Which equation is true when x=10 but not when x= – 10? Select all that apply.

Answers

Answer 1

Applying power rules, the equations that is true when x = 10 but false when x = -10 is given as follows:

x³ = 10000.

Exponents of 10

The behavior of the exponents of 10 is different for even and for odd exponents, as follows:

Even exponents generate even functions, that is, 10^n = (-10)^n if the exponent n is even.Odd exponents generate odd functions, that is 10^n = -(-10)^n if the exponent is odd.

In this problem, we have two exponents, as follows:

Exponent 2 is even.Exponent 3 is odd.

We want different results for the power when x = 10 and when x = -10, hence the correct option will involve the odd exponent 3.

The third power of 10 is calculated as follows:

10³ = 10 x 10 x 10 = 100 x 10 = 1000.

Hence the equation that is true for x = 10 and false for x = -10 is:

x³ = 10000.

As when x = -10, the result is:

(-10)³ = (-10) x (-10) x (-10) = 100 x (-10) = -1000.

Missing information

The options are given by the image at the end of the answer.

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Which Equation Is True When X=10 But Not When X= 10? Select All That Apply.

Related Questions

Fun times Amusement Park Charges a $7 admission fee plus $1.75 per ride. What is the equation, in intercept form for calculating the total cost, C, of going to the park and riding r rides?1. C = 1.75 + 7r2. C = 1.75r3. C = 7r4. C = 7 + 1.75r

Answers

The general form of an equation in intercetp form is:

[tex]y=mx+b[/tex]

Where m is the change of y in function of x and b is the value of b when x is 0

In this situation you have:

y=C

x=r

m= 1.75 ( C increase 1.75 each r)

b= 7 (When there is not ride r=0 the admission fee is 7)

Then, you have the equation:[tex]C=1.75r+7[/tex]or C = 7 + 1.75r

Given v = 60sinθ, what is the instantaneous voltage when θ = 30⁰?Question 11 options:6034.643051.96

Answers

Answer:

Explanations:

Given the expression for the instantaneous voltage expressed as:

[tex]v=60\sin \theta[/tex]

Given the following parameter:

θ = 30⁰

Substitute the given parameter into the formula to have:

[tex]\begin{gathered} v=60\sin 30^0 \\ v=60(0.5) \\ v=30 \end{gathered}[/tex]

Therefore the instantaneous voltage when θ = 30⁰ is 30.

Write a linear equation to represent the given problem and then solve the problem.

The perimeter of a rectangle is 150 cm. The length is 15 cm greater than the width. Find the dimensions.

Perimeter = 2 x Length + 2 x Width

Answers

w=L+15

p=(L+w)

150cm=L+L+15

150cm=2L+15

2L=150cm-15

2L=135cm

2L÷2=135cm÷2

L=67.5

w=67.5+15

w=82.5

Mason went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 45 grams of sugar and each bottle of juice has 15 grams of sugar. Mason purchased a total of 11 bottles of juice and soda which collectively contain 285 grams of sugar. Write a system of equations that could be used to determine the number of bottles of soda purchased and the number of bottles of juice purchased. Define the variables that you use to write the system

Answers

The number of soda bottles = 4

The number of sugar bottles = 7

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Weight of each bottle of soda = 45 grams

Weight of each bottle of sugar = 15 grams

Total weight of sugar and soda = 285 grams

Let the number of soda bottle = x

And, The number of sugar bottle = y

Since, Total number of bottles = 11

So, We can formulate;

⇒ x + y = 11 .... (i)

And, Weight of each bottle of soda = 45 grams

Weight of each bottle of sugar = 15 grams

Total weight of sugar and soda = 285 grams

So, We can formulate;

⇒ 45x + 15y = 285 ... (ii)

Multiply by 15 in equation (i) and subtract from (ii), we get;

⇒ 45x + 15y - 15x - 15y = 285 - 165

⇒ 30x = 120

Divide by 30;

⇒ x = 4

Hence, x + y = 11

4 + y = 11

y = 11 - 4

y = 7

So, The number of soda bottles = 4

The number of sugar bottles = 7.

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What is the slope that passes through these points?

(0, -4) and (-5, -5)

Answers

Answer: m=1/5

Step-by-step explanation:

Evaluate cos 150° without using a calculator.Ο Α.√32B. 2O C. -1/2OD. -32

Answers

Answer:

Explanation:

Note that:

[tex]\begin{gathered} cos(A+B)=cosAcosB-sinAsinB \\ cos(150^0)=cos(90+60) \end{gathered}[/tex]

Applying the addition formula given above to cos 150:

[tex]\begin{gathered} cos(150)=cos(90)cos(60)-sin(90)sin(60) \\ \\ cos(150)=0(\frac{1}{2})-1(\frac{\sqrt{3}}{2}) \\ \\ cos(150)=0-\frac{\sqrt{3}}{2} \\ \\ cos \end{gathered}[/tex]

For the function f(x)= x^2+4x-1, what is the range of f (x) for the domain {-2,0,1}?

Answers

The range of the given function is {-5,-1,4} which is the B option.

Given function:-

[tex]f(x) = x^2+4x-1[/tex]

Domain = {-2,0,1}

We have to find the range of the given function for the given domain.

Putting x = -2 in the given function, we get,

[tex]f(-2) = (-2)^2+4(-2)-1[/tex]

f(-2) = 4 - 8 - 1 = -5

Putting x = 0 in the given function, we get,

[tex]f(0) = (0)^2+4(0)-1[/tex]

f(0) = 0 + 0 -1 = -1

Putting x = 1 in the given function, we get,

[tex]f(1) = (1)^2+4(1)-1[/tex]

f(1) = 1 + 4 - 1 = 4

Hence, the range of the given function is {-5,-1,4}.

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Find the slope of the line.
slope =
11
rise
run
5
11
40
30
20
10
O
2
4
6
8
G
G

Answers

to get the slope of any straight line, we simply need two points off of it, let's use the ones from the picture below.

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{20}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{20}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{0}}} \implies \cfrac{ 20 }{ 5 } \implies \text{\LARGE 4}[/tex]

For a particular rectangle, twice the width is 4 meters shorter than the length. The area of the rectangle is 126 square meters. What is the perimeter of the rectangle? ? meters

Answers

Let l be the length of the rectangle and w its width.

Then its area is given by:

a = l*w

Its perimeter is given by:

p = 2l + 2w

We also know that, for this specific triangle, we have:

2w = l - 4

l = 2w + 4

a = 126 m²

Applying this result in the area formula, we have:

w*l = 126

w(2w + 4) = 126

2w² +4w = 126

2w + 4w - 126 = 0

Therefore, w = 7 m and l = 2*7 + 4 = 10 m

Then, the perimeter is given by:

p = 2*18 + 2*7 = 36 + 14 = 50 m

Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0

Answers

The two equations that are true when x = -2 and x = 2 are x^2 - 4 = 0 and 4x^2 = 16.

We have given x = 2 and x = -2

Substitute the values in the given equations

Equation 1

x^2 - 4 = 0

Substitute x = 2 in LHS, we get

2^2-4 = 4 - 4 = 0 = RHS