A bag contains 5 red and 3 blue marbles. Two marbles are drawn simultaneously from the bag. DETERMIN the probability that at least one is red.
total number of balls = 5 + 3 = 8
The possibilities are:
RR (two red) and RB (one red and one blue)
RR and RB are mutually exclusive
P(RR) =
please help :(Find the coordinates of the midpoint of HXH(4 1/2, -4 1/4) , X(2 3/4, -2 1/4)
To find the coordinates of the midpoint of HX, we would apply the midpoint formula which is expressed as
[tex]\text{Midpoint = }\lbrack\frac{(x1\text{ + x2)}}{2},\text{ }\frac{(y1\text{ + y2)}}{2}\rbrack[/tex]From the information given,
[tex]\begin{gathered} x1\text{ = 4}\frac{1}{2}\text{ = 4.5, x2 = 2}\frac{3}{4}=\text{ 2.75} \\ y1\text{ = -4}\frac{1}{2}=-4.5,\text{ }y2=-2\frac{1}{4}=\text{ - 2.25} \\ \text{Midpoint = }\lbrack\frac{(4.5\text{ + 2.75)}}{2},\text{ }\frac{(-4.5\text{ - 2.25)}}{2}\rbrack \\ \text{Midpoint = (3.625, - 3.375)} \end{gathered}[/tex]relation and functionFunction OperationComposition of functionsymmetryfunction Inversesrate of change scartterplotsMINIMUM STEPS PLEASE!
In order to find f(2) we just have to replace x by 2 in its equation:
f(x) = 3x - 1
↓
f(2) = 3 · 2 - 1
f(2) = 6 - 1
f(2) = 5
Finding g(x) = f(2)Since g(x) = f(2) is
g(x) = 5
using the equation of g, we have that
2x - 3 = 5
In order to find x we just solve the previous equation
2x - 3 = 5
↓ adding 3 both sides of the equation
2x - 3 + 3 = 5 + 3
2x = 8
↓ dividing by 2 both sides of the equation
2x/2 = 8/2
x = 4
Answer- D: x = 4
well I'm stuck on this homework question and need help please thank you
Use the sequence below to complete each task. 34, 25, 16, 7, ... a. Identify the common difference (a). b. Write an equation to represent the sequence. c. Find the 20th term (azo)
Problem
Solution
We have the following sequence of terms 34,25,16,7,....
Part a
The common difference for this case would be:
25-34= -9
16-25=-9
7-16= -9
Then the answer for part a would be -9
Part b
We want to write the following form:
an = a1 + (n-1) d
For this case d=-9, a1= 34
And then we can write the genral expression like this:
an = 34 + (n-1 ) (-9)
With n = 1,2,3,4....
Part c
In order to find the 20 th term we can replace n =20 and we got:
a20= 34 + (20-1) (-9) = 34-171= -137
please help me and answer quick because my brainly keeps crashing before i can see the answer
The surface area of a sphere is given by the formula
[tex]SA=4*pi*r^2[/tex]we have
r=24/2=12 ft ----> the radius is half the diameter
substitute
[tex]\begin{gathered} SA=4*pi*12^2 \\ SA=576pi\text{ ft}^2 \end{gathered}[/tex]HELP PLS (question in image)
Answer:
[tex]106-19\sqrt{x} 10[/tex]
Step-by-step explanation:
Convert the numeral in base ten. (Explanation please)
Converting the given expression which is [tex]43_{8}[/tex] to base ten gives 35 in base ten.
How to convert a number in base eight to base tenConversion of bases is achieved based on how the conversion to be done are are basically of two methods which are
conversion from other bases to base tenconversion from base ten to other basesThe question is about converting other bases (base eight) to base ten. The steps required are as follows:
For other bases, the number 8 as used is replaced by the number required to be convertedThe exponents starts from zero and increases from left to right as seen belowThe given data is a number in base eight
[tex]43_{eight}[/tex]
[tex]43_{eight}=4*8^{1}+3*8^0[/tex]
[tex]43_{eight}=4*8+3*1[/tex]
[tex]43_{eight}=32+3[/tex]
[tex]43_{eight}=35[/tex]
The number 35 is now in base ten and can be written as [tex]35_{10}[/tex]
Learn more about conversion of bases: https://brainly.com/question/28767496
#SPJ1
could you help me no other tutor will help and its heartbreaking so please try your hardest
The triangle has sides
a=8
b=14
c=19
You need to determine the measure of x
To determine the value of x you have to use the Law of Cosines that states that:
[tex]a^2+b^2-ab\cos \theta=c^2[/tex]Where a, b, and c are the sides of the triangle, and theta represents the angle we are looking for.
