which equation represents the function modeled by the graph? (picture of graph below)
Answers
Answer:
The parent function of the graph is given below as
[tex]y=\sqrt[3]{x}[/tex]The parent function has undergone transformation
Hence,
Using a graphing calculator, we will have the graph be
Hence,
The final answer is
[tex]\Rightarrow f(x)=\sqrt[3]{4x+2}[/tex]The FIRST OPTION is the right answer
Related Questions
How do I graph a line with a equation in slope intercept form?An example is y=-3x+3, how do I graph this?
Answers
we have
y=-3x+3
to graph a line we need at least two points
so
Find out the intercepts
y-intercept (value of y when the value of x is zero)
For x=0
y=-3(0)+3
y=3
y-intercept is (0,3)
x-intercept (value of x when the value of y is zero)
For y=0
0=-3x+3
3x=3
x=1
x-intercept is (1,0)
therefore
Plot the points (0,3) and (1,0)
and join them to graph the line
see the attached figure to better understand the problem
what is the slope for (0,-3),(-3,2)
Answers
Given the general rule for the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]We have the following in this case:
[tex]\begin{gathered} (x_1,y_1)=(0,-3) \\ (x_2,y_2)=(-3,2) \\ \Rightarrow m=\frac{2-(-3)}{-3-0}=\frac{2+3}{-3}=-\frac{5}{3} \\ m=-\frac{5}{3} \end{gathered}[/tex]therefore, the slope is m=-5/3
I need help on this and no this isn't a quiz
Answers
Concept:
Parallel planes are planes in the same three-dimensional space that never meet.
Parallel Lines or parallel Segments are always the same distance apart, they will never meet.
skew lines are two lines that do not intersect and are not parallel.
Question: Name a plane parallel to plane PQR:
Answer: plane JKL
Question: Name a segment parallel to segment KP:
Answer: segment OJ
Question: Name a segment that is skew to OJ
Answer: segment SR
Use the given information to answer the questions and interpret key features. Use any method of graphing or solving.
Answers
A quadratic function describes the relationship between the number of products x and the overall profits for a company.
The roots of the quadratic function are given as x = 0 and x = 28. We also know the graph's vertex is located at (14, -40).
The quadratic equation can be written in terms of its roots x1 and x2 as:
[tex]f(x)=a(x-x_1)(x-x_2)[/tex]Substituting the given values:
[tex]\begin{gathered} f(x)=a(x-0)(x-28) \\ \\ f(x)=ax(x-28) \end{gathered}[/tex]We can find the value of a by plugging in the coordinates of the vertex:
[tex]f(14)=a\cdot14(14-28)=-40[/tex]Solving for a:
[tex]a=\frac{-40}{-196}=\frac{10}{49}[/tex]Substituting into the equation:
[tex]f(x)=\frac{10}{49}x(x-28)[/tex]The graph of the function is given below:
The company actually loses money on their first few products, but once they hit 28 items, they break even again.
The worst-case scenario is that they produce 14 items, as they will have a profit of -40 dollars. The first root tells us the profit will be 0 when 0 products are sold.
A French restaurant used 808,870 ounces of cream last year. This year, due to a menu update, it used 90% less. How much cream did the restaurant use this year?
Answers
Answer:
80,887
Step-by-step explanation:
808,870 x (1 - 0.9)
808,870 x 0.1
80,887
is A square with a perimeter of 38 units is graphed on a coordinate grid. The square dilated by a scale factor of 0.8 with the origin as the center of dilation. If (x,y) represents the location of any point on the original square, which ordered pair represents the coordinates of the corresponding point on the resulting square? 0 (0.8x, 0.8y) 0 (x + 38, y + 38) O (x + 0.8, y + 0.8) O (38x, 38y)
Answers
Answer:
(0.8x, 0.8y)
Step-by-step explanation:
in a dilation with the origin as the center all point coordinates are multiplied by the scaling factor.
Is (x + 3) a factor of 7x4 + 25x³ + 13x² - 2x - 23?
Answers
According to the factor theorem, if "a" is any real integer and "f(x)" is a polynomial of degree n larger than or equal to 1, then (x - a) is a factor of f(x) if f(a) = 0. Finding the polynomials' n roots and factoring them are two of their principal applications.
