Which points are included in the solution Set of the systems of equations graphed below?

Which Points Are Included In The Solution Set Of The Systems Of Equations Graphed Below?

Answers

Answer 1

Given:

Required:

We need to find the points are included in the solution

Explanation:

Recall that the solution of the system of inequalities is the intersection region of all the solutions in the system.

The points G and F lie inside the intersection.

The points in the solution are G and F.

Final answer:

Points F and G.

Which Points Are Included In The Solution Set Of The Systems Of Equations Graphed Below?

Related Questions

A shoe salesman earns a commission of 30%
of all shoe sales made.
Yesterday he sold 3 pairs of shoes for $70 each and 2 pairs of shoes for $80
each. How much did he earn in commission yesterday?

Answers

Answer: $111 is earn by shoe salesman as commission .

Step-by-step explanation:

As given the statement in the question be as follow.

Shoes salesman sold 3 pairs of shoes for $70 each and 2 pairs of shoes for $80 each.

Total cost of the pair of shoes = 3 × 70 + 2 × 80

                                                 = 210 + 160

                                                 = $ 370

As given

shoe salesman earns a commission of 30% of all shoe sales made.

30% is written is decimal form

= 0.30

Commission earns = 0.30 × Total cost of the pair of shoes .

                              = 0.30 × 370

                              = $ 111

Therefore $111 is earn by shoe salesman as commission .

what property tells us that m

Answers

Reflexive Property

1) For this assertion m∠GHK ≅ m∠GHK we have the Reflexive Property, which states that the same segment or geometric entity has the same measure.

"A quantity is congruent to itself"

m∠GHK ≅ m∠GHK

a =a

In triangle ABC, angle A is 44 degrees and angle B is 76 degrees. What is the measure of the third angle?

Answers

Answer:

60 degrees

Step-by-step explanation:

Total of angles of a triangle is 180

180-76-44= 60

Julie is 6 feet tall if she stands 15 feet from the flagpole and holds a cardboard square the edges of the square light up with the top and bottom of the flagpole approximate the height of the flagpole

Answers

Using tangent function:

[tex]\begin{gathered} \tan (\theta)=\frac{opposite}{adjacent} \\ \frac{6}{15}=\frac{15}{x-6} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ 6(x-6)=15^2 \\ 6x-36=225 \\ 6x=225+36 \\ 6x=261 \\ x=\frac{261}{6} \\ x=43.5ft \end{gathered}[/tex]

What is the length of the side adjacent to angle 0?

Answers

To answer this question, we always need to take into account the reference angle in a right triangle. The reference angle here is theta, Θ, and we have that:

Then, the length of the side adjacent to theta is equal to 15.

In summary, we have that the length of the side adjacent to the angle Θ is equal to 15.

Rick's average score on his first three tests in math is 80. What must he score on his next test to raise his average to 84?

Answers

SOLUTION

Now, we don't know the scores for his first three tests. But we are told that the average score for the first three tests was 80.

So, let the scores of the first three tests be a, b, and c. That means

[tex]\frac{a+b+c}{3}=80[/tex]

Also, let's assume the total score for his first three tests was x, This means that

[tex]\begin{gathered} a+b+c=x \\ or \\ x=a+b+c \end{gathered}[/tex]

Comparing with the first equation it means that

[tex]\begin{gathered} \frac{a+b+c}{3}=80 \\ \frac{x}{3}=80 \\ x=3\times80 \\ x=240 \end{gathered}[/tex]

Now we are asked "What must he score on his next test to raise his average to 84?"

So this means the total tests becomes 4. Hence

[tex]\begin{gathered} \frac{a+b+c+d}{4}=84 \\ \frac{x+d}{4}=84 \\ \frac{240+d}{4}=84 \\ 240+d=84\times4 \\ 240+d=336 \\ d=336-240 \\ d=96 \end{gathered}[/tex]

So he must score 96 to raise his average score to 84.

Hence, the answer is 96

5|x +1| + 7 = -38
Solve for x

Answers

Answer: No solutions

Step-by-step explanation:

[tex]5|x+1|+7=-38\\\\5|x+1|=-45\\\\|x+1|=-9[/tex]

However, as absolute value is non-negative, there are no solutions.

