What wavelength (in nm) of light is emitted when an electron transitions from the n
= 8 to the n = 2 state?

Answers

Answer 1

The wavelength in nm of light emitted when an electron transitions from n = 8 to n = 2 state is 38900nm.

It is given that the electron transition took place from n = 8 to n = 2. To find the wavelength, the following formula is to be used:

1/λ = R(1/n²₁ - 1/n²₂)

Here, n₁ = 2 n₂ = 8 and R = 109677. Therefore,

1/λ = 109677(1/2² - 1/8²)

1/λ = 109677(1/4 - 1/64)

1/λ = 109677((16-1)/64)

1/λ = 109677((15)/64)

1/λ = 0.234375 x 109677

1/λ = 25,705.5469

λ = 1/25,705.5469

λ = 3.89 x 10⁻⁵cm

λ = 38900 x 10⁻⁹m

λ = 38900nm

Therefore, the wavelength in nm from n=8 to n=2 transition is 38900nm

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Related Questions

does lead melt in atoms or molecules

Answers

Answer:

Atoms

Explanation:

Answer:

atoms

Explanation:

its right, trust

2.65 moles of an ideal gas at 36.9oC and 40,205Pa occupy 54.7mL. Additional gas is added to this container such that the temperature and pressure change to 113.7oC and 131,874Pa, with the volume remaining the same. How many moles of this gas were added?


Answers

The moles of gas added could not be determined because of an apparent error in the data provided for the volume of the container.

What is the number of moles of gas in the container?

The moles of gas in the container is calculated from the ideal gas equation as follows;

PV = nRTn = PV / RT

Data given:

P = 131,874 Pa or 131.874 kPa

V = 54.7 mL = 0.0547 L

T = 113.7 °C or (113.7 + 273) K

T = 386.7 K

R, molar gas constant  = 8.314 L⋅kPa.K/mol

n = (131.874 * 0.0547 L) / (8.314 * 386.7 )

n = 0.000224 moles

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a gas has a volume of 103.4 L at 27.5 atm. what will it’s volume be if the pressure is changed to 69.3 atm

Answers

In this question, we have a gas presenting volume and pressure, and the gas law that we can use to calculate it is Boyle's gas Law, which perfectly correlates both pressure and volume, the formula is:

P1V1 = P2V2

We have:

P1 = 27.5 atm

V1 = 103.4 L

P2 = 69.3 atm

V2 = ?

Now we add these values into the formula:

27.5 * 103.4 = 69.3 * V2

V2 = 41.0 L

8. Based on the Law of Conservation of Matter: At the start of the reaction 20g of
one material and some amount of another material were reacted and produced
30g of solid and 70g of a gas. What is the other amount of reactant used?
a. 20
b. 60g
c. 80g
d. 100g

Answers

Answer:

80g

Explanation:

The law of conservation of matter states that matter cannot be created nor destroyed. Basically, whatever mass you have at the beginning of a reaction, should be the same as at the end of the reaction on the product side.

Since here it lets you know that a total of 100g (30g + 70g) were produced on the product side, that means that we started off with 100g in our reactant side.

We have given that one material is 20g on our reactant side but we need the mass of the other. To find the mass of the other material, simply subtract 20g from the total mass created on the product side.

100g - 20g = 80g

The 80g would be the missing amount from the reactant side that isn't stated.

Consider the following reaction in the forward direction. Identify the base:
CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻

Answers

If we consider the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻ in the forward direction, the base in the reaction is CH₃O⁻

A compound can be acidic, basic or neutral in nature. Basicity of the compound is determined when it either releases hydroxide ions, donates electrons or else accepts the protons from a compound.

In the reaction CH₃O⁻ + H₂O ⇌ CH₃OH + OH⁻:

CH₃O⁻ accepts proton or [H+] ion to become CH₃OH. Thus, CH₃O⁻ is the base in the reaction

H₂O donate [H+] ion or proton, therefore H2O change into OH-. Thus, H₂O is an acid in the reaction.