What is the remainder and factor theorem's formula?When p(x) is divided by xc, the result is p if p(x) is a polynomial of degree 1 or higher and c is a real number (c). For some polynomial q, p(x)=(xc)q(x) if xc is a factor of polynomial p. The factor theorem in algebra connects a polynomial's components and zeros. The polynomial remainder theorem has a specific instance in this situation. According to the factor theorem, f(x) has a factor if and only if f=0.The remainder will be 0 if the polynomial (x h) is a factor. In contrast, (x h) is a factor if the remainder is zero.The factor theorem is mostly used to factor polynomials and determine their n roots. Factoring is helpful in real life for comparing costs, splitting any amount into equal parts, exchanging money, and comprehending time.To learn more about Factor theorem refer to:
https://brainly.com/question/24437791
#SPJ13
Fill in each blanks so that the resulting statement is true
Answers
The next step is to subtract -21x from 9x, which obtains 30x.
Then bring down -2 and form the new dividend 30x - 2
Explanation:Given:
[tex]\frac{9x^2+9x\text{ - 2}}{3x\text{ - 7}}[/tex]To determine the next step in the division, we need to solve the long division:
From our calculation, we subtract -21x from +9x and this gives 30x. We bring down -2 to combine with 30x. The result is 30x - 2
The next step is to subtract -21x from 9x, which obtains 30x.
Then bring down -2 and form the new dividend 30x - 2
help meeeeeeeeee pleaseee !!!!!
Answers
The composition of the two functions evaluated in x = 2 is:
(f o g)(2) = 33
How to find the composition?Here we have the next two functions:
f(x) = x² - 3x + 5
g(x) = -2x
And we want to find the composition:
(f o g)(2) = f( g(2))
So we need to evaluate f(x) in g(2).
First, we need to evaluate g(x) in x = 2.
g(2) = -2*2 = -4
Then we have:
(f o g)(2) = f( g(2)) = f(-4)
f(-4) = (-4)² - 3*(-4) + 5 = 16 + 12 + 5 = 28 + 5 = 33
Learn more about compositions:
https://brainly.com/question/26373912
#SPJ1
Find the quantities indicated in the picture (Type an integer or decimal rounded to the nearest TENTH as needed.)
Answers
Remember that 3, 4 and 5 is a Pythagorean triple, since:
[tex]3^2+4^2=5^2[/tex]Since one side of the given right triangle has a length of 3 and the hypotenuse has a length of 5, then, the remaining leg b must have a length of 4.
Therefore:
[tex]b=4[/tex]The angles A and B can be found using trigonometric identities.
Remember that the sine of an angle equals the quotient of the lengths of the side opposite to it and the hypotenuse of the right triangle.
The side opposite to A has a length of 3 and the length of the side opposite to B is 4. Then:
[tex]\begin{gathered} \sin (A)=\frac{3}{5} \\ \sin (B)=\frac{4}{5} \end{gathered}[/tex]Use the inverse sine function to find A and B:
[tex]\begin{gathered} \Rightarrow A=\sin ^{-1}(\frac{3}{5})=36.86989765\ldotsº \\ \Rightarrow B=\sin ^{-1}(\frac{4}{5})=53.13010235\ldotsº \end{gathered}[/tex]Then, to the nearest tenth:
[tex]\begin{gathered} A=36.9º \\ B=53.1º \end{gathered}[/tex]Therefore, the answers are:
[tex]undefined[/tex]Solve the following system of equations by graphing3x+5y=10y=-x+4
Answers
ANSWER
The point of intersection of the two equations is (5, - 1)
The graph is
STEP BY STEP EXPLANATION
Step 1: The given equations are:
3x + 5y = 10
y= -x + 4
Step 2: Assume values for x in a table (example -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5) to determine the corresponding values for y for both equations
Step 3: Graph the equations and locate the intersection of the two equations
0. Taylor earned the following amount each day. One dollar on the first day Three dollars on the second day Nine dollars on the third day Twenty-seven dollars on the fourth day
Answers
Question:
Solution:
Answer:
[tex]f(t)=3^{(t-1)}[/tex]Step-by-step explanation:
one dollar of the first day = 3^0
three dollars on the second day = 3^1
nine dollars on the third day = 3^2
twenty-seven dollars on the fourth day = 3^3
Numbers increase 3 times a day, it is an exponential function, powers of 3
The function is going to be:
[tex]f(t)=3^{(t-1)}[/tex]match the system of equations with the solution set.hint: solve algebraically using substitution method.A. no solutionB. infinite solutionsC. (-8/3, 5)D. (2, 1)
Answers
We will solve all the systems by substitution method .
System 1.
