What makes water a polar molecule? options:A) The equal forces between oxygen and hydrogenB) The liquid nature of waterC) The uneven bend in the bond between oxygen and hydrogenD) The ionic bond between oxygen and hydrogen

the heat energy required to take it to the melting point is 420J.

The heat capacity, abbreviated Cp, is the amount of heat needed to elevate a mole of a substance's heat content by precisely one degree Celsius.

A material has more thermal energy the hotter it is, says basic thermodynamics. Additionally, when a chemical is present in greater concentrations at a particular temperature, it will have a higher total thermal energy.

Mathematically,

Q = mc∆T

Where,

Q = quantity of heat absorbed by a body

m = mass of the body

∆t = Rise in temperature

C = Specific heat capacity of a substance depends on the nature of the material of the substance.

S.I unit of specific heat is J kg-1 K-1.

Given,

An ice cube of mass = m=25g

initial temperature = T1 = -8°C

final temperature = T2 = 0°C

Heat capacity for solid water = c = 2.1J/g°C

According to heat energy required to take it to the melting point,

Q = mc∆T

Q = 25g×2.1J/g°C × (0+8) °C

Q = (25×2.1×8) J

Q = 420J

Hence, the heat energy required to take it to the melting point is 420J.

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Answer:CO2

Explanation:

A trick that is quick and easy to use when telling covalent bonds from ionic bonds is to look at the atoms that are bonding. If there is a metal involved, then it is ionic bonding (hence AgF, NaCl. and K2S are not covalent bonding as Ag, Na, and K are all metals.

But to be more specific, ionic bonding happens when two ionic or polar atoms (atoms with non-neutral charges,) come together to balance out their charges (as negative charges will be attracted to positive charges and vice versa); the fancy term for this is electrostatic forces. They (usually) give up electrons to another atom, but do not share electrons. Covalent bonding happens when atoms actually share electrons and have their atomic orbitals overlap, meaning that the electrons actually travel through the surrounding volume of both atoms. Ionic bonded atoms will also separate into ions when in a solvent.

Answer: One centimeter per month.

Explanation: Technically speaking, human hair grows about 1/2 inch a month or 6 inches a year.  1/2 inch is approx 1.27 centimeters, or in other words, one centimeter a month.  Therefore, that's your answer.

Let me know if I got it right! :)

Answer:

1 centimeter per month

Explanation:

Human hair typically grows 6 inches in a year. Since there's 12 months, we can tell that hair grows 1/2 an inch per month. 1/2 an inch is about 1 cm.

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Answer:

Explanation:

Here, we want to get the definition of a weak base

A weak base is a base that does not dissociate completely in solution.

What this means is that when the base is placed in a solution, its dissociation into the corresponding metallic and hydroxide ions is incomplete

The electron configurations that are not valid among the options are 1s²2s²2p 3s 3p 4s²4d¹04p5 and 1s²2s²2p 3s³3d5. Options 1 and 2.

The electron configuration of atoms using the various orbital levels follows the order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.

Also, according to Afbau principle, orbitals with low energy levels are filled with electrons before orbitals with higher energy levels.

Using the above,  1s²2s²2p 3s 3p 4s²4d¹04p5 is incorrect for some reasons:

1s²2s²2p 3s³3d5 is incorrect because:

The remaining electron configurations are correct with correctly placed electrons in the various orbitals.

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A sample will likely affect a criminal case because this evidence will provide a nearly exact match to the suspect’s hair (Option D).

DNA testing refers to the techniques used to obtain DNA from samples that can be used to identify an individual in a police case. A sample of hair may be used for DNA testing because it contains cells and therefore also contains DNA.

Therefore, with this data, we can see that DNA testing allow us to identify individuals for which we need to obtain a sample with cells.

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Answer:

The objective of agricultural chemistry is to preserve or improve the fertility of soil, increase the agricultural yield and improve the quality of the crop. To reach those objectives the agricultural industry uses two types of chemicals.

- Fertilizers: increase soil fertility making crops more productive. They usually are compounds that contain three basic elements: P, K and N.

- Pesticides: control weeds (herbicides), insects (insecticides) and diseases from fungus (fungicides).

The following lists consists of ionic compounds except carbon disulfide (CS₂).

Barium hydroxide , Ba(OH)₂ is an ionic compound.

zinc carbonate, ZnCO₃ is an ionic compound.

ammonium sulfate , (NH₄)₂SO₄  is an ionic compound.

calcium chloride, CaCl₂  is an ionic compound.

carbon disulfide, CS₂ is not an ionic compound. In carbon disulfide both the elements are non metallic elements. The bond formed between atoms are by sharing of electron known as covalent bond due to very little difference in electronegativity.

magnesium nitrate, Mg(NO₃)₂  is an ionic compound.

sodium sulfate, Na₂SO₄  is an ionic compound.

copper(II) oxide, CuO  is an ionic compound.

potassium nitride KNO₃  is an ionic compound.

aluminium sulfide, Al₂S₃  is an ionic compound.

sodium sulfite, Na₂S  is an ionic compound.

calcium fluoride, CaF₂  is an ionic compound.