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Calculate the total energy of 9.4 * 10^16 photons of visible light with a wavelength of 4.3 * 10^7 m.

Answers

According to the Planck's equation which is E= hc/λ the total energy  of 9.4×10¹⁶ photons is 43.446×10[tex]^-17[/tex] J.

What is Planck's equation?

Max Planck  discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta  and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.

The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.

Substituting the given value of wavelength of  one photon  in the above formula containing wavelength,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.3×10⁷=4.622×10[tex]^-33[/tex] J.

Now, for energy of 9.4×10¹⁶ photons =4.622×10[tex]^-33[/tex]×9.4×10¹⁶=43.446×10[tex]^-17[/tex] J.

Thus, the energy of 9.4×10¹⁶ photons is 43.446×10[tex]-17[/tex] J.

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An experiment begins
with 87.5g of
potassium and 13.2g of
chlorine. What is the
experiment mass of
the product?

Answers

The experiment mass of the product is 28.1g

What is mass ?
Mass
is a physical body's total amount of matter. It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.

The kilogramme is the primary mass unit in the SI (kg). Although weight is frequently measured using a spring scale rather than a balancing scale and compared directly with known masses, mass is not the same as weight in physics.

2K + Cl2 =====> 2KCl

70g Cl2 produces 2(39+35.5) = 149 g KCl

13.2g Cl2 produces 28.1g KCl

the experiment mass of the product is 28.1g

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What element has the most similar property as fluorine

Answers

Answer:

Chlorine and Bromine are also halogens so they are similar to fluorine

. At standard pressure, what state of matter is xenon at -111 °C?
A) solid
B) liquid
C) gas
D) can be both solid and liquid
E) can be both liquid and gas

Answers

At standard pressure, C) gas state of matter is xenon at -111 °C

What is the state of matter of xenon?

Xenon is an extremely uncommon, odourless, colourless, tasteless, chemically inert gas. It was thought to be absolutely innocuous until Neil Bartlett published the synthesis of xenon haxafluoroplatinate in 1962. When stimulated by an electrical discharge, xenon generates blue light in a gas-filled tube.

Noble gases, which are most commonly encountered as monatomic gases, have entirely filled outer electron shells and hence have little desire to react with other elements, resulting in relatively few compounds with other elements.

In its +6 oxidation state, xenon trioxide is an unstable molecule. It is a highly potent oxidising agent that progressively liberates oxygen from water when exposed to sunshine. When it comes into touch with organic materials, it becomes highly explosive.

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Convert 8.75X10^-4 to regular number

Answers

To convert the given number to regular notation, we have to move the decimal dot as many times as indicated by the exponent of 10. In this case, that exponent is -4, so we have to move the decimal dot 4 times to the left:

It means that the answer is 0.000875.

An intravenous a solution to replace potassium loss contains 35mEq/L each of K+and CL- . How many moles of CL- are in 1.8 L of the solution

Answers

The moles of Cl⁻ ions present in 1.8 L of the intravenous solution is 0.063 moles.

What are the moles of Cl⁻ ions in the intravenous solution?

The moles of Cl⁻ ions in the intravenous solution are calculated using the conversion factor between mEq/L to mmoles

The conversion between milliequivalents per Liter and millimoles per Liter is:

1 Millimole per Liter = 1 Milliequivalents per Liter.

Hence 35 mEq/L = 35 mmol/L

The mmoles of Cl⁻ ions in 1.8 liters of the intravenous solution will be:

moles of Cl⁻ ions = 35 mmol/L * 1.8 L

moles of Cl⁻ions = 63 mmoles

Converting to moles by dividing by 1000:

moles of Cl⁻ ions = 63 / 1000

moles of Cl⁻ ions = 0.063 moles.

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A single electron in an orbital has quantum numbers n = 2, ℓ = 0, mℓ = 0, ms = ½. what are the quantum numbers for the next electron added to this atom?

