The invention of the chronometer was important because it allowed for more accurate navigation at sea.
Prior to the invention of the chronometer, navigators had to use the sun, stars, and other celestial bodies as a means of determining their location.
This was often inaccurate and could put ships in danger of getting lost at sea. The invention of the chronometer allowed for a more accurate and reliable way of keeping track of time and location, which made for safer and more efficient navigation.
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A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. it begins the trip traveling 120 meters per second and decelerates to a velocity of 20 meters per second. what was its acceleration? responses −1.11 m/s2 negative 1.11 meters per second squared, −0.3 m/s2 negative 0.3 meters per second squared, 1.11 m/s2 plus 1.11 meters per second squared, 80 m/s2
Answer:
A. −1.11 m/s2
Explanation:
To calculate the object's acceleration, we can say:
acceleration = (final velocity - initial velocity) / time
The object's initial velocity is 120 m/s, its final velocity is 20 m/s, and the time it takes to travel the 2,500-meter path is 1.5 minutes, or 90 seconds (1.5 x 60 = 90).
Therefore:
acceleration = (20 m/s - 120 m/s) / 90 s = -1.11 m/s^2
Note
The negative sign, means the object is decelerating and not accelerating because the object is slowing down during the trip.
it is decreasing its speed as it travels, so it's slowing down over time. The absolute value of -1.11 is also called deceleration.#SPJ4
Fill in the blank
Waves can be classified by how the particles in the disturbance ______________.
On the way to the moon, the Apollo astronauts reach a point where the Moon’s gravitational pull is stronger than that of Earth’s.
(Part 1/2) Find the distance of this point from the center of the Earth.
The masses of the Earth and the Moon are 5.98 × 1024 kg and 7.36 × 1022 kg, respectively, and the distance from the Earth to the Moon is 3.84 × 108 m.
Answer in units of m.
(Part 2/2) What would the acceleration of the astronaut be due to the Earth’s gravity at this point if the moon was not there?
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2/kg^2.
Answer in units of m/s^2.
Answer:
Approximately [tex]3.46 \times 10^{8}\; {\rm m}[/tex], assuming that the astronauts are travelling along a straight line between the Earth and the Moon.
Approximately [tex]3.34 \times 10^{-3}\; {\rm m\cdot s^{-2}}[/tex].
Explanation:
Let [tex]r[/tex] denote the distance (in meters) between the astronaut and the center of the Earth. Under the assumptions, the distance between the astronaut and the Moon would be [tex](3.84 \times 10^{8} - r)[/tex] meters.
Let [tex]G[/tex] denote the universal gravitational constant. Let [tex]m[/tex] denote the mass of the astronauts. Magnitude of the gravitational attraction from the Earth would be:
[tex]\begin{aligned}\frac{G\, m\, M_\text{earth}}{r^{2}}\end{aligned}[/tex].
Magnitude of the gravitational attraction from the Moon would be:
[tex]\begin{aligned}\frac{G\, m\, M_\text{moon}}{(3.84 \times 10^{8} - r)^{2}}\end{aligned}[/tex].
Equate the two expressions and solve for the distance [tex]r[/tex]:
[tex]\begin{aligned}\frac{G\, m\, M_\text{earth}}{r^{2}} = \frac{G\, m\, M_\text{moon}}{(3.84 \times 10^{8} - r)^{2}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{(3.84 \times 10^{8} - r)^{2}}{r^{2}} = \frac{G\, m\, M_\text{moon}}{G\, m\, M_\text{earth}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{3.84 \times 10^{8} - r}{r} &= \sqrt{\frac{M_\text{moon}}{M_\text{earth}}} \\ &= \sqrt{\frac{5.98 \times 10^{24}\; {\rm kg}}{7.36 \times 10^{22}\; {\rm kg}}}\end{aligned}[/tex].