So first step is to replace the formula with the given data and solve the exponents
[tex]\begin{gathered} 8^2+14^2-8\cdot14\cos thetha=19^2 \\ 64+196-112\cos \theta=361 \\ 260-112\cos \theta=361 \end{gathered}[/tex]Next solve for the cosine of theta:
[tex]\begin{gathered} -112\cos \theta=361-260 \\ -112\cos \theta=101 \\ \cos \theta=\frac{101}{-112} \\ \cos \theta=-\frac{101}{112} \end{gathered}[/tex]And calculate the inverse cosine to determine the measure of the angle
[tex]\begin{gathered} \theta=\cos ^{-1}(-\frac{101}{112}) \\ \theta=154.39 \end{gathered}[/tex]Given that A = {1, 2,2 3} and B = {4, 6}, then find B×A
The solution for set B × A is {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}
Given,
The sets,
A = {1, 2, 3}
B = {4, 6}
We have to find B × A.
Here,
Consider the Cartesian product:
The set of all ordered pairs (x, y) such that x belongs to A and y belongs to B is referred to as the Cartesian Product of sets A and B in mathematics. For instance, the Cartesian Product of A and B is (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), and (2, 5) if A = [1, 2] and B = [3, 4, 5].
The Cartesian product of B × A = {(b, a) | b € B, a € A}
So,
B × A = {4, 6} × {1, 2, 3}
B × A = {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}
Learn more about Cartesian product here:
https://brainly.com/question/24372634
#SPJ1
Determine the common ratio for each of the following geometric series and determine which one(s) have an infinite sum.
I. 4+5+25/4+…
II. -7+7/4-7/9+…
III. 1/2-1+2…
IV. 4- ++...
A. III only
B. II, IV only
C. I, Ill only
D. I, II, IV only
The correct answer is Option A ( III Only). I . -16 sum cannot be negative, II. Not a G.P, III. Sum = 1/4, and IV. Not a G.P.
Solution:Given geometric series,
I. 4 +5 +25 /4 ….
The common ratio(r) is (5/1)/(4/1) = 5/4.
S∞ = a / ( 1 - r)
= 4 / ( 1 - 5/4)
= 4 / -1/4
S∞ = -16.
Since sum cannot be negative.
II . -7 + 7/3 - 7/9+ ....
Here common ratio = -7 / (7/3) = -1/3
but - 7/9 / 7 /3 = 7/9
Here there is no common ratio so this not a G.P.
iii. 1/2 -1 + 2.....
Common ratio = -1 / (1/2) = -2
S∞ = a / ( 1 - r)
= 1/2 / (1 -(-2))
S∞ = 1/4.
iv 4 - 8/5 +16/5.....
Here there is no common ratio.
So this is not a G.P.
To learn more about geometric series refer to :
https://brainly.com/question/24643676
#SPJ13
Given the figure below, determine the angle that is a same side interior angle with respect to
We remember that two interior angles are those inside the are of the lines, Thus, the angles in the area:
Are interior. Now, we identify two sides, the right side, and the left side, which have been separated by the transversal line.
Thus, the angle that is is the same side as ∡3, and also that is interior is ∡5.
What is the constant of proportionality of x 0 4 8 12 y 0 3 6 9
Answer:
3/4
Step-by-step explanation:
As y is changing by 3, x is changing by 4
Find the slope of the line that passes through (54, -61) and (8, -56).