Answers

The quantum numbers for the next electron added to this atom are  n = 2, ℓ = 0, mℓ = 0, ms = -½

The set of numbers used to explain the placement and strength of the electron in an atom are called quantum numbers. There are 4 quantum numbers, particularly, main, azimuthal, magnetic, and spin quantum numbers. The values of the conserved portions of a quantum gadget are given by quantum numbers.

The price of n tiers from 1 to the shell of the outermost electron of that atom. The important quantum variety may be determined by way of searching the period (numbered row) of the element on the periodic table. The principal quantum numbers of electrons inside the S-block and P-block are similar to the period range.

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D
A student mixes a tablespoon of powdered lemonade into 8 ounces of
water. She weighs the powdered lemonade and the water separately.
After mixing, the student finds the weight of the combined mixture.
Which of the following will the student most likely observe about the
weight of the mixture?
A. The weight of the mixture will be less than the combined weight
of the powdered lemonade and the water.
B. The weight of the mixture will be the same as the combined
weight of the powdered lemonade and the water.
. C.The weight of the mixture will be more than the combined
weight of the powdered lemonade and the water.
. D. The weight of the mixture will be the average of the weight of
the powdered lemonade and the weight of the water.

Answers

The weight of the mixture will be the same as the combined

weight of the powdered lemonade and the water.

What is a mixture?

The term mixture has to do with the combination of two or more substances that are not chemically combined together. We can see that due to the fact that substances that can be found in a mixture are not chemically combined together, then they can be separated by the means of physical methods.

We have to also bear in mind that mass can not be created nor destroyed but can be converted from one form to another. This implies that the total mass of the mixture must be the same as the sum of the masses of the individual components that are found in the mixture as this is in obedience to the law of the conservation of mass that have been detailed above in this answer.

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Your spaceship has docked at a space station above Mars. The temperature inside the space station is a carefully controlled 24 ∘C at a pressure of 745 mmHg . A balloon with a volume of 443 mL drifts into the airlock where the temperature is − 95 ∘C and the pressure is 0.115 atm . What is the final volume, in milliliters, of the balloon if n does not change and the balloon is very elastic?

Answers

Answer: the final volume of the balloon is 2.26 x 10^3 mL

Explanation:

The question requires us to determine the new volume of a balloon, given the initial and final conditions.

The following information was provided by the question:

initial temperature = T1 = 24 °C = 297.15 K

initial volume = V1 = 443 mL

initial pressure = P1 = 745 mmHg = 0.980 atm

final temperature = T2 = -95 °C = 178.15 K

final pressure = P2 = 0.115 atm

To solve this problem, we'll need to apply the equation of ideal gases to calculate the number of moles of gas in the balloon, and then use this value and the final temperature and pressure provided to determine the final volume,

The equation of ideal gases can be written as:

[tex]PV=nRT[/tex]

And we can rearrange it to calculate the number of moles:

[tex]PV=nRT\rightarrow n=\frac{PV}{RT}[/tex]

Applying the values provided by the question:

[tex]n=\frac{(0.980atm)\times(443mL)}{R\times(297.15K)}=\frac{1.46}{R}(\frac{atm\times mL}{K})[/tex]

Now, we can rearrange the equation of ideal gases to calculate the volume:

[tex]PV=nRT\rightarrow V=\frac{nRT}{P}[/tex]

And, applying the values provided and the number of moles as calculated:

[tex]V=\frac{(\frac{1.46}{R}atm.mL.K^{-1})\times R\times(178.15K)}{0.115atm}=2.26\times10^3mL[/tex]

Therefore, the final volume of the balloon is 2.26 x 10^3 mL.

Propane (C3H8) is a component of natural gas and is used in domestic cooking and heating. It burns according to the following reaction:

C3H8 + O2 → CO2 + H2O

a. Balance the equation representing the combustion of propane in air.
b. How many grams of carbon dioxide can be produced by burning 20.0 pounds of propane, the typical size of a BBG grill propane tank?
Assume that oxygen is the excess reagent in this reaction.