4. Which of the following rules is the composition of a dilation of scale factor 2 following (after) a translation of 3 units to the right?

Answers

ANSWER

A. (2x + 3, 2y)

EXPLANATION

Let the original coordinates be (x, y)

First, there was a dilation of scale factor 2.

This means that the coordinates become:

2 * (x, y) => (2x, 2y)

Then, there was a translation of 3 units to the right. That is a translation of 3 units on the horizontal (or x axis).

That is:

(2x + 3, 2y)

So, the answer is option A.

Segment AB and segment CD intersect at point E. Segment AC and segment DB are parallel.

Answers

To begin we shall sketch a diagram of the line segments as given in the question

As depicted in the diagram, line segment AC is parallel to line segment DB.

This means angle A and angle B are alternate angles. Hence, angle B equals 41 degrees. Similarly, angle C and angle D are alternate angles, which means angle C equals 56.

Therefore, in triangle EAC,

[tex]\begin{gathered} \angle A+\angle C+\angle AEC=180\text{ (angles in a triangle sum up to 180)} \\ 41+56+\angle AEC=180 \\ \angle AEC=180-41-56 \\ \angle AEC=83 \end{gathered}[/tex]

The measure of angle AEC is 83 degrees

Create a polynomial of degree 6 that has no real roots. Explain why it has no real roots. Is it possible to have a polynomial with an odd degree that has no real roots? Explain.

Answers

Create a polynomial of degree 6 that has no real roots.

y = ( x^2 + 4) ( x^2 +7 ) ( x^2+5)

Multiplying all the terms together

y =x ^6 + 16 x^4 + 83 x^2 + 140

Using the zero product property

0= x^2 +4 x^2+7 =0 x^2 + 5 =0 will each give a complex solution

x^2 = -4 x^2 = -7 x^2 = -5

This means x = 2i or -2i x = i sqrt(7) or -i sqrt(7) x = i sqrt (5) or - i sqrt(5)

These solutions can be in the form a+bi

Therefor it will have no real roots

y = x^6 + 16 x^4 + 83 x^2 + 140 has no real solutions

Complex solutions come in pairs, so an odd degree must have a real solution

Which of the following is NOT an equation?1. 5(2x+1)=10x+52. 4x-13. 5+3=104. x/2+1=7

Answers

By definition, an equation is a statement that two mathematical expressions are equal.

Equations always contain the equal sign "="

Out of the 4 expressions listed, number 2. does not contain the equal sign, which means that this expression is not an equation.

All other expressions contain the equal sign, they can be considered equations.

When point A'(-2,4) is reflected over they-axis, where is the image A"?(2,-4)(2,4)(4,-2)

Answers

Answer:

Explanation

Given a coordinate (x, y), If this coordinate reflected over y axis, the resulting coordinate will be expressed as (-x, y). Note that only the sign of the x coordinate axis was

In a nearby park, a field has been marked off for the neighborhood Pop Warner football team. If the field has a perimeter of 310 yd and an area of 4950 yd', what are the dimensions of the field?

Answers

Answer:

The dimension of the field is ( 110 x 45)

Exolanations:

Perimeter of the field, P = 310 yd

Area of the field, A = 4950 yd²

Note that the shape of a field is rectangular:

Perimeter of a rectangle, P = 2(L + B)

Area of a rectangle, A = L x B

Substituting the values of the perimeter, P, and the Area, A into the formulae above:

310 = 2(L + B)

310 / 2 = L + B

155 = L + B

L + B = 155...............................................(1)

4950 = L x B...............(2)

From equation (1), make L the subject of the formula:

L = 155 - B...................(3)

Substitute equation (3) into equation (2)

4950 = (155 - B) B

4950 = 155B - B²

B² - 155B + 4950 = 0

Solving the quadratic equation above:

B² - 110B - 45B + 4950 = 0

B (B - 110) - 45(B - 110) = 0

(B - 110) ( B - 45) = 0

B - 110 = 0

B = 110

B - 45 = 0

B = 45

Substitute the value of B into equation (3)

L = 155 - B

L = 155 - 45

L = 110

The dimension of the field is ( 110 x 45)

pls help me i’ll give ty brainlist

Answers

[tex]\sqrt{25*7x^{4}*x^{1} } \\=\sqrt{25*x^{4}*7 *x^{1} } \\=\sqrt{25x^{4} } *\sqrt{7x}\\=5x^{2} \sqrt{7x}[/tex]

Option B is the answer.