Answer:
The slope m of the line that passes through the two given points is;
[tex]m=-\frac{5}{46}[/tex]Explanation:
We want to calculate the slope of the line that passes through the given point;
[tex](54,-61)\text{ and }(8,-56)[/tex]Recall that the slope formula can be written as;
[tex]m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]substituting the given points;
[tex]\begin{gathered} (x_1,y_1)=(54,-61) \\ (x_2,y_2)=(8,-56) \end{gathered}[/tex]We have;
[tex]\begin{gathered} m=\frac{-56-(-61)}{8-54}=\frac{5}{-46} \\ m=-\frac{5}{46} \end{gathered}[/tex]Therefore, the slope m of the line that passes through the two given points is;
[tex]m=-\frac{5}{46}[/tex]
A straight line is 180 degrees. Find the value of X.
Given a straight line angle = 180
So, the angles (9x-100) and (40-x) are supplementary angles
So,
[tex](9x-100)+(40-x)=180[/tex]Solve for x:
[tex]\begin{gathered} (9x-x)+(40-100)=180 \\ 8x-60=180 \\ 8x=180+60 \\ 8x=240 \\ x=\frac{240}{8}=30 \end{gathered}[/tex]So, the answer will be x = 30
Given a and b are the first-quadrant angles, sin a=5/13, and cos b=3/5, evaluate sin(a+b)1) -33/652) 33/653) 63/65
We know that angles a and b are in the first quadrant. We also know this values:
[tex]\begin{gathered} \sin a=\frac{5}{13} \\ \cos b=\frac{3}{5} \end{gathered}[/tex]We have to find sin(a+b).
We can use the following identity:
[tex]\sin (a+b)=\sin a\cdot\cos b+\cos a\cdot\sin b[/tex]For the second term, we can replace the factors with another identity:
[tex]\sin (a+b)=\sin a\cdot\cos b+\sqrt[]{1-\sin^2a}\cdot\sqrt[]{1-\cos^2b}[/tex]Now we know all the terms from the right side of the equation and we can calculate:
[tex]\begin{gathered} \sin (a+b)=\sin a\cdot\cos b+\sqrt[]{1-\sin^2a}\cdot\sqrt[]{1-\cos^2b} \\ \sin (a+b)=\frac{5}{13}\cdot\frac{3}{5}+\sqrt[]{1-(\frac{5}{13})^2}\cdot\sqrt[]{1-(\frac{3}{5})^2} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{1-\frac{25}{169}}\cdot\sqrt[]{1-\frac{9}{25}} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{\frac{169-25}{169}}\cdot\sqrt[]{\frac{25-9}{25}} \\ \sin (a+b)=\frac{15}{65}+\sqrt[]{\frac{144}{169}}\cdot\sqrt[]{\frac{16}{25}} \\ \sin (a+b)=\frac{15}{65}+\frac{12}{13}\cdot\frac{4}{5} \\ \sin (a+b)=\frac{15}{65}+\frac{48}{65} \\ \sin (a+b)=\frac{63}{65} \end{gathered}[/tex]Answer: sin(a+b) = 63/65
Evaluate.C15 3 It says I need to evaluate 15^C 3
Explanation
We are required to determine the value of the following:
[tex]_{15}C_3[/tex]This is achieved thus:
We know that the combination formula is given as:
Therefore, we have:
[tex]\begin{gathered} _{15}C_3=\frac{15!}{3!(15-3)!} \\ _{15}C_3=\frac{15!}{3!12!} \\ _{15}C_3=\frac{15\cdot14\cdot13\cdot12!}{3!12!} \\ _{15}C_3=\frac{15\cdot14\cdot13}{3!}=\frac{15\cdot14\cdot13}{3\cdot2\cdot1} \\ _{15}C_3=5\cdot7\cdot13 \\ _{15}C_3=455 \end{gathered}[/tex]Hence, the answer is:
[tex]455[/tex]Please assist me in understanding how to solve number 4
Solution:
Given that;
y varies directly with the square of x
[tex]y\propto x^2[/tex]This expression above becomes
[tex]\begin{gathered} y=kx^2 \\ Where\text{ k is the constant} \end{gathered}[/tex]When
[tex]y=10\text{ and x}=5[/tex]Substitute the values for x and y into the expression above to find k
[tex]\begin{gathered} y=kx^2 \\ 10=k(5)^2 \\ 10=k(25) \\ 10=25k \\ Divide\text{ both sides 25} \\ \frac{25k}{25}=\frac{10}{25} \\ k=\frac{2}{5} \end{gathered}[/tex]The expression becomes
[tex]\begin{gathered} y=kx^2 \\ y=\frac{2}{5}x^2 \end{gathered}[/tex]a) The value of y when x = 20