[tex]\begin{aligned}r &= \frac{3.84 \times 10^{8}\; {\rm m}}{\displaystyle 1 + \sqrt{\frac{5.98 \times 10^{24}\; {\rm kg}}{7.36 \times 10^{22}\; {\rm kg}}}} \approx 3.45653\times 10^{8}\; {\rm m}\end{aligned}[/tex].
In other words, the distance between the astronaut and the center of the Earth should be approximately [tex]3.46 \times 10^{8}\; {\rm m}[/tex].
At [tex]r \approx 3.45653\times 10^{8}\; {\rm m}[/tex] from the center of the Earth, the gravitational field strength of the Earth would be:
[tex]\begin{aligned}g &= \frac{G\, M_{\text{earth}}}{r^{2}} \\ &\approx \frac{(6.672 \times 10^{-11}\; {\rm N \cdot m^{2}\cdot kg^{-2}})\, (5.98 \times 10^{24}\; {\rm kg})}{(3.45653 \times 10^{8}\; {\rm m})^{2}} \\ &\approx 3.34 \times 10^{-3}\; {\rm N\cdot kg^{-1}} = 3.34 \times 10^{-3}\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
Which of the following is true about Russia's natural resources?
A: The forested regions of Siberia are the largest in the world.
B: Its resources are easy to extract.
C: The nation doesn't have large reserves of coal or natural gas.
D: Russia is among the world's bottom producers of nickel and aluminum.
Answer:
A: The forested regions of Siberia are the largest in the world.
Explanation:
During a game of handball, you strike the ball with a mass of. 06 kg, and it accelerates to the left at a rate of 13. 7 m/s2. What force did your hand exert on the ball?.
The force exerted by the hand on the ball has a mass of 0.06 kg is 0.822 N
The mass of the ball = 0.06 kg
The acceleration of the ball = 13.7 m/s²
In physics, force is defined as:
Pushing or pulling an object with mass changes its velocity. A force is an external factor that can alter the body's state of rest or motion. It has size and direction.
The force exerted on the ball can be found using the formula,
F = ma
where F is the force
m is the mass
a is the acceleration
Let us substitute the known values in the above equation, we get
F = 0.06 x 13.7
= 0.822 N
Therefore, the force exerted on the ball is 0.822 N
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what is the magnitude of the force f⃗ on the -10 nc charge in (figure 1)? suppose that a = 2.4 cm.
The force is -7.81105 N in magnitude. The object is propelled by external forces. The object's overall motion is unaffected by an internal force.
In science, what exactly is a force?
The term "force" has a clear definition in science. It is perfectly acceptable to refer to a force at this level as a push or a pull. An object does not "have in it" or "contain" a force. One object is subject to a force from another.
What is an illustration of force?
A force is a push that has the power to accelerate something. This can literally mean pushing something to move it around the room, like a big piece of furniture.
F = Kq1q2/r^2
q1 and q2 = charges
K = electric constant
r = distance of separation
F = force
Then we have;
F = 9 * 10^9 * 5 * 10^-9 * (-10 * 10^-10)/(0.018)^2
F = -4.5 * 10^-8/3.24 * 10^-4
F = -7.81×10⁻⁵ N
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HELP!!!!
My science teacher is no help
A basketball player is dribbling a basketball at a speed of 10 mph. The basketball has a mass of 0.625 kg and a radius of 0.11 m. Calculate the angular momentum of the basketball.
In order to calculate the angular momentum of the basketball, we need to know the rotational speed of the ball. Since the ball is dribbled at a speed of 10 mph, we can assume that its rotational speed is much smaller than this. Let's assume that the rotational speed of the ball is r revolutions per minute (rpm).
The angular momentum of the ball is then given by the following formula:
L = I * w
Where I is the moment of inertia of the ball and w is its angular velocity.
The moment of inertia of a sphere is given by the following formula:
I = (2/5) * m * r^2
Where m is the mass of the ball and r is its radius.