Answer: C

i hope you can see my handwriting

Express the repeating decimal 0.2 as a fraction

Answers

Answer:

The fraction form of the repeating decimal is;

[tex]\frac{2}{9}[/tex]

Explanation:

We want to express the repeating decimal 0.2 (2 repeating) as a fraction.

let x represent the fraction;

[tex]\begin{gathered} x=0.2222\ldots \\ 10x=2.222\ldots \end{gathered}[/tex]

Then subtract x from 10x;

[tex]\begin{gathered} 10x-x=2.222\ldots-0.222\ldots \\ 9x=2.0 \end{gathered}[/tex]

Then we can divide both sides by the coefficient of x;

[tex]\begin{gathered} \frac{9x}{9}=\frac{2}{9} \\ x=\frac{2}{9} \end{gathered}[/tex]

Therefore, the fraction form of the repeating decimal is;

[tex]\frac{2}{9}[/tex]

Find the first four terms of the sequence given by the following

Answers

[tex]54,62,70,78[/tex]

1) In this question, we need to resort to that Explicit formula, with the first term so that we can find the terms:

[tex]\begin{gathered} a_n=54+8(n-1) \\ a_1=54+8(1-1) \\ a_1=54 \\ \\ a_2=54+8(2-1) \\ a_2=54+8 \\ a_2=62 \\ \\ a_3=54+8(3-1) \\ a_3=54+8(2) \\ a_3=54+16 \\ a_3=70 \\ \\ a_4=54+8(4-1) \\ a_4=54+8(3) \\ a_4=78 \\ \end{gathered}[/tex]

2) As we can see, this is an Arithmetic sequence. And the answer is:

[tex]54,62,70,78[/tex]

Mary used the quadratic formula to find the zeros of the equation below. Select the correct zeros of the equation:3x^2 - 9x + 2 = 0Answer choices include:x = fraction numerator 9 plus-or-minus square root of 57 over denominator 6 end fractionx equals fraction numerator negative 9 plus-or-minus square root of 57 over denominator 2 end fractionx equals fraction numerator 9 plus-or-minus square root of 105 over denominator 2 end fractionx equals fraction numerator negative 9 plus-or-minus square root of 105 over denominator 6 end fraction

Answers

We have the next quadratic function given:

[tex]3x^2-9x+2=0[/tex]

Mary used the next quadratic formula:

[tex]x=\frac{-b^\pm\sqrt{b^2-4ac}}{2a}[/tex]

Replace using the form ax²+bx+c

Where a= 3

b=-9

c=2

Then:

[tex]\begin{gathered} x=\frac{-\lparen-9)\pm\sqrt{\left(-9\right)^2-4\left(3\right)\left(2\right)}}{2\left(3\right)} \\ x=\frac{9\pm\sqrt[]{57}}{6}\frac{}{} \end{gathered}[/tex]

Therefore, the correct answer is "x = fraction numerator 9 plus-or-minus square root of 57 over denominator 6 end fraction"

find the slope of the line passing through the points (-5,4) and (3,-3)

Answers

P1 = (-5, 4)

P2 = (3, -3)

Formula

[tex]\text{slope = }\frac{(y2\text{ - y1)}}{(x2\text{ - x1)}}[/tex]

Substitution

[tex]\begin{gathered} \text{ slope = }\frac{(-3-4)}{(3\text{ + 5)}} \\ \text{ slope = }\frac{-7}{8} \end{gathered}[/tex]

Result

[tex]\text{ slope = }\frac{-7}{8}[/tex]

Given f(x), find g(x) and h(x) such that f(x)= g(h(x)) and neither g(x) nor h(x) is solely x.