By substituting the second equation into the first one, we get
[tex]x-3(\frac{1}{3}x-2)=6[/tex]which gives
[tex]\begin{gathered} x-x+6=6 \\ 6=6 \end{gathered}[/tex]this means that the given equations are the same. Then, the answer is B: infinite solutions.
System 2.
By substituting the first equation into the second one, we have
[tex]6x+3(-2x+3)=-5[/tex]which gives
[tex]\begin{gathered} 6x-6x+9=-5 \\ 9=-5 \end{gathered}[/tex]but this result is an absurd. This means that the equations represent parallel lines. Then, the answer is option A: no solution.
System 3.
By substituting the first equation into the second one, we obtain
[tex]-\frac{3}{2}x+1=-\frac{3}{4}x+3[/tex]by moving -3/4x to the left hand side and +1 to the right hand side, we get
[tex]-\frac{3}{2}x+\frac{3}{4}x=3-1[/tex]By combining similar terms, we have
[tex]-\frac{3}{4}x=2[/tex]this leads to
[tex]x=-\frac{4\times2}{3}[/tex]then, x is given by
[tex]x=-\frac{8}{3}[/tex]Now, we can substitute this result into the first equation and get
[tex]y=-\frac{3}{2}(-\frac{8}{3})+1[/tex]which leads to
[tex]\begin{gathered} y=4+1 \\ y=5 \end{gathered}[/tex]then, the answer is option C: (-8/3, 5)
System 4.
By substituting the second equation into the first one, we get
[tex]-5x+(2x-3)=-9[/tex]By combing similar terms, we have
[tex]\begin{gathered} -3x-3=-9 \\ -3x=-9+3 \\ -3x=-6 \\ x=\frac{-6}{-3} \\ x=2 \end{gathered}[/tex]By substituting this result into the second equation, we have
[tex]\begin{gathered} y=2(2)-3 \\ y=4-3 \\ y=1 \end{gathered}[/tex]then, the answer is option D
If 1 centimeter equals 3 ft what is the actual length of the 5cm side of the yard?
Answers
this is
[tex]\begin{gathered} \frac{1}{3}=\frac{5}{x} \\ 1\times x=3\times5 \\ x=15 \end{gathered}[/tex]answer: 15 ft
Kyzell is traveling 15 meters per second. Which expression could be used to convert this speed to kilometers per hour.
Answers
Given:
Kyzell is traveling 15 meters per second
we need to convert meters per second to kilometers per hours
As we know:
1 km = 1000 meters
So, 1 meters = 1/1000 kilometers
And, 1 Hour = 60 minutes = 3600 seconds
So, 1 seconds = 1/3600 Hours
So,
[tex]15\frac{meters}{\sec onds}=15\cdot\frac{1}{1000}\cdot3600\cdot\frac{kilometes}{\text{hours}}=54\frac{kilometrers}{hours}[/tex]So, the answer will be:
15 meters per second = 54 kilometers per hour
Two seamstresses sew 5 curtains in 3 hours. How many curtains will 12 seamstresses sew in the same time if the seamstresses all work at the same rate?
Answers
Answer:
30 curtains
Step-by-step explanation:
You have 6 times as many seamstresses so you will get 6 times as many curtains
6 * 5 = 30 curtains
Use inductive reasoning to find a pattern then make a reasonable conjecture for the next three items in the pattern p g q h r I
Answers
Consider the first, third, and fifth terms of the sequence: p,q,r; these are consecutive letters starting with p.
Similarly, as for the second, fourth, and sixth terms: g,h, i; these are consecutive letters starting with g.
Thus, the seventh term has to be the letter that follows r; this is, s.
Analogously, the eighth and ninth terms are
[tex]\begin{gathered} \text{ eighth}\to\text{letter that follows i}\to j \\ \text{ ninth}\to\text{ letter that follows s}\to t \end{gathered}[/tex]Thus, the missing terms are: s, j, and t.
3. Darren won Round 3 of the game. Sherri is wondering if she lost Round 3 by 5 points or by 25 points. Explain to Sherri how many points Darren won Round3 by and show the mathematics you used to justify your answer.4. Sherri and Darren actually played with a third player, their friend Eric. Unfortunately, Eric forgot to record the points he scored in each of the three roundsin the table.
Answers
Sherry lost the round 3 by 25 points
Explanation:Sherry's point in third round = -10
Darren's point in the third round = 15
To determine the number of points Sherry lost round 3 by, we will subtracct Sherry's point from Darren's point:
[tex]\begin{gathered} \text{Darren's point - Sherry's point} \\ =\text{ 15 - (-10)} \\ =\text{ 15 + 10} \\ =\text{ 25} \end{gathered}[/tex]Sherry lost round 3 by 25 points
Which of the following numbers is divisible by 6?