Substituting these values into the formula for angular momentum, we get:
L = (2/5) * 0.625 kg * (0.11 m)^2 * r rpm
Solving for r, we get:
r = (5/2) * L / (0.625 kg * (0.11 m)^2)
Therefore, the angular momentum of the basketball is directly proportional to its rotational speed. If we want to increase the angular momentum of the ball, we would need to increase its rotational speed.
A car starts rolling down a 1-in-4 hill (1-in-4 means that for each 4m traveled along the road, the elevation change is 1m) How fast is it going when it reaches the bottom after traveling 55m?
(a) ignore friction.
(b) Assume an effective coefficient of friction equal to 0.10
The velocity of the car when it reaches the bottom after traveling 55m is equal to 16 m/s.
What is the equation of motion?Equations of motion are used to explain the concept of motion such as the time, position, velocity, and acceleration at several times. The equations of motion give the expression between velocity, time, displacement, and acceleration.
Given, an effective coefficient of friction = 0.10
The distance traveled by car, S = 55 m
sinθ = 1/4
θ = 14.47°
mgsinθ - μ mg cos θ = ma
9.8 (sin 14.47) - 0.10 cos 14.47 = a
a = 2.448 - 0.968
a = 2.35 m/s²
We can determine the final velocity of the car from the third equation of motion:
v² - u² = 2aS
(v)² - 0² = 2 × 2.35 × 55
v = 16 m/s
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What is the refractive index of glass with respect to air if the speed of light in glass is 2 108 MS 1 and the speed of light in air is 3 108 ms 1?
The refractive index of glass with respect to air is 1.5.
The refractive index or index of refraction is the measure of the bending of a ray of light when passing from one medium into another. It can also be defined as the ratio of the velocity of a light ray in an empty space to the velocity of light in a substance. Refractive index of medium B with respect to medium A is given by
n = Speed of light in medium A/ Speed of light in medium B
when light travels from medium A to medium B. Hence, the refractive index of glass with respect to air is given by
n = Speed of light in air/ Speed of light in glass
Based on the provided information,
Speed of light in air = 3 x 10^8 m/s
Speed of light in glass = 2 x 10^8 m/s
Hence, the refraction index of glass is
n = 3 x 10^8/ 2 x 10^8 = 1.5
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What is the resistance of a 0.100-kW light bulb designed to be used in a 120-V circuit dc?
A. 12.0 Ω
B. 144 Ω
C. 1.2 Ω
D. 0.83 Ω
Answer: B
Explanation:
Power of light bulb: 0.100 kW = (0.100 x 1000) W
= 100W (remember to convert to W, not kW)
Next, apply the formula Power = Voltage^2 / R
Voltage is given in the question to be 120V
Hence, 100 = 120^2/R
100 = 14400/R
R = 14400/100 ohm
R = 144 ohm
A uniform ladder of mass m and length l leans at an angle θ against a frictionless wall
Part A If the coefficient of static friction between the ladder and the ground is μ, determine a formula for the minimum angle at which the ladder will not slip. Express your answer in terms of some or all of the variables m, l, and μ.
The maximum possible angle for the ladder not to slip is calculated to be 48°.
Given that,
Coefficient of friction = 0.45
Mass of the ladder = m
Length of ladder = L
Vertical force = m g
Horizontal force = μ m g
As the ladder is stable, moment is taken as zero.
So,
μ × m g L × sin θ - (m g L)/2 cos θ = 0
tan θ = 1/2 μ = 1/2 × 0.45 = 0.225
tan θ = 0.225
θ = 48°
The required maximum possible angle for the ladder not to slip is calculated to be 48°.
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NEED DONE TNIGHTTTT PLEASEEE
The acceleration due to gravity experienced by the cosmonauts is 8.8 m/s².
