Without using a calculator, simplify
Root of 20.
Answer:
4.472135955 , is the answer. simplified to two decimal places it will be 4.47
A store pays $8 for a pool noodle. The markup is 20%.
Answer:
the price with the markup is 9.60$
Step-by-step explanation:
The product of a particular number and a second value, which is given by the sum of 8 and the original number, is 65. What is the number?
Answer:
there are infinite values of sum X + Y = (Y + 65/Y) since there are infinite values of Y.
Step-by-step explanation:
XY = 65. Given that question is asking you find X + Y, it kind of indicates that there could be very limited possible values of X and Y which you can work out. Again it is an indication of such silly questions. It need not be true that you have limited solutions.
One such solution is represented here. I have assumed X and Y are positive integers only.
Factorize 65 = 65 x 1 or 13 x 5
Therefore (X,Y) can be (65,1) or (13,5) .
So X + Y = 66 or 18.
If we include negative integers as well ,
then XY = 65 => Factors are 65 x 1, 13 x 5 or (-13) x (-5) or (-65) x (-1)
So X + Y = -66 or -18 or 18 or 66.
In general,
XY = 65 => X = 65/Y (assuming Y is not 0 else XY would have been 0 too).
Therefore X + Y = Y + 65/Y.
If X, Y belong to real or complex numbers except 0,
there are infinite values of sum X + Y = (Y + 65/Y) since there are infinite values of Y.
Can someone help me please thank you:)
Answer: bcde
Step-by-step explanation:
The ones that are greater than 1. 1*0.75= 7.5, which is less than the original 10
A rectangle has sides of length of 6 and
[tex]6 \sqrt{3} [/tex]
what is the length of the diagonal
Answer:
Step-by-step explanation:
Say that :
a=6 , b=6[tex]\sqrt{3}[/tex]
and the diagonal is c=?
c^2=a^2+b^2
So
c[tex]\sqrt{a^{2}+b^{2} } =\sqrt{6^{2}+(6\sqrt{3})^{2} } \\=12[/tex]
I hope it will help you :)
Verify the following reduction formula:
[tex]\displaystyle \int \sec^n(u)\, du=\frac{\sec^{n-2}(u)\tan(u)}{n-1}+\frac{n-2}{n-1}\int \sec^{n-2}(u)\, du, \; n\neq 1[/tex]
Answer:
See Explanation.
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyEquality PropertiesAlgebra I
Combining Like TermsAlgebra II
Exponential RulesPre-Calculus
Pythagorean Identities: tan²(x) = sec²(x) - 1Calculus
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integration Rule 1: [tex]\int {cf(x)} \, dx = c\int {f(x)} \, dx[/tex]
Integration Rule 2: [tex]\int {f(x) \pm g(x)} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration 1: [tex]\int {sec^2(u)} \, du = tan(u) + C[/tex]
Integration by Parts: [tex]\int {u} \, dv = uv - \int {v} \, du[/tex]
[IBP] LIPET: Logs, inverses, Polynomials, Exponentials, TrigStep-by-step explanation:
Step 1: Define
[tex]\int {sec^n(u)} \, du[/tex]
Step 2: Rewrite
[Integral - Alg] Separate Exponents: [tex]\int {sec^n(u)} \, du = \int {sec^{n-2}(u)sec^2(u)} \, du[/tex]Step 3: Identify Variables
Using LIPET, we define variables to use IBP.
Use Integration 1.