A. 342 543
B. 322 222
C. 415 642
D. 123 456
Answers
A. 342 543 is odd
B. 322 222 is even but the digits add to 13 which is not a multiple of 3
C. 415 642 is even but the digits add to 22 which is not a multiple of 3
D. 123 456 is even and the digits add to 21 so it is a multiple of 6
123 456 / 6 = 20 576 with no remainder
Add or subtract. Simplify. Change the answers to mixed numbers, if possible.
Answers
Answer:
[tex]\begin{gathered} \frac{1}{8} \\ \\ \text{LCD = 8} \end{gathered}[/tex]Explanation:
Here, we start by finding the lowest common denominator
From what we have, the lowest common denominator is the lowest common multiple of both denominators which is equal to 8
We divide the first denominator by this and multiply the result by its numerator. We take the same step for the second denominator
Mathematically, we have it that:
[tex]\frac{11-10}{8}\text{ = }\frac{1}{8}[/tex]hi i dont understand this question, can u do it step by step?
Answers
Problem #2
Given the diagram of the statement, we have:
From the diagram, we see that we have two triangles:
Triangle 1 or △ADP, with:
• angle ,θ,,
,• hypotenuse ,h = AP,,
,• adjacent cathetus, ac = AD = x cm.
,• opposite cathetus ,oc = DP,.
Triangle 2 or △OZP, with:
• angle θ,
,• hypotenuse, h = OP = 4 cm,,
,• adjacent cathetus, ac = ZP = AP/2,.
(a) △ADP: sides and area
Formula 1) From geometry, we know that for right triangles Pitagoras Theorem states:
[tex]h^2=ac^2+oc^2.[/tex]Where h is the hypotenuse, ac is the adjacent cathetus and oc is the opposite cathetus.
Formula 2) From trigonometry, we have the following trigonometric relation for right triangles:
[tex]\cos \theta=\frac{ac}{h}.[/tex]Where:
• θ is the angle,
,• h is the hypotenuse,
,• ac is the adjacent cathetus.
(1) Replacing the data of Triangle 1 in Formulas 1 and 2, we have:
[tex]\begin{gathered} AP^2=AD^2+DP^2\Rightarrow DP=\sqrt[]{AP^2-AD^2}=\sqrt[]{AP^2-x^2\cdot cm^2}\text{.} \\ \cos \theta=\frac{AD}{AP}=\frac{x\cdot cm}{AP}\text{.} \end{gathered}[/tex](2) Replacing the data of Triangle 2 in Formula 2, we have:
[tex]\cos \theta=\frac{ZP}{OP}=\frac{AP/2}{4cm}.[/tex](3) Equalling the right side of the equations with cos θ in (1) and (2), we get:
[tex]\frac{x\cdot cm}{AP}=\frac{AP/2}{4cm}.[/tex]Solving for AP², we get:
[tex]\begin{gathered} x\cdot cm=\frac{AP^2}{8cm}, \\ AP^2=8x\cdot cm^2\text{.} \end{gathered}[/tex](4) Replacing the expression of AP² in the equation for DP in (1), we have the equation for side DP in terms of x:
[tex]DP^{}=\sqrt[]{8x\cdot cm^2-x^2\cdot cm^2}=\sqrt[]{x\cdot(8-x)}\cdot cm\text{.}[/tex](ii) The area of a triangle is given by:
[tex]S=\frac{1}{2}\cdot base\cdot height.[/tex]In the case of triangle △ADP, we have:
• base = DP,
,• height = AD.