Thus, The following lists consists of ionic compounds except carbon disulfide (CS₂).

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This elements or substances that are not a metal are called non-metals.

I think that the answer is Non-metal

Answer:

The pH of the solution is 1.60.

Explanation:

1st) It is necessary to write and balance the chemical reaction:

Now we can see that 1 mole of NaOH reacts with 1 mole of HCl.

2nd) We have to calculate the moles contained in 15mL of 0.10M NaOH solution and the moles contained in 25mL of 0.10M HCl solution:

• Moles contained in NaOH solution:

• Moles contained in HCl solution:

Now we know that there are 1.5x10^-3 moles of NaOH and 2.5x10^-3 moles of HCl.

3rd) According to the stoichiometry of the reaction, 1 mole of NaOH reacts with 1 mole of HCl, so in this case, 1.5x10^-3 moles of NaOH will react with 1.5x10^-3 moles of HCl, because NaOH will be the limiting reactant and HCl will be the excess reactant.

So, now we have to calculate the excess of HCl:

2.5x10^-3moles - 1.5x10^-3moles = 1x10^-3moles

Now we know that there are 1x10^-3 moles of HCl left.

4th) Excess HCl will remain dissociated into H+ and Cl-, according to the following equation:

That means that for every mole of HCl, 1H+ dissociates. So, in this case, there are 1x10^-3 moles of H+.

Remember that these moles are contained in 40mL, so the molarity of H+ is 0.025M:

5th) Finally, we can calculate the pH of the solution, by replacing the H+ concentration in the pH formula:

So, the pH of the solution is 1.60.

She will keep evidence separated so it doesn’t get contaminated demonstrates the understanding of Locard’s Exchange Principle and is denoted as option C.

This principle states that an individual who commits a crime will bring something into the crime scene and leave with something from it. This also explains that they can be used as evidence during investigation by the appropriate authorities.

Since we are aware that new substances are always brought into and carried away from the crime scene then it is best to keep the evidence separated so it doesn’t get contaminated.

This ensures that the results gotten from the analysis and investigation are accurate and is therefore the reason why option C was chosen as the correct choice.

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The final temperature of the solution will be 29.5 °C.

The heat released when 21.5 g of LiCl is dissolved completely in water is determined from the enthalpy change, ∆H of the solution of LiCl as follows;

Moles of LiCl in 21.5 g = mass/ molar mass

molar mas of LiCl = 42.5 g/mol

Moles of LiCl in 21.5 g = 21.5/42.5

Moles of LiCl in 21.5 g = 0.506 moles

Heat released = 0.506 * -37.0 kJ/mol

Heat released = 18.722 kJ or 18722 J

Heat released = heat gained by solution

mass of solution = 450 + 21.5

mass of solution = 471.5 g

Temperature change of the solution = 18722 / (471.5 * 4.184)

Temperature change of the solution = 9.5 °C

Final temperature of the solution = 20 °C + 9.5 °C

Final temperature of the solution =29.5 °C

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By using an appropriate conversion factor, the size of this popular car's engine is equal to 356.78 cubic inches.

A conversion factor simply refers to a number that is typically used to convert a number in one (1) set of units to another, either by dividing or multiplying.

Generally speaking, an appropriate conversion factor to an equal value must be used when it is necessary to perform any mathematical conversion.

Conversion:

1 cubic centimeter = 0.061023744094732 cubic inches.

5,840 cubic centimeter = X cubic inches.

Cross-multiplying, we have:

X = 0.061023744094732 × 5,840

X = 356.78 cubic inches.

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Complete Question:

A popular car has an engine that is reported to have a volume of 5840 cm³. What is the size in cubic inches?

The original pressure of argon in the cylinder is 5.68 atm.

The original pressure of argon in the cylinder is calculated as follows.

Apply the concept of molar ratio or molar proportion to determine the original pressure of argon in the cylinder.

Pr = [(Pn x Vn) + (Pa x Va) ] / (Vn + Va)

where;

7.15 = [(11.08 x 4.5) + (12 x Pa)] / (4.5 + 12)

7.15(4.5 + 12) = 49.86 + 12Pa

117.98 = 49.86 + 12Pa

68.12 = 12Pa

Pa = 68.12/12

Pa = 5.68 atm

Thus, the original pressure of argon in the cylinder is determined by applying concept of molar ratio.

