)/(68+2.5)
V = 52.50/70.5
V = 0.74 m/s
kinda easy but too lazy
Answer:
We don't promote laziness here, my dear child. :)
What are the applications of diodes and rectifiers?
Answer:
The most common and important application of a diode is the rectification of AC power to DC power. Using the diodes, we can construct different types of rectifier circuits. The basic types of these rectifier circuits are half wave, full wave center tapped and full bridge rectifiers.
Explanation:
Here ya go <3
Why do the snakes only get one unit of energy?
Answer: Snakes are reptiles
Explanation: All reptiles are ectothermic (they obtain body heat from their environment).
As snake belongs to secondary consumer, it get less amount of energy in food cycle. If producer (grass) get 100 unit of energy, according to food chain snakes only gets one unit of energy.
What is food chain?The sequence of events in an ecosystem known as a "food chain" occurs when one live organism eats another organism, which is then eaten by a larger organism. A food chain is created by the transfer of nutrients and energy from one creature to another at various trophic levels.
The feeding habits or connections between living things are also explained by the food chain. Trophic level is the term used to describe the orderly phases in a food chain, from producers at the bottom through primary, secondary, and tertiary consumers. A trophic level is any position along a food chain.
A food chain demonstrates the interdependence of all living things on one another. The direction of energy flow within an ecosystem is described by the food chain.
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Two equal in magnitude, positive charges Q are fixed at distance 2d from each other. The third charge, of magnitude q and unknown sign is positioned very carefully into the midpoint on the line connecting the first two charges. Pick the statement which is correct:
a. The third charge will accelerate towards one of the charges.
b. The third charge will be in equilibrium and this equilibrium is stable.
c. The third charge will be in equilibrium and this equilibrium is unstable.
d. The third charge will be in equilibrium. This equilibrium is stable if charge is positive and unstable if charge is negative.
e. All these statements are wrong.
Answer:
the correct one is d
Explanation:
To answer which statement is correct, let's look for the force on the third charge
F = F₁₃ + F₂₃
force is electric force
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]
In the exercise we are told that the distance between the two charges is 2d, therefore the distance of each charge to the third is x = d and the two falls have a car Q
F₁₃ = k q Q / d²
F₂₃ = k q Q / d²
suppose that charge 3 is positive for which the forces are repulsive
F = k q Q / d₂ - k q Q / d₂
F = 0
suppose that the charge 3 is negative for which the forces are of attraction
F = -k q Q / d₂ + k q Q / d₂
F = 0
We can see that regardless of the sign of charge 3 the forces on it are zero, so it has no acceleration, it is in equilibrium.
Let's analyze the type of equilibrium, for this we move the charge 3 towards one of the sides
charge 3 positive
the force towards the approaching side increases and the other decreases, therefore the load has a net force towards the center, in that case the equilibrium is stable
negative charge 3
The force towards the approaching side is stronger and more attractive and the other decreases, therefore it has an attractive net force that carries it towards the charge, it is closer, in this case the balance is unstable
To review the different answers, the correct one is d
An object accelerates uniformly from rest. If the final velocity of the object after 6.0 s is
18 m/s east, how far did the object travel?
Answer:
54m
Explanation:
Given parameters:
Initial velocity = 0m/s
Time taken = 6s
Final velocity = 18m/s east
Unknow:
How far did the object travel = ?
Solution:
To solve this problem, we use one of the kinematics equation:
We first find the acceleration which is the change in velocity
So;
S = [tex](\frac{v - u}{2} ) t[/tex]
S is the distance
v is the final velocity
u is the initial velocity
t is the time taken
Therefore;
S = [tex]\frac{18 - 0}{2}[/tex] x 6 = 54m