Replacing the values of DP and AD in the formula for S, we get:
[tex]S=\frac{1}{2}\cdot DP\cdot AD=\frac{1}{2}\cdot(\sqrt[]{x\cdot(8-x)}\cdot cm)\cdot(x\cdot cm)=\frac{x}{2}\cdot\sqrt[]{x\cdot(8-x)}\cdot cm^2.[/tex](b) Maximum value of S
We must find the maximum value of S in terms of x. To do that, we compute the first derivative of S(x):
[tex]\begin{gathered} S^{\prime}(x)=\frac{dS}{dx}=\frac{1}{2}\cdot\sqrt[]{x\cdot(8-x)}\cdot cm^2+\frac{x}{2}\cdot\frac{1}{2}\cdot\frac{8-2x}{\sqrt{x\cdot(8-x)}}\cdot cm^2 \\ =\frac{1}{2}\cdot\sqrt[]{x\cdot(8-x)}\cdot cm^2+\frac{x}{2}\cdot\frac{(4-x^{})}{\cdot\sqrt[]{x\cdot(8-x)}}\cdot cm^2 \\ =\frac{1}{2}\cdot\frac{x\cdot(8-x)+x\cdot(4-x)}{\sqrt[]{x\cdot(8-x)}}\cdot cm^2 \\ =\frac{x\cdot(6-x)}{\sqrt[]{x\cdot(8-x)}}\cdot cm^2\text{.} \end{gathered}[/tex]Now, we equal to zero the last equation and solve for x, we get:
[tex]S^{\prime}(x)=\frac{x\cdot(6-x)}{\sqrt[]{x\cdot(8-x)}}\cdot cm^2=0\Rightarrow x=6.[/tex]We have found that the value x = 6 maximizes the area S(x). Replacing x = 6 in S(x), we get the maximum area:
[tex]S(6)=\frac{6}{2}\cdot\sqrt[]{6\cdot(8-6)}\cdot cm^2=3\cdot\sqrt[]{12}\cdot cm^2=6\cdot\sqrt[]{3}\cdot cm^2.[/tex](c) Rate of change
We know that the length AD = x cm decreases at a rate of 1/√3 cm/s, so we have:
[tex]\frac{d(AD)}{dt}=\frac{d(x\cdot cm)}{dt}=\frac{dx}{dt}\cdot cm=-\frac{1}{\sqrt[]{3}}\cdot\frac{cm}{s}\Rightarrow\frac{dx}{dt}=-\frac{1}{\sqrt[]{3}}\cdot\frac{1}{s}\text{.}[/tex]The rate of change of the area S(x) is given by:
[tex]\frac{dS}{dt}=\frac{dS}{dx}\cdot\frac{dx}{dt}\text{.}[/tex]Where we have applied the chain rule for differentiation.
Replacing the expression obtained in (b) for dS/dx and the result obtained for dx/dt, we get:
[tex]\frac{dS}{dt}(x)=(\frac{x\cdot(6-x)}{\sqrt[]{x\cdot(8-x)}}\cdot cm^2\text{)}\cdot(-\frac{1}{\sqrt[]{3}}\cdot\frac{1}{s}\text{)}[/tex]Finally, we evaluate the last expression for x = 2, we get:
[tex]\frac{dS}{dt}(2)=(\frac{2\cdot(6-2)}{\sqrt[]{2\cdot(8-2)}}\cdot cm^2\text{)}\cdot(-\frac{1}{\sqrt[]{3}}\cdot\frac{1}{s})=-\frac{8}{\sqrt[]{12}}\cdot\frac{1}{\sqrt[]{3}}\cdot\frac{cm^2}{s}=-\frac{8}{\sqrt[]{36}}\cdot\frac{cm^2}{s}=-\frac{8}{6}\cdot\frac{cm^2}{s}=-\frac{4}{3}\cdot\frac{cm^2}{s}.[/tex]So the rate of change of the area of △ADP is -4/3 cm²/s.
Answers
(a)
• (i), Side DP in terms of x:
[tex]DP(x)=\sqrt[]{x\cdot(8-x)}\cdot cm\text{.}[/tex]• (ii), Area of ADP in terms of x:
[tex]S(x)=\frac{x}{2}\cdot\sqrt[]{x\cdot(8-x)}\cdot cm^2.[/tex](b) The maximum value of S is 6√3 cm².
(c) The rate of change of the area of △ADP is -4/3 cm²/s when x = 2.
if (11,13) is an ordered pair of the function F(x), which of the following is an ordered pair of the inverse of F(x)
Answers
Given:
There are given that the ordered pair is:
[tex](11,13)[/tex]Explanation:
According to the question:
We need to find the inverse of the given ordered pair.
Then,
To find the inverse of the given relation, we need to switch the x and y-coordinates.
Then,
The inverse is:
[tex](11,13)\rightarrow(13,11)[/tex]Final answer:
Hence, the correct option is C.
How many terms are existed in between 10 to 1000 which are divisible by 6?
Answers
Answer:166
Step-by-step explanation: There are 166 integers between 1 and 1,000 which are divisible by 6
A rectangular field is nine times as long as it is wide. If the perimeter of the field is 1100 feet, whatare the dimensions of the field?The width of the field isfeet.The length of the field isfeet.