[tex]u = [sec(u)]^{n-2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ dv = sec^2(u)du\\du = (n-2)[sec(u)]^{n-3} sec(u)tan(u) \ \ \ \ \ \ \ \ v = tan(u)[/tex]
Step 4: Integrate
Integrate [IBP]: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - \int [{tan(u)(n-2)[sec(u)]^{n-3}sec(u)tan(u)} ]\, du[/tex][Integral - Alg] Multiply: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - \int [{tan^2(u)(n-2)[sec(u)]^{n-2}}] \, du[/tex][integral - Int Rule 1] Simplify: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - (n-2)\int [{tan^2(u)[sec(u)]^{n-2}}] \, du[/tex][Integral - Pythagorean Identities] Rewrite: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - (n-2)\int [{[sec^2(u) - 1][sec(u)]^{n-2}}] \, du[/tex][Integral - Alg] Multiply/Distribute: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - (n-2)\int [{sec^n(u)-[sec(u)]^{n-2}}] \, du[/tex][Integral - Int Rule 2] Rewrite: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - (n-2) [\int {sec^n(u)} \, du - \int {[sec(u)]^{n-2}} \, du ][/tex][Integral - Alg] Distribute: [tex]\int {sec^n(u)} \, du = tan(u)[sec(u)]^{n-2} - (n-2) \int {sec^n(u)} \, du + (n-2)\int {[sec(u)]^{n-2}} \, du[/tex]Rewrite: [tex]\int {sec^n(u)} \, du = sec^{n-2}(u)tan(u) - (n-2) \int {sec^n(u)} \, du + (n-2)\int {[sec(u)]^{n-2}} \, du[/tex][Integral - Alg] Isolate Integral Term: [tex]\int {sec^n(u)} \, du + (n-2) \int {sec^n(u)} \, du = sec^{n-2}(u)tan(u) + (n-2)\int {[sec(u)]^{n-2}} \, du[/tex][Integral - Alg] Combine Like Terms: [tex](n - 1)\int {sec^n(u)} \, du = sec^{n-2}(u)tan(u) + (n-2)\int {[sec(u)]^{n-2}} \, du[/tex][Integral 2 - Alg] Rewrite: [tex](n - 1)\int {sec^n(u)} \, du = sec^{n-2}(u)tan(u) + (n-2)\int {sec^{n-2}(u)} \, du[/tex][Integral - Alg] Isolate Original Integral: [tex]\int {sec^n(u)} \, du = \frac{sec^{n-2}(u)tan(u)}{n-1} + \frac{n-2}{n-1} \int {sec^{n-2}(u)} \, du[/tex]And we have proved the Reduction Formula!
Find the interest generated if one invests $6000 for 9 years at 7% per annum with interest compounded monthly
Answer:
$5,245.06 (nearest cent)
Step-by-step explanation:
Compound Interest Formula
[tex]\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}[/tex]
where:
I = interest accruedP = principal amountr = interest rate (in decimal form)n = number of times interest applied per time periodt = number of time periods elapsedGiven:
P = $6,000r = 7% = 0.07n = 12 (monthly)t = 9 yearsSubstitute the given values into the formula and solve for I:
[tex]\implies \sf I=6000\left(1+\dfrac{0.07}{12}\right)^{12 \times 9}-6000[/tex]
[tex]\implies \sf I=6000\left(\dfrac{1207}{1200}\right)^{108}-6000[/tex]
[tex]\implies \sf I=5245.061831...[/tex]
Therefore, the interest generated is $5,245.06 (nearest cent).
Learn more about compound interest here:
https://brainly.com/question/27747709
https://brainly.com/question/27806277
could anyone help answer this question? please
B(the 2nd one)
Step-by-step explanation:
trust me
Examine A ABC below.
Determine which of the following relationships is true.
DE = 2AC
DE || AC
m2BCA = 2(m_BED)
DE = AC
Answer:
DE║ACStep-by-step explanation:
Given relationships:
DE = 2 AC
Incorrect. Should be DE = 1/2 ACDE║AC
Correctm∠BCA = 2(m∠BED)
Incorrect. Should be m∠BCA = m∠BEDDE = AC
Incorrect. Should be DE = 1/2 ACBRAINLIEST IF CORRECT
Answer:
[tex]100000[/tex]
Step-by-step explanation:
[tex]10^{5}[/tex] means [tex]10[/tex] multiplied by itself by [tex]5[/tex] times.
[tex]10^5 = 100000[/tex]
Hope this helps :)
6x+12=12+6x Am I right? There is no solution 0=0
Answer:
No, it's c, good try though
Step-by-step explanation:
0=0 is true which means no matter what x is, it will be true. If it said 0=1 or something it would be no solution because no matter what, that is not true
Answer:
there are many solutions.