Answers

A. The balanced equation for the reaction is given as

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

B. The mass (in grams) of carbon dioxide that can be produced by burning 20.0 pounds of propane is 27216.49 g

A. Balance equation

The balanced equation for the combustion of propane is:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

B. How to determin the mass (in grams) of CO₂ produced

The mass (in grams) of CO₂ produced from the reaction can be obtained as follow:

Molar mass of C₃H₈ = (12 × 3) +(8 × 1) = 44 g/molMass of C₃H₈ from the balanced equation = 44 × 1 = 44 g = 44 / 453.592 = 0.097 poundMolar mass of CO₂ = 12 + (16 × 2) = 44 g/molMass of CO₂ from the balanced equation = 3 × 44 = 132 g

From the balanced equation above,

0.097 pound of C₃H₈ reacted to produce 132 g of CO₂

Therefore,

20 pound of C₃H₈ will react to produce = (20 × 132) / 0.097 = 27216.49 g of CO₂

Thus, the mass of CO₂ produced is 27216.49 g

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The chemical equation for the combustion of ethanol is as follows:C2HyOH + 302 - 2002 + 3H20

Answers

Answer:

5998kJ

Explanations:

Given the reaction between ethanol and oxygen expressed as:

[tex]C_2H_5OH+3O_2\rightarrow2CO_2+3H_2O[/tex]

For the product

We have 2 moles of CO2 and 3 moles of water. The total bond energy in the product is expressed as:

[tex]\begin{gathered} \triangle H_p=2(2C=O)+3(2O-H) \\ \triangle H_p=4(799)+6(467) \\ \triangle H_p=3196+2802 \\ \triangle H_p=5998kJ \end{gathered}[/tex]

Hence the total energy transferred to build all the bond energy in the product is 5998kJ

In order to both shift the equilibrium and increase the amount of NH3, we should

Answers

Answer:

D. 2 and 3 only.

Explanation:

First let's remember the Le Chatelier's Principle: Le Chatelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish equilibrium.

Let's see the reaction:

[tex]N_2+3H_2\leftrightarrows2NH_3,\text{ }\Delta H=-92\text{ kJ.}[/tex]

You can note that this reaction is exothermic. If we want the equilibrium to move to the left, we have to increase the temperature. In this case, we don't want that because we want to increase the concentration of NH3 and this means that the equilibrium goes to the right, so we have to decrease the temperature.

In the case of pressure, if we want to reach the equilibrium to the right, where is NH3, we have to increase the pressure because the pressure will move in such a way as to decrease the pressure again.

The answer would be D. 2 and 3 only.

In a 250 mL sealed container at 150℃, 0.50 mol of both iodine gas I2(g) and bromine gas, Br2(g) are mixed and allowed to react until they form an equilibrium with iodine monobromide gas IBr(g). The equilibrium constant for this reaction is 1.2 x 102. What are the equilibrium concentrations for iodine gas and bromine gas? I2(g) + Br2(g) ↔ 2IBr(g)

Answers

answer and explanation

now that we have the x value we can find the equilbrium concentratoins of tehegases

for Iodine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

for Bromine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

the concentration of the two gases is 0.14M

Which statement describes the hydrogen bonds in an ethanol molecule? (image attached)thank you :)

Answers

Answer

Only the hydrogen atom attached to the oxygen atom is capable of forming hydrogen bonds. A dipole does not form between the hydrogen and the carbon atoms.

Explanation

The description of the hydrogen bonds in an ethanol molecule is that hydrogen bonding can occur between ethanol molecules, although not as effectively as in water. The hydrogen bonding is limited by the fact that there is only one hydrogen in each ethanol molecule with a sufficient δ+ charge.

Therefore only the hydrogen atom attached to the oxygen atom is capable of forming hydrogen bonds. A dipole does not form between the hydrogen and the carbon atoms.