Answers

Given:

[tex]\begin{gathered} f(x)=g(h(x)) \\ f(x)=\sqrt[]{-4x^2-3}+2 \end{gathered}[/tex]

Solve :

[tex]g(h(x)=\sqrt[]{-4x^2-3}+2[/tex]

The function g(x) convert then x is equal to h(x) then:

[tex]\begin{gathered} h(x)=-4x^2 \\ g(x)=\sqrt[]{x-3}+2 \end{gathered}[/tex]

If a,b ,and c represent the set of all values of x that satisly the equation below, what is the value(A+ b+ c) + (abc)?X^3-20x = x^2(A) -1(B) 0(C) 1(D) 9

Answers

First, we need to find the solutions a, b, and c of the equation:

[tex]x^3-20x=x^2[/tex]

We can rewrite it as:

[tex]\begin{gathered} x^3-x^{2}-20x=0 \\ \\ x(x^{2}-x-20)=0 \\ \\ x=0\text{ or }x^{2}-x-20=0 \end{gathered}[/tex]

Thus, one of the solutions is a = 0.

To find the other solutions, we can use the quadratic formula. We obtain:

[tex]\begin{gathered} x=\frac{-(-1)\pm\sqrt[]{(-1)^{2}-4(1)(-20)}}{2(1)} \\ \\ x=\frac{1\pm\sqrt[]{1+80}}{2} \\ \\ x=\frac{1\pm\sqrt[]{81}}{2} \\ \\ x=\frac{1\pm9}{2} \\ \\ b=\frac{1-9}{2}=-4 \\ \\ c=\frac{1+9}{2}=5 \end{gathered}[/tex]

Now, we need to find the value of the expression:

[tex]\mleft(a+b+c\mright)+abc[/tex]

Using the previous solutions, we obtain:

[tex]\mleft(0-4+5\mright)+0(-4)(5)=1+0=1[/tex]

Therefore, the answer is 1.

find the slope. A. y= -1/2x - 19/2.

Answers

The equation of the line follows the following general structure:

[tex]y=mx+b[/tex]

Where m is the slope of the line and b is the y intercept.

Find the corresponding values in the given formula, this way:

In the given equation, m has a value of -1/2, it means the slope is -1/2.

Find the simple interest owed for the following loan. Principal = 2775 Rate = 7.5% Time = 5 1/2 years

Answers

We would apply the simple interest formula which is xpressed as

I = PRT/100

Where

I represents interest

P represents principal or amount borrowed

T represents time in years

R represents rate.

From the information given,

P = 2775

R = 7.5

T = 5 1/2 = 5.5

I = (2775 * 7.5 * 5.5)/100

I = 1144.6875

Rounding to the nearest cent,

I = 1144.69

xyx2xy1645256720 2258 484 1,2762873 7842,044 3294 1,0243,008 45141 2,025 6,345 ∑x=143 ∑y=411 ∑x2=4,573 ∑xy=13,393 Which regression equation correctly models the data?y = 2.87x + 0.12y = 2.87x + 11.85y = 3.39x – 14.75y = 3.39x – 9.24

Answers

We are asked to identify the correct regression equation.

The regression equation is given by

[tex]y=bx+a[/tex]

Where the coefficients a and b are

[tex]a=\frac{\sum y\cdot\sum x^2-\sum x\cdot\sum xy}{n\cdot\sum x^2-(\sum x)^2}[/tex][tex]b=\frac{n\cdot\sum xy-\sum x\cdot\sum y}{n\cdot\sum x^2-(\sum x)^2}[/tex]

Where n is the number of observations that is 5.

Let us substitute the following into the above formula.

∑x=143

∑y=411

∑x^2=4,573

∑xy=13,393

[tex]a=\frac{411\cdot4573-143\cdot13393}{5\cdot4573-(143)^2}=-14.75[/tex][tex]b=\frac{5\cdot13393-143\cdot411}{5\cdot4573-(143)^2}=3.39[/tex]

So, the coefficients are

a = -14.75

b = 3.39

Therefore, the correct regression equation is

[tex]y=3.39x-14.75[/tex]

14 pointsWhich are the coefficients of the terms in the algebraic expression, x2 - 3x?O and -31 and -3O and 351 and 36

Answers

Answer:

The coefficients of the terms in the algebraic expression are 1 and -3

[tex]1\text{ }and-3[/tex]

Explanation:

The coefficients are the number that multiplies an algebraic term in an algebraic expression.

for example; the coefficient of 3x is 3.