What is the acceleration due to gravity experienced by the cosmonauts?The magnitude of Earth's gravitational field and the acceleration due to gravity experienced by the cosmonauts is calculated as follows;
E = Gm / r²
g = Gm / r²
where;
G is universal gravitation constantm is the mass of Jupiterr is the radius of Jupiter from the spacecraftE is the Earth's gravitational field g is acceleration due to gravityThe acceleration due to gravity experienced by the cosmonauts is calculated as
g = ( 6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / ( 3.59 x 10⁵ + 6.37 x 10⁶ )²
g = 8.79 m/s²
g ≈ 8.8 m/s²
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In the past, the Moon was closer to Earth, and the differences in the heights of the ocean at high and low tides were:
Answer:
"Greater"
If the moon is on the same side of the earth as the sun then one would expect a high tide (greater attraction of the water on the earth)
Likewise, if the moon and sun were on opposite sides of the earth, then one would expect the tide formed to be smaller.
The surface of the sun has a temperature of about 5800K and consists largely of hydrogen atoms.Part A) Find the rms speed of a hydrogen atom at this temperature. (The mass of a single hydrogen atom is 1.67×10−27kg.)Part B) The escape speed for a particle to leave the gravitational influence of the sun is given by (2GM/R)1/2, where M is the sun's mass, R its radius, and Gthe gravitational constant. The sun`s mass is M=1.99×1030kg, its radius R=6.96×108m and G=6.673×10−11N⋅m2/kg2. Calculate the escape speed for the sun.Part C) Can appreciable quantities of hydrogen escape from the sun?Part D) Can any hydrogen escape?
The escape velocity for the Sun is "6.18 x 10⁵ m/s".
The terms kinetic energy, escape velocity, and rms speed are all relevant to this query.
a) The hydrogen atom's rms speed at 5800 K is "11991 m/s." b) The Sun's escape velocity is 6.18 x 105 m/s.
a) To calculate the hydrogen atom's rms speed, we shall utilize the formula for the average kinetic energy of gas molecules. The root mean square speed of an atom is rms speed.
Where v=rms speed = and K = Boltzman's constant = 1.38 x 10-23 J/k, K.E = 1/2mv2 v = 3KT m
1.67 x 10-27 kg is the mass of an atom of hydrogen at absolute zero temperature, or T = 5800 k.
The resulting equation is 3(1.38 a 10-23 J/k) (5800 k) 1.67 10-27 kg v = 11991 m/s.
The following equation yields the Sun's escape velocity:
Ve= 2GM R in which ve = escape velocity equals?
G is equal to 6.673 x 10-" N.m2/kg2 (gravitational constant).
M = Sun's mass, which is 1.99 x 10^30 kg
Sun's radius is 6.96 x 10⁸ meters, thus R
In light of this, 2(6.673 10-11 N.m2/kg2) (1.99 x 1030 kg) 6.96 108 m Ve= Ve = 6.18 x 10^5 m/s
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Combine newton's 2nd law and hooke's law for a spring to find the acceleration of the block a(t) as a function of time. Express your answer in terms of k , m , and the coordinate of the block x(t).
The combined formula of Newton's second law and Hook's law to find the acceleration of a block as function of time is a(t) = [k. t (v0 + vf)]/2m.
What is the Newton's second law of motion?According to Newton's second law of motion, force applied to any object is directly proportional to the product of mass and acceleration.
F = ma
As we know that the Hook's law is given as;
F = kx
Combining two equations together; we get
ma = kx
So, a = kx/m
x is the extension of the spring
So, x = (v0 + vf)*t/2
a = kx/m= {k* (v0 + vf)*t/2}/m
So, a = [k. t (v0 + vf)]/2m
Thus, combined formula of Newton's second law and Hook's law to determine the acceleration of a block as function of time is a(t) = [k. t (v0 + vf)]/2m.
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before backing up your vehicle, you should look to the front, sides, and rear, and continue to look ______ while backing
Before backing up your vehicle, you should look to the front, sides, and rear, and continue to look to the rear while backing.