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The rate constant ( k )= 9.2 x 10⁻³ s⁻¹The half life  (t1/2 )= 75.3 s

It is given that the reaction is 46% complete in 45 s

The relation between rate constant and the half life can be shown as:

For first order reaction:

ln[A]=−kt+ln[A]o

46% complete, 54% remains

A = 0.54

Ao = 1

Put the value of given data in the formula:

ln A = -kt + ln Ao

ln 0.54 = -k.45 + ln 1

-0.616=-k.45

k = 13.6 x 10⁻³ s⁻¹

The half life can be determined by using the formula:

t1/2 = (ln 2) / k

t1/2 = 0.693 / 13.6 x 10⁻³

t1/2 = 0.0509 ×10⁻³ s.

t1/2 = 5.09 ×[tex]10^{5}[/tex] s.

Therefore, the rate constant for the first order reaction will be 13.6 x 10⁻³ s⁻¹ and half life will be 5.09 ×[tex]10^{5}[/tex] s.

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b) firstly we nee dto understant that 1 ton = 2831.68 litres

therefore if 16 967.04 Litres needs transporting we simply divide the 16 967.04 by 2831.68 and the answer is 5.99 which is rounded of to 6. therefore 6 trucks will be needed

c) we need to first find out how many gallons of fuels will be needed to complete a 285 mile distance. so we divide 285 by 7.8 to get 36.54 gallons and we know the price of i gallon to be $3.95 therefoe the cost will be

3.95 x 36.54 = 144.33

the cost is $144.33 per day

The percentage of the sample of As-81 remaining undecayed after 43.2 seconds is 40.6%

We'll beging by calculating the number of half lives that has elapsed. This can be obtained as follow

The following data were obtained from the question:

n = t / t½

n = 43.2 / 33

n = 1.3

Finally, we shall determine the percentage remaining undecayed. This is shown below:

N = N₀ / 2ⁿ

N = 100 / 2^1.3

N = 40.6%

Thus, we can conclude that the percenatge undecayed is 40.6%

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Electron capture occurs when one of the electrons in the atom is captured by the atom's nucleus. The captured electron combines with one proton to form a neutron.

We have to find the nuclide that is produced when the aluminum-28 undergoes an electron capture.

If we look for the atomic number of Al in the periodic table we will see that it is 13. That means that it has 13 protons. Then we are given the atomic mass of aluminum, it is 28. That means that if we add the number of protons and the number of neutrons we get 28.

atomic mass = n° of protons + n° of neutrons = 13 + 15 = 28

atomic number = n° of protons = 13

The nucleus of the aluminum atom will capture one electron that will combine with a proton of the nucleus to form a neutron. So the atomic number will change because it will have 1 proton less. But the atomic mass won't change because we are losing one proton but winning a neutron, so it remains the same. After the electron capture, the new nuclide will have:

atomic mass nuclide = n° of protons + n° of neutrons = 12 + 16 = 28

atomic number nuclide = n° of protons = 12

If we look for the element that has an atomic number of 12 in the periodic table we will see that it is magnesium.

Finally we can express this like a reaction:

28 0 28

Al + e --------> Mg

13 -1 12

Answer:

28

Mg

12

2. Which is the volume of 3.20 moles of O₂?

We are told that at STP one mol of any gas occupies 22.4 L. We will use that relationship to find the volume occupied by 3.20 moles of O₂.

1 mol of O₂ = 22.4 L

volume of O₂ = 3.20 moles of O₂ * 22.4 L/(1 mol of O₂)

volume of O₂ = 71.7 L

Answer: 3.20 moles of O₂ occupies 71.7 L

7. Which is the volume of 100. g of O₂?

In this case we will use the same relationship, but we are given grams instead of moles. So first we have to convert the mass in grams into moles. To do that we use the molar mass of O₂.

atomic mass of O = 16.00 amu

molar mass of O₂ = 2 * 16.00

molar mass of O₂ = 32.00 g/mol

Once that we know that the mass of 1 mol of O₂ is 32.00 g, we can find the number of moles that we have in 100. g of it.

moles of O₂ = mass of O₂ /(molar mass of O₂)

moles of O₂ = 100. g/(32.00 g/mol)

moles of O₂ = 3.13 moles

Finally we can find the volume that 3.13 moles of O₂ occupies (remember that 1 mol of any gas occupies 22.4 L at STP).

volume of O₂ = 3.13 moles * 22.4 L/(1 mol)

volume of O₂ = 70.1 L

Answer: 100. g of O₂ occupies 70.1 L

The reaction to produce nitrogen dioxide from nitrogen and oxygen is as follows:

Since all the reactants and products are gases, we can take the coefficients as liters of substance.

Dividing the volumes we have of each reactant by their corresponding coefficient we can determine the limit reagent:

From this we can conclude that the limit reagent is oxygen.