The second option is the correct answer.

Two atoms with atomic numbers 12 and 17 would

bond to form an ionic compound
bond to form a covalent compound
bond to form a metallic lattice
not bond with each other

Answers

Answer:

bond to form a covalent bond

Explanation:

a covalent bond is formed when two atoms share electron pairs.

explain absolute entropies and it's determination in terms of heat capacity​

Answers

The total entropy that a pure material would accumulate upon warming from absolute zero (where S=0) to the specific temperature is the absolute entropy of that substance at that temperature.

What is entropy?

One of the key ideas that students studying physics and chemistry need to grasp with clarity is entropy. More importantly, entropy has multiple definitions and can be used in a variety of contexts, including the thermodynamic stage, cosmology, and even economics. Entropy is a notion that mostly discusses the spontaneous changes that take place in commonplace phenomena or the universe's propensity for chaos.

Determination in terms of heat capacity​

The third rule of thermodynamics has two significant ramifications: it establishes a constant reference point that enables us to measure the absolute entropy of any substance at any temperature, and it specifies the sign of the entropy of any substance at temperatures above absolute zero as positive. We look at two different approaches to calculating S for a reaction or a physical change in this section.

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A gas occupies a constant volume at 35.0 celsius and 97 kPa. What is the pressure of the gas when the temperature is increased to 75 celsius?

Answers

For this question we are going to use Gay-Lussac's Law, which is an experimental gas law that shows the relationship between temperature and pressure in a gas. The formula is:

P1/T1 = P2/T2

We have:

P1 = 97 kPa

T1 = 308 K, we need to use Kelvin

P2 = ?

T2 = 348 K

Now we add these values into the formula:

97/308 = P2/348

0.315 = P2/348

P2 = 109.6 kPa, this will be new pressure

Parts of a neuron include:
A. dendrites.
B. hormones.
C. cortexes.
D. collosums.

Answers

The parts of the neuron include (A) dendrites.

What are dendrites?Dendrites are appendages that are designed to receive communications from other cells. They take the shape of projections with a tree-like structure that are triggered by other neurons and carry the electrochemical charge to the cell body. These occupy a large surface area of a neuron.These little appendages convey electrical stimulation to the soma and take in information from neighboring neurons. Synapses are also found on dendrites.Dendrites are also called the "arms" of a neuron.

As it is given in the description, Synapses are also found on dendrites.

Therefore, the parts of the neuron include (A) dendrites.

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Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure. The half-life of
Co-60 is 5, 272 years. How much of a 2.000 mg sample will remain after 21, 088 years? You must show your work to receive
credit.
. Show the equation needed
b. Show a picture of you solving for the unknown.
c. Show the final answer

Answers

Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure the half-life of Co-60 is 5, 272 years 2.000 mg sample will remain after 21, 088 years is 0.0625 gm left

Radiation therapy is the cancer treatment that uses high doses of radiation to kill cancer cell and shrink tumor

Here given data is Co-60 is 5, 272 years and we have to find the number of half lives in 21, 088 years = ?

21, 088/5, 272 = 4 half lives

(1/2)⁵   = 1/32 nd  of the original will be left

1/32×2.000mg = 0.0625 gm left

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A patient receives 100 mL of 25% (m/v) mannitol solution every hour.How many grams of mannitol are given in 1 hour?Express your answer using two significant figures.

Answers

Explanation:

A patient receives 100 mL of a 25 % m/v mannitol solution every hour. We have to find the mass in grams of mannitol that the pacient is receiving in 1 hour. We can use the formula of the mass/volume percent to find the answer to our problem.

% m/v = mass of solute in g/(volume of solution in mL) * 100 %

We know the concentration of the solution and we have the volume of solution in mL, so we can solve the formula for the mass of solute and get the answer to the problem.