When you are backing up, you have to turn your head so that you can see above the head restraint. When you are backing up, you should not rely just on the mirrors. When one is backing up a vehicle and using mirrors to direct the vehicle, one's depth perception is impaired.
Because it is harder to keep steering control and the vehicle's balance when the car is in reverse, you should always back at low speeds. Because the reverse gear is more powerful than the driving gear, you should only press the accelerator pedal with extreme caution, if at all. If you don't slow down, your car will drive much too quickly.
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Why does centripetal acceleration point the same way as the centripetal force?
Answer:
If this help please set brainliest.
Centripetal acceleration is defined as the rate of change of velocity of an object moving in a circular path. It always points towards the center of the circular path that the object is following. This is because in order for an object to move in a circular path, there must be a force acting on it that is directed towards the center of the circular path. This force is known as the centripetal force.
The direction of the centripetal acceleration is therefore always the same as the direction of the centripetal force. This is because the centripetal acceleration is the result of the centripetal force acting on the object. The centripetal force causes the object to change direction, and the centripetal acceleration is the rate of change of velocity in that direction.
An auto, starting from rest, undergoes constant acceleration and covers a distance of 1250 meters. The final speed of the auto is 50 m/s. How long does it take to the car to cover the 1250 m
Answer:
25 s
Explanation:
AVERAGE velocity = (50 - 0 ) / 2 = 25 m/s
1250 m / 50 m/s = 25 seconds
A 8.3 cm diameter loop of wire is initially oriented perpendicular to a 1.5 T magnetic field. It is rotated so that its plane is parallel to the field direction in 0.26 s. What is the average induced emf in the loop
A wire loop with an initial 8.3 cm diameter is pointed directly at such a 1.5 T magnetic field. The loop's average induced emf is o.29 v.
How does EMF work?electromagnetic radiation-induced electric and magnetic forces. Researchers are examining whether the electromagnetic fields (EMFs) produced by electrical equipment, wireless and cellular cellphones, and power lines can result in cancer or other negative health effects. likewise known as electromagnetic field.
Do people possess EMF?Non-ionizing EMFs can come from both natural and man-made sources. One examples of a naturally present EMF is the global magnetic field, which makes the compass needle point north. That both ELF and RF categories of the non-ionizing portion of the spectrum apply to human-made EMFs.
∈εc = - (ΔΦ-θ)/Δt
= - (ABΔcosθ)/Δt
= - (π(0.110 m)² 1.5 T(cos90^∘-cos0^∘)/(0.20 s)
= - (π(0.110 m)² 1.5 T(0-1) /(0.20s)
avg. emf = 0.29 V
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The amplitude of a linearly damped harmonic oscillator decreases from 60. 0 cm to 40. 0 cm in 10. 0 s. What will be the amplitude of the harmonic oscillator after another 10. 0 s passes?.
The amplitude of the harmonic oscillator after 20s is calculated to be 32 cm.
What is amplitude?Amplitude is defined as the the maximum displacement from equilibrium. Amplitude of a wave is taken as the distance from the center line to the top of a crest or to the bottom of a trough .
Given, At = 40 cm at 10 s
Given, Ao = 60 cm and time, t = 10
Formula for amplitude is :
At = Ao (e^t/τ)
40 = 60 e^10/τ
ln 2/3 = 10/τ
τ = 24.66
A20 s = 60 e ^(2-/24.66)
A20 s = 32 cm
The amplitude of the harmonic oscillator after 20 s is 32 cm.
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the electric field inside the dome of a highly-charged van de graaff generator is _________.
The electric field inside the dome of a highly-charged van de graaff generator is high voltage current.
The number of charges that pass a given point each second. Just like water flow in a pipe: How much water passes a point each second is defined as current In the flashlight circuit, electrons flow from the negative terminal of the battery to the positive terminal.