[tex]3x=3\times x[/tex]

For the question;

given the expression;

[tex]x^2-3x[/tex]

The coefficient of x^2 is 1

[tex]x^2=1\times x^2[/tex]

while the coefficient of x is -3

[tex]-3x=-3\times x[/tex]

Therefore, the coefficients of the terms in the algebraic expression are 1 and -3

[tex]1\text{ }and-3[/tex]

3/5 ÷ 1/3 = ?????????

Answers

[tex]\frac{3}{5}\text{divide by}\frac{1}{3}[/tex]

Change the division sign to multiplication and then invert 1/3

That is;

[tex]\frac{3}{5}\times3[/tex][tex]=\frac{9}{5}\text{ =1}\frac{4}{5}[/tex]

Graph two or more functions in the same family for which the parameter being changed is the slope, m. and is less than 0.Refer to the graph of f(x) = x + 2

Answers

We have the expression:

[tex]f(x)=x+2[/tex]

If the slope is changing being less than 0, that is:

please help me work through this homework problem! thank you!

Answers

Given:

Given the function

[tex]y=3+\frac{3}{x}+\frac{2}{x^2}[/tex]

and a point x = 3.

Required: Equation of the line tangent to y at x = 3.

Explanation:

The derivative of a function is he slope of the tangent line of the function at a given point. So, finding the derivative gives the slope of the tangent line.

[tex]y^{\prime}=-\frac{3}{x^2}-\frac{4}{x^3}[/tex]

Substitute 3 for x into the derivative.

[tex]\begin{gathered} y^{\prime}|_{x=3}=-\frac{3}{3^2}-\frac{4}{3^3} \\ =-\frac{31}{27} \end{gathered}[/tex]

Therefore, the slope of the tangent line is -31/27.

Substitute 3 for x into y.

[tex]\begin{gathered} y|_{x=3}=3+\frac{3}{3}+\frac{2}{3^2} \\ =3+1+\frac{2}{9} \\ =4+\frac{2}{9} \\ =\frac{38}{9} \end{gathered}[/tex]

(3, 38/9) is the only point on the tangent line where it intersects the original graph.

Plug these coordinates along with slope into the general point-slope form to find the equation.

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-\frac{38}{9}=-\frac{31}{27}(x-3) \end{gathered}[/tex]

Solving for y will give the equation in slope-intercept form.

[tex]\begin{gathered} y=-\frac{31}{27}(x-3)+\frac{38}{9} \\ =-\frac{31}{27}x+\frac{69}{9} \end{gathered}[/tex]

Final Answer: The equation of the tangent line is

[tex]y=-\frac{31}{27}x+\frac{69}{9}[/tex]

Solve for the unknown: 6(B+2) = 30

Answers

The unknown is B

[tex]6(B+2)=30[/tex][tex]\begin{gathered} 6B+12=30 \\ 6B+12-12=30-12 \\ 6B=18 \\ B=\frac{18}{6} \\ B=3 \end{gathered}[/tex]

4x squared- 5x +4-(9x squared +3x -1)

Answers

hello

the question here requires the subtraction of polynomials

[tex]\begin{gathered} 4x^2-5x+4 \\ - \\ 9x^2+3x-1 \end{gathered}[/tex]

if we are to do this, we have to subtract the polynomials based on their degree

this would be equal to

[tex]-5x^2-8x+5[/tex]

the above polynomial is the result after subtraction, but we can as well, decide to multiply through by -1, to make or eilimate the negative sign on the second degree polynomal

[tex]\begin{gathered} (-5x^2-8x+5)\times-1 \\ = \\ 5x^2+8x-5 \end{gathered}[/tex]

I List two types of angle pairs: 14) 15)

Answers

Let's recall that a type of angle pairs are complementary angles. They're complementary if the sum of their degree measurements equals 90 degrees or the right angle.

Example:

[tex]\angle ABZ\text{ and }\angle ZBC\text{ are complementary angles }[/tex]

Let's recall that a second type of angle pairs are suplementary angles. In this case, the angles add up to 180 degrees.

Example:

[tex]\angle ABF\text{ and }\angle FBC\text{ are suplementary angles}[/tex]

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