Step-by-step explanation:
because you Combine like terms: 6x + -6x = 0
0 = 0
and the Solution is going to be many solutions like
0 = 0
Solve the system of equations.
X = 3y + 4
4x - 12y = 16
please help :(
An equilateral triangle has a perimeter of
15x + 24. What is the length of one side of the triangle?
Answer:
one side length is 39
Step-by-step explanation:
is it ok
Describe how to create a line of best fit
Answer:
Plot your point(s) first. Then make the line of best fit. The plotted point(s) on the graph (or other enclosed area) have to be evenly spread out/across the line of best fit.
Hope it helps!
What is the answer to this problem?
Answer:
B
Step-by-step explanation:
You can knock out A, because this isn't talking about temperature, and C and D are proven untrue by the data. The only one left is B, which if you check, is also consistant with the data.
If you sleep 7 hours every night how many hours are you AWAKE in a year?
How do you do this answer this pls
Answer:
7, 5
Step-by-step explanation:
if its a reflection over the y axis it goes into the all positive zone so it will become positive
Answer:
(-7,-5)
Step-by-step explanation:
-3x + 4x + 1- 8 whats the answer
Answer:
x - 7
Step-by-step explanation:
just add/substract like terms only
Solve for y. 3.5y + 2.5y = 345
Answer:
The answer is 57.5
Step-by-step explanation:
Find the sum
10 + 8 + 0.6 + 0.04
10 + 8 + 0.6 + 0.04 = 18.64
There are 4 colors of Starburst flavors: yellow, pink, red, and orange. If the probability of getting an orange is ž, yellow is
10, and the probability of getting red is to what is the probability of getting pink?
Answer:6
Step-by-step explanation:
the answer will be 6 because is in between 10.
PLEASE HELP WILL GIVE YOU 45 POINTS!!!!
Answer:
Side GE = 7.7
Side GF = 5.1
Side FE = 9.2358
Angle ∠E = 56.482°
Angle ∠F = 33.518°
Angle ∠G = 90°
Please give Brainliest thx
WILL GIVE BRAINLIEST FOR RIGHT ANSWER!!!
Answer:
It is B.
Step-by-step explanation:
this is my best subgect in math trust me and please give me brainlyest
i need work shown for the assignment
Answer:
q,p,r i think
Step-by-step explanation:
Answer:
Q, P, R
Step-by-step explanation:
∠Q is the smalest because is across the smallest side
∠P is second largest because is across the middle side
∠R is the largest angle because is across the biggest side
Simplify each expression.
1) 7(3v - 3)
2) -3(-n + 4)
3) -6(-8x - 3)
4) -(3b - 9)
Answer:
Step-by-step explanation:
1 21v - 21
2 3n - 12
3 48x + 18
4 -3b + 9
Answer:
1) 21v-21
2) 3n-12
3) 48x+18
4) -3b+9
Step-by-step explanation:
used distributive property to solve
What percent of 30 is 16.5 ?
Need help ASAP!! Tyyy
Answer:
its 6
Step-by-step explanation:
For his long-distance phone service, Jim pays a $3 monthly fee plus 11 cents per minute. Last month, Jim's long-distance bill was $21.48. For how many minutes was Jim billed?
Answer:
168
Step-by-step explanation:
3 + .11x = 21.48
.11x = 18.48
x = 168
On Monday, I bought 1 dog and 3 cats for a total cost of $7.75. On Tuesday, 1
bought 1 dog and 6 cats for a total cost of $13.75. Can you find the price of each
item?
Answer: The cats cost more
also there is a typo
Step-by-step explanation:
I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$
The distance from the old north church in boston to charlestown is approximately 1,410 meters. even on a fast horse,that distance would take several minutes to travel. on april 18,1775, lanterns were shown from the steeple of the old north church across the charles river to warn american patriots that british soldiers were traveling inland via water. the speed of light is approximately 3 times 10^8 meters per second. how many seconds did it take for the light to be visible in charlestown? express answer using scientific notation. helpppppppp!!
Answer:
It took like 0 seconds.
Step-by-step explanation:
3 x 10^8 = 300000000
If there are 1,410 meters, then it should take no time at all.