We have to base our calculations on this substance.

According to the given equation, 2 L of O2 produce 2 L of NO2, use this ratio to find the volume of nitrogen dioxide produced:

It means that 60.6 liters of nitrogen dioxide gas are made.

Answer: Tetrachloroethylene is an nonpolar molecule.

Kinetic energy refers to the work required to accelerate a body from an initial state of rest to infinite speed. So kinetic energy is related to the motion and speed of a body.

So the answer will be C. motion

Answer:

288 g.

Explanation:

Measurements => Density.

Density is the ratio of the mass of an object to its volume:

where D is density, m is mass, and V is volume.

We have two data: the volume (32.1 mL) and the density (8.96 g/mL) and we need to find the mass.

We can solve for 'm' in the given equation and replace the given data, as follows:

The answer would be that the mass is 288 g.

The mass of the copper that is obtained is 97.2 tons.

We can define the term combustion as the procedure by which a substance can be burnt in oxygen. We can also be able to refer to the process as roasting the object in the air. It is an oxidation reaction.

Having said all all of these, the reaction equation can be written as;

[tex]Cu_{2} S + O_{2} ------ > 2Cu + SO_{2}[/tex]

We know that the percent of the copper that it contains can now be used when we are trying to compute the mass of the copper that can be obtained from the process as we are going to have in the question that is at hand here to solve.

We are now going to proceed to see the mass of the copper that can be produced from the 300 tons of the copper I sulfide ore given.

Thus;

The mass of copper that can be obtained is;

3.24/100 * 3000 tons

= 97.2 tons

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The question requires us to calculate the number of moles of each element (magnesium, chlorine and oxygen) in 8.30 moles of the compound magnesium perchlorate (Mg(ClO4)2).

From the molecular formula of magnesium perchlorate we can take the following information:

- in 1 mol of Mg(ClO4)2, there is only 1 mol of Mg;

- in 1 mol of Mg(ClO4)2, there are 2 moles of Cl;

- in 1 mol of Mg(ClO4)2, there are 8 moles of O.

With the information above, and knowing that the amount of Mg(ClO4)2 given by the question was 8.30 moles, we can calculate the amount, in moles, of each element:

1 mol Mg(ClO4)2 --------------- 1 mol Mg

8.30 mol Mg(ClO4)2 ---------- x = 8.30 mol Mg

1 mol Mg(ClO4)2 --------------- 2 mol Cl

8.30 mol Mg(ClO4)2 ---------- y = 2 x 8.30 mol Cl = 16.6 mol Cl

1 mol Mg(ClO4)2 --------------- 8 mol O

8.30 mol Mg(ClO4)2 ---------- z = 8 x 8.30 mol O = 66.4 mol O

Therefore, there are 8.30, 16.6 and 66.4 moles of Mg, Cl and O in 8.30 moles of magnesium perssufate.

The answer is -2219.9 kJ/mol

Answer:

Explanation:The given reaction is

It is an example of an oxidation reaction because in the above reaction, is getting oxidized to form .

Also, it is a type of combination reaction because magnesium reacts with oxygen to form a single product i.e. Magnesium oxide.

Answer:

To find a process more fingerprints (A uv imaging is used to capture and detect substances such as sweat which prints on a surface)

1) Molar mass of Allicin.

1.1- Write the formula.

1.2- Look for the molar mass of each element in the formula.

C: 12.011 g/mol

H: 1.008 g/mol

O: 15.999 g/mol

S: 32.06 g/mol

1.3- Count how many atoms are there in the formula.

C: 6

H: 10

O: 1

S: 2

1.4- Set the equation.

Plug in the known values.

The molar mass (MM) of Allicin (C6H10OS2) is 162.265 g/mol.

2) Moles of Allicin in the sample.

Allicin sample: 4.20 mg

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

2.1- Convert mg to g.

1g = 1000 mg

2.2- Convert grams to moles.

The molar mass of Allicin (C6H10OS2) is 162.265 g/mol.

Allicin sample: 0.00420 g

There are 0.00002588 moles of Allicin (C6H10OS2) in 4.20 mg of substance.

The result can also be expressed as 2.588*10^(-5) mol.

3) Molecules of Allicin in the sample.

The Avogadro's number is 6.022*10^(23).

1 mol C6H10OS2 = 6.022*10^(23) molecules C6H10OS2

Allicin sample: 0.00002588 mol.

There are 1.558*10^(19) molecules in the sample.

4) C atoms in the sample of Allicin.

The ratio of carbon in one molecule of Allicin is 6 C atoms: 1 molecule of Allicin.

Allicin sample: 1.558*10^(19) molecules C6H10OS2.

There are 9.35*10^(19) C atoms in the sample.