Answers
Given:
The perimeter of the rectangular field is 1100 feet.
According to the question,
l=9w
To find the dimensions:
Substitute l=9w in the perimeter formula,
[tex]\begin{gathered} 2(l+w)=1100 \\ 2(9w+w)=1100 \\ 20w=1100 \\ w=55\text{ f}eet \end{gathered}[/tex]Since the width of the rectangle is 55 feet.
The length of a rectangle is,
[tex]55\times9=495\text{ f}eet[/tex]Hence,
The width of the rectangle is 55 feet.
The length of a rectangle is 495 feet.
help meeeee pleaseeeee!!!
thank you
Answers
The values of f(4) , f(0) and f(-5) are 16/7, -12 and -7/11 respectively.
We are given the function:-
f(x) = (x + 12)/(2x - 1)
We have to find the values of f(4) , f(0) and f(-5).
Putting x = 4 in the given function, we can write,
f(4) = (4+12)/(2*4-1) = 16/7
Putting x = 0 in the given function, we can write,
f(0) = (0 + 12)/(2*0 - 1) = 12/(-1) = -12
Putting x = -5 in the given function, we can write,
f(-5) = (-5 + 12)/(2*(-5) - 1) = 7/(-10-1) = 7/(-11) = -7/11
To learn more about function, here:-
https://brainly.com/question/12431044
#SPJ1
I have no clue what I'm supposed to do I need helpFind the equation of line.
Answers
The general equation of line with slope m and point (x_1,y_1) is,
[tex]y-y_1=m(x-x_1)[/tex]Determine the equation of line.
[tex]\begin{gathered} y-1=3(x+2) \\ y-1=3x+6 \\ y=3x+6+1 \\ =3x+7 \end{gathered}[/tex]So equation of line is y = 3x +7.
A traffic light weighing 16 pounds is suspended by two cables (see figure). Find the tension in each cable. (Round your answers to one decimal place.) lb (smaller value) lb (larger value)
Answers
Step 1: Draw an image to illustrate the problem
Consider the forces along the horizontal axis.
[tex]\begin{gathered} -T_1\cos \theta_1+T_2\cos \theta_2=0 \\ \text{ therefore} \\ T_2\cos 20^0=T_1\cos 20^0 \end{gathered}[/tex][tex]\text{ Dividing both sides by }\cos 20^0[/tex][tex]\begin{gathered} \frac{T_2\cos20^0}{\cos20^0}=\frac{T_1\cos 20^0}{\cos 20^0} \\ \text{thus} \\ T_2=T_1 \end{gathered}[/tex]Consider the forces along the vertical axis.
[tex]\begin{gathered} T_1\sin 20^0+T_2\sin 20^0-16=0 \\ T_1\sin 20^0+T_1\sin 20^0-16=0\text{ (}T_1=T_2) \\ \text{ Thus} \\ 2T_1\sin 20^0=16 \\ T_1=\frac{16}{2\sin 20^0}\approx23.39\text{ pounds} \end{gathered}[/tex]then T₁ = 23.39 pounds
Since T₁=T₂, then T₂ = 23.39 pounds
Hence, smaller value = 23.4 pounds to one decimal place and
larger value = 23.4 pounds to one decimal place
Put the following equation of a line into slope-intercept form, simplifying all fractions. 3x+9y=63
Answers
Answer: y = 63x - 180
Step-by-step explanation: y = mx + b ------(i)
Step one: y = 9, x = 3
9 = 63 (3) + b
9 = 189 + b
-180 = b
b = -180
y = 63x - 180
Answer is
y = -1/3x-6
Consider similar figure QRS and TUV below Where QRS is the pre image of TUV.Part A: What is the scale factor ? Part B:Find the the length of RS.
Answers
Consider similar figure QRS and TUV below Where QRS is the pre image of TUV.Part A: What is the scale factor ? Part B:Find the the length of RS.
Part A
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
so
In this problem
we have that
QS/TV=QR/TU=RS/UV
that means, that the scale factor is
scale factor=TV/QS
substitute the given values
scale factor=2.8/7=0.4
scale factor=0.4Part B
Find the the length of RS
we have that
The length of RS is equal to the length of UV divided by the scale factor
so
RS=5.7/0.4
RS=14.25Part 2
if a figure has four corners then it is a quadrilateral and figure has four corners therefore it is a quadrilateral which statement illustrate this to be true the large attachment account example the law of syllogism the law contrapositive
Answers
The given conditions are true:
law of contrapositive