[tex]\begin{gathered} y=\frac{2}{5}x^2 \\ y=\frac{2}{5}(20)^2 \\ y=\frac{2}{5}(400) \\ y=160 \end{gathered}[/tex]Hence, the value of y is 160
b) The value of x when y = 40
[tex]\begin{gathered} y=\frac{2}{5}x^2 \\ 40=\frac{2}{5}x^2 \\ Crossmultiply \\ 40(5)=2x^2 \\ 200=2x^2 \\ Divide\text{ both sides by 2} \\ \frac{200}{2}=\frac{2x^2}{2} \\ 100=x^2 \\ x^2=100 \\ Square\text{ root of both sides} \\ \sqrt{x^2}=\sqrt{100} \\ x=10 \end{gathered}[/tex]Hence, the value of x is 10
What are the solutions to the equation ? e^1/4x = (4x) [tex]e^1/4x =abs( 4x)[/tex](Round to the nearest hundredth). The solutions are about x = and
The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.
What is the equation?The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
A formula known as an equation uses the same sign to denote the equality of two expressions.
As per the given expression,
e^(x/4) = |4x|
The function e^(x/4) is an exponential function and the plot of this function has been plotted below.
The mode function |4x| has also been plotted below.
The point of intersection is the point where both will be the same or the solution meets.
The first point of intersection is (0.267,1.0691) so x = 0.267 ≈ 0.27
The second point of intersection (-0.2357,0.9428) so x = -0.2357 ≈ -0.24
Hence " The solution of the equation e^(x/4) = |4x| for the x by graphical approach is 0.27 and -0.24.".
For more about the equation,
brainly.com/question/10413253
#SPJ1
Find the length of line segment MN. Round to the nearest hundredths place.
First, look th the graph and set the coordinate of the points:
M = (mx,my)= (-1,2)
N = (nx,ny)= (4,0)
Now, apply the distance formula:
[tex]\text{Distance =}\sqrt[]{(mx-nx)^2+(my-ny)^2}[/tex]Replace with the coordinates:
[tex]D\text{ =}\sqrt[]{(-1-4)^2+(2-0)^2}[/tex][tex]D=\sqrt[]{(-5)^2+2^2}=\sqrt[]{25+4}=\sqrt[]{29}\text{ =5.3}9[/tex]Distance: 5.39
Find the common difference and the recursive formula. 22,19,16,13
The common difference between each term is -3.
19 - 22 = -3
16 - 19 = -3
13 - 16 = -3
The recursive formula of an arithmetic sequence follows the pattern below:
[tex]a_n=a_{n-1}+d,n\ge2[/tex]where d = common difference and number of terms "n" must be more than or equal to two.
To be able to get the recursive formula, we will plug in the common difference assuming that first term a₁ = 22. Therefore, the recursive formula is:
[tex]a_n=a_{n-1}-3,for\text{ n}\ge2[/tex]What's the divisor, dividend, Quotient, and reminder in a long divison problem
In a long division problem, say 8/5:
[tex]\frac{8}{5}\text{ is the quotient}[/tex]• 8 is the divisor
,• 5 is the dividend
[tex]\frac{8}{5}=1\frac{3}{5}[/tex]• 3 is the remainder.
determine the domain and range of the piecewise function graphed below
The domain is all the possible input values, and the range is all the possible output values.
So according to this function (Given in the question).
The domain is [-3, 5] and the range is [-5, 4]
That is all to this question.
I need help pls 1. Is this graph sine or cosine 2. What’s the amplitude of graph 3. What’s the equation of the midline 4. Whats the period of the function Whats the equation of the function Whats the domain and range?
As per given by the question,
There are given that a graph.
Now,
1. The given graph is cosine graph.
2. The aplitute of the given graph is,
From the graph, it is lie between -2 to 2.
So,
The amplitude of the given graph is 2.