The direction of the current, I, is just the opposite: from the positive terminal to the negative terminal. Typical path of an electron as it bounces off atoms in a metal wire. Because of the tortuous path the electron follows, its average velocity is rather small.
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Dana pushed a wooden crate that was at rest on the floor. The crate moved when she applied of force. If the friction coefficient was , what was the weight of the crate
A wooden crate that was lying still on the ground was pushed by Dana with his foot. The force that she applied, which was 49 N, was sufficient to move the crate. Because the friction coefficient was 0.1, we can determine that the weight of the crate is 490 Newtons. The correct answer is B.
To find the weight of the crate, you can use the equation for the force of friction, which is:
Friction = coefficient of friction * normal forceIn this case, the normal force is equal to the weight of the crate, so you can rearrange the equation to solve for the weight:
Weight = Friction / coefficient of frictionPlugging in the values from the problem, you get:
Weight = 49 N / 0.1 = 490 NSince 1 N is equal to 0.225 pounds, the weight of the crate is 490 N * 0.225 pounds/N = 110.5 pounds.
This question should be written as follows and provided with answer choices:
Dana pushed a wooden crate that was at rest on the floor. The crate moved when she applied 49 N of force. If the friction coefficient was 0.1, what was the weight of the crate?
A. 4,9 NB. 490 NC. 49 ND. 0.49 NThe correct answer is B.
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a spring has a length of 0.278 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a 3.22 kg mass hangs from it. what is the force constant of the spring? (use 9.8 m/s2 for g.)
0.278 m when a load of 0.300 kg hangs from it, and 0.750 m when a mass of 3.22 kg hangs from it, a spring will exert 29.4 N/m of force.
What is physics of force K?K stands for the proportionality constant, commonly referred to as the "spring constant." In layman's words, stiffness and strength are shown by the k variable in Hooke's law (F = -kx). An object requires more force to be stretched to a specific length the greater the value of k.
What does k) stand for?The electrostatic constant, also known as the Coulomb constant, electric force constant, or K, is a proportionality constant in electrostatics equations. It is equivalent to 8.9875517923(14)109 kgm3s4A2 in SI base units.
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the electric potential in a region of space is v=300v⋅mx2+y2√, where x and y are in meters.
x ,y=3.0m,1.5m is the electric potential in a region of space is v=300v⋅mx2+y2√, where x and y are in meters.
How the electricity works?This helps conduct electricity by giving the flow of electrons a targeted direction, allowing them to move uniformly while simultaneously creating a positive charge known as an electrical current.
What is electrical in science?Electricity is the movement of electrons between atoms
The outer shells can hold even more. Some atoms with many protons can have as many as seven shells with electrons in them. The electrons in the shells closest to the nucleus have a strong force of attraction to the protons.
The Whole Issue Is This:
A area of space has an electric potential of V=300V*m/(x2+y2)(1/2), where x as well as y are measured in meters.
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1. In a parallel circuit a component has a potential
difference across it of 9V.
a) What would be the voltage through
the other components in the circuit?
Answer: 9 volts
Explanation:
One rule of Parallel circuits: All components share the same voltage
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 2.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do?
Answer:
628 J
Explanation:
Force of friction x distance = work
force of friction = normal force * coeff
= ( 80 kg * 9.81 m/s^2) * .4 = 313.92 N
3139.2N * 2 m = 627.84 J = ~ 628 J
Density is mass per unit of volume. Which pair of lab instruments would a student use to measure the density of seawater?a caliper and a flaska stopwatch and a beakera balance and a beakera meter stick and a temperature probe.
Pair of lab instruments would a student use to measure the density of seawater the a balance and a graduated cylinder.
The volume of the seawater is calculated by a graduated cylinder and the mass is obtained by a balance we can find the density of the sea water.For samples containing solids pouring liquid into the graduated cylinder must be done quickly to avoid loss of solids.