25 % m/v = mass of solute in g/100 mL * 100 %

mass of solute in g = 25 * 100/100 g

mass of solute in g = 25 g

Answer: In 1 hour the patient receives 25 g of mannitol.

Calculate the hardness of a water sample which is 35.1 ppm Mg2+ and 65.8 ppm Ca2+.

Answers

The hardness of water sample with 35.1 ppm Mg²⁺ and 65.8 ppm Ca²⁺ is 6.215 ppm is 100.9 ppm

Hardness of water is a parameter which is defined by the amount of dissolved minerals in the water like calcium and magnesium. Thus, hard water would have high amount of dissolved minerals in the water. They are sweeter in taste and are good for bones and teeth because of the mineral content

Total hardness of water = Degree of hardness of Mg ²⁺ + Degree of hardness of Ca ²⁺

Degree of hardness Mg ²⁺ = 35.1 ppm

Degree of hardness of Ca ²⁺ = 65.8 ppm

Total hardness = 35.1 + 65.8 = 100.9 ppm

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A sheet of gold weighing 10.7 g and at a temperature of 19.8°C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3°C. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings.

Answers

A sheet of gold weighing 10.7 g and at a temperature of 19.8 °C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3 °C. the final temperature of the combined metals is 48.87 °C.

given that :

weight of gold , m= 10.7 g

temperature, T = 19.8 °C

weight of iron , m = 18.7 g

temperature, T = 53.3 °C

final temperature t = ?

specific heat for gold , c = 0.12 J/ g °C

specific heat for iron , c =  0.45 J/ g °C

now, using the specific heat formula we get :

( mc ΔT ) + ( mc ΔT ) = 0

( 10.7 × 0.12 ×( t - 19.8 )  +  ( 18.7 × 0.45 × (t - 53.3 ) = 0

(1.28 t - 25.4) + ( 8.41 t - 448.2 ) = 0

9.69 t = 473.6

t = 48.87 °C

Thus, A sheet of gold weighing 10.7 g and at a temperature of 19.8 °C is placed flat on a sheet of iron weighing 18.7 g and at a temperature of 53.3 °C. the final temperature of the combined metals is 48.87 °C.

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How many liters of oxygen gas are required to burn 6.82 L of acetylene (C2H2) at STP?

Answers

17.05 L of O₂ are needed to react with 6.82 L of acetylene gas C₂H₂ at STP.

The reaction to the given question is :

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

From the equation we see

2 moles of C₂H₂ react with 5 moles of O₂

According to the equation,

        2 liters of Acetylene reacts with  =  5 liters of O₂

So,

             6.82 L Acetylene will produce  =  X L of O₂

Solving for X,

                         X  =  ( 6.82 L × 5 L ) ÷ 2 L

                         X  =  17.05 L of O₂

Thus, 17.05 L of O₂ is needed to react with 6.82 L of acetylene gas C₂H₂.

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How many moles are in 53.99 mg chromium?

Answers

There are 0.001038 moles in 53.99 mg of Chromium.

Follow these steps to write the balanced chemical equation for the reaction between nitric acid and iron (III)hydroxide.1. Start by writing the proper names of the products below (separated by a + sign).Nitric acid +Iron (III) hydroxide I2. Next, write the full, balanced molecular equation with the correct chemical formulas, includingcoefficients.3. Finally, write the net ionic equation for this reaction below, including ionic charges.

Answers

[tex]\begin{gathered} Fe(OH)_{3(s)}+3HNO_{3(aq)}\rightarrow Fe(NO_3)_{3(aq)}+3H_2O_{(l)} \\ Complete\text{ }Ionic\text{ }Equation:Fe(OH)_3+3H^++3NO_3^-\rightarrow Fe_^{3+}+3NO_3^-+3H_2O \\ Net\text{ }Ionic\text{ }Equation:Fe(OH)_{3(aq)}+3H_{(aq)}^+\rightarrow Fe_{(aq)}^{3+}+3H_2O_{(l)} \end{gathered}[/tex]

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