Now,
3. The equation of the midline is,
[tex]y=-2[/tex]Now,
4.The period of the fumction is,
[tex]P=\frac{2\pi}{3}[/tex]Now,
The equation of the function.
First the general form of cosine graph function is,
[tex]y=A\cos (bx+c)+d[/tex]Then,
[tex]y=2\cos (3x+c)+d[/tex]Now,
[tex]y=2\cos (3x-1)+3[/tex]Where, D is vertical shift.
Hence, the equation of the function is,
[tex]y=2\cos (3x-1)+3[/tex]Identify the type of polar graph for the equation: r = 3-5cos θ aLimacon with inner loop bCardioid cDimpled limacon dConvex limacon eRose Curve fCircle gLemniscate
Given the equation:
[tex]r=3-5\cos \theta[/tex]Let's identify the type of polar graph for the equation.
To identify the type of polar graph, use the formula below to get the Cartesian form:
[tex](x^2_{}+y^2)=r(\cos \theta,\sin \theta)[/tex]Thus, we have:
[tex](x^2+y^2)=3\sqrt[]{x^2+y^2}-5x[/tex]We have the graph of the equation below:
We can see the graph forms a Limacon with an inner loop.
Therefore, the type of polar graph for the given equation is a limacon with inner loop.
ANSWER:
Event A, Event B, and Event Care provided. Event A and Event B aremutually exclusive. Event A and Event C are not mutually exclusive.P(A) = 0.45P(B) = 0.30P(C) = 0.25What is the probability of the union of A and B?
Given data:
The probability of A is P(A)=0.45.
The probability of B is P(B)=0.30.
The expression for the mutually exclusive events is,
[tex]P(A\cap B)=0[/tex]The expression for the probability of A union B is,
[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =0.45+0.30-0 \\ =0.75 \end{gathered}[/tex]Thus, the probability of (AUB) is 0.75.
What would -5/6 be when turned into a decimal?
Answer:
answer is -0.8333
round about -0.834
Step-by-step explanation: I hope this helps.
Answer:
currently, Yamir is twice as old as pato. in three years, the sum of their ages will be 30. if pathos current age is represented by a, what equation correctly solves for a?
The given situation can be written in an algebraic way.
If pathos age is a, and Yamir age is b. You have:
Yamir is twice as old as pato:
b = 2a
in three years, the sum of their ages will be 30:
(b + 3) + (a + 3) = 30
replace the b = 2a into the last equation, and solve for a, just as follow:
2a + 3 + a + 3 = 30 simplify like terms left side
3a + 6 = 30 subtract 6 both sides
3a = 30 - 6
3a = 24 divide by 3 both sides
a = 24/3
a = 8
Hence, the age of Pato is 8 years old.
f(x) = square root of x - 5. find f^-1 (x) and it’s domain
Given:
f(x) = root x - 5
Rewrite the function using y,
[tex]y=\sqrt[]{x}-5[/tex]Now, interchange the position of x and y in the function,
[tex]x=\sqrt[]{y}-5[/tex]Isolate the dependent variable
[tex]\begin{gathered} \sqrt[]{y}=x+5 \\ y=(x+5)^2 \end{gathered}[/tex]Therefore,
[tex]f^{-1}(x)=(x+5)^2[/tex]And the domain is minus infinity to infinity
[tex]\begin{gathered} f^{-1}(x)=(x+5)^2 \\ \text{Domain}=(-\infty,\infty) \end{gathered}[/tex]In one us city the taxi cost is 2$ plus .50c per mile . If you are traveling from the airport there is an additional charge of 3.50$ for tolls how far can i travel for 33$
Let the number of miles I can travel for $33 be x;
The total cost of taxi ride from the airport is;
Flat fee + Tolls fee + Charge/Mile = Total cost
Flat fee = $2.00
Toll fee = $3.50
Charge per mile = 0.50x
Total cost = $33.00
Thus, we have;
[tex]\begin{gathered} 2.00+3.50+0.50x=33.00 \\ 0.50x=33.00-5.50 \\ 0.50x=27.50 \\ x=\frac{27.50}{0.50} \\ x=55 \end{gathered}[/tex]Thus, the number of miles