Used when specified by the method, Used for sample volumes and chemical additions, where: Measured volume is greater than 25 mL, and Accuracy within 0.5% is acceptable. If the sample contains large amounts of solids, care must be taken to ensure the contents of the graduated cylinder is mixed during adjustments.
Graduated cylinder should, Have sufficient capacity, Be as close to the desired volume as feasible, Have graduations that allow measurement to the desired volume.
The given question is incomplete, the complete question is
Density is mass per unit of volume. Which pair of lab instruments would a student use to measure the density of seawater?
1. a caliper and
2. a flask
3. a stopwatch and a beaker
4. a balance and a graduated cylinder
5. a meter stick and a temperature probe
Hence, the correct option is 4.
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A student would use a balance and a graduated cylinder as a pair of lab tools to calculate the density of seawater.
We can determine the density of the sea water by using a graduated cylinder to calculate the volume and a balance to get the mass.
Pouring liquid into the graduated cylinder for samples that include solids must be done rapidly to prevent solids loss.
when the method so specifies, Used when the measured volume is higher than 25 mL and an accuracy of 0.5% is acceptable for chemical additions and sample quantities. Care must be taken to ensure that the contents of the graduated cylinder are mixed during adjustments if the sample contains significant amounts of solids.
Graduated cylinders have enough capacity, be as near as you can to the specified volume, have graduations that make it possible to measure the desired volume.
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Which of the following is not a unit of pressure?
O atmosphere
O psi
O N/m2
O mm of mercury
O pascal
O none of the above
The pressure unit is not the Newton. It is a measure of force. Newton is the right answer, thus.
What are the 4 pressure units?Other pressure measurements include pounds per square inch, bar, centimetres of water, millimetres of mercury, inches of mercury (used to measure blood pressure), torr, MSW, and FSW. Atmospheric pressure is measured in atm.
What are the 5 pressure units?Bar, atm, Pascal, kilo Pascal, and torr are the five different pressure units. The perpendicular force applied in a given region is what is referred to as pressure.
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A cylinder with cross-section area A floats with its long axis vertical in a liquid of density p. Part A Pressing down on the cylinder pushes it deeper into the liquid. Find an expression for the force needed to push the cylinder distance z deeper into the liquid and hold it there. Express your answer in terms of the variables P, A, and c. F = pAcg Submit Previous Answers ✓ Correct Part B A 5.0-cm-diameter cylinder floats in water. How much work must be done to push the cylinder 17 cm deeper into the water?
PART A:
The buoyant force is given by F = pAcg, where p is the density of the liquid, A is the cross-sectional area of the cylinder, and g is the acceleration due to gravity.
PART B:
Multiplying the force by the distance the cylinder is pushed, 17 cm, we get the work done to be W = (39.4 N)(0.17 m) = 6.74 J. So, the work done to push the cylinder 17 cm deeper into the water is 6.74 J.
THE CYLINDER EXPRESSIONPart A:
The force needed to push the cylinder distance z deeper into the liquid and hold it there is given by the buoyant force acting on the cylinder, which is equal to the weight of the fluid that the cylinder displaces. This buoyant force is given by F = pAcg, where p is the density of the liquid, A is the cross-sectional area of the cylinder, and g is the acceleration due to gravity.
Part B:
To find the amount of work done to push the cylinder 17 cm deeper into the water, we need to find the force required to do so and multiply it by the distance over which the force is applied. Using the formula from Part A, the force required is F = pAcg = (1000 kg/m³)(pi(0.05 m)²)(9.8 m/s²) = 39.4 N. Multiplying this force by the distance the cylinder is pushed, 17 cm, we get the work done to be W = (39.4 N)(0.17 m) = 6.74 J. So, the work done to push the cylinder 17 cm deeper into the water is 6.74 J.
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The goalkeeper is the only player allowed to use their hands OA True OB. False
Answer:True
Explanation:
